PHP - How To Code 2 Queries With 'if' Statement?

I have this simple form that registers schools. This year I have decide to upgrade and include a feature that checks if the school is already registered or not based on the imputed name. Here is the code (that is the only way I know how):


mysql_connect("", "", "") or die(mysql_error( '' ));
mysql_select_db("") or die(mysql_error( '' ));

$query  = "SELECT * FROM School_Registrations WHERE School_Name= '$_POST[SchoolName]' ";
$result = mysql_query($query);
if (mysql_numrows($result) > 0) {
while($row = mysql_fetch_array($result))

echo" error code here";} 

else {mysql_query("INSERT INTO `database`.`School_Registrations` (all the variables here);") 
or die(mysql_error( '' ));  
 
echo "Success Code";}



I am trying to incorporate this code somewhere into the 'else' statement but I have no luck. I am constantly getting some errors and when I fix one there is one more to take its place. I am lost. The last one I can not fix and I am not sure what it wants from me:

Fatal error: Call to undefined function getPage()

It works by itself without the if/else statement but not in the code listed above


$url = 'http://www.otherpage.com/page.php?';
$url .= 'email='.urlencode($_POST['email']);
 
$result2 = getPage('', $url, '', 15);
 
function getPage($proxy, $url, $header, $timeout) {
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_HEADER, $header);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_PROXY, $proxy);
    curl_setopt($ch, CURLOPT_HTTPPROXYTUNNEL, 1);
    curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
    curl_setopt($ch, CURLOPT_REFERER, 'http://azsef.org');
    curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.0.8) Gecko/2009032609 Firefox/3.0.8');
    $result2['EXE'] = curl_exec($ch);
    $result2['INF'] = curl_getinfo($ch);
    $result2['ERR'] = curl_error($ch);
    curl_close($ch);
    return $result2;
}



Can you tell me why doesn't it work?
Thanks

I'm having issues with the following:

Code: [Select]
<?php
session_start();
$_SESSION['username']=$_POST['username'];
$_SESSION['password']=$_POST['password'];
if($_SESSION['username']=="username" && $_SESSION['password']=="password"){
if($_GET['product']=="add"){
$content.='
<p><label>Product Name:</label> <input type="text" name="product_name" size="30" />
<label>Product Price:</label> <input type="text" name="product_price" size="5" />
</p>
<p><label>Product Category:</label> <input type="text" name="product_category" size="30" /></p>
<p><label>Product Link:</label> <input type="text" name="product_link" size="30" /></p>
<p><label>Product Image:</label> <input type="text" name="product_image" size="30" /></p>
<p><label>Product Tag:</label> <input type="text" name="product_tag" size="30" /></p>
<p><label>Product Keywords:</label> <input type="text" name="keyword" size="30" /></p>
<p><label>Product Features:</label><br />
<textarea name="product_features" rows="10" cols="60"></textarea>
</p>
<p><label>Product Pros:</label><br />
<textarea name="product_pros" rows="5" cols="30"></textarea>
</p>
<p><label>Product Cons:</label><br />
<textarea name="product_cons" rows="5" cols="30"></textarea>
</p>
<p><label>Product Description:</label><br />
<textarea name="product_description" rows="10" cols="60"></textarea>
</p>
<p><label>Product Notes:</label><br />
<textarea name="product_notes" rows="5" cols="30"></textarea>
</p>
';
$logout='<div><a href="./acp_admincp.php?log-out">Log-Out</a></div>';
}
elseif($_GET['product']=="view"){
}
else{
$content.='
<a href="./admincp.php?product=add">Add New Product</a>
<br />
<a href="./admincp.php?product=view">View Products</a>
';
}
}
elseif(isset($_GET['log-out'])){
session_start();
session_unset();
session_destroy();
header("Location: ./admincp.php");
}
else{
$content='
<form action="./admincp.php" method="post">
<p><label>Username:</label> <input type="text" name="username" size="30" />';
$content.='</p>
<p><label>Password:</label> <input type="password" name="password" /></p>';
$content.='<p><input type="submit" value="Submit" name="Submit" /></p>
</form>';
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<base href="http://ghosthuntersportal.com/" />
<title>Ghost Hunter's Portal - Admin Control Panel</title>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<meta name="verify-v1" content="" />
<meta name="keywords" content="ghost, hunters, hunter, ghosts, spirit, spirits, paranormal, investigation, investigator, investigators, k2, emf, meter, kii" />
<meta name="description" content="Ghost Hunters Potal. Parnormal research equipment store." />
<meta name="author" content="Andrew McCarrick" />
<meta name="robots" content="index, follow"
<link rel="stylesheet" type="text/css" href="style.css" />
</head>
<body>
<img src="./logo.png" alt="Ghost Hunter's Portal Admin Control Panel" />
<br />
<div style="color: #AA44AA; font-size: 26px; margin-top: -30px; margin-left: 125px;">Admin Control Panel</div>
<?php
echo $logout;
echo $content;
?>
</body>
</html>

