PHP - Divide A Value From A Query ?!

I have a list generated from an array by foreach as
 
Code: [Select]
foreach ($list_array as $item) {
echo "$item<br />";
}
This is a long list, how can I separate the list to different pages? I mean the simplest way to do so

Hello all,   Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).   The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).   Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:   In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).   I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.   Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.   So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:   1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red. 2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red. 3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.   Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.   Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.   Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.   Cheers guys!

case "update-delete":
	if(isset($_POST['highlight-purchased'])) 
		{
			// ****** Setup customized query to obtain only items that are checked ******
			$sql = "SELECT * FROM shoplist WHERE";
					for($i=0; $i < count($_POST['checkboxes']); $i++)
						{
							$sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or";
						}
					$sql= rtrim($sql, "or");
											
			$statement = $conn->prepare($sql);
			$statement->execute();
																						
			// *** fetch results for all checked items (1st query) *** //
			$result = $statement->fetchAll();

			$statement->closeCursor();
											
			// Setup query that will change the purchased flag to "N", if it's currently set to "Y"
			$sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'";
											
			// Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL
			$sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL";

			$statementSetToN = $conn->prepare($sqlSetToN);
			$statementSetToY = $conn->prepare($sqlSetToY);
											
			/*** loop through the results/collection of checked items ***/
			foreach($result as $row)
				{
					if ($row["purchased"] != "Y")
						{
							// *** fetch one row at a time pertaining to the 2nd query *** //
							$resultSetToY = $statementSetToY->fetch();
															
							foreach($resultSetToY as $row)
								{															
									$statementSetToY->execute();																
								}
						}
					else
						{
							// *** fetch one row at a time pertaining to the 2nd query *** //
							$resultSetToN = $statementSetToN->fetch();
															
							foreach($resultSetToN as $row)
								{															
									$statementSetToN->execute();																
								}
						}
				}
				break;
		}

 CRUD Queston.png   20.68KB   0 downloads    

Here is my code:
// Start MySQL Query for Records
$query = "SELECT codes_update_no_join_1b" .
"SET orig_code_1 = new_code_1,
       orig_code_2 = new_code_2" .
"WHERE concat(orig_code_1, orig_code_2) = concat(old_code_1, old_code_2)";
$results = mysql_query($query) or die(mysql_error());
// End MySQL Query for Records


This query runs perfectly fine when run direct as SQL in phpMyAdmin, but throws this error when running in my script??? Why is this???

Code: [Select]
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= new_code_1, orig_code_2 = new_code_2WHERE concat(orig_code_1, orig_c' at line 1

If you also have any feedback on my code, please do tell me. I wish to improve my coding base.

Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference.

Code:

  Code: [Select]
mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)");
Full code:

Code: [Select]
<?php
include_once("includes/config.php");
 
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title><? $title; ?></title>
<meta http-equiv="Content-Language" content="English" />
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<link rel="stylesheet" type="text/css" href="style.css" media="screen" />
</head>
<body>
 
<div id="wrap">
 
<div id="header">
<h1><? $title; ?></h1>
<h2><? $description; ?></h2>
</div>
 
<? include_once("includes/navigation.php"); ?>
 
<div id="content">
<div id="right">
<h2>Create</h2>
<div id="artlicles">
<?php
 
if(!$_SESSION['user'])
{
 
        $username = mysql_real_escape_string($_POST['username']);
        $password = mysql_real_escape_string($_POST['password']);
        $name = mysql_real_escape_string($_POST['name']);
        $server_type = mysql_real_escape_string($_POST['type']);
        $description = mysql_real_escape_string($_POST['description']);
 
        if(!$username || !$password || !$server_type || !$description || !$name)
        {

        echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>";
        echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'>
       
        <option value='Any'>Any</option>
        <option value='PvP'>PvP</option>
        <option value='Creative'>Creative</option>
        <option value='Survival'>Survival</option>
        <option value='Roleplay'>RolePlay</option>
       
