PHP - Searching Multiple Words Over Multiple Tables

I am trying to export multiple csv files to download from 2 separate tables in my database.

Some background:
I have a web app that links to a phpmyadmin database. There are 2 tables in the database (entering and exiting). These tables hold the phone inventory information of employees currently entering or exiting the organization.

The fields in my tables a

location, firstname, lastname, username, extension, mac, type

What I am trying to do is export the data in these 2 tables to CSV (which I have working now) but I need to have multiple CSVs for each.

For example, for my exiting table, I need to have one CSV export all the fields in the table and I also need another CSV to export just the location and username field. I have a simple html form with a submit button which is currently working now:

<form action="exportexiting.php" method="POST" style="width: 456px; height: 157px">
   <div>
   <fieldset>
   <legend style="width: 102px; height: 25px"><strong>Entering CSV:</strong></legend>
   <input name="Export" type="submit" id="Export" value="Export">
   </fieldset><br/>
   </div>
</form>


This links to my exportexiting.php file:

<?php
$host = 'localhost';
$user = 'root';
$pass = 'xxxx';
$db = 'PhoneInventory';
$table = 'exiting';


 
// Connect to the database
$link = mysql_connect($host, $user, $pass);
mysql_select_db($db);
 
require 'exportcsv.inc.php';

 
exportMysqlToCsv($table);
 
 
 
?>

Then to exportcsv.inc.php:

<?php
 
function exportMysqlToCsv($table,$filename = 'export.csv')
{
    $csv_terminated = "\n";
    $csv_separator = ",";
    $csv_enclosed = '';
    $csv_escaped = "\\";
    $sql_query = "select * from $table";
 
    // Gets the data from the database
    $result = mysql_query($sql_query);
    $fields_cnt = mysql_num_fields($result);
 
 
    $schema_insert = '';
 
    for ($i = 0; $i < $fields_cnt; $i++)
    {
        $l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed,
            stripslashes(mysql_field_name($result, $i))) . $csv_enclosed;
        $schema_insert .= $l;
        $schema_insert .= $csv_separator;
    } // end for
 
    $out = trim(substr($schema_insert, 0, -1));
    $out .= $csv_terminated;
 
    // Format the data
    while ($row = mysql_fetch_array($result))
    {
        $schema_insert = '';
        for ($j = 0; $j < $fields_cnt; $j++)
        {
            if ($row[$j] == '0' || $row[$j] != '')
            {
 
                if ($csv_enclosed == '')
                {
                    $schema_insert .= $row[$j];
                } else
                {
                    $schema_insert .= $csv_enclosed .
               str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, $row[$j]) . $csv_enclosed;
                }
            } else
            {
                $schema_insert .= '';
            }
 
            if ($j < $fields_cnt - 1)
            {
                $schema_insert .= $csv_separator;
            }
        } // end for
 
        $out .= $schema_insert;
        $out .= $csv_terminated;
    } // end while
 
    header("Cache-Control: must-revalidate, post-check=0, pre-check=0");
    header("Content-Length: " . strlen($out));
    // Output to browser with appropriate mime type, you choose
    header("Content-type: text/x-csv");
    //header("Content-type: text/csv");
    //header("Content-type: application/csv");
    header("Content-Disposition: attachment; filename=$filename");
    echo $out;
    exit;
 
}
 
?>



Again, this is working perfectly for only exporting all the data from the exiting table into one CSV file. My question is, how can I make my one submit button export the 2 CSV files that I need?


Thanks for the help...

I have a form where a user can duplicate part of a form like below:


I've named the fields with the HTML arrays (ie. "fieldName[]") and came up with this:

//--> CONTROLLERS
$system_controllers_qty = $_POST['system_controllers_qty'];
$system_controllers_make = $_POST['system_controllers_make'];
$system_controllers_model = $_POST['system_controllers_model'];
$system_controllers_serial_no         = $_POST['system_controllers_serial_no'];
for ($i = 0; $i < count($system_controllers_qty); $i++)
{
echo "qty " . clean($system_controllers_qty[$i]) . "<br/>";
echo "make " . clean($system_controllers_make[$i]) . "<br/>";
echo "model " . clean($system_controllers_model[$i]) . "<br/>";
echo "serial_no " . clean($system_controllers_serial_no[$i]) . "<br/>";
}

