PHP - Function Which Returns Day Of Week Based On Date?
I need to know which day of week was on particular date, so for example I would provide date lets say "Nov 22, 2010" formatted as needed and the function would return "Monday", is there a function in php to do that or how can it be done?
Similar TutorialsI think it is unusual but i dont know to fix it. when my computer clock shows 16: 13 hours , date() reuturns 10:43:16 . My systems time zone is +5.30 GMT. how does date() subtracts 5.30 hrs from the system time? (continuing from topic title) So if I set a date of July 7 2011 into my script, hard coded in, I would like the current date to be checked against the hard coded date, and return true if the current date is within a week leading up to the hard coded date. How could I go about doing this easily? I've been researching dates in php but I can't seem to work out the best way to achieve what I'm after. Cheers Denno Hi, I'm trying to alter the code below. It cuurently finds the start and end date of this week, no matter what day you're on. What I now need is to find the start & end date of next week, again, no matter what day you're on of this week Thanks to aleX_hill for the following code: <?php #THIS WEEK $dayOfWeek = date("w"); #The number of the day of the week. Sun = 0, Sat = 1 $todayDayOfMonth = date("d"); #The day of the month $thisMonth = date("m"); #The number of this month. Jan = 1, Dec = 12 $firstDayOfWeek = $todayDayOfMonth - $dayOfWeek; #The day of the month for the beginning of the week (Sun) if($firstDayOfWeek < 1) #The beginning of the week was in the previous month { $monthBeginWeek = $thisMonth - 1; $firstDayOfWeek = $firstDayOfWeek + date("t",mktime(0,0,0,$monthBeginWeek,1,date("Y"))); } else { $monthBeginWeek = $thisMonth; } $lastDayOfWeek = $todayDayOfMonth + (6 - $dayOfWeek); #Get the day of the month of the end of the week (sat) if($lastDayOfWeek > date("t")) #if the day of the month is larger then the number of days in the month { $monthEndWeek = $thisMonth + 1; $lastDayOfWeek = $lastDayOfWeek - date("t"); #Then take the number of days in the week to get the day number of the next week } else { $monthEndWeek = $thisMonth; } $start_of_week = date("Y-m-d",mktime(0,0,0,$monthBeginWeek,$firstDayOfWeek,date("Y"))); #echo $start_of_week; $end_of_week = date("Y-m-d",mktime(0,0,0,$monthEndWeek,$lastDayOfWeek,date("Y"))); #echo $end_of_week; ?> Any help is much appreciated! TIA Hello, I am writing a CMS for a sports organization league. One of my pages grabs values from the database using only the current week. What I want to do is when the admin enters in a game date, I want it to automatically find the week number for the date they entered. I haven't been able to find anything online that works for me. Any help would be great! Thanks Hi guys! This will seem complex but I really need your help If a have a variable with a date value (i.e. $a = '23/10/2011') How do you work out the week number of that date? Thanks Hi, I have a select box that has every week day as an option. When a user picks "Monday" and submits the form I want to echo the date of monday last week. And if he picks tuesday, I want it to give the date of Tuesday last week, on so on. How would I do that? Thank you in advance! I have the week date range displaying the week range from sunday - saturday
$current_dayname = date("0"); // return sunday monday tuesday etc. echo $date = date("Y-m-d",strtotime('last sunday')).'to'.date("Y-m-d",strtotime("next saturday")); Which outputs in the following format 2015-01-25to2015-01-31 However, when I press next or previous, the dates don't change. <?php $year = (isset($_GET['year'])) ? $_GET['year'] : date("Y"); $week = (isset($_GET['week'])) ? $_GET['week'] : date('W'); if($week > 52) { $year++; $week = 1; } elseif($week < 1) { $year--; $week = 52; } ?> <a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week == 52 ? 1 : 1 + $week).'&year='.($week == 52 ? 1 + $year : $year); ?