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PHP - Multiple If/else Statements
Hi There,
Im trying to figure out how to do this if/else statement. I need it to say, "if this is true, do this. if this is true, do this. If neither is true, do this. So there are three different possible outcomes. I tried to put each new if inside of the previous else. but that doesn't seem to work. $firstname = $_REQUEST['firstname']; $lastname = $_REQUEST['lastname']; if ($firstname == 'Joey' and $lastname == 'Hodara') { $output = 'Welcome to our site, ' . htmlspecialchars($firstname, ENT_QUOTES, 'UTF-8') . ', Oh Glorious Leader!'; } else { if ($firstname == 'Matt' and $lastname == 'Fig') { $output = 'Welcome to our site, ' . htmlspecialchars($firstname, ENT_QUOTES, 'UTF-8') . ', Portagee!'; } else{ if ($firstname == 'Jon' and $lastname == 'Spense') { $output = 'Welcome to our site, ' . htmlspecialchars($firstname, ENT_QUOTES, 'UTF-8') . ', bro!'; } } $output = 'Welcome to our site, ' . htmlspecialchars($firstname, ENT_QUOTES, 'UTF-8') . ' ' . htmlspecialchars($lastname, ENT_QUOTES, 'UTF-8') . '!'; ?> Similar TutorialsHey everyone, i am currently working on a "contact us" script. I want the form to first allow the user which department they want to email. E.g. "Sales" and "Support" By changing this drop down box it will change which email the form is sent to. Im having trouble setting the PHP side of this script up to change the emails. Any help regarding this matter is much appreciated. HTML FORM: Code: [Select] <form name="contactForm" method="post" action="forms/contactUs.php"> <table width="350" border="0"> <tr> <td width="150" class="bold">Department:</td> <td width="200" align="left"> <select name="department" class="dropDown"> <option value="sales">Sales</option> <option value="support">Support</option> </select> </td> </tr> <tr> <td class="bold">Full Name:</td> <td> <input name="name" type="text" class="contactTextBox" /> </td> </tr> <tr> <td class="bold">Company:</td> <td> <input name="company" type="text" class="contactTextBox" /> </td> </tr> <tr> <td class="bold">Email:</td> <td> <input name="email" type="text" class="contactTextBox" /> </td> </tr> <tr> <td class="bold">Comments:</td> <td> <textarea name="com" id="com" cols="5" rows="5" class="contactTextArea" /></textarea> </td> </tr> <tr> <td> </td> <td align="right"> <input type="submit" class="button" value="Submit" /> <input type="reset" class="button" value="Reset" /> </td> </tr> </table> </form>PHP <?php $department = $_POST['department']; $confirm = "sales"; if(isset($_POST['email'])) { if($department == $confirm) { $email_to = "sales@pixemadesigns.com"; $email_subject = "Sales Question"; } else { $email_to = "support@pixemadesigns.com"; $email_subject = "Support Question"; } $fullName = $_POST['name']; $company = $_POST['company']; $email_from = $_POST['email']; $comments = $_POST['com']; $email_message = "Form details below.\n\n"; function clean_string($string) { $bad = array("content-type","bcc:","to:","cc:","href"); return str_replace($bad,"",$string); } $email_message .= "Full Name: ".clean_string($fullName)."\n"; $email_message .= "Company: ".clean_string($company)."\n"; $email_message .= "Email: ".clean_string($email_from)."\n"; $email_message .= "Comments: ".clean_string($comments)."\n"; // create email headers $headers = 'From: '.$email_from."\r\n". 'Reply-To: '.$email_from."\r\n" . 'X-Mailer: PHP/' . phpversion(); @mail($email_to, $email_subject, $email_message, $headers); header("location: ../contactSubmit.html"); ?> <? } ?> Hi. Currently I have code the uses both TRUE. IF statements and FALSE statements to move on. For example. Is it better to use: Code: [Select] Where B=A C=A IF A=B { IF C=B{ ECHO 'HELLO WORLD'; }ELSE ECHO 'C DOES NOT EQUAL B'; }ELSE ECHO 'A DOES NOT EQUAL B'; ' OR is it better to do it like this: Code: [Select] Where B=A C=A IF A<>B { ECHO 'C DOES NOT EQUAL B'; ELSE IF C<>B{ ECHO 'C DOES NOT EQUAL B'; ELSE ECHO 'HELLO WORLD'; '[/code Hi, can't get my head around this one! I have this code :-
if (isset($_SESSION['cartid']) && !isset($_SESSION['lockedcard']) && isset($_POST['cartitem']) && isset($_POST['quantity']) && is_numeric($_POST['quantity'])) {
if ($_POST['quantity'] > 0) {
Which I need to add an OR statement to : - (!isset($_SESSION['lockedpaypal']).
