PHP - Query Was Empty?!?

Hi guys , can someone help me with this code its giving me "query was empty Error" its connecting but...?
and please find attached the entire php page for clarity.
Thanks .


<?php
   
//connect database

require_once "connect_to_mysqli.php";

//query the datbase
$sqlcommand = "SELECT post_id, title, body From posts ORDER by post_id desc";

$query = mysql_query($sqlCommand) or die (mysql_error());
      
while($row = mysql_fetch_array($query)) {
   
      $title = $row["title"];
     
   echo "<h3>$title</h3>";
   }
   // Free the result set if it is large
   mysql_free_result($query);
   // close mysql connection
   mysql_close();
   ?>

What I am looking for is that if any field in a database is empty, the form comes back and puts in the word "empty" into the web page, but not the database.


I got this right now, it shows the first part fine, but the second part it doesn't show the "Empty" comment... I don't understand why... as far as I can tell the code is fine...

Code: [Select]
<?php
            //Nonconformity, Disposition, Comments and Comments & Additional Details
            echo '<div id="box3">';
                if (!empty($row['Nonconformity']) || !empty($row['Disposition']) || !empty($row['Comments']) || !empty($row['CommentsAdditional_Details'])) {
                    echo '<div id="non"><span class="b">Nonconformity:&nbsp;&nbsp;</span><br />' . $row['Nonconformity'] . '</div>';
                    echo '<div id="dis"><span class="b">Disposition:&nbsp;&nbsp;</span><br />' . $row['Disposition'] . '</div>';
                    echo '<div id="comm"><span class="b">Comments:&nbsp;&nbsp;</span><br />' . $row['Comments'] . '</div>';
                    echo '<div id="comma"><span class="b">Comments and/or Additional Details:&nbsp;&nbsp;</span><br />' . $row['CommentsAdditional_Details'] . '</div>';}
                        else
                            if (empty($row['Nonconformity']) || empty($row['Disposition']) || empty($row['Comments']) || empty($row['CommentsAdditional_Details'])) {
                                echo '<div id="non"><span class="b">Nonconformity:&nbsp;&nbsp;</span><br />Empty</div>';
                                echo '<div id="dis"><span class="b">Disposition:&nbsp;&nbsp;<br /></span>Empty</div>';
                                echo '<div id="comm"><span class="b">Comments:&nbsp;&nbsp;<br /></span>Empty</div>';
                                echo '<div id="comma"><span class="b">Comments and/or Additional Details:&nbsp;&nbsp;</span><br />Empty</div>';}
            echo '</div>';
?>

Hello all,   Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).   The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).   Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:   In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).   I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.   Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.   So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:   1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red. 2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red. 3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.   Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.   Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.   Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.   Cheers guys!

case "update-delete":
	if(isset($_POST['highlight-purchased'])) 
		{
			// ****** Setup customized query to obtain only items that are checked ******
			$sql = "SELECT * FROM shoplist WHERE";
					for($i=0; $i < count($_POST['checkboxes']); $i++)
						{
							$sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or";
						}
					$sql= rtrim($sql, "or");
											
			$statement = $conn->prepare($sql);
			$statement->execute();
																						
			// *** fetch results for all checked items (1st query) *** //
			$result = $statement->fetchAll();

			$statement->closeCursor();
											
			// Setup query that will change the purchased flag to "N", if it's currently set to "Y"
			$sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'";
											
			// Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL
			$sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL";

			$statementSetToN = $conn->prepare($sqlSetToN);
			$statementSetToY = $conn->prepare($sqlSetToY);
											
			/*** loop through the results/collection of checked items ***/
			foreach($result as $row)
				{
					if ($row["purchased"] != "Y")
						{
							// *** fetch one row at a time pertaining to the 2nd query *** //
							$resultSetToY = $statementSetToY->fetch();
															
							foreach($resultSetToY as $row)
								{															
									$statementSetToY->execute();																
								}
						}
					else
						{
							// *** fetch one row at a time pertaining to the 2nd query *** //
							$resultSetToN = $statementSetToN->fetch();
															
							foreach($resultSetToN as $row)
								{															
									$statementSetToN->execute();																
								}
						}
				}
				break;
		}

 CRUD Queston.png   20.68KB   0 downloads    

Here is my code:
// Start MySQL Query for Records
$query = "SELECT codes_update_no_join_1b" .
"SET orig_code_1 = new_code_1,
       orig_code_2 = new_code_2" .
"WHERE concat(orig_code_1, orig_code_2) = concat(old_code_1, old_code_2)";
$results = mysql_query($query) or die(mysql_error());
// End MySQL Query for Records


This query runs perfectly fine when run direct as SQL in phpMyAdmin, but throws this error when running in my script??? Why is this???

