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PHP - Embedding Images From Rss Into Php
I'm trying to Embed the images from Apple into my PHP file.
Code: [Select] $phpobj = unserialize($response); if (is_array($phpobj)) { foreach ($phpobj['value']['items'] AS $key => $val) { printf("<div><p><a href=%s>%s</a></p><p>%s</p>\n", $val['link'], $val['title'], $val['description']); } } But the problem is that the image attribute is inside a Table and using something lile $val['img'] is not working. So anybody can help me with this. Here is the RSS feed format from which I'm importing Code: [Select] <item> <title>Dead Awake - Trailer</title> <link>http://trailers.apple.com/trailers/independent/deadawake/</link> <description>DEAD AWAKE is a seductive supernatural thriller starring Rose McGowan, Amy Smart and Nick Stahl set against the backdrop of a mysterious tragedy that shattered their lives a decade ago and which sets them on a path to uncover the truth that lies between the living and the dead.</description> <pubDate>Wed, 01 Dec 2010 00:00:00 PST</pubDate> <content:encoded><![CDATA[ <table> <tr valign="top"> <td width="67"><a href="http://trailers.apple.com/trailers/independent/deadawake/"><img src="http://trailers.apple.com/trailers/independent/deadawake/images/poster.jpg" width="65" height="97" border="0"></a></td> <td> </td> <td><a href="http://trailers.apple.com/trailers/independent/deadawake/"><span style="font-size: 16px; font-weight: 900; text-decoration: underline;">Dead Awake - Trailer</span></a><br /> <span style="font-size: 12px;">DEAD AWAKE is a seductive supernatural thriller starring Rose McGowan, Amy Smart and Nick Stahl set against the backdrop of a mysterious tragedy that shattered their lives a decade ago and which sets them on a path to uncover the truth that lies between the living and the dead.<br /><b>Directed by:</b> Omar Naim<br /><b>Starring:</b> Nick Stahl, Rose McGowan, Amy Smart, Ben Marten, Kim Grimaldi, Brian Lynner, Justin Marxen, James Serpento, Jack Mishler, Shane Simmons, Rachel Storey, Justin Urich, Andrea Leon, Livia Milano, Phyllis Mumford</span></td> </tr> </table> ]]></content:encoded> </item> Similar Tutorialsi want to change the content of my div tag dynamically using javascript in PHP. I am using the following technqiue but it is not working. <?php echo "<script type='text/javascript'>\n"; echo "document.getElementById('mydiv').innerHTML = 'contents of div.......';"; echo "</script>"; ?> please guide me how can i do this Thanks, Best Regards, Nice Candy. HI I am trying to find solutions on how i am able to embed IP Screenshots into a website. Right now i am able to do so but only if i am connected to a certain internet network, then i would be able to see those IP Screenshots images. However if i am not connected to that network, the website are not able to show them. THANKS ALOT!! OK, I've seen this done both ways and want to know which (if any) is the most secure way to do it... I've been coding my pages using echo statements to write HTML, such as: <?php echo "<p><strong>hello, World!</strong></p>"; echo "<p>You a $age year(s) old!</p> "; ... ?> and so on... but is this any better <?php <p><strong>Hello World!</strong></p> echo "<p><strong>You are $age year(s) old!</p>"; ?> Is one of these methods better than the other (using ECHO to write actual HTML statements out rather than just embedding them in the script without ECHO)? Which is the recommended method? Hello. I've asked around in many places now, and I thought I'd ask here too. A few days ago I installed phpBB3 on my site, works like a charm. I used a plugin for wordpress to integrate phpbb to wordpress, all works great. Now my problem is to embed the forum to my wordblog page. I tried using a simple iFrame solution, and it worked almost, but there's a common iFrame problem. The height, it doesn't scale with the embedded page, instead it stays as a 100px high frame with a scroll bar. I've searched google for hours now, and tried every possible javascript and css/div-tag solution I came across. Nothing works. Are there any alternatives to this? I tried using <?php include('../phpBB3/index.php') ?> But I get errors. It might be because I'm including from another directory, so it might be worth giving a try to give the direct path somehow, but how? Anyway, are there any other solutions for this problem? I'm not sure if this is possible
Previously I had a problem of outputting rows of a specific query
This was the solution that was given to me
