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PHP - Hidden Input Field Type Doesnt Store Complete Value
hidden input field type doesnt display the full value i get from table, say if it is a first name and last name i get only the first name. here is my input field
echo "<input type=hidden name=proid value=$result_row[project_id]></include>"; echo "<input type=text value=$result_row[project_name] readonly></include>"; my sql query returns the full name but when i input into the text field it returns an incomplete project name like say if it is fans of soccer, i just get the value "fans" in my display..... Similar TutorialsHi Guys, Appreciate any help here please... Basically I want to hide some inputs on my registration page and populate them will default values. Everything works okay, apart from the input below: Code: [Select] <input type="hidden" name="seek_location" value="Anywhere"> When I use the above, the MYSQL database field for seek_location is left empty... I've noticed that the code below pulls the location into a dropdown list. You know the kind of thing, Australia, UK, USA etc etc: Code: [Select] $seek_location = $wcr[$seek_location]; Code: [Select] <? $p=0;asort($wcr);reset($wcr); while (list ($p, $val) = each ($wcr)) { echo '<option value="'.$p.'">'.$val; } ?> So, all I want to do is have: Code: [Select] <input type="hidden" name="seek_location" value="Anywhere"> Populate seek_location with Anywhere Any help appreciated Thanks Rob i have the following code: <li>Have you read the <?php echo link_to('FAQ','util/faq') ?> ? <select id="yesnolist" onChange="getChoice(this.value)"> <option value="yes" selected="selected">Yes</option> <option value="no">No</option> </select> </li> <input type="hidden" name="text" size=30 id="yesandno"> <?php if ($_GET['yesandno'] == "no") { echo "anything!!!!!!!!!!!!!!!!!!!"; } ?> then my java script for getCoice(): function getChoice(val) { yesNo = new Array("Yes", "No"); var getsel = document.contactus.yesnolist.value; var e = document.getElementById("yesnolist"); var strUser = e.options[e.selectedIndex].value; document.contactus.yesandno.value = strUser; alert(document.contactus.yesandno.value); return strUser; } my alert will gove yes or no depending on what i chose in the dropdown but HOWCOME it does not go into the if ($_GET['yesandno'] == "no") ???? please help??? I have a while loop that fetches data from the database and prints it out organized in a table. Now I want to implement a voting functionality, the problem I'm encountering is, once I've printed out a list of tables one table after other with the while loop I need to figure out a way to tell the query TO WHICH of those tables to ADD or SUBTRACT the vote. I thought of implement a hidden id field into the while loop of contributions, the id field would be fetched from the auto_increment field in the contribution table in the MySQL database. Since the id field is unique there can be no misunderstandings to which table to add the vote. My question how can I do exactly that? How can I add a hidden id field to the while loop with the table WHICH I then can pass along to the voting script. Here's the while loop: while ($row = mysqli_fetch_array($data)) { echo "<table padding='0' margin='0' class='knuffixTable'>"; echo "<tr><td width='65px' height='64px' class='avatar_bg' rowspan='2' colpan='2'><img src='$avatar_path' alt='avatar' /></td><td class='knuffix_username'><strong>" . $user_name; echo "</strong><br />" . $row['category'] . " | " . date('M d, Y', strtotime($row['contributed_date'])) . "</td></tr><tr><td>"; echo "<form action='' method='post'> <input type='submit' name='plusVote' value='Y' /> <input type='submit' name='minusVote' value='N' /> </form></td><td class='votes'>Y[ - ] | N[ - ]</td></tr>"; echo "<tr><td class='knuffix_name' colspan='3'><strong>" . htmlentities($row['name']) . "</strong><br /></td></tr>"; echo "<tr><td colspan='2' class='knuffix_contribution'><pre>" . $row['contribution'] . "</pre><br /></td></tr>"; echo "</table>"; } If I simply add $row['con_id'] it's obviously going to be echo'd out, what is the right practice to have it hidden? so I have this code: Code: [Select] <input type='checkbox' name='title8' value='$title8' /></td><td><strong>$title8</strong> <br /> $date8 <br />$ $price8<input type='hidden' name='price8' value='$price8'> how do I make is so that the hidden field is only going to submit if the checkbox is checked........ With this code I can determine the fieldname and the value. They are $col_key and $col_value respectively: Code: [Select] $sql = "SELECT * FROM $tbl "; $result = mysql_query($sql) while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) { if ($row == 1) { foreach ($line as $col_key => $col_value) { But how do I determine the field TYPE (i.e. varchar, text, date etc)? This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=317004.0 This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=342456.0 Hi all Basically, I have a form which when done will calculate a quote for turf for given areas. Basically each time the user specifies an area it goes into an array, and they can add as many as they want, but the problem seems to be once submitted and it arrives back into the program, it isn't decoding so the multidimensional array is lost. What am I doing wrong here? Full code below, thanks in advance Ste Code: [Select] <?php // Framework // Get the sections $sections_array = base64_decode(unserialize($_POST['sections'])); // Build the rest of the array foreach ($sections_array as $section) { $sections[] = base64_decode(unserialize($section)); } // Set the initial unit $units = $_POST['units']; // Do the new add if ($_POST['a'] == 'add_section') { // Add the new measure if ((is_numeric($_POST['width'])) && (is_numeric($_POST['length']))) { $sections[] = array('length' => $_POST['length'], 'width' => $_POST['width']); } } // Build the output foreach ($sections as $section) { $output .= '<strong>'.$section['width'].' wide</strong> x <strong>'.$section['length'].' long</strong><br />'; $sections_array = base64_encode(serialize($section)); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Untitled Document</title> <style type="text/css"> body,td,th { font-family: Verdana, Geneva, sans-serif; font-size: 11px; } body { margin-left: 0px; margin-top: 0px; margin-right: 0px; margin-bottom: 0px; } .wrap { text-align: center; height: 350px; width: 410px; padding: 0 10px; } </style> </head> <body> <div class="wrap"> <h2>Turf Calculator</h2> <p>To begin, enter the width and length of the first area of garden you wish to turf. You can keep adding sections to work out the final quantity required.</p> <p><?php echo $output; ?></p> <form id="form1" name="form1" method="post" action=""> <table width="0" border="0" cellspacing="0" cellpadding="2"> <tr> <td>Length:</td> <td><input type="text" name="length" id="length" /></td> </tr> <tr> <td>Width:</td> <td><input type="text" name="width" id="width" /></td> </tr> <?php if ($units == '') { ?> <tr> <td>Units:</td> <td><select name="units" id="units"> <option value="feet">Feet</option> <option value="m" selected="selected">Metres</option> <option value="yards">Yards</option> </select></td> </tr> <?php } ?> </table> <p> <input type="submit" name="add" id="add" value="Add This Section" /> <input name="a" type="hidden" id="a" value="add_section" /> <input name="sections" type="hidden" id="sections" value="<?php echo base64_encode(serialize($sections_array)); ?>" /> <?php if ($units != '') { ?> <input name="units" type="hidden" id="units" value="<?php echo $units; ?>" /> <?php } ?> </p> </form> <p> </p> </div> </body> </html> I have created a table called directories. Now basically I have two fields; dirID (INT) directory (VARCHAR) now I am fully aware this might sound like more of an SQL question but I have three physical directories: db/images/web1 db/images/web2 db/images/web3 I have inputted them into the database but I was just wondering, how could I created a page which links those records to a directory. I want to have each row hyperlinked, with the output page displaying list of contents for each directory. How can I possibly achieve this please? This is a cross between HTML, PHP, and MySQL. I'm not exactly sure which to blame (other than myself of course) I'm collecting a bid price in a standard form <input type="number" name="maxbid" value="<?php echo $maxbid ?>"/> I have recalled the value from the database where I store it and display it in the field if it exists. If the field has never been entered, the field shows nothing. It's not required that a bid be entered. There are other fields of data that may be updated and this field is left blank. On the page called by the submit button I'm retrieving the fields $maxbid=$_POST[maxbid]; Then I store the fields in the database either with an INSERT or an UPDATE if(mysql_num_rows(mysql_query("SELECT id FROM data WHERE id = '$id'"))) { echo "Updating....."; mysql_query("UPDATE data SET maxbid='$maxbid', name='$name' where id='$id'"); } else { echo "Inserting....."; mysql_query("INSERT INTO data (id, maxbid,name) VALUES ('$id','$maxbid',$'name')"); } I know I'm not handling the Numeric values correctly, and I'm having a hard time finding the correct method for doing so. Right now, if the name is entered byt the maxbid is left blank, nothing gets inserted or updated. if I enter both the maxbid