PHP - Wierd Problem
For some odd reason, when I add a snippet of PHP code to a certain page, it whitespaces the whole thing. I have other PHP snippets scattered around already. When I delete it, page is ok, with it, nothing but a grey border, all content is white. Freakin wierd. Here is the code...
$day = date('d'); $month = date('m'); $year = date('Y'); $last = last_business_day($year,$month); $lastday = date('d', strtotime($last)); if($day > "15"){ $date2 = date("Y-m-" . $lastday); } else { $date2 = date("Y-m-15"); } $date1= date('Y-m-d'); $time = " 23:59:59"; $date3 = $date2 . $time; $agency = $_SESSION['AGENCY']; $agent = $_SESSION['AGENTNAME']; $query = "SELECT Amount1RS, SUM(BrokerFee), SUM(TotalCollected), SUM(Commission), AVG(BrokerFee), COUNT(ID) FROM accounting WHERE agency = '$agency' AND agent = '$agent' AND Amount1RS = 'New Business' AND Date BETWEEN '$newdate1' AND '$date3'"; $result = mysql_query($query); while($myrow = mysql_fetch_assoc($result)) {//begin of loop $totbroker = $myrow['SUM(BrokerFee)']; $avgbroker = $myrow['AVG(BrokerFee)']; $totcommission = $myrow['SUM(Commission)']; $totproduction = $myrow['SUM(Commission)'] + $myrow['SUM(BrokerFee)']; } $proquery = mysql_query("SELECT COUNT(ID) FROM clients WHERE Status = 'Prospect' AND Agency = '$agency' AND agentname = '$agent'") or die(mysql_error()); $prospects = mysql_fetch_array($proquery); $insquery = mysql_query("SELECT COUNT(ID) FROM clients WHERE Status = 'Insured' AND Agency = '$agency' AND agentname = '$agent'") or die(mysql_error()); $insureds = mysql_fetch_array($insquery); $closing = ($insureds / $prospects) * 100; $closing = floatval($closing); I even put it in teh <head> tag, same result. Anyone encountered this before? Similar TutorialsHello All,
I'm kinda new to PHP and web development and I seem to have a very wierd problem which is driving me nuts (for the last 2 days)...so I'd appreciate any and all help in getting it resolved.
Okay, so here's the problem:
In the code below, I used to have just the first statement below...which essentially accepted input as a textbox for a text field named qty_pkg (in the underlying MySQL table)...and that used to work just fine.
So then I decided to change the input type for that field to be a radio button, accepting one of two choices i.e. "UoM" or "Qty", and therefore I added the remainder of the code, whilst also commenting/remarking out the first statement.
What happens (when I added the radiobutton-related code) is that control no longer goes into the TRUE portion/logic of the "if ( !empty($_POST))" condition-check, but rather, it seems to go into the "ELSE/FALSE" portion of that conditional check. However, a record does get added to my table, even though I do not have an "INSERT INTO..." clause in the ELSE porition of that check. Also, what gets displayed on screen is as follows:
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Array()
There's something wrong somewhere!!!