//--> CPUS
$system_cpus_qty = $_POST['system_cpus_qty'];
$system_cpus_model = $_POST['system_cpus_model'];
$system_cpus_serial_no = $_POST['system_cpus_serial_no'];
$system_cpus_speed = $_POST['system_cpus_speed'];
for ($i = 0; $i < count($system_cpus_qty); $i++)
{
echo "qty " . clean($system_cpus_qty[$i]) . "<br/>";
echo "model " . clean($system_cpus_model[$i]) . "<br/>";
echo "serial_no " . clean($system_cpus_serial_no[$i]) . "<br/>";
echo "speed " . clean($system_cpus_speed[$i]) . "<br/>";
}

//--> DISKS
$system_disks_qty = $_POST['system_disks_qty'];
$system_disks_make = $_POST['system_disks_make'];
$system_disks_model_no = $_POST['system_disks_model_no'];
$system_disks_size = $_POST['system_disks_size'];
$system_disks_serial_no = $_POST['system_disks_serial_no'];
for ($i = 0; $i < count($system_disks_qty); $i++)
{
echo "qty " . clean($system_disks_qty[$i]) . "<br/>";
echo "make " . clean($system_disks_make[$i]) . "<br/>";
echo "model_no " . clean($system_disks_model_no[$i]) . "<br/>";
echo "size " . clean($system_disks_size[$i]) . "<br/>";
echo "serial_no " . clean($system_disks_serial_no[$i]) . "<br/>";
}

//--> MEMORY
$system_memory_qty = $_POST['system_memory_qty'];
$system_memory_serial_no = $_POST['system_memory_serial_no'];
$system_memory_manf = $_POST['system_memory_manf'];
$system_memory_part_no = $_POST['system_memory_part_no'];
$system_memory_size = $_POST['system_memory_size'];
for ($i = 0; $i < count($system_memory_qty); $i++)
{
echo "qty " . clean($system_memory_qty[$i]) . "<br/>";
echo "serial " . clean($system_memory_serial_no[$i]) . "<br/>";
echo "manf " . clean($system_memory_manf[$i]) . "<br/>";
echo "part_no " . clean($system_memory_part_no[$i]) . "<br/>";
echo "size " . clean($system_memory_size[$i]) . "<br/>";
}


This just outputs all the fields I post at the moment. Say I have 3 different disk types, it's going to loop 3 times. Is it possible to make this all into 1 giant query or am I better off doing each query separately? Each section is a different table.

I found this regex, which is what I want, here:

(?=.*\bdog\b)(?=.*\bpuppet\b)(?=.*\bfuzzy\b)

It is suppose to 'succeed' if it can find all the given words in any order.   Yet, when I try to test it against this sequence of words (or any other order of these words):

need fuzzy hand puppet in dogpen for dog

I get no indication of a match.   What am I not understanding?

Hi there

I am beginning to learn regex in php.  I was wondering why the following regex pattern wasn't finding the two words in the string and replacing them with welcome? '/(Hello).*?(Hi)/is'

Code: [Select]
$patterns = array();
$patterns[0] = '/(Hello).*?(Hi)/is';

$replacements = array();
$replacements[0] = 'Welcome';


ksort($patterns);
ksort($replacements);
echo preg_replace($patterns, $replacements, $string);

Any help would be much appreciated.  Thanks a million!

I've been trying to go around with str_replace to replace numbers with words.
I have a database which has table actions. The actions are saved in numbers from 0 to 20.
I'd need to get something to replace the numbers with words to explain what actions these are.

I've tried using this.
$action1 = str_replace("5", "Command", "action1");
But that doesn't work. Not even 100% sure if that is even correct, because I am new to the str_replace thing anyway.

Could someone help me with this, please?

$query = mysql_query("SELECT COUNT(tickets.id),tickets.id,tickets.status,tickets.date,tickets.question,tickets.title,users.position FROM tickets,users WHERE tickets.id='$existing' users.username='$username'");


How do I get it so it selects data from the table tickets where id='$existing', but I also want to get a user's (who is viewing the ID) position (rank). $username is a session. So, any thoughts on how I would do so?

