PHP - Query Help Needed. Count Number Of Days.

I have this block of code that was written by someone years ago :-

<?php

	class BoDelivery {
		
		public function EstimatedDays($off, $standard_days, $saturday, $delay) {
            
            $today = date("N"); // Weekday - number 1-7
            $now = strtotime("now"); // Unix
            
            $off_array = explode(":", str_replace(".", ":", $off));
            
            $off_unix = mktime($off_array[0], $off_array[1], "00", date("n"), date("j"), date("Y"));

            $sending_days_from_now = 0;
            if ($now > $off_unix) {
                $sending_days_from_now++;
            }
            $sending_day = $today + $sending_days_from_now;
            switch ($sending_day) {
                case 6:
                    $sending_days_from_now++;
                    $sending_days_from_now++;
                    break;
                case 7:
                    $sending_days_from_now++;
                    break;
            }
            $sending_day = $today + $sending_days_from_now;

            // Estimated delivery time
            $delivery_days = $standard_days;
            $over_weekends = 0;

            // Add Delay
            if ($delay) {
                $delivery_days = $delivery_days + $delay;
            }
			            
            if ($sending_day == 5 && !$saturday) {
                $delivery_days++;
                $delivery_days++;
                $over_weekends++;
            }
            
            $delivery_day = $sending_day + $delivery_days;

            switch ($delivery_day) {
                case 6:
                    if (!$saturday) {
                        $delivery_days++;
                        $delivery_days++;
                        $over_weekends++;
                    }
                    break;
                case 7:
                    $delivery_days++;
                    $over_weekends++;
                    break;
            }
            
            if ($over_weekends == 0 && $delivery_days > 5) {
                $delivery_days++;
                $delivery_days++;
            }
            
            $delivery_day = $sending_day + $delivery_days;
            
            switch ($delivery_day) {
                case 13:
                    $delivery_days++;
                    $delivery_days++;
                    $over_weekends++;
                    break;
                case 14:
                    $delivery_days++;
                    $over_weekends++;
                    break;
            }
            
            $delivery_day = $sending_day + $delivery_days;
            
            $delivery_days = $delivery_day - $today;
            			
			return $delivery_days;
			
		}
		
	}
	
?>

Which is supposed to calculate the number of days for delivery, taking into account weekends & with a delay variable that we can set.

It isn't working as expected, may never have worked(??) or maybe down to PHP upgrades.

For example, if today (18th)I set the delay to 2 days the delivery estimate is the 21st (which is correct), if I change the delay to 3 OR 4 it becomes the 24th, 5 then becomes the 26th!

I can't get my head around the code at all, I wonder if someone could assist in what may be going on or add comments to the code snippets so I can maybe work it out?

Thanks for any help.

Hi, I have this code :-

$datestarted = $row['datestarted'];
$datestart=date("l d/m/Y @ H:i:s",strtotime($datestarted)); 

Which is been echo'd like this :-

echo '
<tr align="center"'.$rowbackground.'>
<td>'.$datestart.'</td>							
<td align="center">
';

So for example I get this output :-Sunday 18/04/2021 @ 10:45:26

The data in the DB for the above is stored like this :-2021-04-18 10:45:26

What I'd like to do is also echo how many days ago this date was, all of the examples I've tried don't seem to work though?

I've tried several scripts to get the number of days between two dates, but none of them will work. Obviously I'm doing something wrong. One thing I know that is causing a problem is that I'm using variables instead of an actual typed in date. Which in my opinion is how most people would do it - variables not actual dates.

I've tried these:

$todaydate = date('Y/m/d');
$now = date('Y-m-d');
$dd2 = strtotime($now);
$thisyear = 2019;
$payment_day = 29;
$pay_month = 6;

if($pay_month == 1){$newpaymentmonth = 2;}
if($pay_month == 2){$newpaymentmonth = 3;}
if($pay_month == 3){$newpaymentmonth = 4;}
if($pay_month == 4){$newpaymentmonth = 5;}
if($pay_month == 5){$newpaymentmonth = 6;}
if($pay_month == 6){$newpaymentmonth = 7;}
if($pay_month == 7){$newpaymentmonth = 8;}
if($pay_month == 8){$newpaymentmonth = 9;}
if($pay_month == 9){$newpaymentmonth = 10;}
if($pay_month == 10){$newpaymentmonth = 11;}
if($pay_month == 11){$newpaymentmonth = 12;}
if($pay_month == 12){$newpaymentmonth = 1;}

$threezero = array(4, 6, 9, 11); // months with 30 days

// Deal with months that have only 28 days or 30 days, setting the payment day to accommodate months with fewer days.
if ($payment_day > 28 && $pay_month == 2)
{
    $payment_day = 28;
}
elseif ($payment_day == 31 && in_array($pay_month, $threezero))
{
    $payment_day = 30;
}
else
{
    $payment_day = $payment_day;
}

if ($newpaymentmonth == 1){$newpaymentyear = $thisyear + 1;}else{$newpaymentyear = $thisyear;}
$newpaymentdate = date($newpaymentyear.'-'.$newpaymentmonth.'-'.$payment_day);
echo date("Y-m-d", $newpaymentdate) . "<br><br>";

$ddate = new DateTime($thisyear.'-'.$newpaymentmonth.'-'.$payment_day);
$ddate->add(new DateInterval('P5D'));
echo $ddate->format('Y-m-d') . " - New month payment date with 5 day grace period added.<br><br>";

Now, how to calculate the difference in days between today's date and $ddate? I tried the below, but none worked.
 

function DateDiff($strDate1,$strDate2){
return (strtotime($strDate2) - strtotime($strDate1))/  ( 60 * 60 * 24 );  // 1 day = 60*60*24
}
echo "Date Diff = ".DateDiff($now,$ddate)."<br>";

$timeDiff = abs($now - $ddate);
$numberofdays = $timeDiff/86400;
echo "<p>$numberofdays - days between today's date and payment w/grace date.</p>";

$date1 = $now;
$date2 = $ddate;
$diff = date_diff($date1,$date2);
echo 'Days Count - '.$diff->format("%a");

$date1=$now;
$date2=$ddate;
function dateDiff($date1, $date2)
{
      $date1_ts = strtotime($date1);
      $date2_ts = strtotime($date2);
      $diff = $date1_ts - $date2_ts;
      return round($diff / 86400);
}
$dateDiff= dateDiff($date1, $date2);
printf("Difference between in two dates : " .$dateDiff. " Days ");
print "</br>";

This one returns 18112 Days. Should be days 7 days from 2019-08-05.

None of these work, so I'm doing something wrong. Any ideas?

Thanks