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PHP - This Has To Be One For The Books!!!! Php Variable Won't Display In Url
So I have these session variables being stored on login. Each page stores these session variables in local PHP variables. For some reason, all pages display that variable in the URL except one page. I have done some 'echo' work just to ensure variables have values stored and that everything was being read appropriately, no issues there. The variables are apparent everywhere on the page besides the URL. Below you can find all the code I have to make this thing work....maybe someone can point me in the right direction because I am STUMPED!!! LOL
So my first page calls a popup window in javascript defined below. The link involves the following PHP Code: [Select] $customer_id = $_SESSION['cid']; $customer_email = $_SESSION['cust_email']; $customer_fname = $_SESSION['cust_first_name']; $customer_contact_id = $_SESSION['customer_contact_id']; $customer_company_id = $_SESSION['customer_company_id']; $c_project_id = $_GET['pid']; $c_project_id = mysql_real_escape_string($c_project_id ); $c_project_id = eregi_replace("`", "", $c_project_id); Then comes in the Javascript... Code: [Select] <script type="text/javascript"> <!-- $(document).ready(function(){ $(".approval").click(function(){ v = $(this).attr("id"); url = 'deny_approval.php?cid=<?php echo "$customer_id"; ?>&company_id=<?php echo "$customer_company_id"; ?>&customer_contact_id=<?php echo "$customer_contact_id"; ?>&pid=<?php echo "$customer_project_id"; ?>§ion=' + v; window.open(url, "myWindow", "status = 1, toolbar = no, scrollbars = yes, location = no, resizable = no, height = 600, width = 600, resizable = 0" ); }); }); //--> </script> And finally, the HTML.... Code: [Select] <body> <a href="#" id="deny_quote_approval" class="approval">Deny Quote Approval</a><br /><br /> </body> Any ideas?? As always, any help would be greatly appreciated. Bl4ck Maj1k Similar TutorialsHi, i cant seem to get something working, should be simple but its not working for me. I just need to only display a table if a variable in my table = a certain value. The column in the table is called 'option1_available' and if its value is set to 'Y' i want it to display a table. Appreciate any help, Thanks I'm trying to display an html <div> based on the state of a variable set during php execution . The variable is $chk and is set to either 0 or 1 with 0 meaning failed and 1 meaning pass. Here's the code:
if <?php echo "{$chk}";?> == 0
<div class="container">
<div class="row" style="color:red">
<br><br><br><br><br><br>
<center>Database Update Failed</center>
</div>
</div>
else
<div class="container">
<div class="row">
<br><br><br><br><br><br>
<center>Database Updated</center>
</div>
</div>
Thanks in advance, Larry Edited June 19, 2020 by larry29936additioal info I want to retrieve an image id from a db and show the images. I cant get the syntax right for the image tag.Any help appreciated. Code: [Select] function display_covers() { global $wpdb; $query = "select * from wp_cover"; $result = mysql_query($query)or trigger_error("Query: $query\n<br />MySQL Error: " . mysql_error()); echo mysql_error(); if (!$result) return false; echo'<div class="wrap"><p>choose from one of the covers below</p></div>'; echo'<div id="main">'; echo'<table class="main" cellpadding="2">'; //echo"<caption>Please choose a book cover</caption>"; ?> <thead><tr><td colspan="5" ><h6 class="main">Book Covers</h6></td></tr> </thead> <?php $i=0; $size=3; echo "<tbody>"; echo "<tr>"; while ($row = mysql_fetch_array($result,MYSQL_ASSOC)) { /* display picture */ ?> <td class="main"> <?php echo"<img src="/Applications/MAMP/htdocs/wordpress_3/wp-content/plugins/Authors2/jackets/"{.$row['pix'].}""/>"; echo"</td>"; $i++; if($i==$size) { echo "</tr><tr>"; $i=0; } } } This is my code Code: [Select] $file = $file . $line; fclose($fh); echo "<script language= 'JavaScript'>alert(' . $file . ');</script>"; the alert box is not coming up. Please suggest a way to print the contents of the file in a alert box. Using Javascript, how do I do an alert and show the value of a variable? thanks Trying to figure out how to make it so name is a link to the profile when its echo anyone know how to do this? im at a huge stand still Code: [Select] <?php $sql = "SELECT name FROM users WHERE DATE_SUB(NOW(),INTERVAL 5 MINUTE) <= lastactive ORDER BY id ASC"; $query = mysql_query($sql) or die(mysql_error()); $count = mysql_num_rows($query); $i = 1; while($row = mysql_fetch_object($query)) { $online_name = htmlspecialchars($row->name); echo '<a href="Inbox.php">"'[$goauld]'</a>"'; ?> I am building a website that uses session variables extensively. The site is getting a little complicated, and I am starting to lose track of which session variables are assigned, and what their values are. Is there some way where I can create a piece of code that will display all of the existing session variables and their values? Hello wasn't sure where to put this post so if a needs moving please move.