if (isset($_SESSION['cartid']) && ($_SESSION['lockedpaypal'] != '1' || ['lockedcard'] != '1') && isset($_POST['cartitem']) && isset($_POST['quantity']) && is_numeric($_POST['quantity'])) {
if ($_POST['quantity'] > 0) {
Thanks! [About the code] Basically what I have is a web page that de-codes a complex XML document, and displays it as a table. This is working successfully. One of the columns in the tables displays a "rank" of an object as a number (0-9). This is working successfully. What I did was write a code that would translate that rank number into a specified text, depending what number it was. [The Code] (This is only the partial code with the problem in it, the entire code of the page is very extensive.) Code: [Select] $RankNum = "{$Member->Rank}"; // {$Member->Rank} successfully displays the rank number on it's own. Below 'should' translate that number into the name of the rank. if('$RankNum' == 0) { echo('test1');}; if('$RankNum' == 1) { echo('test2');}; if('$RankNum' == 2) { echo('test3');}; if('$RankNum' == 3) { echo('test4');}; if('$RankNum' == 4) { echo('test5');}; [The Problem] All this code keeps displaying "test1" for every value in the entire column, regardless if it equaled 1 or 2 or higher... I know this has to be some simple coding mistake, but I've been sitting here for an hour trying to figure out what I had done wrong. Thanks in advance :) The below is constantly loading the password page no matter what is enter in the password input on the form (on another page). I have checked the $login variable by echoing it and it is carrying the value from the field. <?php $off="yes"; $login=$_POST['login']; if($off=="yes" && (!isset($_SESSION['login']) || $_SESSION['login']!="pass")){ if($login=="" || $_SESSION['login']!="pass"){ header('Location: ./index2.html'); exit(); } elseif(!isset($_SESSION['login'])){ session_start(); $_SESSION['login']=$login; header('Location: ./index.php'); exit(); } } elseif($off=="no" || $_SESSION['login']=="pass"){ content goes here. } ?> Hey guys, is there any way to have a LIKE condition on an IF statement? Something like: Code: [Select] if $GET_['WTV'] LIKE %LOVE% { $category=romance Any clues? Thanks in advance. Anything wrong with this because I got a parse error ONLY after adding to create this. <?php $visible = array('Yes', 'No'); foreach($visible as $visible): $visible2 = array('yes', 'no'); foreach($visible2 as $visible2): ?> Hello, I am learning PDO SQL statements, I have mananged to connect using PDO: Code: [Select] try { $this->link = $dbh = new PDO('mysql:host='.$this->dbhost.';dbname='.$this->dbname.'', $this->dbuser, $this->dbpass); } catch (PDOException $e) { echo 'Connection failed: ' . $e->getMessage(); } I am not getting any error, so I guess that is a good start. I then tried the PDO SQL statement out. My old mySQL query is commented out in the Code: [Select] if (isset($_SESSION['id']) && isset($_SESSION['password'])) { $_SESSION['id'] = ( isset( $_SESSION['id'] ) ) ? $_SESSION['id'] : FALSE; $_SESSION['password'] = ( isset( $_SESSION['password'] ) ) ? $_SESSION['password'] : FALSE; //$logged = mysql_query("SELECT * FROM `db_members` WHERE `id`='".$_SESSION['id']."' AND `password` = '".$_SESSION['password']."'"); //$logged = mysql_fetch_array( $logged ); // the new pdo statement $ff = $dbh->prepare('SELECT * FROM db_members WHERE id = '.$_SESSION['id'].' AND password = '.$_SESSION['password'].''); $ff->execute(); $logged = $ff->fetchAll(); echo $logged['username']; } I am trying to assign the session to logged variable. So all I am asking is go into db_members and check the id and password that is the same as session id and password and collect the rows data such as username. My login script and everything works perfectly, even session id and password is valid when echo'd but I cannot assign it to the logged variable like my old sql statements. Code: [Select] $logged = mysql_query("SELECT * FROM `db_members` WHERE `id`='".$_SESSION['id']."' AND `password` = '".$_SESSION['password']."'"); $logged = mysql_fetch_array( $logged ); I used other PDO statements and it works perfectly but I just don't understand why this is not working.... can I please get some help if you have any solution to this? I am trying to write an if statement that checks to make sure the information put in the text box is an imbedded file. Does anyone know how to do that? Hi Guys, Newbie trying to understand PHP conditionals. In the below Code: [Select] [[*id]] is a global variable which equates to my current page id so it could have the value of 1 for example. I tested it using echo and the correct values pass to it in the cms I'm using. What I cant achieve is for the conditionals below to work correctly so perhaps you can see a syntax error or show me away of doing the same using an array or something perhaps? THANKS Code: [Select] <?php $id='[[*id]]' if ($id=="1" || $id=="2") echo "we are in 1 or 2"; elseif ($id=="3" || $id=="4") echo "we are in 3 or 4"; else echo "not in 1 to 4"; ?