PHP - Adding A Value From Mysql Query Array Into A Php Array
So I'm querying my database to add the results (mapID's) into a PHP array.
The MySQL query I used in the below code would usually return 10 values (only 10 mapID's in the database) Code: [Select] while($data = mysql_fetch_array(mysql_query("SELECT mapID FROM maps"))){ $sqlsearchdata[] = $data['mapID']; } Instead the page takes ages to load then gives this error: Quote Fatal error: Allowed memory size of 8388608 bytes exhausted (tried to allocate 16 bytes) It says the error begins on the first line of the above code. I'm assuming this is not the right way to add the value from the MySQL array into a normal PHP array. Can anyone help me? Similar TutorialsHello guys, Got a question here.. If I have a database table called features with the following columns with example f_id | f_name | f_status 1 | deck | 1 2 | Fireplace | 1 3 | Alarm | 1 I have another table another table called ads that has a column called features and it has the following 1,2,3 (for example) I want to be able to query the db and display all the f_name. Here is what I have so far but it's not working and need some help Code: [Select] // Query the ads table $result3 = mysql_query("SELECT * FROM ads WHERE ad_id='$id2'") or die(mysql_error()); $row3 = mysql_fetch_array( $result3 ); $features = $row3['features']; echo'This is the features ' . $features .''; $feature2 = explode(",", $features); print_r($feature2); echo "test" . $feature2[0]; // piece1 echo $feature2[1]; // piece2 $result = mysql_query("SELECT * FROM features WHERE f_id=$feature2[1]") or die("Sql error : " . mysql_error()); while($row = mysql_fetch_assoc ($result)){ $f_name=$row["f_name"]; echo $f_name; } Hello Guys, I have a question I have the following query $result3 = mysql_query("SELECT * FROM table1 WHERE ad_id='$id2'") or die(mysql_error()); $row3 = mysql_fetch_array( $result3 ); // Grab all the var $features = $row3['features']; I am turning it into an array (comma separated) $feature2 = explode(",", $features); print_r($feature2); ) The result is like so Array ( [0] => 5 [1] => 9 [2] => 13 I want to query the features for just the ids (F_name) are for the features . This query will show all.. I would like to just display the f_name values from the array query. // build and execute the query $sql = "SELECT * FROM features"; $result = mysql_query($sql); // iterate through the results while ($row = mysql_fetch_array($result)) { echo $row['f_name']; echo "<br />"; } Please Advise.. Thanks, Dan I have tried many ways of storing an array of data that comes from a multiple selection form into a mysql table, including serialization. I am currently trying to do it by forming a string, and using the string in the insert query, but keep getting errors, or just nothing happening. I am not sure what I am doing wrong. Code: [Select] $categoryString = array(); if ($categoryArray){ foreach ($categoryArray as $category){ $categoryString[] = $category.'<br />';} } $categoryquery= "INSERT INTO categoryname VALUES('$categoryString')"; mysql_query($categoryquery); Thank you for your time as always. when i run the below code i get an error...
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in...
but when i take out the h>0 then there is no errors in the code. in table users, i need all columns in the array. How to get h>0 working?