>">Next Week</a> <!--Next week--> <a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week == 1 ? 52 : $week -1).'&year='.($week == 1 ? $year - 1 : $year); ?>">Pre Week</a> <!--Previous week--> <table border="1px"> <tr> <td>user</td> <?php if($week < 10) { $week = '0'. $week; } for($day= 1; $day <= 7; $day++) { $d = strtotime($year ."W". $week . $day); echo "<td>". date('l', $d) ."<br>". date('d M', $d) ."</td>"; } ?> </tr> </table> Hi Guys.. How can I change a date on the fly ? Everything is UTC on my server. How can I change a date to something else on the fly? Ie: $timezone = "cet"; $datetime = "2011-09-04 19:53:00"; echo $datetime($timezone); So I can give it a datetime and have it echo the datetime as if it were in the other timezone? Thanks Graham Hello I am on to OOP now and I dont know how to write the syntax to print the results I want The scenario is I have the abstract class, its subclass and then the object that calls the subclass, all in different files. So: part of the subclass reads: Code: [Select] function __construct($v1, $v2, $v3) { $this->speed[] = $v1; // I dont like this either, it is not elegant. I tried to put an array as argument of the constructor and send the parameters $this->speed[] = $v2; // from the object being created, but it did not work, so I leave it like this for now, but I would have preferred to put that $this->speed[] = $v3; // array and then populate it by some looping. } // METHOD TO REPORT TABLE OF ACCELERATION public function acceleration() { return $this->acceleration1 = ($this->speed[1] - $this->speed[0])/5; // I actually need to return the other two speed differences from the other stages, but as you know, once the first return acts, it exits the function // so sure this "return" has to be abandoned and the results of the function have to be printed otherwise. That is the question. } =================================== And now from the Object file I am trying to call the function, but of course, I only get one value, even if I write 3 times return Code: [Select] $objeto = new Motorbike($v1, $v2, $v3); echo '<p>The speeds are ' . $objeto->acceleration() . '</p>'; // Yes, this call works, of course, but that is about it. I cant print any other result. Thanks a lot How can I check if a function has returned false.. I know theirs the following way: if (!checkdate($month, $day, $year)) { //the function has returned false } But is their another way (beside using the ! operator) perhaps === FALSE (not sure if that'd work so asking)? Hi! For all my queries I use safe_query() and this function returns mysql_query() Now I want to count how many queries is being returned in this function... can someone modify the code and assign a variable to return max returns please? I would be grateful, thanks! Code: [Select] // -- MYSQL QUERY FUNCTION -- // $_mysql_querys = array(); function safe_query($query="") { global $_mysql_querys; if(stristr(str_replace(' ', '', $query), "unionselect")===FALSE AND stristr(str_replace(' ', '', $query), "union(select")===FALSE){ $_mysql_querys[] = $query; if(empty($query)) return false; if(DEBUG == "OFF") $result = mysql_query($query) or die('Query failed!'); else { $result = mysql_query($query) or die('Query failed: ' .'<li>errorno='.mysql_errno() .'<li>error='.mysql_error() .'<li>query='.$query); } return $result; } else die(); } ok so this problem has been laughing at me for quite some time now I tryed using some inline php in a form to pass it to my login script. The problem is that whenever the form gets submitted the variable r doesn't contain the actual microtime but it contains the inline php as a string: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Snitch</title> <link rel="stylesheet" type="text/css" href="templates/css/snitch1440x900.css" /> </head> <body> <div id="login-achtergrond"> <div id="login"> <form action="." id="loginform" name="login" method="post"> <input type="hidden" name="actie" value="Login"></input> <input type="hidden" name="r" value="<?php echo microtime();?