PHP - Searching With More Than One Word In A List Of Directories
Hello there,
I am pretty new to php and I was wondering if anyone can give me some input. Basically I am creating a search engine where I can search for words in certain files. I am trying to search using two or more words for instance a file may have the sentence 'the cat ran across the road', and another file has 'the road is long'. I would like to search 'cat road', and have these two files show up with each word highlighted. At the moment 'cat road' is being searched as just one string. I have exploded the keyword, and i have broken the array into separate words but for some reason it is still not searching. Again I would appreciate any feedback. Just to show you a bit of my code to explain: if(!empty($_GET['keyword'])) { $user_input = trim($_GET['keyword']); $user_input = preg_replace("/ {2,}/", " ",$user_input); $keyword = explode(" ", $user_input); for($i=0;$i<count($keyword);$i++) { echo("$keyword[$i]\n"); } $keyword = $_GET['keyword']; } Thanks for your time, Farha Similar TutorialsCode: [Select] $arr = array('../', 'j/', 'AcidBB/', 'fileBOMB/', 'OurHome', 'up'); foreach ($arr as $value) { // echo "Value: $value<br /><br />"; if (is_dir($value)) { echo "<tr> <td>{$value}</td> <td><font color='#66FF33'>Exists</font></td></tr><br />"; } else { echo "<tr> <td>{$value}</td> <td><font color='#FF0000'>Does Not Exist</font></td></tr><br />"; } } ~~~ Solved after posting. Sorry. ~~~ Ok i have an Array of directories i need to check before the script installs itself, I know how to check for directories but i dont know how to scan each array in the list without calling each one seperately in Code: [Select] If() { } Else If { } Else If { } And so on and so on... My Question is, If a For Statement is neaded, How would i go about checking each string in the Array List? $save_planet3 = "SELECT saver_id FROM save_planet WHERE saver_id = '".($_SESSION['user_id'])."' AND map = 1 ORDER BY time_saved DESC"; $save_planet2 = mysql_query($save_planet3) or trigger_error("SQL", E_USER_ERROR); while ($list = mysql_fetch_array($save_planet2)) { $saver_id = $list['saver_id']; When I echo $saver_id im getting a list of numbers 3112 3112 3112 3112 im trying to do a check if $planet_id is equal to any of these numbers So i figure the only way to do this is to put these numbers in a array with keys first. So I tried to explode it but it doesnt give each one a differant key I noticed. $check = explode(",", $saver_id); print_r($check); Array ( [0] => 3112 ) Array ( [0] => 3112 ) Array ( [0] => 3112 ) Array ( [0] => 3112 ) Once i get this in a workable array i should beable to do this right foreach($array as $key => $value) { if ($planet_id == $value) { //something happends Hello, I am quite new in PHP. I am doing a page with list of events (seminars). The events are saved in a XML file in chronological order and their each event has its date in d-m-Y format and time in h:m format. What I need to do is find the next event (with respect to the actual date and time). I can do it using a loop (foreach) and stringtotime() and comparing obtained values. However, this seems to be quite a clumsy way. Is there any better way to do it? Maybe there is a function, package or some extension, which I don't know... I tried xpath, however it does not know how to compare the dates (I use xml 1.0). Thank you very much. Hello, I have been developing a website that needs to display products online, I was originally going to hand-write the PHP code but I thought it would be more beneficial to make it database orientated as new products can easily be added and a search function becomes possible. I have it working so far so good, but the last part I can't seem to get working. I have it so all the products