PHP - Sql Count Queries
Hi all,
I've built a few amateur sites in the past but am keen to utilize php combined with mysql for my current project. However, I have little knowledge of php and am just picking it up as I go (same way I've done for all my computer knowledge) What I'm looking for may sound simple, but I really don't know where to start and I'm hoping there are some kind souls here that will lend a hand. I've got some fantastic help here before and am hoping I'll get lucky again. SQL Database meetingid venue 001 new york 002 chicago 003 new york 004 new york 005 new york 006 texas 007 texas 008 chicago 009 new york 010 new york Question If I hard code everything around it, I'm just looking for the code I would need to have it display as follows: (hard coded text in blue) "New York has been used * times." (Where * would count the number of times "New York" appears in the venue column of the database.) "The most consecutive times New York has been used is % ." (Where % would count the maximum number of consecutive times "New York" appears in the venue column of the database.) Giving the output: New York has been used 6 times. The most consecutive times New York has been used is 3. Similar TutorialsThis topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=312721.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=330871.0 Hi guys, I need your help. I am trying to insert the rows in the mysql database as I input the values in the url bar which it would be like this: Code: [Select] www.mysite.com/testupdate.php?user=tester&pass=test&user1=tester&email=me@shitmail.com&ip=myisp However i have got a error which i don't know how to fix it. Error: Column count doesn't match value count at row 1 <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'mydbusername'); define('DB_PASSWORD', 'mydbpassword'); define('DB_DATABASE', 'mydbname'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($var){ return mysql_real_escape_string(strip_tags($var)); } $username = clean($_GET['user']); $password = clean($_GET['pass']); $adduser = clean($_GET['user1']); $email = clean($_GET['email']); $IP = clean($_GET['ip']); if($username == '') { $errmsg_arr[] = 'username is missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'PASSWORD is missing'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; echo implode('<br />',$errmsg_arr); } else { $sql = "INSERT INTO `members` (`username`,`email`,`IP`) VALUES ('$adduser','$email','$IP')"; if (!mysql_query($sql,$link)) { die('Error: ' . mysql_error()); } echo "The information have been updated."; } ?> Here's the name of the columns i have got in my database: Code: [Select] username IP I have input the correct columns names, so I can't correct the problem I am getting. Please can you help? This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=331562.0 Why am I getting this error when there are 3 Fields with 3 values? Column count doesn't match value count at row 1 Code: [Select] $sql5="INSERT INTO participants (participant_name, team_no, sport) VALUES ('".implode("','$_POST[team]'),('",$_POST['participant_name'])."','$_POST[team]','$sport')"; Anyone can help me? <?php $tbl_name="menu"; $kategorije = mysql_query("SELECT * FROM $tbl_name WHERE Left(menu_name, 1) BETWEEN 'A' AND 'M' ORDER BY menu_name ASC"); if (!$kategorije) { die("Database query failed: " . mysql_error()); } while ($row=mysql_fetch_array( $kategorije )) { echo "<div id=lista-header><h4>{$row["menu_name"]}</h4></div>"; $id_sub=$row['id_menu']; $podkategorije = mysql_query("SELECT * FROM submenu WHERE id_menu=$id_sub ORDER BY sub_name ASC", $connection); if (!$podkategorije) { die("Database query failed: " . mysql_error()); } echo "<ul class=\"pod\">"; while ($pod=mysql_fetch_array( $podkategorije )) { echo "<li><a href=index.php?=podkate?".$pod["id_sub"]." class=black>{$pod["sub_name"]}</a><hr size=1 align=left width=100px color=#cccccc></li>"; } echo "</ul>"; } ?> In this way, I get list with categories and hes subcategories. How to count how many subcategories have each categories, and count how many articles have each categories? Example (I wanna get this kind of look): Categories name (3) subcategoriesname (2) subcategoriesname (4) subcategoriesname (7) Categories name (5) subcategoriesname (1) subcategoriesname (14) subcategoriesname (9) subcategoriesname (2) subcategoriesname ( Categories name (2) subcategoriesname (28) subcategoriesname (17) Where the numbers represent how many categories and sub-items have articles Hey guys - me again! I have a discount box, where i wish to check two "if" queries. These are i) the 'uniquecode' and ii) the 'uses' - so a code can only be used a set amount of times. 