$txt .= $date . " " . $stratoparse . "\n\n";Where a while loop's results were concatenated to a single string What I would like to do is output the results in individual containers with controls such as dragging for repositioning / an x for deletion That's not what I'm here for in this post I want to embed youtube videos, so they are not just stored as links, rather a clickable video so if you have something like string.string2.string3.string4.string5.<iframe src="youtube"...>.string7.string8 how would that video be isolated and parsed / understood as a front end youtube video ? To provide a brief background in case you are wondering why in my right mind, I would want to do this... First it is the primary solution that comes to mind going off what already works Secondly, the purpose or point of the concatenated string comes from the "application" design which is a store and recall interface. Vague, I know. The website has multiple users and they all have access to a single database. They save random strings, whether they are paragraphs or links, possibly videos that are uploaded, etc... these are saved by a keyphrase, later recalled by searching that keyphrase. Currently the output is nothing more than a concatenated string, that was fine initially but some of my friends have been testing the website and they made suggestions which are good such as repositioning and deleting entries. Now I want to automatically parse youtube links into embedded videos... I'll probably use that explode "function" to disect the link and place the url within the src=" " Anyway, I have to look into this but if anyone has any thoughts I'd appreciate it. Edited by moose-en-a-gant, 11 January 2015 - 02:05 AM. Is there a performance or security issue when embedding HTML code to be written to a page using a series of ECHO statements within PHP? Here's two examples: <?php // Some PHP code echo "<p>Hello, World</p>\n"; // More php code ?> versus: <?php> // Some PHP script commands ?> <p>Hello World\n"; <?php // More PHP code ?> Is there a performance issue or potential security flaw that would make the first example any worse/better than the second? (Is one method more "secure" than the other method, I guess is what I'm asking?) I like the ease of just throwing in HTML within a PHP script without having toe escape quote marks, etc. But, I'm a bit concerned about security since whatever technique I use will be incorporated into a "commercial" production website. Hello All,
I am strugling with embending standard smtp code within the one I have. As I am using PHP ocassionaly I have problem with this.
My code is to use mail function to send email through an form with email server installed on host system where the form and server are together.
I want this code to adapt to sth that can login to google account and use google external smtp protocol to send the content of the form defined in $headers
The problem is I am using self generated captcha that validates if the email is sent and all fields are filled (currently under tests what should be filled and not filled) and it works fine
This is my code that works on a local host server:
//Set up the email headers
//Set up the email content
// Required Fileds Validation
And would like sth like this in place of $mailer , but my way is not working The code I thought would be embeded into $mailer $mail->isSMTP();$mail->Host = 'smtp.googlemail.com'; //gmail SMTP server $mail->SMTPAuth = true; $mail->Username = 'GMAIL_USERNAME'; //username $mail->Password = 'GMAIL_PASSWORD'; //password $mail->SMTPSecure = 'ssl'; $mail->Port = 465; //SMTP port Any idea how to adapt it to my code are welcomed and appreciated,
Thanks
Edited April 29, 2019 by slawotrend I have this script from http://lampload.com/...,view.download/ (I am not using a database) I can upload images fine, I can view files, but I want to delete them. When I press the delete button, nothing happens
http://www.jayg.co.u...oad_gallery.php
<form>
<?php $dir = dirname(__FILENAME__)."/images/gallery" ; $files1 = scandir($dir); foreach($files1 as $file){ if(strlen($file) >=3){ $foil = strstr($file, 'jpg'); // As of PHP 5.3.0 $foil = $file; $pos = strpos($file, 'css'); if ($foil==true){ echo '<input type="checkbox" name="filenames[]" value="'.$foil.'" />'; echo "<img width='130' height='38' src='images/gallery/$file' /><br/>"; // for live host //echo "<img width='130' height='38' src='/ABOOK/SORTING/gallery-dynamic/images/gallery/ $file' /><br/>"; } } }?> <input type="submit" name="mysubmit2" value="Delete"> </form>
any ideas please?
