PHP - Oop - Address Bar / Link Class

Hi,   I have the following submit button and would like to change it into a link with a class.  

<input type="image" alt="Click here to Continue" name="I2" src="altimages/buttons/continue.gif" id="submit">

  How would I do this using jQuery?   Thanks!

I have mysqli object in Database class base:

[color=]database class:[/color]

class Database {
  private $dbLink = null;
  
  public function __construct() {
    if (is_null($this->dbLink)) {
      // load db information  to connect
      $init_array = parse_ini_file("../init.ini.inc", true);
      $this->dbLink = new mysqli($init_array['database']['host'],
                           $init_array['database']['usr'],
                           $init_array['database']['pwd'],
                           $init_array['database']['db']);
  
      if (mysqli_connect_errno()) {
        $this->dbLink = null;
      }
    }
  }

  public function __destruct() {
    $this->dbLink->close();
  }
}


Class derived is Articles where I use object dBLink in base (or parent) class and I can't access to mysqli methods (dbLink member of base class):

Articles class:

require_once ('./includes/db.inc');

class Articles extends Database{
  private $id,
              ....
              ....
             $visible = null;
  
  public function __construct() {
    // Set date as 2009-07-08 07:35:00
    $this->lastUpdDate = date('Y-m-d H:i:s');
    $this->creationDate = date('Y-m-d H:i:s');
  }
  
  // Setter
  ....
  ....

  // Getter
  ....
  ....

  public function getArticlesByPosition($numArticles) {
    if ($result = $this->dbLink->query('SELECT * FROM articles ORDER BY position LIMIT '.$numArticles)) {
      $i = 0;
      while ($ret = $result->fetch_array(MYSQLI_ASSOC)) {
        $arts[$i] = $ret;
      }
      $result->close();
      return $arts;
    }
  }
}


In my front page php I use article class:


include_once('./includes/articles.inc');
$articlesObj = new articles();
$articles = $articlesObj->getArticlesByPosition(1);
var_dump($articles);


[color=]Error that go out is follow[/color]

Notice: Undefined property: Articles::$dbLink in articles.inc  on line 89

Fatal error: Call to a member function query() on a non-object in articles.inc on line 89

If I remove constructor on derived class Articles result don't change 
Please help me

Hi

Can you call Class A's methods or properties from Class B's methods?

Thanks.

Ok. I know you can pass the object of a class as an argument. Example:


class A {
    function test() {
        echo "This is TEST from class A";
    }
}


class B {
    function __construct( $obj ) {
        $this->a = $obj;
    }

    function test() {
       $this->a->test();
    }

}


Then you could do:

$a = new A();
$b = new B($a);


Ok so that's one way i know of.

I also thought that you could make a method static, and do this: (assuming class A's test is 'static')

class B {
    function test() {
       A::test(); 
   }
}


But that is not working.


I'd like to know all possible ways of accomplishing this. Any hints are appreciated. thanks

I have an existing instance of my class Database, now I want to call that instance in my Session class, how would I go about doing this?

If a class has a constructor but also has a static method, if I call the static method does the constructor run so that I can use an output from the constructor in my static method?

--Kenoli

Hi,

I need to be able to call a class based on variables.  E.G.

I would normally do:
Code: [Select]
$action = new pattern1()
but i would like to be able to do it dynamicaly:
Code: [Select]
$patNum = 1;
$action = new pattern.$patNum.()
Im wondering if that's possible?  If so what would the correct syntax be?

Many Thanks.

I have two classes:

## Admin.php

<?php
class Admin
{
public function __construct()
{
include("Config.php");
}

/**
* deletes a client
* @returns true or false
*/
function deleteClient($id)
{
return mysql_query("DELETE FROM usernames WHERE id = '$id'");
}
}
?>


## Projects.php

<?php
class Projects
{
public function __construct()
{
include("Config.php");
$this->admin = $admin;
$this->dataFolder = $dataFolder;
}

/**
* Deletes a project
* @returns true or false
*/
function deleteProject($id)
{
$root  = $_SERVER['DOCUMENT_ROOT'];
$theDir  = $root . $this->dataFolder;
$sql  = mysql_query("SELECT * FROM projectData WHERE proj_id = '$id'");
while ($row = mysql_fetch_array($sql))
{
$mainFile = $row['path'];
$thumb = $row['thumbnail'];
if ($thumb != 'null')
{
unlink($theDir . "/" . substr($thumb,13));
}
unlink($theDir . "/" . substr($mainFile,13));
}
$delete = mysql_query("DELETE FROM projectData WHERE proj_id = '$id'");
$getDir = mysql_query("SELECT proj_path FROM projects WHERE id = '$id'");
$res = mysql_fetch_array($getDir);
rmdir($theDir . "/" . $res['proj_path']);
return mysql_query("DELETE FROM projects WHERE id = '$id'");
}
}
?>


How can I call deleteProject() from within Admin.php?

Hi people!

class FirstOne{

public function FunctionOne($FirstInput){
//do stuff and output value
return $value1;
}

}


Then:-


class SecondOne{

public function FunctionTwo($AnotherInput){
//do stuff and output value
return $value2;
}

}


What I want to know is this, if I want to use FunctionOne() in Class SecondOne do I do it like this:-

(Assume as I have instantiated the first class using $Test = new FirstOne(); )


class SecondOne{

function SecondedFunction(){
global $Test;
return $Test->FunctionOne();
}

public function FunctionTwo($AnotherInput){
//do stuff and output value
return $value2;
}

public function FunctionThree(){

//some code here
$this->Test->SecondedFunction();<--I think as I can omit the $this-> reference
}
}


My point is: Do I have to do it this way or is there way of having this done through __construct() that would negate the need for a third party function?

