PHP - Find Next Result That Matches Query

Hi there I am new to this forum and not much of a php expert. I hope you can assist me. My problem is as follows: I have a column consisting of several values (in this case: sceience, art, humanistics and music) I would like to use the following mysqli query in order to count the appearances of each value in this column:     $query = "SELECT SUM (IF(department = 'science', 1, 0)) AS science, SUM(IF(department = 'art', 1, 0))-> AS art FROM new2"   I have tried lots of ways to loop the results but couldn't get the it working. Can anyone suggest any idea?   Thanks   Hanan  

Hi all !,   I am stuck on the following piece of code which does not give an error nor does it give a result. ( i.e. it gives 0 num_rows which should be > 1).    If, however, I execute the query in phpmyadmin by simply substituting the values of $pp,$ll and $room_no in the query it gives the correct result.      Please can someone tell me what I may be doing wrong here.  Thanks !

	$fcon = mysqli_connect($db_host,$db_user,$db_pass,$db_database) or die('Unable to establish a DB connection');

				$pp = "(ms.level = 'Beginner' || ms.level = 'Intermediate')";	  
				$ll = 'ms.diff <= 7';
				$room_no = 4;

				$query = "SELECT md.Member_reg_id, md.fname, md.lname, md.email, md.cell, 
						ms.level, ms.diff, ms.score,  
						r.ID_Status 
						FROM register as r
						JOIN member_detail as md ON r.ID = md.Member_reg_id  
						JOIN memstatus as ms On r.ID = ms.ID  
						WHERE r.CENTERCODE = ? AND r.ID_Status ='A' AND ? AND ?
						ORDER by level, diff, score DESC";
		
				$stmt=$fcon->prepare($query);
				$stmt->bind_param('iss',$room_no,$pp,$ll);
				if(!$stmt->execute()) die('Failed to execute the query'.$fcon->error);
				else
				{
					echo "Executed";
					$stmt->bind_result($Member_reg_id,$fname,$lname,$email,$cell,$level,$diff                                               ,$score,$ID_Status);
					$numrows = $stmt->num_rows;
					$stmt->store_result();
//					echo $numrows;
					while($stmt->fetch())
					{
						echo "<br>".$fname.' '.$lname;
						echo "<br>".$level;
						echo "<br>".$diff;
						echo "<br>".$score;
						echo "<br>".$cell;
						echo "<br>".$email;
					}
				}

Edited by ajoo, 03 January 2015 - 08:00 AM.

hello
I'm using this code:
Code: [Select]
$query="SELECT * FROM `second_content` WHERE CHANGED =0 limit 0,1";to query first row data when I want see it and echo it I recived :
Code: [Select]
Resource id #2can anyone help me ?


thank you

Hello,
So I have a content management site set up, but I'm stuck on one part. I have a query. Code: [Select]
Select `email` FROM author WHERE author.id IN(SELECT authorid FROM job WHERE id = '$_POST[id]')
I'm a beginner in PHP and SQL. Basically I need the query to run, it will come out with one result and I need that to be where the email is sent to.

This is the existing code I have for sending out the email $subject = " Job Application Confirmation";

$message = "Hello $_POST[name] , \r\rYou, or someone using your email address, has applied for the job: $text Using the Resource Locator at Prahan.com. Keep this as future reference. \r\r Full Name: $_POST[name] \r Location: $_POST[location] \r Email: $_POST[email] \r Additional Information: $_POST[info] \r Job ID: $id  \r Job Name: $text  \r \r Expect a response shortly. \r\r Regards, Prahan.com Team";

$headers = 'From: Prahan.com Team <noreply@prahan.com>';

    'Reply-To: noreply@prahan.com' . "\r\n" .

    'X-Mailer: PHP/' . phpversion();

$to1      = 'pratik@prahan.com';

mail($to1, $result, $message, $headers);


Thanks in Advance!

Hi everyone. I have this code that suppose to divide the query result 3 columns in a row. Like this :
Shoes   Hats   Jeans
Shorts  Shirts  Belts
But for some reason this one doesn't work. It gave me everything in a single row. Like this: Shoes Hats jeans Shorts Shirts Belts. I noticed that before I put this two 2 lines of code, it's working fine. It didn't give me any error messages or anythings. Can someone point me out what did I did wrong?

