PHP - Returning Rows Where Date Is...
Hey there,
I'm calculating the current date like so Code: [Select] $currentdate = date('d-m-Y', strtotime('+0 days')); So let's say a MYSQL field has a date of : 25-04-2011 in the format d-m-Y, and I want to return all of the rows that have a date that is -100 to +10 days compared to $currentdate, how do I do this? Any help is much appreciated. Best Regards, Aimless Similar TutorialsAlright, I have a Datetime field in my database which I'm trying to store information in. Here is my code to get my Datetime, however it's returning to me the wrong date. It's returning: 1969-12-31 19:00:00 $mysqldate = date( 'Y-m-d H:i:s', $phpdate ); $phpdate = strtotime( $mysqldate ); echo $mysqldate; Is there something wrong with it? Hello, i am trying to get my form to list usernames ascending as an option, but the select field just returns blank. Here is my code: Code: [Select] /** * editUserForm - Displays the users database table in * a nicely formatted field table. */ function editUserForm(){ $q = "SELECT * " ."FROM ".TBL_USERS." ORDER BY username ASC"; $result = $database->query($q); while ($row = mysql_fetch_assoc($result)) { echo '<option value="'.$row["username"].'">'.$row["username"].'</option>'; } } Code: [Select] <form action="/" method="post"> <div class="column"> <p> <select name="user" id="user" placeholder="Select A User To Edit" class="{validate:{required:true}}"> <option>Select A User To Edit</option> <? editUserForm(); ?> </select> </p> <div class="action_bar"> <input type="submit" class="button blue" value="Submit Post" /> <a href="#modal" class="modal button">Cancel</a> </div> </form> All help is appreciated Hey all, Im currently working on a site which I save a cookie on users computer for 1 month as well a row in a table with the 1 month expiring date plus cookie id. What I would like to know is if theres a way to make the server check the table every day at say 12pm to see if any corresponding user cookies in each row have expired on that day as to remove them from the table to match the expiring cookie on the users computer? I would like not to have to rely on a user/admin accessing in to make a script run instead have something thats timed to go off automatically instead? Is there anyway of doing this? Thanks! Hi I am new to php, I am trying to capture the url and place into a variable but I only get the 1st digit to show, I just cant see what I am doing wrong. Sorry to ask such a basic question but I just can't work it out, I have attached a screen shot of all me code, your help would be very very much appreciated. what Im basically trying to do is just like a phpmyadmin function... you select rows you want to update with a checkbox and then it takes you to a page where the rows that are clicked are shown in forms so that you can view and edit info in them... and then have 1 submit button to update them all at once. Hey, I'm using a script which allows you to click on a calendar to select the date to submit to the database. The date is submitted like this: 2014-02-08 Is there a really simple way to prevent rows showing if the date is in the past? Something like this: if($currentdate < 2014-02-08 || $currentdate == 2014-02-08) { } Thanks very much, Jack I have 2 queries that I want to join together to make one row
Hello. I'm new to pHp and I would like to know how to get my $date_posted to read as March 12, 2012, instead of 2012-12-03. Here is the code: Code: [Select] <?php $sql = " SELECT id, title, date_posted, summary FROM blog_posts ORDER BY date_posted ASC LIMIT 10 "; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { $id = $row['id']; $title = $row['title']; $date_posted = $row['date_posted']; $summary = $row['summary']; echo "<h3>$title</h3>\n"; echo "<p>$date_posted</p>\n"; echo "<p>$summary</p>\n"; echo "<p><a href=\"post.php?id=$id\" title=\"Read More\">Read More...</a></p>\n"; } ?> I have tried the date() function but it always updates with the current time & date so I'm a little confused on how I get this to work. I have tried a large number of "solutions" to this but everytime I use them I see 0000-00-00 in my date field instead of the date even though I echoed and can see that the date looks correct. Here's where I'm at: I have a drop down for the month (1-12) and date fields (1-31) as well as a text input field for the year. Using the POST array, I have combined them into the xxxx-xx-xx format that I am using in my field as a date field in mysql. <code> $date_value =$_POST['year'].'-'.$_POST['month'].'-'.$_POST['day']; echo $date_value; </code> This outputs 2012-5-7 in my test echo but 0000-00-00 in the database. I have tried unsuccessfully to use in a numberof suggested versions of: strtotime() mktime Any help would be extremely appreciated. I am aware that I need to validate this data and insure that it is a valid date. That I'm okay with. I would like some help on getting it into the database. Hi, I have a job listing website which displays the closing date of applications using: $expired_date (This displays a date such as 31st December 2019) I am trying to show a countdown/number of days left until the closing date. I have put this together, but I can't get it to show the number of days. <?php $expired_date = get_post_meta( $post->ID, '_job_expires', true ); $hide_expiration = get_post_meta( $post->ID, '_hide_expiration', true ); if(empty($hide_expiration )) { if(!empty($expired_date)) { ?> <span><?php echo date_i18n( get_option( 'date_format' ), strtotime( get_post_meta( $post->ID, '_job_expires', true ) ) ) ?></span> <?php $datetime1 = new DateTime($expired_date); $datetime2 = date('d'); $interval = $datetime1->diff($datetime2); echo $interval->d; ?> <?php } } ?> Can anyone help me with what I have wrong? Many thanks (continuing from topic title) So if I set a date of July 7 2011 into my script, hard coded in, I would like the current date to be checked against the hard coded date, and return true if the current date is within a week leading up to the hard coded date. How could I go about doing this easily? I've been researching dates in php but I can't seem to work out the best way to achieve what I'm after. Cheers Denno i have a table that shows payments made but want to the payments only showing from a set date(06/12/14) and before this date i dont want to show
this is my sql that doesnt seem to work and is showing dates before the specified date.
