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PHP - Insert Into Two Tables
I have a form that inserts a tables records into my database. Ive tried to modify it so it will insert into two tables but it only seems to insert into one table and not the other. I made a query that counts the rows of the 2nd table and +1, which is then suppose to be inserted.
Code: [Select] <?php $editFormAction = $_SERVER['PHP_SELF']; if (isset($_SERVER['QUERY_STRING'])) { $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']); } if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form1")) { $insertSQL = sprintf("INSERT INTO fleet (FleetName) VALUES (%s)", GetSQLValueString($_POST['ffleetname'], "text")); $insertSQL = sprintf("INSERT INTO ships (ShipName, FleetName, PlayerName, Image, Image2, Cost, HealthA, HealthB, MaxHealthA, MaxHealthB, `Class`, PlanetName) VALUES (%s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s)", GetSQLValueString($_POST['shipname'], "text"), GetSQLValueString($_POST['fleetname'], "text"), GetSQLValueString($_POST['playername'], "text"), GetSQLValueString($_POST['image1'], "text"), GetSQLValueString($_POST['image2'], "text"), GetSQLValueString($_POST['cost'], "int"), GetSQLValueString($_POST['ha'], "int"), GetSQLValueString($_POST['hb'], "int"), GetSQLValueString($_POST['mha'], "int"), GetSQLValueString($_POST['mhb'], "int"), GetSQLValueString($_POST['class'], "int"), GetSQLValueString($_POST['select'], "text")); mysql_select_db($database_swb, $swb); $Result1 = mysql_query($insertSQL, $swb) or die(mysql_error()); $insertGoTo = "ship.php"; if (isset($_SERVER['QUERY_STRING'])) { $insertGoTo .= (strpos($insertGoTo, '?')) ? "&" : "?"; $insertGoTo .= $_SERVER['QUERY_STRING']; } header(sprintf("Location: %s", $insertGoTo)); } $colname_Fleetcount = "-1"; if (isset($_GET['recordID'])) { $colname_Fleetcount = (get_magic_quotes_gpc()) ? $_GET['recordID'] : addslashes($_GET['recordID']); } mysql_select_db($database_swb, $swb); $query_Fleetcount = sprintf("SELECT * FROM fleet"); $Fleetcount = mysql_query($query_Fleetcount, $swb) or die(mysql_error()); $row_Fleetcount = mysql_fetch_assoc($Fleetcount); $totalRows_Fleetcount = mysql_num_rows($Fleetcount); ?> <input name="image1" type="hidden" value="<?php echo $row_Ships['Image']; ?>" /> <input name="image2" type="hidden" value="<?php echo $row_Ships['Image2']; ?>" /> <input name="cost" type="hidden" value="<?php echo $row_Ships['Cost']; ?>" /> <input name="ha" type="hidden" value="<?php echo $row_Ships['HealthA']; ?>" /> [b] <input name="ffleetname" type="hidden" value="<?php echo $totalRows_Fleetcount = mysql_num_rows($Fleetcount) + 1;?>" /> <input name="fleetname" type="hidden" value="<?php echo $totalRows_Fleetcount = mysql_num_rows($Fleetcount) + 1;?>" />[/b] <input name="hb" type="hidden" value="<?php echo $row_Ships['HealthB']; ?>" /> <input name="mha" type="hidden" value="<?php echo $row_Ships['MaxHealthA']; ?>" /> <input name="mhb" type="hidden" value="<?php echo $row_Ships['MaxHealthB']; ?>" /> <input name="class" type="hidden" value="<?php echo $row_Ships['Class']; ?>" /> <input name="playername" type="hidden" value="<?php echo $_SESSION['MM_Username']; ?>" /> <input name="shipname" type="hidden" value="<?php echo $row_Ships['ShipName']; ?