PHP - Match Post Variable To Data In Database: Simplest Script Will Not Work!
Hi all,
Thanks for reading. I'm hella frustrated at this script I wrote: for some reason, it will not work correctly. Basically, it works. The first 4 names in the table on the database show up when searched. But, anything past these four names in the database will not show up as a result when searched! I'm pulling my hair out here! It's really simple - take a gander: Code: [Select] if (isset($_POST['submit'])) { $search = $_POST['search']; $searchQuery = mysql_query("SELECT * FROM Accounts WHERE FullName='$search'"); if (mysql_num_rows($searchQuery) == 0) { $result = "Your search returned no results. Please try again."; } else { $results = 1; while ($getSearchResults = mysql_fetch_array($searchQuery)) { $fullName = $getSearchResults['FullName']; $result = "Name: ".$fullName.""; } } } ?> ...and the HTML form... Code: [Select] <form action="search.php" method="post"> <p>Search: <input type="text" name="search" size="35" maxlength="100" /></p> <p><input type="submit" value="Search" name="submit" /></p> <?php echo $result; ?> </form> Does anyone have any ideas? Similar TutorialsUsing Javascript, how do I do an alert and show the value of a variable? thanks Iv tried asking a lot of people and have had no luck resolving this issue, so I will try here. I have created a Form which gathers its information from a Database. The first form is a Dropdown Option, which when submitted takes you to another page. The new page is Supposed to use the value from the Dropdown to search the database and return the proper rows to populate a few text areas to edit the values. This is where I am stuck. Compared to what most of you create this is probably sloppy and not too well structured, but I am new to this. Anyways, I will provide more information below now. The following is the initial page with the first form. This is where you would select what page you wish to edit. (I believe this may be where the issue resides) - (I included the 'num' value before the 'name' value so that I could see it is getting the value from the database, which it is) <form method="post" action="pageedit.php"><br /> <?php include "config.php"; echo "<select name=\"page\">\n"; $conn = mysql_connect("localhost", "$username", "$password"); if (!$conn) { echo "Unable to connect to DB: " . mysql_error(); exit; } if (!mysql_select_db("$database")) { echo "Unable to select $database: " . mysql_error(); exit; } $sql = "SELECT * FROM sitePages"; $result = mysql_query($sql); if (!$result) { echo "Could not successfully run query ($sql) from DB: " . mysql_error(); exit; } if (mysql_num_rows($result) == 0) { echo "No rows found, nothing to print so am exiting"; exit; } while ($row = mysql_fetch_assoc($result)) { echo "<option value='"; echo $row['num']; echo "'>"; echo $row['num']; echo " - "; echo $row['name']; echo "</option>"; } echo "</select>"; ?> <br /> <input type="submit" /> </form> And then the following is the page that the form is sent to when submitted: (I have attempted to Echo the 'num' value sent so that I could verify that it is indeed sent, but it is not. I will post the message I receive after the PHP snippet <form method="post" action="pageeditinsert.php"><br /> <?php include "config.php"; echo $_POST['num']; $num=$_POST['num']; $conn = mysql_connect("localhost", "$username", "$password"); if (!$conn) { echo "Unable to connect to DB: " . mysql_error(); exit; } if (!mysql_select_db("$database")) { echo "Unable to select $database: " . mysql_error(); exit; } $sql = "SELECT * FROM sitepages WHERE num = '$num'"; $result = mysql_query($sql); if (!$result) { echo "Could not successfully run query ($sql) from DB: " . mysql_error(); exit; } if (mysql_num_rows($result) == 0) { echo "No rows found, nothing to print so am exiting"; exit; } while ($row = mysql_fetch_assoc($result)) { echo "<input name'num' type='hidden' class='form1' value='"; echo $num; echo "' maxlength='10' id='cat' /><br /><br /><br />"; echo "<input name='name' type='text' class='form1' value='"; echo $row['name']; echo "' maxlength='20' id='name' /><br /><br />"; echo "<input name='desc' type='text' class='form1' value='"; echo $row['desc']; echo "' maxlength='100' id='desc' /><br /><br /><br />"; echo "<input name='title' type='text' class='form1' value='"; echo $row['title']; echo "' maxlength='100' id='title' /><br /><br /><br />"; echo "<input name'cat' type='hidden' class='form1' value='cat' maxlength='3' id='cat' /><br /><br /><br />"; } ?