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"SELECT * FROM payments2014, signup2014, editprop2014 WHERE signup2014.userid = payments2014.payment_userid AND editprop2014.prop_id = signup2014.prop_id AND signup2014.userid !='page1' AND signup2014.userid !='page6' AND signup2014.userid !='page4' AND payments2014.payment_transaction_status !='none' AND payments2014.payment_transaction_status !='CANCELLEDa' AND payments2014.payment_type !='deposit' AND payments2014.payment_paid_timestamp NOT LIKE '%2012%' AND payments2014.payment_paid_timestamp NOT LIKE '%2011%' AND payments2014.payment_paid_timestamp >= '06/12/14' ORDER BY payments2014.payment_id DESC"i have some other parts in the statment but this one that should be filtering is host_payments2014.payment_paid_timestamp >= '06/12/14'thanks in advance Hi Guys.. How can I change a date on the fly ? Everything is UTC on my server. How can I change a date to something else on the fly? Ie: $timezone = "cet"; $datetime = "2011-09-04 19:53:00"; echo $datetime($timezone); So I can give it a datetime and have it echo the datetime as if it were in the other timezone? Thanks Graham I'm getting this Time Zone error. Perhaps it's a compatibility issue with PHP 5.3. Looked all over for an answer without finding one. Here is the error message Warning: date() [function.date]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/New_York' for 'EST/-5.0/no DST' instead in /blocked.php on line 41 12/02/12 Here is the code. Line 41 is near the bottom, the one with the d,m,y. Perhaps the echo date (d/m/y") needs to be changed. Appreciate any help! Code: [Select] <table border="3" width="16%" align="center" cellspacing="0" bgcolor="#FF6600" bordercolor="red" bordercolordark="red" bordercolorlight="red"> <tr> <td width="176"> <p align="center"><?php // shows IP Number on Page echo $ip; ?> </p> </td> </tr> </table> <p align="center"><?php // Show the user agent echo 'Your user agent is: <b>'.$_SERVER['HTTP_USER_AGENT'].'</b><br />';?></p> [b]<h1 align="center"><?php echo date("d/m/y");?></h1>[/b] </td> </tr> </table [,code] Hi, Currently I am making a module for joomla. every article has an publish date, if the article was published in 7 days ago, it will displayed as "article in last week", My idea is to use today's date - publish date, if the result is greater than 7 and smaller than 14, the article will be displayed as "article in last week. Any one know how to write this code? Here is what I have got, but not working. <?php $todays_date = date("Y-m-d"); $result = mysql_query("select * from jos_content where $test between $todays_date-14 and $todays_date-7"); while($row = mysql_fetch_array($result)) { echo "$todays_date - $row[title]"; } ?> Hi guys, I'm putting together a small event system where I want the user to add his own date and time into a textfield (I'll probably make this a series of drop-downs/a date picker later). This is then stored as a timestamp - "0000-00-00 00:00:00" which displays fine until I try to echo it out as a UK date in this format - jS F Y, which just gives today's date but not the inputted date. Here's the code I have right now: Code: [Select] $result = mysql_query("SELECT * FROM stuff.events ORDER BY eventdate ASC"); echo "<br />"; echo mysql_result($result, $i, 'eventvenue'); echo ", "; $dt = new DateTime($eventdate); echo $dt->format("jS F Y"); In my mysql table eventdate is set up as follows: field - eventdate type - timestamp length/values - blank default - current_timestamp collation - blank attributes - on update CURRENT_TIMESTAMP null - blank auto_increment - blank Any help as to why this could be happening would be much appreciated, thanks. Hi there, I have a string '12/04/1990', that's in the format dd/mm/yyyy. I'm attempting to convert that string to a Date, and then insert that date into a MySQL DATE field. The problem is, every time I try to do so, I keep getting values like this in the database: 1970-01-01. Any ideas? Much appreciated. Hi, I am trying to convert a String date into numeric date using PHP function's, but haven't found such function. Had a look at date(), strtotime(), getdate(); e.g. Apr 1 2011 -> 04-01-2011 Could someone please shed some light on this? Regards, Abhishek Hi all. I'm having a bit of trouble with my script. I can't get "getDirectoryListings()" to return what folders are inside of #SharedObjects Here's my 2 files, 1 is sollib.php, the other is solindex.php. Code: [Select] solindex.php: <?php require('sollib.php'); $shell= new COM('WScript.Shell'); $data=$shell->regRead('HKEY_LOCAL_MACHINE\Software\Microsoft\Windows\CurrentVersion\ProgramFilesDir'); $regval = trim($data, "Program Files"); if(getenv('AppData')!=''){ $filename = getenv('AppData')."\\Macromedia\\FlashPlayer\\#SharedObjects\\".getDirectoryListings(); die($filename); } ?> sollib.php: <?php die(getDirectoryListings()); function getDirectoryListings() { $final = ""; $filename = getenv('AppData')."\\Macromedia\\FlashPlayer\\#SharedObjects\\"; if ($handle = opendir($filename)) { while (false !== ($file = readdir($handle))) { if(($file != '.') && ($file != '..')) { if(!strpos($file,'.')) { if ($handle2 = opendir($filename.$file)) { while (false !== ($file2 = readdir($handle2))) { die($file2); if(($file2 != '.') && ($file2 != '..')) { $final = $filename."$file\\$file2\\".get_files($file2); die($final); if($file2 == 'www.xatech.com'){ die('files: '.get_files($file2)); } } } } }else{ $final = $file; } } } closedir($handle); } return $final; } function get_files($dir){ //path to directory to scan $directory = $dir; //get all sol files with a .sol extension. $file11 = glob("" . $directory . "*.sol"); //print each file name foreach($file11 as $files10){ $final = $files10; die($final); } } ?> |