My updated code:


<?php
session_start();
include("../includes/mysql.php");
include("../includes/config.php");

?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<link href="../style.css" rel="stylesheet" type="text/css" />
<title><?php echo $title; ?></title>
</head>

<body>
<div id="container">
<div id="content">
<div id="left">
<div class="menu">
<?php include("../includes/navigation.php"); ?>
<div class="menufooter"></div>
</div>
<?php include("../includes/menu.php"); ?>
</div>
<div id="middle">
<?php
$existing = $_POST['existing'];
$ip = $_SERVER['REMOTE_ADDR'];
$username = $_SESSION['user'];

$query = mysql_query("SELECT COUNT(tickets.id),tickets.id,tickets.status,tickets.date,tickets.question,tickets.title,users.position FROM tickets,users WHERE tickets.id='$existing' OR users.username='$username'");
$get = mysql_fetch_assoc($query);

if(!$existing)
{
echo 
'
<div class="post">
<div class="postheader"><h1>Error</h1></div>
<div class="postcontent">
<p>You have not enetered in a ticket ID. Please go back and do so.</p>
</div>
<div class="postfooter"></div>
</div>
';
}
elseif($get['COUNT(id)'] < 1)
{
echo 
'
<div class="post">
<div class="postheader"><h1>Error</h1></div>
<div class="postcontent">
<p>The ticket ID you are trying to use doesnt exist. Please go back or submit another ticket.</p>
</div>
<div class="postfooter"></div>
</div>
';
}
elseif($get['tickets.ip']==$ip || $get['user.position'] >= 1)
{
$status["tickets.status"]["0"] = "Waiting for support...";
$status["tickets.status"]["1"] = "Waiting for user...";
$status["tickets.status"]["2"] = "Ticket Closed...";
$status["tickets.status"]["3"] = "Ticket Opened...";

echo 
'
<div class="post">
<div class="postheader"><h1>View Ticket Status - ID '. $get["id"] .'</h1></div>
<div class="postcontent">
<p>Title: '. $get["tickets.title"] .' - Posted on: '. $get["tickets.date"] .'</p>
<p>Ticket Status: '. $status[$get["tickets.status"]] .'</p>
<p>Question: '. nl2br($get["tickets.question"]) .'</p>
</div>
<div class="postfooter"></div>
</div>
';

}
else
{
echo 
'
<div class="post">
<div class="postheader"><h1>Error</h1></div>
<div class="postcontent">
<p>This is not your ticket. You only have permission to view your tickets. Please go back.</p>
</div>
<div class="postfooter"></div>
</div>
';
}
?>
</div>
</div>
</div>
</body>
</html>

I hope this isn't a stupid question.  I have written a fairly large site using php and SQL.  The site has multiple features (how tos, classifieds, photos, videos, ect) with each section's data housed in its own table.  Now I would like to have one highlight from each section appear in boxes on the index page simutaniously. (basically returning one random item from each table when the page is loaded)  I know how to call each table individually with sql = mysql_query, however, I fear that calling the database that many times over and over in one page load could be problematic if the site begins to get a lot of traffic.   Am I correct in worring about overloading the server and is there a better way to do this?

I am working on a asset project to insert, delete and view assets (items) that i owe. I am having trouble in the insert part.

i have four tables

department (DeptID, DeptName) DeptID is the primary key in this table.

assetcategory (AssetCatID, AssestCategory) AssetCatID is the primary key in this table.

asset (AssetID, AssetDescription, EmpID, AssetCatID, DeptID, Model, Maker, SerialNUm, DateAguired) AssetID is the primary key here.