> <br /><br /><br /> <center><input type="submit" /><input type="reset" /></center> </form> Below is the message I receive when attempting to echo the POSTed 'num' value: Quote Notice: Undefined index: num in C:\wamp\www\gondieCOM\editor\edit\pageedit.php on line 16 Call Stack # Time Memory Function Location 1 0.0025 687600 {main}( ) ..\pageedit.php:0 (I am running the latest WAMP release on my personal PC for testing purposes until I have finished this and upload it to my hosting server) Anyways thanks for your time. Hopefully someone has an idea for me. I've managed to isolate a problem I'm having with my php script. It would seem the script randomly restarts itself with blank post data while it's running. I've managed to mimick the problem using a very basic php script which just pauses and writes to a log: <?php $q = $_POST['q']; if ($q==""){ writelog ("MISFIRE!!!"); die; } writelog("\n*** Error check started ***"); for ($i = 1; $i <= 50; $i++) { writelog ($i); sleep(rand(2,20)); } function writelog($towrite) { $tdate=date('d/m/Y H:i:s'); $file = 'log/testlog.txt'; $current = $towrite." --- ".$tdate."\n"; file_put_contents($file, $current, FILE_APPEND); } writelog("*** Error check ended ***"); ?>To rule out any problems with my AJAX htmlhttp requests, I simply send the script some irrelevant post data using Chrome's Advanced Restful client. This is the ouput of the log from an example test run: *** Error check started *** --- 05/06/2014 18:27:30 1 --- 05/06/2014 18:27:30 2 --- 05/06/2014 18:27:44 3 --- 05/06/2014 18:27:49 4 --- 05/06/2014 18:27:59 5 --- 05/06/2014 18:28:04 6 --- 05/06/2014 18:28:22 7 --- 05/06/2014 18:28:33 8 --- 05/06/2014 18:28:39 9 --- 05/06/2014 18:28:52 10 --- 05/06/2014 18:29:08 11 --- 05/06/2014 18:29:22 12 --- 05/06/2014 18:29:30 13 --- 05/06/2014 18:29:43 MISFIRE!!! --- 05/06/2014 18:29:46 14 --- 05/06/2014 18:29:56 15 --- 05/06/2014 18:30:07 16 --- 05/06/2014 18:30:09 17 --- 05/06/2014 18:30:15 18 --- 05/06/2014 18:30:32 19 --- 05/06/2014 18:30:52 20 --- 05/06/2014 18:30:54Note the logged "Misfire" after the 13th entry. This shows the script tried to run again with blank post data, the same problem I'm having in my more complex script. Why could this be happening? It's not anyone else calling the script, nobody knows about the site and I've ruled it out by logging the IP in my real script. Edited by holdorfold, 05 June 2014 - 02:29 PM. ok..ive done this a million times..i have a working example here and i copied it and amended it for this new project but for some reason i cant get a form to post data to another page. this is the error message i get Notice: Undefined index: username in C:\wamp\www\uni\fyp\site\mobile\login.php on line 16 Notice: Undefined index: password in C:\wamp\www\uni\fyp\site\mobile\login.php on line 17 here is my form code: <form method="post" action="login.php"> <table align="center" cellpadding="0" cellspacing="0"> <tr> <td style="vertical-align:top;">Username: </td><td><input type="text" name="username" value="" /></td> </tr> <tr> <td style="vertical-align:top;">Password: </td><td><input type="password" name="password" value="" /><br /><input type="submit" id="submit" value="Login" /></td> </tr> </table> </form> and here is the code within the login.php where the form should post to $username = $_POST['username']; $password = $_POST['password']; // Help protect against MySQL injection $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); // Selecting data from database where correct username and password are found $sql="SELECT * FROM customer WHERE username='$username' and password='$password'"; $result=mysql_query($sql) or die(mysql_error()); i cant see anything wrong..been looking for hours...please please help me Hi, i'm basically having problems with this code, its for a newsletter script which added the email address into a file, i'm trying to convert it to work with mysql but having a few problems; I've edited the last bit, the code just basically doesn't add it to the database even though i thought i had done it right... any help is very much appreciated! If email