>"></input> <input type="text" id="gebruikersnaam" name="gebruikersnaam" value="" style="opacity:0.7;filter:alpha(opacity=70)"></input> <input type="password" id="paswoord" name="paswoord" value="" style="opacity:0.7;filter:alpha(opacity=70)"></input> <input id="aanmelden" type="submit" name="submit" value="" style="opacity:0;filter:alpha(opacity=0)"> </form> </div> <div id="registreer"> </div> </div> </body> </html> the $_POST['r']; contains "<?php echo microtime();?>" instead of for example: 0.53192500 1305636839 does someone know what I am doing wrong here? I also tryed doing it like this: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Snitch</title> <link rel="stylesheet" type="text/css" href="templates/css/snitch1440x900.css" /> </head> <body> <div id="login-achtergrond"> <div id="login"> <form action=".r=<?php echo microtime();?>" id="loginform" name="login" method="post"> <input type="hidden" name="actie" value="Login"></input> <input type="text" id="gebruikersnaam" name="gebruikersnaam" value="" style="opacity:0.7;filter:alpha(opacity=70)"></input> <input type="password" id="paswoord" name="paswoord" value="" style="opacity:0.7;filter:alpha(opacity=70)"></input> <input id="aanmelden" type="submit" name="submit" value="" style="opacity:0;filter:alpha(opacity=0)"> </form> </div> <div id="registreer"> </div> </div> </body> </html> both $_POST and $_GET contains a string instead of the actual microtime single quotes didn't work eather can anyone see the problem here i am running php 5.3 on my server and GD seems to be enabled. and my host said it was probably something to do with the captcha files or script. <?php session_start(); /* * File: CaptchaSecurityImages.php * Author: Simon Jarvis * Copyright: 2006 Simon Jarvis * Date: 03/08/06 * Updated: 2007-08-12 by Jenny Ferenc (minor visual changes only) * Requirements: PHP 4/5 with GD and FreeType libraries * Link: http://www.white-hat-web-design.co.uk/articles/php-captcha.php * * This program is free software; you can redistribute it and/or * modify it under the terms of the GNU General Public License * as published by the Free Software Foundation; either version 2 * of the License, or (at your option) any later version. * * This program is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the * GNU General Public License for more details: * http://www.gnu.org/licenses/gpl.html * */ class CaptchaSecurityImages { var $font = 'VeraSe.ttf'; function generateCode($characters) { /* list all possible characters, similar looking characters and vowels have been removed */ $possible = '23456789bcdfghjkmnpqrstvwxyz'; $code = ''; $i = 0; while ($i < $characters) { $code .= substr($possible, mt_rand(0, strlen($possible)-1), 1); $i++; } return $code; } function CaptchaSecurityImages($width=130, $height=40, $characters=6) { $code = $this->generateCode($characters); // font size will be 60% of the image height $font_size = $height * 0.6; $image = @imagecreate($width, $height) or die('Cannot initialize new GD image stream'); // set the colours $background_color = imagecolorallocate($image, 255, 255, 255); $text_color = imagecolorallocate($image, 20, 40, 100); $noise_color = imagecolorallocate($image, 100, 120, 180); // generate random dots in background for( $i=0; $i<($width*$height)/3; $i++ ) { imagefilledellipse($image, mt_rand(0,$width), mt_rand(0,$height), 1, 1, $noise_color); } // generate random lines in background for( $i=0; $i<($width*$height)/150; $i++ ) { imageline($image, mt_rand(0,$width), mt_rand(0,$height), mt_rand(0,$width), mt_rand(0,$height), $noise_color); } // create textbox and add text $textbox = imagettfbbox($font_size, 0, $this->font, $code) or die('Error in imagettfbbox function'); $x = ($width - $textbox[4])/2; $y = ($height - $textbox[5])/2; imagettftext($image, $font_size, 0, $x, $y, $text_color, $this->font , $code) or die('Error in imagettftext function'); // output captcha image to browser header('Content-Type: image/jpeg'); imagejpeg($image); imagedestroy($image); $_SESSION['security_code'] = $code; } } $captcha = new CaptchaSecurityImages(); ?