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PHP - Mysql_fetch_array And Tables / Cells Problem
Hello
Im trying to achieve the following output (see the below table. Then on a new row have the next 4 pieces of data that is pulled from the database. So i want the table to automatically have a new row after every 4 cells e.g. 1st piece of data 2nd piece 3rd piece 4th piece 5th piece of data 6th piece 7th piece 8th piece etc etc, until there is no more results within the database to pull back, i guess its a bit like pagination but rather rowination Any one point me in the right direction on what i need to do Similar TutorialsHey guys i have a query that select from multiple tables and works fine however i have the same field name in each table called:: member_id but i want to select specifically the member_id from table1 do i need to change the name when i loop through them? i really dont want to do that but if it confuses php unless is there a way when doin a while loop i specify what table i want it from? while($row = mysql_fetch_array($query)){ $member_id = $row['member_id']; } I am having a problem with my script not returning anything! I echo the variable usually it will say ARRAY and it has something in it.. Nothing at all it coming up no errors I have put or die in it, nothing. I tried error_reporting(E_ALL); , still nothing. If someone can help me with this, I will greatly appreciate it. ~AJ error_reporting(E_ALL); //Get Catagorys and echo $getCatagorys = mysql_query("SELECT * FROM `catagory`") or die("Query failed with error: ".mysql_error()); while($row = mysql_fetch_array($getCatagorys, MYSQL_ASSOC)){ echo ' <tr> <td class="catagoryTD" width="550">'.$row['catagoryTitle'].'</td> <td class="catagoryTD" width="75"><center>Threads</center></td> <td class="catagoryTD" width="75"><center>Posts</center></td> <td class="catagoryTD" width="170"><center>Last Post</center></td> </tr>'; //Get SubCatagorys and echo $catagoryID = $row['catagoryID']; $getSubCatagory = mysql_query("SELECT * FROM `subcatagory` where catagoryID = '$catagoryID'"); while($subrow = mysql_fetch_array($getSubCatagory, MYSQL_ASSOC)){ $subCatagory = $subrow['subcatagoryID']; //Get Stats for number of threads $threads = mysql_query("SELECT * FROM entry WHERE subcatagoryID = '$subCatagory'") or die(mysql_error()); $num_threads = mysql_num_rows($threads); //Get Stats for number of entrys(posts) $posts = mysql_query("SELECT * FROM posts WHERE subcatagoryID = '$subCatagory'") or die(mysql_error()); $num_posts = mysql_num_rows($posts); //Find newest post and find what thread it is from $lastPost = mysql_query("SELECT * FROM `posts` ORDER BY `posts`.`postCreated` DESC") or die(mysql_error()); while($lastPostReturn = mysql_fetch_array($getSubCatagory, MYSQL_ASSOC)){ echo $lastPostReturn; } //Grab User and thread number and date $lastPostUser = $lastPostReturn['postUser']; $lastPostCreated = $lastPostReturn['postCreated']; $lastPostEntry = $lastPostReturn['entryID']; //Find the title of the thread and generate URL\ $lastPostThread = mysql_query("SELECT * FROM `entry` WHERE entryID = '$lastPostEntry'"); while($lastPostThreadReturn = mysql_fetch_array($lastPostThread, MYSQL_ASSOC)){ } echo ' <tr> <td><a href="catagory.php?id='.$subrow['subcatagoryID'].'">'.$subrow['subcatagoryTitle'].'</a></td> <td><center>'.$num_threads.'</center></td> <td><center>'.$num_posts.'</center></td> <td>'.$lastPostThreadReturn['text'].'<br>'.$lastPostCreated.'<br>'.$lastPostUser.'</td> </tr>'; } } Hi, I got a problem with two tables. There is a one with users, and the other is with logs of the users. USERS table - ID - name LOGS table - ID - users_ID - log_datetime I want to list this tables like this Name 1 - log_datetime - log_datetime - log_datetime... Name 2 - log_datetime - log_datetime - log_datetime... Name 3 - log_datetime - log_datetime - log_datetime... So, every names just one time, and below every log belong to that name... Thanks.. T I'm trying to combine 3 tables (attacks, spells, skills) where it brings in all the information from attacks and spells into the table skills. The common row between all 3 is "name". Here is what I have so far. $query = "SELECT * FROM `skills`,`attacks`,`spells` WHERE (`attacks.name`=`skills.name` OR `spells.name`=`skills.name`) AND `user_id`='".