that have the desired category are displayed, but I want a more detailed analysis of the product to appear when the image is clicked, which at the moment, displays a blank page. http://www.webwib.co...?p=floorpuzzles - this is the hand coded version that demonstrates how I want it to work. http://www.webwib.co...hp?floorpuzzles - this is the db version so far, it works how it is intended to apart from the last stage, which returns as a blank page rather than a dedicated page for the selected product. Here is my code, the third segment beginning with "if(isset($_GET['$ID'])){", is my attempt at the final stage. <?php $db=mysql_connect ("localhost", "webwibco_charlie", "Hello123") or die ('I cannot connect to the database because: ' . mysql_error()); $mydb=mysql_select_db("webwibco_products"); include("header.php"); if(isset($_GET['floorpuzzles'])){ echo "<h1>Our Floor Puzzles</h1>"; $sql="SELECT ID, Name, Tags, Description, Category FROM products WHERE Category LIKE '%" . FloorPuzzles . "%'"; $result=mysql_query($sql); while($row=mysql_fetch_array($result)){ $Name =$row['Name']; $ID =$row['ID']; $Description =$row['Description']; echo "<div class=\"box\">"; echo "<h1>$Name</h1>"; echo "<div class=\"floorbox\"><a href=\"?$ID#productspage\"><img src=\"images/products/catalogue/$ID.jpg\" class=\"small\"></a></div>"; echo "<h2>$Description</h2>"; echo "</div>"; } } if(isset($_GET['anothercategory'])){ $sql="SELECT ID, Name, Tags, Description, Category FROM products WHERE Category LIKE '%" . AnotherCategory . "%'"; $result=mysql_query($sql); while($row=mysql_fetch_array($result)){ $Name =$row['Name']; $ID =$row['ID']; $Description =$row['Description']; echo "<h1>Our Floor Puzzles</h1>"; echo "<div class=\"box\">"; echo "<h1>$Name</h1>"; echo "<div class=\"floorbox\"><a href=\"?$ID0#productspage\"><img src=\"images/products/catalogue//$ID.jpg\" class=\"small\"></a></div>"; echo "<h2>$Description</h2>"; echo "</div>"; } } if(isset($_GET['$ID'])){ $sql="SELECT ID, Name, Tags, Description, Peices, Size, Barcode, Category FROM products WHERE ID LIKE '%" . $ID . "%'"; $result=mysql_query($sql); while($row=mysql_fetch_array($result)){ $Name =$row['Name']; $ID =$row['ID']; $Description =$row['Description']; $Pieces =$row['Pieces']; $Size =$row['Size']; $Barcode =$row['Barcode']; echo "<div class=\"1\">"; echo "<h1>$Name</h1>"; echo "<div class=\"bigbox\">"; echo "<div class=\"floorbox\"><img src=\"images/products/catalogue/$ID.jpg\" class=\"big\"></div>"; echo "</div>"; echo "</div>"; echo "<div class=\"2\">"; echo "<p>Puzzle Pieces: $Pieces</p> <p>Puzzle Size: $Size</p> <p>Barcode $Barcode</p>"; echo "</div>"; } } include("footer.php"); ?>Thank you in advance for any assistance given. for some reason my code only posts the first word of the username even tho the last names are in the database. www.checkmyweave.co.uk/new/dropdown.php dropdown.php Quote <?php mysql_connect("localhost","****","****"); mysql_select_db("checkmyw_database") or die("Unable to select database"); ?> <form action="/new/dropdown2.php" Method="POST"> User:<select name="username"> <?php $result = mysql_query("SELECT * FROM members") or die(mysql_error()); while($row = mysql_fetch_array( $result )) { echo "<option value=".$row['username'].">"; echo $row['username']."</option>"; } ?> </select> <form action="/new/dropdown2.php" METHOD="POST"> <input type = "submit" value="New!"> </form> dropdown2.php Quote <?php $username=$_POST["username"]; echo $username ; ?> Im wanting to not allow people to post any links in the comments section of a form (spammers) and have created a comma delimited list of essentially of every known domain name extension. To apply the filter I have the following code: Code: [Select] $WordAllowed = true; $BannedWords = explode(",", ReadDB($Options["ban_words"])); if (count($BannedWords)>0) { $checkComment = strtolower($_REQUEST["comment"]); for($i=0;$i<count($BannedWords);$i++){ $banWord = trim($BannedWords[$i]); if (trim($BannedWords[$i])<>'') { if(preg_match("/".