Learn VBA & Macros in 1 Week!

PHP - Isset Function Help

Full Excel VBA Course - Beginner to Expert

Isset Function Help	View Content

Hi, just began working with the isset function, and having a few problems with the following code.

As you can see I'm trying to assign some variables using the explode function.

This is the string that is taken from the form on my index page
http://mobsters-fb-apache-dynamic-lb.playdom.com/mob_fb/refresh_stat_manual?user_id=100000898907997&auth_key=e5f4a2308d13346b4bf6e8228e9f50636240bf9f&nocache=1290001265332&

$RawHeader = str_replace(' ', '', $_POST['RawHeader']);

if (isset($RawHeader))
   {
   $UserID = explode('user_id=', $RawHeader);
   $UserID = explode('&', $UserID[1]);
   $UserID = $UserID[0];

   $AuthKey = explode('auth_key=', $RawHeader);
   $AuthKey = explode('&nocache=', $AuthKey[1]);
   $AuthKey = $AuthKey[0];
   }

I am new to the isset function so I don't really know if there is anything wrong with it, but if I try echo out both $UserID and $AuthKey it returns nothing.
Any suggestions or solutions?
Thanks

Full Excel VBA Course - Beginner to Expert

Similar Tutorials

Php Problem With Isset Function

!isset Function Not Working

Why (isset($_post['submit'])) Function Not Working?

Call To Undefined Function - Isset Necessary / Good Practice?

Using If Isset More Than Once

Need Help With Isset()

Isset With || And &&

Php 404 Isset Help

Is Isset Different In Wordpress

How Do I Isset All My Variables?

Checkboxes And Isset

Php Switch If Isset

Learn VBA & Macros for Excel in 1 Week!

Php Problem With Isset Function

Similar Tutorials

I am an absolute beginner in php & am trying to validate a form using javascript.
Problem is I am checking if the textbox is left empty before the user clicks on the submit button(using javascript).
On the other hand i'm using isset function of php for the same submit button so that it does not run the code unless and until the button is clicked. Due to this, the default value of text box is being entered into database. How do i prevent this?
Is there an alternate function to isset for such an event?

Here is a sample code
Code: [Select]
<?php
if(isset($_POST[sub]))
$sql="insert into testing values('$_POST[txt1]')";
$exec = mysql_query($sql);
?>

<script type="text/javascript">
function check()
{
var a = document.getElementById('add');
if (a.value = "")
{
return false;
}
}
</script>

<form action="add.php" method="post">
<input type="text" name="txt1" id="add"><br>
<input type="submit" name="sub" value="Click to Add" onclick = "check();">
</form>

I'm using ghost text technique on my page instead of labels so the text boxes have different values at different instances and hence I cant use !empty function either.
How do i unset the submit button so that it does not run the script further?

!isset Function Not Working

Similar Tutorials

For some reason the !isset() function doesnt seem to work i cant find out why hope you guys will be able to help

Here is the html code for the form where the user enters the data

Code: [Select]

<div id="contact_form">

<h2>On Site SEO Signup Form</h2>

<form method="post" name="contact" action="http://www.techbreeze.in/freeseo.php">

<label for="uname">Name:</label> <input name="uname" type="text" class="required input_field" id="uname" />
<div class="cleaner h10"></div>

<label for="email">Email:</label> <input type="text" class="validate-email required input_field" name="email" id="email" />
<div class="cleaner h10"></div>

<label for="website">Website:</label> <input type="text" class="required input_field" id="website" name="website"/>
<div class="cleaner h10"></div>

<label for="ftp">Your FTP Login URL:</label> <input type="text" class="required input_field" id="url" name="url" />
<div class="cleaner h10"></div>

<label for="username">Your FTP Username:</label> <input type="text" class="required input_field" id="user" name="user" />
<div class="cleaner h10"></div>

<label for="password">Your FTP Password:</label> <input type="password" class="required input_field" id="pass" name="pass"/>
<div class="cleaner h10"></div>

<input type="submit" value="Send" id="submit" name="submit" class="submit_btn float_l" />
<input type="reset" value="Reset" id="reset" name="reset" class="submit_btn float_r" />

