PHP - Page Transverse Does Not Happen In My Web Site - Help Please
am a new bie for PHP.Hi i have uploaded review code to my webserver www.clickcity.in, the problem is after entering email and password -> click " sign in ", blank page is displayed.
however url shows as "http://www.clickcity.in/my/login.php?f=login&referer=".please help me to resove the same. now when i again go to www.clickcity.in in the same browser window , user is logged in. Similar TutorialsHi, I've got an issue with one of my pages: http://www.thelondonfiltercompany.com/filters.php?filterid=34 This appears fine in every browser other than IE8 where, for some reason, it decides to shove the main page content into the side bar and turn it into a link. I've been battling with this for hours, I'd just see if there is anything I am missing here! Thanks James Not sure if I'm trying to achieve something totally crazy here, or if this is something pretty standard. Didn't have much luck with searching as I'm not fully down with all the terms. (A) I have one site providing an RSS feed. (B) I have one site I want to search, once for each of the items in the feed A. (C) I want the results of the search in (B) to be displayed on page (C). So for example, the feed on (A) says; apples bananas oranges cheese I want site (B) to search for each of those terms (by passing the item in the feed (A) to the ?search= part of the URL of that page) and then show the results from THAT search on page C. Bit of a complex one, let me know if you need me to clarify. Thanks for any help! Hi everyone, Bit of a random question and im sure there is good reason so if someone could in lighten me that would be great ! With regards to the below code, it seems to just create an infinite loop when you put mysql_fetch_array. Just want to know what wrong with doing this? and why it act in this way ? Code: [Select] $sql = mysql_query("SELECT * FROM cities"); $results = mysql_fetch_array($sql); while($row = $results) { echo $row['City']."<br />"; } thanks Guys hi, i am having issues with sorting within a conditional statement. please see the code below. right now, i ve commented out the sorting below. basically i want to sort by: $venue1->hereNow->count. I am managing to pull the data correctly. see: http://marineboudeau.com/lab/4sq/ <?php if (is_object($venue->response)) { //sort($venue->response->groups[0]->items->hereNow->count); foreach ($venue->response->groups[0]->items as $venue1) { if ($venue1->hereNow->count != '0'){ //var_dump ($venue1); echo "<div style='font-weight:bold;'>".$venue1->name."</div>"; echo "<div>".$venue1->location->address." ".$venue1->location->city."</div>"; echo "<div>".$venue1->hereNow->count."</div>"; echo "</br>"; } } }?>() any idea what i need to do to make it happen? thank you. marine Hi there i was wondering is anyone could help me in creating a page for each site like info.php?site=sitename I've Currently got this but its not really working... Code: [Select] <?php include ("config.php"); $ServerName = $_GET['title']; $server = "SELECT * FROM sites WHERE title='$ServerName'"; $desc = $_GET['content']; $content = "SELECT * FROM sites WHERE content='$desc'"; $url = $_GET['link']; $link = "SELECT * FROM sites WHERE link='$url'"; if ($info== "$server") { echo "<h1>$server</h1>"; echo "<p>$content</p>"; echo "<a href='$link'>Visit Site</a> OR <a href='play.php?server=$server'>Play Now</a>"; } ?>Please relpy ASAP & Thank You in Advance... I think I finally figured out what my problem is! I have this huge login system that I got and I think it's designed so that in order to login it has a popup window come up. Well I want embed this page so the user can login right their on the page. Before I was using include but that screws up all the submit buttons. Anyone know of a simple code to embed a page? Hi everyone,
I have just created this affiliate sub-page where I compare webhosting providers in Denmark.
Page: Sammenligning af webhoteller
All links for all hosting providers are affiliate links.
Do you think this is a good approach and is the text ok? (use google translate)
In other words, do you think people will click and possibly ean me a comission?
Thanks for the feedback!
