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PHP - Changing From Minus To Plus
Hi all
I have a string called $voucher_code which is a value used to deduct or add value to a shopping cart. If the value is a minus I need it to show the minus sign, or if it's a plus value, it needs to show a plus sign. Here's my code: <strong>£ -".number_format(($voucher_code),2)."</strong> How do I modify the above code to show + instead of -- which it does at the moment? Many thanks for your help Pete Similar TutorialsHi Can someone point me in the right direction. I can force php to put a Plus(+) sign in front of positive numbers with printf('%0+4.2f',$x) But I cant get this to work inside <option>printf('%0+4.2f',$x)</option> tags Any help is greatly appreciated. Hi I'm using SimpleXMLElement to work with a supplied XML file, problem is with the way the XML document is formatted. The document uses '-' (minus) in the element names instead of _ so when I go to read the values, nothing is returned: Code: [Select] $developer->developer-region; //returns nothing However if I change the sample XML document that I've been supplied to <developer_region></developer_region> and do Code: [Select] $developer->developer_region; //returns child elements This is not practical to manually change the document, is there a way to use '-' in the xml document? Thanks in advance Ste hi , i want to select qty from master where id=$id , then i want to minus the qty = qty -1 and update in the query . here is my code . can tell me what went wrong ? Code: [Select] $query= "SELECT qty FROM master where id=$id"; $result = mysql_query($query,$dblink); while($myrow = mysql_fetch_row($result)) { qty -= 1; $query = "UPDATE master SET qty='$qty' WHERE id= $id"; $result = mysql_query($query,$dblink); } thanks Hi all I'm building a script which reads a XML document, and so far so good... until now! the document uses '-' extensively all the way through it (not something that I would have chosen) so to combat this I've used {}. The part of the document I am working on now, this simply does not work, and I really cannot see why... XML Code: [Select] <plot> <name-number>87</name-number> <price>183000</price> <bedrooms>4</bedrooms> <status>available</status> <summary>With three double bedrooms, including one en suite and a further bedroom plus family bathroom to the first floor,&nbsp;separate lounge and&nbsp;dining room with kitchen&nbsp;and utility to the ground floor, the Otter is a modern home with a great deal to offer growing families.</summary> <feature>Separate lounge and dining room</feature> <feature>Kitchen with utility room</feature> <feature>Integral garage</feature> <feature>En suite to master bedroom</feature> <property-type>detached-house</property-type> <media> <caption> </caption> <type>image</type> <filename>1855_Otter-WhitehirstGrange.jpg</filename> <indexno>1</indexno> </media> <media> <caption> </caption> <type>floorplan</type> <filename>1386_Otter-WhitehirstGrange.pdf</filename> <indexno>2</indexno> </media> <media> <caption> </caption> <type>brochure</type> <filename>284_brochure.pdf</filename> <indexno>3</indexno> </media> <style-name>Otter</style-name> </plot> PHP Code: [Select] echo $plot->{name-number}; // echoes nothing, should echo 87 echo $plot->price; // echoes 183000 echo $plot->bedrooms // echoes 4 echo $plot->{style-name} // echoes nothing, should echo Otter This is frustrating the hell out of me, and I cannot see why this would work everywhere else in the XML document but not here. Any ideas or help would be received with gratitude! Hi, I'm having trouble with this: Code: [Select] $date = date('d/m/y') ; echo $date; echo "<br/>"; $date1 = strtotime('date -1 month'); echo date('Y-m-d', $date1); My result looks like this: Current Date: 19/05/11 Date minus 1 month: 1970-01-01 I want it to look like this: Current Date: 19/05/11 Date minus 1 month: 2011-04-19 Hey guys, Was wondering if someone could point me on the right path here. I am able to get the page URL using: $url = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI']; But was wondering if there was a way to drop the PHP variables attached to the URL. e.g. mysite.com/catalogue/?item=23 becomes mysite.com/catalogue/ Can anyone help me out? Thanks! Hello, I've been struggling for days on this problem now. And I'm getting frustrated! I know that the answer is simple, and I've done it before but I cannot figure out what I'm doing wrong. What do I want? Well, I get a date from the database in this format: YYYY-MM-DD. I first want to distract one month from that and then set in into this form: YYYY, MM, DD. I've got this but it's not working (I've tried a lot different values). $transformdate = date("Y-m-d", strtotime("-1 month", $d_datevalue)); $startpoint = str_replace("-", ", ", $transformdate); Thanks, NLCJ Hi, I am a beginner with php and I am having a hard time understanding a section in my code. The part I dont get is why we have to minus 1 from the number being passed into the array. For example, $FaceNamePlural[$die1-1] I tried looking at it over and over but I'm still very confused. Can anyone help me on this...Thanks. