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PHP - Get Multiple Form Values From One Input Box

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Get Multiple Form Values From One Input Box	View Content

I have a textarea feild in my form where the user can type in several keywords such as

Textarea Box Below

Cars
Trains
Buses

I have a database with the meanings of the words entered and want to be able to get the three definitions from the database on for submission.

In a normal input box where i only type one word i can grab no problem like so

$word = $_POST['word'];
$sql = "SELECT meaning FROM table WHERE word='$word'";

Though i am trying to get multiple values from the same textarea box

So if a user types in 3 words the query would query the database on thoses three words, the problem is i dont know how to get the diffrent words from the form

for example

$first = $_POST['word']; which would be the first word
$sec = $_POST['word']; which would be the second word etc.

Any help here would be great thanks.

Full Excel VBA Course - Beginner to Expert

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I have the form:

How Do I Convert String Values From An Input Form Into Integers?

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Well the topic may not sound very explicit. So I'll do my best to explain it here. I have a pull down menu as part of a form, which contains the months of the year. I'm trying to store the value of this form entry using the $_POST['month'] variable into a database but first, I need to convert the month values into their corresponding integer values( that is 1 for January, 2 for February etc), in order to easily do date calculations later down the road. Any ideas about how to do this? It may be helpful to include the code for the pull down menu.
Code: [Select]
<p><tab> Date of Birth: <?php //Make the month pull down menu.
//Array to store months.
$months = array (1 => 'January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December');
print '<select name= "month">';
foreach ($months as $key => $value) {
    print "\n<option value=\"$key\">$value</option>";
}
print '</select>'; ?> </tab>

<tab> <?php //Make the day pull down menu
print '<select name= "day">';
for ($day = 1; $day <= 31; $day++) {
    print "\n<option value=\"$day\">$day</option>";
}
print '</select>'; ?> </tab>

<tab><?php //Make the year pull down menu
print '<select name= "year">';
$start_year = date('Y');
for ($y = ($start_year - 18); $y >= 1900; $y--) {
    print "\n<option value=\"$y\">$y</option>";
}
print '</select>'; ?> </tab> </p>

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I have a form: <input id="house" name="element_1" class="element radio" type="radio" value="Daniel" /> <input id="car" name="element_2" class="element radio" type="radio" value="Joe" /> How can I give to "element_1" multiple value instead of only one? Welcome <?php echo $_GET["element_1"]; ?><br> ==== Welcome Daniel element_1 = element_12 = element_13 WHERE element_1 = Daniel element_12 = car element_13 = key Welcome <?php echo $_GET["element_12"]; ?><br> ==== Welcome car I need to create a structure for a 10 different values. I heard that will be easy to use array or object, I don t really now how to structure it.

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Hey all,

I am building a simple cms. I have a posts table and I have an images table. A post has many images and images has a foreign key to the posts table. So when a user edits, updates, creates, and deletes a post, they affect the images related to the post. Sometimes a post can have more than one image, like three images. Hence I rendered this in the view (note that I am using a datamapper that converts tables to objects and fields to key/value pairs):

Code: [Select]
foreach($records as $post){
echo form_open_multipart("homes/update/$post->id"); //File uploads require a multipart form. Default form handling uses the application/x-www-form-urlencoded content type. Multipart forms use the multipart/form-data encoding. //this is critical to pass the id as part of the action attribute of the form, so we can use our params hash to target the id to update the specific record

echo label('Update Title');
echo form_input('title',$post->title);
echo label('Update Body');
echo form_textarea('body',$post->body);

$images = $post->images->include_join_fields()->get();
if(!is_null($images->image_file_name)){
echo label('Update Images');
foreach($images as $image){
echo form_upload('image_file_name',$image->image_file_name);
}
}

}
echo form_submit('submit','Update');
The above line of code will render a few input file types. The problem occurs during posting to my update method. It is looking for one parameter from the input file field and so if I upload three different images, it will only look for one and write only one to database:

Code: [Select]
$field_name = 'image_file_name';
if ( ! $this->upload->do_upload($field_name)){
$error = array('error' => $this->upload->display_errors());
echo $error['error'];
// redirect('homes/edit');
}
else {
$data = array('upload_data' => $this->upload->data());
$image_file_name = $data['upload_data']['file_name'];

Is it possible to do wht I am trying to do? Should I only have on input file type per form submission or is that I need to fix the code to accomodate for multiple submissions by creating an array of sorts?

