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PHP - Run Script Without Echo?
I need help making img src work without using echo.
The session has been started from another page. Code: [Select] <?php $name = $_FILES['change']['name']['myfile']; $tmp_name = $_FILES['change']['tmp_name']['myfile']; if($name) { //start upload process $dblocation = "$name"; $location = "photos/$name"; move_uploaded_file($tmp_name,$location); $origloc = $location; $_SESSION['imglocation'] = $origloc; echo "<img src='../crop.php?h=50&w=50&f=$origloc' />"; } ?> Similar Tutorialsmy site is laid out as follows: beta.domain.com/index.html <-- this page contains an ajax form scripts.domain.com/js/formoperations.js <--ajax javascript scripts.domain.com/php/msgsend.php <--ajax php script The PHP script which is posted below is to echo back "Thank you" once the form is processed & emailed. If the files are in the directories stated above the PHP script does not echo back. It still completes emailing the form data successfully but does the echo does not make it back to beta.domain/index.html. HOWEVER...if I move my PHP file to beta.domain.com/msgsend.php it works flawlessly. Why can't my script echo across subdomains? Thanks! Code: [Select] <?php $fname= urldecode($_GET['param']); $lname = urldecode($_GET['param1']); $email = urldecode($_GET['param2']); $details = urldecode($_GET['param3']); $datereported = date(n."/".j."/".Y." @ ".g.":".i." ".A); $text="<p><b>First Name:</b> ".$fname."</p><p><b>Last Name:</b> ".$lname."</p><p><b>Email Address:</b> ".$email."</p><p><b>Message:</b> ".$details."</p>-End Submission"; $plaintext="First Name: ".$fname."\nLast Name: ".$lname."\nEmail Address: ".$email."\nMessage: ".$details."\n\n End Submission"; $to = 'chris@domain.com'; $subject = 'Web Message'; $random_hash = md5(date('r', time())); $headers = "From: Web Message\r\nReply-To: info@domain.com"; $headers .= "\r\nContent-Type: text/html; charset='iso-8859-1' Content-Transfer-Encoding: 7bit"; ob_start(); ?> <img src="http://uniformimgs.domain.com/emailheadcontact.gif" alt="" /> <p style="font-family:Arial, Helvetica, sans-serif; font-size:12px; margin:15px 0 50px 0;"><?php echo $fname.' '.$lname; ?> has submitted a message from the website on <?php echo $datereported; ?>.</p> <?php echo $text; ?> <? $message = ob_get_clean(); if(mail($to, $subject, $message, $headers)) { echo '<h4>Thanks for your message '.$fname.'!</h4><br/><br/><br/><br/>'; $to = $email; $subject = 'Thanks for your message!'; $random_hash = md5(date('r', time())); $headers = "From: info@domain.com\r\nReply-To: info@domain.com"; $headers .= "\r\nContent-Type: text/html; charset='iso-8859-1' Content-Transfer-Encoding: 7bit"; ob_start(); ?> <img src="http://uniformimgs.domain.com/emailheadcontact.gif" alt="" /> <p style="font-family:Arial, Helvetica, sans-serif; font-size:12px; margin:15px 0 5px 0;">Dear <?PHP echo $fname ?>,</p> <p style="font-family:Arial, Helvetica, sans-serif; font-size:12px; margin:0;">Thank you for sending us a message from our website; we love hearing from you folks! If needed, we'll contact you as soon as possible in regards to your message.</p> <p style="font-family:Arial, Helvetica, sans-serif; font-size:12px; margin:20px 0 0 200px;">Sincerely,</p> <p style="margin: 10px 0 0 200px;"><img src="http://uniformimgs.domain.com/briansig.gif" alt="" /></p> <p style="font-family:Arial, Helvetica, sans-serif; font-size:10px; margin:0px 0 0 200px;">John R Smith, pricipal</p> <p style="font-family:Arial, Helvetica, sans-serif; font-size:10px; margin:200px 0 0 0">This email has been sent by an automated service</p> <? $message = ob_get_clean(); //send the email mail($to, $subject, $message, $headers); } else { echo "<h5>Oops! Seems like we have a problem.</h5><h6>Please try again later or call XXX-XX-XXX.</h6>"; } ?> Hey, I am currently trying to get a variable created inside a require_once script to be echoed inside the main page that called the require. The script below is a basic idea of what i want to do. I just want to be able to create a basic variable none of this session stuff as its makes life harder at the moment. Thank guys, hope the snippet below gives you a better idea. Main Code: Code: [Select] <body> <?php require_once("makesVariable.php"); <div> // Variable I want to be echo "NOT WORKING" echo $var; </div> ?> </body> External PHP Code: Code: [Select] <?php //Function gets called by previous code to create the needed variable function createTheVariable(){ $var = "I am the variable to be called"; return $var; } ?> Hello community, I am working on a database of specialties in the hospital I work. The doctor's referral requests are sent to a mySQL database and I have, with the help of online guidance, produced a working php script that displays the information I need it to. However, I need it a little bit more specific. I intend to make multiple copies of this file for each specialty, so that when they open the file they only have the requests for that particular specialty. My question is, with reference to my code below, can I make echo information so that online, for instance, if 'specialty1 = gastroenterology' (as in, that particular specialty that that referral request is for), then only the rows on the database that have that particular text are displayed only? Hope that makes sense. Code below for your reference and assistance is highly appreciated.
