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PHP - Nav Bar: How To Make A Button Show Active For Each Page Of Your Site?
Hi,
Sorry if this is in the wrong place. I really just need a search term to use for what i'm trying to do. I would like my buttons to appear pressed on each page. For example if you are on the home page the home button will appear pressed. If you are on the screenshots page the screenshots button will appear pressed. Pretty much i want my nav bar to display what page is being viewed. I'm using SMF forums and i've created an extension of my forum that i'm using on the root of my site. As far as i can tell i have the correct code added to the forum that should highlight the home button while on the home page. The part i'm missing is the code to add onto the home page. This is the code I have on the button. $buttons = array( 'overview' => array( 'title' => $txt['overview'], 'href' => 'http://www.wararmada.com', 'show' => true, 'sub_buttons' => array( 'alliance' => array( 'title' => $txt['alliance'], 'href' => $scripturl . '?action=overview;area=alliance', 'show' => true, ), This is the code i have in the language file. $txt['overview'] = 'overview'; I'm not sure what this is called. I don't know anything about php but so far i've been able to get by just using google but I don't really know how to search for this. Thanks for all the help! Similar TutorialsI would like to know how to make my links show that it's active. For example if I click on a link that says overview then that link has to be highlighted. This is the code that I have: Code: [Select] <?php if (isset($this->_params['submenus']) && is_array($this->_params['submenus'])){ foreach ($this->_params['submenus'] as $submenu){ ?> <li class="active"><a href="<?php echo $this->get_uri("/{$submenu['controller']}/{$submenu['action']}") ?>" onclick="javascript:return setSubMenu(<?php echo $submenu['id'] ?>);"><?php echo strtoupper($submenu['name'])?></a></li> <?php } } ?> Unfortunately with this code all the links are selected as active. This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=317523.0 hiii all, i want to show the database field (alise name) as the url after index.php when page or site loads first time. how i can achieve it? please help.... thanks in advance i got a submit button... if user click the submit button iwant to page will auto referesh... can someone teach me Apologies for this because it's probably very simple, but I've never worked with JavaScript or PHP or anything before.
So the website I am producing is to sell tickets for something. To purchase these tickets the user is required to click on the seats they want and it will pop up in a box on the left hand side confirming their seat selection and how much the ticket is.
The website has to feature a "Reset Database" button which totally resets everything. No tickets are selected anymore, the user is logged out etc. I have this working fine.
It also has to feature a "Cancel" button, which simply removes the seats the user has selected, but still keeps them logged in. How do I code this?
This is what the "Cancel" button looks like on the Index page:
<div id="theButtons"> <input type="button" value="Cancel Choices" title="Cancel Choices" onclick="cancel()" /> </div> And this is my code on the JavaScript page: function cancel(){ var s = document.getElementsByTagName('space'); window.location="index.php"; } How do I get this working? Edited by DavidD95, 08 November 2014 - 10:36 AM. Hi All, How would I go about programming a HTML button that cannot be clicked on for two seconds after it loads? As part of a game I wish to stop people simply re-clicking the button and I think a delay of about two seconds would stop abuse of this (if they click it every two seconds then that's fine). I have read the manual for sleep() but it doesn't do exactly what I want - I want the rest of the page to load (and display), and the button to be grayed out for the two seconds, and then the button to be active. James now i use this code to show where the visitors came from to my site. <?php $referer=$_SERVER['HTTP_REFERER']; echo $referer; ?