$query = "SELECT * FROM users WHERE h>0 ORDER BY id"; $result = mysqli_query($link, $query); $data = array(); while($row1 = mysqli_fetch_array($result)) { $data[] = $row1; } print_r($data); Edited by kalster, 27 October 2014 - 07:38 PM. Hi all, I have the following code that queries a MySQL database and outputs results on-screen. Code: [Select] $result= mysql_query (" SELECT email,firstname,lastname FROM tablename WHERE ID IN('".$IDs."') "); if (!$result) {die('Error: Could not search database. ' );} while($row = mysql_fetch_assoc($result)) { echo $row['firstname']," ",$row['lastname'],"<br />"; $emails[]=$row['email']; } var_dump($emails); var_dump($IDs); However, the two var_dump's output the following (in the case of 2 results for the query): array(6) { => string(14) "email1@email.com" [1]=> string(23) "email2@email.com" [2]=> string(14) "email1@email.com" [3]=> string(23) "email2@email.com" [4]=> string(14) "email1@email.com" [5]=> string(23) "email2@email.com" } string(67) "9543219aa68ffa1d434dc8530f23fe48','d4384b2b493867706b0bcedda012ed48" ($IDs is an imploded array) Even though the MySQL table only contains one email per ID, both emails are listed 3 times in $emails, instead of just once. Can anyone see why this is? I'm stuck. Thanks! Using curl_multi, I have loaded up 3 url's and then printed the array. 1) How can I also set a timestamp on output to let me know when each url was run? 2) How can I explode the array to only display the data and timestamp, excluding the text "Array ( =>", "[1] =>", "[2] =>" and " )"? Code <?php function multiRequest($data, $options = array()) { // array of curl handles $curly = array(); // data to be returned $result = array(); // multi handle $mh = curl_multi_init(); // loop through $data and create curl handles // then add them to the multi-handle foreach ($data as $id => $d) { $curly[$id] = curl_init(); $url = (is_array($d) && !empty($d['url'])) ? $d['url'] : $d; curl_setopt($curly[$id], CURLOPT_URL, $url); curl_setopt($curly[$id], CURLOPT_HEADER, 0); curl_setopt($curly[$id], CURLOPT_RETURNTRANSFER, 1); // post? if (is_array($d)) { if (!empty($d['post'])) { curl_setopt($curly[$id], CURLOPT_POST, 1); curl_setopt($curly[$id], CURLOPT_POSTFIELDS, $d['post']); } } // extra options? if (!empty($options)) { curl_setopt_array($curly[$id], $options); } curl_multi_add_handle($mh, $curly[$id]); } // execute the handles $running = null; do { curl_multi_exec($mh, $running); } while($running > 0); // get content and remove handles foreach($curly as $id => $c) { $result[$id] = curl_multi_getcontent($c); curl_multi_remove_handle($mh, $c); } // all done curl_multi_close($mh); return $result; } $data = array(array(),array()); $data[0]['url'] = 'http://search.yahooapis.com/VideoSearchService/V1/videoSearch?appid=YahooDemo&query=Pearl+Jam&output=json'; $data[1]['url'] = 'http://search.yahooapis.com/VideoSearchService/V1/videoSearch?appid=YahooDemo&query=Black+Eyed+Peas&output=json'; $data[2]['url'] = 'http://search.yahooapis.com/VideoSearchService/V1/videoSearch?appid=YahooDemo&query=Nirvana&output=json'; $r = multiRequest($data); print_r($r); ?> Output Array ( => Pearl Jam [1] => Black Eyed Peas [2] => Nirvana ) Preferred Output 01:00:01 Pearl Jam 01:00:02 Black Eyed Peas 01:00:03 Nirvana I have a MySQL table with a list of albums and there is a field called "views" with the number of views each album has received. I'm looking to generate an array of all the albums in the table and sort the array by the number of views (descending). I have a list of functions defined in a ContentController.php file. I created a new function called build_albumlist, which I've pasted below. The function "get_ip_log" already exists and works, and I used it as a template to create the "build_albumlist" function: public function build_albumlist(){ return $this->select_raw("SELECT * FROM albums WHERE deleted = '0' ORDER BY views DESC",array(),'all'); } public function get_ip_log(){ return $this->select_raw("SELECT * FROM sessions ORDER BY ID DESC",array(),'all'); } When I use the function, I get this warning: Warning: mysql_real_escape_string() expects parameter 1 to be string, array given inC:\xampp\htdocs\Controllers\DBController.php on line 10 [font=cabin, 'trebuchet ms', helvetica, arial, sans-serif]The "select_raw" function that I used in "build_albumlist" is defined in the DBController.php file, and is defined as below:[/font] private function clean_array($params){ $final=array(); foreach($params as $param){ $final[]=mysql_real_escape_string($param); } return $final; } public function select_raw($query,$params,$type=''){ $query=str_replace("?","'%s'",$query); $final_query= call_user_func_array('sprintf', array_merge((array)$query, $this->clean_array($params))); if($type==''){ $result=mysql_query($final_query) or die(mysql_error()); return mysql_fetch_assoc($result); } elseif($type=='all'){ $result=mysql_query($final_query) or die(mysql_error()); $final=array(); while($row=mysql_fetch_assoc($result)){ $final[]=$row; } return $final; } Does anyone know why the "build_albumlist" function is generating this warning, while the "get_ip_log" is not? Any help would be great, as I am obviously pretty new to this. I have these two tables...