Employee (EmpID, FirstName, LastName) EmpID is the key here.

and this is the code i have to insert using php.
Code: [Select]
<?php 
if(isset($_POST['submit'])){

$FirstName = mysql_real_escape_string($_POST["FirstName"]);
$LastName = mysql_real_escape_string($_POST["LastName"]);
$DeptName = mysql_real_escape_string($_POST["DeptName"]);
$AssetCategory = mysql_real_escape_string($_POST["AssetCategory"]);
$Model = mysql_real_escape_string($_POST["Model"]);
$Maker = mysql_real_escape_string($_POST["Maker"]);
$SerialNum = mysql_real_escape_string($_POST["SerialNum"]);
$DateAguired = mysql_real_escape_string($_POST["DateAguired"]);
$AssetDescription = mysql_real_escape_string($_POST["AssetDescription"]);
$AssetCatID = mysql_real_escape_string($_POST["AssetCatID"]);
$AssetID = mysql_real_escape_string($_POST["AssetID"]);
$EmpID = mysql_real_escape_string($_POST["EmpID"]);
$DeptID = mysql_real_escape_string($_POST["DeptID"]);

if(empty($FirstName) || empty($LastName) || empty($DeptName) || empty($AssetCategory) || empty($Model) || empty($Maker) || empty($SerialNum) || empty($DateAguired) || empty($AssetDescription))
{
print "Please feel in all fields";
}
else
{
///insert into the department table..........
$query1= "INSERT INTO department VALUES (null,'{$DeptName}')";
$result1 = mysql_query($query1) or die(mysql_error());
$DeptID = mysql_insert_id();

//insert into the assetcategory table
$query2= "INSERT INTO assetcategory VALUES (null,'{$AssetCategory}')";
$result2 = mysql_query($query2) or die(mysql_error());
$AssetCatID = mysql_insert_id();

//insert into the assets table
$query3= "INSERT INTO assets VALUES (null,'{$AssetDescription}', '{$EmpID}','{$AssetCatID}','{$DeptID}','{$Model}','{$Maker}','{$SerialNum}','{$DateAguired}')";
$result3 = mysql_query($query3) or die(mysql_error());
$AssetCatID = mysql_insert_id();


print $query1;

}



}
else {
?>


the page is displaying this error: "Column 'AssetCatID' cannot be null"

I would need help in inserting into all table required data. any help? hope i am making sense

Hey,

I have a query running inner joins... which currently works, but I need some more information pulled from other tables...

Code: [Select]
define('WPSC_TABLE_PRODUCT_LIST', "{$wp_table_prefix}wpsc_product_list");
define('WPSC_TABLE_PRODUCTMETA', "{$wp_table_prefix}wpsc_productmeta");
define('WPSC_TABLE_CATREF', "{$wp_table_prefix}wpsc_item_category_assoc");
define('WPSC_TABLE_CATNAME', "{$wp_table_prefix}wpsc_product_categories");


$cf="Linked Products";
$sku = get_post_meta($post->ID, $cf, true);
$array = explode(",",$sku);

$products = array_count_values($array);

foreach($products as $key => $value) {
$product = $wpdb->get_row("SELECT meta.product_id AS pid, list.name AS name, list.price AS price, retailer.category_id AS catid FROM ".WPSC_TABLE_PRODUCTMETA." AS meta INNER JOIN ".WPSC_TABLE_PRODUCT_LIST." AS list ON ( list.id = meta.product_id ) INNER JOIN ".WPSC_TABLE_SHOPNAME." AS retailer ON ( retailer.product_id = meta.product_id ) WHERE `meta_key` IN ( 'sku' ) AND `meta_value` IN ( '{$key}' ) ORDER BY list.id DESC");
?>
But I also need the category name - So I have to cross reference the following...

wordpdem_wpsc_product_list

id      name
433   itemone
432   itemtwo
431   itemthree

wordpdem_wpsc_item_category_assoc

id   product_id    category_id
1    433                    1
2    432                    2
3    410                    3

wordpdem_wpsc_product_categories

id  name
1   Bread
2   Fish
3   Snacks

I've now written:
Code: [Select]
SELECT
meta.product_id AS pid,
list.name AS name,
list.price AS price,
retailer.category_id AS catid,
category.name AS catname

FROM wordpdem_wpsc_productmeta AS meta
INNER JOIN wordpdem_wpsc_product_list AS list ON ( list.id = meta.product_id )
INNER JOIN wordpdem_wpsc_item_category_assoc AS retailer ON ( retailer.product_id = meta.product_id )
INNER JOIN `wordpdem_wpsc_product_categories``wordpdem_wpsc_product_list` AS category ON ( retailer.category_id = category.id )
WHERE `meta_key` IN ( 'sku' ) AND `meta_value` IN ( '{$key}' ) ORDER BY list.id DESC
However it fails on line 12 (the Where statement...)