        </select></td></tr>
       
        <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>";
        echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>";
        }
        elseif(strlen($password) < 8)
        {
        echo "Password needs to be higher than 8 characters!";
        }
        elseif(strlen($username) > 13)
        {
                echo "Username can't be greater than 13 characters!";
        }
        else
        {
                $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1");
               
                if(mysql_num_rows($check1) < 0)
                {
                        echo "Sorry, there is already an account with this username and/or server name!";
                }
                else
                {
                        $ip = $_SERVER['REMOTE_ADDR'];

                        mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)");
                        echo "Server has been succesfully created!";
                }
        }
       
}
else
{
        echo "You are currently logged in!";
}
 
?>
</div>
</div>
 
<div style="clear: both;"> </div>
</div>
 
<div id="footer">
<a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop
</div>
</div>
 
</body>
</html>

I was just wondering if it's possible to run a query on data that has been returned from a previous query?  For example, if I do

Code: [Select]
$sql = 'My query';
$rs = mysql_query($sql, $mysql_conn);

Is it then possible to run a second query on this data such as

Code: [Select]
$sql = 'My query';
$secondrs = mysql_query($sql, $rs, $mysql_conn);

Thanks for any help

I'm trying to update every record where one field in a row is less than the other. The code gets each row i'm looking for and sets up the query right, I hope I combined the entire query into one string each query seperated by a ; so it's like
UPDATE `table` SET field2= '1' WHERE field1= '1';UPDATE `table` SET field2= '1' WHERE field1= '2';UPDATE `table` SET field2= '1' WHERE field1= '3';UPDATE `table` SET field2= '1' WHERE field1= '4';UPDATE `table` SET field2= '1' WHERE field1= '5';
this executes properly if i run the query in phpMyAdmin, however when I run the query in PHP, it does nothing... Any advice?

Say I have this query:

site.com?var=1

..I have a form with 'var2' field which submits via get.

Is there a way to produce:

site.com?var=1&var2=formdata

I was hoping there would be a quick way to affix, but can't find any info. Also, the query could sometimes be:

site.com?var2=formdata&var=1

I would have to produce:

site.com?var2=updatedformdata&var=1

Is my only option to further parse the query?

here's the code:

Code: [Select]
$companyName = 'big company';
$address1 = 'big bay #8';
$address2 = 'some big warehouse';
$city = 'big city';
$province = 'AB';
$postalCode = 'T1T0N0';
$phone = '0123456789';
$email2 = 'bigKahuna@bigKahuna.edu';

$query = "INSERT INTO clients (
                   companyName, address1, address2, city, province, postalCode, phone, email)
                 VALUES ( ".
                    $companyName.",".$address1.",".$address2.",".$city.",".$postalCode.",".$phone.",".$email2.")";

$result = mysql_query($query, $connexion);

if ($result)
{
// Success!
echo "Fabulous!  check the DB, we did it! :D<br>";
?>

<pre>
<?php
print_r($result);
?>
</pre>

<?php
} else {
// Fail!
echo"CRAAAAAPP!  something went wrong.  FIX IT!  :P<br>";
echo mysql_error();
}

if (isset($connexion)) { mysql_close($connexion); }
i copied it over from an old *working* file to illustrate how a simple INSERT works.

this is the error i get:

Code: [Select]
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'company,big bay #8,some big warehouse,big city,T1T0N0,0123456789,bigKahuna@bigKa' at  line 4
looks completely valid to me.  all the database table elements are set to VARCHAR(80), so it can't be a space/type issue...

halp! 

WR!

What would be the correct way to close a mysql query?

At current the second query below returns results from the 1st query AND the 2nd query
The 3rd query returns results from the 1st, 2nd and 3rd query.
 etc etc.

At the moment I get somthing returned along the lines of...

