PHP - Session For User Id

i have my upload process working that uploads documents to the server and then displays in onto the user page like this:

<?php 
						function find_all_files($dir) 
						{ 
    							$root = scandir($dir); 
    							foreach($root as $value) 
    							{ 
    				    				if($value === '.' || $value === '..') {continue;} 
        							if(is_file("$dir/$value")) {$result[]="$dir/$value";
        							continue;
        							} 
        							foreach(find_all_files("$dir/$value") as $value) 
        							{ 
           							 $result[]=$value; 
       								 } 
	   					 	} 
  					 		 return $result; 
						} 
							$fileupload = 'fileupload';
							$getem = find_all_files($fileupload);
							foreach($getem as $key => $value)
							{
								echo '<a href="'.$value.'">'.$value.'</a><br />';
							}
						?>
						
						
						
						<?php
						if($handle = opendir('members/')) {
						while (false !== ($entry = readdir($handle))) {
							if($entry != "." && $enrty != "..") {
							echo "<a href='download.php?file=".$entry."'>".$entry."</a>\n";
							}
							}
							closedir($handle);
							}
							?>

here they can download the files to their computer however is there a way to only display the file of the user that is logged in through their session?      

Unfortunately I have no code for this yet cuz I don;t even know if its possible...

I am programming an application that is used by a couple of stores, which could end up being a lot of stores.

Anyways, the basis is that the stores would, though a separate application (and therefore separate database) create a username and password, I now want to use this username and password to do the following

1. Allow them to login to my application using the same username and password
2. I want the store the username in a session to pull tables based on the username from my database

For instance, a user has the login store123, after loggin in it now pulls the information from the tables store123_items, store123_prices, store123_settings, etc. Now my database will have quite a lot of store###_tables

I am, sadly, a noobie to PHP and I do recall seeing an article (somewhere on the net, and I stupidly forgot to bookmark it, knowing I would need it eventually) on how to access multiple databases easily.  Now because they are both under my account I can use the same username and password for both, its accessing the MySQL username/password database and storing the info I know I am lacking on how to do it.

Any ideas?

Login.php

Code: [Select]
<?php
    session_start();
    mysql_connect("localhost","root") or die(mysql_error());
    mysql_select_db("cute") or die(mysql_error());
    $username = $_POST['username'];
    $password = $_POST['pass'];
    if (isset($_POST["submit"]))
    {
     $log = "SELECT * FROM regis WHERE username = '$username'";
     $login = mysql_query($log);  
     $row = mysql_fetch_array($login);
     $number = mysql_num_rows($login);
     if ($number > 0)
     {


        $_SESSION['username'] = $row['username'];
        $_SESSION['userlevel'] = $row['userlevel'];
        
         
        if($_SESSION['userlevel']==1)
       {
        $_SESSION['is_logged_in'] == 1;
        header("Location: form2.php");
       }
        else if($_SESSION['userlevel']== 0)
       {
         $_SESSION['is_logged_in'] == 1;
         header("Location: registration.php");
       }
     }

Registration.php

Code: [Select]
<?php
echo 'Welcome:' .$_SESSION['is_logged_in'];?>
form2.php

Code: [Select]
<?php
session_start();
if (empty($_SESSION['is_logged_in']))
{
 header("Location:chatframe.php");
 die();     // just to make sure no scripts execute
}
?>
<?php
mysql_connect("localhost","root") or die(mysql_error());
mysql_select_db("cute") or die(mysql_error());
$message=$_POST['message'];
$a=$_SESSION['username'];



if(isset($_POST['submit'])) //if submit button push has been detected

{


   if(strlen($message)>1)
   {
      $message=strip_tags($message);
      $IP=$_SERVER["REMOTE_ADDR"]; //grabs poster's IP
      $checkforbanned="SELECT IP from ipbans where IP='$IP'";
      $checkforbanned2=mysql_query($checkforbanned) or die("Could not check for banned IPS");

    if(mysql_num_rows($checkforbanned2)>0) //IP is in the banned list
    {
     print "You IP is banned from posting.";
    }

    else
    {
     $thedate = date("U"); //grab date and time of the post
     $insertmessage="INSERT into chatmessages (name,IP,postime,message) values('$a','$IP','$thedate','$message')";
     mysql_query($insertmessage) or die("Could not insert message");
    }
   }
}


 ?>
<html>
<head>
<script type="text/javascript">
function addsmiley(code)
{
var pretext = document.smile.message.value;
              this.code = code;
              document.smile.message.value = pretext + code;
}

function a()
{
 var x = document.smile.message.value;
 if(x=="")
 {
  alert("Please insert an message!");
  return false;
 }

}

</script>
<style type="text/css">
body{ background-color: #d8da3d }
</style>
</head>
<body>
  <form name="smile" method="post" action="form2.php" onSubmit="return a()" >
   Your message:<br><textarea name='message' cols='40' rows='2'></textarea><br>
   <img src="smile.gif" alt=":)" onClick="addsmiley(':)')" style="cursor:pointer;border:0" />
   <img src="blush.gif" alt=":)" onClick="addsmiley('*blush*')" style="cursor:pointer;border:0" />
   <input type='submit' name='submit' value='Send' class='biasa'  ></form>