I have a version working, I just think that it is a little convoluted in the way as I have done it, so I thought I would ask you guys.

Any help/advice is appreciated.

Cheers
Rw

How does one go about using one class inside another?

For example, building a class that does some series of functions, and uses a db abstraction layer class in the process?

I do know how to do this but I am curious about whether or not there is a "preferred" way to do this. I know there are a couple ways to use a class (I'll call Alpha_Class) within another class (I'll class Beta_Class)

Let's say we have this simple class (Beta_Class):

class beta {
    function foo(){
    
    }
}


If I wanted to use the Alpha Class within the Beta Class, I could any number of things. For example:

class beta {
    function foo(){
        $this->alpha = new alpha;
        //$this->alpha->bar();
    }
}


Or you could simply use the $GLOBALS array to store instantiated objects in:

$GLOBALS['alpha'] = new alpha;
class beta {
    function foo(){
        //GLOBALS['alpha']->bar();
    }
}


You could even declare Alpha_Class as a static class and thus would not need to be instantiated:

static class alpha {
    static function bar(){}
}

class beta {
    function foo(){
        //alpha::bar();
    }
}


Those are the only ways I can think of right now. Are there any other ways to accomplish this? I was wondering which way is the best in terms of readability and maintainability.

I have a class in which I have a function called connection. I am now trying to call this function from another class, but it will not work. It works if I put the code in from the other function rather than calling it but that defeats the purpous.

class locationbox

{
   function location()
   {
   
   
   $databaseconnect = new databaseconnect();
         $databaseconnect -> connection();{

$result = mysql_query("SELECT * FROM locations");

while($row = mysql_fetch_array($result)) // line that now gets the error, mysql_fetch_array() expects parameter 1 to be resource, boolean given //in
  {
  echo "<option>" . $row['location'] . "</option>";
    }
   
}
}}

Hi all,

I have two classes. Registration and Connection.

Inside a registration.php I include my header.php, which then includes my connection.php...

So all the classes should be declared when the page is loaded.

This is my code:


registration.php:

<?php include ('assets/header.php'); ?> 
        
    <?php
        class registration{                    
            public $fields = array("username", "email", "password");
            public $data = array();
            public $table = "users";
            public $dateTime = "";
            public $datePos = 0;
            public $dateEntryName = "date";
            
            function timeStamp(){
                return($this->dateTime = date("Y-m-d H:i:s"));
            }
            
            function insertRow($data, $table){      
                    
                    foreach($this->fields as $key => $value){
                        mysql_query("INSERT INTO graphs ($this->fields)
                        VALUES ('$data[$key]')");
                    }
                    
                    mysql_close($connection->connect);
            }
            
            function validateFields(){
            
                $connection = new connection(); 
                $connection->connect();
                        
                foreach($this->fields as $key => $value){
                    array_push($this->data, $_POST[$this->fields[$key]]);
                }
                $this->dateTime = $this->timeStamp();
                array_unshift($this->data, $this->dateTime);                
                array_unshift($this->fields, $this->dateEntryName);   
                
                foreach($this->data as $value){
                    echo "$value";
                }
                
                $this->insertRow($this->data, $this->table);
            }
        }
        
        $registration = new registration();
        $registration->validateFields();
    ?>

<?php include ('assets/footer.php'); ?>



At this point I cannot find my connection class defined on another included/included page.



                $connection = new connection(); 
                $connection->connect;





config.php (included within header.php)

<?
    class connection{ 
        public $dbname = '**';   
        public $dbHost = '**';
        public $dbUser = '**';
        public $dbPass = '**';
        public $connect;
        
        function connect(){
            $this->connect = mysql_connect($this->dbHost, $this->dbUser, $this->dbPass) or die ('Error connecting to mysql');
            mysql_select_db($this->dbname, $this->connect);
        }
    }
?>



Any ideas how to call it properly?

I have problem with # char in address and jquery, or any address with #.
When i put this code in my php:
<a href="#" id="dialog_link" class="ui-state-default ui-corner-all"><span class="ui-icon ui-icon-newwin"></span>Open Dialog</a>
.. my link on that button is still same like link that i am on it, it do not add "#" in address, but if i, instead of href="#", put href="#some_text", that link shows nice, link.php#some_text, but without text in # it doesn't work :S
Why is that happening, and how can i fix that?

Hello,

Please let me know what is the wrong with the following lines of code. I am trying to find the MAC Address of the user who is logging. When I am running the code in localhost it is working. But the same code is not working when I upload it in the server.


<?php
function getMac(){
exec("ipconfig /all", $output);
foreach($output as $line){
if (preg_match("/(.*)Physical Address(.*)/", $line)){
$mac = $line;
$mac = str_replace("Physical Address. . . . . . . . . :","",$mac);
}
}
return $mac;
}

$mac = getMac();
$mac = trim($mac);
echo $mac;
?>


Please help. Thanks a lot in advance.

Regards & Thanks.