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PHP - Why Is My $_get Not Returning A Value?
Hi All
Please take a look at the code below. I am sucessfully accessing a database and pulling the details through into a HTML form with a drop down. However I then want to use a variable (test) in another page. However I cannot get the variable userrow['userid'] to send a value to my getquiz.php. What am I doing wrong? <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML> <HEAD> <TITLE> New Document </TITLE> <META NAME="Generator" CONTENT="EditPlus"> <META NAME="Author" CONTENT=""> <META NAME="Keywords" CONTENT=""> <META NAME="Description" CONTENT=""> </HEAD> <?php include_once "db.inc.php"; ?> <body> <form action="getquiz.php" method="GET"> <tr><td class="title">Please Select User</td> <td><select name="test"> <?php $courseid = mysqli_query($link, 'SELECT id FROM mdl_quiz WHERE course = "225"; '); if (!courseid) { $error = ' Error fetching course id: ' . mysqli_error($link); include 'error.html.php'; exit(); } else { while($row = mysqli_fetch_array($courseid)) { $user = mysqli_query($link, 'SELECT userid FROM mdl_quiz_attempts WHERE quiz =' . $row['id']); while ($userrow = mysqli_fetch_array($user)) { $names = mysqli_query($link, 'SELECT firstname,lastname FROM mdl_user WHERE id=' . $userrow['userid']); while ($usernames = mysqli_fetch_array($names)) {?> <option value="<?php $userrow['userid']?>"> <?php echo $usernames ['firstname'] . " " . $usernames['lastname'] . $userrow['userid']; ?> </option> <?php } } } } ?> </select> </td></tr> <center><input type="submit" value="Submit"></center> </table> </form> </body> </html> Similar TutorialsHi I am new to php, I am trying to capture the url and place into a variable but I only get the 1st digit to show, I just cant see what I am doing wrong. Sorry to ask such a basic question but I just can't work it out, I have attached a screen shot of all me code, your help would be very very much appreciated. As part of the registration procedure, my PHP application generates the mail below and presents the option to a user to click on the url in the mail to activate his account.
Please click on this link http://www.example.org.ng/activate.php?token=XeZNYf8uDVYxAY5+RBqldOosI1hm/FjB0cLnXB8R to activate your account.The activate.php script returns that their is no record of this token in the database, even though it is there. In troubleshooting, i printed the $token = $_GET["token"] in the activate.php script; and this is what i got XeZNYf8uDVYxAY5 RBqldOosI1hm/FjB0cLnXB8R. Notice that the $token variable is missing one character, (the +), which is the 16th character form the left!! Why this would happen is unclear. Any thoughts. If it helps, the is the script generating my random tokens:
function generateToken($length = 40)
{
if(function_exists('openssl_random_pseudo_bytes'))
{
$token = base64_encode(openssl_random_pseudo_bytes($length, $strong));
if($strong == TRUE)
return substr($token, 0, $length); //base64 is about 33% longer, so we need to truncate the result
}
//fallback to mt_rand if php < 5.3 or no openssl available
$characters = '0123456789';
$characters .= 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz^!$';
$charactersLength = strlen($characters)-1;
$token = '';
//select some random characters
for ($i = 0; $i < $length; $i++)
{
$token .= $characters[mt_rand(0, $charactersLength)];
}
return $token;
}
$token=generateToken($length = 40);
Edited by terungwa, 09 June 2014 - 05:17 PM. A few months ago, and a good amount of time before that, I had people telling me to use isset() instead of performing to see if the variable is empty, such as: !$_GET[''] I know the differences in the function and what they do, but when could isset() be used in a situation where it's better/more efficient then: !$_GET[''] I do use isset(), though. how would i get this to work if they have click on the add page and the action is add i want it to do something how would i do it Code: [Select] <?php if(isset($_GET['action'])){ } ?> <a href="pages.php?action=add">Add Page</a> hi all
new to webforum and php, how can I enter $_get['id] as I know this id...my code snippet is below
$sql = "SELECT x,y,z from tablename WHERE Id='" . $_GET["id"] . "'";
