PHP - Run A Php Function Before Completing A Form Submit!

Hi.  Pretty straight forward I guess but as the name suggests am a newbie.  I have a form that requires the user to enter certain parameters.  If the values are blank it submits to itself and loads the error messages.  What I want to do is create PHP code that submits the form to a different url.  What I thought was create two forms (the second with hidden fields replicating the first form), each form having a different url in the action"" code.  What I cant work out is the PHP IF ELSE code to submit form 2 if Form1 is is validated correctly.  This is the PHP code relevant to the form validation.  Help?

<?php
      //If form was submitted
      if ($_POST['submitted']==1) {
          $errormsg = ""; //Initialize errors
          if ($_POST[width]){
             $title = $_POST[width]; //If title was entered
          }
          else{
             $errormsg = "Please enter width";
          }
          if ($_POST[drop]){
             $textentry = $_POST[drop]; //If comment was entered
          }
          else{
             if ($errormsg){ //If there is already an error, add next error
                $errormsg = $errormsg . " & content";
             }else{
                $errormsg = "Please enter drop";
             }
          }
      }

      if ($errormsg){ //If any errors display them
          echo "<div class=\"box red\">$errormsg</div>";
      }

      //If all fields present
      if ($title && $textentry){
         //Do something
          
echo 'THIS IS WHERE I WANT THE CODE TO SUBMIT FORM 2 or SUBMIT FORM 1 TO A DIFFERENT URL';
      }   
      ?>

I've created a code to allow the user to change the background color and scheme of my site. However, I'm having trouble getting a random color to show up if the user has not yet set a color choice. Here's my code. Could someone put it together to make it work?

<?php
if ($_POST['change']){
$thevar = $_POST['change'];
$_SESSION['bcg'] = $thevar;
}

if(isset($_SESSION['thecolor']))
{
$thecolor = $_SESSION['thecolor'];
}
else
{
$num = rand(0,9);
if ($num == 0)
$thecolor = "0DEBDF"; // CYAN
if ($num == 1)
$thecolor = "AE00FF"; // PURPLE
if ($num == 2)
$thecolor = "FFDC01"; // YELLOW
if ($num == 3)
$thecolor = "FF6D2D"; // PEACH
if ($num == 4)
$thecolor = "20ff7f"; // LIGHTER-GREEN
if ($num == 5)
$thecolor = "00E612"; // GREEN
if ($num == 6)
$thecolor = "E6005D"; // PINK
if ($num == 7)
$thecolor = "E600CF"; // PINK-PURPLE
if ($num ==
$thecolor = "e2ff20"; // LIME
if ($num == 9)
$thecolor = "8868ff"; // LAVENDER
// send a cookie that never expires
setcookie("thecolor",$thecolor, time()+604800);
}
?>

Hello, first time poster..  I've looked the web over for a long time and can't figure this one out.

- Below is basic code that successfully checks MySQL for a match and displays result.  I was debugging and forced the "height" and "width" to be 24 and 36 to make sure that wasn't the problem.  That's good.. 
- I'd like to give the user ability to select width and height from a form.. and have it do an onchange this.form.submit so the form can be changing as fields are altered (thus the onchange interaction)
- In a normal coding environment I've done this numerous times with no "Page cannot be displayed" problems.  It would simply change one select-option value at a time til they get down the form and click submit...  but in WordPress I'm having trouble making even ONE single onchange work!
- I've implemented the plugins they offer which allows you to "copy+paste" your php code directly into their wysiwyg editor.  That works with basic tests like my first bullet point above.
- I've copied and pasted the wordpress url (including the little ?page_id=123) into the form "action" url... that didn't work...  tried forcing it into an <option value=""> tag.. didn't work.  I'm just not sure. 

I've obviously put xx's in place of private info..

Why does this form give me Page Cannot Be Displayed in WordPress every time?  It won't do anything no matter how simple.. using onchange..

Code..

