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PHP - Display All Images In A Directory..
How can i display all the images in a certain directory and echo the image names. So if a new image is uploaded, it will still display without edited the gallery.php file.
Cheers. Similar TutorialsI am trying to display images on a html page alphabetically in descending order by their filename. This script inserts all the images in a directory on the page. Just can't figure out how to maintain this with a sorting option <?php $dir = "./plate_cache"; $handle = opendir($dir); while (($file = readdir($handle))!==false) { if (strpos($file, '.png',1)) { echo "<img id=\"plates\" src=\"/tags/plate_cache/$file\"></a><br />;"; } } closedir($handle); } ?> Hey guys, I have a folder which has images. In this folder there are images that start with "refl_". I want to make sure those are not displayed. This is what I tried and it does not work. I want to show all images that don't start with "refl_". I am new to this as I am sure some can see. Thanks for the help if possible! <?php $dir = opendir("img/portfolio/"); while (false !== ($file = readdir($dir))) { $pos = strpos($file, "refl_"); if ($pos == false) { echo '<img src="img/portfolio/' . $file . '" longdesc="img/portfolio/' . $file . '" /></a>'; } } ?> Hi, I have a list of images from a directory that are in order by their "id". How could I display one at a time on a page--starting from the beginning, and have it so the user can click on the image and go to the next one in line. Hi, i want to make an image gallery, this is the first step. uploading files. below is the code I am using , but don't i have to include info about the server? i dont know what to include since it is the server I am working with and not a database, any help greatly appreciated. thanks Code: [Select] <?php // Where the file is going to be placed $target_path = "uploads/"; /* Add the original filename to our target path. Result is "uploads/filename.extension" */ $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> </body> </html> So, We are trying to create a animation using the gifs in a directory by using the first 10 images. We just cannot figure out how to do the animation.. needs to have a 3 second delay between each frame Heres the code at the moment. Which creates the starting images and also sorts the images in the directory by time.. <?php $time = date("YmdHis"); $handle_data = file_get_contents('http://www.bungie.net/Stats/Halo3/Nightmap.ashx'); $img = new Imagick(); $img->readImageBlob($handle_data); $img->writeImage('nightmap/'.$time.'.gif'); foreach (glob('nightmap/*.gif') as $f) { # store the image name $list[] = $f; } sort($list);# sort is oldest to newest, $gif_0 = array_pop($list); $gif_1 = array_pop($list); $gif_2 = array_pop($list); $gif_3 = array_pop($list); $gif_4 = array_pop($list); $gif_5 = array_pop($list); $gif_6 = array_pop($list); $gif_7 = array_pop($list); $gif_8 = array_pop($list); $gif_9 = array_pop($list); ?> ok I got the images to upload to the directory on the server. now I got some code to try to display the image on the same page after you submit it to the directory. so it's like, submit form-> images goes in server directory->echoes back out on same page but just above the upload form. please any help greatly appreciated. thanks. here is the code so far. Code: [Select] <?php // An Example about listing Images. $dir = "uploads/"; $odir = opendir($dir); while($file = readdir($odir)){ if(filetype($file) == "image/JPEG") { echo $file; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <p>UPLOAD YOUR PORTFOLIO AND PRICES</p> <p> </p> <p> <form enctype="multipart/form-data" action="uploader.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="100000" /> Choose a file to upload: <input name="uploadedfile" type="file" /><br /> <input type="submit" value="Upload File" /> </form></p> </body> </html> Hi, I am trying to echo out images on my server's directory "uploads". The images are blank and not showing up. Please help if anyone can. Thank you. here is the page as it is. http://ealike.com/simple_uploader/uploader.php and here is the code. Code: [Select] <?php // Where the file is going to be placed $target_path = "uploads/"; /* Add the original filename to our target path. Result is "uploads/filename.extension" */ $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } //echo out all images $dir = "uploads/"; if (is_dir($dir)) { if ($dh = opendir($dir)) { while (($file = readdir($dh)) !