It works fine as it is getting the variable from a another webpage, but I know an id and want to enter it manually just to check a different webpage , thanks in advance....singhy
Please give example if the known id=xyztest
I am a new programmer. I am working on a personal project for my portfolio, it is a simple blog. I am trying to give the user the ability to delete a blog entry. It works fine, the problem is that when you refresh the page, with out clicking 'delete' the entry is still deleted. $_GET is passing the $id to my function and it is executing. The code I have posted is my effort to fix the problem. How can I connect $_GET to the delete button ? I have tried using a hidden value but this is not working. Any help would be greatly appreciated. AL Code: [Select] // code to display message before deletion if($_GET['T']) { echo("<div style='float:right; width:25%; height:100px; position:absolute; top:150px; right:15%;'>"); echo("<h2>Are you sure you want to delete:<h2>"); echo $_GET['T']; echo("<form method='get' action='?'>"); echo("<input type='submit' name='button' value='Delete'>"); echo("<input type='hidden' name='submit_check' value='1'>"); echo("</form>"); echo("<form action='http://nuke.industry.com/Blogspiracy/UserPage/index.php'>"); echo("<input type='submit' value='Cancel'/>"); echo("</form>"); echo("</div>"); } // code to delete a selected blog entry function delete_blog($id) { global $dbh; $sql = "DELETE FROM tblBlog WHERE tblBlog.id = '$id' LIMIT 1;"; $sth = $dbh->prepare($sql); $sth-> execute(); return; } if (isset($_GET['id']) && ($_GET['submit_check'])) how do I "GET" the hidden value? { $remove = delete_blog($_GET['id']); } [code] I never really thought about it before, but recently I visited a site with a url like: www.example.com/?OR Which made me wonder how you would go about getting that keyname since it is without a value. Any ideas? How to find the name value using php or $_GET here is the url header("Location:http://localhost:8666/OnlineBookingsPhp/index.php?name=Next"); Thanks Please i will like to know what this variable $_GET['id']is used for and how to use it Thanks I am really confused about how people use $_GET to give a page a link so far what I understand is that $_GET grabs the information from a link So if my link was http://localhost/stargate/users/profile.php?goauld=Sam how do I turn this into viewing Sams profile soon as i type in that link with out having to hit a search button first would really appreciate if someone help me understand this please cause it appears i really need to know how to do this. Code: [Select] <?php if(isset($_POST['search'])) { // searches goaulds then displays them $search3 = "SELECT goauld,id FROM users WHERE goauld='".mysql_real_escape_string($_POST['goaulds'])."'"; $search2 = mysql_query($search3) or die(mysql_error()); WHILE($search1 = mysql_fetch_array($search2)){ $grab_goauld = $search1['goauld']; echo '<table width="300" height="5" border="1" align="center">'; echo '<th><center>Goauld Statistics</center></th>'; echo "<tr><td height='340'>$grab_goauld</td></tr>"; } } echo '</table>'; ?> Hello can any one help me with this question iv only just started to use the get function like <code> if (isset($_GET['pageID'])){ echo $row['content']; } </code> can any one if me info how to make it safe how do i get the id from the url so i can use it I have javascript to load to my div the contents from php files something like this: QueryString is an addon javascript file loaded above so it works.. var get_id = $.QueryString["id"]; switch(get_id){ case 'page1': $('#div').load('php.php'); break; } on php.php when i try to get the $_GET['id']; which is obviously 'page1' it cant display it... i get nothing , i use switch in order to create dynamic div so i can click in my links and just load the divs content thanks. Hi I am trying to use 2 codes to get a url link. code1 (test.php): <form action="test1.php" method="GET" /> link: <input type="text" name="link" /><br /> <input type="submit" value="Submit" /> </form> code2 (test1.php) <?php $link = $_GET['link']; echo $link; ?