PHP - Query Order Using Get
I am attempting to order the results of a query using the get value but they wont order.
here is the form: echo "<form name=\"order_form\" action=\"{$site_root}/index.php\" method=\"GET\">"; echo "<input type=\"hidden\" value=\"{$forum_id}\" name=\"forum\" />"; echo "<select name=\"order_by\" style=\"margin-left:5px;\">"; echo "<option value=\"asc\" name=\"order_option\" />Order By: Ascending</option>"; echo "<option value=\"desc\" name=\"order_option\" />Order By: Descending</option>"; echo "</select>"; echo "<select name=\"sort_by\" style=\"margin-left:5px;\">"; echo "<option value=\"topic_name\" name=\"sort_option\" />Sort By: Topic Name</option>"; echo "<option value=\"topic_poster\" name=\"sort_option\" />Sort By: Topic Author</option>"; echo "<option value=\"topic_time_posted\" name=\"sort_option\" />Sort By: Time Posted</option>"; echo "<option value=\"topic_views\" name=\"sort_option\" />Sort By: Topic Views</option>"; echo "<option value=\"topic_replies\" name=\"sort_option\" />Sort By: Topic Replies</option>"; echo "<option value=\"topic_last_poster\" name=\"sort_option\" />Sort By: Last Poster</option>"; echo "<option value=\"topic_last_post_time\" name=\"sort_option\" />Sort By: Last Post Time</option>"; echo "</select>"; echo "<input type=\"submit\" value=\"Order\" />"; echo "</form>"; here is the query: $topic_info_query = $db->query("SELECT f.forum_id, f.forum_name, m.user_id, m.user_username, m.user_group, t.thread_topic_id, t.topic_name, t.topic_poster, t.topic_time_posted, t.topic_views, t.topic_replies, t.topic_last_poster, t.topic_last_post_time, t.topic_locked, t.topic_sticky, t.topic_edited, t.topic_last_poster_id, t.topic_last_poster_group, t.topic_icon FROM ".DB_PREFIX."topics as t LEFT JOIN ".DB_PREFIX."members as m ON t.topic_poster = m.user_username LEFT JOIN ".DB_PREFIX."forums as f ON t.forum_id = f.forum_id WHERE t.forum_id = '$forum_id' '".$sort_by . ' ' . $order_by."'") and here is where $sort_by and $order_by are defined: if (isset($_GET['order_by'])) { $order_by = mysql_real_escape_string($_GET['order_by']); $order_by = strtoupper($order_by); } if (isset($_GET['sort_by'])) { $sort_by = 'ORDER BY t.'.mysql_real_escape_string($_GET['sort_by']); } when i echo '".$sort_by . ' ' . $order_by."' which is how it appears in the query i get: t.topic_last_post_time DESC which is exactly right. But the results are not being sorted. The echoed variables change as does the url but no sorting happens. any ideas? Similar TutorialsScript:
<?php $tqs_admin_flag = "SELECT * FROM `flags`"; $tqr_admin_flag = mysqli_query($dbc, $tqs_admin_flag) or die(mysqli_error($dbc)); while($row_admin_flag = mysqli_fetch_array($tqr_admin_flag)){ //print_r($row_admin_flag); $tqs_admin_flag_thread = "SELECT * FROM `thread` WHERE `id` = '" . $row_admin_flag['thread_id'] . "' ORDER BY `date_created` DESC"; $tqr_admin_flag_thread = mysqli_query($dbc, $tqs_admin_flag_thread) or die(mysqli_error($dbc)); while($row = mysqli_fetch_assoc($tqr_admin_flag_thread)){ include($_SERVER['DOCUMENT_ROOT'] . "/gallerysite/admin_flag_thread.php"); } } ?>This in comparison works: $tqs_admin_flag_thread = "SELECT * FROM `thread` ORDER BY `date_created` DESC";I would appreciate suggestions for which reasons the above script (the way it is) may not work. With the above script the querying and printing on screen does happen, though the "ordering by DESC" does not happen. Edited by glassfish, 24 October 2014 - 11:38 AM. I have a basic query where I am retrieving project records. I basically want to show the records from newest to oldest, but I also want to show the Featured projects first. Each Featured project is marked by "1" in the mysql table column. If it's not featured, then it's marked "0". $find_records = $db->prepare("SELECT * FROM projects ORDER BY project_id DESC, featured DESC LIMIT 10"); $find_records->execute(); $result_records = $find_records->fetchAll(PDO::FETCH_ASSOC); if(count($result_records) > 0) { foreach($result_records as $row) { } } The issue with above query is that the ORDER BY works only for the first component(project_id) and ignores the second component(featured). Do you see what's