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PHP - Strange Twist In Update Script
Hello Code Gents,
I get so stretched breaking point when a trusted resuable code refuses to perform: Here's it Code: [Select] <?php require_once("includes/start_session.php"); require_once("includes/cn.php"); $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); $username=$_GET[$_SESSION['username']]; require_once("includes/nav_menu.php"); ///updates $msg=""; $aid=$_GET['aid']; $staff_id=$_GET['staff_id']; $come="select * from staff_payrolls where staff_id='$staff_id'"; $q1=mysqli_query($dbc,$come); $row=mysqli_fetch_array($q1); $aid = $row['aid']; $staff_id = $row['staff_id']; $basic = $row['basic']; $rent = $row['rent']; $pension = $row['pension']; $union = $row['union']; $tax = $row['tax']; $net = $row['net']; $gross = $row['gross']; if (isset($_POST['submit'])) { $renti=$basic*0.5; $pensioni=$basic*0.05; $unioni=$basic*0.03; $taxi=$basic*0.02; $neti=$basic+$rent; $grossi=$basic+$rent+$pension+$tax; // Grab the profile data from the POST //$staff_id = mysqli_real_escape_string($dbc, trim($_POST['staff_id'])); $basic = mysqli_real_escape_string($dbc, trim($_POST['basic'])); $rent = mysqli_real_escape_string($dbc, trim($_POST['rent'])); $union = mysqli_real_escape_string($dbc, trim($_POST['union'])); $pension = mysqli_real_escape_string($dbc, trim($_POST['pension'])); $tax = mysqli_real_escape_string($dbc, trim($_POST['tax'])); $net = mysqli_real_escape_string($dbc, trim($_POST['net'])); $gross = mysqli_real_escape_string($dbc, trim($_POST['gross'])); $error=false; if (!$error) { if (!empty($aid)) { //UPDATE `ak`.`staff_payrolls` SET `basic` = '' WHERE `staff_payrolls`.`aid` =1; $sql= "UPDATE `ak`.`staff_payrolls` SET `basic` ='$_POST[basic]', `rent`='$renti',`pension`='$pensioni',`union`='$unioni',`tax`='$taxi',`net` ='$neti',`gross` ='$grossi',`salary_date`=SYSDATE() where `staff_payrolls`.`aid` ='$aid'"; mysqli_query($dbc, $sql); } } // End of check for form submission } ?> <p><strong>Welcome to BODE COSMETICS PAYROLL MANAGEMENT SYSTEM.</strong></p> <p><?php echo("Welcome $_SESSION[username]. You can start by the top-pane Navigation") ;?> <p><?php //echo $err ; if (@mysqli_query($dbc, $sql)) { echo 'Record Updated';} $query = "SELECT * FROM staff_payrolls WHERE aid = '$aid'"; $data = mysqli_query($dbc, $query); $row = mysqli_fetch_array($data); $staff_id = $row['staff_id']; $basic = $row['basic']; $rent = $row['rent']; $pension = $row['pension']; $union = $row['union']; $tax = $row['tax']; $net = $row['net']; $gross = $row['gross']; ?> <table> <form name="login" method="post" action=""> <tr> <td> <th scope="col"><strong>STAFF UPDATE AREA</strong></th> </td> </tr> <tr> <td> STAFF ID <th scope="col"><input name="staff_id" type="text" value="<?php echo $row['staff_id']; ?>" disabled="disabled" /></th> </td> </tr> <tr> <td> BASIC SALARY<th scope="col"><input name="basic" type="text" value="<?php echo $row['basic']; ?>" /></th> </td> </tr> <tr> <td> RENT <th scope="col"><input name="rent" type="text" value="<?php echo $rent; ?>" /></th> </td> </tr> <tr> <td> PENSION <th scope="col"><input name="pension" type="text" value="<?php echo $pension; ?>" /></th> </td> </tr> <tr> <td> UNION <th scope="col"><input name="union" type="text" value="<?php echo $union; ?>" /></th> </td> </tr> <tr> <td> TAX <th scope="col"><input name="tax" type="text" value="<?php echo $tax; ?>" /></th> </td> </tr> <tr> <td> NET <th scope="col"><input name="net" type="text" value="<?php echo $net; ?>" /></th> </td> </tr> <tr> <td> GROSS <th scope="col"><input name="gross" type="text" value="<?php echo $gross; ?>" /></th> </td> </tr> <tr> <td> <th scope="col"><input name="submit" type="submit" value="Update_Salary" /></th> </td> </tr> </form> </table> </p> </div> <div class="footer"></div> </div> <div class="post"> <div class="header"> <?php require_once("includes/footer.php");?> The funny thing now is that when I press the submit button, nothing happens. Except for the display of what is in the database. Similar TutorialsHello guys, I have these lines of code echo $_POST['uteamid']; $iddquery1 = mysql_query("Select Driver_ID from Driver where Driver_Name='".$temp."'"); $result = mysql_fetch_assoc($iddquery1); $idquery2 =mysql_query("Select Driver_ID from Driver where Driver_Name='".$_POST['DriverSubst']."'"); $resultidquery2 = mysql_fetch_assoc($idquery2); $replaceid = $result['Driver_ID']; echo $replaceid; $updatequery2 = "Update Team_Driver SET Driver_ID = '".$resultidquery2['Driver_ID']."' where UTeam_ID='".$_POST['uteamid']."' and Driver_ID='".$replaceid."'"; echo $updatequery2; Output of the query is: 5 1 Update Team_Driver SET Driver_ID = '2' where UTeam_ID='5' and Driver_ID='' Why is that last Driver_ID = null? wen it should be 1..and its echoing 1 right before that line. Any help will be appreciated Good morning. I am looking fo some help with an update script to update all rows in a table. This is what I have for a form and all looks well. form.php <?php // run the query and put the results in an array variable called $result $result = mysql_query("SELECT * FROM table ORDER BY 'id', 'title', 'text', 'number'"); print "<form method='post' action='update.php'> <table width='100%' border='0' cellspacing='1' cellpadding='1'><tr> <td align='center'><strong>ID</strong></td> <td align='center'><strong>Title</strong></td> <td align='center'><strong>text</strong></td> <td align='center'><strong>Number</strong></td> </tr>\n"; // start a loop to print all of the courses with their book information // the mysql_fetch_array function puts each record into an array. each time it is called, it moves the array counter up until there are no more records left while ($Update = mysql_fetch_array($result)) { // start displaying the info; the most important part is to make the name an array (notice bookinfo[$i]) print "<td align='center'><p>{$Update['id']}</p></td>\n"; print "<td align='center'><input type='text' name='title' value='{$Update['title']}' /></td>"; print "<td align='center'><input type='text' size='40' name='text' value='{$Update['text']}' /></td>\n"; print "<td align='center'><input type='text' size='40' name='number' value='{$Update['number']}' /></td>\n"; print "</tr>\n"; // add 1 to the count, close the loop, close the form, and the mysql connection } print "<tr> <td colspan='4' align='center'><input type='submit' value='submit' />"; print "</td> </tr> </table> </td> </tr> </form> </table>"; print "</tr>\n"; ?><br /><br /> My question is. How do I update this info into the database with the proper info. ie. Update.php? Hi, long story short a webhost has renewed my hosting for 12 months even though my auto renewal was OFF and I did not authorise a renewal, despite the fact I had not even used the hosting for ~8 months, so clearly I was not interested in renewing.. but they are money grabbing and are ignoring my emails and just copy and paste their "cancellation policy" which is ridiculous.
