PHP - Get Content (preg?)

So i have this script  that outputs Listed Files inside a folder

    echo '<option value="'.$fileName.'">'.$fileName.'</option>';}

like this :

<option value="Fonts/28 Days Later.ttf">Fonts/28 Days Later.ttf</option> etc files ....

i would like to know how may i remove  " Fonts/ " And the .ttf extension from the second part that repeats (the name) using something like preg_replace and to make the first letter uppercase using ucfirst()


And if someone is familiar with preg_replace
could you please give me a tutorial on how it works to replace some text ?

Thanks In Advance

basically what i am trying to do is replace the

<a href="whatever.com"> 

with

<a href="whatever.com" onclick = "if (! confirm("Continue?")) return false;">

so that when the user clicks the url in a message the box pops up first then redirects them to the url if they click confirm. However i am getting the following error:

Code: [Select]
Warning: preg_replace() [function.preg-replace]: Compilation failed: reference to non-existent subpattern at offset 11
here is the code i used.

$message_content = $content_info['message_content'];
$pattern='<a href="\\1">';
$replace='<a href="\\1" onclick = "if (! confirm("Continue?")) return false;">';
$message_content = preg_replace($pattern, $replace, $message_content);
echo $message_content;

Anyone know where i went wrong?

$name = preg_replace('{(\d+)}', convertNumber("$1"), $row['name']); 


why isnt this working?

im having trouble using this function. im trying to change the strings within a post.

eg:

Code: [Select]
This is an example post
[attachment=file.png]

what im trying to do is change [attachment=file.png] to file.png.

Here is the code i have but it doesnt change anything.


$p_content = str_replace('<br>', '', $post_info[$key]['p_content']);
        $attach = preg_split('|\[attachment=|', $p_content);
        
        for($i=0; $i<count($attach); $i++)
        {
            $attach[$i] = str_replace(']', '', $attach[$i]);
            if(file_exists($config['asf_root'].'attachments/'.$attach[$i]))
            {
                $p_content = preg_replace('|\[attachment=([0-9a-zA-Z\.-_])\]|#i', $attach[$i], $p_content);
            }
        }
        echo $p_content;


it first gets all the attachment tags within the post then applies the preg replace to all of them. But the preg replace isnt replacing, so i must have gone wrong somewhere.
Any tips/ideas?

Thanks

Hi, I am having a pretty difficult time getting files to upload to my server that have a Single Quote in the file name.
Example:

myfile's.pdf

I need to strip the file name of the quote before it uploads to the server.
I currently am using SWFUpload and this is the bit of code that was included with it.

I need to modify it to remove the single quotes as well. Been hammering my head over this all day.


$file_name = preg_replace('/[^'.$valid_chars_regex.']|\.+$/i', "", basename($_FILES[$upload_name]['name']));
if (strlen($file_name) == 0 || strlen($file_name) > $MAX_FILENAME_LENGTH) {
HandleError("Invalid file name");
exit(0);
}


thanks

I am very confused....
In my database I have lots of comments, but when displayed on the page, a few catch my eye...

Here is one, it displays wrong
Quote

1. addslashes() is not sufficient enough to prevent SQL injection. Use mysql_real_escape_string().

2. You are not enclosing your values in quotes, this just means they need to have a space in their submission to inject SQL.

3. You should not ever echo out mysql_error() to an end user. Log it for your own purposes, but show the user a generic error message.

Your query would be better off like this:

<?php   
   $sql = mysql_query("SELECT * FROM users_table
   WHERE username='".mysql_real_escape_string($_POST['username'])."' AND
   password='".mysql_real_escape_string($_POST['password'])."' LIMIT 1")or die('Sorry, there has been a database error. The webmaster has been notified of the error. Please try again later.');
?>


but this one displays correctly:
Quote

(That was me, the latest Anonymous poster)

One *last* thing. You're saving the passwords as plain text. BAD idea, especially with the SQL injection problems you have. Someone with the right knowledge can easily steal all your user's passwords.

I'd recommend using md5() to has the passwords (at very least md5, though sha1 would be nicer).

Try this:
<?php
$sql = mysql_query("SELECT * FROM users_table
WHERE username='".mysql_real_escape_string($_POST['username'])."' AND
password=md5('".mysql_real_escape_string($_POST['password'])."') LIMIT 1")or die('Sorry, there has been a database error. The webmaster has been notified of the error. Please try again later.');
?>


And make sure you md5() the passwords when you insert them into the database initially.