Thanks for response.

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Long time lurker, first time poster here. I am having a problem with a multiple file uploader form I am trying to build. I am using the CodeIgniter framework, but I believe my problem is with the form itself.

Here is the form:
Code: [Select]
<form action="http://localhost/show/submit" id="sendfiles" method="post" name="sendfiles" enctype="multipart/form-data">
<input type="hidden" name="doup" value="1" />
<input type="file" name="userfile1" value="" id="userfile1" size="20" /> <br />
<input type="file" name="userfile2" value="" id="userfile2" size="20" /> <br />
<input type="file" name="userfile3" value="" id="userfile3" size="20" /> <br />
<input type="submit" name="submit_btn" value="Upload" /> </form>

The form is being passed to this function:

if(empty($_POST['doup'])){
            foreach($_REQUEST as $k => $v)
                print ">>> $k : $v <br />";

            $data['form_open'] = form_open_multipart(uri_string(), array(
                'id' => 'sendfiles',
                'method' => 'post',
                'name' => 'sendfiles'
            ));
            $data['form_flag'] = form_hidden('doup', '1');
            $data['file1'] = form_input(array(
                'id' => 'userfile1',
                'name' => 'userfile1',
                'size' => '20',
                'type' => 'file',
            ));
            $data['file2'] = form_input(array(
                'id' => 'userfile2',
                'name' => 'userfile2',
                'size' => '20',
                'type' => 'file',
            ));
            $data['file3'] = form_input(array(
                'id' => 'userfile3',
                'name' => 'userfile3',
                'size' => '20',
                'type' => 'file',
            ));
            $data['form_submit'] = form_submit('submit_btn', 'Upload');
            $data['form_close'] = form_close();
            $this->load->view('show/submit', $data);
        } else {
            $config['allowed_types'] = 'mp3';
            $config['max_size']    = '10240';
            $config['upload_path'] = $this->config->item('file_upload_path');
            $uploaded_files = array();
            for($nona=1; $nona<4; $nona++){
                if (strlen($_FILES['userfile'.$nona]['tmp_name']) <=0){
                    echo  "tempname$nona failed";
                    continue;
                }


                //print "------ USERFILE $nona ------ <br />";
                //print sizeof($_FILES['userfile'.$nona])."<br />";
                //foreach ($_FILES['userfile'.$nona] as $k => $v){
                //    print "$k  :  $v <br />";
                //}

                $this->upload->initialize($config);
                $upload = $this->upload->do_upload('userfile'.$nona);
                if (!$upload){
                    $form_errors = array('form_errors' => $this->upload->display_errors());
                    $this->load->view('show/submit', $form_errors);
                    break;
                } else {
                    $data = array('upload_data' => $this->upload->data());
                    $data = $data['upload_data'];
                    $fp = $data['full_path'];
                    $filename = strtolower(random_string('numeric', 16) . $data['file_ext']);
                    $rel_path = 'show/submissons/uploaded/';
                    $path = $this->config->item('media_root_path') . $rel_path;

                    exec('mkdir -p ' . $path , $a1, $r1);
                    exec('mv ' . $fp . ' ' . $path .  $filename, $a2, $r2);

                    array_push($uploaded_files, $path .  $filename);
                }

            }
            $this->session->set_flashdata('img_data',implode("||", $uploaded_files));
           // redirect("show/submit_info");
        }

The problem is this:

When I choose only one file to upload, it works. I can choose any of the 3 inputs and it works great. But as soon as I try to choose 2 or more files, the form fails to post. When I press submit, the page simply reloads and none of the form variables get posted. I have checked settings in php.ini and tried building and rebuilding this form. I'm hoping someone here can provide some insight into what I'm doing wrong?

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Dear All Members

here is my table data..

(4 Columns/1row in mysql table)

id order_no order_date miles
310 001 02-15-2020 MI,108.53
Oh,194.57
PA,182.22
WA,238.57

How to split(miles) single column into (state, miles) two columns and output like following 5 columns /4rows in mysql using php code.