So seeing as they aren't cancelling my account, I want to make a PHP script to fully maximize the server resources. An infinite loop of whatever uses the most memory/cpu/network so they will CANCEL my account. Can anyone help? What is the best way to waste/maximize/slow down a web server? I would appreciate any help.
Thanks! Hi i have this upload script which works fine it uploads image to a specified folder and sends the the details to the database. but now i am trying to instead make a modify script which is Update set so i tried to change insert to update but didnt work can someone help me out please this my insert image script which works fine but want to change to modify instead Code: [Select] <?php mysql_connect("localhost", "root", "") or die(mysql_error()) ; mysql_select_db("upload") or die(mysql_error()) ; // my file the name of the input area on the form type is the extension of the file //echo $_FILES["myfile"]["type"]; //myfile is the name of the input area on the form $name = $_FILES["image"] ["name"]; // name of the file $type = $_FILES["image"]["type"]; //type of the file $size = $_FILES["image"]["size"]; //the size of the file $temp = $_FILES["image"]["tmp_name"];//temporary file location when click upload it temporary stores on the computer and gives it a temporary name $error =array(); // this an empty array where you can then call on all of the error messages $allowed_exts = array('jpg', 'jpeg', 'png', 'gif'); // array with the following extension name values $image_type = array('image/jpg', 'image/jpeg', 'image/png', 'image/gif'); // array with the following image type values $location = 'images/'; //location of the file or directory where the file will be stored $appendic_name = "news".$name;//this append the word [news] before the name so the image would be news[nameofimage].gif // substr counts the number of carachters and then you the specify how how many you letters you want to cut off from the beginning of the word example drivers.jpg it would cut off dri, and would display vers.jpg //echo $extension = substr($name, 3); //using both substr and strpos, strpos it will delete anything before the dot in this case it finds the dot on the $name file deletes and + 1 says read after the last letter you delete because you want to display the letters after the dot. if remove the +1 it will display .gif which what we want is just gif $extension = strtolower(substr($name, strpos ($name, '.') +1));//strlower turn the extension non capital in case extension is capital example JPG will strtolower will make jpg // another way of doing is with explode // $image_ext strtolower(end(explode('.',$name))); will explode from where you want in this case from the dot adn end will display from the end after the explode $myfile = $_POST["myfile"]; if (isset($image)) // if you choose a file name do the if bellow { // if extension is not equal to any of the variables in the array $allowed_exts error appears if(in_array($extension, $allowed_exts) === false ) { $error[] = 'Extension not allowed! gif, jpg, jpeg, png only<br />'; // if no errror read next if line } // if file type is not equal to any of the variables in array $image_type error appears if(in_array($type, $image_type) === false) { $error[] = 'Type of file not allowed! only images allowed<br />'; } // if file bigger than the number bellow error message if($size > 2097152) { $error[] = 'File size must be under 2MB!'; } // check if folder exist in the server if(!file_exists ($location)) { $error[] = 'No directory ' . $location. ' on the server Please create a folder ' .$location; } } // if no error found do the move upload function if (empty($error)){ if (move_uploaded_file($temp, $location .$appendic_name)) { // insert data into database first are the field name teh values are the variables you want to insert into those fields appendic is the new name of the image mysql_query("INSERT INTO image (myfile ,image) VALUES ('$myfile', '$appendic_name')") ; exit(); } } else { foreach ($error as $error) { echo $error; } } //echo $type; ?> Hi Guys, first time poster, so I hope I have it in the right category. I've used a program called Training Peaks for years, great program and it does cost a few $$'s. I'm also going through the Php MySQL learning curve and thought why not build something basic that I could use rather than TP. I've been dabbling with php/mysql for a few years, nothing serious and have been looking at a few core calendar codes like Ajax, Lavarel and one built on html5. I was curious with your knowledge what might be the best way to look at this project (attachment). In a nut shell the option to create a session (training session) it this case, it for Triathlon (swim, bike & run) ability to set a session time, date, distance and maybe some notes. TP has a lot more data that feeds from Garmin data, that's a bit over my head at the moment, so ignore TSS IF's etc The attachment is the calendar in the back ground with the individual session open, again a lot more data there than what I need. Google calendar was an option, but why not make it fun and learn something! Thanks in advance.