Edited by Stiver112, 21 July 2014 - 03:30 PM. I have 2 websites, a companies main website written in PHP and a web application they have purchased written in aspx (main site) www.example.com (web app) www.webapp.com/login.aspx?CompanyName=example The client wants people to be able to login from their main website which then redirect to the webapp (which will be styled like their branding) without the customer realising they have left the main site. I thought i may be able to achieve this with a simple include from a page within the main site such as; Code: [Select] <?php // www.example.com/software include"http://www.webapp.com/login.aspx?CompanyName=example"; ?> This pulls in the login page fine, however when you try to login it does not redirect, it gives a 404 error as it trys to open this URL http://www.example.com/software/login.aspx?CompanyName=example Is there a way of pulling in the necessary html from the aspx site to provide a login box in my clients main site but then have it redirect to the correct aspx page (on the aspx site)? I have thought about using an iframe, but that wont redirect to the webapp upon login, but just keep everything withing the iframe thanks for any advice... This is probably some silly mistake but I can't figure out why this code isn't working. I put this at the top of my php page: Code: [Select] <?php $https_url = 'https://somesite.com'; if ( isset( $_SERVER['HTTPS'] ) && $_SERVER['HTTPS'] == 'off' ) { header('location: ' . $https_url); exit; } else if ( !isset( $_SERVER['HTTPS']) && $_SERVER['SERVER_PORT'] == 443 ) { header('location: ' . $https_url); exit; } ?> When I was just trying this code out it worked and redirected to https. No errors no infinite loops...it worked perfectly. However, once our server guy actually applied the SSL to the page, the code stopped working and I get the error "The page must be viewed over a secure location." It throws the error before it processes anything on that page. I found the code online on another help forum and it worked for everyone else, so what am I doing wrong? I also tried a different version of the code that also works for everyone else but got the same error. Thanks for your help! Hi, Sorry if this is in the wrong place. I really just need a search term to use for what i'm trying to do. I would like my buttons to appear pressed on each page. For example if you are on the home page the home button will appear pressed. If you are on the screenshots page the screenshots button will appear pressed. Pretty much i want my nav bar to display what page is being viewed. I'm using SMF forums and i've created an extension of my forum that i'm using on the root of my site. As far as i can tell i have the correct code added to the forum that should highlight the home button while on the home page. The part i'm missing is the code to add onto the home page. This is the code I have on the button. $buttons = array( 'overview' => array( 'title' => $txt['overview'], 'href' => 'http://www.wararmada.com', 'show' => true, 'sub_buttons' => array( 'alliance' => array( 'title' => $txt['alliance'], 'href' => $scripturl . '?action=overview;area=alliance', 'show' => true, ), This is the code i have in the language file. $txt['overview'] = 'overview'; I'm not sure what this is called. I don't know anything about php but so far i've been able to get by just using google but I don't really know how to search for this. Thanks for all the help! In one of my pages I have a section which contains a hidden line of text. When the user clicks a button the box containing the text will expand showing the line more clearly. I want this to happen live i.e. no page refresh/reload. I've seen such things done on other sites but my question is, is this done using a php function or is JavaScript required to achieve this? I assume that in order for any php functions to take place there must be a page refresh to reload the data/parameters/variables that are required? The site I'm referring to is this one:- http://www.vouchercodes.co.uk/featured-voucher-codes.html If you click on the "Get code and open site" buttons there for any of the vouchers the area expands live and the voucher is revealed however as I say there is no page refresh and it is done live. Is this effect done in JavaScript and not php or is there some way of using php alone to do something similar? Obviously including JScript in a site is more risky as if a user does not have it installed/activated then they may not be able to use such elements hence the reason I want to know how it is done. hiii all, i want to show the database field (alise name) as the url after index.php when page or site loads first time. how i can achieve it? please help.... thanks in advance hello - dear phpfreaks,
i portet over a wordpress site to localhost. (an opensuse linux-box) all went nice and was very smooth to do so. after porting over the files and the db; i added the db-name and user-name etc. but nothing more. then i looked at the site http://localhost/mysite i saw the site - but only once - that is very very interesting. i read that i have to do more. Probably these changes - mentioned below are mandantory in order to avoid a blank page cf: https://managewp.com...#comment-148613 The two fields you need to edit are “siteurl” (highlighted above) and “home” (which you may need to navigate to the second page to find). Just click the “Edit” buttons next to each field, and replace the URL contained in “option_value” with “http://localhost/yourfoldername/”. That’s it! If you now navigate to “http://localhost/yourfoldername/”, your site should load up in all its glory. Please note that if you use custom permalinks, you will need to change them to default (in the WordPress > Settings > Permalinks screen) in order for internal links on your site to work. You can of course change the permalinks back to their custom form at any time. question: is this true? Do i need to make these changes to avoid a blank page!? I have several "sites" located in my html directory, and each has a "general" access point and an "administrator" access point:
