PHP - Using Preg_replace With A Function
Hey, I am trying to write a sort of replace function where {user:1} is converted into a set of information from a database using preg_replace. So I have created the following preg_replace:
$patterns = array(); $patterns[1] = '/\{user:([0-9]+)\}/'; $replacements = array(); $replacements[1] = UserCredit('$1'); ksort($patterns); ksort($replacements); $content_show = preg_replace($patterns, $replacements, $content); echo $content_show; and then the function UserCredit which is just above that on the page: function UserCredit($user_id) { require 'connect.php'; $user_lookup = mysql_query("SELECT * FROM prop_users WHERE ID = '$user_id'"); while($row = mysql_fetch_array($user_lookup)) { $user_name = $row['full_name']; $user_file = $row['credit_file']; $user_url = $row['link_url']; $user_url_alt = $row['link_alt']; } if(mysql_num_rows($user_lookup)==0){ die("An error has occured, Sorry for any Inconvenience Caused! User ID=".$user_id); } require 'close.php'; $output = "<li class=\"clearfix\"><div class=\"credimg\"><img src=\"".$user_file."\" width=\"75px\" height=\"75px\" alt=\"".$user_name."\" /></div><p><strong><a href=\"".$user_url."\" title=\"".$user_url_alt."\">".$user_name."</a></strong><br /><em>Writing / Code</em></p></li>"; return $output; } I have tested the function and it works when I echo UserCredit('1'); And the preg_replace works at simply extracting the value for the user. The only problem is that I can't figure a way for the preg_replace to carry the value of $1 into the function it just literally carries "$1" Is there something obvious that I am missing or am I going around this the wrong way? Similar TutorialsHi,
I'm using TCPDF to create a PDF from a webpage.
This works great but I have the following problem:
I'm building in WordPress and as you may know WP saves images on different sizes. (e.g. 150x150, 300x300 and 1024x1024)
The thing I'm trying to create is that users can download a PDF ready for printing. So High Resolution images.
I use a preg_match_all function to match the image source and remove the additional image size from the filename so the original high resolution image is loaded.
e.g. image-150x150.jpg will be replaced by image.jpg.
So now the original image that has a image size of 6024x6024px and 300 DPI is loaded.
Then TCPDF uses a resize function that resizes the image back to 150x150 px but sets the DPI to 300 so it can be printed on a good quality.
This all works but now the problem comes:
If I do the preg_match_all function the image gets "pulled" from the rest of the content and looses it's position.
So my thought to fix this was. Get a preg_replace function and replace the image tag with a function that executes the whole image change like described above.
This doesn't work......
So i'm stuck here. Hope anyone can assist me with this.
Here is what I have done so far.
function execute(){ preg_match_all("/<img[^>]+src=(?:\"|\')\K(.[^\">]+?)(?=\"|\')/",$content,$matches,PREG_PATTERN_ORDER); for( $i=0; isset($matches[1]) && $i < count($matches[1]); $i++ ) { $search = array('-'.$s1.'x'.$s2.'', '-'.$s3.'x'.$s4.'', '-'.$s5.'x'.$s6.''); $replace = array('', '', ''); $a = $matches[1][$i]; if (strpos($a,'-'.$s1.'x'.$s2.'') !== false) { $w = $s1; $w = $pdf->pixelsToUnits($w); $h = $s2; $h = $pdf->pixelsToUnits($h); $l = '57'; $l = $pdf->pixelsToUnits($l); $t = '170'; $t = $pdf->pixelsToUnits($t); }elseif (strpos($a,'-'.$s3.'x'.$s4.'') !