QUERY 1 RESULTS
Accommodation 1
Accommodation 2
Accommodation 3

QUERY 2 RESULTS
Restaurant 1
Restaurant 2
Restaurant 3
Accommodation 1
Accommodation 2
Accommodation 3

QUERY 3 RESULTS
Takeaways 1
Takeaways 2
Takeaways 3
Restaurant 1
Restaurant 2
Restaurant 3
Accommodation 1
Accommodation 2
Accommodation 3

Code: [Select]

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<?php 
  include($_SERVER['DOCUMENT_ROOT'].'/include/db.php');
?>
<title>Untitled Document</title>
<style type="text/css">
<!--
-->
</style>
<link href="a.css" rel="stylesheet" type="text/css" />
</head><body>
<div id="listhold">

<!------------------------------------------------------------------------------------------------------------------------------------------------------>

<div class="list"><a href="Placestostay.html">Places To Stay</a><br />
<?php
$title ="TITLE GOES HERE";
$query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Accommodation' AND confirmed ='Yes' ORDER BY name");
echo mysql_error();
while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0];
$i = -1;
foreach($nt as $value)
{$i++;
$FileName = str_replace(' ','_',$nt[$i]) . ".php";
$FileUsed = str_replace('_',' ',$nt[$i]);
echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>"  . $nt[$i] . "</a>" . "<br/>";
$FileHandle = fopen($FileName, 'w') or die("cant open file");
$pageContents = file_get_contents("header.php");
fwrite($FileHandle,"$pageContents");}
fclose($FileHandle);
?>
</div>

<!------------------------------------------------------------------------------------------------------------------------------------------------------>

<div class="list"><a href="Eatingout.html">Eating Out</a><br />
<?php
$title ="TITLE GOES HERE";
$query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Restaurant' AND confirmed ='Yes' ORDER BY name");
echo mysql_error();
while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0];
$i = -1;
foreach($nt as $value)
{$i++;
$FileName = str_replace(' ','_',$nt[$i]) . ".php";
$FileUsed = str_replace('_',' ',$nt[$i]);
echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>"  . $nt[$i] . "</a>" . "<br/>";
$FileHandle = fopen($FileName, 'w') or die("cant open file");
$pageContents = file_get_contents("header.php");
fwrite($FileHandle,"$pageContents");}
fclose($FileHandle);
?>
</div>

<!------------------------------------------------------------------------------------------------------------------------------------------------------>

<div class="list"><a href="Eatingin.html">Eating In</a><br />
<?php
$title ="TITLE GOES HERE";
$query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Takeaways' AND confirmed ='Yes' ORDER BY name");
echo mysql_error();
while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0];
$i = -1;
foreach($nt as $value)
{$i++;
$FileName = str_replace(' ','_',$nt[$i]) . ".php";
$FileUsed = str_replace('_',' ',$nt[$i]);
echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>"  . $nt[$i] . "</a>" . "<br/>";
$FileHandle = fopen($FileName, 'w') or die("cant open file");
$pageContents = file_get_contents("header.php");
fwrite($FileHandle,"$pageContents");}
fclose($FileHandle);
?>
</div>

<!------------------------------------------------------------------------------SKILLED TRADES BELOW--------------------------------------------------->

<div class="list"><a href="Skilledtrades.html">Skilled Trades</a><br/>
<?php
$title ="TITLE GOES HERE";
$query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Skilled Trades' AND confirmed ='Yes' ORDER BY name");
echo mysql_error();
while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0];
$i = -1;
foreach($nt as $value)
{$i++;
$FileName = str_replace(' ','_',$nt[$i]) . ".php";
$FileUsed = str_replace('_',' ',$nt[$i]);
echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>"  . $nt[$i] . "</a>" . "<br/>";
$FileHandle = fopen($FileName, 'w') or die("cant open file");
$pageContents = file_get_contents("header.php");
fwrite($FileHandle,"$pageContents");}
fclose($FileHandle);
?>
</div>

I'm restarting this under a new subject b/c I learned some things after I initially posted and the subject heading is no longer accurate.

What would cause this behavior - when I populate session vars from a MYSQL query, they stick, if I populate them from an MSSQL query, they drop.

It doesn't matter if I get to the next page using a header redirect or a form submit.  I have two session vars I'm loading from a MYSQL query and they remain, the two loaded from MSSQL disappear. 

I have confirmed that all four session vars are loading ok initially and I can echo them out to the page, but when the application moves to next page via redirect or form submit, the two vars loaded from MSSQL are empty. 

Any ideas?

