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PHP - Moved: Adding An Encode To My Sql Insert Statement
This topic has been moved to MySQL Help.
http://www.phpfreaks.com/forums/index.php?topic=315503.0 Similar TutorialsThis topic has been moved to Other. http://www.phpfreaks.com/forums/index.php?topic=357168.0 Hi, I would like to know how to write Insert data into a table statement where some of the data is coming from another table? I tried using Insert select statement but did not work. Here is what I am trying.... 1.........$sql = "INSERT INTO table1(id,fname, lname, gender, add1, add2, city, state, zip, country, email, phone, cellphone,employment,employmentinfo,dob, photo1,info) VALUES('$id','$fname','$lname','$gender','$add1','$add2','$city','$state','$zip','$country','$email','$phone','$cellphone','$employment','$employmentinfo','$dob','" . $image['name'] . "','$info') SELECT table2.id from table2 where table2.id=$id"; 2..........$sql = "INSERT INTO table1(id,fname, lname, gender, add1, add2, city, state, zip, country, email, phone, cellphone,employment,employmentinfo,dob, photo1,info) VALUES((SELECT id FROM table2 WHERE table2` WHERE username='".$_POST['username']."'),'$fname','$lname','$gender','$add1','$add2','$city','$state','$zip','$country','$email','$phone','$cellphone','$employment','$employmentinfo','$dob','" . $image['name'] . "','$info')"; I would appreciate your help. Thanks Smita I have a simple INSERT statement that isn't inserting anything into one of the columns: coin_name I've gone over everything and can't figure out why. All other columns get data. HTML form passes everything fine. Is there a good way to debug this? I've triple checked everything and there are no type-o's that I see. Driving me mad... $query = "INSERT INTO Coin (coin_name, coin_value, coin_condition, year_minted, face_value, purchase_price) VALUES ('$coin_name', '$coin_value', '$coin_condition', '$year_minted', '$face_value', '$purchase_price');"; I am new to PHP and am currently learning the ropes. I have writen some code to insert a line into a mySQL database. I have created 3 fields in the mySQL database and am passing values two them. I can use a declared variable to pass information to the filed ID (Index filed in mySQL) but if I use a variable to pass purely text values the database is not updated. mysql_query( "INSERT INTO $tbl_name (category_Name, ID, test) VALUES ($category, $internalId, $category2)" ); If I replace the variables with specific text, the rows are added successfully. mysql_query( "INSERT INTO $tbl_name (category_Name, ID, test) VALUES ('werwerwer', $internalId, 'werrr')" ); It must be something stupid, I am sure. Full code below ob_start(); $host="localhost:8888"; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name="expenses"; // Database name $tbl_name="expense_category"; // Table name $category="test3"; $internalId="7"; $category2="test3"; // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); mysql_query( "INSERT INTO $tbl_name (category_Name, ID, test) VALUES ('werwerwer', $internalId, 'werrr')" ); echo "Done now 6!"; ?> I have a bunch of checkboxes I am pulling from a database, like so. Code: [Select] <?$true_query = mssql_query("SELECT * FROM checkbox_datbase ORDER BY ID ASC"); while ($true_row = mssql_fetch_assoc($true_query)) { $eth_id = $true_row['ID']; $eth_name = $true_row['Value']; echo "<input type=\"checkbox\" name=\"eth_$eth_id\" value=\"1\" class=\"input\" id=\"Ethnic_01\"/>$eth_name <br />"; } ?>How do I put these into a database that I have settup where it needs to match up with a userid. I am trying to do this, and can get it to look correctly by echoing out the various parts, but I can't put while loops into a variable, right? So how would I get all of this into one line in my $sql variable? Code: [Select] echo "INSERT INTO new_database (UserId,"; $true_query = mssql_query("SELECT * FROM checkbox_datbase ORDER BY ID ASC"); while ($true_row = mssql_fetch_assoc($true_query)) { $eth_id = $true_row['ID']; $eth_eth_id = $_POST['eth_' . $eth_id . '']; echo " $eth_id, "; } echo "DateUpdated) VALUES ('$user_ID', "; $true_query = mssql_query("SELECT * FROM checkbox_datbase ORDER BY ID ASC"); while ($true_row = mssql_fetch_assoc($true_query)) { $eth_id = $true_row['ID']; $eth_eth_id = $_POST['eth_' . $eth_id . '']; echo "'$eth_eth_id', "; } echo "'$currenttime')"; This echoes something that looks like this INSERT INTO user_ethnicity (UserId, 1, 2, 3, 4, 5, 6, 7, 8, DateUpdated) VALUES ('', '', '', '', '', '', '', '', '', '2012-01-23 13:24:18 PM') , which I need the actual statement to be $sql = "INSERT INTO user_ethnicity (UserId, 1, 2, 3, 4, 5, 6, 7, 8, DateUpdated) VALUES ('259', '', '', '1', '', '1', '', '', '', '2012-01-23 13:24:18 PM')"; Can anyone help me with this? Folks, Tell me, do you see anything wrong in my INSERT ? If not, then why is it not INSERTING ? I get no php error, nor mysql error. Button I click. Then form data vanishes as if submitted. I check db and no submission came through!