I'm looking for a random number generator, that chooses a number every hour, and when it does it will be out of 100 (these are player ID's) once the number is chosen, I would like 10 Crystals (special payment) to be given to the number (ID). Is this possible and if so, please help. This is all I have (generator) function createRandomAGTNO() { do { $agt_no = mt_rand(1,100); $valid = true; if (preg_match('/(\d)\1\1/', $agt_no)) $valid = false; // Same digit three times consecutively elseif (preg_match('/(\d).*?\1.*?\1.*?\1/', $agt_no)) $valid = false; // Same digit four times in string } while ($valid === false); return $agt_no; } Please reply ASAP? Please could some1 just point out why this php code is not updating the my-sql db? It displays the content of the db but does not update accordingly.. Code: [Select] <?php include("cn.php"); //$username=$_GET['username']; if (!@$_SESSION['username']){ header("location:Not_Logged.php"); } if (isset($_POST['update'])) { $update=$_GET['update'];} else {$update=0;} if ($update = "1") { $username=$_GET['username']; $id=$_GET['id']; $username=$_POST['username']; $password=$_POST['password']; $select="select * from users where username='$_SESSION[username]'"; $rs_cat=mysqli_query($con,$select); $row=mysqli_fetch_array($rs_cat); $username=$row['username']; $password=$row['password']; $update="UPDATE users SET username='$username', password='$password' where id='$id'"; $ur=mysqli_query($con,$update) or die (mysql_error()); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>UPDATE</title> </head> <body> <?php //echo $_SESSION['username'];?> <table align="center" > <form name="login" action="" method="post"/> <tr> <td> <th scope="col"><strong>UPDATE</strong></th> </td> </tr> <tr> <td> USERNAME <th scope="col"><input name="username" type="text" value="<?php echo ("$row[username]");?>"/></th> </td> </tr> <tr> <td> PASSWORD <th scope="col"><input name="password" type="password" value="<?php echo ("$row[password]");?>" /></th> </td> </tr> <tr> <td> <th scope="col"><input name="update" type="submit" value="UPDATE" /></th> </td> </tr> <tr> <td> <th scope="col"><input name="id" type="hidden" value="<?php echo $row[id];?>" /></th> </td> </form> </table> </body> </html> Any sharp locator would be appreciated... I plan to be releasing some scripts and will update the version of the script on my website. Users will be able to download the script and run it on there website. The latest version will be checked by checking my website and compared with the version of the user's script to see if its out of date. I can't get it to work correctly. On http://www.phpfusionmods.com/updates/check.php I have the latest version set to 1.4. In the script the version is set at 1.3 so its obviously out of date. However, its showing that its up to date. Please offer your support. My script is below. <?php $version = "1.3"; function new_version() { $url = "http://www.phpfusionmods.com/updates/check.php"; $url_p = @parse_url($url); $host = $url_p['host']; $port = isset($url_p['port']) ? $url_p['port'] : 80; $fp = @fsockopen($url_p['host'], $port, $errno, $errstr, 5); if (!$fp) return false; @fputs($fp, 'GET ' . $url_p['path'] . ' HTTP/1.1' . chr(10)); @fputs($fp, 'HOST: ' . $url_p['host'] . chr(10)); @fputs($fp, 'Connection: close' . chr(10) . chr(10)); $response = @fgets($fp, 1024); $content = @fread($fp, 1024); $content = preg_replace("#(.*?)text/plain(.*?)$#is", "$2", $content); @fclose($fp); if (preg_match("#404#", $response)) return "Timeout"; else return trim(str_replace("X-Pad: avoid browser bug", "", $content)); } $newversion = str_replace("X-Pad: avoid browser bug", "", new_version()); $new_version = $newversion != "Timeout" && intval(str_replace(".", "", $newversion)) > intval(str_replace(".", "", $version)) ? true : false; if ($new_version) { echo "Download the latest version <a href='http://www.phpfusionmods.com/' target='_blank'>here</a>. <b>v" . str_replace("X-Pad: avoid browser bug", "", $newversion) . "</b>"; } elseif ($newversion == "Timeout") { echo "PHPFusionMods.com has timed out. Check for updates <a href='http://www.phpfusionmods.com/' target='_blank'>here</a>."; } else { echo ("You have the latest version"); } ?> Having trouble with this upload script, it grabs and displays the content from the database fine. It won't however update the database although the code is throwing up no errors; this is the script that displays the content Code: [Select] ############### Code <?php include("includes/connection.php"); $sql="SELECT * FROM mot"; $result=mysql_query($sql); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <td> <table width="400" border="1" cellspacing="0" cellpadding="3"> <tr> <td colspan="4"><strong>List data from mysql </strong> </td> </tr> <tr> <td align="center"><strong>Name</strong></td> <td align="center"><strong>Lastname</strong></td> <td align="center"><strong>Update</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td><? echo $rows['header']; ?></td> <td><? echo $rows['content']; ?></td> // link to update.php and send value of id <td align="center"><a href="update_content.php?id=<? echo $rows['id']; ?>">update</a></td> </tr> <?php } ?> </table> </td> </tr> </table> this next bit of code is the code that user updates the content; Code: [Select] <?php include("includes/connection.php"); $id=$_GET['id']; $sql="SELECT * FROM mot WHERE id='$id'"; $result=mysql_query($sql); $rows=mysql_fetch_array($result); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <form name="form1" method="post" action="update_ac.php"> <td> <table width="100%" border="0" cellspacing="1" cellpadding="0"> <tr> <td> </td> <td colspan="3"><strong>Update data in mysql</strong> </td> </tr> <tr> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> </tr> <tr> <td align="center"> </td> <td align="center"><strong>Name</strong></td> <td align="center"><strong>Lastname</strong></td> </tr> <tr> <td> </td> <td align="center"><input name="name" type="text" id="name" value="<? echo $rows['header']; ?>"></td> <td align="center"><input name="lastname" type="text" id="lastname" value="<? echo $rows['content']; ?>" size="15"></td> </tr> <tr> <td> </td> <td><input name="id" type="hidden" id="id" value="<? echo $rows['id']; ?>"></td> <td align="center"><input type="submit" name="Submit" value="Submit"></td> <td> </td> </tr> </table> </td> </form> </tr> </table> this final bit is the update code for the database which isnt working but not throwing up any errors Code: [Select] <?php include("includes/connection.php"); if(isset($_POST['update'])){ $id = $_GET['id']; $header = $_POST['header']; $content = $_POST['content']; $sql="UPDATE mot SET header = '$header', content = '$content' WHERE id='$id'"; $result=mysql_query($sql); if($result){ echo "Successful"; echo "<BR>"; echo "<a href='mot_edit.php'> View result</a>"; } else { echo "ERROR"; } } ?> Any help would be much appreciated Hi
i've got a script to migrate some tables.