and the name it works. I can't have maxbid show up as a 0, I need it to be blank if nothing is entered. Also when I check $maxbid, it's not an INTEGER (per INTVAL) when I check it, even though maxbid in the table is an INTEGER. When I pass it around, it seems to lose it's INTEGER value, but still shows as a number. I know this sounds confusing, heck I'm confused. If someone could point me to a good tutorial, I'd figure it all out, but most tutorials don't get into the data type that much, and the combination of the form, passing the variables, reading the values from the database, etc. is what's causing me grief. Any guidance would be appreciated. I have this function completely written in my class file that I am working on. The point to this function is to be able to check the login of a user or administrator for either of the control panels associated with my site. It will check the session intime as well as the page / module referenced. Once it passes all those checks, it will check and ensure the emailaddress/password stored in the current session still holds true and the account is still active... if the account is still active it will update the lastActivity as well as update all of the session variables with what is currently in the database. What I am looking for is basically a look at the function, see if it looks good.. If there is any part to it that could create security holes for the site just off the login function itself... Usage: $q->validUser($_SESSION['user'], $_mod); <?php function validUser($sess, $p) { if ($sess['inTime'] == '' && $p != 'login' && $p != 'logout') { session_destroy(); $login = '0'; $_int = ''; return $login; } else if ($sess['inTime'] < time()-3600 && $p != 'login') { $sess['inTime'] = ''; session_destroy(); $this->check_login($sess, $p); } else { $this->user = $sess['emailAddress']; $this->pass = $sess['password']; $login = $this->sql_query("SELECT * FROM users WHERE emailAddress = '".$this->user."' AND password = '".$this->pass."' AND status = '1' LIMIT '1'"); if ($login = $this->sql_numrows($login) < 1) { $sess['inTime'] == ''; session_destroy(); $login = '0'; } else { // logged in, lets update the database for last_activity AND the session. $this->sql_query("UDATE users SET lastActivity = '".now()."' WHERE emailAddress = '".$this->user."'"); $login = $this->sql_query("SELECT * FROM users WHERE emailAddress = '".$this->user."' AND password = '".$this->pass."' AND status = '1' LIMIT '1'"); $login = mysql_fetch_assoc($login); foreach ($login as $key => $value) { $sess[$key] = $value; } $sess['inTime'] = time(); $login = '1'; } return $login; } } ?> That is the main function, sql_query and sql_numrows is: <?php function sql_query($query = "", $transaction = FALSE) { unset($this->query_result); if ($query != "") { $this->num_queries++; if ($transation == BEGIN_TRANSACTION && !$this->in_transation) { $result = mysql_query("BEGIN", $this->db_connect_id); if (!$result) { return false; } $this->in_transaction = TRUE; } $this->query_result = mysql_query($query, $this->db_connect_id); } else { if ($transaction == END_TRANSACTION && $this->in_transaction ) { $result = mysql_query("COMMIT", $this->db_connect_id); } } if ($this->query_result) { unset($this->row[$this->query_result]); unset($this->rowset[$this->query_result]); if ($transaction == END_TRANSACTION && $this->in_transaction ) { $this->in_transaction = FALSE; if (!mysql_query("COMMIT", $this->db_connect_id)) { mysql_query("ROLLBACK", $this->db_connect_id); return false; } } return $this->query_result; } else { if ($this->in_transaction ) { mysql_query("ROLLBACK", $this->db_connect_id); $this->in_transaction = FALSE; } return false; } } function sql_numrows($query_id = 0) { if(!$query_id) { $query_id = $this->query_result; } return ($query_id) ? mysql_num_rows($query_id) : false; } ?> Any insight that can help to benefit these functions would be appreciated. How can I make it so that the things that the user recently typed in an input is not displayed as a drop down. I want nothing to be displayed. I am trying to set the hidden input in the javascript but it doesn't set it in the php. This is the form with the hidden input. It corresponds to a field in the database table with the name of draggables. <form method="post" accept-charset="utf-8" id="myForm2" action="/mealplans/add"> <input type="hidden" name="draggables" id="drag12"/> <button id="myId" type="submit">Submit Form</button> </form> This is where I change the value in the javascript:
if(data == "draggable3"){
alert("data " + data);
var x = document.getElementById("drag12").value;
x = "draggable3";
alert(x);
} //end if
I've also tried getElementsByName but that didn't work either.
