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PHP - Html Button To Pass Variable Content
Hello World,
I need some tips on how to make a button that does something like the code below. .......echo '<tr><td align="left"><a href="add_cart.php?pid=' . $row1['item_id'] . '">Add to Cart</a></td>........ I've been messing with html form and button type with no success. This code does the job but I prefer a button. Thanks Similar TutorialsI have a page that contains a List box containing a list of categories taken from a mysql database, 4 iframe elements and 4 submit button (code to follow)
When an item is selected from the List box the onchange event submits the page to jobs.php and loads it into the joblist iframe. Once the iframe is loaded and visible it makes the "Add Job To Category" submit button visible. This all works great
When I click the "Add Job To Category" Submit button it loads Jobnew.php into the jobed iframe this is working but I can not seem to figure out how to pass the selected item from the List box using this submit button
I hope I am clear in my question if not please advise any help is very much appreciated....
Jobtask.php
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Job Configuration</title>
<head>
</head>
<body>
<div style="position:absolute;left:5px;top:0px;width:1345px;height:50px;z-index:0;">
<img src="images/img0001.png" id="Shape1" alt="" style="border-width:0;width:1345px;height:50px;"></div>
<span style='position:fixed;left:525px;top:8px;font-family:Arial;font-size:32px;width:275px;'>Job Configuration</span>
<form action='index.html' target='' method='post'>
<div style="position:absolute;left:205px;top:55px;width:1345px;height:50px;z-index:0;">
<Input type="submit" action="index.html" Target="_top" method='post'Value="Main Menu">
</div>
</form>
<form style=position:fixed;left:200px;top:82px;>
<iframe name='joblist' id='joblist' style=position:fixed;left:200px;top:px;visibility:hidden;z-index:10 src='' height="475" width="1150" scrolling='yes' frameBorder='0' ></iframe>
<iframe name='job' id='job' style=absolute:fixed;left:200px;top:0px;visibility:hidden;z-index:0 src='' height="475" width="1150" scrolling='yes' frameBorder='0' ></iframe>
<iframe name='jobed' id='jobed' style=position:fixed;left:460px;top:150px;visibility:hidden;z-index:10 src='' height="217" width="350" scrolling='no' frameBorder='0' ></iframe>
<iframe name='newcat' id='newcat' style=position:fixed;left:460px;top:150px;visibility:hidden;z-index:10 src='' height="125" width="350" scrolling='no' frameBorder='0' ></iframe>
</form>
<?php
error_reporting(E_ALL);
include('dbcon/dbconnect.php');
$con=mysqli_connect($host,$user,$password,$db);
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
if (isset($_POST['id'])) {
$insql= "INSERT INTO catagory (Catagory) VALUES ('$_REQUEST[newcat]')";
$con->query($insql);
}
$Catresult = mysqli_query($con, "SELECT CatID, Catagory FROM catagory");
echo "<div id='wb_CatSel' style='position:absolute;z-index:0;text-align:center;'bgcolor='#00b0e6';>";
echo "<span style='position:fixed;left:10px;top:82px;font-family:Arial;font-size:15px;background-color:#00b0e6;width:175px;'>Select Category</span></div>";
echo "<form action='jobs.php' target='joblist' style='position:fixed;left:10px;top:101px;'></td>";
echo "<select name='cat' size='11' style='width: 175px;' onchange='this.form.submit()'>";
while($row = mysqli_fetch_array($Catresult))
{
echo "<option value=\"".$row['CatID']."\">".$row['Catagory']."</option>\n ";
}
echo "</select>";
echo "</form>";
echo "<form action='Jobnew.php' target='jobed' method='post'>";
echo "<div style='position:absolute;left:10px;top:285px;width:1345px;height:50px;z-index:0;'>";
echo "<Input type='hidden' id='id1'><Input type='submit' id='sbtn' style='width:175px;visibility:hidden;' Value='Add Job To Category'></div></form>";
echo "<form action='Jobtask.php' target='' method='post'>";
echo "<div style='position:absolute;left:10px;top:310px;width:1345px;height:50px;z-index:0;'>";
echo "<Input type='submit' style='width:175px;' action='Jobtask.php' Target='_top' method='post' Value='Reset Form'></div></form>";
echo "<form action='newcat.php' target='newcat' method='post'>";
echo "<div style='position:absolute;left:10px;top:335px;width:1345px;height:50px;z-index:0;''>";
echo "<Input type='submit' style='width:175px;'' action='newcat.php' Target='newcat' method='post' Value='Add New Category'></div></form>";