</form>

</div>

And here is the code for the .php file where the !isset() function is used

Code: [Select]
<?php

    // validation expected data exists
    if( !isset($_POST['uname']))
    {
          die ('We are sorry, but all the fields are necessary you cant leave the "Name" field empty!');
    }
if( !isset($_POST['pass']))
   {
      die ('We are sorry, but all the fields are necessary you cant leave the "Password" field empty!');
    }
if( !isset($_POST['email']))
   {
        die ('We are sorry, but all the fields are necessary you cant leave the "Email" field empty!');

   }
   if( !isset($_POST['website']))
    {
          die ('We are sorry, but all the fields are necessary you cant leave the "Website" field empty!');
    }
if( !isset($_POST['url']))
    {
          die ('We are sorry, but all the fields are necessary you cant leave the "FTP URL" field empty!');
    }
if( !isset($_POST['user']))
    {
          die ('We are sorry, but all the fields are necessary you cant leave the "Username" field empty!');


Thanks in advance

Why (isset($_post['submit'])) Function Not Working?

Similar Tutorials

I have a simple log in form. By debugging I found that isset post submit function is not responding. It remains on the same page after submitting form. I have googled all the possible solutions to this problem but none worked. Any help is greatly appreciated. The form is in multiplelogin.php file and the code is in multi.php file. After login redirection is to teachers.php file.

<?php

session_start();

$conn = mysqli_connect("localhost", "root", "", "signup");

if(isset($_SESSION['username'])) {

header('location: teachers.php');

exit();

}

?>

<!DOCTYPE html>

<head>

<link rel="stylesheet" type="text/css" href="bootstrap.css">

<title> Teachers Students Login </title>

</head>

<body class="bg-secondary">

<div class="container">

<div class="row justify-content-center">

<div class="col-log-5 bg-light mt-5 px-0">

<h3 class="text-center text-light bg-primary py-3 px-5"> Log In </h3>

<?php

if(isset($_GET['error'])) {

if ($_GET['error'] == 'invalidemail') {

echo "<p class='alert'> Invalid Email Id! </p>";

} else if ($_GET['error'] == 'wrongpassword') {

echo "<p class='alert'> Incorrect Password! </p>";

}

}

?>

<form action="multi.php" action="post" class="py-4 px-5" id="form">

<div class="form-group px-5">

<input type="email" name="email" class="form-control form-control-lg" placeholder="Email" required>

</div>

<div class="form-group px-5">

<input type="password" name="password" class="form-control form-control-lg" placeholder="Password" required>

</div>

<div class="form-group px-5">

<input type="submit" name="submit" value="Submit" class="btn btn-primary btn-block">

</div>

</form>

</div>

</div>

</div>

</body>

</html>

<?php

ini_set( 'display_errors', 1 );
error_reporting( E_ALL );

if (isset($_POST['submit'])) {

$conn = mysqli_connect("localhost", "root", "", "signup");

$email = $_POST['email'];

$password = $_POST['password'];

$sql = "SELECT * FROM teachersRegist WHERE email=?";

$stmt = mysqli_stmt_init($conn);

if (!mysqli_stmt_prepare($stmt, $sql)) {

header("Location: multilogin.php?error=sqlerror");

exit();

} else {

mysqli_stmt_bind_param($stmt, "s", $email);

mysqli_stmt_execute($stmt);

$result = mysqli_stmt_get_result($stmt);

if ($row = mysqli_fetch_assoc($result)) {

$pwdCheck = password_verify($password, $row['password']);

if ($pwdCheck == false) {

header("Location: multilogin.php?error=wrongpassword");

exit();

} else if ($pwdCheck == true) {

session_start();

$_SESSION['username'] = $row['username'];

$_SESSION['email'] = $row['email'];

header("Location: teachers.php?login=success");

exit ();

} else {

header("Location: multilogin.php?error=wrongpassword");

exit();

}

}

else {

header("Location: multilogin.php?error=invalidemail");

exit();

}

}

}

else {

header("Location: multilogin.php");

exit();

}

?>

Edited September 9, 2020 by tarunrathore

Call To Undefined Function - Isset Necessary / Good Practice?

Similar Tutorials

I have a long list of variables with form fields inserted into them like this:

$page_id = $_POST['exclude'];

I just turned on WP_Debug just to see which error messages would come up and to my surprise it wasn't that bad, the most error messages were "Call to Undefined function".