thanks
Ok, I have a GD image that is then rewrote as a png. My question is, is it possible to find out what site is requesting the image and then use it on the php image. Example, if I didn't want a domain to use my images, could I somehow me able to restirict that site? Hi guys I just want to know something. With php you can handle excel files by saving them as .csv files. Then the php script reads it line by line, and commas separating the fields. But is it possible that I can insert an image (small jpg or png) file in one of these fields...and then handle the image in the php script? Just for intrest I inserted an image in excel worksheet and it did not insert it into a cell, it float. Is there maybe another to insert it in the cell and then control it with php?? Thanx in advance Hey every i'm just trying to change my 'Read More' text after a blog post on my site into am image. Got some code that lets me change the actual text to something else, just can't find how to change the text into an image. Code: [Select] add_filter( 'the_content_more_link', 'child_content_more_link', 10, 2 ); function child_content_more_link( $more_link, $more_link_text ) { return str_replace( $more_link_text, 'my new read more text', $more_link ); } Thanks, Matty44m Ok, so i've managed to upload images, but now i'm trying to rename them to avoid replacement and i've done something like this: mysql_query( "INSERT INTO `softmarket`.`internet_securitate` (`internet_securitateID`, `nume_produs`, `descriere`, `versiune`,`poza`, `pret`, `disponibilitate_produs`) VALUES ('', '$_POST[titlu]', '$_POST[descriere]', '$_POST[versiune]', '$foto', '$_POST[pret]', '$_POST[disponibilitate]');"); Code: [Select] function findexts ($filename) { $filename = strtolower($filename) ; $exts = split("[/\\.]", $filename) ; $n = count($exts)-1; $exts = $exts[$n]; return $exts; } $ext = findexts ($_FILES['foto']['name']) ; $ran2 = $foto."."; $target = "../images/"; $target = $target . $ran2.$ext; while (file_exists($target)) { $ran2 = 'copyof'.$ran2; $target = $target . $ran2.$ext; } if(move_uploaded_file($_FILES['foto']['tmp_name'], $target)) { echo "The file has been uploaded as ".$ran2.$ext; } else { echo "Sorry, there was a problem uploading your file."; } header('Location: succes.php'); but it renames them in a wierd way...what is wrong? Hi, There are 10 images in a folder called "Images". All images are named like 1.jpg, 2.jpg, 3.gif, 4.png, and so on... I am using these images on my website with this link: MyDomain.com/Images/1.jpg Now what i want to do is change the image every minute. from 1... to ...10 all images one by one, every minute... Link should remain same, but it should give different image every time. and if someone copies my link of image, it still gets changed every minute. i hope to get some help, better with some example code... Thanks! This topic has been moved to Application Design. http://www.phpfreaks.com/forums/index.php?topic=346417.0 I have a site where I need to have lets call it image1 displayed, then I want to change this image based on a php if statement, for instance: if $var == $var2 change the image ....blah blah so I was also going to have the names of my images stored in my database, i.e. image1.jpg and image2.jpg in my database. the image is in its own div tag set as the background image of the div tag if that makes any diference. Thanks Ok I have finally got rid of my syntax errors with this upload script. Now im getting the error uploading your image. My folders are called project_files and project_thumbs. This is my script <?php $results = ""; error_reporting(E_ALL); ini_set("display_errors", 1); //Auto Thumbnail Function function create_thumbnail($source,$destination, $thumb_width) { $size = getimagesize($source); $width = $size[0]; $height = $size[1]; $x = 0; $y = 0; if($width> $height) { $x = ceil(($width - $height) / 2 ); $width = $height; } elseif($height> $width) { $y = ceil(($height - $width) / 2); $height = $width; } $new_image = imagecreatetruecolor($thumb_width,$thumb_width) or die('Cannot initialize new GD image stream'); $extension = get_image_extension($source); if($extension=='jpg' || $extension=='jpeg') $image = imagecreatefromjpeg($source); if($extension=='gif') $image = imagecreatefromgif($source); if($extension=='png') $image = imagecreatefrompng($source); imagecopyresampled($new_image,$image,0,0,$x,$y,$thumb_width, $thumb_width,$width,$height); if($extension=='jpg' || $extension=='jpeg') imagejpeg($new_image,$destination); if($extension=='gif') imagegif($new_image,$destination); if($extension=='png') imagepng($new_image,$destination); } //Get Extension Function function get_image_extension($name) { $name = strtolower($name); $i = strrpos($name,"."); if (!$i) { return ""; } $l = strlen($name) - $i; $extension = substr($name,$i+1,$l); return $extension; } //Random Name Function function random_name($length) { $characters = "abcdefghijklmnopqrstuvwxyz01234567890"; $name = ""; for ($i = 0; $i < $length; $i++) { $name .= $characters[mt_rand(0, strlen($characters) - 1)]; } return "image-".