/var/www/html/site1/index.php /var/www/html/site1/administrator/index.php /var/www/html/site2/index.php /var/www/html/site2/administrator/index.php /var/www/html/site3/index.php /var/www/html/site3/administrator/index.phpAll sites are similar except that data will be specific to site1, site2, or site3, etc. Users who log onto /var/www/html/siteX/index.php are totally unrelated to those who logon to /var/www/html/siteX/administrator/index.php, will have different logon credentials, are stored in different DB tables, and each should have their own session. If a user logs off of either the general or administrator site, it should not effect the other site even if they were previously logged on to both on the same PC (and of course not effect other sites). When a user logs off, I would like to destroy their previous cookie and associated session. Users for either will only use https. I am using Apache to rewrite https://www.mysite.com/ to https://mysite.com/. While I named the administrator site "administrator" above, the administrator user has the ability to change the directory name. I am thinking I need to use session_set_cookie_params to specify where I wish the session cookie to be stored since /var/www/html/siteX/administrator/index.php is a sub-directory to /var/www/html/siteX/index.php, but am not really sure. Sorry for the cryptic post, but I am not very well versed in this subject. How would you recommend setting up cookies/sessions for this scenario? Thank you now i use this code to show where the visitors came from to my site. <?php $referer=$_SERVER['HTTP_REFERER']; echo $referer; ?> now, i want to show the 5 latest vistors referer's site url on my site ? Hi, My first post here is a cry for help I have a Windows 2003 server running IIS6/PHP5, the server hosts multiple web sites. The problem is include files that are for site A are showing on site B (each site having its own includes as part of the site files in its own site folder), though not every time, its very random, sometimes the correct includes show, sometimes ones from another site on the same server. This only occurs where the include files for both sites have the same name, such as 'inc-header.php' for example. I can only assume PHP is caching includes and because they have the same name is showing the wrong one on other sites sometimes, if I rename them to something unique then the problem goes away, but its not a practical solution to rename all include files to unique names so I find myself looking for a 'real' fix. I have a feeling its to do with the include_path in the php.ini, but right now its disabled with a semi-colon, and I don't want to set one as I have no global includes, all includes are site specific. Any help would be very much appreciated! Phil Transferring data from sub-domain.site.com Reading sub-domain.site.com What is this all about? I'm going to put all .. images into a separate sub-domain eg: images.site.com. This would create a folder inside my public_HTML called "images" Now when sites have that Transferring data, and Reading... is this .. something relating to what I want. Facebook also does it, and they get their images for the site from a sub domain, how is it all done? I'm not sure if its entirely PHP, but I hope someone can help. Thanks I'm currently running a classified ads site and planning to display my own content from database combined with and external site rss. So here is what i got right now after the db query for the jobs ads (procedural php),
while ($row = mysqli_fetch_array($results, MYSQLI_ASSOC)){ echo '<div class="media margin-none"> <a class="pull-left bg-inverse innerAll text-center" href="#"><img src="'.$foto.'" share_alt="" width="100" height="100"></a> <div class="media-body innerAll"> <h4 class="media-heading innerT"> <a href="' . $row['title'] .'-da' . $row['id_ad'] . '" class="text-inverse">'. $remuneracion .' ' . substr(ucfirst(strtolower($row['title'])), 0, 53) . '</a> <small class="pull-right label label-default"><i class="fa fa-fw fa-calendar-o"></i> ' . $row['date_created'] . '</small></h4> <p>' . substr(ucfirst(strtolower($row['description'])), 0, 80) . ' ...</p>'; echo '</div> </div> <div class="col-separator-h"></div>'; } echo pagination($statement,$per_page,$page, $url_filtros, $filtros); ?>it is the while loop that i use to display ads from my database, what could be the best way to display (in this same loop?) other site's rss feed so i can show my content combined with the external rss? Thanks Hi I made a new design for my website and I made some changes. I want to use layout for my second site.
I'll like to know if my site is easier to browse through now and if you like the design better?. I test my site on internet explorer, chrome, and firefox. It is best to use site on better browsers like firefox and chrome to get a better experience of site. Thanks.