var y = document.getElementsByName("draggables").value; //only changes it on the client
This is actually a cakephp site but this problem is with the PHP so I am publishing it here. This function is throwing the following error: invalid input syntax for type timestamp "1301297896" Code: [Select] function removeInactiveUsers(){ if(!TRACK_VISITORS) return; $timeout = time()-USER_TIMEOUT*60; $result = pg_query_params($this->connection, "delete from active_users where timestamp < $1", array($timeout)); $this->calcNumActiveUsers(); } I know the problem is with $timeout using a php timestamp vs postgresql timestamp but I'm not sure how to fix that Hey guys! I'm making a locally run web based application for entering/storing/editing data. I am trying to do this thing where I export a 'records.txt' file to a different location which can be selected by the user. I have a lame <input type='text' value='H:\'> box going on which I was going to use to define the path for the file to be saved, but I want to be able to use a pop up windows (or whatever native OS finder application) just like the one which appears when you use <input type='file'>. Now that I think about it, I think this is more of a html question, but it's 2.30am and my project is due today... See! what the hell, I just habitually pressed ctrl-s after working in dreamweaver for hours and the exact function which I am looking for popped up, how do I do that?! Please thanks guys Hello, Iv written a small script in JS to add input boxes of the type file to the page.. My problem is when i use multiple of those input boxes and submit the form the $_FILES variable only reads 1 of those boxes.. This is the javascript im using: Code: [Select] function addImageBox() { var imageBoxes = document.getElementById("imageBoxes"); var tr = document.createElement("tr"); var td = document.createElement("td"); var td2 = document.createElement("td"); var inputFile = document.createElement("input"); inputFile.setAttribute("type", "file"); inputFile.setAttribute("name", "image[]"); inputFile.setAttribute("style", "width: 450px"); td.appendChild(document.createTextNode("Image")); td2.appendChild(inputFile); tr.appendChild(td); tr.appendChild(td2); imageBoxes.appendChild(tr); } When i add 2 boxes (making it 3 boxes on the page in total) and count the $_FILES var after submiting the form, the count method returns 1, and when i var_dump it only 1 array is in $_FILES. Any idea's? thanks! I think I understand that there can only be one "submit" button on a page.
I want buttons for separate forms to not trigger the empty errors on the other forms...
How do you accomplish specific button actions?
I think I've tried it with javascript but you can do it with PHP right?
Thanks for any help.
Long time lurker, first time poster here. I am having a problem with a multiple file uploader form I am trying to build. I am using the CodeIgniter framework, but I believe my problem is with the form itself. Here is the form: Code: [Select] <form action="http://localhost/show/submit" id="sendfiles" method="post" name="sendfiles" enctype="multipart/form-data"> <input type="hidden" name="doup" value="1" /> <input type="file" name="userfile1" value="" id="userfile1" size="20" /> <br /> <input type="file" name="userfile2" value="" id="userfile2" size="20" /> <br /> <input type="file" name="userfile3" value="" id="userfile3" size="20" /> <br /> <input type="submit" name="submit_btn" value="Upload" /> </form> The form is being passed to this function: if(empty($_POST['doup'])){ foreach($_REQUEST as $k => $v) print ">>> $k : $v <br />"; $data['form_open'] = form_open_multipart(uri_string(), array( 'id' => 'sendfiles', 'method' => 'post', 'name' => 'sendfiles' )); $data['form_flag'] = form_hidden('doup', '1'); $data['file1'] = form_input(array( 'id' => 'userfile1', 'name' => 'userfile1', 'size' => '20', 'type' => 'file', )); $data['file2'] = form_input(array( 'id' => 'userfile2', 'name' => 'userfile2', 'size' => '20', 'type' => 'file', )); $data['file3'] = form_input(array( 'id' => 'userfile3', 'name' => 'userfile3', 'size' => '20', 'type' => 'file', )); $data['form_submit'] = form_submit('submit_btn', 'Upload'); $data['form_close'] = form_close(); $this->load->view('show/submit', $data); } else { $config['allowed_types'] = 'mp3'; $config['max_size'] = '10240'; $config['upload_path'] = $this->config->item('file_upload_path'); $uploaded_files = array(); for($nona=1; $nona<4; $nona++){ if (strlen($_FILES['userfile'.$nona]['tmp_name']) <=0){ echo "tempname$nona failed"; continue; } //print "------ USERFILE $nona ------ <br />"; //print sizeof($_FILES['userfile'.$nona])."<br />"; //foreach ($_FILES['userfile'.$nona] as $k => $v){ // print "$k : $v <br />"; //} $this->upload->initialize($config); $upload = $this->upload->do_upload('userfile'.$nona); if (!$upload){ $form_errors = array('form_errors' => $this->upload->display_errors()); $this->load->view('show/submit', $form_errors); break; } else { $data = array('upload_data' => $this->upload->data()); $data = $data['upload_data']; $fp = $data['full_path']; $filename = strtolower(random_string('numeric', 16) . $data['file_ext']); $rel_path = 'show/submissons/uploaded/'; $path = $this->config->item('media_root_path') . $rel_path; exec('mkdir -p ' . $path , $a1, $r1); exec('mv ' . $fp . ' ' . $path . $filename, $a2, $r2); array_push($uploaded_files, $path . $filename); } } $this->session->set_flashdata('img_data',implode("||", $uploaded_files)); // redirect("show/submit_info"); } The problem is this: When I choose only one file to upload, it works. I can choose any of the 3 inputs and it works great. But as soon as I try to choose 2 or more files, the form fails to post. When I press submit, the page simply reloads and none of the form variables get posted. I have checked settings in php.ini and tried building and rebuilding this form. I'm hoping someone here can provide some insight into what I'm doing wrong? |
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