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Untitled Document</title> </head> <body> <?php $FaceNameSingular = array("one", "two", "three", "four", "five", "six"); $FaceNamePlural = array("ones", "twos", "threes", "fours", "fives", "sixs"); function CheckForDoubles($die1, $die2) { global $FaceNameSingular; global $FaceNamePlural; if($die1 == $die2) // doubles echo "The roll was double ", $FaceNamePlural[$die1-1], "<br />"; if($die1 != $die2) //not doubles echo "The roll was a ", $FaceNameSingular[$die1-1], " and a ", $FaceNameSingular[$die2-1], ".<br />"; } function DisplayScoreText($Score) { if($Score == 2) echo "you roll snake eyes! <br />"; if($Score == 3) echo "you roll loose duece! <br />"; if($Score == 5) echo "you roll fever five! <br />"; if($Score == 7) echo "you roll natural! <br />"; if($Score == 9) echo "you roll nina! <br />"; if($Score == 11) echo "you roll yo! <br />"; if($Score == 12) echo "you roll boxcars! <br />"; } $dice = array(); $dice[0] = rand(1,6); $dice[1] = rand(1,6); $Score = $dice[0] + $dice[1] ; echo "<p>"; echo "The total score for the roll was $Score . <br />"; CheckForDoubles($dice[0],$dice[1]); DisplayScoreText($Score); echo "</p>"; ?> </body> </html> I insert a time value using the following code
$ti= ( !empty($_POST['time']) ) ? "'{$_POST['time']}'" : 'NULL';
I want to insert a second time value into a differen column which would be the same time minus 1 hour
something along the lines of :
$ti2= ( !empty($_POST['time']) ) ? "'{$_POST['time'] -1 hour}'" : 'NULL';
What would be the correct way to do it
Hello $row[longdescription] contains a description of a product (complete with HTML mark-up). I would like to display the first 250 characters in the results of a search. I would also like to remove any images that may crop up. This is what I have so far... Code: [Select] echo strip_tags(html_entity_decode(substr(preg_replace('/<img[^>]*>/Ui', '', $row[longdescription]), 0, 250))); The thing is (as you guys can probably already see), it also counts the HTML mark-up as characters and I get very different outputs (especially if an image occurs). I'd appreciate if you could advise me as to the correct way of doing this. Thank you As I am VERY new to PDO, can someone help me in converting the below 2 codes so that I can setup the testing site knowing at least this part works. Below is the old SQL that I need to convert but don't have to foggiest on where to start. If I can get some help with this I can slowly work through the rest of my site with a bit more ease. LOGIN CODE:
<?php
if($_POST['submit']){
$Username = protect($_POST['Username']);
$Password = protect(sha1($_POST['Password']));
if(!$Username || !$Password){
echo "<center>Please enter your <b>Username</b> and <b>Password</b>!</center>";
}else{
$res = mysql_query("SELECT * FROM `eusers` WHERE `Username` = '".$Username."'");
$num = mysql_num_rows($res);
if($num == 0){
echo "<center>The <b>Username</b> or <b>Password</b> you supplied is incorrect!</center>";
}else{
$res = mysql_query("SELECT * FROM `eusers` WHERE `Username` = '".$Username."' AND Password = '".$Password."'");
$num = mysql_num_rows($res);
if($num == 0){
echo "<center>The <b>Password</b> you supplied is incorrect!</center>";
}else{
$row = mysql_fetch_assoc($res);
if($row['Active'] != 1){
echo "<center>Your login has been <b>deactivated</b>, Please contact your Manager for assistance.</center>";
}else{
header('Location: secure.php');
$time = date('U')+7200; //2 Hours
mysql_query("UPDATE `eusers` SET `Online` = '".$time."' WHERE `id` = '".$_SESSION['uid']."'");
$_SESSION['uid'] = $row['id'];
}}}}}
?>
ACCESS GRANTED (Each Page):
<?php
if(strcmp($_SESSION['uid'],"") == 0){
printf("<script>location.href='index.php'</script>");
}else{
$time = date('U')+7200; //2 Hours
$update = mysql_query("UPDATE `eusers` SET `Online` = '".$time."' WHERE `id` = '".$_SESSION['uid']."'");
}
?>
Hi, I am changing my ISP and need to import my databases.