schedule (gameid, homeid, awayid, weekno, seasonno)
teams (teamid, location, nickname)
This mysql query below gets me schedule info for ALL 32 teams in an array...
$sql = "SELECT h.nickname AS home, a.nickname AS away, h.teamid AS homeid, a.teamid AS awayid, s.weekno FROM schedule s INNER JOIN teams h ON s.homeid = h.teamid LEFT JOIN teams a ON s.awayid = a.teamid WHERE s.seasonno =2014"; $schedule= mysqli_query($connection, $sql); if (!$schedule) { die("Database query failed: " . mysqli_error($connection)); } else { // Placeholder for data $data = array(); while($row = mysqli_fetch_assoc($schedule)) { if ($row['away'] == "") {$row['away']="BYE";} $data[$row['homeid']][$row['weekno']] = $row['away']; $data[$row['awayid']][$row['weekno']] = '@ '.$row['home']; } }However, I only want to get info for one specific team, which is stored in the $teamid variable. This should be very easy, right? I have tried multiple things, including this one below (where I added an AND statement of "AND (h.teamid=$teamid OR a.teamid=$teamid)"), but this one still outputs too much... $sql = "SELECT h.nickname AS home, a.nickname AS away, h.teamid AS homeid, a.teamid AS awayid, s.weekno FROM schedule s INNER JOIN teams h ON s.homeid = h.teamid LEFT JOIN teams a ON s.awayid = a.teamid WHERE s.seasonno =2014 AND (h.teamid=$teamid OR a.teamid=$teamid)"; $schedule= mysqli_query($connection, $sql); if (!$schedule) { die("Database query failed: " . mysqli_error($connection)); } else { // Placeholder for data $data = array(); while($row = mysqli_fetch_assoc($schedule)) { if ($row['away'] == "") {$row['away']="BYE";} $data[$row['homeid']][$row['weekno']] = $row['away']; $data[$row['awayid']][$row['weekno']] = '@ '.$row['home']; } }Below is the array that the above outputs. In a nutshell, all I want is that 1st array ([1]) which has, in this example, the Eagles full schedule. It's not giving me too much else and I guess I could live with it and just ignore the other stuff, but I'd rather be as efficient as possible and only get what I need... Array ( [1] => Array ( [1] => Jaguars [2] => @ Colts [3] => Redskins [4] => @ 49ers [5] => Rams [6] => Giants [7] => BYE [8] => @ Cardinals [9] => @ Texans [10] => Panthers [11] => @ Packers [12] => Titans [13] => @ Cowboys [14] => Seahawks [15] => Cowboys [16] => @ Redskins [17] => @ Giants ) [27] => Array ( [1] => @ Eagles ) [28] => Array ( [2] => Eagles ) [4] => Array ( [3] => @ Eagles [16] => Eagles ) [14] => Array ( [4] => Eagles ) [15] => Array ( [5] => @ Eagles ) [3] => Array ( [6] => @ Eagles [17] => Eagles ) [] => Array ( [7] => @ Eagles ) [16] => Array ( [8] => Eagles ) [25] => Array ( [9] => Eagles ) [11] => Array ( [10] => @ Eagles ) [7] => Array ( [11] => Eagles ) [26] => Array ( [12] => @ Eagles ) [2] => Array ( [13] => Eagles [15] => @ Eagles ) [13] => Array ( [14] => @ Eagles ) ) Hi All, First time posting here. I've googled the problem, but can't seem to find a response that's the same. All I want to do is have a list of id numbers and for each id number in the array, submit a MySQL query to retrieve information relating to the id number. When I execute the code below however, I end up with only the last item in the array being printed in the echo statement. Any clues? Thanks, Code: [Select] // get array of ids $ids = getIDs($ids); // loop through input list foreach ($ids as &$id) { getVarDetails($id); } function getVarDetails($local) { $con = mysql_connect('localhost:3306', 'root', '********'); if (!