(5 Columns in mysql table)
------------------------------------------------------------------------------------

id order_no order_date state miles

310 001 02-15-2020 MI 108.53

310 001 02-15-2020 Oh 194.57

310 001 02-15-2020 PA 182.22

310 001 02-15-2020 WA 238.57

------------------my php code -----------

<?php
//invoice.php
include('../includes/config.php');

if(isset($_POST["add"]))
{
$order_no=$_GET['order_no'];
$order_date=$_GET['order_date'];
$miles=$_POST['miles'];

$miles = explode("\r\n", $_POST["miles"]);
$newdata = "'" . implode("','", $_POST["miles"]) . "'";
$sql ="INSERT INTO tble_states_miles(order_no,order_date, miles) VALUES(:order_no, :order_date, :newdata)";

$query = $dbh->prepare($sql);
$query-> bindParam(':order_no', $order_no, PDO::PARAM_STR);
$query-> bindParam(':order_date', $order_date, PDO::PARAM_STR);
$query-> bindParam(':miles', $newdata, PDO::PARAM_STR);

$lastInsertId = $dbh->lastInsertId();
if($lastInsertId)
{
echo "<script type='text/javascript'>alert('Added Sucessfull!');</script>";
echo "<script type='text/javascript'> document.location = 'ifta_miles_calculationlist_added.php'; </script>";
}
else
{
$error="Something went wrong. Please try again";
}

if($query->execute()) {

$sql = "update tis_invoice set flag='1' where order_no=:order_no";
$query = $dbh->prepare($sql);
$query-> bindParam(':order_no', $order_no, PDO::PARAM_STR);

$query->execute();

}
}
?>

----------------- my form code ------------------

<?php
               $order_no=$_GET['order_no'];
       $sql = "SELECT * from tis_invoice where order_no = :order_no";
       $query = $dbh -> prepare($sql);
       $query->execute(
array(
':order_no' => $_GET["order_no"]
)
);
       $result = $query->fetchAll();
       foreach($result as $row)
?>

<form method="post">
<table align="center" style="width: 55%">
                       <tr><td>Invoice Number</td></tr>
                       <tr><td><input type="text" name="order_no" value="<?php echo $row["order_no"]; ?>" readonly=""></td></tr>
                       <tr><td>Invoice Date</td></tr>
                       <tr><td><input type="text" name="order_no" value="<?php echo $row["order_date"]; ?>" readonly=""></td></tr>
                       <tr><td>
<textarea name="miles" class="form-control" rows="10" placeholder="" required></textarea>
</td></tr>
                       <tr><td>

<input type="submit" name="add" class="btn btn-primary" value="Add" />
</td></tr></table>
</form>

-- Can any one help how to correct my code..present nothing inserted on table

Thank You

Edited February 8, 2020 by karthicbabu

Table Issue - Multiple Location Values For User Pushes Values Out Of Row Instead Of Wrapping In Cell

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Hi,

My company has 240+ locations and as such some users (general managers) cover multiple sites. When I run a query to pull user information, when the user has multiple sites to his or her name, its adds the second / third sites to the next columns, rather than wrapping it inside the same table cell. It also works the opposite way, if a piece of data is missing in the database and is blank, its pull the following columns in. Both cases mess up the table and formatting. I'm extremely new to any kind of programming and maybe this isn't the forum for this question but figured I'd give it a chance since I'm stuck.

The HTML/PHP code is below:

<table id="datatables-column-search-select-inputs" class="table table-striped" style="width:100%">

<thead>

<tr>

<th>ID</th>

<th>FirstName</th>

<th>LastName</th>

<th>Username</th>

<th>Phone #</th>

<th>Location</th>

<th>Title</th>

<th>Role</th>

<th>Actions</th>

</tr>

</thead>

<tbody>

<?php

//QUERY TO SELECT ALL USERS FROM DATABASE

$query = "SELECT * FROM users";

$select_users = mysqli_query($connection,$query);

// SET VARIABLE TO ARRAY FROM QUERY

while($row = mysqli_fetch_assoc($select_users)) {

$user_id = $row['user_id'];

