PHP - Problem In Including Session

I'm using xampp and am trying to create a login session...these are the my php files
login.php
Code: [Select]
<form action='login1.php' method='post'>
Email: <input type='text' name='id'></br>
Pass : <input type='password' name='pass'></br>
<input type='submit' name='login' value='login'>
login1.php
Code: [Select]
<?php
$id=$_POST['id'];
$pass=$_POST['pass'];

$conn=mysql_connect("localhost","root","");
if (!$conn)
{
die('Could not connect: ' . mysql_error());
}


$e=mysql_select_db('test', $conn);
if(!$e)
{
die(''.mysql_error());
}
else
{
echo 'database selected successfully';
}

$sql=mysql_query("Select email,password from login where email='$id' AND password='$pass'");
$count=mysql_num_rows($sql);
if($count==1) 
{ 
    session_start();
    
    echo "</br>Login Successful</br>";
echo "Please wait 5 seconds ";
/* redirct to the specified page */
header("refresh:5;url=empty.php");
}
else
{

echo "please try to login again</br>";
echo "you will be redirected to the login page in 5 seconds";
     /* redirct to the specified page */
header("refresh:5;url=login.php");
}
mysql_close();
?>
empty.php
Code: [Select]
<?php
session_start();

$logi=$_SESSION['id'];
echo 'welcome '.$logi;



?>

empty.php is supposed to display the email id from login.php
I checked it about an hour ago and it was working fine but now it gives me an error
Undefined index: id in C:\xampp\htdocs\littleprogress\empty.php on line 4
I didn't change anything after checking it. only cleared the history and cookies of my firefox browser
what could be the problem

Hi,
I"m trying to make an external link to a web page. Them problem is that when my user clicks on the link they are taken to the destination web page, but they see an error "Your session has expired". At that point, they must either refresh the browser or exit out and click again in order to see the page.
My question is, how can I go around this problem in my code? If at all possible, I like to be able to add something to the URL so that this does not happen. Any help or guidance is appreciated.

I have this error, and I cann't find soluiton:
Code: [Select]
Notice: Undefined index: ime in C:\wamp\www\web\login_public.php on line 26

Notice: Undefined index: ime in C:\wamp\www\web\login_public.php on line 27
This is the code:
Code: [Select]
<?php require_once("public/includes/session.php"); ?>
<?php require_once("public/includes/connection.php"); ?>

<?php  

if(!$_POST['submit']){
header('refresh:0; url=index.php');}
else {
$korisnik = $_POST['korisnicko_ime']; 
$lozinka = $_POST['lozinka'];
$lozinka_db = sha1($lozinka);

if ($korisnik && $lozinka){
$query = mysql_query("SELECT * FROM korisnik WHERE korisnicko_ime = '$korisnik' ");
$numrow = mysql_num_rows($query);

if($numrow != 0){

while ($row = mysql_fetch_assoc($query)){
$korisnik_db = $row['korisnicko_ime'];
$db_lozinka = $row['lozinka'];
$ime = $row['ime'];
}
if ($korisnik == $korisnik_db && $lozinka_db == $db_lozinka){
echo "Uspesno ste ulogovani";
$_SESSION['ime'] == $ime;
echo $_SESSION['ime'];
}
else { echo "Lozinka je netacna"; }
} else {die("Korisnik ne postoji");}
}
}

?>
What seems to be the problem 

I'm trying to use a boolean 'true' or 'false' to tell the page that when false, he/she is logged out and send them to loggin page..other wise display the name which is taken from the session....i made the session stuff in a class and i have it as follows:

Code: [Select]
<?php
include("includes/functions.php");

class Session{
    
    public $logged_in = false; // the one i'm on about
    public $key;
    