Array()
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Now, if/when I comment/remark the radiobutton-related code, the "if ( !empty($_POST))" logic seems to work fine and the following is displayed on screen (which is what I expect):
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Array ( [datepicker] => 10/30/2014 [store_id] => 48 [new_store_name] => [item_id] => 5 [new_item_name] => [pkg_of] => 1 [price] => 1 [flyer_page] => 1 [limited_time_sale] => Array ( [0] => fri [1] => sat ) [nos_to_purchase] => 1 [create-and-add-more] => Create and Add More ) Notice: Undefined index: qty_pkg in /var/www/create.php on line 54 Array ( [0] => Array ( [item_id] => 5 [0] => 5 [item_name] => BD Cheese Strings [1] => BD Cheese Strings [section_id] => 7 [2] => 7 ) ) ------------------------------------------------------------------------------------------------------------------------------------ The other wierd thing is that if/when I now uncomment the first statement (which used to work just fine before) the "if ( !empty($_POST))" logic no longer seems to work the way it used to. Does/can someone see something wrong with my code somewhere? <!-- <?php echo standardInputField('Qty / Pkg', 'qty_pkg', $qty_pkg, $errors); ?> --> <div class="control-group"> <label class="control-label">Priced by:</label> <div class="priced-by-radio-container"> <div class="pb-radiobuttons-container"> <label class="indent-to-the-left"> <input class='priced-by-radiobutton' type='radio' name='qty_pkg' value='UoM' $pb1> <span class='no-highlight'>Unit of Measure</span> </label> <label> <input class='priced-by-radiobutton' type='radio' name='qty_pkg' value='Qty' $pb2> <span class='no-highlight'>Quantity</span> </label> </div> </div> </div> <?php echo standardInputField('UoM Name/Pkg. Of:', 'pkg_of', $pkg_of, $errors); ?> <?php echo standardInputField('Price:', 'price', $price, $errors); ?> <?php echo standardInputField('Flyer Page #:', 'flyer_page', $flyer_page, $errors); ?> print_r($_POST); if ( !empty($_POST)) { // keep track of $_POST(ed) values by storing the entered values to memory variables $store_id = $_POST['store_id']; $item_id = $_POST['item_id']; $qty_pkg = $_POST['qty_pkg']; $pkg_of = $_POST['pkg_of']; ... ... $sql = "INSERT INTO shoplist (store_id,item_id,qty_pkg,pkg_of,price,flyer_page,limited_time_sale,flyer_date_start,nos_to_purchase,section_id,shopper1_buy_flag,shopper2_buy_flag,purchased_flag,purchase_later_flag,no_flag_set) VALUES(?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)"; $q = $pdo->prepare($sql); $q->execute(array($store_id,$item_id,$qty_pkg,$pkg_of,$price,$flyer_page,$limited_time_sale,$flyerDateStart,$nos_to_purchase,$section_id,$initialize_flag_N,$initialize_flag_N,$initialize_flag_N,$initialize_flag_N,$initialize_flag_Y)); } else { echo "<br />There's something wrong somewhere!!!<br />"; print_r ($_POST); $qty_pkg = ''; $pkg_of = '';;Thanks. two codes: does not echo the script... if($content1_1on1 || $content1_teams) { echo ''; echo "<script type='text/javascript'>$.jGrowl('<b>$header1</b> <br><br> $content1_1on1 <br> $content1_teams');</script>"; } does echo the script... if($content1_1on1 || $content1_teams) { echo 's'; echo "<script type='text/javascript'>$.jGrowl('<b>$header1</b> <br><br> $content1_1on1 <br> $content1_teams');</script>"; } can anyone tell me why it does not echo the script if there is nothing in the first echo?? I can't figure it out hello, just curious if anyone has ever used php to pull any kind of info from a blackberry? im trying to pull something unique from a blackberry like a pin number . Hi Everyone I have a weird session issue going on and i'm not sure what is causing it. Basically any sessions that i set are randomly expiring sooner than they should be. As a test I did the following: Code: [Select] <?php session_start(); if(isset($_SESSION['views'])){ $_SESSION['views'] = $_SESSION['views']+ 1; }else{ $_SESSION['views'] = 1; } echo "views = ". $_SESSION['views']; echo '<p><a href="testpage.php">Refresh</a></p>'; ?> If i continue to click the refresh button, i sometimes get to 30 and then it starts at 1 again. Other times ill get to 20 and then back to 1. It has also sometimes skips a couple of counts from 7 to 11 as an example in one click. Any one come across this before? I have been reading up online and some have mentioned PHP upgrades from php4 to php5 cause some issues and specifically the hosting company changing the session.save_path. If this was the case, it wouldn't even count to 10, would it? Any help would be really appreciated. thanks in advance I keep getting the following error even though it is still inserting it it is driving me nuts any ideas?