> this seems to be the problem line he Code: [Select] $textbox = imagettfbbox($font_size, 0, $this->font, $code) or die('Error in imagettfbbox function'); [\code] I'm getting this Time Zone error. Perhaps it's a compatibility issue with PHP 5.3. Looked all over for an answer without finding one. Here is the error message Warning: date() [function.date]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/New_York' for 'EST/-5.0/no DST' instead in /blocked.php on line 41 12/02/12 Here is the code. Line 41 is near the bottom, the one with the d,m,y. Perhaps the echo date (d/m/y") needs to be changed. Appreciate any help! Code: [Select] <table border="3" width="16%" align="center" cellspacing="0" bgcolor="#FF6600" bordercolor="red" bordercolordark="red" bordercolorlight="red"> <tr> <td width="176"> <p align="center"><?php // shows IP Number on Page echo $ip; ?> </p> </td> </tr> </table> <p align="center"><?php // Show the user agent echo 'Your user agent is: <b>'.$_SERVER['HTTP_USER_AGENT'].'</b><br />';?></p> [b]<h1 align="center"><?php echo date("d/m/y");?></h1>[/b] </td> </tr> </table [,code] I would really appreciate help and I hope my problem can be solved easily. I am attempting to display the date/time based on the user's location. I have installed the timezone.js plugin for help as well. Is there a way to convert the Jquery variable that displays the users timezone location and insert it inside the PHP date_default_timezone_set?
If there is an easier way to display the users timezone date and time please let me know otherwise this was the only solution I could find.
Thanks in advanced...
Here is my code
Header
<header> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.1/jquery.min.js"></script> <script src="Time/detect_timezone.js"></script> <script src="Time/jquery.detect_timezone.js"></script> <script> $(document).ready(function(){ $('#tzvalue').set_timezone({'default' : 'America/Los_Angeles'}); }); </script> </header> How would I go about creating a script to check a date in mysql and if that date is within X days it will send an email alert. /* Output of the table will display the Suite based on the distinct date. The pass rate percentage calculate based on the Suite1 and app1 and the specific date. For example at Apr 4 2011, I need to Sum the total passcount,failcount,errorcount of Bluetooth, GPSA, EMIReceiver($app1) of XA9 on Real MXE($suite1) , then calculate the passrate percentages. But I fail to get the correct value of the passcount, failcount, errorcount value.Helps! Output of the table suite Date Percentages(pass rate) XA9 on Real MXE Apr 4 2011 9:47AM 99.94% XA9 on Real MXE Apr 5 2011 10:48AM 99.94% XA9 on Real MXE Apr 6 2011 9:49AM 99.95% XA9.5 on Real EXA_B40 Apr 4 2011 7:06AM 99.94% XA9.5 on Real EXA_B40 Apr 5 2011 7:14AM 99.93% XA9.5 on Real EXA_B40 Apr 6 2011 7:29AM 99.93% */ $suite1 --> array value (XA9 on Real MXE, XA9.5 on Real EXA_B40) $app1 --> array value (Bluetooth, GPSA, EMIReceiver) if(is_array($suite_type1)){ foreach($suite_type1 as $suite1) { $sql222="Select Distinct a.StopDTTM from Suite a,Test b where a.SuiteID=b.SuiteID and b.SuiteID=a.SuiteID and a.StopDTTM>='$fromdate' and a.StopDTTM<='$to_date' and a.SuiteFilePath like '%$Program%' and a.SuiteFileName='$suite1'"; $result222=mssql_query($sql222,$connection) or die("Failed Query of".$sql222); while($row222 = mssql_fetch_array($result222)) { $datetotest = $row222[0]; $days_to_add = 1; $tilldate = fnc_date_calc($datetotest,$days_to_add); //Query the result based on the date $sql223="Select Distinct a.SuiteFileName, a.SuiteID,a.StopDTTM from Suite a,Test b where a.SuiteID=b.SuiteID and b.SuiteID=a.SuiteID and a.StopDTTM>='$row222[0]' and a.StopDTTM<='$tilldate' and a.SuiteFilePath like'%$Program%' and a.SuiteFileName='$suite1' order by a.StopDTTM"; $result223=mssql_query($sql223,$connection) or die("Failed Query of".