== false) { echo "<img src='$file' alt='$file' height='200' width='200' /> " ; } closedir($dh); } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> </body> </html> I currently have a file upload form that uploads images to a folder on my server called "attachments". This is the directory path: www.mysite.com/docs/attachments/ However, I want the images to upload to www.mysite.com/data/attachments/ instead. I have included the relevant part of the PHP below. I have tried changing this: $cur_dir = $cur_dir."/".$dir; to this: $cur_dir = $cur_dir."www.mysite.com/data/attachments/".$dir; and changing this: $dirs = explode("/","attachments//"); to this: $dirs = explode("www.mysite.com/data/","attachments//"); and also changing this: $_values[$file[0]."_real-name"] = "attachments/".date("YmdHis")."_".$_FILES[$file[0]]["name"]."_secure"; to this: $_values[$file[0]."_real-name"] = "www.mysite.com/data/attachments/".date("YmdHis")."_".$_FILES[$file[0]]["name"]."_secure"; But nothing has worked so far. Any suggestions would be appreciated. foreach($files[$form] as $file){ $str = $file[1]; if (eval("if($str){return true;}")) { $_values[$file[0]] = $_FILES[$file[0]]["name"]; $dirs = explode("/","attachments//"); $cur_dir ="."; foreach($dirs as $dir){ $cur_dir = $cur_dir."/".$dir; if (!@opendir($cur_dir)) { mkdir($cur_dir, 0777);}} $_values[$file[0]."_real-name"] = "attachments/".date("YmdHis")."_".$_FILES[$file[0]]["name"]."_secure"; copy($_FILES[$file[0]]["tmp_name"],$_values[$file[0]."_real-name"]); @unlink($_FILES[$file[0]]["tmp_name"]); }else{ $flag=true; if ($_isdisplay) { //$ExtFltr = $file[2]; //$FileSize = $file[4]; if (!eval("if($file[2]){return true;}")){echo $file[3];} if (!eval("if($file[4]){return true;}")){echo $file[5];} $_ErrorList[] = $file[0]; } } } I have a PHP script that uploads images to a folder on my server (attachments folder). Currently the folder sits within my webroot and is publicly accessible (I have to use chmod 777 due to permissions issue). So, I created the "attachments" folder outside of my webroot (so that it is not publicly accessible), but I do not know how to set the path in the PHP code to upload it to that "attachments" folder outside of the webroot. As you see in the snippet of PHP code below, the code currently uploads the the "attachments" folder within the www (webroot) directory. How do I make it upload to the "attachments" folder OUTSIDE of the www (webroot) directory? foreach($files[$form] as $file){ $str = $file[1]; if (eval("if($str){return true;}")) { $_values[$file[0]] = $_FILES[$file[0]]["name"]; $dirs = explode("/","attachments//"); $cur_dir ="."; foreach($dirs as $dir){ $cur_dir = $cur_dir."/".$dir; if (!@opendir($cur_dir)) { mkdir($cur_dir, 0777);}} $_values[$file[0]."_real-name"] = "attachments/".date("YmdHis")."_".$_FILES[$file[0]]["name"]."_secure"; copy($_FILES[$file[0]]["tmp_name"],$_values[$file[0]."_real-name"]); @unlink($_FILES[$file[0]]["tmp_name"]); }else{ $flag=true; if ($_isdisplay) { //$ExtFltr = $file[2]; //$FileSize = $file[4]; if (!eval("if($file[2]){return true;}")){echo $file[3];} if (!eval("if($file[4]){return true;}")){echo $file[5];} $_ErrorList[] = $file[0]; } } } Thanks hi, Is it possible to display an image that is above the root directory using php? for example if i have an image in /home/user/uploads/test.jpg and lets say my root directory for my site is /home/user/public_html/ is it possible to display test.jpg on /home/user/public_html/index.html ? i am trying to create a secure file upload script and i think not having the file be directly accessed by the public is one of the main steps. Hi I'm trying to setup Pagination at the bottom of the page after showing 10 images in the following script but have no clue where to start and how to implement it into the script. hi to all.Im currently displaying the images from my upload directory but the image does not display.please help thanks Code: [Select] <?php $path = "../assets/tattoos/"; $path2 = "../assets/tattoos-thumbs/"; if(isset($_POST['file']) && is_array($_POST['file'])) { foreach($_POST['file'] as $file) { unlink($path. "/" . $file) or die("Failed to delete file"); unlink($path2. "/" . $file) or die("<meta http-equiv=\"refresh\" content=\"0; url=index.php\" />"); } } ?