I recently took a break from design due to birth of my daughter, i am coming back to learn php and have
PHP solutions: Dynamic Web Design Made Easy – David Powers
was wondering if it is still a good book to use to learn from.
Thanks
Hey guys, I really need a descent php & mySQL book, but i have just been looking on Amazon and the prices are gay, excuse thee expression : P. I was just wondering if anyone on this forum had any they have finished with that they could like to sell to me for a reasonable price. I probably sound like a bit of a scruff, but i am a student and soon to be a father (literally soon, she is due on the 20th of this month ) so money is tight. lol I know some basic PHP from my college. I wanted to learn WordPress, but before jumping into wordpress I think I should expertise PHP functions and arrays because that what mostly used in WordPress.
Can you recommend me some books/resources where advanced level PHP functions and arrays are discussed. Main Focus is PHP Functions, advanced level.
I know some basic PHP from my college. I wanted to learn WordPress, but before jumping into wordpress I think I should expertise PHP functions and arrays because that what mostly used in WordPress.
Can you recommend me some books/resources where advanced level PHP functions and arrays are discussed. Main Focus is PHP Functions, advanced level.
I am attempting to us glob to display contents of a users folder using a session variable. Example: I have a session variable called department Code: [Select] $row_fullname['department']; In department I have the name of the department the user belongs to such as: office, plant, maintenance, and groundskeeping I created a folder called docs inside of docs there are 4 subfolders called office, plant, maintenance, and groundskeeping I found this code which will display the contents of the folder: Code: [Select] <?php $files = glob( './docs/office/*.*' ); foreach ( $files as $file ) { echo '<a href="./docs/office/' . basename( $file ) . '"target="_blank">' . basename( $file ) . '</a><br />'; } ?> The above code works fine, but I would like it to only display the contents of a departments folder only if the user is part on that department. Here is an example that I know is completely wrong but it may help explain what I am trying to do. Code: [Select] <?php ]<?php $files = glob( './docs/echo $row_fullname['department'];/*.*' ); foreach ( $files as $file ) { echo '<a href="./docs/echo $row_fullname['department'];/' . basename( $file ) . '"target="_blank">' . basename( $file ) . '</a><br />'; } ?>Thanks for your time I am working on a website which sells various content, including books/guides in an online format. A lot of people - including here - have stated that they wouldn't make a purchase on my site if I didn't also offer a PDF version of books/guides. (I guess more people read offline than I do personally?!) Right now, I am working on the ecommerce portion so people can browse a catalog, choose a book/guide, add it to their cart, and check out. (Just your textbook ecommerce metaphors.) After making a purchase, when someone logs in, then they can navigate to a gallery which contains thumbnails representing all of the books they have purchased. And by clicking on a given thumbnail, they will be taken to that particular online book which is a series of linked web pages protected from outsiders behind a paywall. I am comfortable with all of this, however I'm stuck on what to do with the PDFs... First off, when someone is in the Product Catalog picking out books and guides, should I give them the chance to specify if they want a PDF version, or should I just give everyone that buys a book/guide both access to the online book/guide PLUS the PDF version as well? Next, for customers who get a PDF, how should I deliver it to them? Do I make the PDF available when they navigate to their online book? Do I build a second gallery which only shows PDFs that have been purchased? Do I leave links to the PDFs up indefinitely, or should I just offer a one-time download? And if so, how would I go about that? In summary, something that seems so simple actually is very confusing the more I think about it. This is probably because I have never bought online books or PDFs before and so I don;t have any examples in my mind to go off of. Could definitely use some advice here, and am hoping this won't be as difficult as it currently seems?! Thanks.