$banWord."/i", $checkComment)){ $WordAllowed = false; break; } } } } if($WordAllowed==false) { $SysMessage = $OptionsLang["Banned_word_used"]; } else { Insert into my table I could have sworn this was working last time I was in this code but recently checking it again it is blocking pretty much everything claiming a banned word is used. The only thing I can get to post is 'lol'. Trying funny phrases like: first! or Great information, thanks, this is a test of the comment section, etc....they all get flagged Can anyone with fresh eyes assist? Im weary and frustrated and its been forever since I wrapped my head around this. My banned word list: Code: [Select] www,http,com,org,.aero,.asia,.biz,.com,.coop,.edu,.gov,.info,.int,.jobs,.mil,.mobi,.museum,.name,.net,.org, .pro,.tel,.travel,.xxx,.a,.bitnet,.ac,.ad,.ae,.af,.ag,.ai,.al,.am,.an,.ao,.aq,.ar,.as,.at,.au,.aw,.az,.ba,.bb,.bd,.be,.bf,.bg ,.bh,.bi,.bj,.bm,.bn,.bo,.br,.bs,.bt,.bv,.bw,.by,.bz,.ca,.cc,.cf,.cg,.ch,.ci,.ck,.cl,.cm,.cn,.co,.com,.cr,.cs,.cu,.cv,.cx,.cy,.cz ,.de,.dj,.dk,.dm,.do,.dz,.ec,.edu,.ee,.eg,.eh,.er,.es,.et,.fi,.fj,.fk,.fm,.fo,.fr,.fx,.ga,.gb,.gd,.ge,.gf,.gh,.gi,.gl,.gm,.gn ,.gov,.gp,.gq,.gr,.gs,.gt,.gu,.gw,.gy,.hk,.hm,.hn,.hr,.ht,.hu,.id,.ie,.il,.in,.io,.iq,.ir,.is,.it,.jm,.jo,.jp,.ke,.kg,.kh,.ki,.km ,.kn,.kp,.kr,.kw,.ky,.kz,.la,.lb,.lc,.li,.lk,.lr,.ls,.lt,.lu,.lv,.ly,.ma,.mc,.md,.mg,.mh,.mil,.mk,.ml,.mm,.mn,.mo,.mp,.mq,.mr, .ms,.mt,.mu,.mv,.mw,.mx,.my,.mz,.na,.nc,.ne,.net,.nf,.ng,.ni,.nl,.no,.np,.nr,.nt,.nu,.nz,.om,.org,.pa,.pe,.pf,.pg,.ph, .pk,.pl,.pm,.pn,.pr,.pt,.pw,.py,.qa,.re,.ro,.ru,.rw,.sa,.sb,.sc,.sd,.se,.sg,.sh,.si,.sj,.sk,.sl,.sm,.sn,.so,.sr,.st,.su,.sv, .sy,.sz,.tc,.td,.tf,.tg,.th,.tj,.tk,.tm,.tn,.to,.tp,.tr,.tt,.tv,.tw,.tz,.ua,.ug,.uk,.um,.us,.uy,.uz,.va,.vc,.ve,.vg,.vi,.vn,.vu,.wf, .ws,.ye,.yt,.yu,.za,.zm,.zr,.zw Thanks in advance for any help I have a situation where I need to put a textbox and a submit button on a page. The user is logged in. The script needs to check against a list of words to make sure the word the user entered is correct and if so submit their information(ie:name, email, time, date, word entered to a database table. The part i'm having trouble with is figuring out how to make it check against a specific set of words. Code: [Select] <p><strong>Enter Word</strong></p> <form action="/paradisepassword.php" method="post"> <input type="hidden" name="action" value="password2paradise" /> <table cellpadding="5px"> <tr> <td style="padding:3px;"><label for="password2paradise">Enter he :</label></td> <td style="padding:3px;"><input name="password2paradise" type="password2paradise" id="password2paradise" value="" maxlength="30" tabindex="5" /></td> </tr> <tr> <td style="padding:3px;"> </td> <td style="padding:3px;"><input name="submit" type="submit" value="Submit Password" tabindex="7" class="generalButton" /></td> </tr> </table> </form> and the php file to process it: <?php include_once($_SERVER['DOCUMENT_ROOT']."/_core/config.php"); include_once($_SERVER['DOCUMENT_ROOT']."/_core/db-connect.php"); include_once($_SERVER['DOCUMENT_ROOT']."/_core/functions.php"); include_once($_SERVER['DOCUMENT_ROOT']."/_core/user-cookies.php"); ///////////////////////////////////////////////////////////////////////////// //function submitParadisePassword($intContestantID, $intDateSent, $intParadisePassword, $strType){ $paradise_password = paradisePassword("password1", "password2", "password3", "password4", "password5", "password6", "password7", "password8", "password9", "password10"); if (!