$con) { die('Could not connect: ' . mysql_error()); } // set database as Ensembl mysql_select_db("Ensembl", $con); $result = mysql_query("SELECT * FROM variations WHERE name = '$local' LIMIT 1"); $row = mysql_fetch_array($result) while($row = mysql_fetch_array($result)) { echo $row['name'] . " " . $row['id']; echo "<br />"; } // close connection mysql_close($con); } Hi all, I have the following MySQL insert query: Code: [Select] $insert= mysql_query ("INSERT INTO tablename (column1,`".$EXPfields."`) VALUES ('$something','".$EXPvalues."')"); where $EXPfields is an array of table-field-names and $EXPvalues is an array of table-field-values. Now I want to write an equivalent query, but using UPDATE instead of INSERT INTO, but I don't want to write out all the field names/values separately, but again want to use $EXPfields and $EXPvalues. So something like this: Code: [Select] $update = mysql_query ("UPDATE tablename SET (column1,`".$EXPfields."`) = ('$something','".$EXPvalues."') WHERE .... "); Is this possible? If so, what is the proper syntax? Thanks! How can i save array from inputs, witch is $igraci and it have 5 values, to mysql base, i tryed but in mysql it shows Array. This is form: <form action="dodaj_klan.php" method="post" > <p> <label>Naziv klana:</label> <input name="naziv" type="text" size="20%" /> <label>Web Sajt:</label> <input name="website" type="text" size="20%" /> <label>E-Mail:</label> <input name="email" type="text" size="20%" /> <br /><br /> <label>Igraci klana(5):</label> <input name="lider" type="radio" value="1" /> <input name="igraci[]" type="text" size="20%" /><br /> <input name="lider" type="radio" value="2" /> <input name="igraci[]" type="text" size="20%" /><br /> <input name="lider" type="radio" value="3" /> <input name="igraci[]" type="text" size="20%" /><br /> <input name="lider" type="radio" value="4" /> <input name="igraci[]" type="text" size="20%" /><br /> <input name="lider" type="radio" value="5" /> <input name="igraci[]" type="text" size="20%" /> <label><i>(obelezi lidera klana)</i></label> <br /><br /> <input class="button" type="submit" name="submit" value="Dodaj" /> </p> </form> Now i wonna save this igraci[] array in mysql, i tried like this but it doesn't work: $igraci = $_POST['igraci']; $query = "INSERT INTO klanovi (naziv, website, email, igraci) VALUES ('{$naziv}', '{$website}', '{$email}', '{$igraci}')"; $result = mysql_query($query, $connection); How can i do this? Thanks.. mysql_query("update pupils set record='running' where pid !='$testing[0]' Say I do a query from a database that only asks for one field in return (which always has a number in it). How do you write the PHP to take the first number returned and add it to the next number returned (NOTE: There may be more than two numbers returned, but for now, I'm always dealing with two) For example, say I do a query that returns the number 27 first and then the number 10 second. FYI, these numbers will be available in the variable $diff['result']. So the code after the query would look something like this, but obviously i'm struggling with the part in comments... Code: [Select] if (!$numbers) { die("Database query failed: " . mysql_error()); } else { while ($diff = mysql_fetch_array($numbers)) { //this would bring back 27 first, in the variable $diff['result'] and then on the 2nd loop through, it would bring back 10 in the $diff['result'] variable //ultimately, i just want the difference between the numbers (which in the case would be 17). It's just a simple addition, so Im obviously an idiot because I can't figure out the syntax for adding the first returned number to the next returned number:) } } HI. I have written a mysql database query to add up invoice totals. It seems to be automatilaly adding .01 to the result when I run a group by. Let me explain more ..
