PHP - Possible To Insert A Space Between A Lowercase And Capital Letter?
okay so this is a pretty weird one but if it's possible it would be a much easier solution that the road I'll have to take.
Is it possible to code for.. $description = insert a space between a lowercase and uppercase letter is found together and not currently having a space.. within the first 50 letters of the description. Code: [Select] if (substr($description,0,50) ?..... Thanks! Similar TutorialsHi everyone, I have a script below, which uplads an image, however, the image name always starts with a capital letter, I want all letters to be small, how to adjust this please, thank you
$target_dir = ""; $target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]); $target_file = "$get_current_user.jpg"; $uploadOk = 1; $imageFileType = strtolower(pathinfo($target_file,PATHINFO_EXTENSION)); // Check if image file is a actual image if(isset($_POST["submit"])) { $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]); if($check !== false) { echo ""; /// was File is an image $uploadOk = 1; } else { echo "File is not an image<br>"; $uploadOk = 0; } } // Check file size if ($_FILES["fileToUpload"]["size"] > 10000000) { echo "Sorry, this image is too large, please resize using Paint<br>"; $uploadOk = 0; } // Allow certain file formats if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg" && $imageFileType != "gif" ) { echo "Only JPG, JPEG, PNG & GIF files are allowed<br>"; $uploadOk = 0; } // Check if $uploadOk is set to 0 by an error if ($uploadOk == 0) { echo "There was an error<br>"; } else { if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) { echo "Uploaded successfully (You may need to clear Cache to see the new image)"; mysql_query("UPDATE user SET user_image = 'https://.../images/users/$get_current_user.jpg' WHERE user_name = '$get_current_user' "); } else { echo ""; /// was Select a suitable image, file not uploaded yet } }
I have a table with postcodes in it. At some point some of the codes will be entered with spaces (LA12 5TH) and some without (LA17HU) what i need is a function to check if there is a space, if not - count back 3 characters from the end of the string and insert a space. I don't know which string function to use - looked at pad but that seems to be for either end of string and not the middle - any ideas? hello, im trying to see if there is a function that can get the value of the last row in mysql and see what is in field initial (this is letters A-Z) and make it one letter higher. then, when it reaches letter Z, wrap around to A again. i am trying to convert all keys to lowercase and i was wondering if it is really possible to do using array_map to convert all keys to lowercase or using array_reduce.
what i am trying to do is to gather details from keys and display it on the page as links that redirect to the details page, i managed to convert it into lowercase, however it did not gather the records mainly due to keys being capitalised and me trying to gather those records using lowercase.
to put things into perspective here is the code: <?php $cakesmade = array(); $cakesmade = array( "kate" => array( "cake" => array( "cakeingredients" => "egg, flour"), "Lovely Chocolate Cake" => array( "cakeingredients" => "chocolate, eggs, flour"), "amazing cake" => array( "cakeingredients" => "lemons, flour") ), ); ?>//links <?php foreach($cakesmade as $id => $donecake) foreach($donecake as $bakedcake => $description) { echo "<a href='/user/$id/baked/$bakedcake'>$bakedcake</a>" } ?> My script forces all names to start with a capital and lower case for the rest. However, some names have a ' or - in them. For example: Rosie O'Donnell or Carrie-Anne Moss With the script, the "D" in O'Donnell is lower case and the "A" in Anne is lower case. What do I need to do to make them capital? Here is what I am using: Code: [Select] <?php echo ucwords(strtolower($row_persons['last_name'])) ?>, <?php echo ucwords(strtolower($row_persons['first_name'])) ?