PHP - Looping Through Curl ?

ok I'm a bit stuck here were I would think something would work easily im getting an error.

What I am trying to loop is..


$data="UPDATE ts12 SET djid='$_POST[TS0]' WHERE id=1";
$data="UPDATE ts12 SET djid='$_POST[TS1]' WHERE id=2";

This would go on for 84 id's. So I figured I could just loop this line so I only have to type it once. Right now I have it set up for just testing 7 ids and I have this code....

if ($edit == yes) {
for ($i=0; $i < 7; $i++){ $n=($i+1);
$data.="UPDATE ts12 SET djid='$_POST[TS$i]' WHERE id=$n";
}
if (!mysql_query($data,$con))  die('Error: ' . mysql_error());
}else{}

The error I am getting is...
PHP Parse error:  syntax error, unexpected T_VARIABLE, expecting ']' in dir/page on line 6


What am I doing wrong here?

ANYONE WHO CAN HELP ME WITH MY LOOP? THIS IS THE CODE THANKS IN ADVANCE. <?php
$testTwo = 'bakit ayaw po gumana paulit ulit bakit';
$testOne = 'bakit paulit ulit bakit ulit';
$tTwo = explode(' ', $testTwo);
$tOne = explode(' ', $testOne); echo"SIMILARITIES:</br>";
foreach($tOne as $first) {
foreach($tTwo as $second) {
if($second == $first) {
echo $second.'&nbsp';
} 
} 
echo"</br>"; 
} ?> THIS IS THE OUTPUT SIMILARITIES:
bakit bakit 
paulit 
ulit 
bakit bakit 
ulit THIS IS MY EXPECTING OUTPUT.
bakit
paulit
ulit
bakit 
ulit 
lang

Hey,

I have the following code that gets the name of the course from the XML.

XML Snippet
Code: [Select]
<?xml version="1.0"?>
<courses>
  <course>
    <id>70</id>
    <name>Marketing and Social Media</name>
    <dates>
      <date>
        <instance_id>6747</instance_id>
        <location />
        <course_type>Day</course_type>
        <date_available>2011/07/13</date_available>
        <time_start>9:30</time_start>
        <time_end>17:00</time_end>
        <availibility>7</availibility>
        <running_dates>
          <running_date>2011/07/13</running_date>
          <running_date>2011/07/14</running_date>
        </running_dates>
      </date>
    </dates>
  </course>
  <course>
</courses>

PHP
Code: [Select]
$dom = new DomDocument();
$dom->load("courses.xml");
$xp = new domxpath($dom);

$titles = $xp->query("/courses/course/name");
foreach ($titles as $node) {

    print $node->textContent . " ";

}


This prints out the course name fine. My question is how Can i get the rest of the data from the same query. For example why cant I do something like..

Code: [Select]
...
foreach ($titles as $node) {

    print $node->name. " ";
    print $node->time_start. " ";
    print $node->course_type. " ";

etc..

}


So I want to loop through get the name and assign the rest of the nodes in there to variables or something.

i have this bit of code which is supposed to do a while loop of rows from a database then inside that does a while loop of columns, so its basically creating a html table of dynamic data from mysql.

the column loop works fine, but the row one isnt, it only goes through and echos out the first row then stops.

ive spent hours now trying to see why and i cant see it hence my call for help.


$totalrows = 4;
$columns = 5;
$columncount = 1;
$rowcount = 1;

echo "<table>";
while ($rowcount <= $totalrows) {
echo "<tr>";
$sql = "SELECT * FROM ville_map WHERE id = '$rowcount'";
$sql_result = mysql_query($sql, $connection); 
while ($row = mysql_fetch_array($sql_result)) { 
$c1 = explode(',', $row["c1"]);
$c2 = explode(',', $row["c2"]);
$c3 = explode(',', $row["c3"]);
$c4 = explode(',', $row["c4"]);
$c5 = explode(',', $row["c5"]);

while ($columncount <= $columns) {
$arraynum = ${'c'.$columncount};
 if ($arraynum[2] > 0) { $playerimage = '<img src="images/player' .$arraynum[2]. '.png"'; } else { $playerimage = ""; }
echo '<td background="images/' .$arraynum[0]. '.jpg" width="50" height="50">' .$playerimage. '</td>' ;
$columncount++;
}
}
echo "</tr>";
$rowcount++;
}
?>
</table>


any help would be much appreciated.