$user_firstname = $row['user_firstname'];

$user_lastname = $row['user_lastname'];

$username = $row['username'];

$user_phone = $row['user_phone'];

$user_image = $row['user_image'];

$user_title_id = $row['user_title_id'];

$user_role_id = $row['user_role_id'];

// POPULATES DATA INTO THE TABLE

echo "<tr>";

echo "<td>{$user_id}</td>";

echo "<td>{$user_firstname}</td>";

echo "<td>{$user_lastname}</td>";

echo "<td>{$username}</td>";

echo "<td>{$user_phone}</td>";

//PULL SITE STATUS BASED ON SITE STATUS ID

$query = "SELECT * FROM sites WHERE site_manager_id = {$user_id} ";

$select_site = mysqli_query($connection, $query);

while($row = mysqli_fetch_assoc($select_site)) {

$site_name = $row['site_name'];

echo "<td>{$site_name}</td>";

}

echo "<td>{$user_title_id}</td>";

echo "<td>{$user_role_id}</td>";

echo "<td class='table-action'>

<a href='#'><i class='align-middle' data-feather='edit-2'></i></a>

<a href='#'><i class='align-middle' data-feather='trash'></i></a>

</td>";

//echo "<td><a href='users.php?source=edit_user&p_id={$user_id}'>Edit</a></td>";

echo "</tr>";

}

?>

<tr>

<td>ID</td>

<td>FirstName</td>

<td>LastName</td>

<td>Username</td>

<td>Phone #</td>

<td>Location</td>

<td>Title</td>

<td>Role</td>

<td class="table-action">

<a href="#"><i class="align-middle" data-feather="edit-2"></i></a>

<a href="#"><i class="align-middle" data-feather="trash"></i></a>

</td>

</tr>

</tbody>

<tfoot>

<tr>

<th>ID</th>

<th>FirstName</th>

<th>LastName</th>

<th>Username</th>

<th>Phone #</th>

<th>Location</th>

<th>Title</th>

<th>Role</th>

</tr>

</tfoot>

</table>

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First, Happy X-Mas to all!

I want to do a form for entering dog-show results. On first site of form the user is able to enter how many dogs for each class (there are youth and open class for example) he want to insert. So on second site there will be formfields for every dog in every class, created with php. User should be able to take dogname from jquery autocomplete - this works for multiple fields. But i need the according id to the dogname - and actual only one id is given - the first one is changing by choosing from autocomplete in next fields...

Data came from a json array like

0: {dogidindatabase: "9892", value: "Excalibur Khali des Gardiens de la Cour ",…}
dogidindatabase: "9892"
label: "<img src='../main/img/female.png' height='20'>Excalibur Khali des Gardiens de la Cour   "
value: "Excalibur Khali des Gardiens de la Cour   "
1: {dogidindatabase: "15942", value: "Excalibur from Bandit's World Kalli",…}
dogidindatabase: "15942"
label: "<img src='../main/img/male.png' height='20'>Excalibur from Bandit's World   Kalli"
value: "Excalibur from Bandit's World   Kalli"

all i need is inside ...

the script in form is

<script type='text/javascript'>
		//<![CDATA[
		$(function() {
		
				$(".dog").autocomplete({
				source: "xxx.php",
				minLength: 3,
				select: function(event, ui) {
					$('#dogidindatabase').val(ui.item.dogidindatabase);
					}
			});
			
			$["ui"]["autocomplete"].prototype["_renderItem"] = function( ul, item) {
				return $( "<li></li>" ) 
  				.data( "item.autocomplete", item )
  				.append( $( "<a></a>" ).html( item.label ) )
  				.appendTo( ul );
			};
	
		});
		//]]>
</script>

and the form looked like

<input type='text' name='dog' class='dog' value='".strip_tags(${'dogname' .($countbabymale+1)})."' size='35' data-required='true' /><br>
	
<input class='readonly' readonly='readonly' type='text' id='dogidindatabase' name='dogidindatabase' size='5'  />

I changed in script and form id='dogidindatabase' to class, but it doesn´t work. Testsite is under http://www.wolfdog-d...how.php?lang=de (only german at first) - Insert a number (higher than 1) under baby 3-6 (first box, the others are not working for testing); submit to get to page 2; you see all post-variables (for testing). Try to insert a dogname in first input-field (choose "exc") and insert first one - the id is under dogname. In second dogname inputfield you can choose second dog - the id for the first one changes to id of seond one .... How can i get both for every dog?