>" /> <input type="submit" name="Submit" value="Submit" /> <input type="hidden" name="MM_insert" value="form1"> </form> Any ideas? Thanks Similar TutorialsQuote $con = mysql_connect("localhost","****","****"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("checkmyw_database", $con); mysql_query("INSERT INTO requests (username, password, email, weavecode, mobile, jobtitle, relationship, sexuality, venue, type) VALUES ('$me', '$pw', '$email','1999','$mobile','$job','$relationship','$sexuality','$venue','newuser')"); mysql_query("INSERT INTO members (username, password, email, weavecode, mobile, jobtitle, relationship, sexuality,) VALUES ('$me', '$pw', '$email','1999','$mobile','$job','$relationship','$sexuality',)"); mysql_close($con); any idea why this doesn't work? Hi guys, Is it possible to insert into two tables in a database? Thanks Hi, I'm quite new to php and not the greatest of coders, so urgently require your help. I want to be able to take data from an un-normalised table and load into 2 normalised tables as below: 1) Table 1 - All Music Tracks (Un-normalised table) Album Name Artist Name Track Name Track Length etc. 2) Table 2 - Albums Table (Normalised table) ID Artist Name Album Name etc. 3) Table 3 - Tracks Table (Normalised table) ID Track Name Album ID (foreign key to Albums table) etc. Can someone please provide some sample code as a starting point? The All Music Tracks table includes both the album name and track name in each row, but I only want the album appearing once in the Albums tables, would I have to do an Distinct select first to get the album names into an array? I'm not sure how I would then have nested loop to do the insert into the Tracks table. Much Appreciated, PD I have 3 tables w/ the following fields: Cities id | state_id | city_name States id | state_name New_cities id | state_id | city_name I am trying to write a script (and still working on it) that will INSERT new cities in cities WHERE New_cities.state_id = Cities.state_id. Obviously I am still in testing and results sort out, but honest to all hell, I might be going about this all wrong, and would appreciate any comments, criticism, assistance or feedback on what I am trying to do. <?php $query = "SELECT * FROM cities, states, new_cities"; if ($results = mysqli_query($cxn, $query)) { $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { if ($row['cities']['state_id'] == $row['new_cities']['new_state_id']) { $insert_city_query = "INSERT INTO cities id, new_state_id, city_name VALUES ('','$new_state_id','$city_name')" or mysqli_error(); } //if ($row['cities']['state_id'] == $row['new_cities']['new_state_id']) echo "$row[new_city_name]<br />"; } //while ($row = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) } //if ($results = mysqli_query($cxn, $query)) ?> I have a form where a user can duplicate part of a form like below: I've named the fields with the HTML arrays (ie. "fieldName[]") and came up with this: //--> CONTROLLERS $system_controllers_qty = $_POST['system_controllers_qty']; $system_controllers_make = $_POST['system_controllers_make']; $system_controllers_model = $_POST['system_controllers_model']; $system_controllers_serial_no = $_POST['system_controllers_serial_no']; for ($i = 0; $i < count($system_controllers_qty); $i++) { echo "qty " . clean($system_controllers_qty[$i]) . "<br/>"; echo "make " . clean($system_controllers_make[$i]) . "<br/>"; echo "model " . clean($system_controllers_model[$i]) . "<br/>"; echo "serial_no " . clean($system_controllers_serial_no[$i]) . "<br/>"; } //--> CPUS $system_cpus_qty = $_POST['system_cpus_qty']; $system_cpus_model = $_POST['system_cpus_model']; $system_cpus_serial_no = $_POST['system_cpus_serial_no']; $system_cpus_speed = $_POST['system_cpus_speed']; for ($i = 0; $i < count($system_cpus_qty); $i++) { echo "qty " . clean($system_cpus_qty[$i]) . "<br/>"; echo "model " . clean($system_cpus_model[$i]) . "<br/>"; echo "serial_no " . clean($system_cpus_serial_no[$i]) . "<br/>"; echo "speed " . clean($system_cpus_speed[$i]) . "<br/>"; } //--> DISKS $system_disks_qty = $_POST['system_disks_qty']; $system_disks_make = $_POST['system_disks_make']; $system_disks_model_no = $_POST['system_disks_model_no']; $system_disks_size = $_POST['system_disks_size']; $system_disks_serial_no = $_POST['system_disks_serial_no']; for ($i = 0; $i < count($system_disks_qty); $i++) { echo "qty " . clean($system_disks_qty[$i]) . "<br/>"; echo "make " . clean($system_disks_make[$i]) . "<br/>"; echo "model_no " . clean($system_disks_model_no[$i]) . "<br/>"; echo "size " . clean($system_disks_size[$i]) . "<br/>"; echo "serial_no " . clean($system_disks_serial_no[$i]) . "<br/>"; } //--> MEMORY $system_memory_qty = $_POST['system_memory_qty']; $system_memory_serial_no = $_POST['system_memory_serial_no']; $system_memory_manf = $_POST['system_memory_manf']; $system_memory_part_no = $_POST['system_memory_part_no']; $system_memory_size = $_POST['system_memory_size']; for ($i = 0; $i < count($system_memory_qty); $i++) { echo "qty " . clean($system_memory_qty[$i]) . "<br/>"; echo "serial " . clean($system_memory_serial_no[$i]) . "<br/>"; echo "manf " . clean($system_memory_manf[$i]) . "<br/>"; echo "part_no " . clean($system_memory_part_no[$i]) . "<br/>"; echo "size " . clean($system_memory_size[$i]) . "<br/>"; } This just outputs all the fields I post at the moment. Say I have 3 different disk types, it's going to loop 3 times. Is it possible to make this all into 1 giant query or am I better off doing each query separately? Each section is a different table. I'm missing something here. I have a form, and when the submit is pressed, the relevant post data inserts into table one, then I want the last insert id to insert along with other form data into a second table. The first table's still inserting fine, but I can't get that second one to do anything. It leapfrogs over the query and doesn't give an error. EDIT: I forgot to add an error: I get: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'usage, why VALUES ('14', '', '123', '','1234', '', '')' at line 1 query:INSERT INTO tbl_donar (donar_fname, donar_name, donar_address, donar_address2, donar_city, donar_state, donar_zip, donar_email, donar_phone, donar_fax, donar_company) VALUES ('test 14', 'asdfa', 'asdf', 'adf','asdf', '', '', '', '123', '', '') Code: [Select] if (empty($errors)) { require_once ('dbconnectionfile.php'); $query = "INSERT INTO tbl_donar (donar_fname, donar_name, donar_address, donar_address2, donar_city, donar_state, donar_zip, donar_email, donar_phone, donar_fax, donar_company) VALUES ('$description12', '$sn', '$description4', '$cne','$description5', '$description6', '$description7', '$description8', '$description9', '$description10', '$description11')"; $result = @mysql_query ($query); if ($result) { $who_donated=mysql_insert_id(); $query2 = "INSERT INTO tbl_donation (donor_id, donor_expyear, donor_cvv, donor_cardtype, donor_authorization, amount, usage, why) VALUES ('$who_donated', '$donate2', '$donate3', '$donate4','$donate5', '$donate6', '$donate7')"; $result2 = @mysql_query ($query2); if ($result2) {echo "Info was added to both tables! yay!";} echo "table one filled. Table two was not."; echo $who_donated; //header ("Location: http://www.twigzy.com/add_plant.php?var1=$plant_id"); exit(); } else { echo 'system error. No donation added'; Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Im doing a search system and Im having some problems.
I need to search in two tables (news and pages), I already had sucess doing my search system for just one table, but for two tables its not easy to do.
I already use a select statment with two tables using UNION because I want to show number of search results, that is number of returned rows of my first sql statment.
But now I need to do a select statment that allows me to acess all fields of my news table and all fields of my pages table.
I need to acess in my news table this fields: id, title, content, link, date, nViews
I need to acess in my pages table this fields: id, title, content, link
Im trying to do this also with UNION, but in this case Im not having any row returning.
Do you see what I have wrong in my code?
