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PHP - Calling Up Class Variable
I am working on a site that was made a while ago and on a custom page I am making I am needing to call up variables and my brain is too fried to think up the solution for this. The standing code is this:
class site{ var $name = 'Site'; var $data = 'on'; { What I need to do is callup the variables, such as $name, as simple as possible. How would I do this? Similar TutorialsHi Can you call Class A's methods or properties from Class B's methods? Thanks. I have an existing instance of my class Database, now I want to call that instance in my Session class, how would I go about doing this? Ok. I know you can pass the object of a class as an argument. Example: class A { function test() { echo "This is TEST from class A"; } } class B { function __construct( $obj ) { $this->a = $obj; } function test() { $this->a->test(); } } Then you could do: $a = new A(); $b = new B($a); Ok so that's one way i know of. I also thought that you could make a method static, and do this: (assuming class A's test is 'static') class B { function test() { A::test(); } } But that is not working. I'd like to know all possible ways of accomplishing this. Any hints are appreciated. thanks Hi, I need to be able to call a class based on variables. E.G. I would normally do: Code: [Select] $action = new pattern1() but i would like to be able to do it dynamicaly: Code: [Select] $patNum = 1; $action = new pattern.$patNum.() Im wondering if that's possible? If so what would the correct syntax be? Many Thanks. This is probably a quick one. I am pretty new to OOP, in fact somewhat a novice. I am working a lot more with objects lately as my previous "flat" php experience doesn't allow me to create clean and expandable applications. Of course though, questions will always pop up (that's what you guys are for?) One concept I am having trouble understanding, is the method to call a class. What is the difference between?: Code: [Select] <?php $cat = new class(); ?> and just simply: Code: [Select] <?php new class(); ?> Both appear to have the same output from my small amount of practice, but the first way seems strange to me. Being that I am very new to OO PHP, the first way looks like it is just defining a var. But in reality it is calling the class and running it? This seems very backwards to me and I am having a hell of a time understanding it. I am aware that the first way seems to be the "proper" way, but just can't fathom it. Could someone explain this to me a little further? thanks much, I have a PHP config file called config.php. inside the file is simular to this: Quote <?php class JConfig { var $offline = '0'; var $editor = 'tinymce'; var $list_limit = '20'; } ?> From another file, i have included config.php, but how do I call $editor to get "tinymce"? Thanks I am calling an object from another class in the constructor of first class but when I call it in another function it does not access it's object. Here is the code. Code: [Select] <?php /* This is controller.php used to control the flow of data between view.php and model.php. This file cotains all the controlling mechanism of the data It was created on 11th Feb 2011 By Narjis Fatima for an Open Source Project and contains all the includes to the database etc. */ include ("view.php"); include ("functions.php"); $name = stripslashes($_GET['username']); $email = stripslashes($_GET['email']); //echo "in controller.php"; check_validate_input($name, $email); $newUser = new controller($name, $email); $action=$_GET['t']; $newUser->display_view($action); class controller { public $my_model; //is an object of model class public $user_info;//=array('id' , 'username' ,'role','email','interests','location', 'homepage'); function __construct($name,$email) { $my_model = new model(); $user_info = $my_model->check_members($name,$email); echo "<pre>"; print_r ($user_info); } function __destruct() { } function display_view($token) { echo "In display function"; echo "<pre>"; print_r ($user_info); if ($this->user_info == NULL) { if (($token=="register")) { show_registration_form(); } else{ show_mailing_form(); } } if ($this->user_info['role'] == "admin") { $myView = new view(); $myView->view_admin_menu(); } if ($this->user_info['role'] == "user") { $myView = new view(); $myView->view_user_menu() ; } }//close of function display_view() } /* name and email cominfg from index.php would be checked by the controoler class to be checked if it a vaild name and email. The database would be connected n the model.php*/ ?> The code for model.php is as follows Code: [Select] <?php //This is model.php created on 10th Feb 2011 .It deals with daytabase connection // //By NArjis Fatima //For the project of EDUForge an Open Source Software //include ("register.php"); class model{ public $dbh; public $user_arr=array('username','password','email','location','interest','homepage'); //cunstructor of model class //function to connect to database function __construct(){ try{ $this->dbh = new PDO("mysql:host=localhost;dbname=phpfaqproject",'root',''); //echo "connected"; } catch(PDOException $e){ echo $e-> getMessage(); } } public function check_members($username,$email) { //get_connected(); $sql = "SELECT * FROM account WHERE (username='" .$username ."' AND email='" .$email."')"; $sth = $this->dbh->prepare($sql); $sth->execute(); $result = $sth->fetch(); /* echo('<pre>'); print_r($result);*/ return ($result); } public function insert_data($user_info) { //$user_info = $user_in; //$dbh; try{ $dbh = new PDO("mysql:host=localhost;dbname=phpfaqproject",'root',''); //echo "connected"; } catch(PDOException $e){ echo $e-> getMessage(); } $dbh->exec("INSERT INTO account (username, userpassword, email, role, location, interest, homepage) VALUES ('" .$user_info['username']."','".$user_info['password'] ."','".$user_info['email']."', 'user','".$user_info['location']."','".$user_info['interests'] ."','".$user_info['homepage']."')"); } } ?> Please somebody help me. I am really stuck. I am also sending my attachment. can someone help me I am trying to call a class function using a varible.... example say i go to index.php?page=contact i want to pull that class with out doing a switch statement can someone help me Code: [Select] <?php $Site = page; $Site->getPage($_GET['page']); ?