<!DOCTYPE html>
<html>
<head>
<title>Specialty Referral Form</title>
<style>
table {
border-collapse: collapse;
width: 100%;
color: #000000;
font-family: arial;
font-size: 10px;
text-align: center;
}
th {
background-color: #588c7e;
color: white;
}
tr:nth-child(even) {background-color: #f2f2f2}
</style>
</head>
<body>
<table>
<tr>
<th>Patient Details</th>
<th>Hospital Number</th>
<th>Date of Birth</th>
<th>Referred by:</th>
<th>New/Repeat Visit to Patient</th>
<th>Specialty</th>
<th>Admission Date</th>
<th>Too Ill for Clinic?</th>
<th>Diagnosis Aware?</th>
<th>Question</th>
<th>History</th>
<th>Medications</th>
<th>Examination</th>
<th>Results</th>
<th>WorkingDiagnosis</th>
<th>Investigation(s) Requested</th>
</tr>
<?php
$conn = mysqli_connect("localhost", "view", "", "referral");
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT patientdetails, hospitalnumber, DoB, referral, admission, specialty1, admissiondate, illness, awareness, question, history, medications, examination, results, workingdiagnosis, investigations FROM referralform";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while ($row = $result->fetch_assoc()) {
echo "<tr><td>" . $row["patientdetails"]. "</td><td>" . $row["hospitalnumber"] . "</td><td>" . $row["DoB"] . "</td><td>"
. $row["referral"] . "</td><td>" . $row["admission"] . "</td><td>" . $row["specialty1"] . "</td><td>" . $row["admissiondate"] . "</td><td>"
. $row["illness"] . "</td><td>" . $row["awareness"] . "</td><td>" . $row["question"] . "</td><td>" . $row["history"] . "</td><td>"
. $row["medications"] . "</td><td>" . $row["examination"] . "</td><td>" . $row["results"] . "</td><td>" . $row["workingdiagnosis"] . "</td><td>"
. $row["investigations"]. "</td></tr>";
}
echo "</table>";
} else { echo "0 results"; }
$conn->close();
?>
</table>
</body>
</html>
I guess what I am looking for is something like echo specialty1 IF it writes a particular specialty and only that specialty. Thank you. Edited April 2, 2020 by samanjI have looked at ob_start, ob_get_contents, etc.. but I can't get it to work. My code looks like this: Code: [Select] ob_start(); echo "starting"; ob_flush(); //do some stuff echo "something else" ob_flush(); //do some stuff echo "something else" ob_flush(); The echoes are only shown at the end of the script execution. Good Afternoon Team, Am sitting with something simple using the language below. If I copy the echo output of my query as included below it works perfectly in phpmyadmin but doesn't work on a website. Variables all seem to echo consistently/correctly and POST checks seem to verify this is working correctly as well. I worry the error comes with the syntax I used in combining the sql queries. That, or perhaps LAST_INSERT_ID does not work in the php script as well as it does in phpmyadmin. All help appreciated.
if(isset($_POST[`region_id`])) {
Hi, I am pretty much a new newbie when it comes to PHP, and have a problem that I need to solve, for a website that has to go live tomorrow. Basically I have been using a javascript upload script called 'uploadify' which had an option for the upload folder which was added to the script in the form: Code: [Select] 'folder' : '/songs/<?php echo $_SESSION["name"];?>', I added the php echo to return the username from a PHP login, so it gets added to the path to the upload folder (each user has their own subfolder for uploading to). With the new version of the uploadify script, the folder option has been moved to a separate PHP file where it is now in the form: Code: [Select] $targetFolder = '/songs/'; I need to find a way of adding the username variable to this line. I have tried using echo in various ways, and googled about, but it has stumped me, simple as it may be. If anyone could let me know how I construct this line I'd be very grateful. Time is of the essence, as they say... Thanks, Nick OK, have no idea what's going on... I've done this a million times... why wont this output!?? I must have a major brain meltdown and dont know it yet!!! Code: [Select] <?php // this echoes just fine: echo $_POST['testfield']; // but this wont echo: echo if (isset($_POST['testfield'])) { $_POST['testfield'] = $test; } echo $test; /// or even this DOESNT echo either!: $_POST['testfield'] = $test; echo $test; ?> Hi All, I'm trying to echo the response from an SLA query, the query works and returns the data when I test it on an SQL application.. but when I run it on my webpage it won't echo the result. Please help? <?php $mysqli = mysqli_connect("removed", "removed", "removed", "removed"); $sql = "SELECT posts.message FROM posts INNER JOIN threads ON posts.pid=threads.firstpost WHERE threads.firstpost='1'"; $result = mysqli_query($mysqli, $sql); echo {$result['message']}; ?> I have a log system that allows 10 logs on each side(Left and right). I am trying to make it so that the left side has the 10 most recent logs, then the right as the next 10. Any ideas? So I need to echo a row from my database with php, but where i need to echo is already inside an echo. This is my part of my code: $con = mysql_connect("$host","$username","$password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("main", $con); $result = mysql_query("SELECT * FROM Vendor"); while($row = mysql_fetch_array($result)) { //I need to echo right here .................. but I get a blank page when I try this. Please Help. echo '<option value=$row['vendor_id']>'; echo $row['vendor_id']; echo '</option>'; } mysql_close($con); Result: A Blank page. Thanks in advance! Hi
I try to echo out random lines of a html file and want after submit password to whole content of the same html file. I have two Problems.