This is most of it.. just missing the db connection (not needed here)
$link = mysql_connect($host,$user,$pass) or die(mysql_error());
mysql_selectdb($db,$link) or die(mysql_error());
$ag_forums_to_kunena_categories = array();
mysql_query("TRUNCATE bzhv8_kunena_messages");
mysql_query("TRUNCATE bzhv8_kunena_messages_text");
$sql = "
SELECT
p.id AS messages_id,
u.name AS messages_name,
a.jos_id AS messages_userid,
p.message AS messages_text_message,
p.posted AS messages_time,
p.edited AS messages_modified_time,
p.edited_by AS messages_modified_by,
p.topic_id AS messages_thread,
t.forum_id AS messages_catid
FROM jos_agora_posts AS p
LEFT JOIN jos_agora_users AS a ON a.username = p.poster
LEFT JOIN jos_agora_topics AS t ON t.id = p.topic_id
LEFT JOIN bzhv8_users AS u ON u.id = a.jos_id
ORDER BY p.id ASC
";
$res = mysql_query($sql) or die(mysql_error());
while ($row = mysql_fetch_object($res))
{
echo $row->messages_id;
//echo "<br />";
//echo $row->messages_name;
//echo "<br />";
//echo $row->messages_userid;
//echo "<br />";
//echo $row->messages_text_message;
//echo "<br />";
//echo $row->messages_time;
//echo "<br />";
//echo $row->messages_modified_time;
//echo "<br />";
//echo $row->messages_modified_by;
//echo "<br />";
//echo $row->messages_thread;
//echo "<br />";
//echo $row->messages_catid;
//echo "<br />";
//if($row->messages_userid == '')
//echo "userid er nul";
//{
// $row->messages_userid = 0;
//}
$cat_id = $ag_forums_to_kunena_categories[$row->messages_catid];
if ($cat_id != 0)
{
echo $cat_id;
echo "kategori id";
echo "<br />";
echo "lige før den skal indsætte";
$sql = "INSERT INTO `bzhv8_kunena_messages` VALUES (".$row->messages_id.", 0, ".$row->messages_thread.", ".$cat_id.", '".$row->messages_name."', ".$row->messages_userid.", '', '', ".$row->messages_time.", NULL, 0, 0, 0, 0, 0, 0, 0, 0, '')";
echo "her bør den køre sql(1)";
$sql2 = "INSERT INTO `bzhv8_kunena_messages_text` VALUES (".$row->messages_id.", '".mysql_escape_string($row->messages_text_message)."')";
echo $sql;
echo "lige efter anden insert echo sql";
echo "<br />";
echo $sql2;
echo "<br />";
echo "her skulle den vise anden insert";
mysql_query($sql) or die(mysql_error());
mysql_query($sql2) or die(mysql_error());
}
else
{
}
}
mysql_close();
But something is not working..
first.. ignore the echo's of course.. just me trying to debug.. same with the else statement...
from what I can tell.. and my php knowledge is non-existant.. this part:
$cat_id = $ag_forums_to_kunena_categories[$row->messages_catid];
it what's causing the problem.. it appears that the $cat_id is not getting any data..
if copy the sql line and run it against my database via phpmyadmin then it works as it should.. but well.. something isn't right..
there are some other stuff in the script that does the same as the above.. but with different tables and they work just fine..
example:
mysql_query("TRUNCATE bzhv8_kunena_topics");
$sql = "
SELECT
t.id AS topic_id,
t.poster AS topic_poster,
t.subject AS topic_subject,
t.posted AS topic_first_post_time,
t.last_post AS topic_last_post_time,
t.last_post_id AS topic_last_post_id,
t.last_poster AS topic_last_poster,
t.num_views AS topic_hits,
t.num_replies AS topic_posts,
t.closed AS topic_locked,
t.sticky AS topic_hold,
t.moved_to AS topic_moved_id,
t.forum_id AS topic_category_id,
t.question AS topic_poll_id,
p.id AS topic_first_post_id,
p.posted AS topic_first_post_time,
a.jos_id AS topic_first_post_userid,
p.message AS topic_first_post_message
FROM jos_agora_topics AS t
LEFT JOIN jos_agora_users AS a ON a.username = t.poster
LEFT JOIN jos_agora_posts AS p ON t.posted = p.posted
ORDER BY t.id ASC
";
$res = mysql_query($sql) or die(mysql_error());
while ($row = mysql_fetch_object($res))
{
echo $row->topic_id;
echo "<br />";
if($row->topic_first_post_userid == '')
{
$row->topic_first_post_userid = 0;
}
$cat_id = $ag_forums_to_kunena_categories[$row->topic_category_id];
echo $cat_id;
echo "<br />";
$sql = "INSERT INTO `bzhv8_kunena_topics` VALUES (".$row->topic_id.", ".$cat_id.", '".mysql_escape_string($row->topic_subject)."', 0, ".$row->topic_locked.", ".$row->topic_hold.", 0, ".$row->topic_posts.", ".$row->topic_hits.", 0, 0, 0, ".$row->topic_first_post_id.", ".$row->topic_first_post_time.", ".$row->topic_first_post_userid.", '".mysql_escape_string($row->topic_first_post_message)."', NULL, ".$row->topic_last_post_id.", ".$row->topic_last_post_time.", 0, NULL, NULL, '')";
echo $sql;
echo "<br />";
mysql_query($sql) or die(mysql_error());
}
the above works fine..
Can someone take a look and give a hint or 2.. or just point at whatever the solution is :-)
OK I have no idea why this will not update the table but here is the code I wrote. I just can't see it Code: [Select] <?php //CONNECT TO DATABASE include("sharons_dbinfo.inc.php"); mysql_connect(localhost,$user,$password); mysql_select_db($database) or die( "Unable to select database"); //OPEN THE ZIP FILE $handle = gzopen('Newegg_com-Daily_Deals_Feed.txt.gz', 'r'); //READ THE WHOLE FILE LINE BY LINE while (!gzeof($handle)) { $buffer = gzgets($handle, 4096); $buffer = str_replace("'" , "" , $buffer); $buffer = str_replace("\"" , "" , $buffer); $data = explode(",", $buffer); //SKIP THE FIRST LINE OF COLUMN NAMES if ($data[4] == "NAME"){} else{ //PUT THIS IN TO MAKE SURE IT WAS LOOKING FOR THE RIGHT RECORD print "Looking for: ". $data['4'] . " to update with new date " . $data['3']."<br>"; $item_name = $data['4']; //QUERY THE TABLE FOR PRODUCT NAME FROM ZIP FILE $query = ("SELECT * FROM `computer_memory` WHERE `NAME` = '$item_name'"); $results = mysql_query($query) or die(mysql_error()."<br /><br />".