ok, here is some code:
Code: [Select]
<?php
// Query member data from the database and ready it for display
$sql = mysql_query("SELECT * FROM products");
while($row = mysql_fetch_array($sql)){
$product = $row["product"];
?>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script>
<script type="text/javascript" src="http://ajax.microsoft.com/ajax/jquery.validate/1.7/jquery.validate.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("#myform").validate({
debug: false,

submitHandler: function(form) {
// do other stuff for a valid form
$.post('process.php', $("#myform").serialize(), function(data) {
$("#price").load("index.php #price");
$('#results').html(data);
});
}
});
});
</script>
<form name="myform" id="myform" method="POST" action=""> 
     
        <input type="hidden" name="hiddenField" id="hiddenField" value="<?php echo $product; ?>" />
<input type="submit" name="submit" value="Submit" style="background-color:lightgreen; height:50px; width:100px;">     </form> 

<?php

}
?>and here is process.php Code: [Select]
<?php
include_once("/connect.php");
?>
<?php 
$price=$_POST['hiddenField'];
 $sql = "INSERT INTO cart (price) 
VALUES('$price')";
 $rs = mysql_query($sql) or die ("Problem with the query: $sql<br>" . mysql_error());
echo mysql_error();
?>.

what is happening is it is supposed to be submitting form without page reload.......but only the first one in the loop does it.  I want all of them to do it.  can anyone help me do this properly.

Hi,

I am having a problem, which if I don't get some help, promises to melt my brain.

It may have a simple solution, but I cannot conjure it with my limited, and relatively new coding skills.

I need to grab everything from a table, group them up by a tag and then, in their tag groups, print them out into div boxes.

details below.

Code: [Select]

<?php




// grab everything from the database and group by tag, sort by adddate

$query = " select * from portfolio group by tag sort by adddate ";
$result = mysql_query ($query);
$row = mysql_fetch_array($result);


/*  I now need to loop through the array putting each tag group into separate div boxes.. HOW?? 
at the momenet I am using a while loop, but I think I should be using a for loop with foreach as well?
*/


// below is my current loop, which just takes each entry and sticks them all into seperate div boxes. which is crap.

while ($row)
   
    {
   
    echo "<div class='boxgrid'><a href=".$row['fullPath']." rel='prettyPhoto[".$row['tag']."]'><img src=".$row['thumbPath']." title=".$row['desc']."/></a></div>";  
  
    $row = mysql_fetch_array($result);

    }    

include('./scripts/footer.php');

mysql_close($con);


// my actual desired output would be like shown below


?>




        <div class="boxgrid">
                <a href="./images/imagename01.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a>
<a href="./images/imagename02.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a>
<a href="./images/imagename03.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a>
<a href="./images/imagename04.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a>
        </div>

        <div class="boxgrid">
        <a href="./images/imagename01.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a>
<a href="./images/imagename02.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a>
        </div>

        <div class="boxgrid">
        <a href="./images/imagename01.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a>
        </div>

        <div class="boxgrid">
        <a href="./images/imagename01.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a>
        </div>

        <div class="boxgrid">
        <a href="./images/imagename01.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a>
        </div>
       






if anyone here can help, It is quite likely that I may cry.

Ben.

I've been over it a few times and for some reason my results are being read out 2 times per row in the database. This error occurs consistently accross my scripts except for one, but for the life of me I can't work out how. Any help would be appreciated. I have a feeling this is rather basic and am sorry for asking something so trivial.

Many thanks.