> Morning all, I'm trying to query a user table and am receiving errors. In the mysql statement I am trying to SELECT all data from the table that matches the username of the person logged in. The error I am receiving is this: Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\123\myaccount.php The database query is written correctly, if I am logged in as the user Admin then I recieve this message as well: Unknown column 'Admin' in 'where clause' from the or die(mysql_error());. In the database the username is: admin but I can login using Admin, is this an issue of upper and lowercase? The PHP code is below: Code: [Select] <?php require_once('connect.php'); $query = mysql_query("SELECT * FROM user WHERE username = $_SESSION[gatekeeper]"); while ($row = mysql_fetch_array($query) or die(mysql_error())); { echo"<div class='BlockContent'>"; echo" <table id='UserList'>"; echo" <tr>"; echo" <th>My Account</th>"; echo" </tr>"; echo" <tr>"; echo" <td id='left'>"; echo" </td>"; echo" </tr>"; echo" </table>"; echo"</div>"; } ?> Our professor in PHP Programming is very choosy that he requires us to verify if the user enter the UPPERCASE format of the user name registered the program will show an invalid user. What he's trying to say is the user must enter a 100% identical to the username he registered. If the username registered is LOWERCASE he must enter a LOWERCASE username if the username registered is UPPERCASE he must enter an UPPERCASE username to LOGIN. I've figured out how to change all of an arrays keys to lowercase: $lower_case_array = array_change_key_case($mixed_array, CASE_LOWER); But I can't seem to find a way to change the values of an array to lower case. Is there a simple way to do this? Hi. I have a standard HTML multiform working. Inputs from here goes into a MySQL table, and is re-used in the website. I want all inputs saved in the database as capital letters, to get a more clean overview, both in the database and on the website. I would also like to know where to insert this new line of code (if any) The first form input field looks like this: <input type="text" name="artist"/> Best regards Morris In querying my database, I'm Selecting nameFirst and nameLast, and it produces a name like Joe Smith. I'm trying to match a photo with the name. Right now I'm uploading photos into a folder naming the file (e.g. SmithJoe.jpg). For reasons that involve writers being able to upload and access photos, I'm trying to use an image plugin. When uploading photos, it strips capital letters, so SmithJoe,jpg goes in as smithjoe.jpg, and it's not matching my database query. Here is the code I'm working with that works quite well with this one exception: $query = 'SELECT * FROM wp_playerRank'; $results = mysql_query($query); while($line = mysql_fetch_assoc($results)) { if ($line['wpID'] == $wp_tagID) { echo '<div class="player">'; // Here is the code that produces the image. I need to get rid of capital letters for ease of use echo '<div><img src="/wp-content/uploads/' . $line['nameLast'] . $line['nameFirst'] . '.jpg"></div>'; echo '<div class="playerData">' . $line['height'] . ' '; if ($line['position'] == 'PG') {echo 'Point Guard';} elseif ($line['position'] == 'SG') {echo 'Shooting Guard';} elseif ($line['position'] == 'SF') {echo 'Small Forward';} elseif ($line['position'] == 'PF') {echo 'Power Forward';} elseif ($line['position'] == 'C') {echo 'Center';} echo '</div>'; echo '<div class="playerData">' . $line['hschool'] . '</div>'; echo '<div class="playerData">' . $line['summer'] . '</div>'; echo '<div class="playerData">Class of ' .$line['year'] . '</div>'; if ($line['committed'] == 'y') { echo '<div> <br>Committed to <strong>'. $line['college'] . '</strong></div> ';} } } i want it so that the 1st letter in this text box when it Submited gets saved to the db as 1st letter <input name="title" type="text" id="title" size="50" /> what php function would I need to use to let's say I have a string I went to the Store And I want to pass that string, or any string through some type of function that would output: I Went To The Store How in the world could I do this? am I overthinking this or is this extremely difficult? hello, i have the following, which is sorting by id number with a horizontal line between. im trying to make it so that it is sorted by supplier with lines between each letter. Code: [Select] <?php if ($PreviousID!=0 && $ManID != $PreviousID) {?