    // $_session[$key] = $value
    public function set($key, $value){//setting session
$_SESSION[$key] = $value;
if(isset($_SESSION[$key])){
    $this->logged_in = true;
}
    }
    
    public function get($key){ //getting session
if(isset($_SESSION[$key])){
    return $_SESSION[$key];
}
else{
    return false;
}
    }
    
    
    public function confirm_logged_in(){ //check if logged in
        if(!$this->logged_in)
redirect_to("login.php"); // a tailored method
    }
    
    public function logout(){ 
session_start();
session_unset();
session_destroy();
$this->logged_in = false; 
    }
}
$session = new Session();
?>
unfortunately when i set the session on one page (say after login) assuming that the $logged_in variable is now turned to TRUE, but when I go to another page (e.g. Index.php)  and Get the allready set session and perform the test confirm_logged_in() it does the OPPOSITE to what I would expect as for example: redirecting me to login.php even when its "supposed to be"  $logged_in=true as set in the set function above.

any help would be appreciated...suggestions to change syntax or any as such...thanks

For a while now I've been getting intermittent problems with PHP either slowing down or very occasionally timing out for no apparent reason. For the first time it's happened a number of times today and there is an error message in the logs:

PHP Fatal error:  Maximum execution time of 30 seconds exceeded in functions.php on line 4, referer:search.php

The odd thing is that line 4 of functions.php only contains: $sess = session_id();

I've never had a problem with PHP that digging around in this forum hasn't solved but this one has me stumped.

Anyone got any ideas?

TIA

I thought I had somewhat of a mastery of sessions, until I encountered this problem.  Basically, I'm trying to built a session expired code which is a little bit deviated from your everyday session expired codes.  I want the user of a website to be logged out automatically after the session expires, and redirected to the login page.  But I also need that, if any other user tried to access that same website without having previously been logged on, he should be redirected not to the login page but the signup page.  So basically, the same page (index.php) should redirect the user to login.php if he was logged in and his session expired after 1 minute, or signup.php if he wasn't logged in and tried to access home.php.

So what I tried to do to accomplish this was

- Declare two session variables $_SESSION['id'] = "some value from database" and  $_SESSION['logged_in'] = TRUE everytime the user succesfully logs in.

-At the top of index.php, right after session_start(), check to see if 1 minute has elapsed since last activity and if so, unset $_SESSION['logged_in'] without destroying the session.  So presumably, all other session variables including $_SESSION['id'] and the session itself remain intact.

-Right below that, check if $_SESSION['id'] is set.  If not(meaning the session is not active and hence no user was logged in), redirect to signup.php.   If it is set, then check if $_SESSION['logged_in'] is set and if not, redirect to login.php

Now to the code itself


Code: [Select]

<?php


//address error handling

ini_set ('display_errors', 1);
error_reporting (E_ALL & ~E_NOTICE);



//Check if max allowable time has elapsed

if (isset($_SESSION['LAST_ACTIVITY']) && (time() - $_SESSION['LAST_ACTIVITY'] > 60)) {

    // last request was more than 1 minute ago
 
    unset($_SESSION['logged_in']);     // unset logged_in session variable for the runtime


}

$_SESSION['LAST_ACTIVITY'] = time(); // update last activity time stamp



        //Get the current page url to pass on to the session expired page.
$url=urlencode("http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']);


//Check whether the session variable id is present or not

if(!isset($_SESSION['id']) || (trim($_SESSION['id']) == '')) {

 session_destroy();

 header("location: signup.php");

exit();

}else{//If session id is set meaning the session is alive and hasn't been destroyed


if(!isset($_SESSION['logged_in'])){//If this variable is not set, then session must have expired because this is the variable we unset upon sesssion expire. The session is still alive though and we must destroy it

//Redirect to login.php and pass on the page url

$msg = "Your Session Expired Due to Inactivity. Login Below";

session_destroy();


header("location: login.php?url=$url&msg=$msg");


}//End of if logged in is not set


}//End of if session id is set




?>



Well the code works just as i want it to, except for this scenario.  If I login with some user's credentials, and open a new page, by typing in url.com in a new window, this new page doesn't redirect to url.com/signup.php but stays on url.com/index.php and all the session variables are available on this new page just like on the old page that was accessed by actually loging in.  Well that's expected.  The problem is, when the session expires on this page, it gets redirected to url.com/signup.php and not url.com/login.php as expected(note that with the old page that was accessed by actually login in, we do get redirected to url.com/login.php)  Now this bothers me because the website is supposed to be redirected to signup.php only if the user started a fresh session without having been logged in as the logic from the code above shows.  So, the $_SESSION['id'] variable actually exists(and I actually tested it by echoing it)but yet, the code behaves as if it doesn't with every new page.  What could possibly be going on here? I have tried using session_regenerate_id(), but that just keeps the session going without ever expiring.  I tried to use the actual session_id()itself in the place of $_SESSION['id'] but in that scenario, the page always gets redirected to url.com/login.php regardless of whether a user was previously logged in or not.


