PHP - Check If A Date Is 10 Days Beyond Another Date

Hi,

I have a job listing website which displays the closing date of applications using:

$expired_date

(This displays a date such as 31st December 2019)

I am trying to show a countdown/number of days left until the closing date.

I have put this together, but I can't get it to show the number of days.

                    <?php 
                    $expired_date = get_post_meta( $post->ID, '_job_expires', true );
                    $hide_expiration = get_post_meta( $post->ID, '_hide_expiration', true );
                    if(empty($hide_expiration )) {
                        if(!empty($expired_date)) { ?>
                                <span><?php echo date_i18n( get_option( 'date_format' ), strtotime( get_post_meta( $post->ID, '_job_expires', true ) ) ) ?></span>
                    
                    <?php
                                        $datetime1 = new DateTime($expired_date);
                                        $datetime2 = date('d');
                                        $interval = $datetime1->diff($datetime2);
                                        echo $interval->d;

                     ?>
                        <?php }
                    } 
                    ?>

Can anyone help me with what I have wrong?

Many thanks

Hi,

I have database stored a field of date. I want to check if the date in the DB field is the same as the current date, how to do it?

Code:

$oracle = mysqli_real_escape_string($con, $_POST['oracle']);
$query 	= mysqli_query($con, "SELECT indate FROM staff WHERE OracleID ='$oracle'");
$row	= mysqli_fetch_array($query);
$num_row = mysqli_num_rows($query);
		
	if ($num_row > 0) 
	{	
		$curdate = date();
		if ($row['indate'] !== $curdate)
		{
			$query1=mysqli_query($con, "update staff set ClockedIn = 0, ClockedOut = 0 where OracleID='$session_id'")or die('Error In Session');
			header('location:home.php');				
		}
	}

WHERE start_date BETWEEN 'start_date".strtotime('-3 day')."' AND 'start_date'";