GET ALL CS RESULTS PHP - FULL FILE
Code: [Select]
<?php

include ('connect.php');

$cat = $_GET['id'];

$sql = "SELECT ind_id, ind_name, cs_name, cs_value, quarter, fiscal_year FROM industry, customer_satisfaction, cs_value, time";

$result = mysqli_query($link, $sql);
$output = mysqli_affected_rows($link); 

if (!$result)
{
$error_num = mysqli_errno($link);
$error_desc = mysqli_error($link);
include ('error.html.php');
exit();
}
else
{
while ($industry_result = mysqli_fetch_array($result))
{
$industry_results[] = array(
'ind_id' => $industry_result['ind_id'],
'ind_name' => $industry_result['ind_name'],
'cs_name' => $industry_result['cs_name'],
'cs_value' => $industry_result['cs_value'],
'quarter' => $industry_result['quarter'],
'fiscal_year' => $industry_result['fiscal_year']
);
}
if (!$industry_results)
{
$error = '<p><i>Database Returned no Results.</i></p>';
}
else
{
include ('all_cs_results.html.php');
}
}

?>

GET ALL CS RESULTS HTML OUTPUT - FULL FILE
Code: [Select]
<ul id="result_list" class="results_list">
<?php foreach ($industry_results as $industry_result): ?>
<li id="cs_result">
<?php echo $industry_result['ind_id']; ?>

</li>
<li id="cs_result">
<?php echo $industry_result['ind_name']; ?>

</li>
<li id="cs_result">
<?php echo $industry_result['cs_name']; ?>

</li>
<li id="cs_result">
<?php echo $industry_result['cs_value']; ?>

</li>
<li id="cs_result">
<?php echo $industry_result['quarter']; ?>

</li>
<li id="cs_result">
<?php echo $industry_result['fiscal_year']; ?>

</li>

<?php endforeach; ?>
</ul>
JQUERY AJAX LAYER - CODE SNIPPET
Code: [Select]
$('#all_cs').click(function(){ $('#display').load('get_all_cs.php', function(){  })});

i have some code which loops through a table, and displays the results. i have then added extra code so that it loops through another table, and prints out the reults, that are related to the first loop. so the page should look like

menu
   submenu 1
   submenu 2
   submenu 3
menu 2
   submenu 4 etc
The problem is that the code only prints out the first row from the first loop and nothing else.

<?php
$list = "SELECT * FROM section_main";
$result = mysql_query($list) or die ("Query failed");

$numofrows = mysql_num_rows($result);
echo "<table border='1' id='section_list'>";
echo "<tr><th>section_id</th><th>section_title</th></tr>";
for($j = 1; $j < $numofrows; $j++) { 
    echo '<tr>';
$row = mysql_fetch_array($result);  
    echo "<td>". $row['section_id'] . "</td><td>". $row['section_title'] . "</td>";

$query = "SELECT section_sub.section_sub_title, section_sub.section_title WHERE  section_sub.section_title = " .$row['section_title']."ORDER BY section_sub_title";

$result2 = mysql_query($query) or die ("query failed2");//This part does not work
$numofrows2 = mysql_num_rows($result2);

for($i = 0; $i<$numofrows2; $i++){
$row2 = mysql_fetch_array($result2);
echo '<tr>'.$row2['section_sub_title'].'';
}
}
echo "</tr>";

echo '</table>';
?>


Any help on whats wrong would be great

I am trying to get it to display the table where only some rows will be shown. It works on picking up each indivual value from the othere page but when it comes to displaying the table it only pics up the first value and only displays that.

Here is my code bellow

Code: [Select]
<?
session_start();

if ($_SESSION['userName'])

{}

else
{
header('location:../index.php');
}
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Deliver-Pizza Order</title>
<link href="css/order.css"  rel="stylesheet" type="text/css" />

</head>

<body>

<div id="container">

     <div id="header">
    <img src="images/logo.jpg" alt="logo" />
       
         <a href="log-off.php" id="logg-off" >log off</a>
       
    <ul id="nav">
    <li><a href="home.php" target="_self">Home</a></li> <span> | </span>
    <li><a href="Pizza-Topping.php" target="_self">Pizza Topping</a></li> <span> | </span>
    <li><a href="order.php" target="_self">Order</a></li> <span> | </span>
        <li><a href="Account.php" target="_self">Account Details</a></li> <span> | </span>
       </ul>
</div>
   