== false) { $w = $s3; $w = $pdf->pixelsToUnits($w); $h = $s4; $h = $pdf->pixelsToUnits($h); $l = '217'; $l = $pdf->pixelsToUnits($l); $t = '20'; $t = $pdf->pixelsToUnits($t); }elseif (strpos($a,'-'.$s5.'x'.$s6.'') !== false) { $w = $s5; $w = $pdf->pixelsToUnits($w); $h = $s6; $h = $pdf->pixelsToUnits($h); $l = '57'; $l = $pdf->pixelsToUnits($l); $t = '310'; $t = $pdf->pixelsToUnits($t); } $content .= $pdf->Image(str_replace($search,$replace,$matches[1][$i]), $l, $t, $w, $h, 'JPG', '', '', true, 300, '', false, false, 0, false, false, false); } }; global $post; $id = $_GET['id']; $content_post = get_post($id);// get the content $content = $content_post->post_content; $content = apply_filters('the_content', $content); $content = str_replace(']]>', ']]>', $content); $content = preg_replace('/<img[^>]+./e',execute(), $content); // replace the image tag with the new image // EXPORT IT ALL $pdf->writeHTML($content, true, false, true, false, ''); Hi, I'm trying to create a simple BB code-type function, but I'm having trouble putting a function within preg_replace. Let me show you what I mean: Code: [Select] $bb_search = array ( '/\[b\]/', '/\[\/b\]/', '/\[img\=(.*?)\]/', ); $bb_replace = array ( '<b>', '</b>', check_image( '\\1' ), ); return preg_replace( $bb_search, $bb_replace, $text_string ); The first two (b and /b) work fine, even the function is recognised, but using \\1 doesn't put the bbcode value as the function value. I know that probably made no sense - I'm terrible at explaining these things, so sorry. If anyone can understand what I mean, even offer a solution, that would be great! Cheers! I'm trying to use preg_replace but I can't get it working. function replaceContent($sContent) { $aReplaceTags = array( "'\[MENU-CARD\](.*?)\[/MENU-CARD\]'is" => '\\1', "'\[CONTACT-FORM\]'is" => "Contactform", ); return preg_replace(array_keys($aReplaceTags), array_values($aReplaceTags), $sContent); } This works great however when I change '\\1' into a function the output of '\\1' will always be 1. function replaceContent($sContent) { $aReplaceTags = array( "'\[MENU-CARD\](.*?)\[/MENU-CARD\]'is" => $this->loadMenuCard('\\1'), "'\[CONTACT-FORM\]'is" => "Contactform", ); return preg_replace(array_keys($aReplaceTags), array_values($aReplaceTags), $sContent); } Anyone knows what I am doing wrong? Hi, Since upgrading to php 5.3 i have a line of code on my site that is giving me a depreciated error. The line of code is as follows: $data=eregi_replace(">"."[[:space:]]+"."<","><",$data); I've got as far as knowing i need to change it from eregi_replace to preg_replace but i can't for the life of me work out where to put any backslashes etc, if any. Is there a formula for working this type of thing out? Every example i see has backslashes and $1's all over the place. Do i simply do this "/ and this /" after and before every double quote? Or is it not as simple as that? Things never are are they! Please could an expert on here offer me any assistance. This is an important line of code(i think) so i didn't want to experiment as i would normally do, i need to get this right first time as i don't know what will happen if i get this wrong. Cheers. i get the following error in the comments in wordpress blog..: Warning: preg_replace() [function.preg-replace]: No ending delimiter '~' found in /home/doughhhh/public_html/wp-content/themes/upload/includes/theme-comments.php on line 75 the content of the file is: Code: [Select] <?php // Fist full of comments if (!function_exists("custom_comment")) { function custom_comment($comment, $args, $depth) { $GLOBALS['comment'] = $comment; ?> <li <?php comment_class(); ?