$_SESSION['userid']."'"; Thanks! Hi, My name is stefan and I've been trying to develop a php/mysql based CRM for private use. I've stumbled upon a problem a few days ago and I just can't figure it out, so if you could help me, I'd really appreciate it. The problem is the following: I have 1 database which contains 5 tables. Each table has info in it but the primary key always is 'ID' 4 Tables are named; Zendingen | Klanten | Manden | Bestemmeling The last table, named 'Combination' has the unique ID of each of those 4 in it. The example will be given below. What I want to do now is create a page that shows all stored rows in 'Combination'-table, but gets the proper client_name or product_info out of the corresponding table. I have searched for it myself but I have no clue where to begin and how to define my searches so they all stranded. This is the piece of code. Code: (php) [Select] $Shipm1 = mysql_query("SELECT * FROM Shipments where Zending_ID = 9") or die(mysql_error()); while($row = mysql_fetch_assoc($Shipm1)) { echo "<br />"; echo $row["ID"]; echo "<br />"; echo $row["Zending_ID"]; echo "<br />"; echo $row["Klant_ID"]; echo "<br />"; echo $row["Mand_ID"]; echo "<br />"; echo $row["Bestemmeling_ID"]; echo "<br />"; }This code returns: Quote 3 ---- the ID of the 'combination' table and thus primary key 9 ---- Zending_ID 47 --- Klant_ID 17 --- Mand_ID 2 ---- Bestemmeling_ID 4 This is another row from the combinations table, 9 notice that it only returns the Zending_ID = 9. 49 21 4 Now this gives me the info I want, but it doesn't displays them how I need it to. I want it to search up each ID in the proper table and return me the product name, client name etc... Anyone who can help or point me in the right direction? Kind regards Stefan Hi, I'm trying to insert data into two different tables using, but am getting an error I can't figure out. If I move the $mysqli->commit(); into the foreach loop, I get at least one returned row before the rest fail. The error current error message is Array ( [0] => Error: Couldn't insert into english! ). Any idea what is causing this?
<?php
$file_array = file('../grammar/conjunctions.txt');
$csv = array_map('str_getcsv', $file_array);
// DB
$mysqli = new mysqli('localhost', 'root', '******', 'angos');
$mysqli->autocommit(false);
$error = array();
foreach($csv as $value)
{
$angos_query = $mysqli->query("INSERT INTO angos (angos, grammar) VALUES ('$value[0]', 'con')");
$id = $mysqli->insert_id; // grab the currant angos table id
if($angos_query == false)
{
array_push($error, "Error: Couldn't insert into angos!");
}
$english_query = $mysqli->query("INSERT INTO english (angos_id, english) VALUES ('$id', '$value[1]')");
if($english_query == false)
{
array_push($error, "Error: Couldn't insert into english!");
}
if(!empty($error))
{
$mysqli->rollback();
}
}
$mysqli->commit();
print_r($error);
// print_r($csv);
?>
More info SQL:
CREATE TABLE angos
(
id int unsigned NOT NULL AUTO_INCREMENT PRIMARY KEY,
angos varchar(255) not null,
grammar varchar(3) not null,
updated TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
CONSTRAINT unique_input UNIQUE (angos)
) engine=InnoDB;
CREATE TABLE english
(
id int unsigned not null primary key,
angos_id int unsigned,
english varchar(255),
grammar_note varchar(500),
CONSTRAINT fk_angos_source FOREIGN KEY (angos_id) REFERENCES angos(id) ON DELETE CASCADE ON UPDATE CASCADE
) engine=InnoDB;