<?php //first I get my $search keyword $search = $url[1]; $pdo = connecting(); //then I want to show number of returned rows for keyword searched $readALL = $pdo->prepare("SELECT title,content FROM news WHERE title LIKE ? OR content LIKE ? UNION SELECT title,content FROM pages WHERE title LIKE ? OR content like ?"); $readALL->bindValue(1,"%$search%", PDO::PARAM_STR); $readALL->bindValue(2,"%$search%", PDO::PARAM_STR); $readALL->bindValue(3,"%$search%", PDO::PARAM_STR); $readALL->bindValue(4,"%$search%", PDO::PARAM_STR); $readALL->execute(); //I show number of returned rows echo '<p>Your search keyword returned <strong>'.$readALL->rowCount().'</strong> results!</p>'; //If dont return any rows I show a error message if($readALL->rowCount() <=0){ echo 'Sorry but we didnt found any result for your keyword search.'; } else{ //If return rows I want to show, if it is a page result I want to show title and link that I have in my page table //if it is a news result I want to show title and link that I have in my news table and also date of news echo '<ul class="searchlist">'; $readALL2 = $pdo->prepare("SELECT * FROM news WHERE status = ? AND title LIKE ? OR content LIKE ? LIMIT 0,4 UNION SELECT * FROM pages where title LIKE ? OR content LIKE ? LIMIT 0,4"); $readALL2->bindValue(1, '1'); $readALL2->bindValue(2, "%$search%", PDO::PARAM_STR); $readALL2->bindValue(3, "%$search%", PDO::PARAM_STR); $readALL2->bindValue(4, "%$search%", PDO::PARAM_STR); $readALL2->execute(); while ($result = $readALL2->fetch(PDO::FETCH_ASSOC)){ echo '<li>'; echo '<img src="'.BASE.'/uploads/news/'.$result['thumb'].'"/>'; echo '<a href="'.BASE.'/news/'.$result['id_news'].'">'.$result['title'].'</a>'; //if it is a news result I also want to show date on my list //echo '<span id="date">'.$result['date'].'</span>'; echo '</li>'; } echo ' </ul>'; //but how can I do my select statement to have access to my news table fields and my page table fields?? } ?> This portion is kind of stumping me. Basically, I have a two tables in this DB: users and users_access_level (Separated for DB normalization) users: id / username / password / realname / access_level users_access_level: access_level / access_name What I'm trying to do, is echo the data onto an HTML table that displays users.username in one table data and then uses the users.access_level to find users_access_level.access_name and echo into the following table data, I would prefer not to use multiple queries if possible or nested queries. Example row for users: 1234 / tmac / password / tmac / 99 Example row for users_access_level: 99 / Admin Using the examples above, I would want the output to appear as such: Username: Access Name: Tmac Admin I am not 100% sure where to start with this, but I pick up quickly, I just need a nudge in the right direction. The code I attempted to create just shows my lack of knowledge of joining tables, but I'll post it if you want to see that I did at least make an effort to code this myself. Thanks for reading! I am trying to write some data from multiple SQL tables to a page. In the first table is a list of places. I then have more tables that are named after the different places. For example, say my first place in the list is called Place1. I have a table named Place1 with data that corresponds to place1. The data contained in the table named Place1 is a list of things to do in this place. It has 21 columns and each one is something to do in the morning, afternoon, and at night for each day of the week in the place Place1. What I am trying to do is display a sort of weekly calendar as a table on a webpage that lists all of the places in one column and then lists seven days of the week as 7 more columns. Then in each data cell I would want to list the things to do in the morning, afternoon and at night for the certain day of the week and for the place. The problem is that I am creating a CMS to allow other users with no coding knowledge to update events for other places, so I have to display data that could have been altered. The only solution I know of is to do a while loop that gets all of the place names and while there are still place names, write the place names to the page and set a variable equal to the place name. Inside the while loop I would create another while loop that each time the first while loop is executed uses the variable set in the first while loop to know which table to reference and then make a call to that table pulling out the 21 columns and writing them to the page. Each time the outer while loop executes, it would (hopefully) write the place name, and then set the variable as the current place name so that the inner while loop uses the variable to write the rest of the information about that place. I don't know if that would even work and if it did, I know it cannot be the best way to do this. I am pretty stuck here and don't really have a good solution so if anyone proposes a solution that is radically different to anything I have done, I am open to everything. Thank you! Hello, I'm having a bit of a problem here, all help to this issues would be much appreciated I am trying to use text boxes to insert numbers into the database based on what is inputed. If I have a string, like this for example: $variable = 09385493; And I want to insert it into the database like this: mysql_query("INSERT INTO integers(number) VALUES ('$variable')"); When checking the integers table in my database, looking at the number field, the $variable that was inserted is outputted as 9385493 Notice the number zero was taken out of the front of the number. If the number is double 0's (009385493), both of those zero's would disappear, too. Thanks Dear Sir/Madame I am trying to insert comments into a table called comments using echo ID in the input form but so far i can insert the comments with the post id but unable re-comment again kindly help me what do i do?