> now, i want to show the 5 latest vistors referer's site url on my site ? Hello I need help with making our dropdown links stay visible when active. Site: London tshirt .com Code: [Select] <dl id="nav"> <dt class="nav"><b>London Tshirts</b></dt> <dd> <ul> <li><a href="/Unisex">Unisex</a></li> <li><a href="/Slimfit">Slimfit</a></li> <li><a href="/Kids">Kids</a></li> </ul> </dd> <dt class="nav"><b>Alternative Tshirts</b></dt> <dd> <ul class="nav"> <li><a href="/England">England</a></li> <li><a href="/Humour">Humour</a></li> <li><a href="/Popular">Popular</a></li> </ul> </dd> <dt class="nav"><b>Magnets</b></dt> <dd> <ul class="nav"> <li><a href="/magnets-ceramic">Ceramic</a></li> <li><a href="/magnets-metal">Metal</a></li> <li><a href="/magents-plastic">Plastic</a></li> </ul> </dd> <dt class="nav"><b>Keyrings</b></dt> <dd> <ul class="nav"> <li class="current"><a href="/keyrings-ceramic">Ceramic</a></li> <li class="current"><a href="/keyrings-metal">Metal</a></li> <li><a href="/keyrings-plastic">Plastic</a></li> </ul> </dd> <dt class="nav"><b>Other gifts</b></dt> <dd> <ul class="nav"> <li><a href="/Hats">Hats</a></li> <li><a href="/Models">Models</a></li> <li><a href="/Bags">Bags</a></li> </ul> </dd> </dl> Thanks P.S. I typed my question, then went to verification, but could not read the letters so requested a new image, this refreshed the page and I lost my message?? Quesion: Show each movie in the database on its own page, and give the user links in a "page 1, Page 2, Page 3" - type navigation system. Hint: Use LIMIT to control which movie is on which page. I have provided 3 files: 1st: configure DB, 2nd: insert data, 3rd: my code for the question. I would appreciate the help. I am a noob by the way. First set up everything for DB: <?php //connect to MySQL $db = mysql_connect('localhost', 'root', '000') or die ('Unable to connect. Check your connection parameters.'); //create the main database if it doesn't already exist $query = 'CREATE DATABASE IF NOT EXISTS moviesite'; mysql_query($query, $db) or die(mysql_error($db)); //make sure our recently created database is the active one mysql_select_db('moviesite', $db) or die(mysql_error($db)); //create the movie table $query = 'CREATE TABLE movie ( movie_id INTEGER UNSIGNED NOT NULL AUTO_INCREMENT, movie_name VARCHAR(255) NOT NULL, movie_type TINYINT NOT NULL DEFAULT 0, movie_year SMALLINT UNSIGNED NOT NULL DEFAULT 0, movie_leadactor INTEGER UNSIGNED NOT NULL DEFAULT 0, movie_director INTEGER UNSIGNED NOT NULL DEFAULT 0, PRIMARY KEY (movie_id), KEY movie_type (movie_type, movie_year) ) ENGINE=MyISAM'; mysql_query($query, $db) or die (mysql_error($db)); //create the movietype table $query = 'CREATE TABLE movietype ( movietype_id TINYINT UNSIGNED NOT NULL AUTO_INCREMENT, movietype_label VARCHAR(100) NOT NULL, PRIMARY KEY (movietype_id) ) ENGINE=MyISAM'; mysql_query($query, $db) or die(mysql_error($db)); //create the people table $query = 'CREATE TABLE people ( people_id INTEGER UNSIGNED NOT NULL AUTO_INCREMENT, people_fullname VARCHAR(255) NOT NULL, people_isactor TINYINT(1) UNSIGNED NOT NULL DEFAULT 0, people_isdirector TINYINT(1) UNSIGNED NOT NULL DEFAULT 0, PRIMARY KEY (people_id) ) ENGINE=MyISAM'; mysql_query($query, $db) or die(mysql_error($db)); echo 'Movie database successfully created!'; ?> ******************************************************************** *********************************************************************** second file to load info into DB: <?php // connect to MySQL $db = mysql_connect('localhost', 'root', '000') or die ('Unable to connect. Check your connection parameters.'); //make sure you're using the correct database mysql_select_db('moviesite', $db) or die(mysql_error($db)); // insert data into the movie table $query = 'INSERT INTO movie (movie_id, movie_name, movie_type, movie_year, movie_leadactor, movie_director) VALUES (1, "Bruce Almighty", 5, 2003, 1, 2), (2, "Office Space", 5, 1999, 5, 6), (3, "Grand Canyon", 2, 1991, 4, 3)'; mysql_query($query, $db) or die(mysql_error($db)); // insert