$query); $result = mysql_fetch_array($results); $num=mysql_numrows($results); //IF THE NAME EXISTS PROCEED TO UPDATE THE RECORD WITH THE NEW INFORMATION if ($num >0) { //UPDATE TABLE WITH THE NEW INFORMATION $update = ("UPDATE `computer_memory` SET `PROGRAMNAME`= '$data[0]', `PROGRAMURL`= '$data[1]', `CATALOGNAME`= '$data[2]', `LASTUPDATED`= '$data[3]', `NAME`= '$data[4]', `KEYWORDS`= '$data[5]', `DESCRIPTION`= '$data[6]', `SKU`= '$data[7]', `MANUFACTURER`= '$data[8]', `MANUFACTURERID`= '$data[9]', `UPC`= '$data[10]', `ISBN`= '$data[11]', `CURRENCY`= '$data[12]', `SALEPRICE`= '$data[13]', `PRICE`= '$data[14]', `RETAILPRICE`= '$data[15]', `FROMPRICE`= '$data[16]', `BUYURL`= '$data[17]', `IMPRESSIONURL`= '$data[18]', `IMAGEURL`= '$data[19]', `ADVERTISERCATEGORY`= '$data[20]', `THIRDPARTYID`= '$data[21]', `THIRDPARTYCATEGORY`= '$data[22]', `AUTHOR`= '$data[23]', `ARTIST`= '$data[24]', `TITLE`= '$data[25]', `PUBLISHER`= '$data[26]', `LABEL`= '$data[27]', `FORMAT`= '$data[28]', `SPECIAL`= '$data[29]', `GIFT`= '$data[30]', `PROMOTIONALTEXT`= '$data[31]', `STARTDATE`= '$data[32]', `ENDDATE`= '$data[33]', `OFFLINE`= '$data[34]', `ONLINE`= '$data[35]', `INSTOCK`= '$data[36]', `CONDITION`= '$data[37]', `WARRANTY`= '$data[38]', `STANDARDSHIPPINGCOST`= '$data[39]' WHERE `ID`= '$id'"); mysql_query($update) or die(mysql_error()."<br /><br />".$update); //if ($update){print "UPDATED ".$result['ID'];} }else{ //IF THE NAME DID NOT EXIST INSERT A NEW RECORD INTO THE TABLE $import="INSERT into computer_memory (`ID`,`PROGRAMNAME`,`PROGRAMURL`,`CATALOGNAME`,`LASTUPDATED`,`NAME`,`KEYWORDS`,`DESCRIPTION`,`SKU`,`MANUFACTURER`,`MANUFACTURERID`,`UPC`,`ISBN`,`CURRENCY`,`SALEPRICE`,`PRICE`,`RETAILPRICE`,`FROMPRICE`,`BUYURL`,`IMPRESSIONURL`,`IMAGEURL`,`ADVERTISERCATEGORY`,`THIRDPARTYID`,`THIRDPARTYCATEGORY`,`AUTHOR`,`ARTIST`,`TITLE`,`PUBLISHER`,`LABEL`,`FORMAT`,`SPECIAL`,`GIFT`,`PROMOTIONALTEXT`,`STARTDATE`,`ENDDATE`,`OFFLINE`,`ONLINE`,`INSTOCK`,`CONDITION`,`WARRANTY`,`STANDARDSHIPPINGCOST`) values('','$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]','$data[7]','$data[8]','$data[9]','$data[10]','$data[11]','$data[12]','$data[13]','$data[14]','$data[15]','$data[16]','$data[17]','$data[18]','$data[19]','$data[20]','$data[21]','$data[22]','$data[23]','$data[24]','$data[25]','$data[26]','$data[27]','$data[28]','$data[29]','$data[30]','$data[31]','$data[32]','$data[33]','$data[34]','$data[35]','$data[36]','$data[37]','$data[38]','$data[39]')"; mysql_query($import) or die(mysql_error()); } } } gzclose($handle); ?> I hope someone can see what I can't Thanks everyone I am attempting to update selected records using '$row[' elements in where clauses. I recieve message 'Record Updated but when I check data base it hasn't changed. CODE: $query = "SELECT cr_num, cr_ci_num, cr_dte, cr_flag, ci_desc, ci_authority, ce_name, ce_email, ce_phone_ext FROM c_record, c_info, c_employee WHERE cr_num = ce_num AND cr_ci_num = ci_num AND cr_dte > '{$dte60}' and cr_dte <= '{$dte90}' AND cr_flag = '00'"; $result = mysqli_query($dbc, $query) or die('ERROR querying database'); while($row = mysqli_fetch_array($result)) { $query = "UPDATE c_record SET cr_flag = '90' WHERE cr_num = '{$row[cr_num]}' AND cr_ci_num = '{$row[cr_ci_num]}'" or die('ERROR UPDATE'); echo 'Update succesfull'; echo "<br />\n" I have a script to let the user update their password, when I submit it i get a 500 error and I'm not sure. Here is the code: If (isset($_POST['update-password'])) { //This makes sure they did not leave any fields blank if (!$_POST['oldpw'] || !$_POST['pass'] || !$_POST['pass2'] ) { $error="<span style="; $error .="color:red"; $error .=">"; $error .= "You did not complete all of the required fields"; $error .="</span>"; setcookie('Errors', $error, time()+20); header('Location /useredit.php'); exit; } // checks if the password is correct $pass = md5($_POST['pass']); if (!get_magic_quotes_gpc()) { $pass = addslashes($pass); } $check = mysql_real_escape_string("SELECT * FROM YBK_Login WHERE pass = '{$pass}'"); mysql_query($check) or die( 'Query string: ' . $check . '<br />Produced an error: ' . mysql_error() . '<br />' ); // this makes sure both passwords entered match if ($_POST['pass'] != $_POST['pass2']) { $error="<span style="; $error .="color:red"; $error .=">"; $error .= 'Your passwords did not match.'; $error .="</span>"; setcookie('Errors', $error, time()+20); header('Location: /useredit.php'); exit; } // here we encrypt the password and add slashes if needed $_POST['pass'] = md5($_POST['pass']); if (!get_magic_quotes_gpc()) { $_POST['pass'] = addslashes($_POST['pass']); $_POST['pass2'] = addslashes($_POST['pass2']); } // now we insert it into the database mysql_real_escape_string($insert = "UPDATE `YBK_Login` SET `pass` = '{$_POST['pass']}', `HR` = '{$_POST['pass2']}', `comment` = '{$_POST['oldpw']}' WHERE `ID` = {$_COOKIE['UID_WatsonN']}"); mysql_query($insert) or die( 'Query string: ' . $insert . '<br />Produced an error: ' . mysql_error() . '<br />' ); $error="<span style="; $error .="color:green"; $error .=">"; $error .= "<p>Thank you, your password has been updated.</p>"; $error .="</span>"; setcookie('Errors', $error, time()+20); header('Location: /useredit.php'); exit; } Hi, Im just in the middle of creating an update script for my mysql database but don't know why it's not working. p.s. I'm a little new to PHP, but know quite a bit, it's probably something really small.. *facepalm* Here's the script: the form (update.php) <? // Connect to the database $link = mysql_connect('###', '###', '###'); if (!$link) { die('Could not connect: ' . mysql_error()); } mysql_select_db('###', $link); $id = $_GET['id']; // Ask the database for the information from the links table $query="SELECT * FROM orders WHERE id='$id'"; $result = mysql_query("SELECT * FROM orders"); $num=mysql_numrows($result); mysql_close(); $i=0; while ($i < $num) { $name=mysql_result($result,$i,"Name"); $location=mysql_result($result,$i,"Location"); $fault=mysql_result($result,$i,"Fault"); ?> <form action="updated.php" method="post"> <input type="hidden" name="ud_id" value="<? echo "$id";?>"> Name: <input type="text" name="ud_name" value="<? echo "$name"?>"><br> Location: <input type="text" name="ud_location" value="<? echo "$location"?>"><br> Fault: <input type="text" name="ud_fault" value="<? echo "$fault"?>"><br> <input type="Submit" value="Update"> </form> <? ++$i; } ?> ------------------------------------------------------ (processor) updated.php <?php // Connect to the database $link = mysql_connect('###', '###', '###'); if (!