is not valid the script is letting me know; if email is valid it says "already added to the list" no matter what. old script <?php /** BY WebResourcesDepot - http://www.webresourcesdepot.com*/ /** YOU CAN EDIT HERE*/ $newsletterFileName = "file.txt"; /** IMPORTANT: EDIT BELOW UNLESS YOU KNOW WHAT YOU ARE DOING*/ function GetField($input) { $input=strip_tags($input); $input=str_replace("<","<",$input); $input=str_replace(">",">",$input); $input=str_replace("#","%23",$input); $input=str_replace("'","`",$input); $input=str_replace(";","%3B",$input); $input=str_replace("script","",$input); $input=str_replace("%3c","",$input); $input=str_replace("%3e","",$input); $input=trim($input); return $input; } /**Validate an email address. Provide email address (raw input) Returns true if the email address has the email address format and the domain exists. */ function validEmail($email) { $isValid = true; $atIndex = strrpos($email, "@"); if (is_bool($atIndex) && !$atIndex) { $isValid = false; } else { $domain = substr($email, $atIndex+1); $local = substr($email, 0, $atIndex); $localLen = strlen($local); $domainLen = strlen($domain); if ($localLen < 1 || $localLen > 64) { // local part length exceeded $isValid = false; } else if ($domainLen < 1 || $domainLen > 255) { // domain part length exceeded $isValid = false; } else if ($local[0] == '.' || $local[$localLen-1] == '.') { // local part starts or ends with '.' $isValid = false; } else if (preg_match('/\\.\\./', $local)) { // local part has two consecutive dots $isValid = false; } else if (!preg_match('/^[A-Za-z0-9\\-\\.]+$/', $domain)) { // character not valid in domain part $isValid = false; } else if (preg_match('/\\.\\./', $domain)) { // domain part has two consecutive dots $isValid = false; } else if (!preg_match('/^(\\\\.|[A-Za-z0-9!#%&`_=\\/$\'*+?^{}|~.-])+$/', str_replace("\\\\","",$local))) { // character not valid in local part unless // local part is quoted if (!preg_match('/^"(\\\\"|[^"])+"$/', str_replace("\\\\","",$local))) { $isValid = false; } } } return $isValid; } $email = GetField($_GET['email']); $pass = validEmail($email); if ($pass) { $f = fopen($newsletterFileName, 'a+'); $read = fread($f,filesize($newsletterFileName)); If (strstr($read,"@")) { $delimiter = ";"; } if (strstr($read,$email)) { echo 3; } else { fwrite($f, $delimiter . $email); echo 1; } fclose($f); } else { echo 2; } ?> edited script <?php /** BY WebResourcesDepot - http://www.webresourcesdepot.com*/ /** YOU CAN EDIT HERE*/ $newsletterFileName = "file.txt"; /** IMPORTANT: EDIT BELOW UNLESS YOU KNOW WHAT YOU ARE DOING*/ function GetField($input) { $input=strip_tags($input); $input=str_replace("<","<",$input); $input=str_replace(">",">",$input); $input=str_replace("#","%23",$input); $input=str_replace("'","`",$input); $input=str_replace(";","%3B",$input); $input=str_replace("script","",$input); $input=str_replace("%3c","",$input); $input=str_replace("%3e","",$input); $input=trim($input); return $input; } /**Validate an email address. Provide email address (raw input) Returns true if the email address has the email address format and the domain exists. */ function validEmail($email) { $isValid = true; $atIndex = strrpos($email, "@"); if (is_bool($atIndex) && !$atIndex) { $isValid = false; } else { $domain = substr($email, $atIndex+1); $local = substr($email, 0, $atIndex); $localLen = strlen($local); $domainLen = strlen($domain); if ($localLen < 1 || $localLen > 64) { // local part length exceeded $isValid = false; } else if ($domainLen < 1 || $domainLen > 255) { // domain part length exceeded $isValid = false; } else if ($local[0] == '.' || $local[$localLen-1] == '.') { // local part starts or ends with '.' $isValid = false; } else if (preg_match('/\\.\\./', $local)) { // local part has two consecutive dots $isValid = false; } else if (!preg_match('/^[A-Za-z0-9\\-\\.]+$/', $domain)) { // character not valid in domain part $isValid = false; } else if (preg_match('/\\.\\./', $domain)) { // domain part has two consecutive dots $isValid = false; } else if (!preg_match('/^(\\\\.|[A-Za-z0-9!#%&`_=\\/$\'*+?^{}|~.