Code: [Select]
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= new_code_1, orig_code_2 = new_code_2WHERE concat(orig_code_1, orig_c' at line 1

If you also have any feedback on my code, please do tell me. I wish to improve my coding base.

Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference.

Code:

  Code: [Select]
mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)");
Full code:

Code: [Select]
<?php
include_once("includes/config.php");
 
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title><? $title; ?></title>
<meta http-equiv="Content-Language" content="English" />
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<link rel="stylesheet" type="text/css" href="style.css" media="screen" />
</head>
<body>
 
<div id="wrap">
 
<div id="header">
<h1><? $title; ?></h1>
<h2><? $description; ?></h2>
</div>
 
<? include_once("includes/navigation.php"); ?>
 
<div id="content">
<div id="right">
<h2>Create</h2>
<div id="artlicles">
<?php
 
if(!$_SESSION['user'])
{
 
        $username = mysql_real_escape_string($_POST['username']);
        $password = mysql_real_escape_string($_POST['password']);
        $name = mysql_real_escape_string($_POST['name']);
        $server_type = mysql_real_escape_string($_POST['type']);
        $description = mysql_real_escape_string($_POST['description']);
 
        if(!$username || !$password || !$server_type || !$description || !$name)
        {

        echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>";
        echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'>
       
        <option value='Any'>Any</option>
        <option value='PvP'>PvP</option>
        <option value='Creative'>Creative</option>
        <option value='Survival'>Survival</option>
        <option value='Roleplay'>RolePlay</option>
       
        </select></td></tr>
       
        <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>";
        echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>";
        }
        elseif(strlen($password) < 8)
        {
        echo "Password needs to be higher than 8 characters!";
        }
        elseif(strlen($username) > 13)
        {
                echo "Username can't be greater than 13 characters!";
        }
        else
        {
                $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1");
               
                if(mysql_num_rows($check1) < 0)
                {
                        echo "Sorry, there is already an account with this username and/or server name!";
                }
                else
                {
                        $ip = $_SERVER['REMOTE_ADDR'];

                        mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)");
                        echo "Server has been succesfully created!";
                }
        }
       
}
else
{
        echo "You are currently logged in!";
}
 
?>
</div>
</div>
 
<div style="clear: both;"> </div>
</div>
 
<div id="footer">
<a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop
</div>
</div>
 
</body>
</html>

I'm trying to update every record where one field in a row is less than the other. The code gets each row i'm looking for and sets up the query right, I hope I combined the entire query into one string each query seperated by a ; so it's like
UPDATE `table` SET field2= '1' WHERE field1= '1';UPDATE `table` SET field2= '1' WHERE field1= '2';UPDATE `table` SET field2= '1' WHERE field1= '3';UPDATE `table` SET field2= '1' WHERE field1= '4';UPDATE `table` SET field2= '1' WHERE field1= '5';
this executes properly if i run the query in phpMyAdmin, however when I run the query in PHP, it does nothing... Any advice?

Say I have this query:

site.com?var=1

..I have a form with 'var2' field which submits via get.

Is there a way to produce:

site.com?var=1&var2=formdata

I was hoping there would be a quick way to affix, but can't find any info. Also, the query could sometimes be:

site.com?var2=formdata&var=1

I would have to produce:

site.com?var2=updatedformdata&var=1

Is my only option to further parse the query?

I was just wondering if it's possible to run a query on data that has been returned from a previous query?  For example, if I do

Code: [Select]
$sql = 'My query';
$rs = mysql_query($sql, $mysql_conn);

Is it then possible to run a second query on this data such as

Code: [Select]
$sql = 'My query';
$secondrs = mysql_query($sql, $rs, $mysql_conn);

Thanks for any help

i have made query and i want replace with no data N/A i have tryed with swich but no luck

Code: [Select]
if (($row['name']) = empty)
  {
    echo('n/a');
}

I have search page in the form of search.php?q=query, as the php script calls for other files and a long process. When visiting search.php directly, the value of q is indeed null, and it makes a long loop and use lots of cpu.

How to kill the script or redirect to the main page when visiting search.php?

Hi everyone!  I'm new to PHP and needed from you.  I have the following code that I can't figure out why it doesn't work on the last elseif.   If I comment out the first elseif (line 19-39), it does go through the last elseif. 

Can someone here help?  Thank you!!!