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Can be those <input ...> types with values changed from a script ?. Imagine it like we have an admin and we want to change some input values with a generated form on that page instead of going source and changing 1 by 1 ?

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Short question: How can I get a string of HTML code and replace all the <input> tags with their values?

Long question: I have a web page with a purchase order on it in HTML format and one or more of the columns is editable via input boxes. So the user can change the quantity/length of the material before submitting it. Once they choose to save it, it sends the string of HTML to a PDF generator (DOMPDF) which converts the HTML to a PDF file and saves it to the server. The user then has a hard copy of the purchase order PDF saved for each job. The problem is DOMPDF doesn't do well with <input> tags, it just leaves them as a blank space. So I want to take that string of HTML and replace all input boxes with their values before sending it to DOMPDF.

Currently I'm using Javascript to do just that when the user clicks to save the modified purchase order. The problem with this is it only works for when the user modifies the purchase order and saves a new modified copy. I need to save a base unmodified copy of it when the page loads so this would strip all the input boxes from the page as soon as it loads and the user would no longer be able to edit anything. So I need something to send the string to DOMPDF when the page loads but not modify what's on the page. Any ideas? Thanks.

Posting Values From An Input Field

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I am having trouble sending information that was entered into a form, on the same page to the next page.

I am sure i have done this a few years ago but cant find the code and cant find the answer online, hope someone can help me.

My code is as follows:

<form method="POST" action="https://.............. .asp ">
<table>
<tr>
<td>Name: </td>
<td><input type="text" name="clientname" /></td>
</tr>
<tr>
<td>E-mail:</td>
<td><input type="text" name="email" /></td>
</tr>
<tr>
<td>Contact No:</td>
<td><input type="text" name="telno" /></td>
</tr>
</table>
<?php
$udate = date("y-m-d H:i:s", strtotime ("+2 hour"));
$uniquevalue = "$udate" . " " . "Simpay Pro";
echo $uniquevalue;
?>
<br />
<input type="hidden" name="info1" value="<?php print $uniquevalue?>">
<input type="hidden" name="info2" value=$clientname>
<input type="submit" value="Submit">
</form>

So basically info1 is working i can see the value on the next page after its submitted, but info2 is the value of the input field.

Is this possible to do it like this, or do i have to send it to another page and then to my last page that displays the values?

Getting Matching Post Values From Input Fields

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Hi

I have a form that is to input data from input fields to a table.
The form is as follows:

                            $query = $DB->query("SELECT country_code, country_id, IF(country_code = '".$country_code."', '', '') AS sel FROM exp_sme_countries WHERE site_id='".$this->settings['site_id']."' ORDER BY country_name ASC");
                            foreach ($query->result as $row)
                            {
                               $options .= '<label>' . 'Phrase for ' . $this->settings['countries'][$row['country_code']] . '</label>' . '<br />';
                               $options .= '<input style="width: 100%; height: 5%;" id="country_data" type="text"  name="country_id[]"  />' . '<br /><br />';
                               $options .= '<input type="hidden"  name="country_data[' . $row['country_id'] . ']" value="'.$row['country_id'].'"  />';
                            }

This outputs:
Code: [Select]
<input style="width: 100%; height: 5%;" id="country_data" type="text" name="country_id[]" />
<input type="hidden" name="country_data[68]" value="68" />

<input style="width: 100%; height: 5%;" id="country_data" type="text" name="country_id[]" />
<input type="hidden" name="country_data[28]" value="28" />

What I need to do, is get the values from the input fields and then match them with the correct hidden field value

So if in the first input field, I typed in 'Test data' and the second input, i typed 'This is great'

On the POST, I need to find the the value ('Test data') and also the value from the hidden field.

So something like:
Quote

The text you entered is: Test data with hidden value of 68
The text you entered is: This is great with hidden value of 28

I'd rather not use $_GET as this is a form that inserts data into a database.

