|
PHP - Select From A Function
hy
I want to make a select in a class: Code: [Select] class test { var $unu = array(); function __construct(){ $link = mysql_connect("", "", "") or die("Couldn't make connection."); $db = mysql_select_db("", $link) or die("Couldn't select database"); //$this->unu = $textin; } function show($col){ $q = mysql_query("SELECT $col FROM categorie"); $qw = mysql_fetch_array($q); $this->unu = $qw; return $this->unu; } } If I want to show how many rows are in that table: Code: [Select] $box = new test(); echo count($box->show("titlu")); it show me that are only 2, although in "categorie" table are 10 rows. Can you please tell me where is the error ? Thanks Similar TutorialsI am designing my own framework, and I have created a select function. I have set a parameter to be an array by default, with the default value of *. When I check if it's an array (with is_array) it says that it isn't. Does anyone have any idea why it would say that? Code: [Select] function select($table, $rows = array('*'), $cond = "") { $query = "SELECT {$rows} FROM `{$table}`"; if (isset($cond)) { $query .= " WHERE {$cond}"; } if (is_array($rows)) { if (isset($rows) && $rows != "*") { foreach ($rows as $v) { print_r($v); } } } //return mysql_query($query); } Any help is appreciated. Thanks. I have a DB It gets records from a sensor every 5 min This is then displayed on a Chart When I request 4 Hrs I get 48 records x 12 Sensors, Not a issue When I request 12 Hrs I get 144 records x 12 Sensors, A little Slower but Still OK But as I start to request longer periods Like 7 Days I start getting larger and Larger data sets causing time out issues with the AJAX Calls (4-30MB per sensor downloads of data) When looking at 4 weeks I really cant see the fine detail so is there a way to request records from MYSQL that drops some records in between Kinda like the Step function in a For loop If I request a period that has 2048 records but only want 204 records is there a way to say give me From -> To dates Step 10 and only return every 10th Record in the data set Thanks Hi, I'm an novice/intermediate PHP prgogrammer, so excuse me if this is a stupid question. I have one php program that consist of a few functions. Inside the function taht is the starting point I pickup a few entries from a MYSQL database, and display those in my html page. I wish to dynamically put a link on those entries that makes it possible for the users to click those entries an get directed to other functions inside this very same PHP program WITH a parameter. The parameters that should accompany the url/link into the selected function to be able to select apropriate records from the mysql tables. Any hints and tips for this would be highly appreciated! Kind Regsrds, Terje Hvidsten. Ive tried to create a function to create a dropdown select box but im getting alot of errors to do with the if statement saying the ($_POST[$name]) value is not set??? function selectBox($name, $firstvalue, $limit, $increment) { // echo "<br>"; // echo $name; // echo "<br>"; // print_r($_POST[$name]); // echo "<br>"; $select ="selected=\"selected\""; $body = "<select name='$name' id='$name' method='POST'> <option value=''>$name</option>"; for ($value = $firstvalue; $value <= $limit; $value += $increment) { $body .= "<option value= '$value' "; if ($_POST["$name"] === $value) { $body .= $select; } $body .= ">$value</option>"; } $body .= "</select>"; // echo $value; // echo $_POST[$name]; // echo $_POST['Width']; return $body; } Any help would be greatly appreciated When i use this code it show everything except for the first record in the table. I have also tried it with the users for the login system im using and then it doesnt show the person im logged in to or also the first record in the table and i need it too show all the records How do i solve this? I thought it had something to do with: Code: [Select] <?php while ($rij = mysql_fetch_array($result)){ echo ("<tr><td>". $rij['ID'] . " </td> " . "<td>" . $rij['naam'] . " " . $rij['telefoon'] . " </td> " . "<td>" . $rij['adres'] . " </td> " . "<td>" . $rij['mobiel`'] . " </td>". "</td></tr>\n "); } ?> But i dont know how to solve it. Code: [Select] <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("root123", $con); $sql= "SELECT * FROM root123 ORDER BY ID;"; $result = mysql_query($sql, $con); $rij = mysql_fetch_array($result); ?> <table width="80%" align="center"> <tr> <th>ID</th> <th width="150px">Naam</th> <th>Gebruikersnaam</th> <th width="300px">Wachtwoord</th> </tr> <?php while ($rij = mysql_fetch_array($result)){ echo ("<tr><td>". $rij['ID'] . " </td> " . "<td>" . $rij['naam'] . " " . $rij['telefoon'] . " </td> " . "<td>" . $rij['adres'] . " </td> " . "<td>" . $rij['mobiel`'] . " </td>". "</td></tr>\n "); } ?