wrong with it? i have this query and i'm trying to order all of the results by `created` ascending. I've tried putting the later query before the first but the single row from the first query(the way it is right now) gets stuck as the last row in the results. How can i order the results of both queries? Code: [Select] ( SELECT * FROM Account_activity WHERE DATE( created ) < '2011-08-01' AND username = '40' ORDER BY created DESC LIMIT 1 ) UNION ( SELECT * FROM Account_activity WHERE MONTH( created ) = '08' AND YEAR( created ) = '2011' AND username = '40' ORDER BY created ASC ) I am trying to use the following query with sorting: $query = mysql_query("SELECT * FROM Table WHERE Date LIKE '$PeriodSelected' ORDER BY Date DESC"); $PeriodSelected is basically supposed to get me all results from month selected and it works fine. Now I am trying to add sorting to this query and although I get no errors it does not matter if I use ASC or DESC my results are sorted in the same way. Not sure what I am doing wrong. This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=332593.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=312690.0 I am loading notifications from a database table called "notifications" and I am having a little trouble getting them to order in the correct way. my query I'm using right now: Code: [Select] $query = mysql_query("SELECT B.* FROM (SELECT A.* FROM notifications A WHERE A.user_id='$session' AND A.from_id!='$session' ORDER BY A.id ASC ) AS B ORDER BY B.state ASC LIMIT 7"); this works well as far as showing the unread notifications on top, then the read notifications below, however it's not ordering the two sets by ID (which the id auto increments so the higher id number is the newest) from newest on top to the oldest on bottom, still keeping them separated by the unread on top, read on bottom (column name is state for showing whether they're read or not). The order the notifications are displaying by their ID is: 3 5 2 4 1 when it should be: 5 3 2 4 1 i am printing the dates from the last 30 days in ascending order and then comparing them in my query to print the results. How can I can print the below array in descending order without affecting my query? Code: [Select] $thirtydaysago = time() - (30 * 24 * 60 * 60); $oneday=24 * 60 * 60; for($i=0;$i<31;$i++) { $d[$i]= $thirtydaysago + ($i*$oneday); echo date('Y-m-d',$d[$i])."<br>"; } for($i=0;$i<31;$i++) { $postsql=mysql_query("SELECT DATE_FORMAT(FROM_UNIXTIME(dateline), '%Y-%m-%d') AS FmtDate, COUNT(postid) AS PostCnt FROM post " . "WHERE dateline < '" . $d[$i+1] . "' AND dateline >= '" . $d[$i] . "' GROUP BY DATE_FORMAT(FROM_UNIXTIME(dateline), '%Y-%m-%d') DESC") or die(mysql_error()); if($postsql_rows=mysql_fetch_assoc($postsql)) { $data_date[$i]["date"]=$postsql_rows['FmtDate']; $data_postcount[$k][$i]["postcount"]=$postsql_rows['PostCnt']; } } $k++; }
Hi everyone. I'm very new into self learning programming. Presently I'm trying to develop a simple basic Robot that would only Place a Market Order every seconds and it will cancel the Order every followed seconds. Using the following library: It would place Trade Order at a ( Price = ex.com api * Binance api Aggregate Trades Price) I have already wrote the api to call for xe.com exchange rate with php <?php $auth = base64_encode("username:password"); $context = stream_context_create([ "http" => [ "header" => "Authorization: Basic $auth" ] ]); $homepage = file_get_contents("https://xecdapi.xe.com/v1/convert_from?to=NGN&amount=1.195", false, $context ); $json = json_decode($homepage, TRUE); foreach ($json as $k=>$to){ echo $k; // etc }; ?> And also for the Binance Aggregate Price in JavaScript
<script> var burl = "https://api3.binance.com"; var query = '/api/v3/aggTrades'; query += '?symbol=BTCUSDT'; var url = burl + query; var ourRequest = new XMLHttpRequest(); ourRequest.open('GET',url,true); ourRequest.onload = function(){ console.log(ourRequest.responseText); } ourRequest.send(); </script>
My problem is how to handle these two api responds and also the functions to use them to place a trade and cancel it. I've got. Hello all,
Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).