   
 
  <br> <br>
  </body>
</html>
In this registration.php when im called back its appear nothing im means the number is not showing and the login code even im had also put the "$_SESSION['is_logged_in'] == 1;" outside if else userlevel statement and then i put $d=  $_SESSION['is_logged_in'] == 1;   and im echoing back but it is nothing im thinks something wrong in session is login

 and also still it cannot redirect to admin -form2.php when session is login in is 1

show list of files uploaded by current session user to the database. I want to show different users when they log in to the website...they can see a list of old files that they have uploaded. can anyone tell me the code/script to this.....please, ty

Hello All,

I have a PHP web application which will refresh itself(ajax calls connecting to the server and get the latest data) periodically. These also update the Database-based session handler class. i.e. There is NO UPDATE to the session data but the timestamp is constantly updated.


Our problem is that garbage collection does not kick in as it looks at the difference between timestamp and session_gc.maxlifetime. So, if  and the user is not interacting with the application.

Now my question is how can I force the timeout even though refreshing happens but the user is not interacting with the application and there are "phantom" session updates made by these ajax calls.

Please let me know. Thanks.

in this page
 http://maximaart.com/newscp/
i have this problem
Code: [Select]
Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/maximasy/public_html/newscp/index.php:1) in /home/maximasy/public_html/newscp/index.php on line 2

my source code is

<?php
session_start();
include_once("config.php"); 
include_once("functions.php");
$errorMessage = '';
if (isset($_POST['txtUserId']) && isset($_POST['txtPassword'])) {
if ($_POST['txtUserId'] === "$user" && $_POST['txtPassword'] === "$pass") {
// the user id and password match,
$_SESSION['basic_is_logged_in'] = true;
require("main.php");
exit;?>

I am trying to create an index page which contains registration and login field
the problem that i get is on successful login a warning is displayed
session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at C:\xampp\htdocs\Eventz.com\index.php:116) in C:\xampp\htdocs\Eventz.com\index.php on line 235

This is the login part of my index.php
this tag is inside an html table below the login form
I also have a registration form and its php code above the login form


Code: [Select]
<?php
if (isset($_REQUEST['pass']))
{
    $id=$_POST['id'];
    $pass=$_POST['pass'];

    $conn =mysql_connect("localhost","root","");
    if (!$conn)
    {
   die('Could not connect: ' . mysql_error());
    }
/*
checking connection....success!
*/
    $e=mysql_select_db('test', $conn);
    if(!$e)
    {
   die(''.mysql_error());
    }
    else
    {
   echo 'database selected successfully';
    }

    if (isset($_REQUEST['id'])  || (isset($_REQUEST['pass'])))
    {
        if($_REQUEST['id'] == "" || $_REQUEST['pass']=="")
        {
       echo "login fields cannot be empty";
        }
        else
        {
            $sql=mysql_query("Select email,password from login where email='$id' AND password='$pass'");
            $count=mysql_num_rows($sql);
            if($count==1) 

    /* $count checks if username and password are in same row */
            {   
                session_start();
                $_SESSION['id']=$id;
                echo "</br>Login Successful</br>";
            }
            else
            {
           echo "</br>invalid</br>";
           echo "please try to login again</br>";

            }
        
        }   
    }
}
?>


Any help or suggestion would be appreciated

I am having trouble resolving an error.

Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/s519970/public_html/header.php:27) in /home/s519970/public_html/admin/login.php on line 2

 What I can gather is I can't use "header (Location: 'admin.php')" after i've used session_start(). I have tried to replace the header (Location: 'admin.php') with this:

                echo "<script>document.location.href='admin.php'</script>";
      echo "<script>'Content-type: application/octet-stream'</script>";

I've been trying to read up on solutions but haven't been able to get it sorted. If anyone can offer some advice that would be greatly appreciated as im new to php.

Code: [Select]
<?php
  session_start();
  if(isset($_SESSION['user']))

                echo "<script>document.location.href='admin.php'</script>";
echo "<script>'Content-type: application/octet-stream'</script>";
?>

<div id="loginform">

<form action="dologin.php" method="post">
<table>
<tr>
<td><span>Username:</span></td>
<td><input type="text" name="username" /></td>
</tr>
<tr>
<td><span>Password:</span></td>
<td><input type="password" name="password" /></td>
</tr>
<tr>
<td colspan="2" align="right"><input type="submit" name="login" value="Login" /></td>
</tr>
</table>
</form>

</div>
I have tried using require_once('yourpage.php'); before my <head></head> tags in the header document where I've specified the html information but this doesn't seem to work. I've been advised to use ob_start("ob_gzhandler"); but I am not sure how to implement this.

Any advice is greatly appreciated!

I'm making a simple login system with MySQL and PHP (very simple, I'm just starting with PHP). The MySQL portion is done, but I need to ensure only people who are logged in can see certain content.

