PHP - File_exists Returning True Even Though The File Patently Doesn't Exist!

I had some code that I'm pretty sure used to work, basically something like the below.

Code: [Select]
if (preg_match("/[a-zA-Z0-9]+/", $_POST['title'])) {
   echo $_POST['title'];exit();
}
Now i just don't get why it always returns true, even when entering special characters like "!#%?"..

The only thing which comes to mind, is that i recently made a move to UTF-8..

I have an IF statement that is constantly returning TRUE, even when it shouldn't be. Basically it checks if an array is empty.

Code: [Select]
<?php

      $error = array();
      

      //No blanks
      if ($street_addr == "" || $city == "" || $state == "" || $zip == "" || $phone1 == "" || 
            $phone2 == "" || $phone3 == "" || $county == "")
               $error[] = "You left something blank!";
      
      //validate zip
      if(!preg_match("/^[0-9]{5}$/", $zip)) 
          $error[] = "The ZIP code must be a 5-digit number.";
          
      //validate phone number
      if (!is_numeric($phone1) || !is_numeric($phone2) || !is_numeric($phone3))
         $error[] = "Phone can only contain digits";
         
      if (strlen($phone1) < 3 || strlen($phone2) < 3 || strlen($phone3) < 4)
         $error[] = "Invalid phone number";

      $count_errors = count($error);
         
      if ($count_errors > 0){
      
         echo "ERROR:<br />";
         
         foreach ($error as $err){
         
            echo "-$err<br />";
         
         }
         
      } else { 
         
          //Other code
      }

?>

So the first part of the IF statement is always executing.

$count_errors DOES return 0 when printed out.

Any help would be greatly appreciated. Thanks!

Here is my code so far (I say it's PDO but it pretty much isn't. What is the object here? The database connection? LOL!);
 

$sql = 
	"
	SELECT 
	SUM(IF(`sent` != 'N' , 1 , 0 )) as 'Emails Sent',	
	SUM(IF(`completed` NOT IN('N','paper') , 1 , 0 )) as 'Completed Electronically', 	
	SUM(IF(`completed` = 'paper' , 1 , 0 )) as 'Completed Manually', 
	SUM(IF(`completed` != 'N' , 1 , 0 )) as 'Total Number Completed',
	SUM(IF(`remindercount` = '1' , 1 , 0 )) as 'Reminder Sent Once',
	SUM(IF(`remindercount` = '2' , 1 , 0 )) as 'Reminder Sent Twice',
	SUM(IF(`remindercount` = '3' , 1 , 0 )) as 'Reminder Sent Thrice'
	FROM `tokens_$survey_id`
	";
				
$statement = $dbh->prepare($sql);
$statement->execute();

$result = $statement->fetch(PDO::FETCH_OBJ);
				
foreach($result as $key => $value) {
	 echo "<tr>
		<td>$key</td>
		<td>$value</td>
	       </tr>";
}

This is all well and good if the tokens_$survey_id table is actually there. Sometimes, for a genuine reason, there won't be a tokens table for that particular survey. How do I account for this? At the moment I get an error..
 

Warning: Invalid argument supplied for foreach() in /var/www/html/index.php on line 149 

I tried this but I am not satisfied this is correct;
 

if(!$result) {
die();
}

I don't want the code to die! If I take out the die() statement then this if is ignored for some reason I don't understand.

I'm just trying to find out if php has the ability to check if any file exists, with only part of the filename given..

I have this path:

if (file_exists($dir.'/'.$c_file.'/templ_*')) {

I added a little star.. That star represents whatever the rest of that file is named for this example.. It could be anything.. So can php match any files that start with "templ_", and say that it does or does not exist??

Thanks

I want to get suggested keywords from yahoo api service. When xml file is empty (no keyword), it gives error. To resolve this problem I used this code:
if (file_exists('http://search.yahooapis.com/WebSearchService/V1/relatedSuggestion?appid=YahooDemo&query=Madonna&results=2')) {
$xmlmetades = simplexml_load_file('http://search.yahooapis.com/WebSearchService/V1/relatedSuggestion?appid=YahooDemo&query=Madonna&results=2');
}


Since it is not a normal .xml file, it is always considered no file, and return nothing.

I'm printing some mysql results to a table and sometimes I have rows with no results so they never get counted...  which results in an ugly looking parenthesis on my page with nothing it  ().  For these times, I'd like to print a zero. 

How can I rewrite the following to achieve this? 

Code: [Select]
if($row['mycount'] does not exist) {
$row['mycount'] = '0';
}

I guess I'm just stupid cause it seems like every time i get stuck and i post on here and its gets answered in less than 30 min.'s and i keep getting stuck!