data into the movietype table $query = 'INSERT INTO movietype (movietype_id, movietype_label) VALUES (1,"Sci Fi"), (2, "Drama"), (3, "Adventure"), (4, "War"), (5, "Comedy"), (6, "Horror"), (7, "Action"), (8, "Kids")'; mysql_query($query, $db) or die(mysql_error($db)); // insert data into the people table $query = 'INSERT INTO people (people_id, people_fullname, people_isactor, people_isdirector) VALUES (1, "Jim Carrey", 1, 0), (2, "Tom Shadyac", 0, 1), (3, "Lawrence Kasdan", 0, 1), (4, "Kevin Kline", 1, 0), (5, "Ron Livingston", 1, 0), (6, "Mike Judge", 0, 1)'; mysql_query($query, $db) or die(mysql_error($db)); echo 'Data inserted successfully!'; ?> ************************************************************** **************************************************************** MY CODE FOR THE QUESTION: <?php $db = mysql_connect('localhost', 'root', '000') or die ('Unable to connect. Check your connection parameters.'); mysql_select_db('moviesite', $db) or die(mysql_error($db)); //get our starting point for the query from the URL if (isset($_GET['offset'])) { $offset = $_GET['offset']; } else { $offset = 0; } //get the movie $query = 'SELECT movie_name, movie_year FROM movie ORDER BY movie_name LIMIT ' . $offset . ' , 1'; $result = mysql_query($query, $db) or die(mysql_error($db)); $row = mysql_fetch_assoc($result); ?> <html> <head> <title><?php echo $row['movie_name']; ?></title> </head> <body> <table border = "1"> <tr> <th>Movie Name</th> <th>Year</th> </tr><tr> <td><?php echo $row['movie_name']; ?></td> <td><?php echo $row['movie_year']; ?></td> </tr> </table> <p> <a href="page.php?offset=0">Page 1</a>, <a href="page.php?offset=1">Page 2</a>, <a href="page.php?offset=2">Page 3</a> </p> </body> </html> I want to show a cookie of a referral's username on a sign up page. The link is like this, www.mysite.com/signup?ref=johnsmith. The cookie doesn't show if I go to that url page. But it does show up once I reload the page. So I'm wondering if it's possible to show the cookie the first time around, instead of reloading the page? Here is my code.
// This is in the header
$url_ref_name = (!empty($_GET['ref']) ? $_GET['ref'] : null);
if(!empty($url_ref_name)) {
$number_of_days = 365;
$date_of_expiry = time() + 60 * 60 * 24 * $number_of_days;
setcookie( "ref", $url_ref_name, $date_of_expiry,"/");
} else if(empty($url_ref_name)) {
if(isset($_COOKIE['ref'])) {
$user_cookie = $_COOKIE['ref'];
}
} else {}
// This is for the sign up form
if(isset($_COOKIE['ref'])) {
$user_cookie = $_COOKIE['ref'];
?>
<fieldset>
<label>Referred By</label>
<div id="ref-one"><span><?php if(!empty($user_cookie)){echo $user_cookie;} ?></span></div>
<input type="hidden" name="ref" value="<?php if(!empty($user_cookie)){echo $user_cookie;} ?>" maxlength="20" placeholder="Referrer's username" readonly onfocus="this.removeAttribute('readonly');" />
</fieldset>
<?php
}
I just want to add a css cass named "active" to my navigation links when its page opened using php.
In my website the content have broken into its individual components. And those components are separated, organized, and put back together using one index file. (website bootstrap file) Actually I am modularizing this website using php.
My Navigation is something similar to this code -
... <li> <a href="index.php?p=dashboard">Dashboard</a> </li> <li> <a href="index.php?p=page-two">Page Two</a> </li> <li> <a href="index.php?p=page-three">Page Page Three</a> </li> ...This is how my index.php looks like -
// Validate what page to show:
if (isset($_GET['p'])) {
$p = $_GET['p'];
} elseif (isset($_POST['p'])) { // Forms
$p = $_POST['p'];
} else {
$p = NULL;
}
// Determine what page to display:
switch ($p) {
case 'dashboard':
$page = 'dashboard.inc.php';
$page_title = 'Control Panel';
break;
case 'page-three':
$page = 'page-three.inc.php';
$page_title = 'Page Three';
break;
case 'page-two':
$page = 'page-two.inc.php';
$page_title = 'Page Two';
break;
// Default is to include the main page.
default:
$page = 'login.inc.php';
$page_title = 'Control Panel Login';
break;
} // End of main switch.