This topic has been moved to Other Libraries and Frameworks. http://www.phpfreaks.com/forums/index.php?topic=307986.0 This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=334128.0 I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment. My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted." The program should not accept any numbers greater than 100 or any characters. Once I do this, I must take a second number and do a similar thing. Finally, I must have a statement show up at the bottom stating which number is greater. Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters. Any help you can provide will be greatly appreciated! My login script stores the user's login name as $_SESSION[ 'name'] on login. For some unapparent reason, i'm getting errors stating that $user and $priv are undefined variables, though I've attempted to define $user as being equal to $_SESSION['name'], using $user to look up the the user's privilege level (stored as the su column ) in the SQL table, and then where the result of the sql query is $priv which is then evaluated in an if statement. I can't seem to figure out why this might not be working. The code I'm using:
<?php
session_start();
function verify() {
//verify that the user is logged in via the login page. Session_start has already been called.
if (!isset($_SESSION['loggedin'])) {
header('Location: /index.html');
exit;
}
//if user is logged in, we then lookup necessary privleges. $_SESSION['name'] was written with the login name upon login. Privleges // are written in db as a single-digit integer of of 0 for users, 1 for administrators, and 2 for special users.
$user === $_SESSION['name'];
//Connect to Databse
$link = mysqli_connect("127.0.0.1", "database user", "password", "database");
if (!$link) {
echo "Error: Unable to connect to MySQL." . PHP_EOL;
echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL;
echo "Debugging error: " . mysqli_connect_error() . PHP_EOL;
exit;
}
//SQL Statement to lookup privlege information.
if ($result = mysqli_query($link, "SELECT su FROM accounts WHERE username = $user", MYSQLI_STORE_RESULT)) {
//LOOP TO CYCLE THROUGH SQL RESULTS AND STORE Privlege information as vairable $priv.
while ($row = $result->fetch_assoc()) {
$priv === $row["su"];
}
}
// close SQL connection.
mysqli_close($link);
// Verify privleges and take action. Only a privlege of "1" is allowed to view this page. A privlege of "2" indicates special
//accounts used in other scripts that have certain indermediate additional functions, but are not trusted administrators.
if ($priv !== 1) {
echo $_SESSION['name'];
echo "you have privlege level of $priv";
echo "<br>";
echo 'Your account does not have the privleges necessary to view this page';
exit;
}
}
verify();
?>
I have just re-installed Xampp and suddenly my sites are now displaying lots of: Notice: Use of undefined constant name - assumed 'name' in ... Notice: Use of undefined constant price - assumed 'price' in ... this is an example of the line its refering too: $defineProducts[1001] = array(name=>'This is a product', price=>123); Hello everyone, I can get Test 2 to successfully operate the if statement using a variable variable. But when I try the same method using a session variable (Test 1) the if statement is not executed. Please could you tell me why the if statement in Test 1 is not being executed? Code: [Select] <?php # TEST 1 $_SESSION[test_variable] = "abcd"; $session_variable_name = "_SESSION[test_variable]"; if ($$session_variable_name == "abcd") { echo "<br>line 373, abcd<br>"; } # TEST 2 $test_variable = "efgh"; $test_variable_name = "test_variable"; if ($$test_variable_name == "efgh") { echo "<br>line 379, efgh<br>"; } ?> Many thanks, Stu |
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