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '`campaignid`,`ipaddress`,`cc`,`country`,`oldadddate`,`oldaddtime`,`oldtimestring' at line 1
`oldrecordid`,`campaignid`,`ipaddress`,`cc`,`country`,`oldadddate`,`oldaddtime`,`oldtimestring`,`adddate`,`addtime`,`timestring` '1','1','58.9.96.60','TH','Thailand','2014-07-16','02:11:41','1405501901','2014-07-16','02:43:45','1405503825' my insert strings // INSERT IP RECORDS LOG $fi=""; $fi="`campaignid`,`ipaddress`,`cc`,`country`,`adddate`,`addtime`,`timestring`"; $fv=""; $fv="'$campaignid','$IpAddress','$cocode','$coname','$cdate','$ctime','$nowtime'"; echo "$fi<br />"; echo "$fv<br />"; $insertid="";$insertid=insertdata('iprecords',$fi,$fv,'yes');my function which has always worked until today if(!function_exists('insertdata')){ function insertdata($table,$fields,$params,$idrequired){ global $db_host; global $db_name; global $db_user; global $db_pass; $db_con=mysqli_connect($db_host,$db_user,$db_pass,$db_name); if(mysqli_connect_errno($db_con)){return false;} $insertinfo="INSERT INTO $table ($fields) VALUES ($params)"; $rinsertinfo = mysqli_query($db_con,$insertinfo); if($idrequired=="yes"){ $insertid =mysqli_insert_id($db_con); if($insertid==true) { return $insertid; } // END if($insertid==true) else { return false; } // END else } // END if($idrequired=="yes") else { return $rinsertinfo; } // END else mysqli_close($db_con); } // END function insertdata($table,$fields,$params.$idrequired) } // END if(!function_exists('insertdata')) Edited by shadiadiph, 16 July 2014 - 04:58 AM. I'm using WampServer to test php pages locally. I just started having this warning message show up: Warning: session_start() [function.session-start]: open(c:/wamp/tmp\sess_3c3f4g0dhb6qu007v167pv1u45, O_RDWR) failed: Permission denied (13) in C:\wamp\www\page_include\index.inc.php on line 2 The warning shows up and I am directed to the login page. The funny thing is, when I refresh the browser, the warning goes away and the page is directed to the page the user is directed to after they are signed in. I haven't changed any of my code since everything was working fine. Is this a problem with WampServer or possibly something that I should be looking at changing my code to fix? Any suggestions? Thanks. I got a code that figurse out if the user have watched that movie already or not now the wierd thing about it it let see if he watched buth not if he didnt watched: Code: $uid = $_COOKIE["cookname"]; $tid = $torrent["id"]; $con = mysql_connect("localhost","jornherm_acbteam","*******"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("jornherm_acbteam", $con); $query5 = "SELECT uid, tid FROM torrents_seen WHERE uid = '$uid' AND tid = '$tid'"; $gezien = mysql_query($query5); while($row = mysql_fetch_assoc($gezien)) { $uid2 = $row['uid']; $tid2 = $row['tid']; if (empty($tid2)) { echo "<img src=\"./images/notseen.png\" border=\"0\">"; } else { echo "<img src=\"./images/seen.png\" border=\"0\">"; } } DB Structu tid,uid tid=the id of the movie uid=the username Guys thanks for helping me solve the problem i had but now i have another problem and i am lost. i have included the code below for you to have overview.