> <form name="form1" method="post"> <?php $imageDir = "../assets/tattoos/"; $dir_handle = @opendir($path) or die("Unable to open folder"); while (false !== ($file = readdir($dir_handle))) { if($file == "index.php") continue; if($file == ".") continue; if($file == "..") continue; echo "<input type='CHECKBOX' name='file[]' value='$file'>"; echo "<img src='../assets/tattoos/$file' style='height:auto;width:8%;' alt='$file'>"; } closedir($dir_handle); ?> <input type="submit" name="Delete" value="Delete"> </form> I have this code, which calls an image directory and adds a checkbox next to it, you check the boxes you wish, hit delete and the pictures are removed from the server. I need them to display in a grid view, like 4 columns by X amount of rows. Any help would be greatly appreciated. Hi guys. Just a quick PHP question. I have a script running that gets the files from a directory. There is then a switch function that decides what to do with the file, ie... if it is a PNG... DO THIS.. if it is a docx... DO THIS.. etc. And i want each file to be in a different cell on the table. The table can be longer wider than 5 columns (however it can be as high as it wants). I currently have this bit working... but instead of one item in each cell... it is displaying every item in each cell. Any ideas Chaps? Here is my code Many thanks in advance if you could possibly help.. echo "<table><tr>"; $count = count(glob("../../shared/files/*.*", GLOB_BRACE)); for($i=1; $i <= $count; $i++) { /// echo "<td>"; /// if ($handle = opendir('../../shared/files/')) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { $break = pathinfo($file); $b = $break['extension']; switch (@$break[extension]) { case 'bmp' : echo 'A BMP<br>'; break; case 'png' : echo 'A PNG<br>'; break; case 'doc' : case 'docx' : echo 'A DOC OR DOCX<br>'; break; default: echo 'FILE NOT RECOGNISED<br>'; } } } closedir($handle); } /// echo "</td>"; /// if($i % 3 == 0) echo "</tr><tr>"; } echo "</tr></table>"; ?> I am trying to display images on a html page alphabetically in descending order by their filename. <?php $dir = "./plate_cache"; $handle = opendir($dir); while (($file = readdir($handle))!==false) { if (strpos($file, '.png',1)) { echo "<img id=\"plates\" src=\"/tags/plate_cache/$file\"></a><br />;"; } } closedir($handle); } ?> Any help is greatly appreciated! I have this script from http://lampload.com/...,view.download/ (I am not using a database) I can upload images fine, I can view files, but I want to delete them. When I press the delete button, nothing happens
http://www.jayg.co.u...oad_gallery.php
<form>
<?php $dir = dirname(__FILENAME__)."/images/gallery" ; $files1 = scandir($dir); foreach($files1 as $file){ if(strlen($file) >=3){ $foil = strstr($file, 'jpg'); // As of PHP 5.3.0 $foil = $file; $pos = strpos($file, 'css'); if ($foil==true){ echo '<input type="checkbox" name="filenames[]" value="'.$foil.'" />'; echo "<img width='130' height='38' src='images/gallery/$file' /><br/>"; // for live host //echo "<img width='130' height='38' src='/ABOOK/SORTING/gallery-dynamic/images/gallery/ $file' /><br/>"; } } }?> <input type="submit" name="mysubmit2" value="Delete"> </form>
any ideas please?
thanks
My images generator comprises
an array of image names extracted form an images table from a database using a select statement
a random number generator,
and a string that builds the correct pathname for the selected file.
To select one of the images for display, i generate a random number between 1 and the length of the array.
Though the generator is working, I noticed one of the random numbers is throwing up this error:
Warning: getimagesize(images/): failed to open stream: No such file or directory in
An inspection of the array reveals 2 array elements (representing my number of images) but one array element is NULL ( the first entry in the banner table
image_generator.php
require_once('connection.inc.php');
$sql = 'SELECT `filename` FROM banner';
$result = $mysqli->query($sql, MYSQLI_STORE_RESULT) or die(mysqli_error());
$row = $result->fetch_array(MYSQLI_ASSOC);//an array of image names
$count = $result->num_rows;
for ($i = 1; $i <= $count; ++$i)
{
$row[$i] = $result->fetch_array(MYSQLI_ASSOC);
}
$i = rand(1, $count); //a random number generator,
//The random number is used in the final line to build the correct pathname for the selected file.
