PHP - Mysql Table Values With Comma
Hello Guys,
I am trying to insert a value in my table like this image.jpg,image2.jpg,image3.jpg Currently it just runs the image names together Here is my code.. I tried to use explode, but it just adds the word "array" in the table. Please advise $filename2 = $phstring; } $csv = $filename2; $fphoto = explode(',', $csv); // Insert ad details into mysql $query = "INSERT INTO ads (ad_type,ad_title,ad_body,ad_category,ad_photo,ad_member,ad_status,ad_city,ad_state,ad_zip)VALUES('".$ad_type."','".$ad_title."','".$ad_body."','".$catid."','".$fphoto."','".$vname."','".$ad_status."','".$city."','".$state."','".$zip."')"; Similar Tutorials
Table Issue - Multiple Location Values For User Pushes Values Out Of Row Instead Of Wrapping In Cell
I have a file that is uploaded by the user that has a series of rows of data in an html table. The columns are always a constant, but the number of rows in the file can change. These rows of the html table are the only information in the file when I am processing it. I need to either convert the file to a CSV file or write the values to a CSV list so that I can then insert them into a database. Any suggestions would be wonderful...I've spent the last three hours spinning my wheels. Here is an example of one row of data from the file: Code: [Select] <tr><td bgcolor=#dddddd class=dataFT >5 (Excellent)</td><td bgcolor=#dddddd class=dataFT >5 (Excellent)</td><td bgcolor=#dddddd class=dataFT >5 (Excellent)</td><td bgcolor=#dddddd class=dataFT > </td><td bgcolor=#dddddd class=dataFT > </td><td bgcolor=#dddddd class=dataFT >DATA</td><td bgcolor=#dddddd class=dataFT >1015020</td><td bgcolor=#dddddd class=dataFT >155498322</td><td bgcolor=#dddddd class=dataFT >DATA</td><td bgcolor=#dddddd class=dataFT >4731751</td><td bgcolor=#dddddd class=dataFT >2011-09-25 11:18:33 (-5:00)</td><td bgcolor=#dddddd class=dataFT >2011-09-25 12:16:50 (-5:00)</td><td bgcolor=#dddddd class=dataFT >0:58:17</td><td bgcolor=#dddddd class=dataFT >0:58:16</td><td bgcolor=#dddddd class=dataFT >DATA</td><td bgcolor=#dddddd class=dataFT >DATA</td><td bgcolor=#dddddd class=dataFT >DATA</td><td bgcolor=#dddddd class=dataFT >Resolved</td></tr> This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=342695.0 I created a simple search box which will query my table and match the input value to one of my columns. two of these columns store comma separated values. if i query a column other than a column which stores my csv i can see my search results. if i query a column which stores my csv i will not see results unless the search value matches the first value within the column. how would i be able to get say the second or third or forth value. here is the code i am using to query the table any help would be appreciated thanks. Code: [Select] $q = $this->db->query("SELECT * FROM table WHERE col1 LIKE 'searchvalue'". " OR col2 LIKE 'searchvalue'". " OR col3 LIKE 'searchvalue'". " OR col4 LIKE 'searchvalue'". " OR FIND_IN_SET('searchvalue', col5) > 0 ". " OR FIND_IN_SET('searchvalue', col6) > 0"); Hello, I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints? Thanks in advance, Vero Hello all, I'm trying to get better at manipulating arrays and I'm stumped on this one. What would be the most efficient way of converting an array such as this: Quote Array ( [3] => 3 [9] => 1 [15] => 9 ) Into this: Quote 3,3,3,9,15,15,15,15,15,15,15,15,15 What gets put in for the values is my problem. I have tried every way I can think of but I get errors in the code or I don't get the row inserted. Can anyone give me a code sample using $ variables, preferably a multi-line list? I would have to fix up my code to show you what I am trying as it is in between tries now. I have to be doing something wrong and may have to put together a simple test script but a working example would be better. Everything I look at on the web shows "xxxxx xxxx" examples not $variables. Thanks in advance. I am trying to give role based access here. I want to display the pages which user has access in checkbox format. Here is my code $sql = "SELECT p.page_id AS pid, p.page, p.href, ra.pages AS rpage FROM pages p INNER JOIN role_access ra WHERE p.page_id IN (ra.page) AND ra.role=1"; $query = mysqli_query($con, $sql) or die(mysqli_error($con)); $checked_arr = array(); while($row = mysqli_fetch_array($query)) { $checked_arr = explode(",",$row['rpage']); foreach ($checked_arr as $page) { echo "<br/><input type='checkbox' name=\"pages[]\" value='$page' />$page<br>"; } My tables are like this ROLE CREATE