The solution to this problem is simple, all I have to do is wrap an isset around all the form field variables, like this:

$page_id = isset($_POST['exclude']);

My question is, is this really necessary or considered as good practice? Should I now go ahead and wrap to all the variables in that long list an isset around?

Or should I just turn WP_Debug off again and leave it as is?

I personally would like to adopt to the good practice way, but I don't know how much of an advantage it is to wrap an isset around every single form field variable.

Any suggestions?

Using If Isset More Than Once

Similar Tutorials

Hi all

I need to do a multiple if isset to get three variables from the URL. Here is my code for just one:

if(isset($_GET['category'])) {
$fetchproducts = mysql_query(" SELECT * FROM `products` WHERE category = '".$_GET['category']."'");
while($returnedProduct = mysql_fetch_array($fetchproducts)) {
include('product-cell.php');
}

How do I combine this to check what is the 'type' and 'colour' from the URL and fetch from the SQL accordingly?

Many thanks for you help

Pete

Isset

Similar Tutorials

I believe that my problem is with the isset on line 7 and 39, but I do not know of anyway around it. Can someone enlighten me.

<?php
session_start();
if (isset($_GET['logout'])){
    unset($_SESSION['logged_in']);
}
?>
<html>
    <head>
        <title>Add a New Car!</title>
        <?php
        if (isset($_POST['submit'])) {
            //print_r($_POST);
            $password = md5($_POST['password']);
            //echo'<p>'.$password.'</p>';
            $username = ($_POST['username']);
            //echo'<p>'.$username.'</p>';
        }
        $db = new PDO('sqlite:login.sqlite');
        $login = 'SELECT * FROM login
        WHERE userid="'.$username.'"
        AND password="'.$password.'";';
        //echo'<p>'.$login.'</p>';
        $attempt = $db->query($login);
        foreach ($attempt as $row) {
        //print_r($row);
        $_SESSION['logged_in'] = $username;
        }
        ?>
    </head>
    <body>
                <?php
        if (!isset($_SESSION['logged_in'])){
        ?>
            <form method="post" action="Db_login.php">
            <p>Username:<br /><input type="text" name="username" /> </p>
            <p>Password:<br /><input type="password" name="password" /></p>
            <p><input type="submit" name="submit" value="Log In!" /></p>
            </form>
        <?php
        } else {
        ?>
        <?php
        if(isset($_POST['submit'])) {
            print_r($_POST);
            $make = ($_POST['make']);
            $model = ($_POST['model']);
            $year = ($_POST['year']);
            $fuel = ($_POST['fuel_type']);
            $vin = ($_POST['vin_number']);
            $reg = ($_POST['reg_number']);
        }
        $db = new PDO('sqlite:cars.sqlite');
        $sqlCars = 'INSERT INTO cars ( )
        VALUES("'.$make.'","'.$model.'","'.$year.'","'.$fuel.'","'.$vin.'","'.$reg.'");';
        echo'<p>'.$sqlCars.'</p.>';
        ?>
        <form method="post" action="Db_new_Cars.php" enctype="multipart/form-data">
            <p>Make:<br /><input type="text" name="make" /> </p>
            <p>Model:<br /><input type="text" name="model" /></p>
            <p>Year:<br /><input type="text" name="year" /></p>
            <p>Fuel Type:<br /><input type="text" name="fuel_type" /></p>
            <p>Vin Number:<br /><input type="text" name="vin_number" /></p>
            <p>Reg Number:<br /><input type="text" name="reg_number" /></p>
            <p>Choose a image to upload:<br />
            <input type="file" name="myfile"></input></p>
            <p><input type="submit" name="submit" value="Submit!" /></p>
        </form>
        <h1> Protected Content!</h1>
        <p>You are logged in as <em><?php echo $_SESSION['logged_in']; ?> </em></p>
        <p><a href="Db_login.php?logout=true">Log out!</a></p>
        <p><a href="New_Cars.php">Add a new car</a></p>
        <p><a href="Book_Out_Cars.php">Book out a car</a></p>
        <?php
        }
        ?>

    </body>
</html>

Need Help With Isset()

Similar Tutorials

guys this thing called isset() is bugging me.What is the difference in when you say
Code: [Select]
if(isset($_POST['name']))
and
Code: [Select]
if($_POST['name'])
and
Code: [Select]
if(!$_POST['name'])

and why would someone require a code such as Code: [Select]
if($_POST['submit']=='Submit')
And what is that code which tells you the user has entered something into the form
Thanks People

Isset With || And &&

Similar Tutorials

This is blowing my mind. I have this function and all I want it to do is check to make sure that the var $race is set and = '0'. The default value from the form is '0'. I also want it to check the value of race and if it is anything but the two listed , submit error. Yes I've tried to replace the || with &&.. Nothing works(Meaning that it will error when its not suppose to or it wont error when its suppose to).. Any ideas?