$selectedImage = "images/{$row[$i]['filename']}";
if (file_exists($selectedImage) && is_readable($selectedImage))
{
$imageSize = getimagesize($selectedImage);
}
var_dump($row)
array (size=1)
'filename' => string 'ginsomin2.jpg' (length=13)
null
RANDON IMAGE DISPLAY
require_once 'image_generator.php';
<div id="banner" class="wrapper clearfix">
<img src="<?php echo $selectedImage; ?>" alt="banner">
</div>
Kindly advice how i may proceed from here?
Thanks.
Hi guys, I've been working on a script for a while now, and I'm sure it doesn't look great and all, and it's probably really messed up.. But right now I've finally got it working! There's only 1 thing I'd really like to add.. Searching through & listing of remote directories! The directories I'm trying to list have directory listings enabled, and I think it *should* be possible. I just have no clue how. Here's my current code in a beautiful mix of HTML and PHP: <? $border_size = "0"; function returner($what) { $what=explode("/",$what); $tps=count($what); $what=$what[$tps-1]; return $what; } $page_url= ""; $home_url=returner(__FILE__); if(isset($_GET['q'])) { $qtext=$_GET['q']; } else { $qtext=""; } function getdirsize($directory, $format=FALSE) { $size = 0; if(substr($directory,-1) == '/') { $directory = substr($directory,0,-1); } if(!file_exists($directory) || !is_dir($directory) || !is_readable($directory)) { return -1; } if($handle = opendir($directory)) { while(($file = readdir($handle)) !== false) { $path = $directory.'/'.$file; if($file != '.' && $file != '..') { if(is_file($path)) { $size += filesize($path); } elseif(is_dir($path)) { $handlesize = getdirsize($path); if($handlesize >= 0) { $size += $handlesize; } else { return -1; } } } } closedir($handle); } if($format == TRUE) { if($size / 1048576 > 1) { return round($size / 1048576, 1).' MB'; } elseif($size / 1024 > 1) { return round($size / 1024, 1).' KB'; } else { return round($size, 1).' bytes'; } } else { return $size; } } if(isset($_GET['type'])){ $type=$_GET['type']; } else { $type="new"; } $textures=0; $models=0; $avatars=0; $seqs=0; $sounds=0; foreach (glob("textures/*.jpg") as $texture){ $textures++; } foreach (glob("models/*.zip") as $model){ $models++; } foreach (glob("avatars/*.zip") as $avatar){ $avatars++; } foreach (glob("seqs/*.zip") as $seq){ $seqs++; } foreach (glob("sounds/*.zip") as $sound){ $sounds++; } ?> <!DOCTYPE html> <html> <head> <title>ObjectPath Search</title> <style type="text/css"> #wrapper { width: 850px; margin: 30px auto 30px auto; padding: 10px; } body { color:#C6C6C6; background:#1E1E1E; /* margin:0; padding:0; */ overflow-x:hidden; } #tabs { font: 85% "Trebuchet MS", sans-serif; } .left { float: left; } .right { float: right; } a:link, a:visited, a:active { color: #3DB015; text-decoration: none; } a:hover { color: #00E0FF; } h2 { color: #3DB015; padding-bottom: 0.2em; font-size: 110%; } ul#icon {margin: 0; padding: 0;} ul#icon li {margin: 1px; position: relative; padding: 1px 0; cursor: pointer; float: left; list-style: none;} ul#icon span.ui-icon {float: left; margin: 0 1px;} </style> <link type="text/css" href="http://objects.jk-hosting.com/search/css/black-tie/jquery-ui-1.8.2.custom.css" rel="stylesheet" /> <script type="text/javascript" src="http://objects.jk-hosting.com/search/js/jquery-1.4.2.min.js"></script> <script type="text/javascript" src="http://objects.jk-hosting.com/search/js/jquery-ui-1.8.2.custom.min.js"></script> <script type="text/javascript"> function formHandler(form){ var URL = document.form.site.options[document.form.site.selectedIndex].value; window.location.href = URL; }; $(function(){ // Tabs $('#tabs').tabs(); }); </script> </head> <body> <div id="wrapper"> <div id="tabs"> <!-- Tabs start --> <ul> <li><a href="#tab-search">Search</a></li> <li><a href="#tab-list">List Objects</a></li> <li><a href="#tab-info">OP info</a></li> </ul> <div id="tab-search"><!-- Searchtab start --> Please enter a string to search for, and choose a folder to search in. <br /><br /> <form name="Search"> <input type='hidden' value='search' name='type'> <input value='<? print $qtext; ?