PS:  I dont think this has anything to do with the problem but worth noting that the url of a page opened after a user logs in is url.com/index.php but that of a page opened after a user is already logged in is simply url.com

I am trying to send some arrays to another page using sessions. The first array I send works fine when I simply print the array on the next page but the second and third arrays are not being created.

Code
Code: [Select]
<?php
 
require("dbconn.php");
$query = mysql_query("SELECT username, idcustomers FROM customers
WHERE username='$customeruser' ");

if (!$query) {
die('Invalid query: ' . mysql_error());}

$row = mysql_fetch_assoc($query);
echo $row['username'];
$id=$row['idcustomers']; 
echo $id;

$productquery = mysql_query("SELECT productid, price1, price2, price3, price1_type, price2_type, price3_type, prod_name, price_det FROM  product_pricing
WHERE idcustomers='" . mysql_real_escape_string($id) . "' ORDER BY productid");

if (!$productquery) {
die('Invalid query: ' . mysql_error());}


$counter = 1;
$itemcode_array = array();
while ($row = mysql_fetch_assoc($productquery)) {



?>
<tr class="ordertable">
<td class="table_item" name="itemcode<?php echo $counter;?>"><?php echo $row['productid']; ?></td><?php $itemcode_send = $row['productid']; array_push($itemcode_array, $itemcode_send); ?>
<td class="table_name" name="prodname<?php echo $counter;?>"><?php echo $row['prod_name']; ?></td><?php $prod_name_send = $row['prod_name']; array_push($prodname_array, $prod_name_send); ?>
<td class="table_pdet" name="prod_det<?php echo $counter;?>"><?php echo $row['price_det']; ?></td><?php $price_det_send = $row['price_det']; array_push($pricedet_array, $price_det_send); ?>
<td class="table_price" name="price1<?php echo $counter;?>"><?php echo $row['price1_type']; ?> $<?php echo $row['price1']; ?></td>
<td class="table_quant" name="quant1"><input type="text" name="quant1<?php echo $counter;?>" size="4" /></td>
<td class="table_price" name="price2<?php echo $counter;?>"><?php echo $row['price2_type']; ?> $<?php echo $row['price2']; ?></td>
<td class="table_quant" name="quant2"><input type="text" name="quant2<?php echo $counter;?>" size="4" /></td>
<td class="table_price" name="price3<?php echo $counter;?>"><?php echo $row['price3_type']; ?> $<?php echo $row['price3']; ?></td>
<td class="table_quant" name="quant3"><input type="text" name="quant2<?php echo $counter;?>" size="4" /></td>
<td class="table_note" name="notes"><input type="text" name="note<?php echo $counter;?>" size="28" /></td>
</tr>

<?php
($counter++);
} ?>
<?php mysql_close($dbConn); ?>

</table>
<p><input type="submit" name="submit" value="Confirm" />&nbsp;<input type="reset" /></p>
</form>


<?php print_r($prodname_array);

$_SESSION["itemcode"] = $itemcode_array;
 $_SESSION["prodname"] = $prodname_array;
 $_SESSION["pricedet"] = $pricedet_array; ?>



There is some redundant and error testing code in there.

The problem is $prodname_array; and $pricedet_array; are not being created even though $itemcode_array which is created the same way works fine. All values from the database are being displayed correctly  (eg $row['prod_name'].

Hi. I have to check if a session is started or not, and then, check for the rank of the user. For that i use two functions like is_administrator,etc.