$paradise_password == paradisePassword); { // success! $query_insert="INSERT INTO ".DB_DATABASE.".paradisepassword_2010 ( accountID, nickname, firstName, lastName, email, paradisePassword, sentFromUrl, dateSent, dateSentTimestamp, ipAddress ) VALUES ( '".mysql_real_escape_string($_POST['accountID'])."', '".mysql_real_escape_string($_POST['nickname'])."', '".mysql_real_escape_string($_POST['firstName'])."', '".mysql_real_escape_string($_POST['lastName'])."', '".mysql_real_escape_string($_POST['email'])."', '".mysql_real_escape_string($_POST['paradisePassword'])."', '".mysql_real_escape_string($_POST['sentFromUrl'])."', '".date("Y-m-d")."', '".time()."', '".$_SERVER['REMOTE_ADDR']."' ) "; mysql_query($query_insert); header("Location: ".$_POST['sentFromUrl']."?p2p=success"); } else { header("Location: ".$_POST['sentFromUrl']."?p2p=fail"); } //} ?> what am i missing? Hello! Hey guys does anyone know of a good dynamic directory solution? What i mean by this is when i am creating an application and i use require_once 'includes/config.php'; and then i create a class that needs the config file so i include it into the class like so: require_once '../include/config.php'; then i make a new folder named member then i have to require this class (created above) and it fails to find the directory. What would be a good solution for this? Thanks guys!! I am using the following code: Code: [Select] <?php $target = "images/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> I am using this to upload photos to the directory called 'images'. How could I change this code so that I can choose an existing directory to upload it to and also create a new directory to upload it to if I wanted? So I have a simple template that I want to be the index page of the website that I'm working on, however, I don't want to have to create several almost identical files for each of the directories.
Is there perhaps anyway that I can change the content of the main div yet the address be a different directory.
So for example, this is the main index page:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <head> <title>Matthew Noskiw's website - Home</title> <link rel='stylesheet' type='text/css' href='./inc/CSS/styles/default.css' /> <link rel='stylesheet' type='text/css' href='./inc/CSS/static/navigation.css' /> </head> <body> <div id='Container'> <div id='Header'> <div class='right'> <ul id='Navigation'> <li id='NavButton' class='active'><a href='./'>Home</a></li> <li id='NavButton'><a href='./about'>About</a></li> <li id='NavButton'><a href='./blog'>Blog</a></li> <li id='NavButton'><a href='./contact'>Contact</a></li> </ul> </div> <span>noskiw.co.uk</span> </div> <hr /> <div id='MainContent'> <h2>Home</h2> <br /> <span> Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum. </span> <br /><br /> <span> Sed ut perspiciatis unde omnis iste natus error sit voluptatem accusantium doloremque laudantium, totam rem aperiam, eaque ipsa quae ab illo inventore veritatis et quasi architecto beatae vitae dicta sunt explicabo. Nemo enim ipsam voluptatem quia voluptas sit aspernatur aut odit aut fugit, sed quia consequuntur magni dolores eos qui ratione voluptatem sequi nesciunt. Neque porro quisquam est, qui dolorem ipsum quia dolor sit amet, consectetur, adipisci velit, sed quia non numquam eius modi tempora incidunt ut labore et dolore magnam aliquam quaerat voluptatem. Ut enim ad minima veniam, quis nostrum exercitationem ullam corporis suscipit laboriosam, nisi ut aliquid ex ea commodi consequatur? Quis autem vel eum iure reprehenderit qui in ea voluptate velit esse quam nihil molestiae consequatur, vel illum qui dolorem eum fugiat quo voluptas nulla pariatur? </span> </div> <hr /> <div id='Footer'> <span>Matthew Noskiw</span> </div> </div> </body> </html>But if you look in the <h2> tag in the 'MainContent' div, then