>' type='text' name='q'> <select name='map'> <option selected='selected' value='models'>Models</option> <option value='avatars'>Avatars</option> <option value='textures'>Textures</option> <option value='seqs'>Seqs</option> <option value='sounds'>Sounds</option></select> <input type='submit' value='Search'> </form> </div> <!-- Searchtab end --> <div id="tab-list"><!-- Listtab start --> Please pick a folder to browse. <br /><br /> <form name="form"> <select name="site" onChange="javascript:formHandler()"> <option value="#">Look in folder...</option> <option value="<? print $page_url; ?>?type=list&map=models">Models</option> <option value="<? print $page_url; ?>?type=list&map=avatars">Avatars</option> <option value="<? print $page_url; ?>?type=list&map=textures">Textures</option> <option value="<? print $page_url; ?>?type=list&map=seqs">Seqs</option> <option value="<? print $page_url; ?>?type=list&map=sounds">Sounds</option> </select> </form> </div> <!-- Listtab end --> <div id="tab-info"><!-- Info tab start --> The OP currently contains: <br /><br /> <table> <tr><td><b><? echo $models; ?></b></td> <td>Models</td></tr> <tr><td><b><? echo $avatars; ?></b></td> <td>Avatars</td></tr> <tr><td><b><? echo $textures; ?></b></td> <td>Textures</td></tr> <tr><td><b><? echo $seqs; ?></b></td> <td>Seqs</td></tr> <tr><td><b><? echo $sounds; ?></b></td> <td>Sounds</td></tr> </table> </div> <!-- Info tab end --> </div> <!-- Tabs end --> </div> <!-- Start PHP generated content --> <? if($type=="search" || $type=="list") { $M=$_GET['map']; if($type=="search") { $Q=$_GET['q']; $empty="Nothing found with <b>\"" . $Q . "\"</b> in it's name.<br />\nPlease make a more general search query, or try a different folder.\n\n"; } else { $Q=""; $empty='This folder is empty'; } if($M=="textures") { $ext="jpg"; } else { $ext="zip"; } $i=0; print "<hr>\n"; $endfile=array(); $endsize=array(); $endsize2=array(); foreach (glob($M."/*".$Q."*.".$ext) as $filename) { $filename = explode(".", $filename); $filename=$filename[0]; $filename = explode("/", $filename); $filename=$filename[1]; $i++; $endfile[$i]=$filename; if($ext=="jpg") { $endfile[$i]="<a name='".$endfile[$i]."' href='".$pageurl."?type=view&name=".$endfile[$i]."&folder=".$M."&from=".$type."&addon=".$Q."'>".$endfile[$i]."</a>"; } $endsize[$i]=$size; $endsize2[$i]=$size2; } if($i != 1) { print "<b>".$i."</b> items were found.\n<hr>\n"; } else { print "<b>".$i."</b> item was found.\n<hr>\n"; } echo("<table width='100%' border='" . $border_size . "' cellspacing='0' cellpadding='0' >\n"); if($i!=0) { for ($t = 1; $t < $i; $t++) { $thumbfile = $M."/".$endfile[$t].'.jpg'; if(file_exists($thumbfile)) { $thumbnail = "<a name='".$endfile[$t]."' href='".$page_url."?type=view&name=".$endfile[$t]."&folder=".$M."&from=".$type."&addon=".$Q."'><ul id='icon'><li class='ui-state-default ui-corner-all' title='".$endfile[$t]."'><span class='ui-icon ui-icon-image'></span></li></ul></a>"; } else { $thumbnail = ""; } if($t=="1") { echo("<tr><td width='10%'>Number</td><td width='3%'><ul id='icon'><li class='ui-state-default ui-corner-all' title='".$endfile[$t]."'><span class='ui-icon ui-icon-image'></span></li></ul></td><td width='60%'>Name</td></tr>\n"); } echo("<tr><td>" . $t . "</td><td>".$thumbnail."</td><td>" . $endfile[$t] . "</td></tr>\n"); flush(); } $thumbfile = $M."/".$endfile[$t].'.jpg'; if(file_exists($thumbfile)) { $thumbnail = "<a name='".$endfile[$t]."' href='".$page_url."?type=view&name=".$endfile[$t]."&folder=".$M."&from=".$type."&addon=".$Q."'><ul id='icon'><li class='ui-state-default ui-corner-all' title='".$endfile[$t]."'><span class='ui-icon ui-icon-image'></span></li></ul></a>"; } else { $thumbnail = ""; } echo("<tr><td>" . $t . "</td><td>".$thumbnail."</td><td>" . $endfile[$t] . "</td></tr>\n"); } print "</table>\n"; if($i=="0") { print $empty; } } elseif($type=="view") { $filename=$_GET['name']; $folder=$_GET['folder']; if($_GET['from']=="list"){ $addon="?type=list&map=".$folder."#".$filename; } if($_GET['from']=="search"){ $addon="?type=search&q=".$filename."&map=".$folder."#".