>> <a name="comment-<?php comment_ID() ?>"></a> <div id="li-comment-<?php comment_ID() ?>" class="comment-container"> <div class="comment-head"> <?php if(get_comment_type() == "comment"){ ?> <div class="avatar"><?php the_commenter_avatar($args) ?></div> <?php } ?> <div class="reply"> <?php comment_reply_link(array_merge( $args, array('depth' => $depth, 'max_depth' => $args['max_depth']))) ?> </div><!-- /.reply --> </div><!-- /.comment-head --> <div class="comment-entry" id="comment-<?php comment_ID(); ?>"> <span class="arrow"></span> <div class="comment-info"> <div class="left"><span class="name"><?php the_commenter_link() ?></span></div> <div class="right"> <span class="date"><?php echo get_comment_date(get_option( 'date_format' )) ?> <?php _e('at', 'themejunkie'); ?> <?php echo get_comment_time(get_option( 'time_format' )); ?></span> <span class="perma"><a href="<?php echo get_comment_link(); ?>" title="<?php _e('Direct link to this comment', 'themejunkie'); ?>">#</a></span> <span class="edit"><?php edit_comment_link(__('Edit', 'themejunkie'), '', ''); ?></span> </div> <div class="clear"></div> </div> <?php comment_text() ?> <?php if ($comment->comment_approved == '0') { ?> <p class='unapproved'><?php _e('Your comment is awaiting moderation.', 'themejunkie'); ?></p> <?php } ?> </div><!-- /comment-entry --> </div><!-- /.comment-container --> <?php } } // PINGBACK / TRACKBACK OUTPUT if (!function_exists("list_pings")) { function list_pings($comment, $args, $depth) { $GLOBALS['comment'] = $comment; ?> <li id="comment-<?php comment_ID(); ?>"> <span class="author"><?php comment_author_link(); ?></span> - <span class="date"><?php echo get_comment_date(get_option( 'date_format' )) ?></span> <span class="pingcontent"><?php comment_text() ?></span> <?php } } if (!function_exists("the_commenter_link")) { function the_commenter_link() { $commenter = get_comment_author_link(); if ( preg_match( '~]* class=[^>]+>~', $commenter ) ) {$commenter = preg_replace( '~(]* class=[\'"]?)~', '\\1url ' , $commenter ); } else { $commenter = preg_replace( '~(<a )/', '\\1class="url "~' , $commenter );} echo $commenter ; } } if (!function_exists("the_commenter_avatar")) { function the_commenter_avatar($args) { $email = get_comment_author_email(); $avatar = str_replace( "class='avatar", "class='photo avatar", get_avatar( "$email", $args['avatar_size']) ); echo $avatar; } } ?> help! [attachment deleted by admin] im trying to do a complex(i think) prg replace but i keep getting the error: Code: [Select] Failed evaluating code: $lang->showing-1,1 the code i am trying to replace is: Code: [Select] <asf: lang[showing-<asf: var[num_report_alerts]>,<asf: var[num_report_alerts]>]> and the preg_replace is: Code: [Select] $content = preg_replace('|\<asf: lang\[(.*?)-(.*?)\]\>|e', '$lang->replace_vars($lang->//1, array(\\2))', $content); its supposed to take everything inside <asf: lang[]> and echo \\1 which would be "showing" and then add \\2 into an array which would be "array(1,1)". So the output would be showing 1 of 1. Anyone know where im going wrong? I'm trying to search a string for all occurences of a pattern, then append text after that pattern. The example is:
SUM("foo") as "bar"
and have it display as:
SUM("foo") over() as "bar"
The "SUM" could be any SQL aggregate and be case insensitive. So For bonus points, let's say the valid aggregates are array('SUM', 'MAX', 'MIN', 'AVG'). My plan right now is to figure it out for SUM, then loop it replacing the aggregate.
This is what I have so far... and it is not working.