Code: [Select]
function check_Race ($race,$display_name,$member_id,$description,$ip) {

//echo "This is the race". $race;
//exit;

if (isset($race) && $race ='0' && $race !== 'White' && $race !== 'Black'){

echo "This is an errror.!";
$t_error="19";
$member_id = $member_id;
notify_Admin($t_error,$member_id,$ip);
// logOut ($t_error);
exit;

}

Need Isset()?

Similar Tutorials

Isn't this code redundant...

if (isset($_SESSION['loggedIn']) && $_SESSION['loggedIn'] == TRUE){

After all, if $SESSION['logged_in'] == TRUE then it is *obviously* set...

Debbie

Isset

Similar Tutorials

i Have two page login.php and verify.php

In login.php user is entering Username and Password and in the action of the form i am writing verify.php.

If verification is a success then i will start a session()

Code: [Select]
session_start();

$_SESSION['ls']="loggedin"; // ls stands for login status
$_SESSION['id']=$row['id'];
$_SESSION['user_name']=$row['user_name'];
$_SESSION['email']=$row['email'];
header('location : members.php');
die (" ");
and will redirect them to members.php
....

Everything is working fine...

But in login.php i have written a code on the top...

Code: [Select]
<?php
if(isset($_SESSION['ls']) && isset($_SESSION['id']) && isset($_SESSION['user_name']) && isset($_SESSION['email']) )
{
header('location:members.php');
die(" ");

}
?>
I want if a session is started and if user will access login.php they will automatically go to members.php

But this script is not working...

Iam not getting whats the problem...
also i m not getting any error login.php or anything

CODE WRITTEN ON THE TOP OF members.php IS :

Code: [Select]
<?php
session_start();
if(@$_SESSION['ls']!=="loggedin" ) // Checks if the person has done stage one (Registration.php)
{
header('Location: login.php'); //If they haven't done it, it sends them back.
die (" ");
}
?>

Isset()

Similar Tutorials

I want to get the COUNT of the fields (ArrayM11 - ArrayM19), which has the word "YES". The code isn't working. Appreciate any help.

$Array1 = array();
for($j=0;$j<count($ArrayM1);++$j) {
$result = array_count_values($ArrayM1[$j]);
if (isset($result['YES'])) {
$points1 = $result['YES'];
}
}

Php 404 Isset Help

Similar Tutorials

Hello all, i am hoping someone can help me.

i have some code i have been working on and i am trying to add a 404 page if it cant find the page, i know it will be some sort of if statment, but with me been pretty much a noob at php i am stuck.

heres the code that the page calls.

Code: [Select]
function get_content() {

//Get page name from browser if none call it home
$page = (isset($_GET['page'])) ? $_GET['page'] : 'home';

//Get The Page Content
$sql = "SELECT * FROM content WHERE page = '$page'";
$res = mysql_query($sql) or die (mysql_error());
while($row = mysql_fetch_assoc($res)){

//Show The Page Content
echo '<h1>' . $row['title'] . '</h1>';
echo $row['body'];
}
}

thanks all.

Isset Help

Similar Tutorials

why dose this not work

<?php

if(isset($_SESSION['SESS_ADMIN']))
$loc = ../admin/admin.php;
else
$loc= ../head/head.php";

?>
<form><INPUT TYPE="button" value="Main Menu" onClick="parent.location='<?php echo $loc; ?>'"></form>
</body>

</HTML>

Isset Help?

Similar Tutorials

Hi there,

I'm inserting data into a mysql database. My submissions works fine, however when a part of the form is not filled out the php scripit crashes. How can I submit all data that is set and skip pieces that aren't filled out?

For example I have a plant database which has an option to insert different types of common names for the plant. It's ok if they aren't all filled out.