?>
</body>
</html>
I know this is 'old stuff', but I am new to this and very frustrated- I am trying to pass a variable to a new url via an html onclick event, and failing. I have found several posts about it but the code posted in those posts does not work when I try it. I have struggled mightly with this. Here is my code: first an echo of two versions of the onclick statement, and two versions of the actual button code. The echos from the two versions appear identical, but the first button with no variable works while the second using a variable results in no action. Can anyone point me in the direction of a solution? I suspect there is some simple principal I am missing relating to parsing strings. <?php echo "window.location.href='ManageTitles.php?dog=2'"; echo "\n" ; echo "window.location.href='ManageTitles.php?dog={$row_rsDogsowned['idDogInfo']}'"; ?> <form methd="POST" Name="form3" action="<?php echo $editFormAction; ?>"> <input type="button" value="works" onclick="window.location.href='ManageTitles.php?dog=2'" /> <input type=button onclick="window.location.href='ManageTitles.php?dog={$row_rsDogsowned['idDogInfo']}'" value="fails" /> </form Hi guys, I need your help, I have got a problem with the if statement. When I don't insert the pass function in the url like this: Code: [Select] http://www.mysite.com/myscript.php?image=myimagelocation&strings=mystrings&user=test I will get this on my php page: Code: [Select] PASSWORD are missing Code: [Select] <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'mydbusername'); define('DB_PASSWORD', 'mydbpass'); define('DB_DATABASE', 'mydbname'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($var){ return mysql_real_escape_string(strip_tags($var)); } $image = clean($_GET['image']); $strings = clean($_GET['strings']); $username = clean($_GET['user']); $pass = clean($_GET['pass']); if($username == '' && $pass) { $errmsg_arr[] = 'username are missing'; $errflag = true; }elseif($username && $pass =='') { $errmsg_arr[] = 'PASSWORD are missing'; $errflag = true; } if($username == '' && $pass == '') { $errmsg_arr[] = 'username or password missing'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; echo implode('<br />',$errmsg_arr); } else { $insert = array(); if(isset($_GET['image'])) { $insert[] = 'image = \'' . clean($_GET['image']) . '\''; } if(isset($_GET['strings'])) { $insert[] = 'strings = \'' . clean($_GET['strings']) . '\''; } if(isset($_GET['user'])) { $insert[] = 'user = \'' . clean($_GET['user']) .'\''; } if(isset($_GET['pass'])) { $insert[] = 'pass = \'' . clean($_GET['pass']) . '\''; } if (count($insert)>0) { $names = implode(',',$insert); $required_fields = array('image', 'strings', 'user'); if($image && $strings && $username) { echo "working 1"; } elseif($username && $pass) { echo "working 2"; } } } ?> Do anyone know how to fix this? so I need some help passing these variable from this page to final.php. how do I pass these arrays? I know if it were singled....not arrayed, I could use hidden fields in a form and echo them out....but these are multiples....not singled. The form way is prefered.....but it doesn't have to be. I just need these passed to the page where I am going to process them. I am not good at working with arrays. Thanks in advance Code: [Select] <?php include_once("connect.php"); session_start(); foreach($_POST["product"] AS $key => $val) { $product = $val; $month = $_POST['month'][$key]; $day = $_POST['day'][$key]; $year = $_POST['year'][$key]; $date = $_POST['date'][$key]; $price = $_POST['price'][$key]; $qty = $_POST['qty'][$key]; $id = $_POST['id'][$key]; $total = $_POST['total'][$key]; $academy = $_POST['academy'][$key]; $priceunit = $price * $qty; } ?> Hello
I'm using a form to collect user data (is a Cognito form) it is displayed on vacation rental properties pages, so it collects user´s email, in date, out date, etc. in the cognito form I have one text hidden field called REF, I wonder how to do in order to use the same form and be able to identify where the info comes from. I thougt that if I could put the page url into the REF variable, the problem would be solved, but I'm not sure if that is possible and how to do it. It is? If not: is it possible to handle that ? I have researched all over forums from past day. Not getting correct solution. I have 2 textboxes and a button. First box is to enter value and i will click button, i need to get the value.