$link) { die('Could not connect: ' . mysql_error()); } mysql_select_db('###', $link); $query="UPDATE orders SET Name='" . $_POST['ud_name'] . "', Location='" . $_POST['ud_location'] . "', Fault='" . $_POST['ud_fault'] . "' WHERE $id='" . $_POST['ud_id'] . "'"; echo $query; $checkresult = mysql_query($query); if ($checkresult) echo '<p>update query succeeded'; else echo '<p>update query failed'; mysql_close(); ?> ------------------------------------------------------ Every time I want to update, it comes up with: UPDATE orders SET Name='TEST', Location='TEST', fault='jbjh' WHERE ='' update query failed Any help would be appreciated. Hello, Ive got a fairly successful website and im looking at cloning it, I want to set up a cron to check the main site if there are any new posts and if there are insert it into the DB. Ive got them on 2 separate hosts so i don't want to just read from the DB increase the main site goes down and brings the whole 2nd site down. What would be the easiest way to do it? Not looking for people to give code, Just their suggestions. Cheers I am moving my website to a new Service Provider. The script I use for multiple updating worked on the older server but not on the new one. It shows the information but does not update the records. Any help would be greatly appreciated. Old Server : PHP 5.2.11 MYSQL: 5.0.92-community New Server : PHP 5.2.17 MYSQL: 5.1.47-community Script: <?php include("head.php"); $host="localhost"; // Host name $username="xxxxxxx"; // Mysql username $password="xxxxxxx"; // Mysql password $db_name="xxxxxxx"; // Database name $tbl_name="xxxxxxx"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name limit 20"; $result=mysql_query($sql); // Count table rows $count=mysql_num_rows($result); ?> <title>PowerMan South Africa</title> <META HTTP-EQUIV="Pragma" CONTENT="no-cache"> <META HTTP-EQUIV="Expires" CONTENT="-1"> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <link rel="stylesheet" href="style.css" type="text/css" media="screen" /> <style type="text/css" media="screen,projection"> @import url(calendar.css); </style> </head> <table width="500" border="0" cellspacing="1" cellpadding="0"> <form name="form1" method="post" action=""> <tr> <td> <table width="500" border="0" cellspacing="1" cellpadding="0"> <tr> <td align="center"><strong>ID</strong></td> <td align="center"><strong>Company</strong></td> <td align="center"><strong>contact</strong></td> <td align="center"><strong>Email</strong></td> <td align="center"><strong>Telephone</strong></td> <td align="center"><strong>Type</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td align="center"><? $id[]=$rows['id']; ?><? echo $rows['id']; ?></td> <td align="center"><input name="company[]" type="text" id="company" value="<? echo $rows['company']; ?>"></td> <td align="center"><input name="contact[]" type="text" id="contact" value="<? echo $rows['contact']; ?>"></td> <td align="center"><input name="email[]" type="text" id="email" value="<? echo $rows['email']; ?>"></td> <td align="center"><input name="telephone[]" type="text" id="telephone" value="<? echo $rows['telephone']; ?>"></td> <td align="center"><input name="type[]" type="text" id="type" value="<? echo $rows['type']; ?>"></td> </tr> <?php } ?> <tr> <td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td> </tr> </table> </td> </tr> </form> </table> <?php // Check if button name "Submit" is active, do this if($Submit){ for($i=0;$i<$count;$i++){ $sql1="UPDATE $tbl_name SET company='$company[$i]', contact='$contact[$i]', email='$email[$i]',type='$type[$i]', telephone='$telephone[$i]' WHERE id='$id[$i]'"; $result1=mysql_query($sql1); } } if($result1){ header("location:update_multiple.php"); echo "<meta http-equiv=Refresh content=0;url=update_multiple.php>"; } mysql_close(); ?> Hey all. I've created a script that updates a website's config in a database. The script itself works fine but I feel it is rather uncanny. Where can I look to find better methods of achieving what I'm trying to accomplish? Here's my script that updates my table with columns id, showlogin, colorscheme, blogmenu, aboutus. I explain the script below it. if (isset($_POST['submit'])) { // id will always be 1 and only query if only submit was pressed $sql = "UPDATE config SET id=1"; // showlogin values are 1 for show login form and 2 for don't if(!empty($_POST['showlogin'])) { $showlogin = $_POST['showlogin']; $sql .= ", showlogin='$showlogin'"; } if(!empty($_POST['colorscheme'])) { $colorscheme = $_POST['colorscheme']; $sql .= ", colorscheme='$colorscheme'"; } if(!empty($_POST['blogmenu'])) { $blogmenu = $_POST['blogmenu']; $sql .= ", blogmenu='$blogmenu'"; } else { $sql .= ", blogmenu=2"; } if(!empty($_POST['aboutus'])) { $aboutus = $_POST['aboutus']; $sql .= ", aboutus='$aboutus'"; } else { $sql .= ", aboutus=2"; } mysql_query($sql, $connect) or die (mysql_error()); } It works like this. I have a form with a few selects and checkboxes. The selects are the colorscheme and showlogin. The checkboxes are blogmenu and about us, both defaulting to the number 2 if they are not checked. 1 means show this item on the live site and 2 means do not show. This is pulled out of the database on page loads. So, I hope I was clear as my mind is spaghetti right now. Cheers! Hello, I am trying to pick up php again and just exercising my skills. So I have it so that it fills my form with the values of what I want to edit, and when I click the edit button, it doesn't edit any of the information. When I echo out $result, I get a MYSQL query string that has the same values as the table, so its not getting the new values that are edited. <?php @mysql_connect('localhost', 'root', '') or die("Could not connect to Mysql Server. " . mysql_error()); @mysql_select_db('tutorials') or die("Could not connect to Database. " . mysql_error()); if(isset($_GET['edit'])) { $id = $_GET['edit']; $query = "SELECT `username`, `password` FROM `users` WHERE `id` = '$id'"; $result = mysql_query($query); $row = mysql_fetch_array($result); $name = $row['username']; $password = $row['password']; } if(isset($_POST['edit'])) { $id = $_GET['edit']; $query = "UPDATE `users` SET `username` = '$name', `password` = '$password' WHERE `id` = '$id'"; $result = mysql_query($query); echo $query; if(!