I can log-in, and get to the page with the two links on it. However, once I click one of the links it falls back to the log-in page, and it ends up being a never ending loop.

It's doing this:
Log-In --> Page with links ---> Log-In page again

Should be doing this:
Log-In --> Page with links --> Add Product page or View Products page

I can never get into the the actual sub page.

Just to be clear, the address bar actually shows product=add or product=view, but it still shows the log-in page.

Hello all,

I've tried several ways to calculate a commission in the multi level marketing script, but it all ended up with nothing, recursive functions, nested sets nothing worked, and i'm running out of time to keep trying

I've made multiple queries on the same table, and it's working, but only the first 3 queries, not more, I tried to perform it 4 times (although I need the queries to be performed 13 times) but still only 3 times

example: A recruited B and C, and B recruited D, and D recruited E.... what's supposed to happen is A takes a commission on B, C, D, and E
but now it only takes commission on the first three, and no commission for anyone comes after that, and the same for B, C, D, and E each takes commission on only 3 members down the line, and no more

here is the queries

Code: [Select]
<?
 $result = mysql_query("SELECT * FROM users");


echo "<table width='589' border='1'>
<tr>
<th>ID</th>
<th>Name</th>
<th>National ID</th>
<th>Commission</th>
</tr>";

while($row = mysql_fetch_array($result))
  {
 
$query = mysql_query("SELECT * from users where recruiteris = '".$row['id']."'");
$num_rows=mysql_num_rows($query);

              $id1 = $row['id']; 
               
                $commission = $num_rows;
               
               
            $_SESSION['id1'] = $id1;
               
  echo "<tr>";
  while ($roww = mysql_fetch_array($query))
  {
  $querry=mysql_query("select * from users where recruiteris = '".$roww['id']."'");
    $num_rowss = mysql_num_rows($querry);
  while ($rowws= mysql_fetch_array($querry))
   { $var3= '10';

  $querrys=mysql_query("select * from users where recruiteris = '".$rowws['id']."'");
    $num_rowsss = mysql_num_rows($querrys);
   while ($rowwss= mysql_fetch_array($querrys))
   
   {
    $querryss=mysql_query("select * from users where recruiteris = '".$rowwss['id']."'");
    $num_rowssss = mysql_num_rows($querryss);
   while ($rowwsss= mysql_fetch_array($querryss))
   {
   
   
    $querryr=mysql_query("select * from users where recruiteris = '".$rowwsss['id']."'");
    $num_rowssr = mysql_num_rows($querryr);
    }
    }
    }
    }
    $total= ($commission + $num_rowws + $num_rowwss + $num_rowwsss + $num_rowss + $num_rowssr) * $var3;
 echo  "<td><a href=\"user.php?id=".$row['id']."\">".$row['id']."</a></td>";
echo "<td>" . $row['fname'] .''. $row['lname'] ." </td>";
 echo"<td> ". $row['nid'] ." </td>";
  echo  "<td>".$total."</td>
   </tr>";
  }
 
echo "</table>";
        ?> 

Good day everyone. I go by the nickname Sbosh and I am a newbie in PHP.