hello all, i want to display each row from mysql table in a different page using this code: Code: [Select] <? require_once('config.php'); //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die("can't connect: " . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("can't select database"); } mysql_query("SET NAMES 'hebrew'"); //mysql_set_charset('utf8',$link); if (isset($_GET["page"])) { $page = $_GET["page"]; } else { $page=1; }; $start_from = $page-1; $qry='SELECT * FROM ordering limit 0, 1'; $result = mysql_query($qry); while($row = mysql_fetch_array($result)){ echo "<div dir='rtl' charset='utf8'><h2>"," hover cam: ",$row['hover_camera'], "<br> stills: ",$row['stills'], "<br> video_photographers: ",$row['video_photographers'], "<br> increase: ",$row['increase'], "<br> video_edit: ",$row['video_edit'], "<br> digital_album: ",$row['digital_album'], "<br> photo_album: ",$row['photo_album'], "<br> small_digital_album: ",$row['small_digital_album'], "<br> video_clip: ",$row['video_clip'], "<br> magnets: ",$row['magnets'], "<br> comments: ",$row['comments'], "<br> date: ",$row['date'], "<br><br></h2></div>"; } $sql = "SELECT COUNT(userid) FROM ordering"; $result = mysql_query($sql,$link); $row2 = mysql_fetch_row($result); $total_records = $row2[0]; $total_pages = $total_records ; for ($i=1; $i<=$total_pages; $i++) { echo "<a href='table.php?page=".$i."'>".$i."</a> "; }; ?> this is the table: Code: [Select] CREATE TABLE IF NOT EXISTS `ordering` ( `userid` int(11) unsigned NOT NULL AUTO_INCREMENT, `hover_camera` varchar(10) DEFAULT NULL, `stills` int(5) NOT NULL, `video_photographers` int(5) NOT NULL, `increase` int(5) NOT NULL, `video_edit` varchar(10) NOT NULL, `digital_album` varchar(10) DEFAULT NULL, `photo_album` varchar(10) DEFAULT NULL, `small_digital_album` varchar(20) DEFAULT NULL, `video_clip` varchar(10) DEFAULT NULL, `magnets` int(10) NOT NULL, `comments` text NOT NULL, `date` date NOT NULL, PRIMARY KEY (`userid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 ; the problem is that only the first row is displayed no matter which page i choose and i want each page to display the row assigned to it (page 15 = row 15 etc...) any suggestions? Hello, I will try to explain this in as much detail as I can. I am probably making a simple mistake but I have gone through the code multiple times and can't figure it out. I have 3 HTML Site tables, pending, accepted and denied applications. I have accept, deny, and delete buttons on all the tables for each row. I could probably do with out the accept and deny buttons on the last two HTML Site tables, but in the case an admin making a mistake and clicking the wrong button. I don't want the admin to have to delete the app and have the user fill out a new one. User experience and all that. My problem: The last two HTML Site tables, Accept and Denied, the three buttons do not function but in Pending they do. I don't remember assigning those functions to one table and looked thought the code and didn't see any place I did it is only looking for id at the displayed row. Enough of my jabbering. Here is what I am working with.
Here is the code, I have done for the deletes and edits to the application status.
//DELETE APPLICATION
if(isset($_POST['delete'])) {
$to_change = mysqli_real_escape_string($conn, $_POST['to_change']);
$sql = "DELETE FROM apps WHERE id = $to_change";
if(mysqli_query($conn, $sql)) {
$feedback['delete'] = '<div class="green white-text alert-box">Success the user deleted from list.</div>';
header('Location: admin.php');
} else {
$feedback['ui_feedback'] = '<div class="red white-text alert-box">Connection Error</div>';
}
} else {
$feedback['ui_feedback'] = '<div class="red white-text alert-box">Connection Error</div>';
}
//UPDATE APPLICATION STATUS TO ACCEPT
if(isset($_POST['accept'])) {
$to_change = mysqli_real_escape_string($conn, $_POST['to_change']);
//QUERY DB
mysqli_query($conn, "UPDATE apps SET app_status='Accepted' WHERE id = $to_change");
$feedback['accept'] = '<div class="green white-text alert-box">Success, the user was accepted.</div>';
header('Location: admin.php');
} else {
$feedback['ui_feedback'] = '<div class="red white-text alert-box">Connection Error</div>';
}
//UPDATE APPLICATION STATUS TO DENIED
if(isset($_POST['denied'])) {
$to_change = mysqli_real_escape_string($conn, $_POST['to_change']);
//QUERY DB
mysqli_query($conn, "UPDATE apps SET app_status='Denied' WHERE id = $to_change");
$feedback['denied'] = '<div class="green white-text alert-box">Success, the user was denied.</div>';
header('Location: admin.php');
} else {
$feedback['ui_feedback'] = '<div class="red white-text alert-box">Connection Error</div>';
}
I know the $feedback doesn't work I wanted to see it worked and it didn't I will research that later.