-])+$/', str_replace("\\\\","",$local))) { // character not valid in local part unless // local part is quoted if (!preg_match('/^"(\\\\"|[^"])+"$/', str_replace("\\\\","",$local))) { $isValid = false; } } } return $isValid; } $email = GetField($_GET['email']); $pass = validEmail($email); if ($pass) { $user_name = "_db"; $password = ""; $database = "_db"; $server = "localhost"; $db_handle = mysql_connect($server, $user_name, $password); $db_found = mysql_select_db($database, $db_handle); if ($db_found) { $SQL2 = "SELECT * FROM newsletter WHERE email = '$_GET[email]'"; $result = mysql_query($SQL2); mysql_close($db_handle); } if (strstr($SQL2,$email)) { echo 3; } else { $user_name = "_db"; $password = ""; $database = "_db"; $server = "localhost"; $db_handle = mysql_connect($server, $user_name, $password); $db_found = mysql_select_db($database, $db_handle); if ($db_found) { $SQL = "INSERT INTO newsletter (email,subscribed) VALUES ('$_GET[email]',1)"; $result = mysql_query($SQL); mysql_close($db_handle);} echo 1; } } else { echo 2; } ?> Hello all, I can't get the data store in the $ART_ID variable to pass into the database. The original $Artisan variable is set up like this: 1. Artisan Name. So the explode is taking just the number. If I put an echo after the explode and the $ART_ID variable it outputs the correct information but it doesn't store in the database as that data. The query is in correct order too. Thanks in advance. $CType_Type = $_REQUEST["CTYPE_Type"]; $Artisan = $_REQUEST['Artisan']; $Quantity = $_POST['Quantity']; $HAnswer1 = $_POST["HAnswer1"]; $HAnswer2 = $_POST["HAnswer2"]; $HAnswer3 = $_POST["HAnswer3"]; $HAnswer4 = $_POST["HAnswer4"]; $break = explode(".", $Artisan); $ART_ID = $break[0]; if(!$Quantity) { die('Quantity field is empty. Please enter the quantity of handicrafts made.'); } else { $ctypeQuery = mysql_query("SELECT CTYPE_ID FROM CraftType WHERE CTYPE_Type = '".$CType_Type."'"); while($row = mysql_fetch_array($ctypeQuery)) { $CTYPE_ID = $row["CTYPE_ID"]; $sql = ("INSERT INTO Handicraft VALUES (`HANDI_ID`, '".$Quantity."', 'NULL', '".$CTYPE_ID."', '".$ART_ID."', 'NULL', '1')"); if(!mysql_query($sql)) { die('Error inserting Handicraft Type into table: ' . mysql_error()); } else { -----data in this section doesn't affect the rest of the code---- } } } HI, according to my knowledge session_destroy() function would destroy all session variables and mysql_close() would close connection with the database. i make a simply logoff.php file and close myssql connection and destroy session. but i still get values from the database and session variables. and doesnt work properly here is the code Code: [Select] <?php session_start(); /* * To change this template, choose Tools | Templates * and open the template in the editor. */ require_once '../database/db_connecting.php'; $dbname="sahansevena";//set database name $con= setConnections();//make connections use implemented methode in db_connectiong.php mysql_select_db($dbname, $con); //update the time and date of the admin table $update_time="update admin set last_logged_date =CURDATE(), last_log_time=CURTIME() where username='$uname'limit 3,4"; //my admin table contain 5 colums they are id, username,password, last_logged_date, last_log_time $link= mysql_query($update_time); // mysql_select_db($dbname, $link); //$con=mysql_connect('localhost', 'root','ijts'); $result="select * from admin where username='a'"; $result=mysql_query($result); mysql_close($con); //here i just check after closing data baseconnection whether i do get reselts but i do, why? echo "after the cnnection was closed"; echo "<html>"; echo "<table border='1' cellspacing='1' cellpadding='2' align='center'>"; echo "<thead>"; echo"<tr>"; echo "<th>"; echo ID; echo"</th>"; echo" <th>";echo Username; echo"</th>"; echo"<th>";echo Password; echo"</th>"; echo"<th>";echo Last_logged_date; echo "</th>"; echo "<th>";echo Last_logged_time; echo "</th>"; echo" </tr>"; echo" </thead>"; echo" <tbody>"; while($row= mysql_fetch_array($result,MYSQL_BOTH)){ echo "<tr>"; echo "<td>"; echo $row[0]; echo "</td>"; echo "<td>"; echo $row[1]; echo "</td>"; echo "<td>"; echo $row[2]; echo "</td>"; echo "<td>"; echo $row[3]; echo "</td>"; echo "<td>"; echo $row[4]; echo "</td>"; echo "</tr>"; } echo" </tbody>"; echo "</table>"; echo "</html>"; session_destroy(); session_commit(); echo "session and database are closed but i still get values".$_SESSION['admin']; ?> Hey, sorry I'm a newb so prepare for me to do everything wrong even though I read the FAQ.