Here is the code, that works without input box 1
In this code i want to modify my web address, at the end after ky= i want add my first textbox value, then click event and output in second textbox, let me know where i messed.
<script type="text/javascript">
function Assign()
{
<?php
$html = file_get_contents("http://geoportaal.maaamet.ee/url/xgis-ky.php?ky=79401:006:0812" );
preg_match_all('(<li.*?>.*?</li>)', $html, $matches);
$one=$matches[0][0];
?>
document.getElementById("OutputField").value = "<?=$one?>";
}
</script>
<input id="InputField" type="text" style="width:200px"/>
<input type="submit" value="Assign Value" onclick="Assign()"/>
<input id="OutputField" type="text" style="width:200px"/>
Hi, I will start off trying to explain what I am trying to make the best I can. What I want to create is a script that gets the gold value from this website: http://www.lbma.org.uk/pages/index.cfm?page_id=46&title=current_statistics and then save it to a variable which I will use to calculate values of different gold karats. Here is the content in bold I need on the website I linked: Quote LONDON GOLD FIXING USD GBP EUR AM 1588.00 1005.127 1251.083 PM 1589.50 1004.741 1249.803 So what help do I need? Well, I don't expect you to figure out the calculating part for me but some help how to get that content pointed out above and save it to a variable is what I would appreciate getting some help with. I don't know much PHP, only some and I have been trying to figure this out for a day now without any success. I suppose php get contents and/or curl should be used here but I don't know how really. I would very much appreciate the help I can get on this. Thank you! Hello! I've got an issue! I'm trying to pass a very very long variable from JS to PHP through $_GET, but it seems too long for get. Is there any encryption function that works on both JS and PHP, so I can encrypt it in JS, send it though GET and decrypt it in PHP? Thanks ! Hi, I have this script, it all works fine apart from when I pass the variable on, it only passes the first word and not the whole variable The form that actions to the samples page passes the $siteName as My Test Site, if I type echo $siteName in the sameples page, it will print My Test Site, however when I use this Code: [Select] createSample&siteName=$siteName to pass the variable to the next page, it just echos 'My' instead of My Test Site. Even when I scroll over the link above it just shows My in the url. Code: [Select] case "samples": // Get submitted data and assign to variables $siteName = $_POST['siteName']; $adminEmail = $_POST['adminEmail']; $sendmailLoc = $_POST['sendmailLoc']; $imgdir = $_POST['imgdir']; $imgdirbase = $_POST['imgdirbase']; // Write variable data to text file $FileName = "data/server.txt"; $FileHandle = fopen($FileName, 'w') or die("can't open file"); $data = "<?php\n\$siteName = '$siteName';\n?>"; fwrite($FileHandle, $data); $data = "<?php\n\$adminEmail = '$adminEmail';\n?>"; fwrite($FileHandle, $data); $data = "<?php\n\$sendmailLoc = '$sendmailLoc';\n?>"; fwrite($FileHandle, $data); $data = "<?php\n\$imgdir = '$imgdir';\n?>"; fwrite($FileHandle, $data); $data = "<?php\n\$imgdirbase = '$imgdirbase';\n?>"; fwrite($FileHandle, $data); fclose($FileHandle); // Displays the create sample pages page ECHO <<<SAMPLES <table border=0 align=center bgcolor=#00CCFF> <tr> <td><span class=style1><b><center>Create Sample Pages</center></b></span></td> </tr> <tr> <td>Would you like Member Site Maker to create sample pages for: <ul> <li>index.html</li> <li>login.html</li> <li>search.html</li> <li>register.html</li> </ul> </td> </tr> <tr> <td><a href=installation.php?cmd=createSample&siteName=$siteName>Yes</a> </td> <td><a href=installation.php?cmd=mysql>No</a> </td> </tr> </table> SAMPLES; break; Can anybody tell me where I am going wrong please? Thanks Hi guys, I have a trouble with my php snippet, when I insert the