PHP - Define Another Database?

Imagine a site programmed using full OOP.

Where would you store information like this:

$companyName = "ABC Ltd";
$companyPhone = "02476 999 999";
$companyAddress etc...

Would you just define them in the public scope? (and use global or pass them in when needed??)

Is there a better way?

They will be needed in more places than just a navigation bar and would be needed by more than one class.

Ive got a simple function that's counting percentages of the results, and what I want is when the first line does $variable / 100 - to go on 2 decimals(ex. 0.72142141 what I want is to write 0.72).

Code: [Select]
function postotak(){
$p = $bodovi / 100;
$postotak = $p * 100;

im doing it wrong can some one help me ? , thanks
{
Code: [Select]
define('userlevel'( 9="admin" , 1="guest"));}

I'm being told I have an undefined variable.   Similar to sumUsagekWH (in the code below) there are other placeholders called sumUsageKHW, sumUsageWKWp, sumUsageWKWi and so on.  Each script of code looks similar to below where the 'totalUsage' is added into sumUsageKHW, sumUsageKHE and so on.  All references are highlighted red below to make it easier to follow.    So, if I am only using these sumUsagesXXXX's as placeholders for the following post....   <input name="electric_charge_total" type="hidden" id="electric_charge_total" value="<?php echo number_format($basic_charge + ($sumUsageKWH * $energy_charge) + ($sumUsageWKWp * $peak_rate) + ($sumUsageWKWi * $intermediate_rate) + ( ($sumUsageWKW+$sumUsageWEW) * $base_rate),"2"); ?>" align="right"/>   how to I define them in PHP?    Based on the code below, they are only used as a way to introduce totalUsage ( it looks silly the way it was done, but later the code will be expanded so it makes sense).  What I mean is that totalUsage is being entered (in the below case) into sumUsageKWH from the $sumUsageKWH += $row[totalUsage]   Notice: Undefined variable: sumUsageKWH in C:\xampp1\htdocs\Utrack\invoice.php on line 73

<?php
$sql = ";WITH TOTAL_KWH_WINTER AS
(
SELECT CONVERT(VARCHAR(10),cdate,111)AS trans_date, datepart(hh, cdate) as trans_hour, comm_id,
MIN((total_energy_a+total_energy_b+total_energy_c)/100) AS minUsage,
MAX((total_energy_a+total_energy_b+total_energy_c)/100) AS maxUsage, meter_multiplier
  FROM [radiogates].[dbo].[purge_data] LEFT OUTER JOIN [radiogates].[dbo].[ops_invoice] on [radiogates].[dbo].[purge_data].[comm_id] = [radiogates].[dbo].[ops_invoice].[meter_id] 
  where comm_id='$comm_id'and meter_multiplier is not null 
  group by comm_id, CONVERT(VARCHAR(10),cdate,111), datepart(hh, cdate), meter_multiplier
)
SELECT *, datepart(weekday, trans_date) as trans_date_day, datepart(month, trans_date) as 
 
trans_date_month, ((maxUsage - minUsage)*meter_multiplier) as totalUsage
FROM TOTAL_KWH_WINTER 
 
where datepart(weekday, trans_date) IN ('1', '2', '3', '4', '5', '6', '7') 
AND DATEPART(MONTH, trans_date) IN ('10','11','12','1','2','3','4') 
and trans_date BETWEEN '$startdate2 00:00:01' AND '$enddate2 24:00:00' ";
$query = sqlsrv_query($conn, $sql);
if ($query === false){  exit("<pre>".print_r(sqlsrv_errors(), true));}while ($row = sqlsrv_fetch_array($query))
{   $sumUsageKWH += $row[totalUsage];}sqlsrv_free_stmt($query);?> 

 

I am trying to use absolute path across my project excluding the domain as of now and I am trying to do it as follows:


Code: [Select]
    define('root', '/php_projects/myproject/');


    // The Standard Data

    $path = "path.php";
    $connectvars = "connectvars.php";
   
   
   
    // The CSS Styles

    $reset_css = root . "view/reset.css";
    $style_css = root . "view/style.css";
This works so far, the only problem I am having is that it is producing a notice. And my question is, how can I get rid of the notice?

The notice is this one:

Code: [Select]
Notice: Constant root already defined in C:\xampp\htdocs\php_projects\myproject\path.php on line 3
Why does the notice get produced in first place? I never defined it twice, as it states.

How come I cannot do this?

define('IMG_EXT', array("jpg", "jpeg", "png", "gif", "bmp", "tif"), true);

<HTML>

<?php

 $arr = array("sue" => "betsy", "frank" => "marge");

?>

</HTML>


This produces the following HTML page:

"betsy", "frank" => "marge");

Its like when I use the => to make my associative array, the code thinks I'm closing the php codeblock and then just prints the rest of it to the screen...