The content of Instructors.txt as follow:
ID#|fName lName|email_address|course1:course2:course3
ID#|fName lName|email_address|course1:course3
ID#|fName lName|email_address|course1:course2:course4
ID#|fName lName|email_address|course2:course3:course5:course6

<?php
  //If we submitted the form
  if(empty($_POST['Location'])) {
    $FH = fopen("Locations.txt", "rb");
    print "<FORM name=\"myForm\" action=\"test4.php\" method=\"POST\">\n";
    print "<P>    Location:\n";
    print "<select name=\"Location\">\n";
    print "<option value=\"\">-- Select --\n";
    while (!feof($FH)){
      $line_of_text = fgets($FH);
      $line = explode('|', $line_of_text);
      print "<option value=$line[1]>$line[1]";
    }
    fclose($FH);

    print "<input type=\"submit\" value=\" Next 1 \">\n";
    exit();
  }
  elseif(empty($_POST['Instructor'])) {

    $location = ($_POST['Location']);
    $FH = fopen("Instructors.txt", "rb");
    print "<FORM name=\"myForm\" action=\"test4.php\" method=\"POST\">\n";
    print "<P>    Location: <input type=text value=$location>\n";
    print "<P>  Instructor: \n";
    print "<select name=\"Instructor\">\n";
    print "<option value=\"\">-- Select --\n";
    while (!feof($FH)){
      $line_of_text = fgets($FH);
      $line = explode('|', $line_of_text);
      if ($line[0] == "$location") {
        print "<option value=\"$line[1]\">$line[1]\n";
      }
    }
    fclose($FH);
    print "<input type=\"submit\" value=\" Next 2 \">\n";
    exit();

  }
  elseif(empty($_POST['Course'])) {
    $location = ($_POST['Location']);
    $instructor = ($_POST['Instructor']);

    $FH = fopen("Instructors.txt", "rb");
    print "<FORM name=\"myForm\" action=\"test4.php\" method=\"POST\">\n";
    print "<P>    Location: <input type=text value=$location>\n";
    print "<P>  Instructor: <input type=text value=\"$instructor\">\n";
    print "<P>      Course: \n";
    print "<select name=\"Course\">\n";
    print "<option value=\"\">-- Select --\n";
    while (!feof($FH)){
      $line_of_text = fgets($FH);
      $line = explode('|', $line_of_text);
      if ($line[1] == "Bert Vandenber") {
        $course = explode(':', $line[3]);
        for ($i=0; $i<count($course); $i++) {
          print "<option value=\"$course[$i]\">$course[$i]\n";
        }
      }
    }
    fclose($FH);
    print "<input type=\"submit\" value=\" Next 3 \">\n";
    exit();
  }
?>

I don't get the logic behind the construct.  I can't ever see myself using this because it doesn't make sense when I code it. 

I understand isset($var) and why I should use it sometimes to avoid undefined messages.

But with empty() it makes more sense to always test the variable directly because if the value is NULL, 0, '', or false then it evaluates as TRUE.  Is there any situation where empty should be used always?

  
Am trying to get user input then compare it with the value in database then return an output in form of echo. It shows a blank page of whick i cant figure out the error. This is what i have tried so far.

This is a file called t12.php   

<?php

  include 'db.php';
  error_reporting(E_ALL | 
   E_WARNING | E_NOTICE);
    
  ini_set('display_errors', 
  TRUE);

     if (session_status() 
    == PHP_SESSION_NONE) 
    {
    session_start();
    }


  if(!isset($_SESSION['login']))
    {
         echo (" 
   <script>location.href='../clogin/'</script>");
    die();

  if(isset($_POST['transfer']))

     {

     $username = 
    $_SESSION['login'];

     $transAmount = 
    $_POST['transAmount'];

     $totalTrans = 
    $transAmount + 30;

    $sql = "SELECT * FROM 
   customer WHERE username = ?";
    $stmt = $connection->prepare($sql); 
    $stmt->bind_param('s', $username);
    $stmt->execute();
    $result = $stmt->get_result();
    $count =  $result->num_rows;
      if($count == 1) 
     {  
 
    while ($row = $result->fetch_assoc())
     {
 
        if($totalTrans > $row['transLimit']) 
    {
    
    echo 'you have exceeded limit';

    exit(); 
    }
     else
     {
      echo"limit passed";
      }

      }//while loop
      }//count

       }//submit
       }//session
       ?>

                     
The html form is this...

   

<form action="t12.php" method="post">
          <input type="number" name="transAmount" placeholder="Enter Amount"> 
   </input><br>
    <button type="submit" name="transfer">Proceed</button></form>

 

 

 

Have tried lot of stuffs but doesnt work out. I would appreciate if you can take your time to check for me and point out the errors. Also please be nice with your comments. Thanks in advance

I have this line in my code

$result2 = mysqli_query($link, 'Select * from categories where cat_loc ='.$nav['id']);

how do I say "if $result2 is empty or false"? (basically if it didn't find any cat_loc = to $nav['id'])

 to echo '</li>';

Hello:

I have this bit of code in the works (which does not work):
Code: [Select]
<?php if ( $mySubHeader; != "" ) { echo " 

<h2>
<?php echo $mySubHeader; ?>

</h2>

"; }

What I am trying to do is to show the H2 tag only if it has a value from the database.

Otherwise, I do not want to show it.

What is the correct way to do this?

Thanks.