Any ideas what I've done wrong?

I'm having a hard time grasping how to select data from several tables.

Here's the code

Code: [Select]
<?php 
require_once "config.php";
$gamedate = $_SESSION['date'];
echo "These umpires are not currently scheduled on this date, and have not asked for the day off:<br />";

$umpirelist = Array('umpire 1 name', 'umpire 2 name', 'umpire 3 name');

$dbc = mysql_pconnect($host, $username, $password);  
mysql_select_db($db,$dbc);  

foreach($umpirelist as $data) { 

//now get stuff from a table           
$sql = "SELECT calendar.date, calendar.ump1, calendar.ump2, calendar.ump3, calendar.ump4, calendar.ump5, vacation.date, vacation.umpire FROM umps, calendar, vacation WHERE umps.full_name = $data AND $gamedate = `calendar.date` AND $gamedate = `vacation.date` AND $data NOT IN ('calendar.ump1', 'calendar.ump2', 'calendar.ump3', 'calendar.ump4', 'calendar.ump5') AND $data NOT IN ('vacation.umpire') order by umps.full_name asc"; 

$rs = mysql_query($sql,$dbc);  
$matches = 0; 
while ($row = mysql_fetch_assoc($rs))  {
$matches++; 
echo "$row[$data]<br />";
}
}
?>

The table CALENDAR holds the date of the game, who is playing, and what umpires are schedule for that game.  it does have a unique "row_number" column as well, but didn't think I'd need it in this select.

The table VACATION has the date, and umpire's name that is on vacation.

The table UMPS contains the umpires name (same names as the array in the code) and email addresses and login info.

I'm getting this error:

Quote

Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource on line 152



This is line 152

Quote

while ($row = mysql_fetch_assoc($rs))  {



Can someone please point me in the right direction as to where I'm going wrong?

Thanks!

hi im trying to echo out all the possibilities from one column in 2 different tables, both with the same structure. if that makes sense

this is what i have

$query = mysql_query("SELECT * FROM stanjamesprem,centrebetprem GROUP BY eventname ORDER BY eventtime ");
while($row = mysql_fetch_assoc($query))
   {
   echo $row[eventname];
   }

if i take one of the tables out it works fine but if i have 2 table names it doenst work

please help me

cheers matt

any questions please ask away

Hi, I want to be able to retrieve records from db tables to build an xml file. The problem I am having is that I don't know how to retrieve a value after using foreign key to get appropriate value. You see below I want to make a new attribute to store to var $newAttr.

Code: [Select]
<?php
$doc=new DOMDocument();
mysql_connect("localhost","root");
mysql_select_db("xmlDB");

$edges=mysql_query("SELECT * FROM edge");
while($row=mysql_fetch_assoc($edges)) {
if($row['flag']=='val') {
$curValue=mysql_query("SELECT val FROM value,edge WHERE val.edge_id=edge.edge_id");
if($curRowIsAttribute=mysql_query("SELECT is_Attribute FROM value,edge WHERE value.is_Attribute='Y' AND value.edge_id=edge.edge_id")) {
//create attribute node
$newAttr=$dom->createAttribute();//HELP HERE PLEASE THEN I SHOULD BE ABLE TO COMPLETE NEXT TWO LINES BELOW!

//set attribute value
...

//append attribute to current element
...

}//END IF
}//END IF
}//END BIG WHILE 
?>

Any help much appreciated!

 
I'm not sure if this belongs in the PHP or SQL sections or both but-
Is it possible to insert form data (one record) into 2  different tables when I click submit?
  As is, I have 2 distinct log-in scripts each linked to 2 separate databases .  I want to merge them into one log-in form that populates both tables(in different dbs). I don't want my visitors to log into 2 different forms.  Can one form's action attribute send the POST data to two different processing scripts? and can the input from a text  box be sent to 2 different fields?
I don't have any code, I just wanted to know if it can be done or point me to a sample that I can work from.