This is the input form:
<div>
<form action="ehscomment.php" method="post">
<input type="hidden" name="id" value="<?php echo $id ?>">
<div>
<label>Add comment</label>
<div>
<textarea rows="6" cols="110" name="comment" placeholder="comment"></textarea>
</div>
</div>
<input type="submit" name="postcomment" value="comment"></form>
</div>
And this is ehscomment.php
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "registration";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
if(isset($_POST['postcomment'])){
$id = $_POST['id'];
$comment = $_POST['comment'];
$sql = "INSERT INTO comments (id,comment)
VALUES ('$id','$comment')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();}
?>
Error message: Error: INSERT INTO comments (id,comment) VALUES ('242','asddd') I am wondering about the following problem: I have two sessions, one for the user ($_SESSION['user_id']) and second one for the products inside cart ($_SESSION['cart']). I need to insert data into table racun. I did it this way and it works, but i want to know if this can be done better? Code: [Select] while ($row=mysql_fetch_array($query)){ $id = $_SESSION['korisnik_id']; $idp = $row['product_id']; $kol = $_SESSION['cart'][$row['product_id']]['quantity'] ."<br>"; $insert = "INSERT INTO racun (product_id, quantity, korisnik_id) VALUES ('$idp', '$kol', '$id') "; $result = mysql_query($insert); } I get the following message: Quote name4Query failed: Unknown column 'late' in 'field list' with this code. What does it mean? Code: [Select] <?php $apt=$_POST['search_term']; $stat = mysql_connect("localhost","root",""); $stat = mysql_select_db("prerentdb"); $query = "SELECT name FROM payments WHERE late = 'L'"; $stat = @mysql_fetch_assoc(mysql_query($query)); echo $stat["name"]; $name=$_POST['name']; $apt=$_POST['apt']; $amtpaid=$_POST['amtpaid']; $rentdue=$_POST['rentdue']; $prevbal=$_POST['prevbal']; $hudpay=$_POST['hudpay']; $tentpay=$_POST['tentpay']; $datepaid=$_POST['datepaid']; $late=$_POST['late']; $comments=$_POST['comments']; $paidsum=$_POST['paidsum']; $query = " INSERT INTO payhist (name,apt,amtpaid,rentdue,prevbal, hudpay,tentpay,datepaid,late,comments,paidsum) VALUES('$name','$apt','$amtpaid','$rentdue','$prevbal', '$hudpay','$tentpay','$datepaid','$late','$comments','$paidsum')"; $stat = mysql_query($query) or die('Query failed: ' . mysql_error()); mysql_close(); echo "data inserted<br /><br />"; ?> Just a quick question I have a form, couple of drop down boxes, input fields etc.. at the end is the submit button. now my question is should my insert into database sqls go before the submit button inside the form? out side the form? after the button inside the form? If by any chance you could give me some advice on the best way to layout my sql that would be great. They are big and go into three tables, at the moment I have them as three seperate queries but I think they must be able to go into one. can someone please help me with the layout and syntax. here is what the queries look like at the moment: if ($IBselect=$_POST ['IBselect']); { //CUSTOMER $enterCust="INSERT INTO customer(username, password, title, firstName, lastName, address, town, country, postCode, phone, email, dateCust) VALUES ('$_POST[username]', '$_POST[password]', '$_POST[title]', '$_POST[firstName]', '$_POST[lastName]', '$_POST[address]', '$_POST[town]', '$_POST[country]', '$_POST[postCode]', '$_POST[phone]', '$_POST[email]', 'DATE: Auto CURDATE()', CURDATE()"; $enterCust_query=mysql_query($enterCust)or die(mysql_error()); //CARD $enterCard="INSERT INTO card(cardNumber, name, expDate, cardID) VALUES ('$_POST[cardNumber]','$_POST[name]', ' $_POST[expDate]', '$_POST[cardID]')"; $enterCard_query=mysql_query($enterCard); //BOOKING $RCenterBook=mysql_query("INSERT INTO booking (custNumber, cardID, rideName, seatNo1, seatNo2, price, price2, dateBook, ID_time_tbl) VALUES ('$custNumber', '$_POST[cardID]', '$rideName', '$_SESSION[IBextract]', '$_SESSION[IBextract2]', '$IBendPrice1', '$IBendPrice2', 'DATE: Auto CURDATE()', CURDATE()', '$_SESSION[IB_slot_Time]'"); $IBenterBooking_query=mysql_query($IBenterBook); if (!mysql_query($enterCard, $enterCust, $IBenterBook)) { die("Error:" .mysql_error()); } echo "1 record added IB"; } Thanks =) I'm trying to use PDO and get used to doing things this way. I've been away from php/mysql for a few years, so, I'm crusty. I'm not getting any error messages back on this code, but the insert just doesn't happen. My first guess is that I'm doing something wrong with the datetime now() function. But, I may not have the PDO code right. I tried the script the old fashion way with mysql_query() and that worked. So, it has to be something in this code. I believe my server is set up to do PDO as it shows: PDO PDO support enabled PDO drivers mysql, sqlite pdo_mysql PDO Driver for MySQL, client library version 5.0.45 My php version is 5.2.14 and Mysql is 5.0.45. Any help would be appreciated. Code: [Select] $DBH = new PDO("mysql:host=$host;dbname=$dbname", $user, $pass); $DBH->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION ); $sql=$DBH->prepare("INSERT INTO assets(asset_name,date_added,short_desc) VALUES (:asset_name,NOW(),:short_desc)"); $sql->bindParam(':asset_name',$asset_name); $sql->bindParam(':short_desc',$short_desc); $name=$_POST["input1"]; $short_desc=$_POST["input2"]; $DBH->exec(); echo $name; echo "\nPDO::errorInfo():\n"; print_r($DBH->errorInfo()); } catch(PDOException $e) { echo "Syntax Error: ".$e->getMessage(); } hey developers,
i have problem to get last insert id. btw.. i try to put that code on my mvc creation.
on register_model page i write like this:
public function numbering(){ $sth = $this->db->prepare('SELECT * FROM member_data'); $result = $this->db->lastInsertId(); return $result; } and for the controllers page, i write the code like this: $c = $this->model->numbering(); foreach ($c as $key => $value) { $data = $result('id'); } $abc['member_id'] = $data; but i didn't get the results,.. can you help me? Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'like (comment_id, name, like) VALUES ('102','Steven','1')' at line 1 $sql="INSERT INTO like (comment_id, name, like) VALUES ('$_POST[comment_id]','$_POST[name]','$_POST[like]')"; if (!mysql_query($sql,$con)) { die('Error:' . mysql_error()); } echo "You have succesfully liked this comment.<br /><INPUT TYPE=\"button\" VALUE=\"Back\" onClick=\"history.go(-1);\">"; mysql_close($con) Table: comment_id name like For some reason, I cannot spot this error. Can you find it? My $con = mysql_connect is a part I left out but it connects fine! The data form is echo'ing fine but it's not inserting into the MySQL Table. Thanks in Advanced! Hey, who can help? Example: I want to insert a row with a input and a select option. I am inserting now with select option, but i want to insert with a input too, because if i need to insert a link instead of choosing from select option. --------- (puts a link)Link: ...link... (chooses nothing)Select: Choose one... Submit --------- I need something like if LINK is filled insert it. Nothing happens to SELECT, but they have to have the same row names. Hope its clear enough. Cheers |
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