> Code: [Select] <?php class page extends site { function getPage($page) { return $this->$page; } function Contact() { echo '<h2>Contact test</h2>'; echo '<form> </form>'; } } ?> Hi How do I turn this: Code: [Select] if($LCname=='Business_solutions'){ $newChild = Business_solutions::find_by_id(1); } In to something like this: Code: [Select] $newChild = $LCname::find_by_id(1); I'm calling lots of class's, and want to make it more dynamic. The 2nd example would be perfect, but that does not work. Is there an alternative? Thanks Does anyone know if it's possible to call a class with an arbitrary number of variables? I'll explain what I mean. Here is my class construct definition: Code: [Select] function __construct($file, $outFile = 'newpdf.pdf', $fontSize = 70, $alpha=0.6, $overlayMsg = 'N O T F O R S H O P', $degrees = 45) { I know that I have to pass over the $file variable for it to work now. But can I create the class passing just the $file var and the $overlayMsg var? Everything else I would want to leave as default. How would I do that? Thanks Mike I am calling my class constructor with the following code class controller{ function _construct($name,$pass){ session_start(); get_model_class($name, $pass); echo "I\'m in controller"; } } function get_model_class($username, $password){ $my_model = new model(); $my_model->check_users($username,$password); } $username = $_POST['username']; $password = $_POST['password']; echo "in controller.php"; $newUser = new controller($username,$password); but it is not entering the constructor Dear all , i am trying the following : i have a class named ACCOUNT with many properties in .some of these properties are array , it is like this : Code: [Select] class ACCOUNT { PRIVATE $DB_LINK; PRIVATE $COMP; PRIVATE $BRANCH; PRIVATE $CURRENCY; PRIVATE $GL; PRIVATE $CIF; PRIVATE $SL; PRIVATE $EXIST; PRIVATE $STATUS; private $ACCOUNT_NAME=ARRAY("LA"=>'',"LE"=>'',"SA"=>'',"SE"=>''); private $ACCOUNT_BALANCE =ARRAY('FC_YTD','CV_YTD','CV_BAL','YTD_BAL','BLOCKED_CV','BLOCKED_FC'); private $CY_NAME=ARRAY("LA"=>'',"LE"=>'',"SA"=>'',"SE"=>''); private $ACCOUNT_NAME_USR=ARRAY("LA"=>'',"LE"=>'',"SA"=>'',"SE"=>''); private $LEDGER_NAME= ARRAY("LA"=>'',"LE"=>''); i have created the following method to call any property [code] FUNCTION GET_SPECIFEC_ATT($ATT,$LANG) { $ATT=$ATT."['L$LANG']"; ECHO $this->$ATT; } but i am getting the below error : Notice: Undefined property: ACCOUNT::$BRANCH_NAME['LA'] in D:\wamp\www\EBANK\account.class on line 186 if i used this : Code: [Select] echo $this->BRANCH_NAME['LA']; it is working fine . and the method is working fine i can iam trying to call property which is NOT an array. Can you please help me in what iam doing wrong ? Thanks in advance Hi all, I have two classes. Registration and Connection. Inside a registration.php I include my header.php, which then includes my connection.php... So all the classes should be declared when the page is loaded. This is my code: registration.php: <?php include ('assets/header.php'); ?> <?php class registration{ public $fields = array("username", "email", "password"); public $data = array(); public $table = "users"; public $dateTime = ""; public $datePos = 0; public $dateEntryName = "date"; function timeStamp(){ return($this->dateTime = date("Y-m-d H:i:s")); } function insertRow($data, $table){ foreach($this->fields as $key => $value){ mysql_query("INSERT INTO graphs ($this->fields) VALUES ('$data[$key]')"); } mysql_close($connection->connect); } function validateFields(){ $connection = new connection(); $connection->connect(); foreach($this->fields as $key => $value){ array_push($this->data, $_POST[$this->fields[$key]]); } $this->dateTime = $this->timeStamp(); array_unshift($this->data, $this->dateTime); array_unshift($this->fields, $this->dateEntryName); foreach($this->data as $value){ echo "$value"; } $this->insertRow($this->data, $this->table); } } $registration = new registration(); $registration->validateFields(); ?> <?php include ('assets/footer.php'); ?> At this point I cannot find my connection class defined on another included/included page. $connection = new connection(); $connection->connect; config.php (included within header.php) <? class connection{ public $dbname = '**'; public $dbHost = '**'; public $dbUser = '**'; public $dbPass = '**'; public $connect; function connect(){ $this->connect = mysql_connect($this->dbHost, $this->dbUser, $this->dbPass) or die ('Error connecting to mysql'); mysql_select_db($this->dbname, $this->connect); } } ?> Any ideas how to call it properly? I have a class in which I have a function called connection. I am now trying to call this function from another class, but it will not work. It works if I put the code in from the other function rather than calling it but that defeats the purpous. class locationbox { function location() { $databaseconnect = new databaseconnect(); $databaseconnect -> connection();{ $result = mysql_query("SELECT * FROM locations"); while($row = mysql_fetch_array($result)) // line that now gets the error, mysql_fetch_array() expects parameter 1 to be resource, boolean given //in { echo "<option>" . $row['location'] . "</option>"; } } }} This is a bit of a more advanced question so I am hoping there are some advanced programmers online at this time . Anyways basically I want to be able to "queue" functions from a class in a single call and am wondering if I am doing it correctly or if there is a better way to do it. Here is my code: <?php class test { private static $one; private static $two; private static $three; public function callOne($val){ $one .= $val; return $this; } public function callTwo($val){ $two .= $val; return $this; } public function callThree($val){ $three .= $val; return $this; } public function print(){ echo $this->one.' '.$this->two.' '.$this->three; } } ?> now when I want to call this I can do: $test = new test(); $test->callOne('one')->callTwo('two')->callThree('three'); $test->callOne('another one'); $test->print(); Is there a better way to do this or is there a different method of doing this? Just wanna make sure I am doing it right lol. Hello,
I am having some troubles and was hoping someone could guide me through it.