When I do a select on the field that I am adding up the result is $132.25 - the query is as follows
select ttl_invoice_due from 65_it where st_id = 96011;
When I run the following query that uses sum and group by - the $132.25 becomes $132.26 - the sum query is
SELECT 65_st.job_compid, 65_client.uid_client, 65_client.comp_name, Sum(65_it.ttl_invoice_due) AS SumOftotal_due, Sum(65_it.ttl_invoice) AS SumOftotal_invoice, Sum(65_it.ttl_invoice_payments) AS SumOftotal_amnt_paid FROM 65_client INNER JOIN (65_st INNER JOIN 65_it ON 65_st.st_id = 65_it.st_id) ON 65_client.uid_client = 65_st.uid_client WHERE 65_st.uid_client = 1905 and 65_st.job_compid = 1 and 65_st.sales_date<=curdate() GROUP BY 65_st.job_compid, 65_client.uid_client HAVING (((Sum(65_it.ttl_invoice_due))<>0)) order by 65_client.comp_name;
The 65_it.ttl_invoice_due field is defined in the table as Double(12,2)
I dont know why the sum is returing $132.26 where it should be $132.25 as in the simple query ?.
I've got a site running, and I would like to add up the totals from each location to one number, now I know it can be done, I just don't know how it'll work with my current code (see below) <table summary="" border="1" width="1100"> <tr> <td>Date</td> <!-- <td>Employee</td> --> <td>Store</td> <td>Customers</td> <td>Quotes</td> <td>Phone Calls</td> <td>Services In</td> <td>Services Out</td> <td>Invoices</td> <td>Conversion</td> <td>End of Day</td> <td>Emails</td> <td colspan=3>Notes</td> </tr> <? $x = 1; $y=1; $lastdate=0; while ($list = mysql_fetch_assoc($query)) { $dateadd = $list['dateadd']; $dateb = strtotime($list['dateadd']); $date = date("M j Y", $dateb);$date2 = date("Y-m-d", $dateb); $firstname = $list['firstname'];$lastname = $list['lastname'];$store = $list['store'];$customers = $list['cust'];$sales = $list['sales'];$invoices = $list['invoices'];$sin = $list['servin'];$sout = $list['servout'];$eod = $list['eod']; $phone = $list['phone']; $notes = $list['notes']; $emails = $list['emails']; if ($store == "1") {$storename = "Broadmead";} elseif ($store == "2") {$storename = "Duncan";} elseif ($store == "3") {$storename = "Surrey";} elseif ($store == "4") {$storename = "Sooke";} elseif ($store == "5") {$storename = "Nanaimo";} elseif ($store == "6") {$storename = "Shelbourne";} ?> <?php if ($lastdate == $date) { ?> <tr> <td width="125"><?=$date;?></td> <!-- <td width="125"><?=$firstname;?> <?=$lastname;?></td> --> <td width="100"><?=$storename;?></td> <td width="71"><?=$customers;?></td> <td width="71"><?=$sales;?></td> <td width="80"><?=$phone;?></td> <td width="80"><?=$sin;?></td> <td width="90"><?=$sout;?></td> <td width="71"><?=$invoices;?></td> <td width="71"><? $convbase = $sout+$sales; if (!$invoices==0 && !$customers==0) {$conv = $invoices / $customers * 100;} else {$conv=0;} echo money_format('%(#1n', $conv) . "\n"; ?>%</td> <td width="71">$<?echo money_format('%(#1n', $eod) . ""; ?><td> <td width="71"><?=$emails;?> </td> <td width="150"><?if (!$notes==NULL){echo $notes;} else {echo " ";}?></td> </tr> <?php } else { ?> <tr> <td colspan="9">Daily Total</td> <td><?echo money_format('%(#1n', $total) . ""; ?> </td> <td colspan="4"> </td> </tr> </table> <hr width="1100" align="left" color="0000ff"> <table summary="" border="1" width="1100"> <tr> <td width="125"><?=$date;?></td> <!-- <td width="125"><?=$firstname;?> <?=$lastname;?></td> --> <td width="100"><?=$storename;?></td> <td width="71"><?=$customers;?></td> <td width="71"><?=$sales;?></td> <td width="80"><?=$phone;?></td> <td width="80"><?=$sin;?></td> <td width="90"><?=$sout;?></td> <td width="71"><?=$invoices;?></td> <td width="71"><? $convbase = $sout+$sales; if (!$invoices==0 && !