$l= 'SUM("foo") as "bar"';
$l=preg_replace('/([^"]+")/','\0 over()',$l);
Thanks,
Ryan
i have: $msg = ereg_replace("[^A-z0-9]"," ",$msg); $msg = ereg_replace(" "," ",$msg); $msg = ereg_replace(" "," ",$msg); how will i apply preg_replace please??? thank you After days of searching I found this thread http://www.phpfreaks.com/forums/index.php?topic=236954.0 that helped me do what I was trying to do. I've gotten the code to create and rename my html document but I can't figure out how to use the preg_replace part. This is my template with the 3 variables I want to replace with values from a form. Code: [Select] <html> <head> <link rel="stylesheet" type="text/css" href="style.css" /> </head> <body> <?php include_once('content.php') ?> </body> <SCRIPT language="JavaScript" SRC="javascript.js"></SCRIPT> <script type="text/javascript"> function nametitle(){ parent.iframe1.document.getElementById("div1").innerHTML = "VARIABLE1 <br>VARIABLE2"; parent.iframe1.document.getElementById("quotes").innerHTML = "VARIABLE3"; } </script> </html> I've spent hours reading and trying to understand how to make it work but it's a little over my head. Could someone help me with this? Thanks, Hi, I'm kind of new to PHP and very new to Regular Expressions and I was wondering if someone could help run through this code snippet from a callback function in a Joomla plugin called Affliates Feed. So far I have this is passed a pointer to variable item (I understand this is effectively the same as passing the variable but a lot less CPU intensive. Creates an array with keys and values Now the for loop I am stuck with, I understand the interation through the array. But what is preg_replace returning and why pass it back that way hasn't it already done its job? Can any one help? And please feel free to be as basic as possible :help: Thanks, Adam Code: [Select] function gardening(&$item) { #renaming categories, not the most efficient use for example strtolower first, and use only lowercase in the rename array $rename=array( ' Gardening?' => '', 'Climber Plants' => 'Climbing Plants', 'Seeds.*Bulbs' => 'Seeds Bulbs', 'Plant protection' => 'Horticultural goods', 'Garden structures' => 'Garden buildings',); foreach ( $rename as $k => $v ) { list($item['menu_1'],$item['menu_2'])=preg_replace("#$k#",$v,array($item['menu_1'],$item['menu_2'])); } $item['menu_1']=ucfirst(strtolower($item['menu_1'])); $item['menu_2']=ucfirst(strtolower($item['menu_2'])); $item['menu_3']=ucfirst(strtolower($item['menu_3'])); $item['menu_4']=ucfirst(strtolower($item['menu_4'])); } Hello ppl, I have this website link http://www.somesite.com/anotherpage/yetotherpage.html what i want to make is using preg_replace that the final result will be www.somesite.com I am trying to pull out the image HTML tag but its not working as expected. Here is what I am doing $removeimagetag='/<a href/'; $replacwith = "illegal"; $_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']); in the 'descr' there is a <a href="http://s635.photobucket.com...... When it post it does not strip out the <a href So the image is displayed. I tried a modified version to test to see if it work that looked like this. $removeimagetag='/goofy/'; $replacwith = "illegal"; $_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']); When the word goofy appears in the text then its replaced with the word illegal, Also I would like to make it so that it replaces the entire line from the <a href....... to the </a> with a phrase that says "this feature is not allowed" rather than just the part in the front...the <a href. Any help you can be will be greatly appreciated. Hi everyone, how do i add and ampersand symbol into preg_replace preg_replace("/[^a-zA-Z0-9\s\-\'\,\.\_]/" where do i place the symbol? & I currently have some custom tags, similar to BBCode, to be used for comments on my site. I'm trying to create a [nobr] tag (note: I know the no break tag will work in many major browsers, but it's deprecated, so I'm trying to be compliant). The idea is that if I encounter the [nobr] tag, I need to remove all line breaks. Here's the best I can do, but it's not working as I had hoped. Here's what I currently use to replace line breaks with a break tag. Code: [Select] $str=str_replace("\r\n","<br>",$str); Here's my attempt at introducing this new tag. Code: [Select] function BbToHtml($str) { $before=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\1",$str); $during=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\2",$str); $after=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\3",$str); $during=str_replace("\r\n","",$during); if($during != "") { // If the [nobr] tag was found, go with the new string. $str = $before.