var function in the url bar something is like: http://www.mysite.com/delete.php?favorites&id=0 or http://www.mysite.com/delete.php?whateveritis&id=0 It doesn't get pass the favorites function to delete the id. It is the same things that it goes for each different function. Here's the current code: <?php Code: [Select] session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'mydbuser'); define('DB_PASSWORD', 'mydbpass'); define('DB_DATABASE', 'mydbtablename'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($var){ return mysql_real_escape_string(strip_tags($var)); } $favorites = clean($_GET['favorites']); $id = clean($_GET['id']); if($favorites && $id == ''){ // both are empty $errmsg_arr[] = 'favorites id are missing.'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; echo implode('<br />',$errmsg_arr); } else { $insert = array(); if(isset($_GET['id'])) { $insert[] = 'id = \'' . clean($_GET['id']) .'\''; } if(isset($_GET['favorites'])) { $insert[] = 'favorites = \'' . clean($_GET['favorites']) . '\''; } if($favorites && $id) { mysql_query("DELETE FROM favorites WHERE id='$id'"); $deleted = mysql_affected_rows(); if($deleted > 0) { echo "favorites channels is deleted"; } else { echo("favorites is already deleted"); } } } ?> If you do know how to get pass the favorites function, then please say so as i need your help. Any advice would be much appreicated. Hi All, I have a function that i want to pass a variable into so that i can do some SQL on it. The information that i want to pass into it is a data-id on a button that is used to trigger the function. The button that will be clicked is this <div class='modaltrigger btn btn-primary' data-id='$itemId' data-toggle='modal'>Manage</div> This button is being created by another function. I would like to know either how i pass the variable from one function to another or how i pass it from the data-id to the function in php. Thanks in advance. Can someone explain to me how this is done? Here's my search form: <form action="search" method="get" enctype="multipart/form-data"> <input type="text" name="string" maxlength="100" /><br /><br /> <input type="submit" value="Search" /> </form> When I submit it, the URL is search.php?string=Bleh What I would like is for the URL to be search/string/Bleh I'm already doing this with some other variables, like search/tag/Bleh and search/author/Bleh, instead of search.php?tag=Bleh and search.php?author=Bleh. However, those ones are passed via a link, not a form. Any ideas? You guys are great, thanks again for the help last week. Now I almost got this working but a small hiccup. here is my code: Code: [Select] <?php include("config.php"); $my_t=getdate(date("U")); $my_t1=$my_t[weekday]; $result = mysql_query("SELECT * FROM tourney where day_of_week = '$my_t1'") or die(mysql_error()); if ($result == '') echo "<br>Empty Set\n"; print_r ($my_t1); This prints correctly Code: [Select] while ($result = mysql_fetch_array($result,MYSQL_ASSOC)) { This is my error. "Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /hermes/bosweb/web017/b172/ipg.dswdesignsnet/pp4c/charity1.php on line 8" Code: [Select] print "<b>Starting Time: <br></b>".$row{'start_time'}."<br><b>Tournament: </b><br>".$row{'tourney'}."<br><b>Buy-in: <br>".$row{'buy_in'}."<br><b>Starting Chips: <br>".$row{'start_chips'}."</font><p>"; This prints headers correctly, but no variables. Code: [Select] } mysql_close($dbh); ?