TABLE `role` ( `rid` int(5) NOT NULL, `role_name` varchar(50) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `role` (`rid`, `role_name`) VALUES (1, 'Admin'), (2, 'Others'); ALTER TABLE `role` ADD PRIMARY KEY (`rid`); ROLE-ACCESS CREATE TABLE `role_access` ( `id` int(10) NOT NULL, `page` varchar(160) NOT NULL, `role` int(7) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `role_access` (`id`, `page`, `role`) VALUES (1, '1,2,3,4,5', 1), (2, '2,4,5', 2); ALTER TABLE `role_access` ADD PRIMARY KEY (`id`); PAGES CREATE TABLE `pages` ( `page_id` int(11) NOT NULL, `code` varchar(10) NOT NULL, `page` varchar(100) NOT NULL, `href` varchar(255) NOT NULL ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `pages` (`page_id`, `code`, `page`, `href`) VALUES (1, 'Patient', 'Registration', '/patient_registration.php'), (2, 'Patient', 'List', '/patient_list.php'), (3, 'Patient', 'Edit', '/edit_patient.php'), (4, 'Patient', 'Export', '/export_patient.php'), (5, 'Patient', 'MRD', '/patient_MRD.php'); ALTER TABLE `pages` ADD PRIMARY KEY (`page_id`);
In above query i get result like this
But required result is
if i change checkbox display like while($row = mysqli_fetch_array($query)) { $checked_arr = explode(",",$row['rpage']); $pname = $row['page']; foreach ($checked_arr as $page) { echo "<br/><input type='checkbox' name=\"pages[]\" value='$page' />$pname<br>"; } } i get result
How to get the names for that file.
Apologies... I'm a noob trying to reverse engineer code. I have a script that can retrieve values from a MySQL database (based on a session login that recognizes which user you are) and places those values into the text fields of a form, pre-populating the form. Code: [Select] <?php mysql_connect('localhost', 'db', 'password'); mysql_select_db('users'); $id = mysql_real_escape_string($_SESSION['userid']); $select = "SELECT * FROM user_info WHERE md5(Member_No) = '$id';"; $query = mysql_query($select); if ($row = mysql_fetch_array($query)) { ?> <form> FIRST name: <input type="text" name="First" value="<?php echo stripslashes($row['First']); ?>" LAST name: <input type="text" name="Last" value="<?php echo stripslashes($row['Last']); ?>" > Birthday: <input type="text" name="Birthday" value="<?php echo stripslashes($row['Birthday']); ?>" <input type="submit" value="Submit"> </form> <?php } ?> I want to be able to connect to that same database and update ALL the values (3 in the example above) with the single click of the form button. I think I was told some time ago that it's not possible to update all the values at once? Thanks, ~Wayne Hello there, i'm not sure if this goes to mysql, or this section, but since it's PHP based, i would say here. So, here's the thing, i have full set up table that reads from mysql database and display it as table. Everything is working just fine, even "order" buttons that i made, now i would like to have below the table some counts, for example: My table name "canonkickoff" has column named "Prevoz" which contain only Yes and No answers, i would like to see below the table how much "Yes" answers are inside the column. Also i have other column called "VelicinaMajice", which contain 6 different answers ( XS, S, M, L, XL, XXL ), i would like to see (again, below the table) how much of every has been answered. Like: There a XS = 6 S = 1 M = 2 L = 3 And 32 answered with Yes. Could anyone help me out? Here's the full php table: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title>CanonKickOff 2012 Tabela.</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> <link rel="stylesheet" href="table.css" type="text/css"> </head> <body style="margin: 0 0 0 0;"> <? include("passwd.php"); @$start = $_GET["start"]; if($start =='') $start =0; include("lib.php"); $link = mysql_connect($host,$username,$password); if (!$link) { die('Could not connect: ' . mysql_error()); } $db_selected = mysql_select_db($db, $link); if (!$db_selected) { die ("Can't use $db : " . mysql_error()); } //total number of records in the table $orderBy = array('Kompanija', 'id', 'ImePrezime', 'Email', 'Prevoz', 'VelicinaMajice', 'SlazemSe'); $order = 'id'; if (isset($_GET['orderBy']) && in_array($_GET['orderBy'], $orderBy)) { $order = $_GET['orderBy']; } $res = mysql_query("SELECT * from `$table` ORDER BY '.$order"); $res2 = mysql_query("SELECT * from `$table` "); @$rows = mysql_num_rows ($res2); $result = mysql_query("SELECT * from `$table` ORDER BY $order limit $start,40"); if (!