> How to write 2 "if" statements together? if($userResult==$myResult) and ($userResult<0) { Hey Guys, I am creating an array and I have a need to put a if statement inside it. Is this even possible? Here is where I am at so far, its just not working. function load_permissions($gid) { $data = array(); $this->db->select('`groups`.`name` AS `permission_name`, `permissions`.``'); $query = $this->db->get('`groups`,`permissions`'); if ($query->num_rows() > 0){ foreach ($query->result_array() as $row){ $data[] = array( "name" => $row['permission_name'], "read" => if($row['level'] >= 1) { img("img/true.gif") } else { img("img/false.gif") }, ); } } $query->free_result(); return $data; Thanks, Peter I have a general dbInsert class method that accepts three arguments: table, fields, and values - the last two each as an array. I am using a PDO connection and prepared statements to sanitize everything. I am having a problem with the bindParam() function accepting the parameter ID's though... here's my code and the result I am getting, any advice? My arguments: $this->_table = "testdata"; $this->_fields = array('product_id', 'store_id', 'description', 'price', 'colors', 'sizes'); $this->_values = array("20002157", "2005", "Kids polo shirt", "12.59", "White", "Large"); My object: $_crud = new Crud(); $_makeCrud = $_crud->dbInsert($this->_table, $this->_fields, $this->_values); My class: public function dbInsert($table, $fields, $values) { $_table = $table; $_fields = implode(", ", $fields); // Create and format the list of insert values $_values = ""; // replaces values with "?" placeholders foreach ($values as $value) { $_values .= "?" . ", "; } // trims off last comma and space $_values = substr($_values, 0, -2); // checks database connection if (isset($this->_dbh)) { // Create the SQL Query $this->_sql = 'INSERT INTO ' . $_table . ' (' . $_fields . ') VALUES (' . $_values . ')'; // Build the query transaction $this->_dbh->beginTransaction(); // Build the prepared statement $this->_stmt = $this->_dbh->prepare($this->_sql); // Bind the parameters to their properties foreach ($values as $key => $val) { // starts $key at 1 $key = (int) $key + 1; $this->_stmt->bindParam($key, $val); } // Execute the query $this->_stmt->execute(); $this->_affectedRows = $this->_stmt->rowCount(); } } What my new table row should look like: Code: [Select] product_id store_id description price colors sizes ---------------------------------------------------------------------------------------------- 20002157 2005 kids polo shirt 12.59 white large But this is what my new row DOES look like: Code: [Select] product_id store_id description price colors sizes ---------------------------------------------------------------------------------------------- Large 0 Large 0.00 Large Large So it's taking the value of that last $value and inserting it in all the fields, the store_id and price are 0 and 0.00 because of their numeric type... I assume it is a syntax error, missing quotes somewhere, but where? this is working fine : Code: [Select] while($tags=mysql_fetch_array($d_b->sql_answer,MYSQL_ASSOC)){ echo $tags['tag_name'] . "<br/>"; } display : Code: [Select] html css javascript c++ php but when i try to do some sql statements inside like this : Code: [Select] while($tags=mysql_fetch_array($d_b->sql_answer,MYSQL_ASSOC)){ $sql="SELECT * FROM user WHERE user_languages LIKE '% {$tags[tag_name]} %'"; //to apply the $sql $d_b->apply($sql); //number of results $num=$d_b->num_rows(); $sql="UPDATE tags SET tag_folowers={$num}"; $d_b->apply($sql); } it return an error : Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given I'm sure you can do this in PHP, but for some reason when I view news.php - It automatically tells me I liked the post, when I haven't even clicked like yet! while($fetch = mysql_fetch_assoc($query)) { if($_GET['like'] == $fetch['id']) { $like = mysql_real_escape_string($_GET['like']); $has_liked = mysql_query("SELECT * FROM likes WHERE id = '$like' AND username = '". $_SESSION['user'] ."'"); if(mysql_num_rows($has_liked) > 0) { echo " <div id='post-1' class='post'> <h2 class='title'><font color='white'>#". $i." ".$fetch['title'] ."</font> <h3 class='date'>". $fetch['date'] ."</h3> <div class='entry'> <p>". nl2br(stripslashes($fetch['content'])) ."</p> </div> <p class='meta'><b>You've already liked this announcement.