$con = mysql_connect("xxxx.xxxxxxx.com","xxxxxx","xxxxx");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }
mysql_select_db("xxxxxx", $con);
$myprodwidth=24;
$myprodheight=36;
$result = mysql_query("SELECT * FROM product_sizes WHERE prodwidth='$myprodwidth' and prodheight='$myprodheight'");
while($row = mysql_fetch_array($result))
  {
  echo $row['prodprice'];
  }
mysql_close($con);


<form method="post" action="">
<select name="myheight" onchange="this.form.submit();">
<option selected="selected" value="">select height</option>
<option value="xxxxxxxxx.com/wordpress/?page_id=199&height=36">36</option>
<option value="xxxxxxxxx.com/wordpress/?page_id=199&height=36">48</option>
</select>

Hi all,

What I am trying to achieve is, I thought quite simple!

Basically, a user signs up and chooses a package, form is submitted, details added to the database, email sent to customer, then I want to direct them to a paypal payment screen, this is where I am having issues!

Is their any way in php to submit a form without user interaction? Here is my code for the form process page
Code: [Select]
<?php
include('config.php');
require('scripts/class.phpmailer.php');

$package = $_POST['select1'];
$name = $_POST['name'];
$email = $_POST['email'];
$password = md5($_POST['password']);

$domain = $_POST['domain'];
$a_username = $_POST['a_username'];
$a_password = $_POST['a_password'];


$query=mysql_query("INSERT INTO orders (package, name, email, password, domain, a_username, a_password)
VALUES
('$package', '$name', '$email', '$password', '$domain', '$a_username', '$a_password')");

if (!$query)
{
echo "fail<br>";
echo mysql_error();
}

else
{
$id = mysql_insert_id();
$query1=mysql_query("INSERT INTO customers (id, name, email, password)
values
('$id', '$name', '$email', '$password')");

if (!$query1)
{
echo "fail<br>";
echo mysql_error();
}


if($package=="Reseller Hosting")
{

//email stuff here - all works - just cutting it to keep the code short


if(!$mail->Send())
{
   echo "Message could not be sent. <p>";
   echo "Mailer Error: " . $mail->ErrorInfo;
   exit;
}
?>


<form name="_xclick" action="https://www.paypal.com/cgi-bin/webscr" method="post">
<input type="hidden" name="cmd" value="_xclick-subscriptions">
<input type="hidden" name="business" value="subscription@jollyhosting.com">
<input type="hidden" name="currency_code" value="USD">
<input type="hidden" name="item_name" value="Jolly Hosting Reseller Packages">
<input type="hidden" name="no_shipping" value="1">

<!--1st month -->
<input type="hidden" name="currency_code" value="USD"> 
<input type="hidden" name="a3" value="3.00">
<input type="hidden" name="p3" value="1">
<input type="hidden" name="t3" value="M">
<input type="hidden" name="src" value="1">
<input type="hidden" name="sra" value="1">
</form>';


<?php
}

//last
}
//end
?>

Hi-
the code below lets me upload a CSV file to my database if I have 1 field in my database and 1 column in my CSV.
I need to add to my db "player_id" from the CVS file and "event_name" and "event_type" from the form... any ideas???

here's the code:
Code: [Select]
<?php
$hoststring =""; 
$database = "";
$username = "";
$password = "";
$makeconnection = mysql_pconnect($hoststring, $username, $password);
?>
<?php
ob_start();
mysql_select_db($database, $makeconnection);
$sql_get_players="
SELECT * 
FROM tabel 
ORDER BY player_id ASC";
//
$get_players = mysql_query($sql_get_players, $makeconnection) or die(mysql_error());
$row_get_players = mysql_fetch_assoc($get_players);
//
$message = null;
$allowed_extensions = array('csv');
$upload_path = '.'; //same directory

if (!empty($_FILES['file'])) {

if ($_FILES['file']['error'] == 0) {
// check extension
$file = explode(".", $_FILES['file']['name']);
$extension = array_pop($file);

if (in_array($extension, $allowed_extensions)) {

if (move_uploaded_file($_FILES['file']['tmp_name'], $upload_path.'/'.$_FILES['file']['name'])) {

if (($handle = fopen($upload_path.'/'.$_FILES['file']['name'], "r")) !== false) {
$keys = array();
$out = array();
$insert = array();
$line = 1;

while (($row = fgetcsv($handle, 0, ',', '"')) !== FALSE) {

foreach($row as $key => $value) {    

if ($line === 1) {
$keys[$key] = $value;       
} else {       
$out[$line][$key] = $value;              
}       
}                
$line++;          
}        

fclose($handle);            

if (!empty($keys) && !empty($out)) {        
$db = new PDO(
'mysql:host=host;dbname=db', 
'user', 
'pw');   

