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PHP - Stop Re-submit On Form On Page Refresh
Hi All,
Is there any way that PHP can detect if a page has been refreshed? Basically I have a form that when submitted, inserts a row in to a database, but I am finding that when I refresh the page, it repeats the insert statement. Any ideas? Thanks Matt Similar TutorialsHello, I'm having trouble figured out how to do this... Basically I want update.php to run after the user hits the 'update' button, and after update.php runs (which will take about 60 seconds) I want the index.php to reload. How can this be done? thanks! <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>Server List</title> </head> <body> <?php $mlink = @mysql_connect("localhost","user","pass"); mysql_select_db("dbname", $mlink); $result = mysql_query("SELECT * FROM ServerList"); while($row = mysql_fetch_array($result)){ echo $row['HostName']. " - ". $row['UsedSlots']. " / ". $row['MaxSlots']; echo "<br />"; } ?> <br/> <br/> <form action="update.php" method="post"> <button type="submit">update</button> </form> </center> </body> </html> Hi Guys, Im trying to create a registration form so users can sign up to my website, however i have noticed that when the page is refreshed the form automatically submits. Please could somebody help me stop this? Thanks <body> <form name="registration_form" method="post" onsubmit="return Validate();"> First Name: <input type="text" name="first_name"><br /> Last Name: <input type="text" name="last_name"><br /> Email: <input type="text" name="email"><br /> Confirm Email: <input type="text" name="confirm_email"><br /> Username: <input type="text" name="username"><br /> Password: <input type="password" name="password"><br /> Confirm Password: <input type="password" name="confirm_password"><br /> <input type="submit" value="Register"> </form> <?php $connect=mysql_connect("localhost","leemp5_admin","p7031521"); mysql_select_db("leemp5_database",$connect) or die (mysql_errno().":<b> ".mysql_error()."</b>"); $insert_query = 'insert into users (username,first_name,last_name,email,password) values ( "' . $_POST['username'] . '", "' . $_POST['first_name'] . '", "' . $_POST['last_name'] . '", "' . $_POST['email'] . '", "' . $_POST['password'] . '" )'; mysql_query($insert_query); ?> </body> This may not the best place to post this but I'm sure quite a few people here can help. I have an a tag which uses the event trigger "onClick" However when I click on this link the page refreshes. Is there anyway I can stop this? I have copied my code below. <a href=\"#\" class=\"" . $a[$i] . "\" onClick=\"locationValue('" . $a[$i] . "', '" . $_GET['search_type'] . "')\"> The following code works. The user checks off what foods they want to be added. Then the foods and their nutrient values get added into the database. However, if the user refreshes, it updates the database with the values they selected before - thus doubling the amount of foods stored in the database. How do I stop this from happening? Right now i'm taking values from the POST array and running an INSERT SQL query to put them into the database. (look for the following comment below: //Look here PHPFREAKS.COM) Code: [Select] <?php include 'top.php'; ?> <?php if (!loggedin()) {//1 if start header('Location: need-to-log-in-mmp.php'); }//1 if end ?> <title>My Meal Planner - Vitamin K Tracker</title> </head> <div id="container"> <?php include 'header.php'; ?> <?php include 'nav.php'; ?> <div id="content-container"> <div id="content_for_site"> <h2>My Meal Planner</h2> <br /> My Meal Que: <br /> <ul> <form action="my-meal-planner.php" method="POST"> <?php //do sql query to return the foods and nutrients that a person added to their que $query = "SELECT DISTINCT foods.id, `name`, `source`,`vit_k`, `cal`,`protein`, `fiber`, `carbs`, `sugar`, `sodium`, `chol`, `total_servings` FROM `foods` LEFT JOIN users_foods ON foods.id=users_foods.food_id WHERE users_foods.user_id =". $_SESSION['user_id']." ORDER BY users_foods.id"; $query_run = mysql_query($query, $link); //echo mysql_errno($link) . ": " . mysql_error($link). "\n"; while ($row = mysql_fetch_array($query_run)){ ?> <input type="checkbox" name="<?php echo $row["id"]; ?>"<?php echo ' value="'.$row["id"].'" />'; echo ' Food Name: '. $row["name"]." | Vitamin K: ". $row["vit_k"]." | Fiber: ". $row["fiber"]." | Calories: ". $row["cal"]." | Protein: ". $row["protein"]." | Carbs:". $row["carbs"]." | Sugar: ". $row["sugar"]." | Sodium: ". $row["sodium"]." | Cholesterol: ". $row["chol"]." | Source: ". $row["source"]." | Total Servings: ". $row["total_servings"]. "<br />How many servings will you have? "?