<?php if (isset($_SESSION['first_name'])) { echo "<div id=\"login_status\">Welcome, Daniel | <a href=\"BASE_URL sm-login/panel\">My Account</a> | <a href=\"BASE_URL sm-login/logout\">Logout</a></div><!-- Show If Logged In -->"; } ?>

this is my code but BASE_URL is a define variable containing = http://localhost/ when i run the script php treats it as just BASE_URL
 e.g. BASE_URL%20sm-login/pane.php not http://localhost/sm-login/panel.php

i know the define is working cos i echo it out earlyer

I would like to know how to use an underscore in a define function like this example below.

Code: [Select]
/** The name of the database for WordPress */
define('DB_NAME', 'Database_name');

/** MySQL database username */
define('DB_USER', 'User_name');

/** MySQL database password */
define('DB_PASSWORD', 'password_here');

/** MySQL hostname */
define('DB_HOST', 'Dtabase_host');


Any help appreciated and thanks in advance.

My goal was to create a constant that could be included on the pages, that no matter where it was located in the structure, would be able to find the template files, css, images, etc.  using the following code:

Code: [Select]
if($_SERVER['HTTP_HOST'] == "localhost"){
    define('SITEURL', 'http://' . $_SERVER['HTTP_HOST']);
    define('SITEPATH', $_SERVER['DOCUMENT_ROOT']);
    define('CSS', $_SERVER['DOCUMENT_ROOT'] . '/css/');
    define('IMAGES', $_SERVER['DOCUMENT_ROOT'] . '/images/');
}
else{
    define('SITEURL', 'http://' . $_SERVER['HTTP_HOST']);
    define('SITEPATH', $_SERVER['DOCUMENT_ROOT']);
    define('TEMPLATE', $_SERVER['DOCUMENT_ROOT'] . '/incs/template/');
    define('CSS', $_SERVER['DOCUMENT_ROOT'] . '/css/');
    define('IMAGES', $_SERVER['DOCUMENT_ROOT'] . '/images/');
}

I put the above in a variables.php file that is in the includes folder (named incs) and I call it using the typical include statement.

The problem is that when I use the constant to grab the CSS file, its not working when using:

Code: [Select]
<link rel="stylesheet" href="<?php echo CSS . "template.css" ?>" type="text/css" media="screen" />

I can view the page source and it has the path right, but I cannot figure out how to get it to actually pull in the css file.  I know the echo command is not correct, at least I dont think it is, but have not been able to figure out any other way.

Also, is there a better way to define the constants to the file locations and have it automatically detect whether its on the test server or production and then be able to reference those locations no matter where it is in the structure?

Hi , how I can save something into form?
I mean , insert something in variable  and than insert it into value in the form so when i send the form the value will be send too.
I also want that it will be can not change.
for example :

<input name="email" value="a@s.d"/>

but this example can be change if you insert something else.

thanks , Mor.

I have a main file index.php into which iam loading myinnerpage.php. I have defined a variable inside index.php & checks it on myinnerpage.php, but when i load innerpage it shows restricted access, any idea why? following is my code.

index.php
Code: [Select]
<?php
    define( '_JEXEC', true ); 
?>
<div class="mypage">
</div>
<ul>
    <li><a href="#" onclick="loadpages('myiinerpage.php')">about page</a></li>   
</ul>

<script type="text/javascript">
    var $jq = jQuery.noConflict();
    function loadpages(page)
    {
        $jq('.mypage').load('myfolder/'+page);
    }
   
</script>

and now in the myiinerpage.php which is in the folder myfolder i have the following code.

Code: [Select]
<?php
defined('_JEXEC') or die('Restricted access');
?>

<div>
my page elements
</div>



but when i click on the link it shows restricted access. I have loaded jquery too, any idea y this is happening?

Is this proper PHP...

    function setHeat(Building $b) {
        $this->hotness = $b->getInsideHeat();
    }

That looks more like Java to me.  I thought you didn't define data-types anywhere in PHP?!


TomTees

As you can see here I have the following code

Code: [Select]
<?php
session_start();

session_register('hazard2');

//INITIALIZE ERROR VARIABLES
$errorFound = false;
$errorIcon['hazard2'] = '';

if (isset($_POST['submitbutton'])) { 

//SET SESSION VARIABLES
$_SESSION['hazard2'] = $_POST['hazard2'];

     //TEST FORM INFORMATION
     if(count($_POST['hazard2']) != 3) {
        $errorFound = true;
$errorIcon['hazard2'] = 'Error Question 2';
     }
    
     //IF NO ERRORS WERE FOUND, CONTINUE PROCESSING

     if (!$errorFound) {
header( "Location: hazardresult.php" );
}

     }

?>
It's lazy I know, but the script is on a file called hazard2.php, is there anyway to have all of the hazard2's in the code come from the file name. So when I make hazard3, I don't have to change all the hazard2's to hazard3's

Thank you

Been googling this for hours now and I can't find something that doesn't give a parse error.

I found this thread: http://www.phpfreaks.com/forums/index.php?topic=160855 ..and tried to work around the answer but with no luck.

All I really want to do is something like this:

<td class="

<?php
if ($time<20:00&>1:00) { echo "class1";}
else if($time>20:00&<2:00) { echo "class2";}?>

"></td>

I want the class to change to another one if the user see the table cell within a specific hour of the day.