This is the code:
<table style="width:100%; margin-left:auto; margin-right:auto"> so i want to call my php file with a query string to select a record out of a XML file... im close but cant get the variable i pass to be the record selected.. example... index.php?auction=1 i highlighted in red, where it doesnt pick up the proper row Code: [Select] <?php ini_set('display_errors', 1); error_reporting(E_ALL); $auction = $_GET{auction}; // parse the xml $xmlFileData = file_get_contents("items.xml"); $xmlData = new SimpleXMLElement($xmlFileData); [color=red]$location = $xmlData->item[$auction];[/color] //Retrieving the content from the selected item $title = $location->title; $value = $location->value; $itemnumber = $location->itemnumber; $description = $location->description; $donatedby = $location->donatedby; $image1 = $location->image1; $image2 = $location->image2; $image3 = $location->image3; $image4 = $location->image4; $image5 = $location->image5; $image6 = $location->image6; $image7 = $location->image7; $image8 = $location->image8; ?> <style> .itemimages img {width: 10px; height: 10px;} img.large {width: 100px; height: 100px;} </style> <script language="JavaScript" src="http://code.jquery.com/jquery-1.5.min.js" type="text/javascript"></script> <script> $().ready(function() { $(".itemimages img").click( $("#largepic").attr("src","this"); }); }); </script> <table border="1" cellpadding="10"> <tr> <td valign="top"> <img src="<?php echo $image1 ?>" alt="" border="0" class="large" id="largepic"><br> <div class="itemimages"> <?php // image 1 if (trim(''.$image1) != '') { echo "<img src='"; echo $image1; echo "' alt='' border='0'/> "; } // image 2 if (trim(''.$image2) != '') { echo "<img src='"; echo $image2; echo "' alt='' border='0'/> "; } // image 3 if (trim(''.$image3) != '') { echo "<img src='"; echo $image3; echo "' alt='' border='0'/> "; } // image 4 if (trim(''.$image4) != '') { echo "<img src='"; echo $image4; echo "' alt='' border='0'/> "; } // image 5 if (trim(''.$image5) != '') { echo "<img src='"; echo $image5; echo "' alt='' border='0'/> "; } // image 6 if (trim(''.$image6) != '') { echo "<img src='"; echo $image6; echo "' alt='' border='0'/> "; } // image 7 if (trim(''.$image7) != '') { echo "<img src='"; echo $image7; echo "' alt='' border='0'/> "; } // image 8 if (trim(''.$image8) != '') { echo "<img src='"; echo $image8; echo "' alt='' border='0'/> "; } ?> </div> </td> <td valign="top"> <?php echo $title ?><br> Estimated Value: <?php echo $value ?><br> Item Number: <?php echo $itemnumber ?><br><br> <?php echo $description ?><br><br> Donated by: <?php echo $donatedby ?><br> </td> </tr> </table> Hows it going guys. I am currently having a problem. I had a program that worked. I migrated the website and now the program is broken. Any time i try to run it, i get this error: Quote Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/thegoo20/public_html/class/wordgame/wordgame.php on line 31 Here is the code at that point: Code: [Select] function changeword(){ $result = mysql_query("Select words from CurrentWords"); $totalwords = array(); while ($row = mysql_fetch_array($result)){ $totalwords[] = $row["words"]; } $_SESSION['word'] = $totalwords[rand(0, count($totalwords)-1)]; $_SESSION['scrambled'] = str_shuffle($_SESSION['word']); } where line 31 is the while statement. Any help would be appreciated. Thanks Okey so i made a table that you put your name,author,and message when you submit it , it echoes a table with the name,author and message written (and it also echoes a delete buttom,so delete this post oif necessary) im new to php and i have been with this problem for a couple of weeks so i guess its time to ask for some help the problem is that i dunnot know how to make my delete buttom work! i tried if statement but it dosent work i also tried ternary operation and dint work :S i read that there is something like $post[ID](and this is supposed to get the ID of the post submmited, and delete it) im not sure, im so confused! help! XD this is the code <?php $tittle=$_POST['tittle']; $author=$_POST['author']; $message=$_POST['message']; if ($_POST['submitnews']){ $currentdate= date("y-m-d"); $currenttime=date("H:i:s",strtotime("-6 hours")); $post=mysql_query("INSERT INTO news VALUES('','$tittle','$author','$message','$currentdate','$currenttime')"); echo"Posted!"; } $select=mysql_query("SELECT * FROM news ORDER BY id DESC"); while ($row= mysql_fetch_assoc($select)) { $id=$row['id']; $tittle=$row['tittle']; $author=$row['author']; $message=$row['message']; $date=$row['date']; $time=$row['time']; if ($_SESSION['admin']) { echo " <table width='488px' id='news_table'> <tr> <td> </td> <td> <center><font size='5'>$tittle</font></center><br> </td> </tr> <tr> <td> </td> <td> $message </td> </tr> <tr> <td> </td> <td> <font size='1'>Posted By:<font color='green'>$author</font> on <font color='gray'>$date</font> at <font color='gray'>$time</font></font> <input name='delete' type='submit' value='delete'> <td> </td> </tr><br><br> </table>"; Hi, I am trying to write in an existing excel file. But for some reason, I can't open the workbook (but I know I have made similar code work before). Here I am just pasting the code upto the error line $filename="C:\\apache\\htdocs\\GAC2\\dload\\template.xls"; $excel = new COM("excel.application") or die("Unable to instanciate excel"); $excel->Visible = 1; $excel->DisplayAlerts = 1; try{ $wkb = $excel->Workbooks->Open($filename); }catch (Exception $e) { echo 'Caught exception: ', $e->getMessage(), "\n"; } //........ Later part of the code This returns the following error Code: [Select] Caught exception: Source: Microsoft Office Excel Description: Unable to get the Open property of the Workbooks class For record, the I have already validated the file location. And I have tried the following line instead without any positive result. Code: [Select] $filename="C:\apache\htdocs\GAC2\dload\template.xls"; Looking for any help please. -Abd Hey guys i just installed a new Theme on my IPB 3.3.4 its called Dashboard now, the start page looks fine but if i try to click on "My Profile" an error pops up.