$during.$after; } else { // If the [nobr] tag was not found, go ahead like normal. $str=str_replace("\r\n","<br>",$str); } return $str; I can't get that working. Any ideas on how to fix that, or a completely alternate method of doing it? Thank you! Hi there! I need to echo some text from a database table, this text should be linked to a url stored in the same database. I am trying to do this with preg_replace but I am terrible at it! I keep getting this error: Warning: Wrong parameter count for preg_replace() while($row = mysql_fetch_array( $result )) { $reg_exUrl = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/"; echo preg_replace ($reg_exUrl, $row['title'); Any suggestion? Thanks Okay, i know there are lots of these questions out there and tons of ways to do this. I do have it working to replace URLs with <a href="URLs">URLs</a> but now i need some help detecting <a href=""></a> so the preg_replace will not double up the code and mess up the link. here is my code so far. Code: [Select] <?php echo 'COMMENTS<br /><br />'; while($rows = mysql_fetch_array($comres)){ list($comid, $menu_title, $post_id, $comdate, $comname, $comment) = $rows; $comment = nl2br($comment); $comment = preg_replace('/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/', '<a href="$0" target="_new">$0</a>', $comment); $comment = str_replace("´", "'", $comment); $comdate = date("g:ia - M j, Y",strtotime("$comdate")); echo 'User: '.$comname.'<font color="#B20303"> - '.$comdate.'</font><br />'; echo ' - '.$comment.'<br /><br />'; } ?> so with this code, if someone commented a link like this http://example.com it will turn it this <a href="http://example.com" target="_new">http://example.com</a> but now if someone knew some basic HTML coding, and they used this <a href="http://example.com">Example.com</a> it will look like this... <a href=<a href="http://example.com" target="_new">http://example.com</a>>Example.com</a> Hi guys, this is what im trying to achieve, im trying to remove the links to the current page for all my web pages with a single script, like for example, if i am on a home page, then the home page hyperlink is disabled, and if i am on a about us page the hyperlink for about us is disabled, i have went through many forums and posts but the more i read the more confused i get, however i came up with a method of my own with many bits of code i've read about everywhere. firstly, the script collects the current url of the page(i dont need https or any sub direct, its just for example index.php) then it stores the page name, index.php into a variable say - $current Then a menu.php which is the navigation file is loaded and heres the part i cant get to work, i would like to match find that <a href="index.php"> index </a> and replace that with <a> index </> so that the link to the current page is disabled..i tried using preg_replace but failed miserably and opted to use str_replace Heres the code: <?php //the function below gets the current page url or file //i got this off webcheatsheet - http://www.webcheatsheet.com/PHP/get_current_page_url.php function getPage(){ return substr($_SERVER["SCRIPT_NAME"],strrpos($_SERVER["SCRIPT_NAME"],"/")+1); } //store the current url or the file name into a variable $current = getPage(); echo "The current page name is ".$current; $menu=file_get_contents("menu.php"); $string = "<a>"+$current+"</a>"; $link = "<a href="+ current +"> "; //i could not get preg_replace to work or come up with an effective regular expression //which is why i use str_replace instead. $menu=str_replace("" , $string, $menu); echo $menu; ?> How come preg_replace won't traverse multiple lines?
<?php
$str = ' Hi all. I'm having a bit of an issue with preg_replace and I'm not sure how to solve it. I'm having preg_replace find a "bus" (short for business) prefix in a file name and then print "Business Management" instead of "bus". I also have another prefix of "bus_it_requests". When preg_replace finds that prefix, it prints "Business Management It Requests" but I need it to print "Business It Requests". How do I have preg_replace make the distinction in the prefix matches? Code: [Select] $str = preg_replace('/('.$word.')/i', '<em>\1</em>', $str); how come this doesn't work when $word = 'http://www.google.com', or any other URL? |