$name; } $images_location = "/project_files/"; $thumbs_location = "/project_thumbs/"; $thumb_width = "100"; $maximum_size = "5000000"; //Check And Save Image if($_POST) { if($_FILES['image']['name'] == ""){ $results = "Please select the image you would like to upload by clicking browse"; } else{ $size=filesize($_FILES['image']['tmp_name']); $filename = stripslashes($_FILES['image']['name']); $extension = get_image_extension($filename); if($size > $maximum_size) { $results = "Your file size exceeds the maximum file size!"; } else if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) { $results = "Only the following extensions are allowed. 'jpg', 'jpeg', 'png', 'gif'."; } else { $image_random_name=random_name(15).".".$extension; $copy = @copy($_FILES['image']['tmp_name'], $images_location.$image_random_name); if (!$copy) { $results = "Error while uploadin your image! Please try again!"; } else{ create_thumbnail($images_location.$image_random_name,$thumbs_location.$image_random_name, $thumb_width); $results = "Your image has been uploaded!"; } } } } ?> and the form Code: [Select] <html> <head> <title>test</title> </head> <body> <?php echo $results; ?> <form action="#" method="post" enctype="multipart/form-data"> <input type="hidden" name="MAX_FILE_SIZE" value="5000000" /> <input type="file" name="image" /> <input type="submit" value="Upload Image" /> </form> </body> </html> Hello all , I am facing a problem when trying to to show image files generated from php code in IE8 . it is working fine on firefox and IE9 . but in IE8 its showing the famous red X instead of the image ; belw is the code: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html dir="RTL" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:v="urn:schemas-microsoft-com:vml" lang="en-us" > <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/> <head> <title>header </title> <link rel="stylesheet" type="text/css" href="style.css" /> </head> <body> <?php mb_internal_encoding('UTF-8'); /** * @author IT Department * @copyright 2011 */ INCLUDE ("header.php"); INCLUDE ("connect.php"); if (isset($_GET['id'])) { $ID=$_GET['id']; $sql="select employees.USER_ID, employees.NAME_ARAB, employees.NAME_ENG, employees.TITLE_ARAB, employees.TITLE_ENG, department.DEP_NAME_ENG, department.DEP_NAME_ARAB, location.LOC_DESC_ENG, location.LOC_DESC_ARAB, employees.MOBILE, employees.EMAIL, employees.DEP, employees.LOC FROM employees,location,department WHERE employees.DEP=department.DEP_ID AND employees.LOC=location.LOC_ID and employees.USER_ID=$ID "; //echo $sql; $result=mysql_query($sql,$link); mysql_query("SET NAMES 'utf8'"); ECHO '<html DIR="RTL">'; echo "<table width=100% border='1' cellpadding='8' align='center' bgcolor='white'>"; while ($row = mysql_fetch_array($result, MYSQL_NUM)) { //$row = mysql_fetch_assoc($result); echo"<tr align='center'>"; echo"<td>"; ECHO " الرقم الوظيفي :"; echo"</td>"; echo"<td colspan='2'>"; ECHO "<strong>$row[0]</strong>"; echo"</td>"; echo"<td>"; ECHO " : User ID "; echo"</td>"; echo"<td rowspan='7'>"; ECHO "<img src='IMAGE.php?id=".$row[0]."' width='225' height='300'/>"; //the image echo"</td>"; echo "</tr>"; the php image file is : Code: [Select] <?php INCLUDE ("connect.php"); $ID = "'".$_GET['id']."'"; $sql="SELECT PHOTO FROM employees WHERE USER_ID=$ID"; $result=mysql_query($sql,$link); $row = mysql_fetch_array($result); header("Content-type: image/pjpeg"); print ( $row[0]); ?> Thanks in advance for your help Hi all, while I was coding a script for my website something struck me which ive not really got an idea how to code it, but anyway, in my Database ive got a table which holds image URL's but how could I echo them out in PHP which will show the image? Not just the writing. Thanks for your help. Hi, I have this upload script that uploads a file and writes path to DB: Code: [Select] <?php $uploadDir = '../uploads/'; if(isset($_POST['upload'])) { foreach ($_FILES as $file) { $fileName = $file['name']; $tmpName = $file['tmp_name']; $fileSize = $file['size']; $fileType = $file['type']; if($fileName==""){ $filePath = '../img/none.jpg'; } else{ $filePath = $uploadDir . $fileName; } if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); $filePath = addslashes($filePath); } $fileinsert[]=$filePath; } ?> this works fine for a single image, but I eed to upload 2 images with a single submission....any ideas how to do this? Thanks I am designing a web site which will dynamically generate labels which will be printed out by the end user. I have coded the part which generates each label into an image, but sometimes a user will want to print multiple copies of the same label on a page. I am working on the basis of an A4 page initially and depending on the design of the label, they will be different sizes (but they wont be mixing different designs on a single page so for each a4 sheet, every label will be the same size). I have no idea how to go about the dynamic arranging of images onto the page without them being half chopped off. Ideally they will just be arranged onto a HTML page which I can just add a print button to. Any suggestions are most welcome |
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