you'll see it reads "Home". What I want to happen is that when I change the page, for example, go to /about I want it to read <h2>About</h2>. I have 4 different pages for this so far, is there any way to get it down to just one yet they be in different directories? P.S The reason this is in the PHP Help section is because I assumed that it would more than likely be something to do with PHP. Edited by ghostrider1337, 02 August 2014 - 02:36 PM. I am a php newb. I have 2 somewhat simple problems. First I have a huge list of movies that I would like sorted in a drop down list alphabetically. I already have the drop down list made and the movies show up correctly. But I cannot figure out how to sort the list. Here is the code <?php $dir="/backup/Movies"; if ($handle = opendir($dir)) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != ".." && $file != "index.php") { $thelist .= '<option>'.$file.'</option>'; } } closedir($handle); } ?> <form action="listen.php" method="post" name="table"> <select name="Movie"> <P><?=$thelist?></p>' </select> </form> Second problem is inside this directory there are a few other directories is it possible to make the directories show at the top instead of them being sorted alphabetically with the movies. Thanks in advance Jake I have one input upload and need it to go to two directories here is my upload code that handles the move_upload_file portion. Code: [Select] move_uploaded_file($_FILES['fillPDF']['tmp_name'], $strNewsPath . $strFilename); Thanks in advance. i need to convert the following path Code: [Select] $url=http://www.test.com/images/1/7/4/7/9/thumb.jpg to Code: [Select] $updated_url= /home/vhosts/test.com/httpdocs/images/1/7/4/7/9/thumb.jpgThe directories in the url are created dynamically Right now what i am doin is Code: [Select] $updated_url='/home/vhosts/'.$url.'/httpdocs/images/'.basename($url)which gives me /home/vhosts/test.com/httpdocs/images/thumb. But I also need to get the directories 1/7/4/7/9. It may be differ for different urls. Can this be done through some form of string replacement or pattern matching method? Here is my code which i use to recieve uploaded files.
$filepath = $_SERVER['DOCUMENT_ROOT'] . "file/"; $fileunzippath = $filepath."unzipped/"; $exclude_list = array(".", "..", "...", "index.php", ".php", ".htaccess"); if($_FILES["zip_file"]["name"]) { $filename = $_FILES["zip_file"]["name"]; $source = $_FILES["zip_file"]["tmp_name"]; $type = $_FILES["zip_file"]["type"]; $name = explode(".", $filename); $accepted_types = array('application/zip', 'application/x-zip-compressed', 'multipart/x-zip', 'application/x-compressed'); foreach($accepted_types as $mime_type) { if($mime_type == $type) { $okay = true; break; } } $continue = strtolower($name[1]) == 'zip' ? true : false; if(!$continue) { $message = "The file you are trying to upload is not a .zip file. Please try again."; } $string = preg_replace(array('/\s/', '/\.[\.]+/', '/[^\w_\.\-]/'), array('_', '.', ''), $filename); $clean_name = strtr($string, array('Š' => 'S','Ž' => 'Z','š' => 's','ž' => 'z','Ÿ' => 'Y','À' => 'A','Á' => 'A','Â' => 'A','Ã' => 'A','Ä' => 'A','Å' => 'A','Ç' => 'C','È' => 'E','É' => 'E','Ê' => 'E','Ë' => 'E','Ì' => 'I','Í' => 'I','Î' => 'I','Ï' => 'I','Ñ' => 'N','Ò' => 'O','Ó' => 'O','Ô' => 'O','Õ' => 'O','Ö' => 'O','Ø' => 'O','Ù' => 'U','Ú' => 'U','Û' => 'U','Ü' => 'U','Ý' => 'Y','à' => 'a','á' => 'a','â' => 'a','ã' => 'a','ä' => 'a','å' => 'a','ç' => 'c','è' => 'e','é' => 'e','ê' => 'e','ë' => 'e','ì' => 'i','í' => 'i','î' => 'i','ï' => 'i','ñ' => 'n','ò' => 'o','ó' => 'o','ô' => 'o','õ' => 'o','ö' => 'o','ø' => 'o','ù' => 'u','ú' => 'u','û' => 'u','ü' => 'u','ý' => 'y','ÿ' => 'y')); $clean_name = strtr($clean_name, array('Þ' => 'TH', 'þ' => 'th', 'Ð' => 'DH', 'ð' => 'dh', 'ß' => 'ss', 'Œ' => 'OE', 'œ' => 'oe', 'Æ' => 'AE', 'æ' => 'ae', 'µ' => 'u')); $clean_name = preg_replace(array('/\s/', '/\.