$result) { echo mysql_error(); }else{ echo 'updated post'; } } ?> <form method="POST" action="" > <input type="text" name="name" value="<?php echo $name; ?>" /> First name <br /> <input type="text" name="password" value="<?php echo $password; ?>" /> Last name <br /> <input type="submit" name="edit" value="edit" /> </form> I believe it has something to do with the values of $name and $password in the form conflicting with the first if isset and the second if isset. Thanks for any help possible Hi all, As you will see this is my first post in I really hope somebody can nail this for me, as I have been working on this for some time and I cannot get it to work. Basically this is the final part of a CMS I'm building, and all was fine until I needed to build in an option of a multiple image uploader to accompany all other stock details. I have managed to nail the 'insert' part of the multiple image uploader in this case up to 4 images, and the code is below for this part, any help with improvements though will be greatly appreciated. Code: [Select] if(isset($_POST['btnsubmit'])) { $flag=$_POST['flag']; if ($flag==0) { $name=$_POST['txtname']; $desc1=$_POST['e1m1']; $meta=$_POST['txtmeta']; $sr=$_POST['srno1']; $name=$_POST['txtname']; $ref=$_POST['Ref']; $desc=$_POST['e1m1']; $maker=$_POST['Maker']; $date=$_POST['Date']; $weight=$_POST['Weight']; $height=$_POST['Height']; $depth=$_POST['Depth']; $width=$_POST['Width']; $price=$_POST['txtprice']; $sold=$_POST['txtsold']; $active=$_POST['active']; $pcats=$_POST['pcats']; $subcats=$_POST['subcats']; $str_str=''; $p=''; $j=0; for($i=0;$i<=3;$i++){ $j++; $p=$_REQUEST['p$j']; $file=$_FILES['pic']['name'][$i]; if(!empty($file) ){ $str_str.=",pic$j='$file'"; } else if(!empty($p))$str_str.=",pic$j='$p'"; $path1="imgdata/stock/".$file; copy($_FILES['pic']['tmp_name'][$i], $path1); } $q24=mysql_query("update stock set stock_Name='$name', stock_MetaTitle='$meta', parent_Category='$pcats', sub_Category='$subcats', stock_Image='imgdata/stock/$pic[0]', stock_Image2='imgdata/stock/$pic[1]', stock_Image3='imgdata/stock/$pic[2]', stock_Image4='imgdata/stock/$pic[3]', stock_Ref='$ref', stock_Description='$desc1', stock_Maker='$maker', stock_Date='$date', stock_Weight='$weight', stock_Height='$height', stock_Depth='$depth',stock_Width='$width', stock_Price='$price', stock_Sold='$sold', stock_Active='$active', stock_DateTime='$dt2' where stock_Id=$sr") or die (mysql_error()); $flag=1; $conf="Data Updated Successfully - Click <a href='http://www.accendsandbox.co.uk/adminSallam/admin_categories.php'>here</a> to continue"; $update="1"; Code: [Select] <tr> <td bgcolor="#A0B050" width="161"> <div style="font-family:Verdana, Arial, Helvetica, sans-serif; position:relative; font-size:12px; color:#293334; font-weight:bold; position:relative; float:left; left:1px;">Stock Image 1 (Main):</div> </td> <td bgcolor="#888888"> <input type="file" name="pic1[]" id="pic1[]" size="50" /> </td> </tr> <tr> <td bgcolor="#A0B050" width="161"> <div style="font-family:Verdana, Arial, Helvetica, sans-serif; position:relative; font-size:12px; color:#293334; font-weight:bold; position:relative; float:left; left:1px;">Stock Image 2:</div> </td> <td bgcolor="#888888"> <input type="file" name="pic1[]" id="pic1[]" size="50" /> </td> </tr> <tr> <td bgcolor="#A0B050" width="161"> <div style="font-family:Verdana, Arial, Helvetica, sans-serif; position:relative; font-size:12px; color:#293334; font-weight:bold; position:relative; float:left; left:1px;">Stock Image 3:</div> </td> <td bgcolor="#888888"> <input type="file" name="pic1[]" id="pic1[]" size="50" /> </td> </tr> <tr> <td bgcolor="#A0B050" width="161"> <div style="font-family:Verdana, Arial, Helvetica, sans-serif; position:relative; font-size:12px; color:#293334; font-weight:bold; position:relative; float:left; left:1px;">Stock Image 4:</div> </td> <td bgcolor="#888888"> <input type="file" name="pic1[]" id="pic1[]" size="50" /> </td> </tr> <input type="submit" name="btnsubmit" value="Submit"> <input type="submit" name="btndelete" value="Delete" DEFANGED_OnClick="return check();"> <input type="hidden" name="srno1" value="<?= $rows["stock_Id"];?>"> <input type="hidden" name="action" value="Upload"> All seems to be fine above, I can upload 1,2,3 or 4 images and the image goes into the server and the path to the database. But I then needed the option for my client to be able to click to edit a certain stock and then aswel as edit the other details, if he wanted to change one pic, no pics or all 4 he could and when he clicked submit, if there was a new image it would change if not it would stay as it is. So here is my attempt and at the moment it doesnt work, so I'm looking for help of any kid and anything can change. Code: [Select] $name=$_POST['txtname']; $ref=$_POST['Ref']; $desc=$_POST['e1m1']; $maker=$_POST['Maker']; $date=$_POST['Date']; $weight=$_POST['Weight']; $height=$_POST['Height']; $depth=$_POST['Depth']; $width=$_POST['Width']; $price=$_POST['txtprice']; $sold=$_POST['txtsold']; $meta=$_POST['txtmeta']; $active=$_POST['active']; $pcats=$_POST['pcats']; $subcats=$_POST['subcats']; $pic1=''; for($i=0;$i<4;$i++){ if(isset($_FILES['pic1']['name'][$i]))$pic1[$i]=$_FILES['pic1']['name'][$i]; else $pic1[$i]=''; } for($i=0;$i<4;$i++){ if(isset($_FILES['pic1']['name'][$i]))$path1= "./imgdata/stock/".