<!-- NEW APPLICATIONS -->
<div id="new_apps" class="container white container-style">
<h4 class="blue-text text-darken-3">New Applications</h4>
<div class="table-responsive">
<table class="highlight centered row">
<thead>
<tr class="">
<th class="blue-text text-darken-3">ID</th>
<th class="blue-text text-darken-3">Name</th>
<th class="blue-text text-darken-3">Email</th>
<th class="blue-text text-darken-3">Discord</th>
<th class="blue-text text-darken-3">Steam Hex ID</th>
<th class="blue-text text-darken-3">DOB</th>
<th class="blue-text text-darken-3">Department</th>
<th class="blue-text text-darken-3">Date Applied</th>
<th class="blue-text text-darken-3">Status</th>
<th class="blue-text text-darken-3">Actions</th>
</tr>
<tbody class="">
<?php if($pending): ?>
<?php foreach($pending as $pend): ?>
<tr>
<td><?php echo $pend['id']; ?></td>
<td><?php echo $pend['first_name'] . " " . $pend['last_name']; ?></td>
<td><?php echo $pend['email']; ?></td>
<td><?php echo $pend['discord_name']; ?></td>
<td><?php echo $pend['steam_hex']; ?></td>
<td><?php echo $pend['dob']; ?></td>
<td><?php echo $pend['dept_select']; ?></td>
<td><?php echo $pend['created_at']; ?></td>
<td><?php echo $pend['app_status']; ?></td>
<td>
<form action="<?php echo $_SERVER['PHP_SELF'] ?>" method="POST">
<input type="hidden" name="to_change" value="<?php echo $pend['id']; ?>">
<button type="submit" name="accept" class="tooltipped btn-floating btn-flat btn-small transparent" data-postion="bottom" data-tooltip="Accept"><i class="material-icons green-text text-darken-3">check_circle</i></button>
<button type="submit" name="denied" class="tooltipped btn-floating btn-flat btn-small transparent" data-postion="bottom" data-tooltip="Deny"><i class="material-icons yellow-text text-darken-3">not_interested</i></button>
<button type="submit" name="delete" class="tooltipped btn-floating btn-flat btn-small transparent" data-postion="bottom" data-tooltip="Delete"><i class="material-icons red-text text-darken-3">delete</i></button>
</form>
</td>
</tr>
</tbody>
<?php endforeach; ?>
<?php else: ?>
<div class="blue darken-3 white-text table-empty-box">There are no applications</div>
<?php endif; ?>
</thead>
</table>
</div>
</div>
<!-- ACCEPTED APPLICATIONS-->
<div id="accepted_apps" class="container white container-style">
<h4 class="blue-text text-darken-3">Accepted Applications</h4>
<div class="table-responsive">
<table class="highlight centered row">
<thead>
<tr class="">
<th class="blue-text text-darken-3">ID</th>
<th class="blue-text text-darken-3">Name</th>
<th class="blue-text text-darken-3">Email</th>
<th class="blue-text text-darken-3">Discord</th>
<th class="blue-text text-darken-3">Steam Hex ID</th>
<th class="blue-text text-darken-3">DOB</th>
<th class="blue-text text-darken-3">Department</th>
<th class="blue-text text-darken-3">Date Applied</th>
<th class="blue-text text-darken-3">Status</th>
<th class="blue-text text-darken-3">Actions</th>
</tr>
<tbody class="">
<?php if($accepted): ?>
<?php foreach($accepted as $accept): ?>
<tr>
<td><?php echo $accept['id']; ?></td>
<td><?php echo $accept['first_name'] ." " . $accept['last_name']; ?></td>
<td><?php echo $accept['email']; ?></td>
<td><?php echo $accept['discord_name']; ?></td>
<td><?php echo $accept['steam_hex']; ?></td>
<td><?php echo $accept['dob']; ?></td>
<td><?php echo $accept['dept_select']; ?></td>
<td><?php echo $accept['created_at']; ?></td>
<td><?php echo $accept['app_status']; ?></td>
<td>
<form action="<?php echo $_SERVER['PHP_SELF'] ?>" method="POST">
<input type="hidden" name="to_change" value="<?php echo $accept['id']; ?>">
<a type="submit" name="accept" class="tooltipped btn-floating btn-flat btn-small transparent" data-postion="bottom" data-tooltip="Accept"><i class="material-icons green-text text-darken-3">check_circle</i></a>
<a type="submit" name="denied" class="tooltipped btn-floating btn-flat btn-small transparent" data-postion="bottom" data-tooltip="Deny"><i class="material-icons yellow-text text-darken-3">not_interested</i></a>
<a type="submit" name="delete" class="tooltipped btn-floating btn-flat btn-small transparent" data-postion="bottom" data-tooltip="Delete"><i class="material-icons red-text text-darken-3">delete</i></a>
</form>
</td>
</tr>
<?php endforeach; ?>
<?php else: ?>