$db->exec("SET CHARACTER SET utf8");        

foreach($out as $key => $value) {        
$sql  = "INSERT INTO `table` (`";
$sql .= implode("`player_id`", $keys);    
$sql .= "`) VALUES (";    
$sql .= implode(", ", array_fill(0, count($keys), "?"));    
$sql .= ")";    
$statement = $db->prepare($sql);    
$statement->execute($value);       
}      

$message = '<span>File has been uploaded successfully</span>';      
}
}
}
} else {
$message = '<span>Only .csv file format is allowed</span>';
}
} else {
$message = '<span>There was a problem with your file</span>';
}
}
ob_flush();?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>CSV File Upload</title>
</head>
<body>

<form class="form" action="" method="post" enctype="multipart/form-data">
<h3>Select Your File</h3>
<p><?php echo $message; ?></p>
<input type="file" name="file" id="file" size="30" />
<br/>
<label>Event Name:</label><input name="event_name" type="text" value="" />
<br/>
<label>Event Type:</label><input name="event_type" type="text" value="" />
<br/>
<input type="submit" id="btn" class="button" value="Submit" />
</form>

<br/>
<h3>Results:</h3>
<?php do { ?>
<p><?php echo $row_get_players['player_id'];?></p>
<?php } while ($row_get_players = mysql_fetch_assoc($get_players)); ?>
</body>
</html>

Hi all,
I have a regular comment section and i want the submit button to call a mysql_query function in comment.class.php
so
Code: [Select]
<form method="post" action="../php/comment.class.php?action=addcomment" name="commentform" id="commentform" onsubmit="validateForm()">
<label for "body">Your Comment</label>
<div><textarea cols="20" rows="4" name="body" id="body"></textarea></div>
<input type="submit" id="submit" value="Submit"/>

and my comment.class.php is...
Code: [Select]
function addcomment($body){
$body=mysql_real_escape_string($_POST['body']);
if($body!=''){
         mysql_query("INSERT INTO comment(uid,screenname,body) VALUES ('$_SESSION[uid]','$_SESSION[screenname]','$body')") or die('lame');
}
header("location:../index.php");
}

but when I click submit, i'm taken to a blank page with the URL: http://test/php/comment.class.php?action=addcomment

any tips? and is there a better alternative to header?

Thanks

Code: [Select]
<?php

$db = mysql_connect("localhost", "root") or die("Could not connect."); //username and password

if(!$db) 

die("no db");

if(!mysql_select_db("simple",$db)){
if(!mysql_select_db("regis",$db)){//database name

  die("No database selected.");}}
$message=$_POST['message'];


  print "<form action='registration.php' method='post'onsubmit='return msg();'>";

  print "Your message:<br>";

  print "<textarea name='message' cols='40' rows='2'></textarea><br>";

  print "<a onClick=\"addSmiley(':)')\"><img src='smile.gif'></a> ";

  print "<a onClick=\"addSmiley(':(')\"><img src='blush.gif'></a> ";

  print "<a onClick=\"addSmiley(';)')\"><img src='images/wink.gif'></a> ";

  print "<input type='submit' name='submit' value='Set Name'></form>";

  print "<script language=\"Java Script\" type=\"text/javascript\">\n";

  print "function addSmiley(a)\n";

  print "{\n";

  print "document.form.message.value += a;";

  print "document.form.message.focus();\n";

  print "}\n";

  print "</script>\n";

  print "<br><br>";
?>

 <script type="text/javascript">
 <?php
  function msg(){

if(isset($_POST['submit'])) //if submit button push has been detected

{



   if(strlen($message)<1)

   {    
    // print "You did not input a message";
      echo"<SCRIPT LANGUAGE='javascript'>alert('You did not input a message')</SCRIPT>";

   }

   else

   {

      $message=strip_tags($message);

      $IP=$_SERVER["REMOTE_ADDR"]; //grabs poster's IP

      $checkforbanned="SELECT IP from admin where IP='$IP'";

      $checkforbanned2=mysql_query($checkforbanned) or die("Could not check for banned IPS");

      if(mysql_num_rows($checkforbanned2)>0) //IP is in the banned list

      {

         print "You IP is banned from posting.";