This is two lines I put in:
Code: [Select]
$vuong_query = tep_db_query("select categories_id from " . TABLE_GENDER_CATEGORIES . " where parent_id = 1");
 while ($product_check = tep_db_fetch_array($vuong_query)) {
This is the whole piece of code:
    Code: [Select]
  <tr>
    <td><table width = "100%" border="1" bordercolor="maroon">
      <tr>
<?php
$vuong_query = tep_db_query("select categories_id from " . TABLE_GENDER_CATEGORIES . " where parent_id = 1");
 while ($product_check = tep_db_fetch_array($vuong_query)) {

$categories_querys = tep_db_query("select c.categories_id, cd.categories_name, c.categories_image from " . TABLE_CATEGORIES . " c, " . TABLE_CATEGORIES_DESCRIPTION . " cd where c.categories_id = '" . $product_check['categories_id'] . "' and c.categories_id = cd.categories_id and cd.language_id = '" . (int)$languages_id . "' order by sort_order, cd.categories_name");
    

    $number_of_categories = tep_db_num_rows($categories_querys);

    $rows = 0;
    while ($categories = tep_db_fetch_array($categories_querys)) {
      $rows++;
      $cPath_new = tep_get_path($categories['categories_id']);
      $width = (int)(100 / MAX_DISPLAY_CATEGORIES_PER_ROW) . '%';
      echo '         <td align="center" class="smallText" width="' . $width . '" valign="top"><a href="' . tep_href_link(FILENAME_DEFAULT, $cPath_new) . '">' . tep_image(DIR_WS_IMAGES . $categories['categories_image'], $categories['categories_name'], SUBCATEGORY_IMAGE_WIDTH, SUBCATEGORY_IMAGE_HEIGHT) . '<br>' . $categories['categories_name'] . '</a></td>' . "\n";
      if ((($rows / MAX_DISPLAY_CATEGORIES_PER_ROW) == floor($rows / MAX_DISPLAY_CATEGORIES_PER_ROW)) && ($rows != $number_of_categories)) {
echo '       </tr>' . "\n";
echo '       <tr>' . "\n";
      }
    }
}
    ?>
      </tr>
            </table>
          </td>
        </tr>
Thanks anyone for helping me out.
Vanvoquan

Hello!

I am busy developing a script that returns all users that have the cell "Available" set to 1
but I am unsure how to do this, I am familiar with basic SQL and I have made this:

$sql = "SELECT * FROM `clans` WHERE `available` =1 LIMIT 0 , 30";
if ($result = mysql_query($sql)) {
if (mysql_num_rows($result)) { 
$row = mysql_fetch_assoc($result);
echo ($row['name']);

but it only displays information from the first row found, and I want it to display all the rows found, how can I do this?
Thanks

- GreenFanta

Hello, I am new to the board and PHP. I created a simple store locator app with PHP. It pulls the info from a database. I want to  take the website field from the table, once it is returned from the query, and have it print out a a hyperlink.
Please help.

Thanks, I have posted most of the relevant code.


<?php   if (isset ($stores)) {     if (!empty ($stores)) {       
   echo '<p><strong>' . count ($stores) . ' results were found.</strong></p>';     foreach ($stores as $value) {         
   echo '<p><strong>' . $value['name'] . '</strong><br />';       
   echo $value['address'] . '<br />';       
   echo $value['town'] . ', ' . $value['state'] . ' ' . $value['postal'];     
   echo '&nbsp;<a target="_blank" href="http://maps.google.com/maps?q=',
            $value['address'], ' ', $value['town'], ', ', $value['state'], ' ',
            $value['postal'],'">Map this location</a><br />';       
   echo 'Phone: ' . $value['phone'] . '<br />';
   echo 'Website: ' . $value['website'] .  '<br />'; 
   echo 'Email: ' . $value['email'] . '<br />';   
   echo 'Hours: ' . $value['hours'] ;     
   echo '</p>';       }     }
      else {     
   echo '<p><strong>No results found</strong></p>';   }   }   
   ?>
   

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=306966.0

Hi,

I have attached sql script for table structure and sample data.

When I run following sql query ,I get result set.

Code: [Select]
select * from tablename order by col10 desc
I want to create array using result set.

Following is the require structure of array.

Code: [Select]
<?php

$resultSet[]=array
    (
        ('0') =>array (
              ('col10value1') => array
                    (
                        ('0') => array
                            (
                                ('col1') => 'col1',
                                ('col2') => 'col2',
                                ('col3') => 'col3',
                                ('col4') => 'col4',
                                ('col5') => 'col5',
                                ('col6') => 'col6',
                                ('col7') => 'col7',
                                ('col8') => 'col8',
                            ),
                        ('1') => array
                            (
                                ('col1') => 'col1',
                                ('col2') => 'col2',
                                ('col3') => 'col3',
                                ('col4') => 'col4',
                                ('col5') => 'col5',
                                ('col6') => 'col6',
                                ('col7') => 'col7',
                                ('col8') => 'col8',
                            ),
                    ),
            ),
 