I'm trying to use a simple php script to input data to register but I get this error:
"Failed to run query: SQLSTATE[HY093]: Invalid parameter number: parameter was not defined" once I fill out the form.
I've seen other people get this error but I seem to have different problems to them and can't figure it out.
My PHP script is just
<?php require("config.inc.php"); //if posted data is not empty if (!empty($_POST)) { if (empty($_POST['username']) || empty($_POST['password'])) { $response["success"] = 0; $response["message"] = "Please Enter Both a Username and Password."; die(json_encode($response)); } $query = " SELECT 1 FROM users WHERE username = :user"; $query_params = array( ':user' => $_POST['username'] ); try { $stmt = $db->prepare($query); $result = $stmt->execute($query_params); } catch (PDOException $ex) { die("Failed to run query: " . $ex->getMessage()); $response["success"] = 0; $response["message"] = "Database Error. Please Try Again!"; die(json_encode($response)); } $row = $stmt->fetch(); if ($row) { die("This username is already in use"); $response["success"] = 0; $response["message"] = "I'm sorry, this username is already in use"; die(json_encode($response)); } $query = "INSERT INTO users ( username, password ) VALUES ( :user, :pass ) "; $query_params = array( ':username' => $_POST['username'], ':password' => $_POST['password'] ); try { $stmt = $db->prepare($query); $result = $stmt->execute($query_params); } catch (PDOException $ex) { die("Failed to run query: " . $ex->getMessage()); $response["success"] = 0; $response["message"] = "Database Error. Please Try Again!"; die(json_encode($response)); } $response["success"] = 1; $response["message"] = "Username Successfully Added!"; echo json_encode($response); } else { ?> <h1>Register</h1> <form action="index.php" method="post"> Username:<br /> <input type="text" name="username" value="" /> <br /><br /> Password:<br /> <input type="password" name="password" value="" /> <br /><br /> <input type="submit" value="Register New User" /> </form> <?php } ?>and the config: <?php $username = "root"; $password = ""; $host = "localhost"; $dbname = "drinkdealz"; $options = array(PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES utf8'); try { $db = new PDO("mysql:host={$host};dbname={$dbname};charset=utf8", $username, $password, $options); } catch(PDOException $ex) { die("Failed to connect to the database: " . $ex->getMessage()); } $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $db->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC); if(function_exists('get_magic_quotes_gpc') && get_magic_quotes_gpc()) { function undo_magic_quotes_gpc(&$array) { foreach($array as &$value) { if(is_array($value)) { undo_magic_quotes_gpc($value); } else { $value = stripslashes($value); } } } undo_magic_quotes_gpc($_POST); undo_magic_quotes_gpc($_GET); undo_magic_quotes_gpc($_COOKIE); } header('Content-Type: text/html; charset=utf-8'); session_start(); ?>Sorry if I uploaded anything wrong and it's only a localhost so I don't really care about passwords etc (none will be the same when I upload it) So if any of you can even point me in the direction of what to look for that would be brilliant. Cheers, Kieran I'm trying to make the simplest login and this isnt working can someone explain why? thanks if ($_POST['user'] == 'admin' && $_POST['pass'] != '1234') { echo "fail"; } else { echo "win"; no matter what I do it says win Hello, I am trying to replace a url and add a sub-id to it, however I'm not quite there. Any help is always appreciated here. In the end, I would like the value of gotoUrl to have the cpId 123abc45 attached to it.