> </table> I am currently using a javascript to redirect the page using a select tag and the onchange property. Each page calls a different function. I want to be able to pass the <select> value to a variable that I can use within a php condition statement on the same page. This will generate the required output based on the <select> value. This way I dont require a seperate page for each query. So onchange.... $select_value == this.value? Then within my page: Code: [Select] if ($select_value == 'alpha') { get_query_alpha(); } if ($select_value == 'bravo') { get_query_bravo(); } This is my current set up... Code: [Select] <p>Order by: <select name="query" id="query" onchange="gotourl(this.value)"> <option value="query1.php" >Sort by A</option> <option value="query2.php" >Sort by B</option> <option value="query3.php" >Sort by C</option> <option value="query4.php" >Sort by D</option> </select></p> <table> <?php get_query_1();?> </table> and js... Code: [Select] function gotourl(url){ window.location= url; } function selectsubject(){ alert("Please select a subject!"); } Is there a simple way to do this? Thanks. Hi, I am making a login page which consists of 2 pages, index.php and config.php Following is a code of config.php Code: [Select] <?php define("HOST", "localhost"); define("USER", "aaaabbbccc"); define("PASS", "aaabbbccc"); define("DATABASE", "pricetagindia"); $connection = @mysql_connect(HOST, USER, PASS); $select_db = @mysql_select_db(DATABASE, $connection); if(!$connection) { echo "<h1>Cannot connect to database</h1>"; exit(0); } if(!$select_db) { echo "<h1>Cannot select database</h1>"; exit(1); } ?> Here is a coding of index.php Code: [Select] <?php include('config.php'); $_error = "<p></p>"; if (isset($_POST['username']) || isset($_POST['password'])) { $username = $_POST['username']; $password = $_POST['password']; if($username == NULL || $password == NULL) { $_error = "<p>Username and Password, both fields are required.</p>"; } else { // Check in DB $password = md5($password); $checkuser_query = "SELECT * FROM users WHERE username = '$username.' AND password = '$password'"; $checkuser_result = mysql_query($checkuser_query); $checkuser_count = mysql_num_rows($checkuser_result); if($checkuser_count == 1) { echo "match found"; } else { echo "nothing found error, username was ".$username." and pass is ".$password; echo "<p></p>"; echo $checkuser_result; } } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Price Tag India</title> </head> <body> <center> <h1>Price Tag India</h1> <p> </p> </center> <center> <form action="index.php" method="post" target=""> <table width="389" height="168" border="0"> <tr> <td width="141">Username :</td> <td colspan="2"><label for="username"></label> <input type="text" name="username" id="username" /></td> </tr> <tr> <td>Password :</td> <td colspan="2"><label for="password"></label> <input type="password" name="password" id="password" /></td> </tr> <tr> <td> </td> <td width="56"><input type="submit" name="button" id="button" value="Submit" /></td> <td width="223"><input type="reset" name="button2" id="button2" value="Reset" /></td> </tr> <tr> <td> </td> <td colspan="2"> <?php echo $_error; ?> </td> </tr> </table> <p> </p> </form> </center> </body> </html> I have attached the screenshot of database. Problem is when I do valid login i.e. with user admin and its password, it is not working, I spent 1 hour for solving this issue but didnt find any solution. Its frustrating now.....I know its simple but still its not working. It is giving me error as Code: [Select] nothing found error, username was admin and pass is 62cc2d8b4bf2d8728120d052163a77df Resource id #5 Hi Guys I don't know if this is possible but can someone point me in the right direction. I have a php function which takes two inputs and returns an output. for simplicity's sake let's say it's an addition function. What I want to do is use a mysql select statement to show all the rows from a database where field1 and field2 equal '3'. Here's the sort of thing I mean. function addNumbers($one,$two) { return $one + $two; } mysql_query("SELECT * FROM table WHERE 'addNumbers(field1,field2)' = '3'"); What I actually want to do is a lot more complex than this but I am trying to understand how to make the syntax work in simple terms first. Can anybody help? Many Thanks Dan Here is my query: Code: [Select] $db->query("SELECT cache.