<div id="Featured">
<img src="images/banner1.jpg" alt="banner" name="banner"" ID="banner"></div><!--end Featured-->
<div class="featuredimage" id="main">
<div id="content" class="tiles">
    <h1>Order</h1><hr />

<div id ='staff'><div style="width:920px; height:autopx; overflow:auto; heightmax:300px">

<table>
<tr>
<th>pizza number</th>
<th>Type</th>
<th>Size</th>
<th>Topping</th>
    <th>Cost</th>
<th>Information</th>
    </tr>

    <?php

mysql_connect("localhost", "root", "")or die("cannot connect"); 
    mysql_select_db("deliverpizza")or die("cannot select DB");

$sql="SELECT * FROM `pizzatopping` ";

$result= mysql_query($sql);


while($row = mysql_fetch_assoc($result))
{
     $pizza    = $row['id'];
if(isset($_POST["pizza$pizza"])) {
    

if ($_POST["pizza$pizza"] == $row['id']){

$id = $row['id'];

$dis="SELECT * FROM `pizzatopping` where id='$id'";
$result= mysql_query($dis);

while($row =mysql_fetch_assoc($result)){
?>
            <tr>
<td><?php echo $row['id'] ?></td>
<td><?php echo $row['type'] ?></td>
<td><?php echo $row['size'] ?></td>
<td><?php echo $row['topping'] ?></td>
<td><?php echo $row['cost'] ?></td>
<td><?php echo $row['info'] ?></td>
            </tr>
            <?php
}

}
}
} 

?>
</table>
</div>
</div>
   
</div>
</div>
<!--end content-->

<div id="footer"><span><p>Created By Ryan Williams</p></span></div><!--end footer-->
</div><!--end container-->




</body>
</html>

I have a website of grids of webcam images. I have decided to make a looping webpage where I want just 1 image per page and every 2 seconds moves on to the next image.   I have the following code - but it only gets 1 image.  I was going to update the database record  with the next image but have decided it will be easier to get an array and loop round that somehow.  Normally when I loop its easy to display the results in a table but this time i want it to display 1 image (record) at a time then move on...   The code below works fine (only showing the first image form the website in my database)   I hope someone can help me out please. TIA

<html>
<head>
<title>My webcam page </title>
</head>


<?php


    $host = 'localhost';    
    $user = 'my_User';
    $pass = 'my_Password';
    $db = 'my_db';


    $con = mysqli_connect($host, $user, $pass, $db) or die(mysqli_connect_error());


    $sql = "SELECT * FROM `websites` WHERE `currentshowing`=1 LIMIT 0, 30 ";
    $result  = mysqli_query($con,$sql);
    if (!$result) 
    {
        die("Error: Data not found..");
    }
    $test = mysqli_fetch_array($result);
    $webpic=$test['webpic'];
    $basesite=$test['basesite'];
    $location=$test['location'];
    
?>


<div align="center">
<h1>MY WEBSITE (Ongoing work)</h1>
</div>


<td><div align="center"><?PHP echo $location; ?><br>
        <a href="<?PHP echo $basesite; ?>">
        <img src="<?PHP echo $webpic; ?>" 
        alt="<?PHP echo $location; ?>" 
        width="80%" border="0"/>
        </a></div></td>


</body>
</html>

Ok i have been after the solution for this for a while and I have finally got it in a state where it is producing results but....... they are wrong so I will start from the beginning with what I have and what I am trying to do.

I have these tables

Members
Id                        Name

Clubs
ID                       Name

Permission
ID                      Name

Link
MemberID                   PermissionID                      ClubID

When a member joins a club thier ID ant the ID of the club are entered into the link table along with their permission (as a number)
so

MemberID                             PermissionID                    ClubID
01                                                  02                              01


I have a loop which is going to echo the clubs a member is a part of. So for my querys

function GetUser($user)

 {

$qFindUser = "SELECT * FROM members WHERE email = '$user'";

 

$rFindUser = mysql_query($qFindUser);

  

$UserInfo = mysql_fetch_array($rFindUser);

return $UserInfo;

  }

 function GetLinkByMemberID($link) {
 

$qLink = mysql_query("SELECT * FROM link WHERE memberID = '$link'");