Here my script...

function scoring($user){
$query = "SELECT Game_ID, Pick FROM Cfb WHERE User_ID= 1";
$result = mysql_query($query);

$query1 = "SELECT Game_ID, Pick FROM Cfb WHERE User_ID= $user";
$result1 = mysql_query($query1);

$affected = mysql_num_rows($result);

for($i=0; $i< $affected; $i++) {
$scores =mysql_fetch_assoc($result);
$scores1 =mysql_fetch_assoc($result1);

$main = array_diff_assoc($scores,$scores);
$me = array_diff_assoc($scores, $scores1);

$m = count($me);
$m1 = count($main);

if ($m == $m1){
$points += 1;
}else{
$points += 0;
}
}

echo '<br />';
echo '<br />';
echo $user;
echo '<br />';
echo $points;
echo '<hr />';
}

$sql="SELECT  id FROM users WHERE approved=1 AND user_level !=10";
    $result=mysql_query($sql);
while($row = mysql_fetch_object($result))
   {
    $ids[] = $row->id;
   }
   
print_r($ids);


Alright heres what this script does...
The script has a function that scores 1 individual user for his/her choices.
Then I'm getting the user_ids from the users table at the bottom. Taking those and plugging them back into the function to score all the users at one time.

Problem...
Not all users will make picks. So how do i break the script in the function if that user_id is not is the CFB table attached to picks

I have 2 tables im using Cfb and users

users controls user info such as id # name username ect..
Cfb controls the picks. When a user makes there selection it stores there User_ID, Game_ID, and Pick

So not all user ids are in the Cfb table. So if the script tries to input a user id thats not in the Cfb table it needs to break. Right now it just screws everything up!

So how can i make it break that way?

Thanks for any help

Delete.

I'm working on a WordPress theme and I'm trying to build in a simple if statement which will check if the user has add his own logo into the images folder if he doesn't then the name of the blog will appear as normal text in place of the graphic logo.

This is how it looks like:


<?php

$logo_dir = get_template_directory_uri() . "/images/logo.png";

if (file_exists($logo_dir)) { ?>

<li><img src="<?php bloginfo ('template_directory'); ?>/images/logo.png" alt="<?php bloginfo('description'); ?>" /></li>

<?php } else { ?>

<li id='blog_name'><a href="<?php bloginfo('url'); ?>"><?php bloginfo('name'); ?><font>*</font></a></li>

<?php } ?>




I've echo'd out $logo_dir, the URL is correct, but still for some reason it's seeing it as if there would no file exist. If I turn it around into !file_exists then the graphic logo WILL show up. So it's always seeing it as non-existent.

Any ideas why this could be or am I using this function in a wrong fashion? As far as I've understood the PHP manual, this is the correct way of using it.

First time post, be easy on me...   I'm using preg_match_all to return an array with all the matches.  I know I'm missing something fundamental, but I either keep looking past it or am more screwy than I know.   Sample String

CC-BY-ND-NC

I'm using the following code

preg_match_all("/cc|creative commons|copyright|by|sa|nc|nd/i",$exifmeta['copyright'],$cmeta)

I would expect to see

Array
(
    [0] => Array
        (
            [0] => CC
            [1] => BY
            [2] => ND
            [3] => NC
        )

)

What I get is

Array
(
    [0] => Array
        (
            [0] => CC
            [1] => BY
            [2] => ND
            [3] => NC
            [4] => sa
        )

)

Hi,
No matter what I seem to change in my code, I sill get the same error!

"Table 'suvoocom_wl.beta' doesn't exist"

This is my 'core.php' file;

Code: [Select]
<?php
session_start();

@include ('config.php');
@include ('connect.php');

// #########################################################################
// Check if Writing Lounge is under maintenance, and avoid, if possible

$qry="SELECT * FROM fuse_rights WHERE username='".$_SESSION['username']."'";
$result=mysql_query($qry);

if($result) {
if(mysql_num_rows($result) == 1) {

$checks = mysql_fetch_assoc($result);
$am = $checks['avoid_maintenance'];

}
}

if(isset($_SESSION['username']) && $am == 0)
{ 

$result = mysql_query("SELECT * FROM break") or die(mysql_error());  

while($row = mysql_fetch_assoc($result)) {
 if($row['on'] == 1) {
   header('location:../maintenance');
   exit();
 }
}
} 
if(isset($_SESSION['username']) && $am == 1)
{ 
} else {
$result = mysql_query("SELECT * FROM break") or die(mysql_error());  

while($row = mysql_fetch_assoc($result)) {
 if($row['on'] == 1) {
   header('location:../maintenance');
   exit();
 }
 }
 }
 
// #########################################################################
// Check if Writing Lounge has BETA activated

if(!session_is_registered(betaaccess)){

$result = mysql_query("SELECT * FROM beta") or die(mysql_error());  

while($row = mysql_fetch_assoc($result)) {
 if($row['on'] == 1) {
   header('location:../BETA');
   exit();
 }
 }
 }
 
// #########################################################################
// Check if the user logged in is banned

$result = mysql_query("SELECT username FROM bans WHERE username = '".$_SESSION['username']."'") or die(mysql_error());  

if (mysql_num_rows($result) > 0) {
   header('location:../banned');
   exit();
}

// #########################################################################
// Define the variables Writing Lounge will use later on

$remote_ip = $_SERVER[REMOTE_ADDR];
$H = date('H');
$i = date('i');
$s = date('s');
$m = date('m');
$d = date('d');
$Y = date('Y');
$j = date('j');
$n = date('n');
$today = $d;
$month = $m;
$year = $Y;
$date_normal = date('d-m-Y',mktime($m,$d,$Y));
$date_reversed = date('Y-m-d', mktime($m,$d,$y));
$date_full = date('d-m-Y H:i:s',mktime($H,$i,$s,$m,$d,$Y));
$date_time = date('H:i:s',mktime($H,$i,$s));
$date_hc = "".$j."-".$n."-".$Y."";
$regdate = $date_normal;
$forumid = strip_slashes($_GET['id']);
?>

It's basically the backbone to my website.