<div class="blue darken-3 white-text table-empty-box">There are no applications</div>
<?php endif; ?>
</tbody>
</thead>
</table>
</div>
</div>
<!-- deniedED APPLICATIONS -->
<div id="denieded_apps" class="container white container-style">
<h4 class="blue-text text-darken-3">Denied Applications</h4>
<div class="table-responsive">
<table class="highlight centered row">
<thead>
<tr class="">
<th class="blue-text text-darken-3">ID</th>
<th class="blue-text text-darken-3">Name</th>
<th class="blue-text text-darken-3">Email</th>
<th class="blue-text text-darken-3">Discord</th>
<th class="blue-text text-darken-3">Steam Hex ID</th>
<th class="blue-text text-darken-3">DOB</th>
<th class="blue-text text-darken-3">Department</th>
<th class="blue-text text-darken-3">Date Applied</th>
<th class="blue-text text-darken-3">Status</th>
<th class="blue-text text-darken-3">Actions</th>
</tr>
<tbody class="">
<?php if($denied): ?>
<?php foreach($denied as $deny): ?>
<tr>
<td><?php echo $deny['id']; ?></td>
<td><?php echo $deny['first_name'] ." " . $deny['last_name']; ?></td>
<td><?php echo $deny['email']; ?></td>
<td><?php echo $deny['discord_name']; ?></td>
<td><?php echo $deny['steam_hex']; ?></td>
<td><?php echo $deny['dob']; ?></td>
<td><?php echo $deny['dept_select']; ?></td>
<td><?php echo $deny['created_at']; ?></td>
<td><?php echo $deny['app_status']; ?></td>
<td>
<form action="<?php echo $_SERVER['PHP_SELF'] ?>" method="POST">
<input type="hidden" name="to_change" value="<?php echo $deny['id']; ?>">
<a type="submit" name="accept" class="tooltipped btn-floating btn-flat btn-small transparent" data-postion="bottom" data-tooltip="Accept"><i class="material-icons green-text text-darken-3">check_circle</i></a>
<a type="submit" name="denied" class="tooltipped btn-floating btn-flat btn-small transparent" data-postion="bottom" data-tooltip="Deny"><i class="material-icons yellow-text text-darken-3">not_interested</i></a>
<a type="submit" name="delete" class="tooltipped btn-floating btn-flat btn-small transparent" data-postion="bottom" data-tooltip="Delete"><i class="material-icons red-text text-darken-3">delete</i></a>
</form>
</td>
</tr>
<?php endforeach; ?>
<?php else: ?>
<div class="blue darken-3 white-text table-empty-box">There are no applications</div>
<?php endif; ?>
</tbody>
</thead>
</table>
</div>
</div>
Any help would be amazing even if you tell me to look at a line lol I am getting back into php after only doing it for a few weeks after switching to firebase, just coming back to what works and not having limits. Thank you for taking the time to read this! hello i have a mysql table and i want to display each row in a different page with an added condition, the code: Code: [Select] if (isset($_GET["page"])) { $page = $_GET["page"]; } else { $page=1; }; $start_from = $page-1; $qry="SELECT * FROM ordering WHERE userid='$page' AND email='$email' LIMIT 0,1"; $result = mysql_query($qry); while($row = mysql_fetch_array($result)){ echo "<div dir='rtl' charset='utf8'><h2>"," hover cam: ",$row['hover_camera'], "<br> stills: ",$row['stills'], "<br> video_photographers: ",$row['video_photographers'], "<br> increase: ",$row['increase'], "<br> video_edit: ",$row['video_edit'], "<br> digital_album: ",$row['digital_album'], "<br> photo_album: ",$row['photo_album'], "<br> small_digital_album: ",$row['small_digital_album'], "<br> video_clip: ",$row['video_clip'], "<br> magnets: ",$row['magnets'], "<br> comments: ",$row['comments'], "<br> date: ",$row['date'], "<br><br></h2></div>"; } $sql = "SELECT COUNT(userid) FROM ordering"; $result = mysql_query($sql,$link); $row2 = mysql_fetch_row($result); $total_records = $row2[0]; $total_pages = $total_records ; for ($i=1; $i<=$total_pages; $i++) { echo "<a href='myorders.php?page=".$i."'>".$i."