http://adjade.com
Quesion: Show each movie in the database on its own page, and give the user links in a "page 1, Page 2, Page 3" - type navigation system. Hint: Use LIMIT to control which movie is on which page. I have provided 3 files: 1st: configure DB, 2nd: insert data, 3rd: my code for the question. I would appreciate the help. I am a noob by the way. First set up everything for DB: <?php //connect to MySQL $db = mysql_connect('localhost', 'root', '000') or die ('Unable to connect. Check your connection parameters.'); //create the main database if it doesn't already exist $query = 'CREATE DATABASE IF NOT EXISTS moviesite'; mysql_query($query, $db) or die(mysql_error($db)); //make sure our recently created database is the active one mysql_select_db('moviesite', $db) or die(mysql_error($db)); //create the movie table $query = 'CREATE TABLE movie ( movie_id INTEGER UNSIGNED NOT NULL AUTO_INCREMENT, movie_name VARCHAR(255) NOT NULL, movie_type TINYINT NOT NULL DEFAULT 0, movie_year SMALLINT UNSIGNED NOT NULL DEFAULT 0, movie_leadactor INTEGER UNSIGNED NOT NULL DEFAULT 0, movie_director INTEGER UNSIGNED NOT NULL DEFAULT 0, PRIMARY KEY (movie_id), KEY movie_type (movie_type, movie_year) ) ENGINE=MyISAM'; mysql_query($query, $db) or die (mysql_error($db)); //create the movietype table $query = 'CREATE TABLE movietype ( movietype_id TINYINT UNSIGNED NOT NULL AUTO_INCREMENT, movietype_label VARCHAR(100) NOT NULL, PRIMARY KEY (movietype_id) ) ENGINE=MyISAM'; mysql_query($query, $db) or die(mysql_error($db)); //create the people table $query = 'CREATE TABLE people ( people_id INTEGER UNSIGNED NOT NULL AUTO_INCREMENT, people_fullname VARCHAR(255) NOT NULL, people_isactor TINYINT(1) UNSIGNED NOT NULL DEFAULT 0, people_isdirector TINYINT(1) UNSIGNED NOT NULL DEFAULT 0, PRIMARY KEY (people_id) ) ENGINE=MyISAM'; mysql_query($query, $db) or die(mysql_error($db)); echo 'Movie database successfully created!'; ?> ******************************************************************** *********************************************************************** second file to load info into DB: <?php // connect to MySQL $db = mysql_connect('localhost', 'root', '000') or die ('Unable to connect. Check your connection parameters.'); //make sure you're using the correct database mysql_select_db('moviesite', $db) or die(mysql_error($db)); // insert data into the movie table $query = 'INSERT INTO movie (movie_id, movie_name, movie_type, movie_year, movie_leadactor, movie_director) VALUES (1, "Bruce Almighty", 5, 2003, 1, 2), (2, "Office Space", 5, 1999, 5, 6), (3, "Grand Canyon", 2, 1991, 4, 3)'; mysql_query($query, $db) or die(mysql_error($db)); // insert data into the movietype table $query = 'INSERT INTO movietype (movietype_id, movietype_label) VALUES (1,"Sci Fi"), (2, "Drama"), (3, "Adventure"), (4, "War"), (5, "Comedy"), (6, "Horror"), (7, "Action"), (8, "Kids")'; mysql_query($query, $db) or die(mysql_error($db)); // insert data into the people table $query = 'INSERT INTO people (people_id, people_fullname, people_isactor, people_isdirector) VALUES (1, "Jim Carrey", 1, 0), (2, "Tom Shadyac", 0, 1), (3, "Lawrence Kasdan", 0, 1), (4, "Kevin Kline", 1, 0), (5, "Ron Livingston", 1, 0), (6, "Mike Judge", 0, 1)'; mysql_query($query, $db) or die(mysql_error($db)); echo 'Data inserted successfully!'; ?> ************************************************************** **************************************************************** MY CODE FOR THE QUESTION: <?php $db = mysql_connect('localhost', 'root', '000') or die ('Unable to connect. Check your connection parameters.'); mysql_select_db('moviesite', $db) or die(mysql_error($db)); //get our starting point for the query from the URL if (isset($_GET['offset'])) { $offset = $_GET['offset']; } else { $offset = 0; } //get the movie $query = 'SELECT movie_name, movie_year FROM movie ORDER BY movie_name LIMIT ' . $offset . ' , 1'; $result = mysql_query($query, $db) or die(mysql_error($db)); $row = mysql_fetch_assoc($result); ?> <html> <head> <title><?php echo $row['movie_name']; ?></title> </head> <body> <table border = "1"> <tr> <th>Movie Name</th> <th>Year</th> </tr><tr> <td><?php echo $row['movie_name']; ?></td> <td><?php echo $row['movie_year']; ?></td> </tr> </table> <p> <a href="page.php?offset=0">Page 1</a>, <a href="page.php?offset=1">Page 2</a>, <a href="page.php?offset=2">Page 3</a> </p> </body> </html> |