*,u.username from search_cache cache LEFT Join users as u ON u.id = 'NEED HELP HERE' where ident = '{$username}' ORDER BY DATE DESC") or error('Unable to send the message.', __FILE__, __LINE__, $db->error()); Here is my data inside my search_cache Here is my while loop: Code: [Select] while($recent = $db->fetch_assoc($rec)){ $data = unserialize($recent['search_data']); } Now I can use $data['search_type'] as a array and If I use echo $data['search_type']['2'] it echo's out the user_id 32 as seen in the screenshot at the very end. Problem is, I want to use that 'NEED HELP HERE' to join with that id 32 dynamically, how the hell is that possible with mysql or is it? Or would it be easier to just add a new row/column named user_id and just join of that instead of trying to do all this? would that be faster? Hi, i got help earlier with the this code-- exploding a field and getting an array, then inserting the array into a multiselect box-- That part is easy and works fine. Now the explode function gives an array of words with duplicate words in it: I tried several ways most either give a blank option/value, or the array word.. here is the code: $query = "SELECT DISTINCT property_functionsexperience FROM #__users_profiles WHERE published = '1' ORDER BY property_functionsexperience ASC"; $functionsexperiencelistgeneral=doSelectSql($query); foreach($functionsexperiencelistgeneral as $words) $property_funcexperilist=$words->property_functionsexperience; $wording = explode(', ', $property_funcexperilist); foreach($wording as $funciex) $funcexi=array_unique($funciex); $funcexpList .= "<option value=\"".$funcexi.','."\">".$funcexi."</option>"; $funcexpList .= "</optgroup>"; } $funcexpList.="</select>"; $output['FUNCEXPLIST']=$funcexpList; this code is adapted slightly from the working original that gives the double words-- this code gives a blank, but i think its on the correct track!? Hi all. Here is my scripts which allow user to check multiple rows of data and delete it , but it require select data and click for twice to delete the rows , what should be the error? Code: [Select] <form name="frmSearch" method="post" action="insert-add.php"> <table width="600" border="1"> <tr> <th width="50"> <div align="center">#</div></th> <th width="91"> <div align="center">ID </div></th> <th width="198"> <div align="center">First Name </div></th> <th width="198"> <div align="center">Last Name </div></th> <th width="250"> <div align="center">Mobile Company </div></th> <th width="100"> <div align="center">Cell </div></th> <th width="100"> <div align="center">Workphone </div></th> <th width="100"> <div align="center">Group </div></th> </tr> </form> <? echo "<form name='form1' method='post' action=''>"; while($objResult = mysql_fetch_array($objQuery)) { echo "<tr>"; echo "<td align='center'><input name=\"checkbox[]\" type=\"checkbox\" id=\"checkbox[]\" value=\"$objResult[addedrec_ID]\"></td>"; echo "<td>$objResult[addedrec_ID] </td>"; echo "<td>$objResult[FirstName]</td>"; echo "<td>$objResult[LastName] </td>"; echo "<td>$objResult[MobileCompany] </td>"; echo "<td>$objResult[Cell] </td>"; echo "<td>$objResult[WorkPhone] </td>"; echo "<td>$objResult[Custgroup] </td>"; echo "</tr>"; } echo "<td colspan='7' align='center'><input name=\"delete\" type=\"submit\" id=\"delete\" value=\"Delete\">"; if (isset($_POST['delete']) && isset($_POST['checkbox'])) // from button name="delete" { $checkbox = ($_POST['checkbox']); //from name="checkbox[]" $countCheck = count($_POST['checkbox']); for($d=0;$d<$countCheck;$d++) { $del_id = $checkbox[$d]; $sql = "DELETE from UserAddedRecord where addedrec_ID = $del_id"; $result2=mysql_query($sql) or trigger_error(mysql_error());;; } if($result2) { $fgmembersite->GetSelfScript(); } else { echo "Error: ".mysql_error(); } } echo "</form>"; Thanks for every reply. hirealimo.com.au/code1.php this works as i want it: Quote SELECT * FROM price INNER JOIN vehicle USING (vehicleID) WHERE vehicle.passengers >= 1 AND price.townID = 1 AND price.eventID = 1 but apparelty selecting * is not a good thing???? but if I do this: Quote SELECT priceID, price FROM price INNER JOIN vehicle....etc it works but i lose the info from the vehicle table. but how do i make this work: Quote SELECT priceID, price, type, description, passengers FROM price INNER JOIN vehicle....etc so that i am specifiying which colums from which tables to query?? thanks I have 2 queries that I want to join together to make one row