> What did I forget to do or what did I do wrong. I'm still learning mysql and php. I have a table that has 5 columns Quote player_id fname lname team I'm trying to get all the values from that table using this sql command Code: [Select] include_once('../database_connection.php'); $player_id = addslashes($_REQUEST['edit_player']); $sql_query = "Select * from nba_info where player_id = '$player_id'"; $result = MYSQL_QUERY($sql_query); "edit_player" above is came from a different page. They I'm fetching the data using while Code: [Select] while($row = mysql_fetch_array($result)) { $row['player_id']; $row['fname']; $row['lname']; $row['team']; $row['email']; } Then I'm trying to pass that values to a variable here Code: [Select] $id = $row['player_id']; $fname = $row['fname']; $fname = $row['lname']; $lname = $row['team']; $email = $row['email']; When I'm trying to put that variables in a textbox value, they are not showing up Here Code: [Select] <table> <form name="edit_player_form" method="post" action=""> <tr> <td>Players ID</td> <td><input type="text" name="playerid" size="20" value="<?php echo $id; ?>" /></td> </tr> <tr> <td>First Name</td> <td><input type="text" name="fname" size="20" value="<?php echo $fname; ?>" /></td> </tr> <tr> <td>Last Name</td> <td><input type="text" name="lname" size="20" value="<?php echo $lname; ?>" /></td> </tr> <tr> <td>Team</td> <td><input type="text" name="team" size="20" value="<?php echo $team; ?>" /></td> </tr> <tr> <td>Email</td> <td><input type="text" name="email" size="20" value="<?php echo $email; ?>" /></td> </tr> <tr> <td><div align="center"> <input type="submit" name="Submit" value="Edit This Player"> </div></td> </tr> </form> </table> I wonder why it ain't showing up on the textbox value? tried almost everything... Anyone? Hi, Im trying to pass a variable ($in_this_instance) into, and then back out of a function. The variable goes into the function no problem, and is echo'ed out fine. However the echo after the close of the function, does not give anything out. Code: [Select] $in_this_instance = 'boo'; function in_this_instance($data) { global $in_this_instance; echo $in_this_instance; $in_this_instance = 'hoo'; $rep_val = '[front banner]'; $test = strpos($data, $rep_val); if ($test === false) { return $data; } else { return $data;; } } add_filter('the_content', 'in_this_instance'); echo $in_this_instance; Could any one give me a pointer please? Many Thanks! When i execute the following code, it works and retrieves the record info i am looking for for the appropriate record, 2155015898: $adgrouppass = 2155015898; $selector->adGroupIds = array($adgrouppass); However, when i try to get the adgroup variable from my url, which is where it is located, it doesn't work: $adgroup = trim($_GET['adgroup']); $adgrouppass = $adgroup; $selector->adGroupIds = array($adgrouppass); yet, in trying to fix it, if i echo the above variable, it says it is correct, which is 2155015898. Not sure if the $adgrouppass needs to be a string or variable to get it to pass it correctly. Can anyone help? I am passing the variable $searchno from form1.html using <form action="display1.php" method="post" Display1.php reads my database and displays the data. Now I want to link from the displayed page to display2.php and pass and capture the same variable $searchno. How do I do that? i have to pass a variable to so many pages i mean variable post from index.html to page1.php and it has to pass to other pages like page2.php, page3.php and so on, i tried session_start() but i am getting the below error so please tell me how it is possible to Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by and Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent i knw dis mst a simple question but how to pass variable to other page for eg i hav created a page where user submits username n telephone then via sms some random number goes to user mobile ...i want this random number variable in other page dis is my code for startreg.php <form action="startregprocess.php" method="post"> username:<input type="text" name="username"> telephone<input type="text" name="telephone" <input type="submit" name="submit"> </form> <?php srand ((double) microtime( )*1000000); $random_number = rand( ); echo $random_number; ?> i want tht $random_number in other page called startregprocess.php |
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