My code is as follows: Code: [Select]
<?php

//insert general plant data into db
$queryplant="INSERT INTO actualplanttable (id, scientific, common1, common2, common3, family, genus, description, planting, growing, care, duration, reference)
VALUES ('NULL', '$_POST[scientific]', '$_POST[common1]', '$_POST[common2]', '$_POST[common3]', '$_POST[family]', '$_POST[genus]', '$_POST[description]', '$_POST[planting]', '$_POST[growing]', '$_POST[care]','$_POST[duration]','$_POST[reference]')";
mysql_query($queryplant)
or die ('Error updating actualplanttable');

//insert maintenance data into db
$querymaintenance="INSERT INTO plantmaintenancelinktable (plant_id, maintenance_id)
VALUES ('$inserted_id', '$_POST[maintenance]')";
mysql_query($querymaintenance)
or die ('Error updating plantdurationtable');

?>

Should I be trying to work an isset function into this code? Any help would be greatly appreciated.

Thanks!

Bill...

Is Isset Different In Wordpress

Similar Tutorials

What I remember from my college days is that isset check whether the variable has a value set or not and return true or false value. However I encountered a code in wordpress - // Set up the content width value based on the theme's design and stylesheet.

How Do I Isset All My Variables?

Similar Tutorials

In my index.php I use a global $_GET variable he

Code: [Select]
$ibforums->input = $std->parse_incoming();
parse_incoming function is:

Code: [Select]
function parse_incoming()
{
global $HTTP_GET_VARS, $HTTP_POST_VARS, $HTTP_CLIENT_IP, $REQUEST_METHOD, $REMOTE_ADDR, $HTTP_PROXY_USER, $HTTP_X_FORWARDED_FOR;
$return = array();

if( is_array($HTTP_GET_VARS) )
{
while( list($k, $v) = each($HTTP_GET_VARS) )
{
//-- mod_sec_update_131 begin
if (strpos($k, "amp;") === 0)
$k = substr($k, 4);
//-- mod_sec_update_131 end

if ( $k == 'INFO' )
{
continue;
}

if( is_array($HTTP_GET_VARS[$k]) )
{
while( list($k2, $v2) = each($HTTP_GET_VARS[$k]) )
{
$return[$k][ $this->clean_key($k2) ] = $this->clean_value($v2);
}
}
else
{
$return[$k] = $this->clean_value($v);
}
}
}

// Overwrite GET data with post data

if( is_array($HTTP_POST_VARS) )
{
while( list($k, $v) = each($HTTP_POST_VARS) )
{
if ( is_array($HTTP_POST_VARS[$k]) )
{
while( list($k2, $v2) = each($HTTP_POST_VARS[$k]) )
{
$return[$k][ $this->clean_key($k2) ] = $this->clean_value($v2);
}
}
else
{
$return[$k] = $this->clean_value($v);
}
}
}

//----------------------------------------
// Sort out the accessing IP
// (Thanks to Cosmos and schickb)
//----------------------------------------

$addrs = array();

foreach( array_reverse( explode( ',', $HTTP_X_FORWARDED_FOR ) ) as $x_f )
{
$x_f = trim($x_f);

if ( preg_match( '/^\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}$/', $x_f ) )
{
$addrs[] = $x_f;
}
}

$addrs[] = $_SERVER['REMOTE_ADDR'];
$addrs[] = $HTTP_PROXY_USER;
$addrs[] = $REMOTE_ADDR;

//header("Content-type: text/plain"); print_r($addrs); print $_SERVER['HTTP_X_FORWARDED_FOR']; exit();

$return['IP_ADDRESS'] = $this->select_var( $addrs );

// Make sure we take a valid IP address

$return['IP_ADDRESS'] = preg_replace( "/^([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})/", "\\1.\\2.\\3.\\4", $return['IP_ADDRESS'] );

$return['request_method'] = ( $_SERVER['REQUEST_METHOD'] != "" ) ? strtolower($_SERVER['REQUEST_METHOD']) : strtolower($REQUEST_METHOD);

return $return;
}
Now, I use my $ibforums->input throughout my forum system, and I use it in EVERY SINGLE file, I have around 50 Files and I get "unidetified variable" errors.

is there a way I can just make sure my global $ibforums->input is ISSET so it it's a GLOBAL ISSET? So I don't have to go through each file that uses $ibforums->input and put a isset( ) around it? It would take over prob 10 days to go through each file and change all 300-500 errors, using the $ibforums->input, there has to be a way I can globally defined my $ibforums->input Variable with a isset..