Error message:
Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE), expecting identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING) in C:\xampp\htdocs\board\cache\skin_cache\cacheid_4\skin_profile.php on line 1035
skin_profile.php on line 1035:
<span class='ipsType_smaller desc lighter blend_links'><a href='" . $this->registry->getClass('output')->formatUrl( $this->registry->getClass('output')->buildUrl( "app=members&module=profile&section=status&type=single&status_id={$status['status_id']}", "public",'' ), "array($status['member_id'], $status['members_seo_name'])", "members_status_single" ) . "'>{$this->lang->words['ps_updated']} " . $this->registry->getClass('class_localization')->getDate($status['status_date'],"manual{%d %b}", 0) . " · " . intval($status['status_replies']) . " {$this->lang->words['ps_comments']}</a></span>
i have the following sql running on local but i get an error. the sql: $sql = "SELECT * FROM '".TBL_PARENTS."'" or die(mysql_error()); the config file: define('DB_PREFIX', 'forum_'); define('TBL_PARENTS', DB_PREFIX.'parents'); the error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''forum_parents'' at line 1 the echoed sql: SELECT * FROM 'forum_parents' as you can see when it is echoed it looks fine. Any ideas? The server im using is wamp server. hello! I have a problem with utf-8 ...
In horizontalmenu.php I have:
print '<a href="/calcioitalia/coaches/'.$name.'.html').'">'.$name.'</a>';where $name=José Márioand in .htaccess I have AddDefaultCharset UTF-8 AddCharset UTF-8 .htmland doesn't work... How could I solve this problem? Thank u! I do not receive email for my published php file which is: <?php ///// easend.php ///// $youremail = "acdelco40108@yahoo.com"; /*put the email address here, between quotes, the email address you want the message sent to*/ $to = $youremail; $email = $_POST['EMail']; $name2 = $_POST['Name']; $street2 = $_POST['Street']; $city2 = $_POST['City']; $state2 = $_POST['State']; $zip2 = $_POST['Zip']; $Phone = $_POST['Home_Phone']; $Cell = $_POST['Cell_Phone']; $education = $_POST['email1']; $comments = $_POST['email2'] ; $headers = "From:" . $email; $fields = array(); $fields{"Name"} = "Name"; $fields{"Street"} = "Street"; $fields{"City"} = "City"; $fields{"State"} = "State"; $fields{"Zip"} = "Zip"; $fields{"Home_Phone"} = "Home Phone"; $fields{"Cell_Phone"} = "Cell Phone"; $fields{"EMail"} = "Email"; $fields{"email1"} = "Education"; $fields{"email2"} = "Comments"; $subject = "We have received the following information from your employment application"; $body = "We have received the following information from your employment application:\n\n"; foreach($fields as $a => $b) { $body .= sprintf("%20s: %s\n",$b,$_POST[$a]); } mail ($to, $subject, $body, $headers); //send mail to owner #end create email vars $headers = "From:" . $to; mail ($email, $subject, $body, $headers); //send mail to user #end create email vars echo "<head><META HTTP-EQUIV=\"Refresh\" CONTENT=\"2; URL=ThankYou.html\"></head>"; ?> Code: [Select] <?php require('config.php'); $sql = "SELECT m.Title as title , f.Reg_URL as reg FROM website_main as m JOIN website_front as f LIMIT 0,01 "; $result = @mysql_query($sql) or die(mysql_error()); echo "<table border='3'>"; echo "<font size='9'><tr> <th><FONT COLOR=red><center>Title</center></font></th> <th><FONT COLOR=red>reg</th> </tr></font>"; // keeps getting the next row until there are no more to get while($row = mysql_fetch_array( $result )) { // Print out the contents of each row into a table $reg = $row['reg']; echo "<tr><td bgcolor=''><center>"; echo $row['title']; echo "</td><td bgcolor=''><center>"; echo '.