PHP - Moved: Left Joined Table All Nulls?

Hi there   Just joined.

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Here is the original query:

Code: [Select]
$query_extract = mysql_query("SELECT downloads,date,title,username,views,id FROM skins ORDER BY id DESC LIMIT 100");

Is it possible to also grab the row username from the table users, without making multiple queries?

Below is my query, I have a column called boolActivate in my tblProperties table but I can't figure out how to put in a where clause so it reads something like WHERE boolActivate = 1     $strQuery = sprintf( "SELECT p.*, a.strAreaName FROM tblProperties p LEFT JOIN tblAreas a ON p.intAreaID = a.intID WHERE p.intID = %d", intval($intPropertyID));   Using MYSQL 5
Edited by datoshway, 04 November 2014 - 06:35 PM.

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Hi there,
is it possible to join a variable and a string inside a $_POST variable inside a mysql query (UPDATE in this case)

Here is what i am trying to accomplish:

$update = "UPDATE mona SET STKFF='$_POST[$counter."NAME"]' WHERE id='$userid'";

if (!mysql_query($update))
  {
  die('Error: ' . mysql_error());
  }
else echo " <br> Update Complete";

Its the '$_POST[$counter."NAME"]' bit that im worried about, is this possible without having to do:
$foo=$counter."NAME"
'$_POST[$foo]'


Thanks
Chris

I am trying to implement this for two days now but stuck with logics ! Please help.
What I can get the due left of every person easily for the following table [image attached] -
table link:  https://ibb.co/xC53Cf4
where
1.inc_due is the column to get total due for specific person like cust_id
2. inctype_id =11 is the type of dues paid for specific person (cust_id)
3. echo only due left by cust_id or person id

Hi,    I have the following query 

SELECT 
user_details.User_club_ID, 
user_details.fname, 
user_details.lname, 
user_details.email, 
user_details.club_No 
club.CLUBCODE, 
club.club_id
FROM user_details, club
WHERE club_id = $cid AND user_details.club_No = club.CLUBCODE AND user_status = 'active'";

which I converted to a prepared statement as 

SELECT 
user_details.User_club_ID, 
user_details.fname, 
user_details.lname, 
user_details.email, 
user_details.club_No 
club.CLUBCODE, 
club.club_id
FROM user_details, club
WHERE club_id = ? AND user_details.club_No = club.CLUBCODE AND user_status = ?";

Please note that user_status is a field in the table user_details. The original query (non -PDO) works correctly.   I want to know if this is correct and that the comparison in the WHERE clause  i.e. user_details.club_No = club.CLUBCODE is security safe. If not then how should this be modified.   Also if there is a better way to write this statement, kindly show that as well.  Thanks    Thanks all !
Edited by ajoo, 11 December 2014 - 02:35 AM.

Back with a new problem. 

I have 8 tables interconnected. 

Table#1 - Users
user_id | name

Table#2 - user_categories
id | user_id | category_id

Table#3 - user_cities
id | user_id | city_id

Table#4 - user_dates
id | user_id | dates_available

Table#5 - categories
category_id | category_name

Table#6 - cities
city_id | city_name

Table#7 - provinces
province_id | province_name

Table#8 - categories
country_id | country_name

Each user will have multiple categories, cities and available dates listed in these tables. I simply want to retrieve and list each user and their data on a page. 

Here's my query.

$url_city = 1;
$url_category = 2;
$url_date = '2021-07-19';

$find_records = $db->prepare("SELECT user_categories.*, categories.*, user_cities.*, cities.*, provinces.*, countries.*, user_dates.*, users.* FROM users
LEFT JOIN user_categories ON users.user_id = user_categories.user_id
LEFT JOIN user_cities ON users.user_id = user_cities.user_id
LEFT JOIN user_dates ON users.user_id = user_dates.user_id
LEFT JOIN categories ON user_categories.category_id = user_categories.category_id
LEFT JOIN cities ON user_cities.city_id = cities.city_id
LEFT JOIN provinces ON cities.province_id = provinces.province_id
LEFT JOIN countries ON provinces.country_id = countries.country_id
WHERE user_cities.city_id = :city_id AND user_categories.category_id = :category_id AND user_dates.date_available = :date_available GROUP BY users.user_id");
$find_records->bindParam(':city_id', $url_city);
$find_records->bindParam(':category_id', $url_category);
$find_records->bindParam(':date_available', $url_date);
$find_records->execute();
$result_records = $find_records->fetchAll(PDO::FETCH_ASSOC);
if(count($result_records) > 0) {
	foreach($result_records as $row) {

		$user_id    	  =	$row['user_id'];
        $name    		  =	$row['name'];

        $country_id       =	$row['country_id'];
        $country_code     =	$row['country_code'];
        $country_name     =	$row['country_name'];

        $province_id      =	$row['province_id'];
        $province_code    =	$row['province_code'];
        $province_name    =	$row['province_name'];

        $city_id          =	$row['city_id'];
        $city_name        =	$row['city_name'];

        $category_id      =	$row['category_id'];
        $category_name    =	$row['category_name'];

     }
}

There are no errors but the above query would only return a single row with only 1 "user" despite having multiple users in the "users" table. If I remove the GROUP BY, then it'll return multiple rows of the same user instead of all the relevant users.

So what do you think I am doing wrong with my query? 

Edited July 20 by imgrooot

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Is there a recommended way to code in order to have a dual language support, especially when one is English (left to right), and the other is Hebrew (right to left)?

Should I design every page twice or is there a ready made solution?

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