Good Day Guys   I have a bit of a urgent problem.   Here is my Query:   $query = "SELECT distinct Img.propertyId as PropertyId, Title, ImageUrl, Location, Bedrooms, Bathrooms, Parking, Price FROM PROPERTIES as Prop LEFT JOIN IMAGES as Img ON Img.PropertyId = Prop.PropertyId WHERE 1=1 AND Price >=1000 AND Price <=5000 ";

I am trying to create a query which reads and uses a previous query which could go on for upto four queries.

For example:

Query: $carcolour(red), Query: $carmodel(ford), Query: $enginesize(1600), Query: $carlocation(New York)

This displays all red cars, which are Ford, which 1600CC, which are located in New York.

or

Query: $enginesize(1600), Query: $carcolour(red), Query: $carmodel(ford), Query: $carlocation(New York)

This displays all 1600CC cars, which red car, which are Ford, which are located in New York. (Same result as above)

I have found this guide but Im not sure it what I am looking for.  I have also come across the Join function. 
However this seems to be based on joining two seperate queries.

http://www.suite101.com/content/how-tor-run-multiple-mysql-queries-with-php-a105672

Can anyone advise on the best way to create a set of queries which reads and uses the results of the previous query?

Hi, I am trying to get the sum of two queries and echo the result, both $hometotal and $awaytotal work on their own but I don't know how to put them together or whether it can be put into one query. I have tried a few different variations but keep getting SQL syntax errors. Does anybody know how I can write this code? Thanks in advance

Code: [Select]
<?php
$hometotal = "SELECT SUM(test_results.hts) FROM test_teams, test_results WHERE test_teams.team = '$team' AND test_teams.teamid = test_results.hometeam";
$awaytotal = "SELECT SUM(test_results.ats) FROM test_teams, test_results WHERE test_teams.team = '$team' AND test_teams.teamid = test_results.awayteam";
$total = $hometotal + $awaytotal;
$result = mysql_query($total) or die(mysql_error());

$row = mysql_fetch_assoc($result);

                echo $total;
                ?>

Hi all,

Can anyone help me out.. I tried to run this query but it does not seem correct in particular the OR AND part. As the search dept (AND) did not give me any results when I run the query.

Anyone has idea what is the correct way to do it?


$query = ("SELECT `firstname`, `surname`, `deptname` FROM profile JOIN dept ON profile.dept_id = dept.id  WHERE surname LIKE '{$_POST['searchname']}' OR firstname LIKE '{$_POST['searchname']}' AND dept.id LIKE '{$_POST['dept']}'") or die (mysql_error());



I tried to put brackets e.g

$query = ("SELECT `firstname`, `surname`, `deptname` FROM profile JOIN dept ON profile.dept_id = dept.id  WHERE (surname LIKE '{$_POST['searchname']}' OR firstname LIKE '{$_POST['searchname']}') AND dept.id LIKE '{$_POST['dept']}'") or die (mysql_error());

....but it still did not work.

Thanks.

hey guys im trying to make a league website and below the query calculates the wins losses and draws of a team in each row

what i want in this query is to make a points column which will add all the wins losses and draws up all together

win = 3 pts
draw = 2 pts
loss = 0 pts

so if a team has won a game and drawn a game the points colum will be 5...i hope this explains what i want...is this possible please?

 
$team_select  = "SELECT @rank := @rank + 1 AS 'rank',
                        t.team_id,
                        t.team_name, 
                        COUNT(r.league_match_result_id) AS 'matches_played',
                        COUNT(CASE r.result WHEN 'Win' THEN '3' END) AS 'wins', 
                        COUNT(CASE r.result WHEN 'Loss' THEN '0' END) AS 'losses',
                        COUNT(CASE r.result WHEN 'Draw' THEN '1' END) AS 'draws'
                 FROM teams t
                 LEFT JOIN league_match_results r ON r.team_id = t.team_id
                 LEFT JOIN team_leagues tl ON tl.team_id = t.team_id
                 RIGHT JOIN league_matches m ON r.league_match_id = m.league_match_id
                 WHERE tl.league_id = :1
                 GROUP BY t.team_id
                 ORDER BY team_name";