      }

     else
      
       if(strlen($message)>=1)
       {

         $message=strip_tags($message);
         echo("<SCRIPT LANGUAGE='JavaScript'>window.alert('$message')</SCRIPT>");
        // die("<meta http-equiv=\"refresh\" content=\"0; url=registration.php\">");
       }
        $message=$_POST['message'];
         $message=strip_tags($message);
     /*   if($_POST['username'] && $_POST['pass'])
       {

         $name = mysql_query("SELECT * FROM Persons");
         $thedate = date("U"); //grab date and time of the post

         $insertmessage="INSERT into mesej (name,IP,postime,message) values('$name','$IP','$thedate','$message')";

         mysql_query($insertmessage) or die("Could not insert message");

        }     */

   }
}
return false;
}
return true;
</script>
?>







This is my code in my submit2.php im clicked submit button but if it is empty it should return an javascript alert error but why it directs through registration.php without reading the rules?

I have a simple log in form. By debugging I found that isset post submit function is not responding. It remains on the same page after submitting form. I have googled all the possible solutions to this problem but none worked. Any help is greatly appreciated. The form is in multiplelogin.php  file and the code is in multi.php file. After login redirection is to teachers.php file.

<?php

session_start();

$conn = mysqli_connect("localhost", "root",  "", "signup");

if(isset($_SESSION['username'])) {
    
    header('location: teachers.php');

    exit();
     
}

?>

<!DOCTYPE html>

<head>

  <link rel="stylesheet" type="text/css" href="bootstrap.css">

  <title> Teachers Students Login </title>

</head>

<body class="bg-secondary">

    <div class="container">

        <div class="row justify-content-center">

            <div class="col-log-5 bg-light mt-5 px-0">

                <h3 class="text-center text-light bg-primary py-3 px-5"> Log In </h3>

                <?php
            
                if(isset($_GET['error'])) {
                
                    if ($_GET['error'] == 'invalidemail') {
                    
                        echo "<p class='alert'> Invalid Email Id! </p>";
                    
                    } else if ($_GET['error'] == 'wrongpassword') {
                    
                        echo "<p class='alert'> Incorrect Password! </p>";
                    
                    } 
                 
                }
            
                ?>

                <form action="multi.php" action="post" class="py-4 px-5" id="form">

                    <div class="form-group px-5">

                        <input type="email" name="email" class="form-control form-control-lg" placeholder="Email" required>

                    </div>

                    <div class="form-group px-5">

                        <input type="password" name="password" class="form-control form-control-lg" placeholder="Password" required>

                    </div>

                    <div class="form-group px-5">

                        <input type="submit" name="submit" value="Submit" class="btn btn-primary btn-block">

                    </div>

                </form>

            </div>

        </div>

    </div>

</body>

</html>

 

<?php

 ini_set( 'display_errors', 1 ); 
 error_reporting( E_ALL );

 if (isset($_POST['submit'])) {
     
    $conn = mysqli_connect("localhost", "root",  "", "signup");
     
     $email = $_POST['email'];

     $password = $_POST['password'];
     
     $sql = "SELECT * FROM teachersRegist WHERE email=?";

     $stmt = mysqli_stmt_init($conn);
     
     if (!mysqli_stmt_prepare($stmt, $sql)) {

         header("Location: multilogin.php?error=sqlerror");

         exit();

     } else {
         
         mysqli_stmt_bind_param($stmt, "s", $email);

         mysqli_stmt_execute($stmt);

         $result = mysqli_stmt_get_result($stmt);
         
         if ($row = mysqli_fetch_assoc($result)) {
             
             $pwdCheck = password_verify($password, $row['password']);

             if ($pwdCheck == false) {
                 
                 header("Location: multilogin.php?error=wrongpassword");

                 exit();
                 
             } else if ($pwdCheck == true) {
                 
                 session_start();

                 $_SESSION['username'] = $row['username'];

                 $_SESSION['email'] = $row['email'];

                 header("Location: teachers.php?login=success");

                 exit ();
                 
                 
             } else {
                 
                  header("Location: multilogin.php?error=wrongpassword");

                 exit();
                 
             }
             
         } 
         
        else {
             
        header("Location: multilogin.php?error=invalidemail");

        exit();
             
             
         }
         
        }
     
    } 

    else {
     
    header("Location: multilogin.php");

    exit();
          