Well, but this isnt working. I cant get any clear way to know if a session have been already started or not.
Code: [Select]
function is_administrator() {
session_start();
if (isset($_SESSION['usr']) and empty($_SESSION['usr'])) {

$l = conect();
$user = $_SESSION['usr'];
$cons = "SELECT * FROM `users` WHERE usr='" . $user . '\';';
$res = mysql_query ($cons,$l);
$ob = mysql_fetch_array($res);

if ($ob['tipo'] == 'A') {
return true;
}

}
return false;
}

What i want to do is to check if a sesion exist, if not, return false. If the sesion exist, check for the user rank and return true/false.

page.php
<a href="cart.php?action=add&id=38">

cart.php

session_start();
$cart = $_SESSION['cart'];

$action = $_GET['action'];

switch ($action) {
   case 'add':
if ($cart)
   $cart =$cart. ','.$_GET['id'];
   else
      $cart = $_GET['id'];
}


$_SESSION['cart'] = $cart;
echo $cart;
output:
 Insted of one time it adds the id two times.

It prints : 38,38.
can pls suggest me what's problem in the code. Thank's in advance.

i have a login script im using
 if someone landed accidentally on  a page i want him to be redirected and not have access

Code: [Select]
<?php
if (isset($session->logged_in)){

}
else{header("Location: ../index.php");}


?>

which is the best place to put this code :

Code: [Select]
if(isset($_SESSION['last_ip'])===false){
$_SESSION['last_ip']=$_SERVER['REMOTE_ADDR'];
}
if($_SESSION['last_ip']!==$_SERVER['REMOTE_ADDR']){
session_unset();
session_destroy();
}
like this :

Code: [Select]
class session {
public $user_on=false;
public $user_id;

function __construct(){
//make sure that javascript can not access session variable
ini_set('session.cookie_httponly',true);
session_start();
//set the last ip the user has logged on with
if(isset($_SESSION['last_ip'])===false){
$_SESSION['last_ip']=$_SERVER['REMOTE_ADDR'];
}
if($_SESSION['last_ip']!==$_SERVER['REMOTE_ADDR']){
session_unset();
session_destroy();
}
$this->check_login();
}

private function check_login(){
if(isset($_SESSION['user_id'])){
global $user;
$this->user_id=$_SESSION['user_id'];
$this->user_on=true;
$user->find_by_id($this->user_id);
} else {
unset($this->user_id);
$this->user_on=false;
}
}
}
OR :
Code: [Select]
function __construct(){
//make sure that javascript can not access session variable
ini_set('session.cookie_httponly',true);
session_start();
$this->check_login();
}

private function check_login(){
if(isset($_SESSION['user_id'])){
global $user;
                        [b]//set the last ip the user has logged on with
if(isset($_SESSION['last_ip'])===false){
$_SESSION['last_ip']=$_SERVER['REMOTE_ADDR'];
}
if($_SESSION['last_ip']!==$_SERVER['REMOTE_ADDR']){
session_unset();
session_destroy();
}[/b]
                elseif($_SESSION['last_ip']===$_SERVER['REMOTE_ADDR']){
$this->user_id=$_SESSION['user_id'];
$this->user_on=true;
$user->find_by_id($this->user_id);
                 }
} else {
unset($this->user_id);
$this->user_on=false;
}
}
}

Hi,
I my first problem is hashing passwords to md5.
My second problem is defining session on value from db.
There is my code but not working.
Code: [Select]
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

 
$username=$_POST['username'];
$password=$_POST['password'];
$hash = md5($password);


$username = stripslashes($username);
$password = stripslashes($password);
$username = mysql_real_escape_string($username);
$password = mysql_real_escape_string($password);

$sql="SELECT * FROM $tbl_name WHERE where username = '$username' and password = '$hash'";
$result=mysql_query($sql);

$count=mysql_num_rows($result);

if($count==1){
$sql2="SELECT access FROM $tbl_name WHERE username='$username' and password='$password'";
$access=mysql_query("$sql2");
session_register("username");
session_register("password");
session_register("access");
$_SESSION["access"]=$access;
header("location:success.php");
}
else {
echo "Invalid Username or Password";Thanks for any answers.

I am having probelm in saving Session variables ALthough I'm writing session_start();
in the header of my php script and saving the values of Session array in the next page. It does not print the values or show right results.