$Link = mysql_fetch_array($qLink);

return $Link;

 }

 function GetClub1($clubs)

 {

$qFindClub = mysql_query("SELECT * FROM clubs WHERE clubID = '$clubs'");

 
 return $qFindClub;
 }

 function GetPermission($per) {
 

$qPermission = mysql_query("SELECT * FROM `permissions` WHERE permissionID = '$per'");

$permission = mysql_fetch_array($qPermission);

return $permission;

 }

$User = GetUser($_SESSION['Username']); // returns as array from the login details all member details
$Link = GetLinkByMemberID($User['memberID']); // returns as a fetch array all clubs the member is a part of
$Club = GetClub1($Link['clubID']);  // returns as the query
$permission = GetPermission($Link['permission']); //returns as array so I can echo the permission word not ID


Now the loop is limited by 3 so

<?php 

$Club = mysql_fetch_array($Club);
  $stack3 = ($Club+$Link);

for($i = 0; ($CP = ($stack3)) && $i < 3; $i++ ){ ?>
  <tr>
    <th scope="col"><img name="" src="" width="32" height="32" alt="" /></th>
    <th scope="col"><?php  echo $CP['name']; //from the club table
 ?><span class="ownertext">
<?php
echo $CP['permission']; //from the link table

 ?>


The problem I'm having the the loop is returning the first record its selects 3 times and not echoing each club once.  I have worked on it for so long I can no longer make sense of it.  Can anyone see my errors and point out just how to fix it? Im guessing it involves something to do with how Im finding my permission but I really dont know.

As im sure you can see from the code Im a php beginner so Im struggling to make sense of this.

I have a loop which works fine but before the loop I run a query which I store as $AlbumName

From this array and within the loop I want to echo $AlbumName['album_name']; but obvisouly its not working.  Can somebody please show me how to do it?

 <?php 

  

  

  

  $qImage = "SELECT * FROM photos";

  $rImage = mysql_query($qImage);

  $Array = mysql_fetch_array($rImage);

  $qAlbumName = "SELECT * FROM albums WHERE id =".$Array['album']."";

  $rAlbumName = mysql_query($qAlbumName);
$AlbumName = mysql_fetch_array($rAlbumName);

  

  while ($row_images = mysql_fetch_assoc($rImage) )

  {

  ?>

  
            <?php echo $row_images['id'];
           
             echo $row_images['name']; 
           echo $row_images['photo_description'];
         

echo $AlbumName['album_name'];

           } ?>

Hi

I have two albums with pictures in them, what I want to know is how do I put the first image of my album next to the albums name. For example I have an album called gallery 1 and I have 2 pictures in it and before you click the link to go see those images i want the first picture to be next to gallery 1. I hope that made sense. Thank you for your help.

This is the code I got so far

public function home(){
      
      $galleries_model = new galleries_model('galleries');
      $galleries = $galleries_model -> get_all();
      
      
      
      foreach($galleries as $gallery){
         
         $sql = ("SELECT * FROM gallery_images WHERE id = gallery_id LIMIT 1");
         
         
         $this->_params['list'][] = $gallery;
      }
      
      
      
      
   }
   

      
   
}   

I've made a loop here..

Code: [Select]
<form name="formdeliver" method="post" action="addOrder.php"  onSubmit="return confirm('Are you Sure the data inputed are correct? Click Ok to continue.')">
<div id="apDiv2" style="overflow:auto ">
<?php 
$host="localhost"; 
$username="root"; 
$password="";
$db_name="SEdatabase";
$tbl_name="bottlenumbers"; 

mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");

$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);