The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).
Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:
In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).
I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.
Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.
So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:
1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red.
2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red.
3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.
Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.
Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.
Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.
Cheers guys!
case "update-delete": if(isset($_POST['highlight-purchased'])) { // ****** Setup customized query to obtain only items that are checked ****** $sql = "SELECT * FROM shoplist WHERE"; for($i=0; $i < count($_POST['checkboxes']); $i++) { $sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or"; } $sql= rtrim($sql, "or"); $statement = $conn->prepare($sql); $statement->execute(); // *** fetch results for all checked items (1st query) *** // $result = $statement->fetchAll(); $statement->closeCursor(); // Setup query that will change the purchased flag to "N", if it's currently set to "Y" $sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'"; // Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL $sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL"; $statementSetToN = $conn->prepare($sqlSetToN); $statementSetToY = $conn->prepare($sqlSetToY); /*** loop through the results/collection of checked items ***/ foreach($result as $row) { if ($row["purchased"] != "Y") { // *** fetch one row at a time pertaining to the 2nd query *** // $resultSetToY = $statementSetToY->fetch(); foreach($resultSetToY as $row) { $statementSetToY->execute(); } } else { // *** fetch one row at a time pertaining to the 2nd query *** // $resultSetToN = $statementSetToN->fetch(); foreach($resultSetToN as $row) { $statementSetToN->execute(); } } } break; }CRUD Queston.png 20.68KB 0 downloads Here is my code: // Start MySQL Query for Records $query = "SELECT codes_update_no_join_1b" . "SET orig_code_1 = new_code_1, orig_code_2 = new_code_2" . "WHERE concat(orig_code_1, orig_code_2) = concat(old_code_1, old_code_2)"; $results = mysql_query($query) or die(mysql_error()); // End MySQL Query for Records This query runs perfectly fine when run direct as SQL in phpMyAdmin, but throws this error when running in my script??? Why is this??? Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= new_code_1, orig_code_2 = new_code_2WHERE concat(orig_code_1, orig_c' at line 1 If you also have any feedback on my code, please do tell me. I wish to improve my coding base. Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference. Code: Code: [Select] mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); Full code: Code: [Select] <?php include_once("includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><? $title; ?></title> <meta http-equiv="Content-Language" content="English" /> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> </head> <body> <div id="wrap"> <div id="header"> <h1><? $title; ?></h1> <h2><? $description; ?></h2> </div> <? include_once("includes/navigation.php"); ?> <div id="content"> <div id="right"> <h2>Create</h2> <div id="artlicles"> <?php if(!$_SESSION['user']) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $name = mysql_real_escape_string($_POST['name']); $server_type = mysql_real_escape_string($_POST['type']); $description = mysql_real_escape_string($_POST['description']); if(!$username || !$password || !$server_type || !$description || !$name) { echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>"; echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'> <option value='Any'>Any</option> <option value='PvP'>PvP</option> <option value='Creative'>Creative</option> <option value='Survival'>Survival</option> <option value='Roleplay'>RolePlay</option> </select></td></tr> <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>"; echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>"; } elseif(strlen($password) < 8) { echo "Password needs to be higher than 8 characters!"; } elseif(strlen($username) > 13) { echo "Username can't be greater than 13 characters!"; } else { $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1"); if(mysql_num_rows($check1) < 0) { echo "Sorry, there is already an account with this username and/or server name!"; } else { $ip = $_SERVER['REMOTE_ADDR']; mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); echo "Server has been succesfully created!"; } } } else { echo "You are currently logged in!"; } ?