Thank you

Isset Problem

Similar Tutorials

Hi guys, first time posting here.

Anyway, heres my problem.

I have this section of code at the beggining of my page:

Code: [Select]
if (isset($_POST['userChoice'])) {
$try = check_word($_POST['userChoice']);
echo ("We are into the loop");
}
else {
echo ("<br/>about to call change word");
changeword();
echo ("<br/> we called the changeword");
}

And here is my form:
Code: [Select]
<html>
<head>
</head>
<body>
<form name="wordguess" action="Index.php" method="POST">
<table>
<tbody>
<tr>
Try to guess what the following word is: <?=$scrambled ?> <br/>
</tr>
<tr>
Your Guess: <input type="text" id="userChoice" size="20" /> <br/>
</tr>
<tr>
<td>
<input type="submit" name="submit" id="submit" value="Submit">
</td>
</tr>
<tr>
<?=$correct?>
</tr>
</tbody>
</table>
</form>
</body>
</html>'

Now, how i assumed it worked was that the first time the page is loaded it would display the form and that's it. However, even when they hit the submit button on the form, its not really doing the POST, so when the page reloads, gives me the same stuff so it always goes on the else part of the if.

Any help would be appreciated.

Thanks,
GoodVibe

Isset Question

Similar Tutorials

Hi Everyone,

I am a great fan of the 'isset' function, which I use alot when submitting forms, but not wanting to navigate away from the page. Normally I just use a form with a submit button with a name, for example:

Code: [Select]
<input type='submit' name='updatetable' value='Go!'/>
and then use the following:

<?php if (isset ($_POST['updatetable'])) { do this stuff... } ?>

But I want to start to use images as submit buttons, so when you click on them, you are able to submit the underlying data. Is there a way to do this using the isset function? Because effectively, the image, which would submit using javascript, wont have a name.

Any ideas appreciated

Many Thanks
Matt

Checkboxes And Isset

Similar Tutorials

Hey all,

I am fairly new in the php world and have set myself a challenge to create a display of a database.
I have the database displaying what I want but now am trying to have a 'complete' field where if ticked it will delete that field from the db.

The row ['complete'] line 30 is saved in the db as '0' when ticked I want this to change to a '1' and delete that line from the db.

I have tried a few things but am getting a little bit lost. Any help would be much appreciate
<?php
$con = mysql_connect("Host","USER","PASS");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("TABLE", $con);

$result = mysql_query("SELECT * FROM Priority");

echo "<table border='1' width='100%'>
<tr>
<td width='5%'>Ticket Number</td>
<td width='5%'>Order #</td>
<td width='65%'>Ticket Info</td>
<td width='15%'>Assigned by</td>
<td width='5%'>Priority</td>
<td width='10%'>Complete</td>
</tr>";

while($row = mysql_fetch_array($result))
  {
  echo "<tr>";
  echo "<td>#" . $row['ID'] . "</td>";
  echo "<td>" . $row['OrderNumber'] . "</td>";
  echo "<td>" . $row['TicketInfo'] . "</td>";
  echo "<td>" . $row['Assignedby'] . "</td>";
  echo "<td>" . $row['Priority'] . "</td>";
  echo "<td><input type='checkbox' name='Check' value='Check' /></td>";
//the last row, where the checkbox is is actually a row called ['complete']
         }
if(isset($Check) && $Check != "") {
mysql_query("UPDATE Priority SET Complete = '1' WHERE $row = 'ID'");
}

echo "</table>";

mysql_close($con);
?>

<?php
$con = mysql_connect("HOST","USER","PASS");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_query("DELETE FROM Priority WHERE Complete='1'");

mysql_close($con);
?>

Php Switch If Isset

Similar Tutorials

i know theres a way but i just forget. i want to do a switch function.

Code: [Select]
switch ($_GET['page']) {
case 0:
include 'page';
break;
case 1:
include 'page1';
break;
case 2:
include 'page2';
break;
default:
include 'page';
}
?>
just like that but if there is no $_GET page i just want it to do the default. instead of doing if isset GET page do switch else default page. i just want it to be simpler by doing something like switch(isset$_GET etc.