><input type="text" name="<?php echo $row["id"]."serving"; ?>"<?php echo ' />'; echo '<br /><br />'; } ?> </ul> Select a date: <input id="date" type="text" name="add_to_calendar"><br /> <input type="submit" value="add to calendar" ><br /> <input type="button" value="delete" name="delete"> </form> <?php //updates the date of the food if (isset($_POST['add_to_calendar']) && !empty($_POST['add_to_calendar'])){ $add_to_calendar = $_POST['add_to_calendar']; $date_array = explode("/", $add_to_calendar); //Look here PHPFREAKS.COM for ($i=1; $i<1000; $i++){ if (!empty($_POST[$i])){ $id = $_POST[$i]; $serv = $id. "serving"; $serving = $_POST[$serv]; $month = $date_array[0]; $day = $date_array[1]; $year = $date_array[2]; //echo 'month: '. $month . ' day: ' . $day . ' year: ' . $year . "<br />"; if (substr($month,0,1) == '0'){ //takes out a zero in front of month if it exists $month = substr($month,1,1);} if (substr($day,0,1) == '0'){ //takes out a zero in front of day if it exists $day = substr($day,1,1);} //echo 'POST ARRAY READS AS: <br />'; //print_r($_POST); //echo '<br />'; $query = "INSERT INTO `users_calendar` VALUES ('','".$_SESSION['user_id']."','".$id."','".$month."','".$day."','".$year."','".$serving."')"; //echo '<br /> The query reads as: ' . $query; $query_run = mysql_query($query) or die(mysql_error()); //columns in users_calendar: //DONEid DONEuser__id DONEfood_id DONEcalendar_month DONElendar_day DONEcalendar_year servings } } } ?> <br /> </div> <script type="text/javascript" src="js/datepicker.js"></script> <div id="clear"></div> <?php //include 'footer.php'; ?> </div> </div> </body> </html> hi i hv a form to submit on this url http://localhost/site/index.php?action=search and in my html <form method="GET" action="<?php echo $_SERVER['PHP_SELF'];?>" name="searchForm"> // my code </form> // i also tried //http://localhost/site/index.php?action=search& // but did not helped now problem is i wants to go that URL so after submit it should look a like this as i am loading search page with action. http://localhost/site/index.php?action=search&searchstring=word but it keeps me redirecting to http://localhost/site/index.php?searchstring=word how can i make it work so it will goto this URL http://localhost/site/index.php?action=search&searchstring=word Thanks for help. I have the website he http://bossexclusive.com/babyauction/index.php , and http://bossexclusive.com/babyauction/thanks.php . When you press submit on the index.php, it takes you to thanks.php. then, after 5s, it takes you back to index.php. My question is: How could I make it so when I press submit, the box submits the form, but instead of redirecting to thanks.php, it displays the same thank you message on the side, but stays on index.php? If that didn't make sense, let me know. My html and php are below (HTML) Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Baby Auction | Discounted Premium Brand Baby Products</title> <link rel="stylesheet" type="text/css" href="styles.css"/> </head> <body> <div id="main"> <div id="contact"> <h1>Sign up to recieve Auction notifications</h1> <form action="emailer.php" method="post"> <input type="text" name="email" id="email" placeholder="yourname@email.com" /> <input type="image" name="submit" src="images/submit.jpg" width="146px" height="20px" value="Submit"> </form> </div> </div> <div class="copyright"> <?php include 'footer.php'; ?> </div> </body> </html> and emailer.php: Code: [Select] <?php $email = trim(strip_tags($_POST['email'])); $subject = "Contact form submitted!"; $to = 'BlankingOutMyEmail@gmail.com'; $body = <<<HTML $message HTML; $headers = "From: $email\r\n"; $headers .= "Content-type: text/html\r\n"; mail($to, $subject, $body, $headers); header('Location: thanks.php'); ?> I have two pages. one is insert_events.php and the other is veiw_events. In insert_events i have a form which have a submit button. I want when i click on the submit button, it redirects me to the view_events.php page showing the events. Any idea about this problem will be appreciated. Thanks I am creating a user inbox system. I am retrieving all the unread messages. Each message row contains a "reply" form. So say I have 10 messages showing on a single page. That's 10 forms. What I would like to know is how can I submit any one of the 10 forms and not have it affect the remaining 9 forms? Here is the basic code.