To check if people are logged in, my website checks that they have the $_SESSION['user'] variable set. If it is set, then it lets them continue through the website, if not, it tells them to login. Is that enough security, or can people simply inject a session cookie into their browser to spoof that they are logged in?

My idea was to generate a session key cookie when they login (just a random string of letters and numbers) and store that in the database, then on every page, check to make sure their session key is the same thing that's in the database. Is this necessary? It seems expensive.

hi everyone.

i'm wondering what the best way is to create a session variable and pass it to an iframe.
i need to do something along these lines, but it doesn't seem to pass the ID. Any hints on how i should accomplish this?

Code: [Select]
session_start();
  $_SESSION['ID']=$_GET['ID']; // id from previous page
$ID=session_id();

 <iframe src="iframepage.php?ID=<?php echo $ID; ?>" style="width:680px; height:200px;" noresize="noresize" frameborder="0" border="0" scrolling="Yes" allowtransparency="true" /> </iframe>

I would appreciate your assistance, there are tons of login scripts and they work just fine. However I need my operators to login and then list their activities for the other operators who are logged in to see and if desired send their clients on the desired activity. I have the login working like a charm and the activities are listed just beautifully. How do I combine the two tables in the MySQL with PHP so the operator Logged in can only make changes to his listing but see the others.

FIRST THE ONE script the member logges in here to the one table in MSQL:
<?php
   session_start();
   
   require_once('config.php');
   
   $errmsg_arr = array();
   
   $errflag = false;
   
   $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
   if(!$link) {
      die('Failed to connect to server: ' . mysql_error());
   }
   
   $db = mysql_select_db(DB_DATABASE);
   if(!$db) {
      die("Unable to select database");
   }
   
   function clean($str) {
      $str = @trim($str);
      if(get_magic_quotes_gpc()) {
         $str = stripslashes($str);
      }
      return mysql_real_escape_string($str);
   }
   
   $login = clean($_POST['login']);
   $password = clean($_POST['password']);
   
   if($login == '') {
      $errmsg_arr[] = 'Login ID missing';
      $errflag = true;
   }
   if($password == '') {
      $errmsg_arr[] = 'Password missing';
      $errflag = true;
   }
   
   if($errflag) {
      $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
      session_write_close();
      header("location: login-form.php");
      exit();
   }
   
   $qry="SELECT * FROM members WHERE login='$login' AND passwd='".md5($_POST['password'])."'";
   $result=mysql_query($qry);
   
   if($result) {
      if(mysql_num_rows($result) == 1) {
         session_regenerate_id();
         $member = mysql_fetch_assoc($result);
         $_SESSION['SESS_MEMBER_ID'] = $member['member_id'];
         $_SESSION['SESS_FIRST_NAME'] = $member['firstname'];
         $_SESSION['SESS_LAST_NAME'] = $member['lastname'];
         session_write_close();
         header("location: member-index.php");
         exit();
      }else {
         header("location: login-failed.php");
         exit();
      }
   }else {
      die("Query failed");
   }
?>

................................................. ................................
Now I need the person who logged in to the table above to be able to make multiple entries to the table below

<?
$ID=$_POST['ID'];
$title=$_POST['title'];
$cost=$_POST['cost'];
$activity=$_POST['activity'];
$ayear=$_POST['aday'];
$aday=$_POST['ayear'];
$seats=$_POST['special'];
$special=$_POST['seats'];
mysql_connect("xxxxxx", "xxx350234427", "========") or die(mysql_error());
mysql_select_db("xxxx") or die(mysql_error());
mysql_query("INSERT INTO `activity` VALUES ('ID','$title', '$cost','$activity', '$aday', '$ayear', '$special', '$seats')");
Print "Your information has been successfully added to the database!"
?>
Click <a href="member-profile.php">HERE</a> to return to the main menu
  <?php      
?>

hi,

i have made a website where people resgister their details of them and products.

they have to enter the following details in form

Name of company

name of the product

company address

email id 

password 

mobile number contact

and 

brief details about their company 

after filling all details user is registered on website.

user can then login with email id and pwd.

now after login ..user will get a page where he can upload the photos of products images and their price, so now my question is that when he finishes uploading (|by clicking on upload button) the product images and price text box ..then on final uploaded webspage it should show all other things which he registerd before (company name , mobile number etc) along with images and price...hence the main question that user does not need to enter mobile and address while uploading images and filling proce ..but on the final page it should show mobile and address along with price and images..as user is not going to enter mobile and address again and again as he will have multiple products to upload.

thanks in advance .

Actually, what i want to do is to use the email to fetch the $email,$password and $randomnumber from database after

Hi,

so far I have managed to set up a somewhat basic login website with a mysql database backend.

Once they have logged on they go to a "main menu" page.

What I need to define is that user A sees button A but only that button, etc.

(Then of course that same rule would have to apply if they tried to directly go to the page, but I am guessing I can do that in the same way that I currently do to force a login).

If anyone has any tutorials or sample code I would much appreciate it.

Thanks,