Do I I have to create a new datarbase or can I change my database name to import?
My new host has a different database prefix ie: -web147xxxxxxxx
My old one was arewene1_wor1.
Many thanks.
Salting passwords... How can you update the salting without getting all the users to change their password? Is the salting set in stone once created? Hi, I have a second website under the same domain www.lucyeleanorbrown.com/weddings.html which I wanted to change to www.weddings.lucyeleanorbrown.com, I have been looking around for PHP for this but am unsure of what to search for, could anyone give me a suggestion? Thank you okay i need help with this part of code i need to set time 00:00 to 24:00 Code: [Select] $vrijeme_otvoreno = "$rv_od_h:$rv_od_min"; $vrijeme_zatvoreno = "$rv_do_h:$rv_do_min"; if ($vrijeme_otvoreno =="00:00" && $vrijeme_zatvoreno == "00:00") { $vrijme_zatvoreno = "24:00"; echo $vrijeme_zatvoreno; } echo "$vrijeme_otvoreno - $vrijeme_zatvoreno <br>"; i get echo 00:00 - 00:00 and i need it to be 00:00 - 24:00 hello guys i have a project with Georgian calendar but when i contact to the developer they tell me we not support any other calendar so you must do this alone or get help from local developer. as manager i need to have basic knowledge from what is under my control. so please guide me to how change Georgian to Persian (jalali) calendar. i done translating from en to per but the most problem is the calendar. project address: https://drive.google.com/open?id=1eKestInuUiUJHotYltNuVsqRGnq4ujNN thank you for your attention and your kind best regards Any chance you could help me out with some probably simple code ? I need to change an image when the script change state. So instead of $Streamstatus "off"or "on" I would like to change an image. Cheers Code: [Select] <?php $request = 'http://api.own3d.tv/liveCheck.php?live_id='; $arg = 'Zerkilive'; $session = curl_init($request.$arg); curl_setopt($session, CURLOPT_HEADER, false); curl_setopt($session, CURLOPT_RETURNTRANSFER, true); $response = curl_exec($session); curl_close($session); if (preg_match("/true/",$response, $result)) { $streamStatus="on"; $color="green"; } else { $streamStatus="off"; $color="red"; } echo $streamStatus; ?> Hi, I'm using the following code: <td>$row[color]</td> and the possible values for this field are 1, 2 and 3. But I want the return to be red for 1, blue for 2, and green for 3. How do I write it so that instead of getting a row of 1's, 2's and 3's, I change those numbers to their corresponding colors? Thanks! Hi I'm using a form that uses number_format. It works fine until the number in question gets into the thousands. I can enter "3000", click Calculate and it comes back as "3,000.00" which is perfect. But if I click Calculate again, it changes to "3.00". How can I get it to remain "3,000.00"? Here's the code: Code: [Select] <form action="test.php" method="POST" > <?php if (empty($_POST['data1'])) { $number = ''; } else { str_replace(",","",$_POST['data1']); $number = number_format((double)$_POST['data1'],2); } ?> <input type="text" style="40" name="data1" value="<?php echo $number; ?>"> <input type="submit" name="submitCalc" value="Calculate" /><br /> <a href="test.php">Reset Form</a> </form> // SESSION TEST if ($_SESSION['username']) { require_once("../mysql.php"); // Find Username from Session ID // Find Username from ID $finduser="SELECT username FROM users WHERE id='$_SESSION[username];'"; $finduserquery=mysql_query($finduser)or die(mysql_error()); $userfetch = mysql_fetch_array($finduserquery); // Set Username Variable $userfromid = $userfetch['username']; echo "lol" . ucwords($userfromid); } else { } Everytime I load this page more than once when logged in, it seems to turn the variable blank. Therefore making the user not be able to view other pages that use a session. Help? Thanks |
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