> <hr /> <?PHP } $PreviousID = $ManID; include 'config.php'; include 'javascript.php'; @mysql_select_db ("citycore", $conn) OR DIE (mysql_error()); $sql = "SELECT * FROM supplier ORDER BY supplier"; $result = @mysql_query($sql, $conn) or die(mysql_error()); //$row2 = mysql_query($sql, $conn); $PreviousID=0; while ($row = mysql_fetch_array($result)) { $ManID = $row['id']; $id=$row['id']; $supplier=$row['supplier']; $address=$row['address']; $city=$row['city']; $province=$row['province']; $postal=$row['postal']; $phone2=$row['phone2']; $phone=$row['phone']; $fax=$row['fax']; $email=$row['email']; ?> <div align="center"> <table border="1" width="95%" style="border-collapse: collapse"> <tr> <td><?php echo $row['supplier'];?></td> <td><a href="http://mapof.it/<?php echo($address .' ' .$city .',' .' ' .$province .' ' .$postal); ?>" target="_blank"><?php echo($address .' ' .$city .',' .' ' .$province .' ' .$postal); ?></a></td> </tr> </table> </div> <?PHP } ?> I want to be able to replace, let's say, every fifth letter from a string. The string is unknown, though, it could come from database, or a POST form. So I'm unsure if I could use str_replace. I think I may need to use preg_replace(), but I'm not not sure. I am trying to get a paragraph from a website. Everything works but the first letter is kept on missing. The code shown below is used to get the paragraph. Not sure why the first letter is missing. Please help!!! Code: [Select] if ( isset( $offer[ 0 ] ) ) { // Tidy it up - remove commas and weird Word chars $off = strip_tags( $offer[ 0 ] ); $off = substr( $off, strpos( $off, ";" ) + 1 ); $off = str_replace("'", "", $off ); $off = trim( $off ); } else { $off = "0"; } hi, I have a list of towns and need to get the first letter from each town and just display it once before the start of that lettered group ie; what I have: Aberdeen Arundel Aberyswith Bath Bristol Brighton Cardiff coventry what I would like: A Aberdeen Arundel Aberyswith B Bath Bristol Brighton C Cardiff coventry here is the code which writes out my list: Code: [Select] <ul class="edgetoedge"> <?php while($row1 = mysql_fetch_array($locals)) { echo '<li class="forward"><a href="townpubs.php?RSTOWN='.$row1['RSTOWN'].'" rel="external">'.$row1['RSTOWN'].'<small class="listcounter">'.$row1['PubCount'].'</small></a></li>'; } ?> </ul> Hi, I have pagination system with FIRST LETTER separated and everything is OK.
$page = (int)(!isset($_GET["page"]) ? 1 : $_GET["page"]); if ($page <= 0) $page = 1; $per_page = 5; $startpoint = ($page * $per_page) - $per_page; $statement = "restaurants ORDER BY `name`"; // make foo the current db '" . addslashes($_GET['id']) . "' $result = mysqli_query($mysqli,"SELECT name FROM restaurants WHERE cuisine_ID_obsolete=5 ORDER BY name LIMIT {$startpoint} , {$per_page}"); if (mysqli_num_rows($result) == 0) { echo "No records are found."; } else { $lastFoundLetter = ''; // displaying records. while ($row = mysqli_fetch_array($result)) { $firstLetter = substr($row['name'], 0, 1); if ($firstLetter != $lastFoundLetter) { if ($lastFoundLetter != '') { echo "</br>"; } echo strtoupper($firstLetter) . "<br/>"; $lastFoundLetter = $firstLetter; } echo $row['name'] . "<br/>"; } } echo pagination($statement,$per_page,$page); ?>Function for pagination: <?php function pagination($query,$per_page=10,$page=1,$url='?'){ global $mysqli; $query = "SELECT COUNT(*) as `num` FROM restaurants WHERE cuisine_id_OBSOLETE = '12'"; $row = mysqli_fetch_array(mysqli_query($mysqli,$query)); $total = $row['num']; $adjacents = "1"; $prevlabel = "<img src='files/prev.png'>"; $nextlabel = "<img src='files/next.png'>"; $page = ($page == 0 ? 1 : $page); $start = ($page - 1) * $per_page; $prev = $page - 1; $next = $page + 1; $lastpage = ceil($total/$per_page); $lpm1 = $lastpage - 1; // //last page minus 1 $pagination = ""; if($lastpage > 1){ $pagination .= "<ul class='pagination'>"; if ($page > 1) $pagination.= "<li><a href='{$url}page={$prev}'>{$prevlabel}</a></li>"; if ($lastpage < 7 + ($adjacents * 2)){ for ($counter = 1; $counter <= $lastpage; $counter++){ if ($counter == $page) $pagination.= "<li><a class='current'>{$counter}</a></li>"; else $pagination.