$result) { die('Invalid query: ' . mysql_error()); } echo 'Sortiraj Po: <br>'; echo '<a href="?orderBy=id">ID:</a> '; echo '<a href="?orderBy=ImePrezime">Ime i Prezime:</a> '; echo '<a href="?orderBy=Kompanija">Kompanija:</a> '; echo '<a href="?orderBy=email">Email adresi:</a> '; echo '<a href="?orderBy=Prevoz">Prevoz:</a> '; echo '<a href="?orderBy=VelicinaMajice">Velicina majice:</a> '; echo '<a href="?orderBy=SlazemSe">Slazu se:</a> '; echo "<p align=center class = 'menu'> Ocitana tabela: $table </p>"; $cols = mysql_num_fields($result); $records = mysql_num_rows ($result); echo "<table align='center' width='1200' >"; echo "<tr bgcolor='BBCCDD' class='menu'>"; for ($i = 0; $i < $cols;$i++) { echo "<td align='center'>".mysql_field_name($result,$i)."</td>"; } echo "</tr>"; while ($row = mysql_fetch_array($result, MYSQL_NUM)) { echo "<tr bgcolor='F6F6F6' class='normal'>"; foreach ($row as $value) { echo "<td align='center'>".$value ."</td>"; } echo "</tr>"; } $end = $start + $records; echo "<tr align = 'center' bgcolor = 'BBCCDD' class='menu'><td colspan=$cols> $start do $end od ukupno: $rows </td></tr>"; echo "<tr align = 'center' class='mylink'><td colspan=$cols> "; if($start != 0) { $prev = $start - 40; echo "<a href='tabela.php?start=$prev'> Prethodna </a> "; } if($start<$rows-10) { $next = $start + 40; echo "<a href = 'tabela.php?start=$next'>Sledeca</a> "; } echo "</td></tr>"; echo "</table>"; ?> </body> </html> Hi all, I have a table... id | Name | Downloads | 01 | tom | 5 02 | thomas | 2 03 | tommy | 15 I need a button in my page whcih on submit would resent the 'downloads' column so all values are set to 0, Is this possible and how if it is? Thanks for any advice Hi, i don't understand how to show ENUM type data in php. Now i use: <input type="text" name="type" style="width: 362px; height: 35px;" value="<?php echo $type; ?>"> But it print only the value that is set to topic i see. How to display all ENUM values in radio buttons and that checked button would be that one from the topic. For example: ENUM ('city','town','vilage') . I select town when writing a topic. And when i edit data i see 3 radio buttons and TOWN would be checked. Thank you for answer. p.s maybe someone know a good site where is a tutorial how to show enum in php I am pulling 5 addresses and I am wanting to store these 5 addresses in columns in a separate table. On the query string I put LIMIT 5. How can I store the results of each of the 5 loops into columns in a separate table? The columns are A1(for name), A2(for address), A3 (for city), A4 (for state), A5 (for zip), A6 (for phone), A7 (for miles), .... then I also have B1-B7, C1-C7, D1-D7, and E1-E7. I am basically wanting to store up to 5 addresses in an array and then update them into a mysql table. Code: [Select] foreach ($zips as $key => $value) { $result = mysql_query("SELECT State FROM extreme WHERE Zip = '$key' AND Type='store' AND `InStore` <> 'NO' LIMIT 5", $db); $num_rows = mysql_num_rows($result); while($myrow = mysql_fetch_array ($result)) { $Dealer=$myrow['Dealer']; $Address=$myrow['Address']; $City=$myrow['City']; $State=$myrow['State']; $Zip=$myrow['Zip']; $Phone=$myrow['Phone']; $Miles = $value; } } I need to some how pull comma separated images $data[23] from this $data array and then put them into there own array so I can insert them into separate rows in a database. This is the provided array: $data[0] => VIN $data[1] => StockNumber ...(all the other number here) $data[23] => Image_URLs (comma seperated) $data[24] => Equipment // I need something like this (obviously doesn't work?!@#) $delimiter = ","; $img = explode($delimiter, $data[23]); foreach($img as $pic){ $sqlPic = "insert into class_prodimages (pid image rank) values('".$LastId['id']."', '$pic', '".rand(1,20)."')"; } Any help here? Hi, My company has 240+ locations and as such some users (general managers) cover multiple sites. When I run a query to pull user information, when the user has multiple sites to his or her name, its adds the second / third sites to the next columns, rather than wrapping it inside the same table cell. It also works the opposite way, if a piece of data is missing in the database and is blank, its pull the following columns in. Both cases mess up the table and formatting. I'm extremely new to any kind of programming and maybe this isn't the forum for this question but figured I'd give it a chance since I'm stuck. The HTML/PHP code is below: <table id="datatables-column-search-select-inputs" class="table table-striped" style="width:100%"> <thead> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> <th>Actions</th> </tr> </thead> <tbody> <?php //QUERY TO SELECT ALL USERS FROM DATABASE $query = "SELECT * FROM users"; $select_users = mysqli_query($connection,$query);