1) How do i state that question in php, bearing in mind the "if uses > 0" needs to relate to the same row as the unique code entered? 2) Also, i have stored the session price in $_SESSION['sessionprice'] - is this the best way to do this, and if not how should i store the current price. 3) Lastly, and how do I do the php mathematics of "$_SESSION['sessionprice'] minus the discount" - again bearing in mind the "discount" needs to relate to the same row as the unique code entered? (as different codes will have different discounts). This is how far i've gotten: Code: [Select] <?php //connection settings bla bla bla $uniquecode = $_POST['discountcode']; mysql_connect($localhost,$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $discountcodecheck = mysql_query("SELECT uniquecode FROM discounttable WHERE uniquecode = '".$uniquecode."'"); $remainingusescheck = mysql_query("SELECT uses FROM discounttable WHERE uniquecode = '".$uniquecode."'"); if (mysql_num_rows($discountcodecheck) > 0) and if (mysql_num_rows($remainingusescheck) > 0) // <-- this "and if" doesn't work { // discount calculation: // session price minus the unique code's corresponding discount // update $_session['discountammount'] } else { ?><script type="text/javascript"> alert("Discount Code Entered Is Either Not Valid Or Has Been Previously Used."); history.back(); </script><?php } // rest of code and close connection ?> Any help or comments will, as always be politely welcomed and appreciated Cheers, Tom. noob question: I have following two queries I'd like to combined into one - how is this done? $temp = @mysql_query("SELECT * FROM purchased_leads WHERE leadID = '{$_REQUEST[leadid]}'"); "SELECT refundNotes FROM leads WHERE leadID = '{$_REQUEST[leadid]}'" ive had these queries working okay until i checked on it today, it's not working anymore.. these are the errors::: Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\wamp\www\arrastre\add.php on line 105 Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\wamp\www\arrastre\add.php on line 117 if(isset($_POST['add'])){ if($billnmbr=="" or $orno=="" or $payor=="" or $arrastre=="" or $wharfage=="" or $total=="" or $date=="" or $tcl==""){ echo "At least one field was left blank."; } else{ $query = mysql_query("select * from `arrastre` WHERE `billnmbr`='$billnmbr'"); /*****************this is my line 105************/ $count = mysql_num_rows($query); if($count==1){ echo "This billnumber is already in the database."; } else{ $bll = strtoupper($billnmbr); $payr = strtoupper($payor); $query="insert into `arrastre` (`billnmbr`, `orno`, `payor`, `arrastre`, `wharfage`, `total`, `date`, `tcl`) values ('$bll', '$orno', '$payr', '$arrastre', '$wharfage', '$total', '$date', '$tcl')"; $result=mysql_query($query); $query = mysql_query("select * from `arrastre` where `billnmbr`= '$billnmbr'", $link); /************and this is my line 117*************/ $count = mysql_num_rows($query); if($count==1){ echo "last bill number added: ".$billnmbr; } } Thank you very much for your time and have a nice day. Good day everyone. I go by the nickname Sbosh and I am a newbie in PHP. I am currently learning php using video tutorials. I need help with regards to php queries. I have the following code: "SELECT 'food', 'calories' FROM 'diet' ORDER BY 'id'" which is supposed to display content from a table inside phpmyadmin which i created manually using phpmyadmin. But It gives an error saying i must check the MariaDB version on how to right this query, something like that. Please assist on the proper way of writing this code. Again I am a newbie in PHP and just starting to learn, so your help will be highly appreciated. Hello all, I've tried several ways to calculate a commission in the multi level marketing script, but it all ended up with nothing, recursive functions, nested sets nothing worked, and i'm running out of time to keep trying I've made multiple queries on the same table, and it's working, but only the first 3 queries, not more, I tried to perform it 4 times (although I need the queries to be performed 13 times) but still only 3 times example: A recruited B and C, and B recruited D, and D recruited E.... what's supposed to happen is A takes a commission on B, C, D, and E but now it only takes commission on the first three, and no commission for anyone comes after that, and the same for B, C, D, and E each takes commission on only 3 members down the line, and no more here is the queries Code: [Select] <? $result = mysql_query("SELECT * FROM users"); echo "<table width='589' border='1'> <tr> <th>ID</th> <th>Name</th> <th>National ID</th> <th>Commission</th> </tr>"; while($row = mysql_fetch_array($result)) { $query = mysql_query("SELECT * from users where recruiteris = '".