// Make sure the file exists:
if (!file_exists('./modules/' . $page)) {
$page = 'login.inc.php';
$page_title = 'Control Panel Login';
}
include('./includes/header.html');
include('./modules/' . $page);
include('./includes/footer.html');
I tried it something like this -
case 'dashboard': $page = 'dashboard.inc.php'; $page_title = 'Control Panel'; $class == ($page == $p) ? 'active' : ''; break; And adding this class to my navigation <li> <a class="<?php echo $class;?>">.... </li>But this is not working for me. hope somebody may help me out. Thank you. Edited by thara, 02 January 2015 - 06:00 AM. Not sure if I'm trying to achieve something totally crazy here, or if this is something pretty standard. Didn't have much luck with searching as I'm not fully down with all the terms. (A) I have one site providing an RSS feed. (B) I have one site I want to search, once for each of the items in the feed A. (C) I want the results of the search in (B) to be displayed on page (C). So for example, the feed on (A) says; apples bananas oranges cheese I want site (B) to search for each of those terms (by passing the item in the feed (A) to the ?search= part of the URL of that page) and then show the results from THAT search on page C. Bit of a complex one, let me know if you need me to clarify. Thanks for any help! Hi, First of all, this is not a spam. Someone with the username Pikachu2000 removed it thinking it was a spam so now I have to post it again. I really need you help fixing this problem. Anyway, I'm building a site where I used a "php include once" for the navigation menu. I was able to show the active pages when they don't have sub pages but I can't seem to show the active sub pages. I've been trying for days and nothing I try seems to work! I'm sure some people have asked this before but I can't find any forums that describe how to do this with sub navs rather then just the main nav buttons. The coding is below along with a link to one of the sub pages in the site I'm working on. The problem is with the sub pages under "Our Coffee Farm". Thanks for reading my post. Website Link: http://vanessajohodesigns.com/sarpa/the_farm/plantation.php before DOCTYPE: <?php $thisPage="The Plantation"; ?> after body tag: <?php include_once("../includes/nav.php");?> nav.php include once file: <div class="arrowsidemenu"> <div<?php if ($thisPage=="Home") echo " class=\"active\""; ?>> <a href="../index.php">Home</a></span></div> <div class="menuheaders"><a>Our Coffee Farm</a></div> <ul class="menucontents"> <li<?php if ($thisPage=="The Plantation") echo " class=\"active\""; ?>><a href="plantation.php">The Plantation</a></li> <li<?php if ($thisPage=="Blooming & Harvest") echo " class=\"active\""; ?>><a href="bloom_harvest.php">Blooming & Harvest</a></li> <li<?php if ($thisPage=="Coffee Processing") echo " class=\"active\""; ?>><a href="processing.php">Coffee Processing</a></li> </ul> <div<?php if ($thisPage=="About Us") echo " class=\"active\""; ?>> <a href="../about_us.php">About Us</a></div> <div<?php if ($thisPage=="Rainforest Alliance") echo " class=\"active\""; ?>> <a href="../rainforest_alliance.php">Rainforest Alliance</a></div> <div<?php if ($thisPage=="Social Commitment") echo " class=\"active\""; ?>> <a href="../social_commitment.php">Social Commitment</a></div> <div<?php if ($thisPage=="News & Events") echo " class=\"active\""; ?>> <a href="../news_events.php">News & Events</a></div> <div<?php if ($thisPage=="Web Cameras") echo " class=\"active\""; ?>> <a href="../webcams.php">Web Cameras</a></div> <div<?php if ($thisPage=="Photo Gallery") echo " class=\"active\""; ?>> <a href="../gallery.php">Photo Gallery</a></div> <div<?php if ($thisPage=="Contact Us") echo " class=\"active\""; ?>> <a href="../contact_us.php">Contact Us</a></div> <!