// SET VARIABLE TO ARRAY FROM QUERY while($row = mysqli_fetch_assoc($select_users)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_phone = $row['user_phone']; $user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id'];
// POPULATES DATA INTO THE TABLE echo "<tr>"; echo "<td>{$user_id}</td>"; echo "<td>{$user_firstname}</td>"; echo "<td>{$user_lastname}</td>"; echo "<td>{$username}</td>"; echo "<td>{$user_phone}</td>";
//PULL SITE STATUS BASED ON SITE STATUS ID $query = "SELECT * FROM sites WHERE site_manager_id = {$user_id} "; $select_site = mysqli_query($connection, $query); while($row = mysqli_fetch_assoc($select_site)) { $site_name = $row['site_name']; echo "<td>{$site_name}</td>"; } echo "<td>{$user_title_id}</td>"; echo "<td>{$user_role_id}</td>"; echo "<td class='table-action'> <a href='#'><i class='align-middle' data-feather='edit-2'></i></a> <a href='#'><i class='align-middle' data-feather='trash'></i></a> </td>"; //echo "<td><a href='users.php?source=edit_user&p_id={$user_id}'>Edit</a></td>"; echo "</tr>"; } ?>
<tr> <td>ID</td> <td>FirstName</td> <td>LastName</td> <td>Username</td> <td>Phone #</td> <td>Location</td> <td>Title</td> <td>Role</td> <td class="table-action"> <a href="#"><i class="align-middle" data-feather="edit-2"></i></a> <a href="#"><i class="align-middle" data-feather="trash"></i></a> </td> </tr> </tbody> <tfoot> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> </tr> </tfoot> </table>
Hi all, Just curious why this works: Code: [Select] while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){ $import="INSERT into $prodtblname ($csvheaders1) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]')"; } And this does not: $headdata_1 = "'$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]'"; while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){ $import="INSERT into $prodtblname ($csvheaders1) values($headdata_1)"; }it puts $data[#'s] in the database fields instead of the actual data that '$data[0]','$data[1]'... relates to. I wrote a script to create the values in $headdata_1 based on the number of headers in $csvheaders1 but can't seem to get it working in the sql statement. Thanks How can i save array from inputs, witch is $igraci and it have 5 values, to mysql base, i tryed but in mysql it shows Array. This is form: <form action="dodaj_klan.php" method="post" > <p> <label>Naziv klana:</label> <input name="naziv" type="text" size="20%" /> <label>Web Sajt:</label> <input name="website" type="text" size="20%" /> <label>E-Mail:</label> <input name="email" type="text" size="20%" /> <br /><br /> <label>Igraci klana(5):</label> <input name="lider" type="radio" value="1" /> <input name="igraci[]" type="text" size="20%" /><br /> <input name="lider" type="radio" value="2" /> <input name="igraci[]" type="text" size="20%" /><br /> <input name="lider" type="radio" value="3" /> <input name="igraci[]" type="text" size="20%" /><br /> <input name="lider" type="radio" value="4" /> <input name="igraci[]" type="text" size="20%" /><br /> <input name="lider" type="radio" value="5" /> <input name="igraci[]" type="text" size="20%" /> <label><i>(obelezi lidera klana)</i></label> <br /><br /> <input class="button" type="submit" name="submit" value="Dodaj" /> </p> </form> Now i wonna save this igraci[] array in mysql, i tried like this but it doesn't work: $igraci = $_POST['igraci']; $query = "INSERT INTO klanovi (naziv, website, email, igraci) VALUES ('{$naziv}', '{$website}', '{$email}', '{$igraci}')"; $result = mysql_query($query, $connection); How can i do this? Thanks.. Hi guys I'm having problem on how to display my php mysql result like this.. Digitalpoint, phpfreaks, adsense here's my code Code: [Select] $result = mysql_query ("SELECT dateline, dateline_from, eventid, title FROM vb_event WHERE calendarid = 1 AND dateline_from >= '$day_before' ORDER BY dateline_from LIMIT 2"); while($row = mysql_fetch_array( $result )) { echo "<a href='/forum/calendar.php?do=getinfo&e=" . $row['eventid'] . "&c=1' title='". $row['title'] . "' style='font-size:12px;'>" . $row['title'] . "</a> " ; } the result is Digitalpoint, phpfreaks, adsense, how to remove the "," in the end? it should be like this.. Digitalpoint, phpfreaks, adsense with no , comma in the end.. Thank you.. Hi All,
I want to copy into a table values from another table that partially match a given value, case-insensitively. So far I do as follows but I wonder whether there is a quicker way.