I.E.
http://example.com/?Aff=56732&SID=123abc45 http://example.com/?Aff=56732&uv=123abc45&product=1834234 http://example.com/?Aff=56732&cid=123abc45&ace=2gs244s3 $gotoUrl = "http://example.com/?Aff=56732&SID="; // OR could be listed as such: // $gotoUrl = "http://example.com/?Aff=56732&uv=default&product=1834234"; // $gotoUrl = "http://example.com/?Aff=56732&cid=&ace=2gs244s3"; // Will attach this to replace value $cpId = "123abc45"; // Possible sid replacements, depending on the url $sidList = array("sid","SID","cid","uv"); if ($gotoUrl){ foreach($sidList as $sidVar){ if (preg_match("/$sidVar/i", $gotoUrl)){ $gotoUrl = preg_replace("#{$sidVar}(?=.*\d)(?=.*[a-z])(?=.*[A-Z])$#", "{$sidVar}={$cpId}", $gotoUrl); } } echo $gotoUrl; } Edited by iwpg, 13 August 2014 - 10:36 PM. Hello, how do you search for a filename containing a date and then match it to a variable? Please note the filename may only contain some of the variable being matched to. Any help appreciated... $post='{"cart_items":[{"configuration":{"price":100,"recharge_number":"9999999999"},"product_id":"999","qty":1}]}';i try this n reslut was :There are no valid items in cart: help me plz Edited by ShivaGupta, 30 November 2014 - 01:11 AM. Hello to all, I have problem figuring out how to properly display data fetched from MySQL database in a HTML table. In the below example I am using two while loops, where the second one is nested inside first one, that check two different expressions fetching data from tables found in a MySQL database. The second expression compares the two tables IDs and after their match it displays the email of the account holder in each column in the HTML table. The main problem is that the 'email' row is displayed properly while its while expression is not nested and alone(meaning the other data is omitted or commented out), but either nested or neighbored to the first while loop, it is displayed horizontally and the other data ('validity', 'valid_from', 'valid_to') is not displayed.'
Can someone help me on this, I guess the problem lies in the while loop? <thead> <tr> <th data-column-id="id" data-type="numeric">ID</th> <th data-column-id="email">Subscriber's Email</th> <th data-column-id="validity">Validity</th> <th data-column-id="valid_from">Valid From</th> <th data-column-id="valid_to">Valid To</th> </tr> </thead> Here is part of the PHP code:
<?php while($row = $stmt->fetch(PDO::FETCH_ASSOC)) { echo ' <tr> <td>'.$row["id"].'</td> '; while ($row1 = $stmt1->fetch(PDO::FETCH_ASSOC)) { echo ' <td>'.$row1["email"].'</td> '; } if($row["validity"] == 1) { echo '<td>'.$row["validity"].' month</td>'; }else{ echo '<td>'.$row["validity"].' months</td>'; } echo ' <td>'.$row["valid_from"].'</td> <td>'.$row["valid_to"].'</td> </tr>'; } ?>
Thank you. Why isn't this working? function friendFunction(){ v=$("Donald"); $.post('./action/friendaction.php',{ user:v.val()},function(d){ alert(d) }); }It works if I change it to user:"bob" though. Hi guys, I pretty new to php, and was writing a small script after a I read a chapter (4) about if-statements of a book. But it seems I am doing something wrong. Maybe someone could help me in the right direction. In a nutshell: I have a small form, and when someone presses submit it should go to another page and include the variables of the previous page. So far I am only been able to include html form variables which I recover on the next page with $_POST['xxxx']; here under ill Put a part of my script which is not of any use, but its more for me to understand how to get php variables on the next page. I am using a self referencing script and i have some comments added to read along. Code: [Select] <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>bla bla bla</title> </head> <body> <?php //code to be executed when monkey button pressed if (isset($_POST['monkey'])){ echo $_POST[$number1]; echo 'monkey pressed'; } //code to be executed when snakes button pressed if (isset($_POST['snakes'])){ echo $_POST[$number1]; echo 'snakes pressed'; } ?> <h1>bla bla bla</h1> <h3> <?php $number1 = $number1.mt_rand(1,100000); echo $number1; ?> </h3> <form action="<?php echo $_PHP['PHP_SELF']; ?