Dear All, I wish to have 2 drop down boxes, Country Select Box and Locality Select Box. The locality select box will be affected by the value chosen in the country select box. All is working fine except that the locality select box is not being populated. I know that the problem is in the sql statement WHERE country_id='$co' because i am having an error that $co is an undefined variable. All the rest works fine because i have replaced the $co variable directly with a number (say 98) for a particular country id and it worked fine. In what way can i define this variable $co so that it is accepted by my sql statement? Thank you for your help in advance. MySQL Tables indicated below: CREATE TABLE countries( country_id INT(3) UNSIGNED NOT NULL AUTO_INCREMENT, country_name VARCHAR(30) NOT NULL, PRIMARY KEY(country_id), UNIQUE KEY(country_name), INDEX(country_id), INDEX(country_name)) ENGINE=MyISAM; CREATE TABLE localities( locality_id INT(10) UNSIGNED NOT NULL AUTO_INCREMENT, country_id INT(3) UNSIGNED NOT NULL, locality_name VARCHAR(50), PRIMARY KEY (locality_id), INDEX (country_id), INDEX (locality_name)) ENGINE=MyISAM; Extract PHP script included below: // connect to database require_once(MYSQL); if(isset($_POST['submitted'])) { // trim the incoming data /* this line runs every element in $_POST through the trim() function, and assigns the returned result to the new $trimmed array */ $trimmed=array_map('trim',$_POST); // clean the data $co=mysqli_real_escape_string($dbc,$trimmed['country']); $lc=mysqli_real_escape_string($dbc,$trimmed['locality']); } ?> <form action="form.php" method="post"> <p>Country <select name="country"> <option>Select Country</option> <?php $q="SELECT country_id, country_name FROM countries"; $r=mysqli_query($dbc,$q) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($dbc)); while($row=mysqli_fetch_array($r)) { $country_id=$row[0]; $country_name=$row[1]; echo '<option value="' . $country_id . '"'; if(isset($trimmed['country']) && ($trimmed['country']==$country_id)) echo 'selected="selected"'; echo '>' . $country_name . '</option>\n'; } ?> </select> </p> <p>Locality <select name="locality"> <option>Select Locality</option> <?php $ql="SELECT locality_id, country_id, locality_name FROM localities WHERE country_id='$co' ORDER BY locality_name"; $rl=mysqli_query($dbc,$ql) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($dbc)); while($row=mysqli_fetch_array($rl)) { $locality_id=$row[0]; $country_id=$row[1]; $locality_name=$row[2]; echo '<option value="' . $locality_id . '"'; if(isset($trimmed['locality']) && ($trimmed['locality']==$locality_id)) echo 'selected="selected"'; echo '>' . $locality_name . '</option>\n'; } // close database connection mysqli_close($dbc); ?> </select> </p> <p><input type="submit" name="submit" value="Submit" /></p> <input type="hidden" name="submitted" value="TRUE" /> </form> Hello all, I have some piece of code that is nested like this $variable = 'This is a global argument'; function parentFunction($variable) { function childFunction() { echo 'Argument of the parent function is '.$GLOBALS['variable']; } childFunction(); } parentFunction(5); What I want to know is - Is there a way to access a variable from the parent function without passing arguments to the child function? (Something like how classes have parent::?). I don't want to use $GLOBALS because it might cause some variable collision, and I didn't want to pass arguments because incase I decide to change the arguments in the parent function I'd have to do it in the child function aswell. From my searching around in the Internet it seems like this is not possible, but if theres a slight chance that there might be something out there, i'm willing to give it a shot . Thanks in advance Question 1) Is the only and proper way to call a parent function "parent::function()"? Are there other/better ways from within a child function? Question 2) What are the deciding factors for when to make a function or attribute static? How do you make that decision? Assuming 5.3... Thanks. I have this function completely written in my class file that I am working on. The point to this function is to be able to check the login of a user or administrator for either of the control panels associated with my site. It will check the session intime as well as the page / module referenced. Once it passes all those checks, it will check and ensure the emailaddress/password stored in the current session still holds true and the account is still active... if the account is still active it will update the lastActivity as well as update all of the session variables with what is currently in the database. What I am looking for is basically a look at the function, see if it looks good.. If there is any part to it that could create security holes for the site just off the login function itself... Usage: $q->validUser($_SESSION['user'], $_mod); <?php function validUser($sess, $p) { if ($sess['inTime'] == '' && $p != 'login' && $p != 'logout') { session_destroy(); $login = '0'; $_int = ''; return $login; } else if ($sess['inTime'] < time()-3600 && $p != 'login') { $sess['inTime'] = ''; session_destroy(); $this->check_login($sess, $p); } else { $this->user = $sess['emailAddress']; $this->pass = $sess['password']; $login = $this->sql_query("SELECT * FROM users WHERE emailAddress = '".