Could someone point my in the right direction or provide an example?

Should I Escape Values From Radio Input Fields?

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Hey Guys. I have a quick question. Should i "prep" input values coming from a radio or checkbox input field? Can an SQL injection occur through those 2 input fields, or is it only text fields?

$variable = Multiple Values

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Hi Guys,

I don't know how to do this but basically I want the value of $postcode3 to equal the value of $postcodep1 aswell as $postcodep2 like this...

else {$postcode3 = $postcodep1 $postcodep2;}

That doesn't work...

Say
$postcodep1 = LS14
$postcodep2 = 2AB

Then
$postcode3 = LS14 2AB

How do I write this in the above php code?!

Thanks,
S

Multiple Post Values

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I'm sorting out a simple PHP email form, and I would like, when the email arrives in my inbox, for it to display both the email of the sender AND their name as specified in the form on my website.

So far I have
$from    = $_POST['from'];
with the 'from' being the client's email address. I would also like their name ('name') to show up next to their email in the header.

I have tried such things like

$from    = $_POST['from' . 'name'];
//or
$from    = $_POST['from']; $_POST['name'];

and a few more, but I'm terrible at PHP coding in general. I have searched, but I really am at a loss as to what to search for.

Can someone please give me an idea as to what I should do?

Thanks,
Sacha.

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Is is possible to give multiple values in a single checkbox?
i need to have a checkbox that holds multiple values.

Help Anyone..

Multiple Values In A Checkbox

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I have a form that has a list of checboxes, each checkbox has multiple values. IE. Checkbox1 has Date 1 and Cost1. Checkbox2 has Date2 and cost2 and so on.

This is what I have in form.

echo "<input type=checkbox name=service_id[] value=".$id."><label>".$description."</label> Date:<input type=date name=date[] value=".date('Y-m-d').">Date:<input type=number name=cost[] value=".$cost."><br>";

When i run the for loop to insert the values into a table i have this.

foreach($_POST['service_id'] as $key => $value){
$cat1=$_POST['service_id'][$key];
$cat2=$_POST['date'][$key];
$cat3=$_POST['cost'][$key];}

The problem is that when I select certain boxes (ie, checkbox #2), it inserts Date1 and Cost1 but does use the correct service id (ie checkbox)
I am clearly not storing the values into the array correctly. Any thoughts?

Multiple Select Options In A Multiple Page Form

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This seems to be a bit of a challenge but I am creating a multiple page form and on one of the pages I have a select field. I would like the user to have the ability to select multiple options but I am using some functions to move the data in hidden fields from page to page. I don't think my functions are jiving with my my foreach loop cause I keep getting an invalid argument error.

Thanks in advance for any help.

Here is my function:

function setSelected($fieldName, $fieldValue) {
if(isset($_POST[$fieldName]) && $_POST[$fieldName] == $fieldValue) {
echo 'selected="selected"';
}
}

And here is my loop:

$selections = "";

if(isset($_POST["selections"])) {
foreach ($_POST["selections"] as $selection) {
$selections .= $selection . ", ";
}
}

Problem With Arrays And Multiple Values Per Key

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I am very grateful for any input. I have a field in a database that contains references (pattern: authorYYYY), such as the following string: "authorA1989; authorB1978a; authorB1984; authorC1999; authorC2000a; authorC2000b; authorC2002; authorD2009" What I want is an output as the following in order to create a proper bibliography (therefore accessing another table and picking out the respective reference details): authorA 1989 authorB 1978a 1984 authorC 1999 2000a 2000b 2002 authorD 2009 I somewhat fail to group the values (years) per author. I know that keys are unique, but is there a way to work around this? Many thanks for any help!

Check String For Multiple Values

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Hi all, i've got a string ($currentcatid) which contains one number which changes dependant on which page the visitor is on.. ie it may be perhaps "23" or "17" .

I need to do a check against this string to see if it contains any of the following values .. 31,32, 1, 24 . I cant remember how i did it before but i think it was with pipes..

something along the lines of
if ($currentcatid =="31"||"32"||"1"||"24") { action }

can anyone help?

Thanks