--end .arrowsidemenu --></div> Hi, I would like to do the following but not sure how. If the you/user is on index.php of http://www.domain.com/ show one page If not show another How would I do this? Thanks i am making online jobs portal where people send data after finish work and then we check that update thier earning stat for that i am confused i want that if user earn 50$ per month we add those but when i next month add earning of that user that show show also 50$ and if i include 50 more there i can show last month earning one table and in one this month earn and in one table total earning till now and when USer earning total earning reach on 100$ or grater 100$ automatically show him 3 buttons where he can choose how he witdhraw the money and how much minimum $100 after once when he send us request for withdraw money those buttons again disapear and total balance - how much he requested us for withdraw so tell me how i make table strcute and which code i'll use ok, how do I make this button go to the specific link that is set with it.......it goes to page without eventid=eventid: Code: [Select] <form action= \"editevent.php?eventid=".$row['eventid']."\" method=\"link\"><INPUT TYPE=\"submit\" VALUE=\"Edit\"></form>"; Hey again, was making a registration form with php and postgresql and im stuck at making a 'log out' button, i need to make something simple like - press on a link, it redirects u to the index page and if u try to go 'back' it wouldn't let u.. I found something on google like this: <a href="test.php?logout=1">Log out</a> and on test.php: <?php if(isset($_GET['logout'])){ session_unset; session_destroy; } ?> Succesfully logged out, go back to index page: <a href="index.php">Home</a> but i didnt use any sessions at all.. is there something like 'session_destroy' with postgre? i mean smth like 'pg_desroy'? How can i make echo "<b>Site:</b> ".$req_user_info['site']."<br>"; linkable The site raw fron the db contains an site url. Regards i have an html form which is a "post" on it i have an array of checkboxes and a sumbit button, once button is clicked i go to another page where i handle those boxes checked the problem now is if NO checkboxes are checked and i hit the submit...i get errors on the other page my code: foreach($product_names as $product_row) { ?> <tr> <td > </td><td width='200px'><?php echo $product_row->getName(); ?></td> <td width='200px'><input type="checkbox" name="graphic[]" value="<?php echo $product_row->getId();?>" /></td> <td width='200px'><input type="checkbox" name="text[]" value="<?php echo $product_row->getId();?>" /></td> </tr> <?php } ?> </table> <table> <tr> <td> <input type='submit' name='submit' value='Submit'> <?php if ( (isset($graphic)) || (isset($text) )) { echo "checkboxes checked"; //show submit button } else { //hide submit botton and echo "no boxes check"; } ?> the above is NOT working please help???? so this is my code Code: [Select] <? $b=$_GET['b']; $m=$_GET['m']; $y=$_GET['y']; if ($b <> '' && $m <> '' && $y <> '') { $branch=$b; $leavemonth=$m; $leaveyear=$y; } else { $branch=$_POST['branch']; $leavemonth=$_POST['leavemonth']; $leaveyear=$_POST['leaveyear']; } $connection=mysql_connect("$server", "$username", "$password") or die("Could not establish connection"); mysql_select_db($database_name, $connection) or die ("Could not select database"); $query="SELECT * from tblworkgroup"; $result=mysql_query($query);?> Branch <select name="branch" > <option value="all">ALL Branches</option> <? while($row=mysql_fetch_array($result)) { ?> <option value= "<?=$row['WorkGroupID']?>" <? if ($branch==$row['WorkGroupID']){ echo 'selected'; } ?> ><?=$row['WorkGroupName']?></option> <? } ?> </select> </td> </tr> <br><br><br> Month <select name="leavemonth" > <option value = "1" <? if ($leavemonth==1){ echo 'selected'; } ?>>January</option> <option value = "2" <? if ($leavemonth==2){ echo 'selected'; } ?>>February</option> <option value = "3" <? if ($leavemonth==3){ echo 'selected'; } ?>>March</option> <option value = "4" <? if ($leavemonth==4){ echo 'selected'; } ?