<?php
//include('error_reporting.php');
ini_set('error_reporting','E_ALL');//Same as: error_reporting(E_ALL);
ini_set('display_errors','1');
ini_set('display_startup_errors','1');
?>
<form name = "submit_link" method = "POST" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<label for="domain">Domain:</label>
<input type="text" name="domain" id="domain" placeholder="Input Domain">
<br>
<label for="domain_email">Domain Email:</label>
<input type="email" name="domain_email" id="domain_email" placeholder="Input Domain Email">
<br>
<label for="url">Url:</label>
<input type="url" name="url" id="url" placeholder="Input Url">
<br>
<label for="link_anchor_text">Link Anchor Text:</label>
<input type="text" name="link_anchor_text" id="link_anchor_text" placeholder="Input Link Anchor Text">
<br>
<textarea rows="10" cols="20">Page Description</textarea>
<br>
<label for="keywords">Keywords:</label>
<input type="text" name="keywords" id="keywords" placeholder="Input Keywords related to Page">
<br>
<button type="submit">Click me</button>
<br>
<input type="reset">
<br>
</form>
<?php
if($_SERVER['REQUEST_METHOD'] === 'POST')
{
/*
if(ISSET($_POST['submit_link']))
{*/
mysqli_report(MYSQLI_REPORT_ALL|MYSQLI_REPORT_STRICT);
mysqli_connect("localhost","root","","test");
$conn->set_charset("utf8mb4");
if(mysqli_connect_error())
{
echo "Could not connect!" . mysqli_connect_error();
}
$query = "INSERT into links (domain,domain_email,url,link_anchor_text,page_description,keywords) VALUES (?,?,?,?,?,?)";
$stmt = mysqli_stmt_init($conn);
if(mysqli_stmt_prepare($stmt,$query))
{
mysqli_stmt_bind_param($stmt,'ssssss',$_POST['domain'],$_POST['domain_email'],$_POST['url'],$_POST['link_anchor_text'],$_POST['page_description'],$_POST['keywords']);
mysqli_stmt_execute($stmt);
mysqli_stmt_close($stmt);
mysqli_close($conn);
}
else
{
die("INSERT failed!");
}
//}
}
?>
@MacGuyver,
I will do the VALIDATIONS later. Remember, I was testing myself how much I can code without notes. What you see above was from my memory. Am still a beginner php student for 3yrs now, however! As for validation stuff will have to check notes and learn or relearn. Meaning, have to memorise the code before I add it here on current project. And so for now, ignore VALIDATIONS and let me know why it's not submitting data into db.