$filename; } print"<center><a href='".$home_url."'>Home</a></center>"; print "<hr>\n<center><img src='".$folder."/".$filename.".jpg'></img></center>\n<hr>\n<br />\n<a href='".$page_url."".$addon."'>Previous Page</a>\n"; } $htmlshow=""; if($_GET['type']=="returnOPfile") { if(isset($_GET['split'])) { $splitter=$_GET['split']; } else { $splitter=" | "; } if(isset($_GET['html'])) { $htmlshow="<br />"; } foreach (glob("textures/*.jpg") as $texture){ if(isset($_GET['size'])) { $size=$splitter.filesize($texture); } $texture = explode("/", $texture); $texture=$texture[1]; print "textures".$splitter.$texture.$size."\n".$htmlshow; } foreach (glob("models/*.zip") as $model){ if(isset($_GET['size'])) { $size=$splitter.filesize($model); } $model = explode("/", $model); $model=$model[1]; print "models".$splitter.$model.$size."\n".$htmlshow; } foreach (glob("avatars/*.zip") as $avatar){ if(isset($_GET['size'])) { $size=$splitter.filesize($avatar); } $avatar = explode("/", $avatar); $avatar=$avatar[1]; print "avatars".$splitter.$avatar.$size."\n".$htmlshow; } foreach (glob("seqs/*.zip") as $seq){ if(isset($_GET['size'])) { $size=$splitter.filesize($seq); } $seq = explode("/", $seq); $seq=$seq[1]; print "seqs".$splitter.$seq.$size."\n".$htmlshow; } foreach (glob("sounds/*.zip") as $sound){ if(isset($_GET['size'])) { $size=$splitter.filesize($sound); } $sound = explode("/", $sound); $sound=$sound[1]; print "sounds".$splitter.$sound.$size."\n".$htmlshow; } } ?> <!-- End PHP generated content --> </body> </html> So right now my question to you PHP freaks is, can you please help me edit my script so I can search through a remote directory? *This* is one of the directories I wish to be able to search through & list.. Thanks in advance. Edit; It might help if you know what the site currently looks like. *Click* I read everywhere where it says not to stoe images in MYSQL but I have a code where I'm trying to display the images. They are all jpegs that are stored in the table. Here is the code Code: [Select] <?php include "dbaptsConfig.php"; include "searchaptsstyle.css"; // test id, you need to replace this with whatever id you want the result from $id = "1"; // what you want to ask the db $query = "SELECT * FROM `apartments` WHERE `id` = ".$id; // actually asking the db $res = mysql_query($query, $ms); // recieving the answer from the db (you can only use this line if there is always only one result, otherwise will give error) $result = mysql_fetch_assoc($res); // if you uncomment the next line it prints out the whole result as an array (prints out the image as weird characters) // print_r($result); // print out specific information (not the whole array) echo "<br/>"; echo "<div id='title'>".$result['title']."<br/></div>"; echo "<br/>"; echo "<div id='description'>".$result['description']."<br /></div>"; echo "<br/>"; echo "<div id='table'><tr>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Provider's Phone Number: ".$result['phone']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Provider: ".$result['service']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Borough: ".$result['county']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Town: ".$result['town']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Bedrooms: ".$result['rooms']."</td>"; echo "<td> </td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Bathrooms: ".$result['bath']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Square Footage: ".$result['square']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Rent: ".$result['rent']."<br /></td>"; echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Listed On: ".$result['time']."<br /></td>"; echo "</tr></div>"; header("Content-type: image/jpeg"); echo "<td bgcolor='#FFFFFF' style='color: #000' align='center'> Listed On: ".$result['image1']."<br /></td>"; ?> Thanks I want to display thumbnails for a picture gallery and when user clicks on image the larger image opens in a new window. I can't find a straight answer on the php.net website. Can someone help? |
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