Q: When ever I try call my get_status function all I get is a white page of nothing, no errors to work from etc... Can anyone here see what I am doing wrong?
PATH: index.php
NOTICE //<<-- KILLS PAGE
<?php
spl_autoload_register(function ($class) {
include '/lib/' . $class . '.inc';
});
$servers = new servers;
echo $servers->get_servers();
echo "STATUS: ".$servers->get_status("0.0.0.0",80); //<<-- KILLS PAGE
?>
Page works fine until I want to use the status function, I get no errors or anything just a blank page.
PATH: Lib/Servers.inc
NOTICE //<<-- KILLS PAGE
<?php
ini_set('display_errors',1);
ini_set('display_startup_errors',1);
error_reporting(E_ALL);
error_reporting(-1);
include_once '../../Global-Includes/ServerStatus/db-connect.php';
//namespace xStatus;
class servers {
private $db_Hostname = HOSTNAME;
private $db_Username = USERNAME;
private $db_Password = PASSWORD;
private $db_Database = DATABASE;
private $dbSQL = '';
function __construct() {
} // End Construct
public function get_servers(){
$db = new mysqli($this->db_Hostname,$this->db_Username,$this->db_Password,$this->db_Database);
$message = '';
// list current servers from database
$sql = "SELECT * FROM tbl_servers";
$res = $db->query($sql);
if ($res->num_rows > 0) {
$message = '<h3>Current Servers</h3>';
while ($row = $res->fetch_assoc()) {
$message .= $row['HostGame'] . '<br>';
$message .= $row['HostIP'] . '<br>';
$message .= $row['HostPort'] . '<br>';
$message .= $this->get_status($row['HostIP'],$row['HostPort']) . '<br>'; //<<-- KILLS PAGE!
}
}
$message .= "<br>End of the \"Server List\" ";
return $message;
}
public function get_status(&$ServerIP,&$ServerPort){
if(@stream_socket_client("tcp://".$this.$ServerIP.":".$this.$ServerPort."", $errno, $errstr, 1) !== false) {
return "Online";
} else {
return "Offline";
}
return "Offline";
}
} // End class
?>
Kind regards and thank you.
How can I make a link that posts to a script? I using just a link but since it doesn't post I just get a URL with a variable and I can't do anything with it. If you need anything else then just ask Hi, I wrote this to retrieve a file based on a POST value. For some reason it will not retrieve the file content and display it at all. I get this message: Warning: fopen(18.txt) [function.fopen]: failed to open stream: No such file or directory in /home/content/x/y/z/path/html/includes/different.php The 18 is the correct POST value. So that is a positive There is a file named 18.txt in /home/content/x/y/z/path/html/includes/18.txt Thanks. <?php $id5 = $_POST[id]; //Display Text File $myFile = $id5; $myFile .= ".txt"; $fh = fopen($myFile, 'r'); $theData = fgets($fh); fclose($fh); echo $theData; ?> I need to call usort from a class function, and I'm puzzled about how to define the comparison function. I've tried to define the comparison function in the same class, but I can't get usort to call it. I found one hint that it will work if I make the comparison function static, but I tried that, and it didn't work for me. If I define the comparison function outside the class, it won't have access to object properties that it needs to operate. The only solution I can think of is to define the comparison function outside the class and put the object properties it needs in globals. Is there a cleaner way to do this?
My script has 3 classes (that are relevant to this discussion): DB, User and Validate. They are all in independent files and loaded automatically, when required, by an autoloader.
The error messages I am getting a Any pointers as to what I am doing wrong, or what I should be doing, would be most welcome. |
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