PHP - Check For Letters And Spaces

How in php using the preg_replace php function can i allow only the basic english a-z letters, numbers 0-9 and unicode code letters and remove anything else?

Does anyone knows if FPDF supports Norwegian letters or not? When I write codes of letters it is not showing letter. Are there any command to specify charset?
For example in this code is it possible to specify charset?

$pdf=new FPDF();
$pdf->AddPage();

$pdf->SetFont('Arial','',14);
$pdf->Write(5,'F&#248lgende ');

Hello,

I have a script coded in PHP and alot of JavaScript and I have problems with

languages like Arabic and Hebrew ( non Latin characters) ..

It is showed as question marks in the website like this ( ?????????) and in the database ..

I converted the SQL Database from Latin Swedish to UTF-8 in phpmyadmin and now the database is correct but the website is still in question marks .

In every HTML code you can see this :

........... content="text/html; charset=utf-8"/>

and I tried changing the same php pages to UTF-8 using text editors but nothing happened .

any help will be great. thanks.

Would someone tell me how to allow foreign letters, normal english letters and numbers using the preg_replace php function?

I forgot my password for my old account so had to create a new one. New laptop.    Anyway, I've searched and searched but can't find a jQuery, javascript or anything else to do what I want to do. I want to fade out all the different paragraphs of a div one letter at a time starting with the first.    Here is something CLOSE though the string has to be input. I'm pulling data in from a database with PHP. So not sure if I can target individual letters in different paragraphs. 

$(function () {
    var string = " David";
    var q = jQuery.map(string.split(''), function (letter) {
        return $('<span>' + letter + '</span>');
    });

    var dest = $('#fadeIn');

    var c = 0;
    var i = setInterval(function () {
        q[c].appendTo(dest).hide().fadeIn(1000);
        c += 1;
        if (c >= q.length) clearInterval(i);
    }, 1000);
});

I know I can get my target from a div then split it into characters with something like this: 

function arrayMe(string) {

	// For all matching elements
	$(string).each(function() {

		var myStr = $(this).html();

		myStr = myStr.split("");

		var myContents = "";
		for (var i = 0, len = myStr.length; i < len; i++) {
			myContents += '' + myStr[i] + '';
		}

		$(this).html(myContents);
	});
}

Then call the function:

$('document').ready(function() {
	var myStringType = $('.sample-text');
	arrayMe(myStringType);
});

Where my div as a class of sample-text. (These are just code snippets I have pulled from the net in my search for an answer).   But using the fade in which nice in jsfiddle, How can I put all these together to fade out my text a single letter at a time? I'm not sure if different paragraphs will work or not or if I'm going to have to have one long paragraph (bad for my application).    Thanks for the help here guys. You've always come through for me before. It's just been awhile since I've been stumped. 

This topic has been moved to PHP Regex.

http://www.phpfreaks.com/forums/index.php?topic=331361.0

I'm looking for a method to replace everything between brackets.

The patterns that I'm looking for are defined: "/\[([2-9TJQKA][hdcs])\]/"
The pattern inside the bracket could accur 2 or even 3 times inside the brackets.

For example first occurance would be [Ac Kd], here I want to replace Ac into an imge and Kd too.
Later in the text I will most of the time get 3 sets, instead of two: [Jc Td 9d]. The sets always consist of [2-9JQKA][hdcs] and also in this order.
Another example: [2d 2s 2h], or [3s 4h 5c].

If I use the following function, it would not work optimally because some texts do contain some of those sets which should not be converted, ONLY the sets between the brackets:
 

$haystack = setReplace($haystack);

function setReplace($haystack)
{
   $array = array("2s", "2h", "2d", "2c", 
	  	  "3s", "3h", "3d", "3c",
		  "4s", "4h", "4d", "4c",
		  "5s", "5h", "5d", "5c",
		  "6s", "6h", "6d", "6c",
		  "7s", "7h", "7d", "7c",
		  "8s", "8h", "8d", "8c",
		  "9s", "9h", "9d", "9c",
		  "Ts", "Th", "Td", "Tc",
		  "Js", "Jh", "Jd", "Jc",
		  "Qs", "Qh", "Qd", "Qc",
		  "Ks", "Kh", "Kd", "Kc",
		  "As", "Ah", "Ad", "Ac");
		
   for($i=0;$i < count($array);$i++)
   {	
	$result = str_replace($array[$i], "<img src=\"/images/".$code[$i].".png\">",$haystack);
   }
			
return $result;
}

Any ideas?
Edited by dde, 20 January 2015 - 10:21 AM.

Maybe it's a Regex question, but I'm wondering how one would go about generating alphanumeric passwords that do not contain either the letters 'oh' or 'el', or the numbers 1 (one) or 0 (zero)?

In other words, the p/w can contain any letters of the alphabet - apart from 'oh' and 'el' - and any digits from 2 to 9 inclusive.

The p/w length is not critical - let's say 8 characters.

Thanks in advance for your help.

I'm certain this has been done a hundred times before, but I have been unable to find any information on an efficient way of doing this:

I'm creating a membership system, and the password for new users needs to contains both numbers and letters.  How do I go about checking this?  The key is not that it contains only numbers and letters, but that it contains both.  The password cannot be all letters or all numbers.  Know what I mean?

  Cheers guys and gals.

Can I somehow mix letters with numbers to create an array with range()?

e.g. I want my array for postcode ranges such as array('AB1','AB2', 'AB3', 'AB4', 'AB5', 'Ab6', 'AB7', 'AB8', 'IV5', 'IV6', 'IV7', 'IV8', 'IV9', 'IV10');

I know I can do range(1,8); but was wondering if there was something along the lines of range("AB1", "AB8");

My script forces all names to start with a capital and lower case for the rest.  However, some names have a ' or - in them.

For example:

Rosie O'Donnell

or

Carrie-Anne Moss

With the script, the "D" in O'Donnell is lower case and the "A" in Anne is lower case.

What do I need to do to make them capital?

Here is what I am using:

Code: [Select]
<?php echo ucwords(strtolower($row_persons['last_name'])) ?>, <?php echo ucwords(strtolower($row_persons['first_name'])) ?>

I need users to input ONLY  numbers or letters with numbers.  How can i go about fixing that.


Thank you.

Say I have a string (stored in a variable we'll call $mystring) that could be something like this...

"cat / dog / monkey / / / / / / / /"

Or this string could also have no real data in it, in which case it would look like...

"/ / / / / / / / / /"

QUESTION:  What is the easiest/most efficient way to run a check on that string to see if there are any non-slash characters in it.  In plain english, the check would say, "Are there any letters in this string, or is it only spaces and slashes?"

Any ideas?

Hi,

Does anyone know how to create a php file which will ask the user to enter three random characters from their pre-selected word. It would be like with online banking where you have to enter for example letters 2, 4 and 5 from your memorable data.  Any help would be greatley appreciated.

Thanks

This topic has been moved to JavaScript Help.

http://www.phpfreaks.com/forums/index.php?topic=318062.0