</a> "; }; the table is as so: Code: [Select] CREATE TABLE IF NOT EXISTS `ordering` ( `userid` int(11) unsigned NOT NULL AUTO_INCREMENT, `hover_camera` varchar(10) DEFAULT NULL, `stills` int(5) NOT NULL, `video_photographers` int(5) NOT NULL, `increase` int(5) NOT NULL, `video_edit` varchar(10) NOT NULL, `digital_album` varchar(10) DEFAULT NULL, `photo_album` varchar(10) DEFAULT NULL, `small_digital_album` varchar(20) DEFAULT NULL, `video_clip` varchar(10) DEFAULT NULL, `magnets` int(10) NOT NULL, `comments` text NOT NULL, `date` date NOT NULL, `fname` varchar(100) NOT NULL, `email` varchar(100) NOT NULL, PRIMARY KEY (`userid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; now to the problem: this code displays all the userid as page numbers however, the email condition is good only for part of the rows it's a little hard to explain, i'll try an example: suppose the email '1@1.com' is at rows 22,25 and 30 my code displays 30 page numbers and page 22 is user 22, page 25 is user 25 etc. what i want is to display only the page numbers of the pages with the conditional email, and if possible to display them as 1,2,3 instead of 22,25,30 Hi. I just have a quick question. If I perform a mysql query like the one below that returns all of the rows in a table. How do I then add all of this data into an array. If I use the following code bellow the variable $array will only contain the first row of the table. $rs = mysql_query($query, $conn); $array = mysql_fetch_array ($rs); Here is my code Code: [Select] // Show the events for this day: $getEvent_sql = "SELECT cal_title, cal_description, date_format(cal_start_time, '%l:%i %p') as fmt_date FROM calendar WHERE month(cal_start_time) = '".$m."' AND dayofmonth(cal_start_time) = '".$d."' AND year(cal_start_time)= '".$y."' ORDER BY cal_start_time"; $getEvent_res = myload($getEvent_sql); echo "<pre>"; print_r($getEvent_res); echo "</pre>"; if (count($getEvent_res) > 0){ $event_txt = "<ul>"; while($ev = mysql_fetch_array($getEvent_res)){ echo "Inside"; echo $ev; $event_title = stripslashes($ev["cal_title"]); $event_shortdesc = stripslashes($ev["cal_description"]); $fmt_date = $ev["fmt_date"]; $event_txt .= "<li><strong>".$fmt_date."</strong>: ".$event_title."<br/>".$event_shortdesc."</li>"; echo $event_title; } $event_txt .="</ul>"; mysql_free_result($getEvent_res); } else { $event_txt = ""; } if ($event_txt != ""){ echo "<p><strong>Today's Events:</strong></p> $event_txt <hr/>"; } I can't get inside the while loop. The array is populated, I've checked that. The count of $getEvent_res = 3. echo "Inside", and echo $ev give me nothing. Any ideas what I'm doing wrong? $getEvent_res = myload($getEvent_sql); The myload is a custom function that just works, I didn't write it, but I know it works. Hey guys, i'm sure this is simple i have a script that always brings back the same error and I beleive it's going to be the php version im on the code is Code: [Select] function check_user( $u ) { $res = query("SELECT COUNT(*) FROM `usertable` WHERE `userid`=$u"); list($total_rows) = mysql_fetch_array($res) or die (mysql_error()); if( $total_rows > 0 ) return true; else return false; } the error is Code: [Select] Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/bofs/public_html/thief/inc/userinc.php on line 10 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 any idea's Hi everyone, Bit of a random question and im sure there is good reason so if someone could in lighten me that would be great ! With regards to the below code, it seems to just create an infinite loop when you put mysql_fetch_array. Just want to know what wrong with doing this? and why it act in this way ? Code: [Select] $sql = mysql_query("SELECT * FROM cities"); $results = mysql_fetch_array($sql); while($row = $results) { echo $row['City']."<br />"; } thanks Guys I have some OOP code im working on and I have some interactions with the database. However, mysql_fetch_array fails to be working. Have I missed something? Code: [Select] class core { var $array_batsmen = ''; var $array_bowlers = ''; // Query to get batsmen function get_batsmen() { return $this->array_batsmen = mysql_query('SELECT id, name, ability, strength FROM wtw_players WHERE team_id = 1 ORDER BY id ASC'); } // Query to get bowlers function get_bowlers() { $this->array_bowlers = mysql_query('SELECT id, name, ability, strength FROM wtw_players WHERE team_id = 2'); } // Generate array of batsmen to be used function generateBatsmen() { while ($array = mysql_fetch_array($this->array_batsmen)) { echo $array['name']; } } } The functions are called later normally, i've only included the necessary parts. Basically I have the var $array_batsmen which stores the mysql_query. This is then later used with a mysql_fetch_array to return names from the earlier query. But nothing happens! It doesn't return anything (don't worry, I have