$this->user."' AND password = '".$this->pass."' AND status = '1' LIMIT '1'"); if ($login = $this->sql_numrows($login) < 1) { $sess['inTime'] == ''; session_destroy(); $login = '0'; } else { // logged in, lets update the database for last_activity AND the session. $this->sql_query("UDATE users SET lastActivity = '".now()."' WHERE emailAddress = '".$this->user."'"); $login = $this->sql_query("SELECT * FROM users WHERE emailAddress = '".$this->user."' AND password = '".$this->pass."' AND status = '1' LIMIT '1'"); $login = mysql_fetch_assoc($login); foreach ($login as $key => $value) { $sess[$key] = $value; } $sess['inTime'] = time(); $login = '1'; } return $login; } } ?> That is the main function, sql_query and sql_numrows is: <?php function sql_query($query = "", $transaction = FALSE) { unset($this->query_result); if ($query != "") { $this->num_queries++; if ($transation == BEGIN_TRANSACTION && !$this->in_transation) { $result = mysql_query("BEGIN", $this->db_connect_id); if (!$result) { return false; } $this->in_transaction = TRUE; } $this->query_result = mysql_query($query, $this->db_connect_id); } else { if ($transaction == END_TRANSACTION && $this->in_transaction ) { $result = mysql_query("COMMIT", $this->db_connect_id); } } if ($this->query_result) { unset($this->row[$this->query_result]); unset($this->rowset[$this->query_result]); if ($transaction == END_TRANSACTION && $this->in_transaction ) { $this->in_transaction = FALSE; if (!mysql_query("COMMIT", $this->db_connect_id)) { mysql_query("ROLLBACK", $this->db_connect_id); return false; } } return $this->query_result; } else { if ($this->in_transaction ) { mysql_query("ROLLBACK", $this->db_connect_id); $this->in_transaction = FALSE; } return false; } } function sql_numrows($query_id = 0) { if(!$query_id) { $query_id = $this->query_result; } return ($query_id) ? mysql_num_rows($query_id) : false; } ?> Any insight that can help to benefit these functions would be appreciated. I need to call usort from a class function, and I'm puzzled about how to define the comparison function. I've tried to define the comparison function in the same class, but I can't get usort to call it. I found one hint that it will work if I make the comparison function static, but I tried that, and it didn't work for me. If I define the comparison function outside the class, it won't have access to object properties that it needs to operate. The only solution I can think of is to define the comparison function outside the class and put the object properties it needs in globals. Is there a cleaner way to do this? I want to define a function instead of repeating query in all my php pages. I call a function by passing an $id value and from that function i have to get all the info related to that id, like name, description and uom.
I am trying to do this, but i dont know how to get these values seperately.
here is my function
function items($item_id)
{
$details = array();
$result = mysql_query("select item_id, name, uom, description from items where item_id=".$item_id."") or die (mysql_error());
while($row = mysql_fetch_array($result))
{
$details[] = array((stripslashes($row['name'])), (stripslashes($row['uom'])), (stripslashes($row['description'])));
}
return $details;
}
and i call my function like this
$info = items($id);Can somebody guide me in this When I put this chunk of code into it's own function: function fetch_all ($dbc, $query) { include ('knuffix_list_func.php'); pagination_start ($dbc, $query); $offset = $pag_array[0]; $rows_per_page = $pag_array[1]; $query = $query . " LIMIT $offset, $rows_per_page"; echo "test query: " . $query; knuffix_list ($query, $dbc); pagination_end ($pag_array); } And when I echo out the query as you can see in the example, then I notice that the variables $offset and $rows_per_page never get appended. I set the variable $pag_array to a global inside the function pagination_start(). It usually works when I DON'T wrap a function around this chunk of code, but if I do wrap a function around everything then the global suddenly won't work anymore. Btw, this also won't work if I wrap a function around the function DECLARATIONS. Any ideas, how I could make it work? |
|||||||