$_FILES['pic1']['name'][$i]; //echo $_FILES['pic1']['tmp_name'][$i]." :". $path1; if(!empty($_FILES['pic1']['name'][$i])&&isset($_FILES['pic1']['name'][$i]))copy($_FILES['pic1']['tmp_name'][$i], $path1); } $q=mysql_query("insert into stock (stock_Name, stock_MetaTitle, parent_Category, sub_Category, stock_Ref, stock_Description, stock_Maker, stock_Date, stock_Weight, stock_Height, stock_Depth, stock_Width, stock_Price, stock_Sold, stock_Image, stock_Image2, stock_Image3, stock_Image4, stock_Active, stock_DateTime) values('$name','$meta','$pcats','$subcats','$ref','$desc','$maker','$date','$weight','$height','$depth','$width','$price','$sold','imgdata/stock/$pic1[0]','imgdata/stock/$pic1[1]','imgdata/stock/$pic1[2]','imgdata/stock/$pic1[3]','$active','$dt2')") or die (mysql_error()); $conf="Data Inserted Successfully - Click <a href='http://www.accendsandbox.co.uk/adminSallam/admin_stock.php'>here</a> to continue"; $update=1; Code: [Select] <tr> <td bgcolor="#A0B050" width="161"> <div style="font-family:Verdana, Arial, Helvetica, sans-serif; position:relative; font-size:12px; color:#293334; font-weight:bold; position:relative; float:left; left:1px;">Stock Image 1 (Main):</div> </td> <td bgcolor="#888888"> <input type="file" name="pic[]" size="50" /> <input type="hidden" name="p1" value="<?php echo $pic1;?>" /> <img src="<?php echo $pic1;?>" height="100px" /> </td> </tr> <tr> <td bgcolor="#A0B050" width="161"> <div style="font-family:Verdana, Arial, Helvetica, sans-serif; position:relative; font-size:12px; color:#293334; font-weight:bold; position:relative; float:left; left:1px;">Stock Image 2:</div> </td> <td bgcolor="#888888"> <input type="file" name="pic[]" size="50" /> <input type="hidden" name="p2" value="<?php echo $pic2;?>" /> <img src="<?php echo $pic2;?>" height="100px" /> </td> </tr> <tr> <td bgcolor="#A0B050" width="161"> <div style="font-family:Verdana, Arial, Helvetica, sans-serif; position:relative; font-size:12px; color:#293334; font-weight:bold; position:relative; float:left; left:1px;">Stock Image 3:</div> </td> <td bgcolor="#888888"> <input type="file" name="pic[]" size="50" /> <input type="hidden" name="p3" value="<?php echo $pic3;?>" /> <img src="<?php echo $pic3;?>" height="100px" /> </td> </tr> <tr> <td bgcolor="#A0B050" width="161"> <div style="font-family:Verdana, Arial, Helvetica, sans-serif; position:relative; font-size:12px; color:#293334; font-weight:bold; position:relative; float:left; left:1px;">Stock Image 4:</div> </td> <td bgcolor="#888888"> <input type="file" name="pic[]" size="50" /> <input type="hidden" name="p4" value="<?php echo $pic4;?>" /> <img src="<?php echo $pic4;?>" height="100px" /> </td> </tr> What happens above as its all on the same page, is when a stock item is selected to be edited the form to update the images changes to the image upload options above, instead of the original ones for a new stock item at the top of this post. I can provide anything you need to help me with this, so please can somebody take a look and see if it can be got working, as its been a long problem for me this. Cheers I have a php script that I've been running that seems to have been working but now I'm wondering if some of my logic is potentially off. I select records from a db table within a date range which I put into an array called ```$validCount``` If that array is not empty, that means I have valid records to update with my values, and if it's empty I just insert. The trick with the insert is that if the ```STORES``` is less than the ```Quantity``` then it only inserts as many as the ```STORES``` otherwise it inserts as many as ```Quantity```. So if a record being inserted with had Stores: 14 Quantity:12
Then it would only insert 12 records but if it had It would only insert 1 record. In short, for each customer I should only ever have as many valid records (within a valid date range) as they have stores. If they have 20 stores, I can have 1 or 2 records but should never have 30. It seems like updating works fine but I'm not sure if it's updating the proper records, though it seems like in some instances it's just inserting too many and not accounting for past updated records. This is the logic I have been working with:
if(!empty($validCount)){
for($i=0; $i<$row2['QUANTITY']; $i++){
try{
$updateRslt = $update->execute($updateParams);
}catch(PDOException $ex){
$out[] = $failedUpdate;
}
}
}else{
if($row2["QUANTITY"] >= $row2["STORES"]){
for($i=0; $i<$row2["STORES"]; $i++){
try{
$insertRslt = $insert->execute($insertParams);
}catch(PDOException $ex){
$out[] = $failedInsertStore;
}
}
}elseif($row2["QUANTITY"] < $row2["STORES"]){
for($i=0; $i<$row2["QUANTITY"]; $i++){
try{
$insertRslt = $insert->execute($insertParams);
}catch(PDOException $ex){
$out[] = $failedInsertQuantity;
}
}
}
}
Let's say customer 123 bought 4 of product A and they have 10 locations
customerNumber | product | category | startDate | expireDate | stores Because they purchased less than their store count, I insert 4 records. Now if my ```$validCheck``` query selects all 4 of those records (since they fall in a valid date range) and my loop sees that the array isn't empty, it knows it needs to update those or insert. Let's say they bought 15 this time. Then I would need to insert 6 records, and then update the expiration date of the other 9 records.
customerNumber | product | category | startDate | expireDate | stores There can only ever be a maximum of 10 (store count) records for that customer and product within the valid date range. As soon as the row count for that customer/product reaches the equivalent of stores, it needs to now go through and update equal to the quantity so now I'm running this but it's not running and no errors, but it just returns back to the command line
$total = $row2['QUANTITY'] + $validCheck;
if ($total < $row2['STORES']) {
$insert_count = $row2['QUANTITY'];
$update_count = 0;
} else {
$insert_count = $row2['STORES'] - $validCheck; // insert enough to fill all stores
$update_count = ($total - $insert_count); // update remainder
}
for($i=0; $i<$row2['QUANTITY']; $i++){
try{
$updateRslt = $update->execute($updateParams);
}catch(PDOException $ex){
$failedUpdate = "UPDATE_FAILED";
print_r($failedUpdate);
$out[] = $failedUpdate;
}
}
for($i=0; $i<$insert_count; $i++){
try{
$insertRslt = $insert->execute($insertParams);
}catch(PDOException $ex){
$failedInsertStore = "INSERT_STORE_FAILED!!!: " . $ex->getMessage();
print_r($failedInsertStore);
$out[] = $failedInsertStore;
}
}```
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