>" method="post"> <input type="submit" value="monkey" name="monkey" /> <input type="submit" value="snakes" name="snakes" /> </form> </body> </html> What is the most effect approach to doing this? Code: [Select] <?php $catid = $_POST['catid']; if($catid = "Automotive"){ $catid = '3'; } if($catid = "Business"){ $catid = '4'; } if($catid = "Careers"){ $catid = '5'; } if($catid = "Education"){ $catid = '6'; } if($catid = "Financial"){ $catid = '7'; } if($catid = "Government"){ $catid = '8'; } if($catid = "Health"){ $catid = '9'; } if($catid = "Mobile"){ $catid = '10'; } if($catid = "Organization"){ $catid = '11'; } if($catid = "Programming"){ $catid = '12'; } if($catid = "Software"){ $catid = '13'; } if($catid = "Travel"){ $catid = '14'; } if($catid = "Web"){ $catid = '15'; } if($catid = "Other"){ $catid = '16'; } if($catid = "Gaming"){ $catid = '17'; } ?> I tried this and it works; Code: [Select] <?php $catid = "Automotive"; if($catid = "Automotive"){ $catid = '3'; } echo $catid; ?> But... When I add another if statement... Code: [Select] <?php $catid = "Automotive"; if($catid = "Automotive"){ $catid = '3'; } if($catid = "Gaming"){ $catid = '17'; } echo $catid; ?> It echos $catid as 17 and not 3 which is defined as a variable. I hope there is a simple solution for this! Thanks in advanced! Hi, I've currently started to modify a chat script of mine to output a moderation panel but the moderation page seems empty(blank) every time I load it. What im trying to do is to take the ID part in my URL via the $_GET and look it up in my database table in the column named id, then select that specific row to be able to retrieve the StringyChat_ip and place it into another table to ban the IP and the second thing im trying to do is to be able to delete the specific row from my table.
My Http link look something like
http://imagecrab.fre.../ban.php?id=159
and my ban.php page where I want to lookup the 159 part and do the banning etc looks like
<? include("admin_code_header.php"); if ($_POST["DeletePost"]) { $id = $_POST['id']; $query = "DELETE FROM ".$dbTable." WHERE id='".$id."'"; mysql_query($query); echo "ID removed from system: ".$id; } if ($_POST["BanIP"]) { $IP_To_Add = $_POST["ip"]; $sql = "INSERT INTO ".$IPBanTable." (ip) VALUES (\"$IP_To_Add\")"; $result = mysql_query($sql); } $result = mysql_query("SELECT * FROM ".$dbTable." WHERE id='".$id."'",$db); while ($myrow = mysql_fetch_array($result)) { $msg = $myrow["StringyChat_message"]; $idm = $myrow["id"]; ?> <html> <form name="form<? echo $myrow["id"];?>" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input name="DeletePost" type="submit" id="DeletePost" value="Delete"> <input name="BanIP" type="submit" id="BanIP" value="Ban <? echo $myrow["StringyChat_ip"];?>"> </form> </html> <? } ?> hi guys, im new to this forum I'm new also to php, I need help from you guys: I want to display personal information from a certain person (the data is on the mysql database) using his name as a link: example: (index.php) names 1. Bill Gates 2. Mr. nice Guy i want to click Bill Gates (output.php) Name: Bill Gates Country:xxxx Age: xx etc. How can i make this or how to learn this? I know this should be easy... I have several text input boxes where I enter data to be sent to one column of my database. Code: [Select] [while($row = mysql_fetch_array( $result )) { $i=1; if ($row['game_id']='$i') { echo "<tr>"; echo "<td>"; echo $row['date']; echo "</td><td>"; echo $row['team_name']; echo "</td><td>"; echo $row['owner']; echo "</td><td>"; echo "<input type='text' size='4' name='result[]'>"; echo "</td></tr>"; Not every box has a value so my array will end up with several numbers and several "blanks". I echoed the array using Code: [Select] $result = ("$_POST[result]"); and all the values are returned as expected. Now I need to UPDATE the "pt_spread" column in the database inserting all the values (even the blank values). I tried the following but can't get it to actually post anything into the database. Code: [Select] <?php header("Location: admin_main_entry.php"); include("opendatabase.php"); $result = ("$_POST[result]"); foreach ($result as $spread) { $sql = " UPDATE schedule SET pt_spread = '$spread' WHERE week_id = '$weekID'" ; mysql_query($sql); } mysql_close($con) ?>Can anyone show me the correct way to do this? Thanks. |