I am currently learning php using video tutorials. I need help with regards to php queries.

I have the following code:

"SELECT 'food', 'calories' FROM 'diet' ORDER BY 'id'"

which is supposed to display content from a table inside phpmyadmin which i created manually using phpmyadmin. But It gives an error saying i must check the MariaDB version on how to right this query, something like that.

Please assist on the proper way of writing this code. Again I am a newbie in PHP and just starting to learn, so your help will be highly appreciated.

ive had these queries working okay until i checked on it today, it's not working anymore..
these are the errors:::
Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\wamp\www\arrastre\add.php on line 105
Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\wamp\www\arrastre\add.php on line 117


if(isset($_POST['add'])){
if($billnmbr=="" or $orno=="" or $payor=="" or $arrastre=="" or $wharfage=="" or $total=="" or $date=="" or $tcl==""){
echo "At least one field was left blank.";
}
else{
$query = mysql_query("select * from `arrastre` WHERE `billnmbr`='$billnmbr'"); /*****************this is my line 105************/
$count = mysql_num_rows($query);
if($count==1){
echo "This billnumber is already in the database.";
}

else{
$bll = strtoupper($billnmbr);
$payr = strtoupper($payor);
$query="insert into `arrastre` (`billnmbr`, `orno`, `payor`, `arrastre`, `wharfage`, `total`, `date`, `tcl`)
values ('$bll', '$orno', '$payr', '$arrastre', '$wharfage', '$total', '$date', '$tcl')";
$result=mysql_query($query);

$query = mysql_query("select * from `arrastre` where `billnmbr`= '$billnmbr'", $link); /************and this is my line 117*************/
$count = mysql_num_rows($query);
if($count==1){
echo "last bill number added: ".$billnmbr;
}
}
Thank you very much for your time and have a nice day.

Hey guys - me again!

I have a discount box, where i wish to check two "if" queries.  These are i) the 'uniquecode' and ii) the 'uses' - so a code can only be used a set amount of times.

1) How do i state that question in php, bearing in mind the "if uses > 0" needs to relate to the same row as the unique code entered?

2) Also, i have stored the session price in $_SESSION['sessionprice'] - is this the best way to do this, and if not how should i store the current price. 

3) Lastly, and how do I do the php mathematics of "$_SESSION['sessionprice'] minus the discount" - again bearing in mind the "discount" needs to relate to the same row as the unique code entered? (as different codes will have different discounts).


This is how far i've gotten:

Code: [Select]
<?php
//connection settings bla bla bla

$uniquecode = $_POST['discountcode'];

mysql_connect($localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");

$discountcodecheck = mysql_query("SELECT uniquecode FROM discounttable WHERE uniquecode = '".$uniquecode."'");
$remainingusescheck = mysql_query("SELECT uses FROM discounttable WHERE uniquecode = '".$uniquecode."'");

if (mysql_num_rows($discountcodecheck) > 0) and if (mysql_num_rows($remainingusescheck) > 0)  // <-- this "and if" doesn't work
{
// discount calculation:
// session price minus the unique code's corresponding discount
// update $_session['discountammount']

}
else
{
?><script type="text/javascript">
alert("Discount Code Entered Is Either Not Valid Or Has Been Previously Used.");
        history.back();
      </script><?php
}

// rest of code and close connection
?>

Any help or comments will, as always be politely welcomed and appreciated

Cheers,

Tom.

Hi,

noob question: I have following two queries I'd like to combined into one - how is this done?