= "<li><a href='{$url}page={$counter}'>{$counter}</a></li>"; } } elseif($lastpage > 1 + ($adjacents * 2)){ if($page < 1 + ($adjacents * 2)) { for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++){ if ($counter == $page) $pagination.= "<li><a class='current'>{$counter}</a></li>"; else $pagination.= "<li><a href='{$url}page={$counter}'>{$counter}</a></li>"; } $pagination.= "<li class='dot'>...</li>"; $pagination.= "<li><a href='{$url}page={$lpm1}'>{$lpm1}</a></li>"; $pagination.= "<li><a href='{$url}page={$lastpage}'>{$lastpage}</a></li>"; } elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2)) { $pagination.= "<li><a href='{$url}page=1'>1</a></li>"; $pagination.= "<li><a href='{$url}page=2'>2</a></li>"; $pagination.= "<li class='dot'>...</li>"; for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++) { if ($counter == $page) $pagination.= "<li><a class='current'>{$counter}</a></li>"; else $pagination.= "<li><a href='{$url}page={$counter}'>{$counter}</a></li>"; } $pagination.= "<li class='dot'>..</li>"; $pagination.= "<li><a href='{$url}page={$lpm1}'>{$lpm1}</a></li>"; $pagination.= "<li><a href='{$url}page={$lastpage}'>{$lastpage}</a></li>"; } else { $pagination.= "<li><a href='{$url}page=1'>1</a></li>"; $pagination.= "<li><a href='{$url}page=2'>2</a></li>"; $pagination.= "<li class='dot'>..</li>"; for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++) { if ($counter == $page) $pagination.= "<li><a class='current'>{$counter}</a></li>"; else $pagination.= "<li><a href='{$url}page={$counter}'>{$counter}</a></li>"; } } } if ($page < $counter - 1) $pagination.= "<li><a href='{$url}page={$next}'>{$nextlabel}</a></li>"; $pagination.= "</ul>"; } return $pagination; } ?>Problem is, since I have FIRST LETTER separated, with $per_page. How to exclude FIRST LETTER and "<br/>" from $per_page variable? Hi.. I have code for auto increment of JO Number, now it display: 120504001 by using this code: <?php $sql = "SELECT jo_number FROM job_order ORDER BY jo_date DESC LIMIT 1"; $result = mysql_query($sql, $con); if (!$result) { echo 'failed'; die(); } $total = mysql_num_rows($result); if ($total <= 0) { $currentSRNum = 1; $currentYear = (int)(date('y')); $currentMonth = (int)(date('m')); $currentDay = (int)(date('d')); $currentSRYMD = substr($row['jo_number'], 0, 6); $currentYMD = date("ymd"); if ($currentYMD > $currentSRYMD) { $currentSRNum = 1; } else { $currentSRNum += 1; } } else { //------------------------------------------------------------------------------------------------------------------ // Stock Number iteration.... $row = mysql_fetch_assoc($result); $currentSRNum = (int)(substr($row['jo_number'],0,3)); $currentSRYear = (int)(substr($row['jo_number'],2,2)); $currentSRMonth = (int)(substr($row['jo_number'],0,2)); $currentSRNum = (int)(substr($row['jo_number'],6,4)); $currentYear = (int)(date('y')); $currentMonth = (int)(date('m')); $currentDay = (int)(date('d')); $currentSRYMD = substr($row['jo_number'], 0, 6); $currentYMD = date("ymd"); if ($currentYMD > $currentSRYMD) { $currentSRNum = 1; } else { $currentSRNum += 1; } } //------------------------------------------------------------------------------------------------------------------ $yearMonth = date('ymd'); $currentSR = $currentYMD . sprintf("%03d", $currentSRNum); ?> now I want it to be: JO120504001 JO120504002 JO120504003 JO120504004 JO120505001 JO120504002 JO120504003 Any help is highly appreciated. Thank you so much Hello, I am attempting to develop a simple php script which will generate a 4 letter sequence when a button is pressed. However the sequence has a few rules it has to follow. For example: the letters have to be A B C D E F G H J K L M P Q and R The second letter must be a letter AFTER the first The fourth letter must be a letter AFTER the third There can't be 2 of the same number. I am a bit confused on how I will do this as I am quite new to php, I though about generating the first as $1, then generating the second as $2, then if $1 > $2, then I would regenerate $2 until it wasn't. Then repeating that for $4. However I am not sure on the coding which would be involved in doing this. If someone could give me a few pointers or a link to a website which would help me it would be much appreciated. |