        ('1') => array (
          ('col10value2') => array
                (
                    ('0') => array
                        (
                            ('col1') => 'col1',
                            ('col2') => 'col2',
                            ('col3') => 'col3',
                            ('col4') => 'col4',
                            ('col5') => 'col5',
                            ('col6') => 'col6',
                            ('col7') => 'col7',
                            ('col8') => 'col8',
                        ),
                ),
        ),
    );   
?>

Hello.  This one is driving me up the wall.  It used to work,

I have a sports league database (MsSql) and one of the tables contains team Captain's first name, last name, etc..  To create a unique but simple login, the query searches for the captain's first initial of their first name + lastname + league.  However since there is the remote possibility of two similar usernames (i.e. David Smith) if the last name is found, the query adds an integer to the end of the last name.

So the result would look like this:  DSmithM4A

At the moment, my database is completely blank.  However what is happening when I run the query below is I get: DSmith1M4A

Can someone figure out why this code is not working correctly?  If there is not more than one "Smith" no integer is supposed to be returned.  There is something in the "Captain Count" that I think is not working correctly.

Code: [Select]
    /*
     * Gather captian information
     */
    $strCaptainFirstInitial = substr($arrPost['cpt_first'],0,1);
    $strCaptainLastName = preg_replace("/[^a-zA-Z]/","",$arrPost['cpt_last']);
    $strCaptainName = strtolower($strCaptainFirstInitial.$strCaptainLastName);
    $sqlCaptainSearch = sprintf
    (
        $strCaptainSearch,
        $strCaptainName
    );
    $resCaptainSearch = mssql_query($sqlCaptainSearch,$conDB);
 
    /*
     * Create unique captain login and Password
     */
    $strCaptainCount = (mssql_num_rows($resCaptainSearch) > 0)
        ? mssql_num_rows($resCaptainSearch)
        : "" ;
    $strLeagueTypeInitial = substr($arrLeagueSearch['type'],0,1);
    $strCaptainLogin =
        $strCaptainName .
        $strCaptainCount .
        $strLeagueTypeInitial .
        $arrLeagueSearch['size'] .
        $arrLeagueSearch['division'];

Hello -

Suppose I had a MySQL result set that was something like this:
ITEM: COLOR: ball red ball blue book red book green book black
If I were to use the code:
Code: [Select]
do {
   echo $row_myQuery['item'] . " - " . echo $row_myQuery['color'] . "<br />";
} while ($row_myQuery= mysql_fetch_assoc($myQuery));

Then I end up with this:

Code: [Select]
ball - red
ball - blue
book - red
book - green
book - black
MY QUESTION:

What I'd like to know is, how could I re-write that php code so that I could get an output like this?:

Code: [Select]
ball - red, blue
book - red, green, black
Thanks!

Hi,

i have a database with multiple records. One of those values is an image. When i query the database and i want only the images as a result it gives the result in a field. It then fills up the field horizontal and when there is no more field left it starts a new row. That is what i want.

But now i want some extra info next to the picture so i put that in a table with two colums like this:

echo '<table border="1" width="400"><td><a href="'.$row['website'].'"> <img src="'.$row['prod_img'].'">
               '.$row['prod_name'].' <a href="'.$row['website'].'">'.$row['website'].'</td></table>
            ';}}

But i still want the result to fill up the field and when the field is full i want the next results on a row below this....

Anyone?

soo i get info from a form and i want to search for it in my db .. if i find user_name AND user_password the $result returns true .. otherwise false ..

<?php require_once("../includes/connection.php"); ?>
<?php
$user_name=$_POST["user_name"];
$user_password=$_POST["user_password"];
?>
<?php
$query = "SELECT *
          FROM users
          WHERE  '{$user_name}' = user_name
          AND '{$user_password}'= user_password
          ";
$result = mysql_query($query,$connection);
if($result==false){ 
redirect("../index.php");}
elseif($result==true){
redirect("../welcome.php");
}
?>
<?php //close connection!
mysql_close($connection);
?>


but the problem is that it always returns TRUE !!!!
whats the problem here exactly ???

I have a table korisnici in SQLite with INTEGER field aktivan that can have only 0 or 1 value (CHECK constraint).

Field aktivan has value 0 but PHP returns value 1, why? Is this a bug?

This is PHP code that I am running:

 $sql = "SELECT ime, aktivan FROM korisnici WHERE lower(ime) = '" . $ime . "'" . " AND sifra = '" . $_POST["sifra"] . "'";
                
$result = $db->query($sql);
$row = $result->fetchArray(SQLITE3_ASSOC);

$row['aktivan'] = 1 but in table the value is 0.

When I run same query in DB Browser for SQLite I get correct value 0.

Is this a bug?