$reg.'; echo "</td></tr>"; } ?> I got a problem i try to use an attribute for $reg but only appears as .$reg. on website anyone know why? Parts i have problems with are $reg = $row['reg']; and echo '.$reg.';. thank you I Have An error on line 42 not sure what it is can any one tell? $foundnum = mysql_num_rows($run); Hi there, I have a map of America made in flash, where you click on a state and the page should display the SQL database information for that state in the HTML table - but instead all it shows is the first entry of the database regardless of which state you click and it doesn't display the 2 radio buttons. My code is as follows Flash Actionscript 3 (just showing one state) Code: [Select] function waClick(event:MouseEvent):void { var waURL:URLRequest = new URLRequest("restaurants.php?state=Washington"); navigateToURL(waURL, "_self"); } wa_btn.addEventListener(MouseEvent.CLICK, waClick); PHP code Code: [Select] <?php include("mvfconnect.php"); $theChoice = $_GET['state']; $query = "SELECT * FROM restaurants WHERE" .$theChoice; $result = @ mysql_query($query); if (!$result) { $message="Unfortunately we are having problems with this page, we promise to have it fixed as soon as possible"; die($message); } $num = mysql_num_fields($result); $i=0; while ($row = mysql_fetch_array($result, MYSQL_ASSOC)){ $show1=substr($row['state'],0,50)."..."; $show2=substr($row['city'],0,50)."..."; $show3=substr($row['rname'],0,50)."..."; $show4=substr($row['address'],0,50)."..."; $show5=substr($row['pnum'],0,50)."..."; $show6=substr($row['web'],0,50)."..."; $show7=substr($row['dishes'],0,50)."..."; $show8=substr($row['dish_details'],0,50)."..."; $show9=substr($row['challenges'],0,50)."..."; $show10=substr($row['challenge_details'],0,50)."..."; $show11=substr($row['youtube'],0,50)."..."; $show12=substr($row['images'],0,50)."..."; echo "<tr>". "<td>".$row['city']."</td>". "<td>".$row['rname']."</td>". "<td>".$row['address']."</td>". "<td>".$row['pnum']."</td>". "<td>".$row['web']."</td>". "<td>".$row['dishes']."</td>". "<td>".$row['challenges']."</td>". "<td id='state".$i."' style='display:none'>".$row['state']."</td>". "<td id='city".$i."' style='display:none'>".$row['city']."</td>". "<td id='rname".$i."' style='display:none'>".$row['rname']."</td>". "<td id='address".$i."' style='display:none'>".$row['address']."</td>". "<td id='pnum".$i."' style='display:none'>".$row['pnum']."</td>". "<td id='web".$i."' style='display:none'>".$row['web']."</td>". "<td id='dishes".$i."' style='display:none'>".$row['dishes']."</td>". "<td id='dish_details".$i."' style='display:none'>".$row['dish_details']."</td>". "<td id='challenges".$i."' style='display:none'>".$row['challenges']."</td>". "<td id='challenge_details".$i."' style='display:none'>".$row['challenge_details']."</td>". "<td id='youtube".$i."' style='display:none'>".$row['youtube']."</td>". "<td id='images".$i."' style='display:none'>".$row['images']."</td>". "<td><input type='radio' name='vid' id='vid".$i."' onclick='openVideo(".$i.")' /></td>". "<td><input type='radio' name='pic' id='pic".$i."' onclick='openImage(".$i.")' /></td>". "<td class='last'style='display:none'>".$show1." ".$show2." ".$show3." ".$show4." ".$show5." ".$show6." ".$show7." ".$show8." ".$show9." ".$show10."</td>". "</tr>"; $i++; } ?> I have used this code before and it has worked fine, can someone please help me out! |