I am trying to create a query to insert data into a table in my Access database. I have the following query:
INSERT INTO Issues (DateRequested, CustomerID, ComputerID, Issue, ItemsIncl, ImageName) VALUES (#1/14/2015#, 1, 1, "Computer freezes while I'm on the internet.", "AC Adapter", "none.gif")which should be performed from within my PHP page. However, when I check the database afterward, the new record isn't there. I then tried performing the query directly in Access and it worked fine. Why would it work in Access, but not when I run the same query in PHP? Chris Hello, guys. I am experiencing some problems with an INSERT statement in this page. It simply won't write to the database! I added echo at the bottom to check my variables and they print the values just fine. I checked the database, table and datafield names and everything is correct, plus I don't have any issues with the other 25 tables of my database. I'm using XAMPP btw... Any help would be appreciated! Code: [Select] <!DOCTYPE html> <html> <head> <meta content="text/html; charset=utf-8" http-equiv="content-type"> <title>Doctors</title> <link rel="stylesheet" href="style.css" media="screen" /> </head> <body > <?php session_start(); $inc_code=$_SESSION['incident']; $doc_code=$_REQUEST['doctor_code']; $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } $mdb = "registry_db"; mysql_select_db($mdb, $con); mysql_query("SET NAMES 'utf8'", $con); ?> <div id="myform"> <p> <h2>Doctor in charge</h2> </p> <?php $sql="INSERT INTO doctors_per_incident(Incident_code, doctor_code) VALUES ('$inc_code', '$doc_code')"; echo "1 record added"." ".$inc_code." ".$doc_code; mysql_close($con); ?> </div> </body> </html> So I have this snippet of code: Code: [Select] $row['ratings'] = ""; $ratingsSQL = $this->ipsclass->DB->query( "SELECT `pid` , `rating` , COUNT(`rating`) as ratings FROM `ibf_ratings` WHERE `pid` = '" . $row['pid'] . "' GROUP BY `rating` "); $i = 0; $ratingshtml = ""; if( $this->ipsclass->DB->get_num_rows( $ratingsSQL ) ) { while( $rrow = $this->ipsclass->DB->fetch_row( $ratingsSQL ) ) { $ratingshtml .= "<div class=\"rate_it_display\" style=\"background-image: url( 'style_images/rate/" . str_replace( ' ' , '' , strtolower( $this->ratings[$rrow['rating']] ) ) . ".png' ) \"> " . $rrow['ratings']. " x " . $this->ratings[$rrow['rating']] . "!</div>"; $i++; } $ratingshtml .= "<a href=\"#\" onclick=\"return RateItExpand( {$row['pid']} );\" style=\"color: #999;\">(list)</a>"; } $row['ratings'] = $this->ipsclass->compiled_templates['skin_topic']->ratings( $row['pid'] , $row['author_id'] , $ratingshtml ); I want to add an if statement to the code so that the ratings won't load unless a user clicks a button at the top of the screen. Can anyone help me with this? I'd be very appreciative. Thanks in advance. I am trying to insert a record into a mysql database which has a $ as part of the value of a field. But it seems that when the INSERT query is processed its actually looking for a variable with that name and not just inserting the raw text. Here is the insert query $query = "INSERT mytable SET myfield='I would like to have this field contain this information with a $matches[1] showing in the field value as well'"; $matches[1] has no value. Its not a variable which is in this script. I am not trying to insert the value of it. I just want to insert the actual text characters $matches[1] How can I do that? Within PHP I am attempting to insert some data into a MySQL table, however the value that needs to be stored inside the database field contains a semi-colon ; $q_options_data = "INSERT INTO mytable SET myfield = 'a:5:{s:13:\"administrator\";a:2:{s:4:\"name\";s:13:\"Administrator\";'"; I tried just escaping the ; with a \; but that didn't work I am using PHP 5.2.9 and MySQL 5.0.91-community Thanks, Chad Hi, Im just having some trouble with this...maybe a fresh pair of eyes can help? Im getting a "Warning: mysqli_stmt::bind_param() [mysqli-stmt.bind-param]: Number of elements in type definition string doesn't match number of bind variables" error when I try run this: Code: [Select] $date = date("Y-m-d"); $header = $_POST['header']; $summary = $_POST['summary']; $content = $_POST['content']; $query = "INSERT INTO articles (pubdate, title, summary, content) VALUES(?, ?, ?, ?)"; $stmt = $mysqli->stmt_init(); if ($stmt->prepare($query)){ $stmt->bind_param('i,s,s,s', $date, $header, $summary, $content); $stmt->execute(); $stmt->close(); } else { echo "ERROR: SQL statement failure!"; echo "<a href='addnews.php'> -> OK</a>"; } $mysqli->close(); It looks fine to me, just can't see whats wrong lol! I'm trying to create a INSERT query statement that makes use of the content of 'include' files. When I call up the include it simply echos it to the screen but I can't seem to capture the text string and actually make it function as part of the query. I've tried setting the include as a variable but again it only outputs to the screen. Help please! Here's a portion of the code... if (($_POST['sched_templates']) == "sched_TestingOnly.htm") { $query = include 'sched_TestingOnlyQuery1.htm'; } if (@mysql_query ($query)) { mysql_close(); // End adding Registration to the database header ('Location: redirectfile.htm'); exit(); } else { print "<p><b>Sorry, your entry could not be entered. } Hi People. Please can someone tell me the code to add a time stamp (date and time) to insert into the database at the time of filling out the form. At the moment my form is putting "null" into this database field. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Stranded Flyer</title> </head> <body> <?php $host = 'localhost'; $usr = "the_user"; $password = 'thepassword'; $db_name = 'thedbname'; //connect to database mysql_connect ("$host","$usr","$password") or die ('Error During Connect:<br>'.mysql_error()); mysql_select_db ("$db_name") or die ('Error Selecting DB:<br>'.mysql_error()); $surname = mysql_real_escape_string($_POST['surname']); $firstname = mysql_real_escape_string($_POST['firstname']); $phone1 = mysql_real_escape_string($_POST['phone1']); $phone2 = mysql_real_escape_string($_POST['phone2']); $location = mysql_real_escape_string($_POST['location']); $qualifications = mysql_real_escape_string($_POST['qualifications']); $expertise = mysql_real_escape_string($_POST['expertise']); $assistance = mysql_real_escape_string($_POST['assistance']); $languages = mysql_real_escape_string($_POST['languages']); $e-mail = mysql_real_escape_string($_POST['e-mail']); $consent = mysql_real_escape_string($_POST['consent']); $published = mysql_real_escape_string($_POST['published']); $comments = mysql_real_escape_string($_POST['comments']); $other_info = mysql_real_escape_string($_POST['other_info']); $errorstring = ""; // default value of errorstring function makeSafe($value) { if (get_magic_quotes_gpc()) { $value = stripslashes($value); } $value = mysql_real_escape_string($value); return $value; } if(isset($_POST['submit'])) { // Validate all the code inputs // Captcha Validation require_once('recaptchalib.php'); $privatekey = "6Ld2xscSAAAAADwh3mCFkTObSHLAEKUAcU3ocpSv"; $resp = recaptcha_check_answer ($privatekey, $_SERVER["REMOTE_ADDR"], $_POST["recaptcha_challenge_field"], $_POST["recaptcha_response_field"]); if (!$resp->is_valid) { // What happens when the CAPTCHA was entered incorrectly $errorstring = $errorstring. "Invalid CAPTCHA, please try again"; } else { if ($surname =="") $errorstring = $errorstring. "Surname<br>"; if ($phone1 =="") $errorstring = $errorstring. "phone1<br>"; if ($phone2 =="") $errorstring = $errorstring. "phone2<br>"; if ($location =="") $errorstring = $errorstring. "location<br>"; if ($qualifications =="") $errorstring = $errorstring. "qualifications<br>"; if ($assistance =="") $errorstring = $errorstring. "assistance<br>"; if ($languages =="") $errorstring = $errorstring. "languages<br>"; if ($e-mail =="") $errorstring = $errorstring. "e-mail<br>"; if ($consent =="") $errorstring = $errorstring. "consent<br>"; if ($published =="") $errorstring = $errorstring. "published<br>"; if ($comments =="") $errorstring = $errorstring. "comments<br>"; if ($other_info =="") $errorstring = $errorstring. "other info<br>"; // does the errorstring = "nothing"? } // Figure out which error message to show i.e. field validation or CAPTCHA if ($errorstring !="") if (strstr($errorstring,"CAPTCHA")) echo $errorstring; else echo "You have not put anything in the following fields: <br><br> $errorstring"; //echo "If you have nothing to put in the box please type the word \"None\" or \"N\/A\""; //die ("Please try again, ensuring that you fill out all the fields!"); else { //echo "Your data has been saved"; $insert_query = "INSERT INTO HelperFormData (surname, firstname,phone1, phone2, location, qualifications, expertise, assistance, languages, e-mail, consent, published, comments, other_info,) VALUES ('$surname', '$firstname', '$phone1','$phone2', '$location', '$qualifications', '$expertise', '$assistance', '$languages', '$e-mail', '$consent', '$published', '$comments', '$other_info')"; $insert_action = mysql_query($insert_query) or die ('Error During Insert :<br>'.mysql_error().'