if(isset($_POST['submit'])) {
$post_message = trim($_POST['message']);
$errors = array();
$db->beginTransaction();
if(empty($post_message)) {
$errors[] = 'The message field can not be empty!';
}
if(empty($errors)) {
$db->commit();
echo 'success';
} else {
$db->rollBack();
}
}
<form action="" method="post">
<fieldset>
<textarea name="message" maxlength="10000" placeholder="What would you like to say?"></textarea>
</fieldset>
<fieldset>
<input type="submit" name="submit" value="Submit" />
</fieldset>
</form>
Hi Guys, I am fairly new to PHP, and I recently changed my whole site to use PHP sessions, which worked fine. Then I added PHP parts in my pages that display different menu choices depending on if a PHP session exists. This also works fine, until I found that any HTML/PHP pages that have form/submits no longer work, and I get kicked back to the index.php After slow backtracking, I removed new parts, and found the forms started working again if I removed the PHP part that chooses which JavaScript file to reference, as follows from contact.php <?php if (isset($_SESSION['SESS_MEMBER_ID'])){ echo "<script language=\"JavaScript\" type=\"text/javascript\" src=\"menu_horz.js\"></script>"; } else {echo "<script language=\"JavaScript\" type=\"text/javascript\" src=\"log_menu_horz.js\"></script>"; } ?> I tried changing the echo ".." to use single quotes ' ' instead, but then it doesn't work at all then with a form or no form on the page. I assume I am doing something wrong, but I can't find any resources that give me a definitive way of referencing Javascript files. What freaked me out was only the ones with forms were an issue. I am using <?php session_start(); ?> at the beginning of every page (before any output). Other PHP code on the page is working fine. Only the above part seems to be the problem, and works too, as long as I don't submit a form. - Could it be more weirder :-) - I tried also to find a workaround, but it would mean having PHP inside my JavaScript file, but I am not sure it would work, since JS is client side, and PHP server... Essentially, I just want to run certain JS menus depending if the person is logged in or not. - Example contact.php attached Any ideas of what the problem might be with the code above? Will be grateful for any help you can give. Regards D I have two pages one is db.php and another is form.php. In form.php i have created a form which contains different fields and a submit button. But i want to write the queries in db.php. And when i click on the submit button the insert query in db.php should be executed and insert data in database but the focus remains on form.php. How can i do this??? Any Idea? Hi everyone, as the title stated, I would like to know how I could submit a form in one page(cart) and unset a session variable on other page.
Right now my form is setting a variable within the page back to 0, however I would like the form to unset the session variable from other page as well.
The issue with my code is that every time I attempt to clear out all items, my code can empty out the cart. But whenever I close and reopen the cart, the same content will show up again. So I need to unset the session variable.
Please let me know what should I do in order to solve the problem and I greatly appreciate your help.
My code is currently looking like this:
cart.php
if(!empty($_GET['aID']))
{
$aID = $_GET['aID'];
echo $aID;
if(isset($_POST['removeAll']))
{
$aID = "0";
}
$cartSQL = "SELECT * from article where aID in ($aID)";
echo "cart sql :$cartSQL";
$cartQuery = mysqli_query($dbc, $cartSQL) or die (mysqli_error($dbc));
while($row = mysqli_fetch_array($cartQuery, MYSQLI_BOTH))
{
$aTitle[] = $row[ 'name' ];
}
}
<form action = "" method = "POST">
<td style = "width = 200px"><input type="submit" value="Empty cart" name="removeAll"></td>
</form>
And this is the session variable from other page where I would like it to be unset upon submitting the form.
if(!empty($cartSubmit))
$_SESSION["cartSubmit"] = $cartSubmit;
else
$cart = $_SESSION["cartSubmit"];
<a href="javascript:popup('cart.php?aID=<?php if(empty($cartSubmit)) echo "$cart"; else echo "$cartSubmit";?>')">Cart</a>
Alright, so I play a browser game called Politics and War. I run an alliance that has 74 members. In that alliance we offer a bank service for all our members, but I - being the leader - am the only one who can access the bank. I have been building a site that works with the game API to gather data for members and create a dashboard. One of the features I am trying to build is allowing them to withdraw from their account instantly.
So, what I need: To be able to submit a POST request to login to the site (specifically on this page --> https://politicsandwar.com/login) with my username and password, but then I need to keep the session active and navigate to a different page (the alliance bank page). On that page I first need to scrape a value from a hidden input (token) and then I need to submit a POST request to this same page while still being logged in.
I am not asking someone to do it for me, but rather someone to help me know how to go about this. I have never submitted post requests with PHP, but I have used PHP cURL in the past. I also have made POST requests with JS, but never PHP.
Thank you so much for anyone that is able to help! Hello All, i could really use some coding help. I have a form that users use and submit. i'd like the page to refresh and show the new data when submit button is pressed however, right now it only shows when i manually refresh the page. here is the code, can someone please tell me what to add or take away to make it work. thanks <iframe src="http://pickthefights.com/smack/?id=<?php echo $idvar; ?>&smack=yes" width="300" height="100">;Your browser does not support iframes.</iframe> <form name="smack" method="post" action="http://pickthefights.com/smack-reg/" target="_blank" name="smack" > <input type="hidden" value="<?php echo $_SESSION[uid] ?>" name="session" > <input type="hidden" value="<?php echo $idvar ?>" name="idvar" > Smack Talk : <input type="text" name="comment" > <input value="Smack" type="submit" name="smack"> </form> Say I have an "Entries" table. I want to submit same multiple entries using a form submission. And If I have other queries submitted in the same form, I want those quarries to be submitted only once. Is that possible to do? Here's my code.