} 
     
?>
 

Edited September 9, 2020 by tarunrathore

I can't submit php form using IE 8.  This works fine on Firefox very well.
I tried following code but none of them is working.   
1.  <button type="submit">Submit</button>

2.  <input type="submit" value="Submit" name="submit">


 I would appreciate if any one help me in this.

hello everyone, I have a php form, everything works, I do not carry any header() at the end of the form because I have to stay on the same page and because I feel it wipes out the message you sent the form successfully, but for this though if reloading  the page shows me the popup asking me to resend the form.  how can i solve?  I found a function in js with replacestate but I saw that it doesn't work with mobile Safari.

if ( window.history.replaceState ) { window.history.replaceState( null, null, window.location.href ); }

 

Can anybody see as to why, if any, this form takes forever to execute?
Code: [Select]
<?php
if(isset($_POST['submitted'])){
    $z = $_POST['zipcode'];
    $r = $_POST['radius'];
    
    $sql = mysql_query("SELECT DISTINCT m.LocAddZip, m.MktName,m.LocAddSt,m.LocAddCity,m.LocAddState,m.x1,m.y1,z1.lat,z2.long
    FROM mrk m, zip z1, zip z2
    WHERE m.LocAddZip = z1.zipcode
    AND z2.zipcode = $z
    AND ( 3963 * acos( truncate( sin( z2.lat / 57.2958 ) * sin( z1.lat / 57.2958 ) + cos( z2.lat / 57.2958 ) * cos( z1.lat / 57.2958 ) * cos( z1.long / 57.2958 - z2.long / 57.2958 ) , 8 ) ) ) <= $r ")
    
    or die(mysql_error());
        while($row = mysql_fetch_array( $sql )) {
            $store = $row['MktName']."<br />";
            $store .= $row['LocAddSt']."<br />";
            $store .= $row['LocAddCity'].", ".$row['LocAddState']." ".$row['LocAddZip'];
            $lat1 = $row['lat'];
            $lon1 = $row['long'];
            $lat2 = $row['y1'];
            $lon2 = $row['x1'];
            $dis = distance($lat1, $lon1, $lat2, $lon2);
     
            echo "<p>".$store."</p>";        
            echo ceil($dis) . " mile(s) away";
            echo "<hr/>";
        }
}
?>

I get a timeout error sometimes, and sometimes I don't.
Is it the form, or would it be on the server?

Thanks in advance

Code: [Select]
<?php
 
if (isset($_POST['checking'])) { echo $_POST['checking']; }
if (isset($_POST['test'])) { echo $_POST['test']; }
 
?>
 
 
<form id="testform2" action="testform.php" method="post">
 
<select name="checking" onchange="this.form.submit()"><option value="5">5</option><option value="6">6</option></select>
<input type="text" name"test" id="test">
 <a href="#" onclick="this.form.submit()">submit it!</a>
</form>


It works when I try to submit by selecting a new value from the dropdown box but when I try to click the link it won't display the text field value. That is a test case for a problem I m having in one of my codes.

Hi,
I want to submit a form using ajax ans jquery with two fields input text and file.

Code: [Select]
<script>
$(document).ready(
function()
{


$('#basicinfofrm').ajaxForm(function() {
url: ''+PN+'.php',
type:'POST',
data:'action=yes&'+frmFeilds,
success: function(html)
{ 
 alert(html);

}

    }).submit();
</script>
<form action='' method='post'>
    <label>name</label>
    <input type='text' name='txtname' />
    <input type='file' name  = 'txtfile' />
   <input type='submit' value='save' />
</form>

but is is not working...
can anyone tell me how to?
i don't want to refresh my page
Thanks

Hi, I have setup a basic enquiry form with a Captcha - once the code has been inserted and is correct I want to action the form (submit) in PHP.

<?php

session_start();
if($_SERVER['REQUEST_METHOD'] == 'POST'){
$vResult = '';
if(strtolower($_SESSION['security_code']) != strtolower($_POST['security_code'])){
$vResult = 'Invalid code!';
}
else{
"/enquiry.php"
}
}
?>

I want to submit the form to /enquiry.php - I tried header(Location.. and realised that just redirects, and doesn't submit the form.

Any suggestions or tips would be great.

Cheers,

Paul