> </div> </div> <div style="clear: both;"> </div> </div> <div id="footer"> <a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop </div> </div> </body> </html> I was just wondering if it's possible to run a query on data that has been returned from a previous query? For example, if I do Code: [Select] $sql = 'My query'; $rs = mysql_query($sql, $mysql_conn); Is it then possible to run a second query on this data such as Code: [Select] $sql = 'My query'; $secondrs = mysql_query($sql, $rs, $mysql_conn); Thanks for any help I'm trying to update every record where one field in a row is less than the other. The code gets each row i'm looking for and sets up the query right, I hope I combined the entire query into one string each query seperated by a ; so it's like UPDATE `table` SET field2= '1' WHERE field1= '1';UPDATE `table` SET field2= '1' WHERE field1= '2';UPDATE `table` SET field2= '1' WHERE field1= '3';UPDATE `table` SET field2= '1' WHERE field1= '4';UPDATE `table` SET field2= '1' WHERE field1= '5'; this executes properly if i run the query in phpMyAdmin, however when I run the query in PHP, it does nothing... Any advice? Say I have this query: site.com?var=1 ..I have a form with 'var2' field which submits via get. Is there a way to produce: site.com?var=1&var2=formdata I was hoping there would be a quick way to affix, but can't find any info. Also, the query could sometimes be: site.com?var2=formdata&var=1 I would have to produce: site.com?var2=updatedformdata&var=1 Is my only option to further parse the query? here's the code: Code: [Select] $companyName = 'big company'; $address1 = 'big bay #8'; $address2 = 'some big warehouse'; $city = 'big city'; $province = 'AB'; $postalCode = 'T1T0N0'; $phone = '0123456789'; $email2 = 'bigKahuna@bigKahuna.edu'; $query = "INSERT INTO clients ( companyName, address1, address2, city, province, postalCode, phone, email) VALUES ( ". $companyName.",".$address1.",".$address2.",".$city.",".$postalCode.",".$phone.",".$email2.")"; $result = mysql_query($query, $connexion); if ($result) { // Success! echo "Fabulous! check the DB, we did it! :D<br>"; ?> <pre> <?php print_r($result); ?> </pre> <?php } else { // Fail! echo"CRAAAAAPP! something went wrong. FIX IT! :P<br>"; echo mysql_error(); } if (isset($connexion)) { mysql_close($connexion); } i copied it over from an old *working* file to illustrate how a simple INSERT works. this is the error i get: Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'company,big bay #8,some big warehouse,big city,T1T0N0,0123456789,bigKahuna@bigKa' at line 4 looks completely valid to me. all the database table elements are set to VARCHAR(80), so it can't be a space/type issue... halp! WR! What would be the correct way to close a mysql query? At current the second query below returns results from the 1st query AND the 2nd query The 3rd query returns results from the 1st, 2nd and 3rd query. etc etc. At the moment I get somthing returned along the lines of... QUERY 1 RESULTS Accommodation 1 Accommodation 2 Accommodation 3 QUERY 2 RESULTS Restaurant 1 Restaurant 2 Restaurant 3 Accommodation 1 Accommodation 2 Accommodation 3 QUERY 3 RESULTS Takeaways 1 Takeaways 2 Takeaways 3 Restaurant 1 Restaurant 2 Restaurant 3 Accommodation 1 Accommodation 2 Accommodation 3 Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <?php include($_SERVER['DOCUMENT_ROOT'].'/include/db.php'); ?> <title>Untitled Document</title> <style type="text/css"> <!-- --> </style> <link href="a.css" rel="stylesheet" type="text/css" /> </head><body> <div id="listhold"> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Placestostay.html">Places To Stay</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Accommodation' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Eatingout.html">Eating Out</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Restaurant' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Eatingin.html">Eating In</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Takeaways' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------SKILLED TRADES BELOW---------------------------------------------------> <div class="list"><a href="Skilledtrades.html">Skilled Trades</a><br/> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Skilled Trades' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> I'm restarting this under a new subject b/c I learned some things after I initially posted and the subject heading is no longer accurate. What would cause this behavior - when I populate session vars from a MYSQL query, they stick, if I populate them from an MSSQL query, they drop. It doesn't matter if I get to the next page using a header redirect or a form submit. I have two session vars I'm loading from a MYSQL query and they remain, the two loaded from MSSQL disappear. I have confirmed that all four session vars are loading ok initially and I can echo them out to the page, but when the application moves to next page via redirect or form submit, the two vars loaded from MSSQL are empty. Any ideas? Hello, I have classes in a database with no set UNIX date, just the day like Wednesday and in two other columns the start and end dates. I want to be able to order by the day first and then by end_time but php orders the day column by spelling and not the day it holds in chronological order. Is there anyway to change the query to order the day column as a date? See the query below? Code: [Select] $query = "SELECT * FROM zumba_timetable WHERE end_time>'$current_time' ORDER BY day, end_time ASC LIMIT 0,1"; |