a return later on). The loop just doesn't seem to work :/ Hey, I have been having a problem with this code for a while now where I connect to the MySQL database to retrieve the desired information, but always get an error message. I have tried to correct it myself by changing bits of the code and searched the internet, but still have no idea how to fix it. Any help would be appreciated. The error is as follows: Notice: An error occured1: in <filelocation> on line 18 Warning: mysql_fetch_array() expects parameter 1 to be resource, null given in <filelocation> on line 21 Notice: An error occured2: in <filelocation> on line 15 My code as is follows: require_once('../mysqli_connect.php') ; $query = "SELECT * FROM database WHERE mem_id='".($_GET['id'])."'"; $result = @mysql_query($dbc, $query) OR trigger_error("An error occured1: " . mysql_error()); $row = mysql_fetch_array($result) OR trigger_error("An error occured2: " . mysql_error()); echo "<b>Date: </b> ".$row['date']; echo "<br><b>ID: </b> ".$row['mem_id']; Thanks. Hi All, I am sorry to bother you but wondered if you might be able to spot my mistake... When I click on this page http://www.freepspwallpaper.co.uk/free-psp-wallpapers/free-babes-psp-wallpapers/ if returns an error as below (look carefully its hidden behind the header color). Im a bit of a newbie and cannot seem to remove it. Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/freepspw/public_html/dbconnect.php on line 22 Can anyone help? Peter Hello if some one be nice to help me out it be most kind... i got this error "Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in/home/23url/public_html/new.php on line 66" the code is - $getbans =mysql_query("SELECT banned FROM $tab[banned];"); $bans = array(); LINE 66 > while($ban=mysql_fetch_array($getbans)) { array_push($bans, $ban[0]); } many thanks Hi I post this thread under php, because I guess that my coding is wrong. I always get the following message Quote Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/content/g/w/o/gwolff2005/html/admin/update.php on line 23 Update data in mysql The code is Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <?php $host="xxxx"; // Host name $username="xxxx"; // Mysql username $password="xxxxx; // Mysql password $db_name="xxxxx"; // Database name $tbl_name="sp_users"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get value of id that sent from address bar $id=$_GET['user_id']; // Retrieve data from database $sql="SELECT * FROM '$sp_users' WHERE id='$user_id'"; $result=mysql_query($sql); $result=mysql_query("select * from '$sp_users' WHERE id='$user_id'"); $rows = mysql_fetch_array($result); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <form name="form1" method="post" action="update_ac.php"> <td> <table width="100%" border="0" cellspacing="1" cellpadding="0"> <tr> <td> </td> <td colspan="3"><div align="center" class="style1">Update data in mysql </div></td> </tr> <tr> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> </tr> <tr> <td align="center"> </td> <td align="center"><span class="style7">Name</span></td> <td align="center"><span class="style7">Lastname</span></td> <td align="center"><span class="style7">Email</span></td> </tr> <tr> <td> </td> <td align="center"><input name="name" type="text" id="name" value="<? echo $rows['user_first_name']; ?>"></td> <td align="center"><input name="lastname" type="text" id="lastname" value="<? echo $rows['user_surname']; ?>" size="15"></td> <td><input name="email" type="text" id="email" value="<? echo $rows['user_login']; ?>" size="15"></td> </tr> <tr> <td> </td> <td><input name="id" type="hidden" id="id" value="<? echo $rows['user_id']; ?>"></td> <td align="center"><input type="submit" name="Submit" value="Submit"></td> <td> </td> </tr> </table> </td> </form> </tr> </table> <? // close connection mysql_close(); ?> </body> </html>What am I doing wrong. Thanks for your help! I do a query and then do a while loop to go threw it, but later down the page I need to loop threw that data again, but nothing is there. Example while ($row = mysql_fetch_array($sqlmaps)) { //some code } //some code while ($row = mysql_fetch_array($sqlmaps)) { //it dose not work here now } Do need to do that exact same query 2 times to get the data? |
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