$customers==0) {$conv = $invoices / $customers * 100;} else {$conv=0;} echo money_format('%(#1n', $conv) . "\n"; ?>%</td> <td width="71">$<?echo money_format('%(#1n', $eod) . ""; ?><td> <td width="71"><?=$emails;?> </td> <td width="150"><?if (!$notes==NULL){echo $notes;} else {echo " ";}?></td> </tr> <?php } $lastdate = $date; } // end while ?> </table> Any help would be appreciated. Here's the code: Code: [Select] $year_values = array('Any', 'N/A', '2000', '2001', '2002', '2003', '2004', '2005', '2006', '2007', '2008', '2009', '2010', '2011', '2012'); $db_year = explode(', ', $row['YEAR']); foreach($year_values as $year_value) { $selected_year = null; $year_label = $year_value; if(in_array($year_value, $db_year)) { $selected_year = ' checked="checked"'; $year_label = "<b>$year_value</b>"; } echo '<input type="checkbox" name="year" value="' . $year_value . '"' . $selected_year . ' />' . $year_label . ' '; } ?> [/code That pulls the data of the database and puts it in check boxes. The user can check/uncheck certain boxes but the problem is when it goes to the verify page it has only one value from the array that was selected. On the verify page it just checks if a box was checked and then implodes the array before submitting it into the database. [code] $year_s=implode($year,", "); So like I said there is only one value from the array when there should be as many as the user checks. So basically I believe the value isn't added to the array. from what i understand from the coding... $form->getField('uri') is for the Sql table field (field uri) location and ->getValue() is the inputbox Value so ->setUri is grabbing the inputbox value and inserting it into Field 'uri' but what I need to do is combine getValue with the string/url profile.site.com/file?name= Code: [Select] $new_uri ->setUri($form->getField('uri')->getValue()) ->setHost($form->getField('host')->getValue()) ->setUser($user->isAuthorized() ? $user->getId() : 0) ->save(); Hi I currently pass a URL to our website as follows: http://website.com/?nid=10 but want to extend this to include a keyword from google as well. For example http://website.com/?nid=10&kw={keyword}. However it may not always have a keyword so if it does not it needs to just use the nid array. This is the current script, how do I go about changing it so that if it just contains a nid and no keyword it will do one search of the array and return the result, and if it does have a nid&keywordod it returns something different. For example if it had nid=1 it would return 0844 000 0300 and if it had nid=1&kw=help it would return 0844 000 0350 Thats what I am looking to achieve. Is this possible and how do I change the array. I have had a little attempt but not sure what I am doing and just got coding errors. <?php $GLOBALS['ct_get_parameter_name'] = 'nid'; $GLOBALS['ct_default_number_id'] = 0; // source_id => phone number $GLOBALS['numbers'] = array( 0 => '0844 000 3000', 1 => '0844 000 0300', 2 => '0844 000 0301', 3 => '0844 000 0302', ); session_start(); if (array_key_exists($GLOBALS['ct_get_parameter_name'], $_REQUEST)) { $_SESSION['ct_source'] = $_REQUEST[$GLOBALS['ct_get_parameter_name']]; } function get_phone_number() { $numbers =& $GLOBALS['numbers']; $default_number_id = $GLOBALS['ct_default_number_id']; if (isset($_SESSION['ct_source'])) { if (array_key_exists($_SESSION['ct_source'], $numbers)) { return $numbers[$_SESSION['ct_source']]; } else { // otherwise return first number return $numbers[$default_number_id]; } } else { // return first number return $numbers[$default_number_id]; } } ?> Many thanks in advance. Roy i need help with adding an integer into an array something like this $Loaded[count($Loaded)+1] = $To; |