if(isset($_POST['submit'])) {
$entries = 10;
$id = 55;
$name = 'Smith';
$insert = $db->prepare("INSERT INTO entries(id, name) VALUES(:id, :name)");
$insert->bindParam(':id', $id);
$insert->bindParam(':name', $name);
$result_insert = $insert->execute();
if($result_insert == false) {
echo 'Fail';
} else {
echo 'Success';
}
}
?>
<form action="" method="post">
<input type="submit" name="submit" value="SUBMIT" />
</form>
Edited January 13, 2019 by imgrooot Hi. Pretty straight forward I guess but as the name suggests am a newbie. I have a form that requires the user to enter certain parameters. If the values are blank it submits to itself and loads the error messages. What I want to do is create PHP code that submits the form to a different url. What I thought was create two forms (the second with hidden fields replicating the first form), each form having a different url in the action"" code. What I cant work out is the PHP IF ELSE code to submit form 2 if Form1 is is validated correctly. This is the PHP code relevant to the form validation. Help? <?php //If form was submitted if ($_POST['submitted']==1) { $errormsg = ""; //Initialize errors if ($_POST[width]){ $title = $_POST[width]; //If title was entered } else{ $errormsg = "Please enter width"; } if ($_POST[drop]){ $textentry = $_POST[drop]; //If comment was entered } else{ if ($errormsg){ //If there is already an error, add next error $errormsg = $errormsg . " & content"; }else{ $errormsg = "Please enter drop"; } } } if ($errormsg){ //If any errors display them echo "<div class=\"box red\">$errormsg</div>"; } //If all fields present if ($title && $textentry){ //Do something echo 'THIS IS WHERE I WANT THE CODE TO SUBMIT FORM 2 or SUBMIT FORM 1 TO A DIFFERENT URL'; } ?> Hello. I hope one of the PHP/HTML gurus here can help me. I have a web page that has been altered a bit to add some Google Analytics stuff and I've moved it to a 2nd directory. The original one works fine, the 2nd one won't post the form when I click the submit button. 1st URL https://www.theneutralizer.info/neutralizer 2nd URL: https://www.theneutralizer.info/neutralizer2 I have changed the action property to the correct script, and it does exist. But the problem is when clicking the button nothing happens. Anyone have any ideas? I can send the PHP code if needed, but since it's HTML output, it should work the way it is displayed in the browser. David Hi I have an include page full of functions in a secure folder with htaccess. My problem is if the include file does not exsist, I get the following. Warning: include(secure/SecureFunctions.php) [function.include]: failed to open stream: No such file or directory in /home/fhlinux190/d/otoole.co.uk/user/htdocs/streetangels/index.php on line 3 Warning: include(secure/SecureFunctions.php) [function.include]: failed to open stream: No such file or directory in /home/fhlinux190/d/otoole.co.uk/user/htdocs/streetangels/index.php on line 3 Warning: include() [function.include]: Failed opening 'secure/SecureFunctions.php' for inclusion (include_path='.:/usr/share/pear-php5') in /home/fhlinux190/d/otoole.co.uk/user/htdocs/streetangels/index.php on line 3 TIA Desmond. Fatal error: Call to undefined function session_init() in /home/fhlinux190/d/des-otoole.co.uk/user/htdocs/streetangels/index.php on line 6 Is there any way to suppress this as it is giving hackers information. Hello everyone, I'm not a php coder so I really need help on a simple question... I am trying to direct users to a page in my mySQL database (http://www.educatorsoverseas.com/index.php?section=teacher&act=registration) via the button form below: <FORM METHOD="LINK" ACTION="http://www.educatorsoverseas.com/index.php?section=teacher&act=registration" target="_blank"> <INPUT TYPE="submit" VALUE="Sign Up"> </FORM> But when when users click on the button it is directing instead to the mySQL authentication page (http://www.educatorsoverseas.com/index.php?section=auth). I don't know why this is happening but can anyone tell me how to make it go to the proper page? When I copy and paste the correct page it works, so I am at a loss as to what to do. Hi guys, basically my problem is I have a jquery pop out window that holds a login form using the "require_once" function but when I enter my login details and send them, if there is another another form on the page e.g contact form it will send that form aswell so it will come up for the errors for the register form because they are empty. can anyone tell me how to stop this from happening? i have a form with two buttons, one is for submitting the form while button is for generating a random a code and placing it in a textfield. this works fine but the problem is anytime i click on the generate button, it refreshes the page thereby validating the form , which i don't want. How do i make it perform the function without refreshing the page.... |
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