$row['id']."'"); $num_rows=mysql_num_rows($query); $id1 = $row['id']; $commission = $num_rows; $_SESSION['id1'] = $id1; echo "<tr>"; while ($roww = mysql_fetch_array($query)) { $querry=mysql_query("select * from users where recruiteris = '".$roww['id']."'"); $num_rowss = mysql_num_rows($querry); while ($rowws= mysql_fetch_array($querry)) { $var3= '10'; $querrys=mysql_query("select * from users where recruiteris = '".$rowws['id']."'"); $num_rowsss = mysql_num_rows($querrys); while ($rowwss= mysql_fetch_array($querrys)) { $querryss=mysql_query("select * from users where recruiteris = '".$rowwss['id']."'"); $num_rowssss = mysql_num_rows($querryss); while ($rowwsss= mysql_fetch_array($querryss)) { $querryr=mysql_query("select * from users where recruiteris = '".$rowwsss['id']."'"); $num_rowssr = mysql_num_rows($querryr); } } } } $total= ($commission + $num_rowws + $num_rowwss + $num_rowwsss + $num_rowss + $num_rowssr) * $var3; echo "<td><a href=\"user.php?id=".$row['id']."\">".$row['id']."</a></td>"; echo "<td>" . $row['fname'] .''. $row['lname'] ." </td>"; echo"<td> ". $row['nid'] ." </td>"; echo "<td>".$total."</td> </tr>"; } echo "</table>"; ?> I need two queries cause I don't know how to put them into one. Problem here is I need to know the field Liters from the database in the first query to subtract it from the second query to be able to calculate the average fuel consumption of the chosen range.
This is my code, hope you can help
function getContent() { include 'connection.php'; $dx = date('m', strtotime('today - 30 days')); if (!isset($_POST["month_select"])) { $month = $dx; $year = "2014"; } else { $month = $_POST["month_select"]; $year = $_POST["year_select"]; } //last fuel fill value $query2 = "SELECT d.liter as FirstFill FROM members AS m LEFT OUTER JOIN diesel AS d ON d.userid = m.id WHERE YEAR(dato) = $year AND MONTH(dato) = $month AND d.liter > 0 ORDER BY d.id ASC LIMIT 1"; $sql2=$oDB->prepare($query2); $sql2->execute(); $row2 = $sql2->fetchAll(); return $row2; $FirstFill = $row2['FirstFill']; $query = "SELECT m.username, m.id, 10 * (SUM(d.liter) - $FirstFill) / (MAX(d.km) - MIN(d.km)) as AvgFuel FROM members AS m LEFT OUTER JOIN diesel AS d ON d.userid = m.id WHERE YEAR(dato) = $year AND MONTH(dato) = $month AND d.liter > 0 GROUP BY m.id ORDER BY AvgFuel ASC"; $sql=$oDB->prepare($query); $sql->execute(); $row = $sql->fetchAll(); return $row; } Edited by Aero77, 23 May 2014 - 12:39 PM. I have two seperate piece of code. One which sorts description and one which sorts price. However, I am looking to almalgamate them into one. I have tried the following however I appear to be way off. I want to select a product description with one link and then select a price range. However, I want the price range to read the description. <?phpif( isset($_GET['description' ; 'price' ])) $description = $_GET['description' ; 'price']; $query = "SELECT * FROM productfeed WHERE description like '%$description%' LIMIT 0, 10"; $query = "SELECT * FROM productfeed WHERE price like '%$price%' LIMIT 0, 10"; $fetchdata = mysql_query($query) or die("query: $query<br> This has an error: " . mysql_error() . '<br>');while($row = mysql_fetch_array($fetchdata)) { $id = $row['id']; $image = $row['awImage']; $link = $row['link']; $description = $row['description']; $fulldescription = $row['fulldescription']; $price = $row['price']; <?phpif( isset($_GET['description'])) $description = $_GET['description']; $query = "SELECT * FROM productfeed WHERE description like '%$description%' LIMIT 0, 10"; $fetchdata = mysql_query($query) or die("query: $query<br> This has an error: " . mysql_error() . '<br>');while($row = mysql_fetch_array($fetchdata)) { $id = $row['id']; $image = $row['awImage']; $link = $row['link']; $description = $row['description']; $fulldescription = $row['fulldescription']; $price = $row['price']; <?phpif( isset($_GET['price'])) $price = $_GET['price']; $query = "SELECT * FROM productfeed WHERE price like '%$price%' LIMIT 0, 10"; $fetchdata = mysql_query($query) or die("query: $query<br> This has an error: " . mysql_error() . '<br>');while($row = mysql_fetch_array($fetchdata)) { $id = $row['id']; $image = $row['awImage']; $link = $row['link']; $description = $row['description']; $fulldescription = $row['fulldescription']; $price = $row['price']; UPDATE: If I remove lastedit = NOW() from the query, and just leave SET content = $var, it works. :/ If already double checked to see if a user would make it to this point in the code, and they do. And the variable $pid IS assigned a value. I've also done a quick check and changed the UPDATE queries to SELECT queries, and then echoed out the number of rows and it returned a successful result. Yet, people still can't seem to have their posts updated...why? My code: //if it's a thread, update the thread, if it's a post, update the post if($type == 2) { //update thread mysql_query("UPDATE threads SET lastedit = NOW() AND content = '{$content}' WHERE id = {$id}") or die(mysql_error()); //send them to their post redirect('viewthread.php?forum='. $forum_id .'&id='. $id .'&page='. $page); } else { //update post mysql_query("UPDATE posts SET lastedit = NOW() AND content = '{$content}' WHERE id = {$pid}") or die(mysql_error()); //send them to their post redirect('viewthread.php?forum='. $forum_id .'&id='. $id .'&page='. $page .'&post='. $post); } This must be easy enough, but I'm a noob so go easy on me, please :-)
I have two pieces of code and they're working well on their own. All I need is to put these two conditions into one query.
The first one:
<?php function childtheme_cat_limited_blog( $query ) { if ( $query->is_home() && $query->is_main_query() ) { $query->set( 'events_categories', 'mycategory1' ); } } add_action( 'pre_get_posts', 'childtheme_cat_limited_blog' ); ?>And the second: <?php function childtheme_cat_limited_blog( $query ) { if ( $query->is_home() && $query->is_main_query() ) { $query->set( 'category_name', 'mycategory2' ); } } add_action( 'pre_get_posts', 'childtheme_cat_limited_blog' ); ?>I'm sure it's a piece a cake for you guys, but I can't figure it out for the life of me, so any help would be greatly appreciated! Thank you! (My goal is here to display posts from two categories on a homepage of a Wordpress site, but to complicate things the two categories are from two different post types.) This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=319917.0 Here is the original query: Code: [Select] $query_extract = mysql_query("SELECT downloads,date,title,username,views,id FROM skins ORDER BY id DESC LIMIT 100"); Is it possible to also grab the row username from the table users, without making multiple queries? Hi all I have a site with 4 SQL queries that I need to paginate so that it returns 10 hits per page maximum. Basically there will be varying values of adverts in each SQL table. Here's my code: Code: [Select] <!-- Get Trader premium adverts --> <?php $gettraderads = mysql_query("SELECT * FROM `trade-adverts` WHERE type = 'premium' AND paid = 1 AND categoryid = 1 AND live = 1 AND approved = 1 AND dateexpired >= '".$todaysdate."' ORDER BY id DESC "); $numtraderads = mysql_num_rows($gettraderads); while ($showtraderads = mysql_fetch_array($gettraderads)) { include('trader-ad-cell.php'); } ?> <!-- Get Trader standard adverts --> <?php $gettraderads = mysql_query("SELECT * FROM `trade-adverts` WHERE type = 'standard' AND categoryid = 1 AND live = 1 AND approved = 1 AND dateexpired >= '".$todaysdate."' ORDER BY id DESC "); $numtraderads = mysql_num_rows($gettraderads); while ($showtraderads = mysql_fetch_array($gettraderads)) { include('trader-ad-cell.php'); } ?> <!-- Get premium adverts --> <?php $getads = mysql_query("SELECT * FROM `adverts` WHERE categoryid = 1 AND type = 'premium' AND paid = 1 AND live = 1 AND approved = 1 AND dateexpired >= '".$todaysdate."' ORDER BY id DESC "); while ($showads = mysql_fetch_array($getads)) { include('ad-cell.php'); } ?> <!-- Get standard adverts --> <?php $getads = mysql_query("SELECT * FROM `adverts` WHERE categoryid = 1 AND type = 'standard' AND live = 1 AND approved = 1 AND dateexpired >= '".$todaysdate."' ORDER BY id DESC "); while ($showads = mysql_fetch_array($getads)) { include('standard-ad-cell.php'); } ?> Many thanks for your help Pete |