Code: [Select]
session_start();
require_once ("functions.php");

$token=$_GET['t'];
if(!isset($token)){
 
$name = stripslashes($_POST['username']);
$email = stripslashes($_POST['email']);

check_validate_input($name, $email);
}
if($token=='register')
{
show_registration_form();
}
  $my_model = new model();
  $arr_info = $my_model->check_members($name,$email);
 
   if (($arr_info==NULL)&&($token!='register'))
    {   
    echo '<p> Hello Guest</p><br />';
       show_mailing_form();
    }
   
  else if (($arr_info['role']=='user')||($arr_info['role'] == 'admin'))
    {
         $_SESSION['userId']=$arr_info['id'];
         $_SESSION['user_role']=$arr_info['role'];
         $_SESSION['user_name']=$arr_info['name'];
        print_r  ($_SESSION);}
here it does not print session array.

Hello,

I have the $_session code working, but after I destroy the session and I am asked to log in again, my browser doesn't ask me for my password and just logs me in.

I don't understand because I have destroyed my session and I have deleted the data in $_SESSION and I have deleted the info in the cookie so it shouldn't log me in automatically. I thought it was something in my browser, but I erased my history and I never saved any password.

Here's my code:

This is the welcome page

<?php
    require_once 'login.php';
    $connection = new mysqli($db_hostname, $db_username, $db_password, $db_database);
    
    if ($connection->connect_error) die($connection->connect_error);
    
    if (isset($_SERVER['PHP_AUTH_USER']) && isset($_SERVER['PHP_AUTH_PW']))
    {
        $un_temp = mysql_entities_fix_string($connection, $_SERVER['PHP_AUTH_USER']);
        $pw_temp = mysql_entities_fix_string($connection, $_SERVER['PHP_AUTH_PW']);
        
        $query = "SELECT * FROM users WHERE username='$un_temp'";
        $result = $connection->query($query);
        
        if (!$result) die($connection->error);
        elseif ($result->num_rows)
        {
            $row = $result->fetch_array(MYSQLI_NUM);
            
            $result->close();
            
            $salt1 = "qm&h*";
            $salt2 = "pg!@";
            
            $token = hash('ripemd128', "$salt1$pw_temp$salt2");
            
            if ($token == $row[3])
            {
                session_start();
                $_SESSION['username'] = $un_temp;
                $_SESSION['password'] = $pw_temp;
                $_SESSION['forename'] = $row[0];
                $_SESSION['surname'] = $row[1];
                
                echo "$row[0] $row[1] : Hi $row[0], you are now logged in as '$row[2]'";
                
                die("<p><a href=continue.php>Click here to continue</a></p>");
            }
            else die("Invalid username/password combination");
        }
        else die("Invalid username/password combination");
    }
    else
    {
        header('WWW-Authenticate: Basic realm="Restricted Section"');
        header('HTTP/1.0 401 Unauthorized');
        die("Please enter your username and password");
    }
    $connection->close();
        
    function mysql_entities_fix_string($connection, $string)
    {
        return htmlentities(mysql_fix_string($connection, $string));
    }
        
    function mysql_fix_string($connection, $string)
    {
        if (get_magic_quotes_gpc()) $string = stripslashes($string);
        return $connection->real_escape_string($string);
    }
?>

and this is the other page:

<?php
    session_start();
    
    if(isset($_SESSION['username']))
    {
        $username = $_SESSION['username'];
        $password = $_SESSION['password'];
        $forename = $_SESSION['forename'];
        $surname = $_SESSION['surname'];
        
        destroy_session_and_data();
        
        echo "Welcome back $forename. <br>
            Your full name is $forename $surname.<br>
            Your username is '$username'
            and your password is '$password'.";
    }
    
    else echo "Please <a href='authenticate2.php'>Click here</a> to log in.";
    
    function destroy_session_and_data()
    {
        $_SESSION = array();
        setcookie(session_name(), '', time() - 2592000,'/');
        session_destroy();
    }
?>

 

When I type the website in i first get prompt to enter my password, when I am authenticated the webpage says: You are now logged in click here to continue. When I do I am directed to another page which confirms that I am still logged in. Then I press refresh and the webpage asks me to "Click here to log in". I do, but it doesn't ask me for my password again. Why? My personal info should be destroyed.

Thank you for responding. It's greatly appreciated