This is my 'config.php' file;

Code: [Select]
<?php
$sqlhostname = "localhost";
$sqlusername = "suvoocom_wl";
$sqlpassword = "*****";
$sqldb = "suvoocom_wl";
?>

And this is my 'connect.php' file;

Code: [Select]
<?php
mysql_connect("$sqlhostname", "$sqlusername", "$sqlpassword")or die("Unable to connect.");
mysql_select_db("$sqldb")or die("Unable to select the database you provided. Either I do not have premission to connect to that database, or the database doesn't exist.");
?>

Does anyone have any ideas? :S
Thanks!

Hi,

My site was working fine, but I just switched servers/web hosts and now I'm getting the following errors (in blue). The thing is, I don't get the error if I try to run the query loop after just using 'mysql_select_db' once, but if I use it again to select a different database and then run the query loop, I start getting the error.

Code: [Select]
mysql_select_db ("database1", $mysql_con);

$mysql_query = mysql_query ("SELECT ID FROM someTable1", $mysql_con);
$someVar1 = 0;

while ($mysql_array = mysql_fetch_array ($mysql_query))
{
$someVar1 ++;
}


////// The above code gives me no error. But If I then try to select a different database and run a loop in the same way (in the same file), I start getting the below error...


mysql_select_db ("database2", $mysql_con);

$mysql_query = mysql_query ("SELECT ID FROM someTable2", $mysql_con);
$someVar2 = 0;

while ($mysql_array = mysql_fetch_array ($mysql_query))
{
$someVar2 ++;
}
Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/snubby5/public_html/coozymcmillan.com/view.php on line 86

So I looked it up and somewhere it told me to add some extra code to handle errors better:

Code: [Select]
if ($mysql_query === FALSE) {
    die (mysql_error ()); // TODO: better error handling
}
But when I do that, I get a different error:

Table 'database1.someTable2' doesn't exist

It doesn't seem to recognize that I switched databases, and it says 'database1.someTable2' doesn't exist (because it doesn't), when really it should be checking for 'database2.someTable2' (which exists).

So to reiterate, I can run the query loop fine after selecting database1, but after that if I select database2, it either gives me the first error, or If I add the 'die' code it gives me the second error.


Thanks much!

PS: I can get it working if I put everything into one database, but I have multiple websites (which sometimes need to call eachothers' databases) and it would be a huge hassle to cram them all into one database unless I have to.

Hi all

My code give this:

<b>Warning</b>:  file_exists(): open_basedir restriction in effect. File(/tmp) is not within the allowed path(s): (/home/clients/........

I get the tmp folder and check for its existanse and whether it is writeable

$t=sys_get_temp_dir();
writelog("t=$t");
if(file_exists($t)) writelog("t1=YES"); else writelog("t1=NO");
if(is_writable($t)) writelog("t2=YES"); else writelog("t2=NO");

Both gives no which is fine, I can process that. I do it to avoid the output above, but I still get that.

How should I check for allowed paths?

This runs on several systems where I cannot access php.ini or other system stuff.

 

Hi all,

I want to make a script that identifies if an image JPG file exists.

Would somthing like this work?


<?php
$file = "images/image.jpg";
if ($file > 0) {
echo "file exists";
}
else { echo "no file"; }
?>

So in my last thread I was working on checking if a file was there...I resorted to something not in the library and used

$pic_exists_jpg = fopen($jpg_path,'r');
$pic_exists_jpeg = fopen($jpeg_path,'r');
$pic_exists_gif = fopen($gif_path,'r');
$pic_exists_png = fopen($png_path,'r');
if ($pic_exists_jpg != '0') {
$jpg_test = '1';
} elseif ($pic_exists_jpg == '1') {
$jpg_test = '2';
} elseif ($pic_exists_jpg == '0') {
$jpg_test = '2';
} elseif ($pic_exists_jpeg != '0') {
$jpeg_test = '1';
} elseif ($pic_exists_gif != '0') {
$gif_test = '1';
} elseif ($pic_exists_png != '0') {
$png_test = '1';
}

now for some reason php is being a poo and no matter what returning that there is a file there. no matter what method i use be it fopen or file_exists or anything else, it saying I have a file in that directory BUT I DO NOT! THERE IS NOT ONE OF THOSE FILES. I know I have my paths right because If I echo them directly I get the picture...what the heck?!