Do you see where the php tags are? when my script see it, it formats the php but some format not only the php, but the text as well, and I am not sure why.
if you take a look at this page http://beta.phpsnips.com/snippet.php?id=4 and scroll down to the date: 08/20/2008

The first comment displays nice
The second displays okay, "Would be better off as: " is formated as php and shouldn't be
The third one formats the entire post as php

Here is my php to check each comment (it is in a while loop):
$comment = preg_split("/^(<\?php.*?[^\'\"]\?>[^\'\"])/ms", $cow['comment'], -1, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);
foreach($comment as $line){
preg_match('/<\?php.*?\?>/s', $line, $matches);
if($matches[0]){
echo '<div class="phpComment">';
highlight_string($line);
echo '</div>';
}else{
echo nl2br(htmlentities(str_replace('<br />','',$line)));
}
}

Anyone see what is wrong, and why it is formating funky?

i keep getting this at top of page
Warning: preg_replace() [function.preg-replace]: No ending delimiter '`' found in C:\xampp\htdocs\socialtscripts\activation.php on line 16
here is the code that it is reffering to
Code: [Select]
preg_replace("`", "", $id);

Code: [Select]
line 129- function filterBadWords($str)
 {
    $result = mysql_query("SELECT badwords FROM clean") or die(mysql_error());
    $replacements = "*";
   
    while($row = mysql_fetch_assoc($result))
    {     
          $bad_words= $row['badwords'];
          $spaced_bad_words = preg_replace("/(.)/i", "\${1} ", $bad_words);
          $spaced_bad_words = trim($spaced_bad_words);
          $str = preg_replace("/$bad_words | $spaced_bad_words/i", str_repeat('*', strlen($bad_words)), $str);
    }
   
    return $str;
Line 143 - }
I go this error "Warning: preg_replace() [function.preg-replace]: Compilation failed: unmatched parentheses at offset 1 in C:\xampp\htdocs\login\chatlog3.php on line 139"

Code: [Select]
$text = preg_replace('{-(\d+)}e', '-convertNumber("$1")', $text);
i have strings im trying to replace like this:

name-2 > name-two
name-p2 > name-p2

im trying to match and replace the first one and basically ignore the second one. ive included the hyphen in the code. so why isnt this working?

I've never really made my own bbcode parser function before, but I'm going off of different tutorials to help me create my own style of parsing.  I've actually never really used preg_replace much, either.  My code is returning an odd error and I have no idea how to fix it.  I'm using codeigniter and the error it returns is below:

Quote

preg_replace() [function.preg-replace]: Compilation failed: nothing to repeat at offset 6


This is the code for my function:
Code: [Select]
function bbParse($string){

$codes = array(
'/\[b\](*?)\[\/b\]/' => '<b>\\1</b>', //bold tags
'/\[h2\](*?)\[/h2\]/' => '<h2>\\1</h2>', //h2 tags
'/\[h3\](*?)[\/h3\]/' => '<h3>\\1</h3>', //h3 tags
'/\[quote\](*?)\[\/quote\]/' => '<blockquote>\\1</blockquote>', //quote tags using the template's blockquote tag
'/\[img\](*?)\[/img\]/' => '<img src=\'\\1\' alt=\'Image Not Available\'>', //image tags
'/\[url\=(*?)\](*?)\[/url\]/' => '<a href=\'\\1\' title=\'\\2\'>\\2</a>', //anchor tags
'/\[p\](*?)\[/p\]/' => '<p>\\1</p>' //paragraph tags
);



$string = preg_replace(array_keys($codes), array_values($codes), $string);

return $string;


}

Hi all

I am trying to do an email validation check. Here's my code:

if (!preg_match($email) == "^[a-z0-9]+([-_\.]?[a-z0-9])+@[a-z0-9]+([-_\.]?[a-z0-9])+\.[a-z]")
{
include("checkout-email-error.php");
exit;
}


It doesn't seem to allow any email addresses through? All help greatly appreciated!

Thanks
Pete

This topic has been moved to PHP Regex.

http://www.phpfreaks.com/forums/index.php?topic=351288.0

Hello, I am trying to replace a url and add a sub-id to it, however I'm not quite there. Any help is always appreciated here. In the end, I would like the value of gotoUrl to have the cpId 123abc45 attached to it. I.E.

http://example.com/?Aff=56732&SID=123abc45
http://example.com/?Aff=56732&uv=123abc45&product=1834234
http://example.com/?Aff=56732&cid=123abc45&ace=2gs244s3

$gotoUrl = "http://example.com/?Aff=56732&SID=";
// OR could be listed as such:
// $gotoUrl = "http://example.com/?Aff=56732&uv=default&product=1834234";
// $gotoUrl = "http://example.com/?Aff=56732&cid=&ace=2gs244s3";

// Will attach this to replace value
$cpId = "123abc45";
// Possible sid replacements, depending on the url
$sidList = array("sid","SID","cid","uv");

	if ($gotoUrl){
		foreach($sidList as $sidVar){
			if (preg_match("/$sidVar/i", $gotoUrl)){
			$gotoUrl = preg_replace("#{$sidVar}(?=.*\d)(?=.*[a-z])(?=.*[A-Z])$#", "{$sidVar}={$cpId}", $gotoUrl);
			}
		}
        echo $gotoUrl;
        }

Edited by iwpg, 13 August 2014 - 10:36 PM.