[\.]+/', '/[^\w_\.\-]/'), array('_', '.', ''), $clean_name); $target_path = $filepath.$clean_name; // change this to the correct site path if(move_uploaded_file($source, $target_path)) { echo "Source: ".$source."<br/>"; echo "Type: ".$type."<br/>"; echo "Filename: ".$filename."<br/>"; $zip = new ZipArchive(); $x = $zip->open($target_path); if ($x === true) { $zip->extractTo($fileunzippath.$clean_name); // change this to the correct site path $zip->close(); $exclude_list; $dir_path = $_SERVER['DOCUMENT_ROOT']; $dir_path .= "/file/unzipped/"; $directories = array_diff(scandir($fileunzippath.$clean_name), $exclude_list); foreach($directories as $entry) { if(is_dir($dir_path.$entry)) { if($entry != 'part0' || $entry !='part1') { rmdir($entry); } } } } $message = "Your .zip file was uploaded and unpacked."; } else { $message = "There was a problem with the upload. Please try again."; } }Specifically i want to highlight this part: $exclude_list; $dir_path = $_SERVER['DOCUMENT_ROOT']; $dir_path .= "/file/unzipped/"; $directories = array_diff(scandir($fileunzippath.$clean_name), $exclude_list); foreach($directories as $entry) { if(is_dir($dir_path.$entry)) { if($entry != 'part0' || $entry !='part1') { rmdir($entry); } } }When I upload a zip file containing 2 directories(one called 'part0', and one called 'bad'), they get unzipped correctly and it gives no errors, however the fake directories(not called part0 or part1) I put in there are still there. Any Help? How do I include a file that is located two directories above the file that I want to include the file into? My absolute hosting path is /home/content/52/8840652/html if this would be of any use. I'm not quite sure about the PHP include functions. Any help would be greatly appreciated, Thanks! This topic has been moved to mod_rewrite. http://www.phpfreaks.com/forums/index.php?topic=347966.0 Hello everyone, This is a fairly simple question, but the explanation of the question isn't... I'll do my best. I have a site where my folders/sub-folders/files are arranged similar to this: _ Root Folder -| Root-IncludeFile1.php | Root-IncludeFile2.php | _ | Sub-Folder 1 -| Sub1-File1.php | |_Sub1-File2.php | _ | Sub-Folder 2 -| Sub2-File1.php | |_Sub2-File2.php | _ |_Sub-Folder 3 -| Sub3-IncludeFile1.php |_Sub3-IncludeFile2.php Hopefully that makes sense to everyone. Anyway, I know that to include a file that is in the root folder in file in a sub-folder, I can do this - include("../includefile1.php"); -but I'm trying to include a file that is in a sub folder in a file that is in another sub-folder. For example, I'm trying to include "Sub3-IncludeFile1.php" in "Sub-File1.php" I'm lost on this because I can't get it to work. I'm not getting any error messages except to say that the variables located in the file that should be included are not found. I've tried to do this: include("http://www.mysite.com/Sub-Folder3/Sub3-IncludeFile1.php"); and it doesn't work. Can someone please point me in the right direction? Thanks in advance for your help. I have written a piece of code that create a directories, files on the server using mkdir and touch and also inserts the form data into the table.. the code gets executed and the info gets stored in the database but the part which has the create directories. and files dont work as it doesnt create the directory and files on the server.. do i need to make changes to the php.ini file to enable the mkdir and touch feature to get enabled? as i said the code executes without any error.. I dont know wat to do.. please any help would be appreciated!! thanku This topic has been moved to mod_rewrite. http://www.phpfreaks.com/forums/index.php?topic=321151.0 |