> If I input a link as a text such as "Yahoo" it works. But if I input a link as "http://yahoo.com", it didn't work . I cannot seem to get my link to work.. I want to build a php script that has more than one $_GET command.. The link I want to make is: index.php?section=tutorial&viewing=18-classes_or_ids. Here is my PHP code.. <?php $section = $_GET['section']; switch ($section) { case "home": include("home.html"); break; case "register": include("register.html"); break; case "tutorial_home": include("tutorial.html"); break; default: include("home.html"); } $tutorial = "?section=" . urlencode('tutorial&viewing') . $_GET['tutorial&viewing']; switch ($tutorial) { case "18-classes_or_ids": include("classesorids.html"); break; } ?> Please help me!! I have a link (http://site.com/user/redirect). This link directs me to "site.com/user.php?level=site.com/123.php?hp=1" How can I echo just "site.com/123.php?hp=1"? I know how to use $_GET but I don't know how I can apply it to this. I am seen people have dynamic pages that loads the information from a database and then displays that information from the url. EG domain.com/somedirectory/something I have a website that does this but uses domain.com/something.php?id=something . This works great but when I go to try and get the statistics for that page from facebook for number of people that have liked that page. When I go to: http://graph.facebook.com/http://likebook.cz.cc/ It shows me the information: Code: [Select] { "id": "**************", "name": "LikeBook", "picture": "http://profile.ak.fbcdn.net/hprofile-ak-snc4/hs178.ash2/41817_130259343675613_3465_s.jpg", "link": "http://www.facebook.com/pages/LikeBook/130259343675613", "category": "Website", "description": "Collect every like at LikeBook.cz.cc", "fan_count": 3 } But when I try and go to: http://graph.facebook.com/http://likebook.cz.cc/like.php?id=31 It shows me: Code: [Select] { "id": "http://likebook.cz.cc/like.php" } So what I need to do is. Make a dynamic page within that sub directory. So that http://likebook.cz.cc/like/31 does grabs the information from line 31 of my database, like http://likebook.cz.cc/like.php?id=31 would do. Thank you ~AJ I have some javascript for a tabbed interface in index.php. The content of each tab is in content.php which uses $_GET to define which tab is selected. But i want to include queries based on variables from index.php how would i do this? here is the code for the tabbed interface: <script language="JavaScript" type="text/javascript" src="<?php echo SITE_ROOT; ?>/js/ahahLib.js"></script> <script language="JavaScript" type="text/javascript"> function makeactive(tab) { document.getElementById("tab1").className = ""; document.getElementById("tab2").className = ""; document.getElementById("tab3").className = ""; document.getElementById("tab"+tab).className = "active"; callAHAH('includes/content.php?content= '+tab, 'content', 'Loading...', 'Error'); } </script> <ul id="tabmenu" > <li onclick="makeactive(1)"> <a class="" id="tab1">Account Information</a> </li> <li onclick="makeactive(2)"> <a class="" id="tab2">Second Page</a> </li> <li onclick="makeactive(3)"> <a class="" id="tab3">Third Page</a> </li> </ul> <div id="content"></div> and the code in content.php if ($_GET['content'] == 1) { echo 'Content for Page 1'; } if ($_GET['content'] == 2) { echo 'Content for Page 2'; } if ($_GET['content'] == 3) { echo 'Content For Page 3'; } ive tried adding the variable $user_id to the content.php url as follows: callAHAH('includes/content.php?user=$user_id&content= '+tab, 'content', 'Loading...', 'Error'); } but that just brought up an error. Hi there, I am new to this forum want to say Hi to everyone . I just learn a little bit of PHP. I couldn't figure this out. Could someone please help me? Many thanks. 1. when I ran the 1st code below, it showed me "thank you" in the browser. <?php $title=$_GET[title]; echo $title; ?> 2. when I ran the 2nd code below, I got what I wanted. <?php $sql = "SELECT * FROM mytable WHERE title='thank you' "; ... ?> 3. when I ran the 3rd code below, it showed me a blank page . <?php $title=$_GET[title]; $sql = "SELECT * FROM mytable WHERE title='<?php echo $title; ?>' "; ... ?> How to make the 3rd code work like the 2nd one? It seems a php code under php is NOT working. Do I need to escape variables passed via link? Is it possible that someone does an SQL Injection via unescaped $_GET variable? (Yes I am using it in an SQL query, not inserting it into a DB tho) |
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