$name = $_SESSION['customername'];
$q = $_SESSION['quantity'];

echo "<table border='1'>
<tr>
<td><font size = '2'>Customer Name : $name </font></td></tr><tr>
<td><font size = '2'>Quantity : $q </font></td>
</tr>
</table><br>";


for($i = 0; $i < $q; $i++){
    echo "Bottle Number :";

echo "<select name=\"bottlenum[]\" onChange=\"this.name\"> 
    <option>Select</option>";

    if(mysql_num_rows($result)) 
    { 
    while($row = mysql_fetch_assoc($result)) 
    { 
    echo "<option>" .$row['BottleNumber']. "</option>"; 
    } 
  echo "</select>";
    } 
    else {
    echo "<option>No Customer Encoded</option></select>";  
    } 

    
echo "<font size = 2 >Type :</font>
<select name=\"bottletype[]\" onChange=\"this.name\"'>'; 
    <option selected>Select .. </option>
     <option> Slim </option>  
     <option> Round </option>  
 </select><br>";
}

?>

<br>
  <input type="image" src="continue.png" width="100" height="25" name="login" border="0" />
 </div> </form>
So what it basically do is..
User will input some data w/c i included as $_POST['customername'] and $_POST['quantity']
So when the user will input 5 quantity.. i want my loop to have 5 pairs of 2 drop down list.. well i suceeded there.
but, my problem is the 1st pair will output the  .$row['BottleNumber'].  w/c i included at the loop, and then the rest will have no output.. when i clicked them the dropdown list will only show the Select one. but for the 1st pair its working fine.

Sorry for the bad english.. someone help me pls

Ok I have this form with 6 fields that the user enters a geocaching code.  In the database I have a table called cacheinfo.  There are 6 enteries in the database in this table. Now Im trying to confirm that each field entered matches the right geo code.  I have it working but I feel that its a very bad way of doing it my way. 

can someone please show me a better way as I have other situations I do something simliar and its just getting silly.  Here is the code;


if(isset($_POST['nextbtn'])){
$cache1 = trim($_POST['cache1']);
$cache2 = trim($_POST['cache2']);
$cache3 = trim($_POST['cache3']);
$cache4 = trim($_POST['cache4']);
$cache5 = trim($_POST['cache5']);
$cache6 = trim($_POST['cache6']);

$cache1 = mysql_real_escape_string($cache1);
$cache2 = mysql_real_escape_string($cache2);
$cache3 = mysql_real_escape_string($cache3);
$cache4 = mysql_real_escape_string($cache4);
$cache5 = mysql_real_escape_string($cache5);
$cache6 = mysql_real_escape_string($cache6);

$FetchCache = mysql_query("SELECT * FROM cacheInfo WHERE cacheInfoID='1'") or die('can not find cache information');
$cache1 = mysql_fetch_array($FetchCache);
if($cache1 !==$cache1['cacheCode']){
$url = "/register-cache.php?error=true";        
header("Location: $url");  
}


$FetchCache = mysql_query("SELECT * FROM cacheInfo WHERE cacheInfoID='2'") or die('can not find cache information');
$cache2 = mysql_fetch_array($FetchCache);
if($cache2 !==$cache2['cacheCode']){
$url = "/register-cache.php?error=true";        
header("Location: $url");  
}


$FetchCache = mysql_query("SELECT * FROM cacheInfo WHERE cacheInfoID='3'") or die('can not find cache information');
$cache3 = mysql_fetch_array($FetchCache);
if($cache3 !==$cache3['cacheCode']){
$url = "/register-cache.php?error=true";        
header("Location: $url");  
}

$FetchCache = mysql_query("SELECT * FROM cacheInfo WHERE cacheInfoID='4'") or die('can not find cache information');
$cache4 = mysql_fetch_array($FetchCache);
if($cache4 !==$cache4['cacheCode']){
$url = "/register-cache.php?error=true";        
header("Location: $url");  
}

$FetchCache = mysql_query("SELECT * FROM cacheInfo WHERE cacheInfoID='5'") or die('can not find cache information');
$cache5 = mysql_fetch_array($FetchCache);
if($cache5 !==$cache5['cacheCode']){
$url = "/register-cache.php?error=true";        
header("Location: $url");  
}


$FetchCache = mysql_query("SELECT * FROM cacheInfo WHERE cacheInfoID='6'") or die('can not find cache information');
$cache6 = mysql_fetch_array($FetchCache);
if($cache6 !==$cache6['cacheCode']){
$url = "/register-cache.php?error=true";        
header("Location: $url");  
}
// If all match now run the rest of my code......
}