$sql223); while($row223 = mssql_fetch_row($result223)){ foreach($app_type1 as $app1) { $sql3="Select Sum(b.passcount),Sum(b.failcount),Sum(b.errorcount) from Suite a,Test b where a.SuiteID=b.SuiteID and b.SuiteID=a.SuiteID and a.StopDTTM>='$row222[0]' and a.StopDTTM<='$tilldate' and a.SuiteFilePath like '%$program%' and a.SuiteFileName = '$suite1' and b.Product='$app1'"; $result3=mssql_query($sql3,$connection) or die("Failed Query of ". $sql3); $row3 = mssql_fetch_row($result3); $total_passcount+=$row3[0]; $total_failcount+=$row3[1]; $total_errorcount+=$row3[2]; } $overall_total=$total_passcount+$total_failcount+$total_errorcount; echo "<tr>"; echo "<td><a href='detailsreport.php?suiteID=".$row223[1]."&suitetype=".$row223[0]."&fromdate=".$fromdate."&to_date=".$to_date."&date=".$row222[0]."&tilldate=".$tilldate."&SuiteFilePath=".$Fprogram."'>" . $row223[0] . "</a></td>"; //Suite File Name echo "<td>" . $row223[2] . "</td>"; //Pass percentage if($total_passcount>0){ echo "<td bgcolor=00FF33>" . number_format((($total_passcount/$overall_total)*100),2)."%</td>"; } else{ echo "<td bgcolor=00FF33>0%</td>"; } } } } echo "</table>"; } I would like to know the best practice to achieve the following: I have a list of dates related to live events for performing artists. When someone views the web page that contains a section to display the dates, I would only want to show the dates from today into the future and not show any dates from the past. What is the best way to accomplish this? Thanks in advance... Hi. Im searching for a way to enter multiple records at once to mysql databased on a date range. Lets say i want to insert from date 2010-11-23 to date 2010-11-25 a textbox with some info and the outcome could look in database like below. ---------------------------------------------------------- | ID | date | name | amount | ----------------------------------------------------------- | 1 | 2010-11-23 | Jhon | 1 | | 2 | 2010-11-24 | Jhon | 1 | | 2 | 2010-11-25 | Jhon | 1 | ----------------------------------------------------------- The reason i need the insertion to be like this is because if quering by month and by user to see vacation days then vacations that start in one month and end in another month can be summed by one month. If its in one record then it will pop up in both months. Help is really welcome. I'm working on a project that has a lot of different timezone options, and all I have from the users is their UTC offset. After weeks of doing tweaks, I come to new issues every time I add something, one would think it would be a lot easier to just get the correct time and day :) The latest issue is that when I try to rewrite a date to a better fomat, it disregards the GMT offset. Like this: 4/14/19, 12:00 PM GMT+2 (=$date) becomes ... 14-04-2019 10:00 when using this code: $bp_date_to_format = date_create_from_format('Y-m-d\TH:i:sP', $date); echo date_format($bp_date_to_format, 'd-m-Y H:i'); I figured it would just rewrite the format, keeping the exact time. It isn't. We do have all these sorts of localization functions as well, but because there doesn't seem to be one single standard (each 3rd party API connection we have uses its own default datetime format so it seems). // Remove UTC Text $UTC_offset = str_replace('UTC', '', $timezone); // Get Offset in Minutes if (stripos($UTC_offset, ':') !== false) { // Calculate seconds from offset list($hours, $minutes) = explode(':', $offset); $seconds = $hours * 60 * 60 + $minutes * 60; } else { $seconds = $UTC_offset * 60 * 60; } // Get User timezone name from seconds $timezone = timezone_name_from_abbr('', $seconds, 1); if ($timezone === false) { $timezone = timezone_name_from_abbr('', $seconds, 0); } // Set new TZ return date_default_timezone_set($timezone);
Isn't there any "one way"solution that can be used? It's confusing to say the least.
Cheers. |