1st Problem When I echo out the random lines of the html file I don't get just the text but the code of the html file as well. I don't want that. I just want the text. How to do that?
for($x = 1;$x<=40;$x++) {
$lines = file("$filename.html");
echo $lines[rand(0, count($lines)-1)]."<br>";
}
I tried instead of "file("$filename.html");" "readfile("$filename.html");" But then I get the random lines plus the whole content. Is there anything else I can use instead of file so that I get the random lines of text without the html code?P.S file_get_contents doesn't work either have tried that one.
2nd Problem:
As you could see in my first problem I have a file called $filename.html. After I submit the value of a password I want the whole content. But it is like the program did forget what $filename.html is. How can I make the program remember what $filename.html is? Or with other words how to get the whole content of the html file?
My code:
if($_POST['submitPasswordIT']){
if ($_POST['passIT']== $password ){
$my_file = file_get_contents("$filename.html");
echo $my_file;
}
else{
echo "You entered wrong password";
}
}
If the password isn't correct I get: You entered wrong password. If the password is correct I get nothing. I probably need to create a path to the file "$filename.html", but I don't know exactly how to do that.
What is the correct way to write an if/else statement within an echo? I need to alter this so that I can query to see what data is found and if not correct not to echo the rest of the statement. Code: [Select] echo '<td class="productbox"> <h1>' . $product_title . '</h1> </td>'; So from the above code which is echoed within the single quotes, what is the correct way to include an if else check on a value from the database. I know how its done, but just want to save time and write it the correct way within this. Hi, I have created a class "friendClass" and tried to echo it. It prints nothing without any errors, not sure what was it going on? Any helps would be appreciated! Code: [Select] class friendClass{ //attributes - variable public $name; public $sex; public $title; public $country; //methods - function public function eat(){} public function watch(){} public function drive(){} public function speak(){} } $friend1 = new friendClass; $friend2 = new friendClass; $friend3 = new friendClass; $friend4 = new friendClass; $friend1 -> name = "Bach"; $friend1 -> title = "Muscian"; $friend1 -> sex = "Male"; $friend1 -> country = "Germany"; $friend1 -> eat("Bread"); $friend1 -> speak("German"); $friend1 -> drive("Horse"); $friend1 -> watch("Beethoven"); echo "Name is: ".$friend1->name; Hi freaks, Yes im a noob... I have some data in a db that im echoing out, but the last row wont multiply? The rest works great... I have tried having the data as the following: 1.12 or 0.12 & I have tried having it as a var. Do I need to have a % in there somewhere? Im adding up all the data then I want to multiply by 12% (*$row['markup']) <?php echo $row['Stock1']*$row['qty']+$row['cutting']+$row['production']+$row['additional']+$row['pluscover']+$row['selfcover']*$row['markup'];?> any help would be appreciated. cuzzmunger. Code: [Select] <span class="hotspot" onmouseover="tooltip.show('User ID :');" onmouseout="tooltip.hide();"> i want to know how to echo this above code Code: [Select] <?php $sum_num = mysql_query("SELECT SUM(likes) as totallikes FROM facebook"); echo $sum_num; ?> i got this result Resource id #27 how to get a number only? Hi I once found out how to do this 4 years ago but I lost my backups and memory on the matter. I want this xml to be echoed? out as it is. When I try the standard echo and print, I get the first two lines of the code in gray when I view the page's source. I get no xml at all. Code: [Select] <?xml version="1.0" encoding="utf-8"?> <!DOCTYPE blah [ <!ELEMENT cart (title, items)> <!ELEMENT title (#PCDATA)> <!ELEMENT items (item)+> <!ELEMENT item (prive, deprive, onprive+)> <!ELEMENT security (#PCDATA)> <!ELEMENT answer (#PCDATA)> <!ATTLIST answer correct (yeah) #IMPLIED> ]> this is followed by the standard displaying of xml items could anyone help me over here? thanks in advance... I saw that <?=$var?> instead of <?php echo $var; ?> can be used for echo, does it work on every server? |
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