$temp = @mysql_query("SELECT * FROM purchased_leads WHERE leadID = '{$_REQUEST[leadid]}'");

"SELECT refundNotes FROM leads WHERE leadID = '{$_REQUEST[leadid]}'"

Hi everyone

I have the following PHP code

$sql.= "INSERT INTO `data` (`info`, `write`, `date`) VALUES";
$sql.= "(";
        for ($c=0; $c < $num; $c++) {
$sql.= '"'.str_replace('"', "", $data[$c]).'",';
        }
$sql.= "'".date('Y-m-d')."');";

If I

print $sql;

I get

Code: [Select]
INSERT INTO `data` (`info`, `write`, `date`) VALUES("data99","n",'2010-10-05');
INSERT INTO `data` (`info`, `write`, `date`) VALUES("data101","y",'2010-10-05');
INSERT INTO `data` (`info`, `write`, `date`) VALUES("data876","n",'2010-10-05');
what would I need to do to my PHP code in order for it to process each QUERY either all at once or one at a time

Whatever I try, it either inserts nothing, or just does the first INSERT

Any ideas?

Thanks

I've been playing around with PDO lately, and I've been trying to get use to the basic functions as I've mentioned in some of my other posts/questions. Recently I switched to the ? bind/token (can't remember it's called), so I reformatted my processQuery. I've also tried to add in a fetching option in the method, but I can't seem to get anything to work.

I've looked up several internet tutorials but it seems like I'm doing everything the same. Yet, the query doesn't seem to run. :/

$database->processQuery2("INSERT INTO test (test, testa) VALUES (?, ?)", array('noob', 'newb2'), false);

Now for my method:


public function processQuery2($query, array $binds, $fetch)
    {
        $query_handle = $this->dbc->prepare($query);
        
        if(count($binds) > 0)
        {
            $i = 1;
            $value = array();
            
            foreach($binds as $bind)
            {
                $query_handle->bindParam($i, $value[$i]);
                $value[$i] = $bind;
                $i++;
            }
        }
        $query_handle->execute();
        
        //if($fetch == true)
        //{
            //return $query_handle->fetchAll();
        //}
    }


Any reasons to why it's not working? No errors are outputted, either.

Here is the original query:

Code: [Select]
$query_extract = mysql_query("SELECT downloads,date,title,username,views,id FROM skins ORDER BY id DESC LIMIT 100");

Is it possible to also grab the row username from the table users, without making multiple queries?

Hi all,

I've built a few amateur sites in the past but am keen to utilize php combined with mysql for my current project.  However, I have little knowledge of php and am just picking it up as I go (same way I've done for all my computer knowledge)

What I'm looking for may sound simple, but I really don't know where to start and I'm hoping there are some kind souls here that will lend a hand.  I've got some fantastic help here before and am hoping I'll get lucky again.

SQL Database
meetingid venue
001 new york
002 chicago
003 new york
004 new york
005 new york
006 texas
007 texas
008 chicago
009 new york
010 new york

Question
If I hard code everything around it, I'm just looking for the code I would need to have it display as follows: (hard coded text in blue)

"New York has been used * times." 
(Where * would count the number of times "New York" appears in the venue column of the database.)
"The most consecutive times New York has been used is % ." 
(Where % would count the maximum number of consecutive times "New York" appears in the venue column of the database.)

Giving the output:
New York has been used 6 times.
The most consecutive times New York has been used is 3.

whats the differance between

mysql_query("UPDATE banned SET time

and doing

$safe4 = "UPDATE banned SET time
mysql_query($safe4);


is there a reason as to why do it the 2nd way i mentioned?

if someone could please explain it to me so i wont be in confusion on this anymore

   // Check for this userID if exsist in cp_credits
   $sql = "SELECT * FROM `cp_credits` WHERE account_id = $userid";
   
   // Execute Query
   $r = mysqli_query($dbc, $sql);
   
   
   // If there are result in $r
   if($r){
      // Print a message indicating success or not:
      while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)){
      $user_balance           = $row['balance'];
      $user_last_donation_date = $row['last_donation_date'];
   }
   }
   else{
   $user_balance = "nothing";
   $user_last_donation_date = "nothing";
   }

but either of my else statement does not work. Whats wrong with this?

Can any boy clarify these queries.
How do I find out if an array has values posted to each of its elements? I need to know that EVERY element has been filled out.
How can I send variables from a PHP script to another URL using POST without using forms and hidden variables?