<br><br>Error occured running the following code :<br>'.$insert_query); $id = mysql_insert_id(); echo "Thank you, Your details have been submitted."; //include "resultcard.php"; // Output what the form looks like // End of how the form looks } } if(!isset($_POST['submit']) || (isset($_POST['submit']) && !empty($errorstring))) { ?> <form name = "form1" method ="post" action=""> <table width="700" border="0" cellspacing="5" cellpadding="5" bgcolor = "#dddddd"> <caption> Submit Your Details </caption> <tr> <td width = "50"> </td> <td width = "240"> </td> <td width = "250"> </td> <td width = "160"><b>Example Input</b></td> </tr> <tr> <td> </td> <td>Surname</td> <td><input type='text' name='surname' size = '40' maxlength='30' value = '<?php echo $surname; ?>'></td> <td>Smith</td> </tr> <tr> <td> </td> <td>First Name</td> <td><input type='text' name='firstname' size = '40' maxlength='30' value = '<?php echo $firstname; ?>'></td> <td>Bill</td> </tr> <tr> <td> </td> <td>Phone 1</td> <td><input type='text' name='phone1' size = '40' maxlength='30' value = '<?php echo $phone1; ?>'></td> <td>07777 777777</td> </tr> <tr> <td> </td> <td>Phone 2</td> <td><input type='text' name='phone2' size = '40' maxlength= '30'value = '<?php echo $phone2; ?>'></td> <td>0118 123 4567</td> </tr> <tr> <td> </td> <td>Location</td> <td><input type='text' name='location' size = '40' maxlength='40'value = '<?php echo $location; ?>'></td> <td>52.289071,-1.952004</td> </tr> <tr> <td> </td> <td>Qualifications</td> <td><input type='text' name='qualifications' size = '40' maxlength='30' value = '<?php echo $qualifications; ?>'></td> <td>Electrician</td> </tr> <tr> <td> </td> <td>Expertise</td> <td><input type='text' name='qualifications' size = '40' maxlength='30' value = '<?php echo $expertise; ?>'></td> <td>Flexwings</td> </tr> <tr> <td> </td> <td>Assistance Offered</td> <td><input type='text' name='assistance' size = '40' maxlength='50' value = '<?php echo $assistance; ?>' /></td> <td>Trailer and Tow Car</td> </tr> <tr> <td> </td> <td>Language Skills</td> <td><input type='text' name='published' size = '40' maxlength='50' value = '<?php echo $language; ?>' /></td> <td><p>English / Spanish</p></td> </tr> <tr> <td> </td> <td>E-Mail</td> <td><input type='text' name='comments' size = '40' maxlength='50' value = '<?php echo $e-mail; ?>' /></td> <td><p>example@mail.net</p></td> </tr> <tr> <td> </td> <td>Consent</td> <td> <select name = "surface"> <option value = "Yes" <?php if ($_POST['consent'] == 'Yes') { echo 'selected="selected"'; } ?>>Yes</option> <option value = "No" <?php if ($_POST['consent'] == 'No') { echo 'selected="selected"'; } ?>>No</option> </select> </td> <td>Yes</td> </tr> <tr> <td> </td> <td>Published</td> <td> <select name = "food"> <option value = "Yes" <?php if ($_POST['published'] == 'Yes') { echo 'selected="selected"'; } ?>>Yes</option> <option value = "No" <?php if ($_POST['published'] == 'No') { echo 'selected="selected"'; } ?>>No</option> </select> </td> <td>Yes</td> </tr> <tr> <td> </td> <td>Comments</td> <td><textarea name= "remarks" input type = 'text' rows = "5" cols = "29" /><?php echo $remarks; ?></textarea></td> <td>As much info as possible 500 characters max</td> </tr> <tr> <td> </td> <td>Other Info</td> <td><textarea name= "warnings" input="input" type = 'text' rows = "5" cols = "29" /><?php echo $warnings; ?></textarea></td> <td>As much info as possible 500 characters max</td> </tr> <tr> <td> </td> <td><input type='submit' name='submit' value='Submit Your Info' /></td> <td colspan="2"> <? require_once('recaptchalib.php'); $publickey = "6Ld2xscSAAAAAH3_KiJoRLR4sEWFFQR4yAr5F1xi"; // you got this from the signup page echo recaptcha_get_html($publickey);?></td> </tr> </table> </form> </body> </html> <?php } ?> base64_encode is a perfect standard php encoding, but this produces = most of times. Is there an alternative making the encode by alphanumeric only? i know of Bace64 rot_13 is thare more than just this? (for urls) This topic has been moved to Editor Help (Dreamweaver, Zend, etc). http://www.phpfreaks.com/forums/index.php?topic=308819.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=312323.0 This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=358684.0 |
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