>>April</option> <option value = "5" <? if ($leavemonth==5){ echo 'selected'; } ?>>May</option> <option value = "6" <? if ($leavemonth==6){ echo 'selected'; } ?>>June</option> <option value = "7" <? if ($leavemonth==7){ echo 'selected'; } ?>>July</option> <option value = "8" <? if ($leavemonth==8){ echo 'selected'; } ?>>August</option> <option value = "9" <? if ($leavemonth==9){ echo 'selected'; } ?>>September</option> <option value = "10" <? if ($leavemonth==10){ echo 'selected'; } ?>>October</option> <option value = "11" <? if ($leavemonth==11){ echo 'selected'; } ?>>November</option> <option value = "12" <? if ($leavemonth==12){ echo 'selected'; } ?>>December</option> </select> Year <select name="leaveyear" > <option value = "2010" <? if ($leaveyear==2010) { echo 'selected';} ?>>2010</option> <option value = "2011" <? if ($leaveyear==2011) { echo 'selected';} ?>>2011</option> <option value = "2012" <? if ($leaveyear==2012) { echo 'selected';} ?>>2012</option> <option value = "2013" <? if ($leaveyear==2013) { echo 'selected';} ?>>2013</option> <option value = "2014" <? if ($leaveyear==2014) { echo 'selected';} ?>>2014</option> <option value = "2015" <? if ($leaveyear==2015) { echo 'selected';} ?>>2015</option> <option value = "2016" <? if ($leaveyear==2016) { echo 'selected';} ?>>2016</option> <option value = "2017" <? if ($leaveyear==2017) { echo 'selected';} ?>>2017</option> </select> <input type='submit' name='submit' value='Preview' Class="button" onclick='return validate()'> </div> </form> <br /><br /> <div id="box" valign="top"> <h3> <strong>Leave Application Details</strong>  </h3> <br><br> <FORM name="printbutton" method="post" align="left" action="report_print.php" target="_blank"> <input type="hidden" name="leavemonth" value="<?php echo $leavemonth; ?>"> <input type="hidden" name="leaveyear" value="<?php echo $leaveyear; ?>"> <input type="hidden" name="branch" value="<?php echo $branch;?>"> <Input type = "Submit" Name = "Submit1" Class="button" VALUE = "Print Leave Details"> </form> <table width="80%" align="center" > <thead> <tr> <th width="700px" align="left">Name</a></th> <th width="500px" align="center"></a>Application Date</th> <th width="500px" align="center"></a> </th> <th width="500x" align="right"></a>Reason</th> </tr> </thead> <tbody> <? /*echo "branch:".$branch.'<br />'; echo "leavemonth:".$leavemonth.'<br />'; echo "leaveyear:".$leaveyear.'<br />';*/ //-------------------------------------------------- if ($leavemonth =='' || $leaveyear =='' || $branch == '') { // one value missing, so don't display } else { // start display data $branchtracker = ''; if ($branch=='all'){ $branch = '%'; } $rs = mysql_query( " call vwleavereport('$leavemonth', '$leaveyear', $branch, 0);"); $query="SELECT *, MONTH(tblleaveapplication.DateFrom) as DFMonth, MONTH(tblleaveapplication.DateTo) as DTMonth, YEAR(tblleaveapplication.DateFrom) as DFYear FROM `tblleaveapplication` LEFT JOIN `tblemployee` ON tblleaveapplication.employeeid = tblemployee.id WHERE WorkGroupID LIKE '".$branch."' AND ( (MONTH(tblleaveapplication.DateFrom)=".$leavemonth." AND YEAR(tblleaveapplication.DateFrom)=".$leaveyear.") OR (MONTH(tblleaveapplication.DateTo)=".$leavemonth." AND YEAR(tblleaveapplication.DateFrom)=".$leaveyear.") ) ORDER BY WorkGroupID "; $result = mysql_query($query); while($row=mysql_fetch_array($result)) { if ($branchtracker<>$row['WorkGroupID']){ echo '<tr><td colspan=4 style="background-color: #e8e8e8; font-weight: bold;">'.$row['WorkGroupID'].'</td></tr>'; $branchtracker = $row['WorkGroupID']; } echo '<tr>'; echo '<td>'.$row['EmployeeName'].'</td>'; echo '<td>'.$row['DateFrom'].'</td>'; echo '<td>'.$row['DateTo'].'</td>'; echo '<td>'.$row['Purpose'].'</td>'; echo '</tr>'; } } ?> the problem is i want the print button only appear when there is output.. |
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