$input_table=array('1'=>'toto','2'=>'tota','3'=>'hello','4'=>'TOTO','5'=>'toto'); $input_table_2 = array_map('strtolower', $input_table); $value_to_look_for='Tot'; $value_to_look_for_2=strtolower($value_to_look_for); $output_table=array(); foreach ($input_table_2 as $k=>$v) { if(false !== strpos($v, $value_to_look_for_2)) { $output_table[]=$input_table[$k]; } }One drawback is that $input_table_2 is 'foreached' whereas there might be no occurrences, which would lead to a loss of time/resources for big arrays. Thanks. Hi All ,
I have a small table with 4 fields namely Day_ID, Dues, Last_Visit, Points. where Day_ID is an auto-increment field. The table would be as follows:
Day_ID -- Dues --- Last_Visit --- Points.
1 --------- 900 -------- 1/12 -------- 6
2 --------- 700 -------- 4/12 -------- 7
3 --------- 600 -------- 7/12 -------- 5
4 --------- 600 -------- 9/12 -------- 6
5 --------- 600 -------- 10/12 ------- 6
6 --------- 600 -------- 14/12 ------- 6
So this is the record of a person's visit to say a club. The last row indicates the last date of his visit to the club. His points on this date are 6. Based on this point value of 6 in the last row I want to retrieve all the previous BUT adjoining all records that have the same Points i.e. 6.
So my query should retrieve for me, based on the column value of Points of the last row (i.e. Day_ID - 6 ), as follows:
4 --------- 600 -------- 9/12 -------- 6
5 --------- 600 -------- 10/12 ------- 6
6 --------- 600 -------- 14/12 ------- 6
This problem stated above had been completely resolved, thanks to a lot of help from Guru Barand by this following query :-
$query = "SELECT cv.day_id, cv.dues, cv.last_visit, cv.points FROM clubvisit cv WHERE last_visit >= ( SELECT MAX(last_visit) FROM clubvisit WHERE points <> ( SELECT points as lastpoints FROM clubvisit JOIN ( SELECT MAX(last_visit) as last_visit FROM clubvisit ) as latest USING (last_visit) ) )";I am using this and it works perfectly except that now there is a slight change in the table because the criteria for points is now dependent on more than one column cv.points and is more like cv.points1, cv.points2, cv.points3 etc. So now I need to make a selection based on each of these cv.points columns. As of now I can still get the results by running the query multiple times for each of the cv.points columns ( seperately for cv.points1, cv.points2, cv.points3) and it works correctly. However I am wondering if there is a better way to do this in just one go. This not only makes the code repetitive but also since the queries are interconnected, involves the use of transactions which I wish to avoid if possible. The values that I require for each of the cv.point columns is 1. day_id of the previous / old day on which the cv.points value changed from the current day value, and 2. cv.points on that old/ previous day. So for example if the table is as below: Day_ID -- Dues --- Last_Visit --- Points1 --- Points2. 1 --------- 900 -------- 1/12 ----------- 9 ------------ 5 2 --------- 600 -------- 4/12 ----------- 6 ------------ 6 3 --------- 400 -------- 7/12 ----------- 4 ------------ 7 4 --------- 500 -------- 9/12 ----------- 5 ------------ 8 5 --------- 600 -------- 10/12 ---------- 6 ------------ 8 6 --------- 600 -------- 11/12 ---------- 6 ------------ 8 7 --------- 600 -------- 13/12 ---------- 6 ------------ 7 8 --------- 500 -------- 15/12 ---------- 5 ------------ 7 9 --------- 500 -------- 19/12 ---------- 5 ------------ 7 Then I need the following set of values : 1. day_id1 -- Day 7, points1 ---- 6, days_diff1 -- (9-7 = 2) . // Difference between the latest day and day_id1 2. day_id2 -- Day 6, points2 ---- 8, days_diff2 -- (9-6 = 3) 3. day_id3 -- .... and so on for other points. Thanks all ! |