</b></p> </div> "; } else { mysql_query("UPDATE news SET likes = likes + 1 WHERE id = '". $_GET['id'] ."'"); echo " <div id='post-1' class='post'> <h2 class='title'><font color='white'>#". $i." ".$fetch['title'] ."</font> <h3 class='date'>". $fetch['date'] ."</h3> <div class='entry'> <p>". nl2br(stripslashes($fetch['content'])) ."</p> </div> <p class='meta'><b>You liked this announcement.</b></p> </div> "; } } else { echo " <div id='post-1' class='post'> <h2 class='title'><font color='white'>#". $i." ".$fetch['title'] ."</font> <h3 class='date'>". $fetch['date'] ."</h3> <div class='entry'> <p>". nl2br(stripslashes($fetch['content'])) ."</p> </div> <p class='meta'><a href='news.php?like=". $fetch['id'] ."'>Like</a></p> </div> "; } } Hi, What is a shorter way instead of having all these if statements? Here it is: Code: [Select] if($matchno==1) return 66; elseif($matchno==2) return 67; elseif($matchno==3) return 68; elseif($matchno==4) return 69; elseif($matchno==5) return 70; elseif($matchno==6) return 71; elseif($matchno==7) return 72; elseif($matchno==8) return 73; elseif($matchno==9) return 74; elseif($matchno==10) return 75; elseif($matchno==11) return 76; elseif($matchno==12) return 77; elseif($matchno==13) return 78; elseif($matchno==14) return 79; elseif($matchno==15) return 80; elseif($matchno==16) return 81; elseif($matchno==17) return 82; elseif($matchno==18) return 83; elseif($matchno==19) return 84; elseif($matchno==20) return 85; elseif($matchno==21) return 86; elseif($matchno==22) return 87; elseif($matchno==23) return 88; elseif($matchno==24) return 89; elseif($matchno==25) return 90; elseif($matchno==26) return 91; elseif($matchno==27) return 92; elseif($matchno==28) return 93; elseif($matchno==29) return 94; elseif($matchno==30) return 95; elseif($matchno==31) return 96; elseif($matchno==32) return 97; someone please code shorter? I will learn this way. Thanks. How could I make it so that if the $date variable is past than $memberdate then something shows else something else does. <?php $date = date('Y-m-d H:i:s', time()-3600); $memberdate = '2011-01-29 01:03:28'; ?> Thanks in advance, I realised I could convert it into a unix timestamp but there must be a better way. Ty. I always have trouble reading shorthand statements, as i am used to always using brackets. So when i view someones code and they use shorthand, i get confused. Can i get a clear explanation on the example below:
if ( have_posts() ) : while ( have_posts() ) : the_post(); the_content(); endwhile; else: echo "<p>Sorry, no posts matched your criteria.</p>"; endif;I've always been accustomed to using brackets, so i have trouble understanding the above quickly. I can't get these two if, elseif and else statements too work, here is the code: if(empty($this->password)){ $this->errors[] = 'You must enter a password!'; } elseif(!strlen($this->password) >= 6){ $this->errors[] = 'Your password must be longer than 6 characters!'; } if(empty($this->email)){ $this->errors[] = 'You must enter an email address!'; } elseif(!preg_match('/^[a-zA-Z0-9._-]+@[a-zA-Z0-9._-]+\.[a-zA-Z]{2,4}$/',$this->email)){ $this->errors[] = 'Your password can only contain these characters: a-z, A-Z and 0-9!'; } if(empty($this->confemail)){ $this->errors[] = 'Please confirm your email address!'; } elseif(!$this->confemail == $this->email){ $this->errors[] = 'The email addresses you entered did not match!'; } The if and elseif statements for "email" work just fine but the other 2 doesn't. With the "password" i first want to check if the field is empty, and when it is, it works as it should. But when i for example type "test" too check if the password is longer than 6 characters i don't get any message at all? With the "confemail" i want to first check if the field is empty, and when it is, it works as it should. But when i type in "test@test.com" in both fields to try to compare "confemail" to "email" i still get the "Please confirm your email address!" message? Okay i'm trying to compare these sets of variables. code looks like this.. Code: [Select] if( $row->cash > $finalcash && $row->core1 > $finalcore1 && $row->core2 > $finalcore2 && $row->core3 > $finalcore3 && $row->core4 > $finalcore4 ) { return true; } else { return false; } First question is this the appropriate way of doing this? Or would a nested if statement work better? example: Code: [Select] if ($row->cash > $finalcash) { if ($row->core1 > $finalcore1) { if ($row->core2 > $finalcore2) { if ($row->core3 > $finalcore3) { if ($row->core4 > $finalcore4) { } else { return false; } } else { return false; } } else { return false; } } else { return false; } } else { return false; } I know it looks pretty messy, so i'm wondering if anybody is aware of an alternative to achieving this? |
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