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PHP - Mysqli_result To Array
Hey Guys,
So I have a zip code database with 40,000 some entries... and I am reading a query and returning it and need it to store it in array similar to this snippet of code . $cities = array( array('city'=>'New York', 'state'=>'NY', 'zip'=>'10001'), array('city'=>'Los Angeles', 'state'=>'CA', 'zip'=>'90001'), array('city'=>'Chicago', 'state'=>'IL', 'zip'=>'60601'), array('city'=>'Houston', 'state'=>'TX', 'zip'=>'77001'), array('city'=>'Phoenix', 'state'=>'AZ', 'zip'=>'85001'), array('city'=>'Philadelphia', 'state'=>'PA', 'zip'=>'19019'), array('city'=>'San Antonio', 'state'=>'TX', 'zip'=>'78201'), array('city'=>'Dallas', 'state'=>'TX', 'zip'=>'75201'), array('city'=>'San Diego', 'state'=>'CA', 'zip'=>'92101'), array('city'=>'San Jose', 'state'=>'CA', 'zip'=>'95101'), array('city'=>'Detroit', 'state'=>'MI', 'zip'=>'48201'), array('city'=>'San Francisco', 'state'=>'CA', 'zip'=>'94101'), array('city'=>'Jacksonville', 'state'=>'FL', 'zip'=>'32099'), array('city'=>'Indianapolis', 'state'=>'IN', 'zip'=>'46201'), array('city'=>'Austin', 'state'=>'TX', 'zip'=>'73301'), array('city'=>'Columbus', 'state'=>'OH', 'zip'=>'43085'), array('city'=>'Fort Worth', 'state'=>'TX', 'zip'=>'76101'), array('city'=>'Charlotte', 'state'=>'NC', 'zip'=>'28201'), array('city'=>'Memphis', 'state'=>'TN', 'zip'=>'37501'), array('city'=>'Baltimore', 'state'=>'MD', 'zip'=>'21201'), ); Here is the code I currently have... But it is not being stored into an array, it is just a mysqli_result object with the correct amount of num_rows, and fields. $cities = $zip->getAllZipCityState(); function getAllZipCityState() { // Get ALL Zip / City / State $query = 'SELECT ' . $this->dbZip . ', ' . $this->dbCity . ', ' . $this->dbState . ' '; $query.= 'FROM ' . $this->dbTable . ' '; //$qry = mysql_query($query,$this->db); $qry = $this->db->query($query); if(!$qry){ echo "MySql Error #".mysqli_errno($this->db).': '.mysqli_error($this->db).'<br>'; die; } //return mysqli_fetch_array($qry); return $qry; } Thanks! Similar TutorialsHello, I have a serious problem that I need to fix for a client and I have no idea how to fix it. I have a client that is running vBulletin 4.2.2 P1 and since a server upgrade we have gotten this error when they to access a hack that we have installed called Easy Forms. I would not ask here except there is little to no help on vbulletin.org. The coder who created this hack is in the wind and has not been on the site since October 4, has a full PM box and is not answering messages and others on the site are trying to help but I'm not a php coder so i have no idea where to start to fix it even with their help. Here is the error we get:
Fatal error: Cannot use object of type mysqli_result as array in /home/public_html/forum/forms.php on line 1242
The form.php is the file that pertains to the hack we have installed. This hack was isntalled BEFORE the host went and screwed around with stuff and it worked fine before hand.
The code around that line and including that line is:
$formbits = $vbulletin->db->query_read("SELECT * FROM " . TABLE_PREFIX . "formbits WHERE fid = $fid ORDER BY displayorder ASC");
while($formbit = $vbulletin->db->fetch_array($formbits))
{
($hook = vBulletinHook::fetch_hook('easy_forms_view_question_start')) ? eval($hook) : false;
if ($formbit[guestonly] && $vbulletin->userinfo[userid])
{
continue;
}
$formbit['value'] = $q[$formbit[id]];
$bbcode_parser = new vB_BbCodeParser($vbulletin, fetch_tag_list());
$formbit[question] = $bbcode_parser->parse($formbit[question]);
$bbcode_parser = new vB_BbCodeParser($vbulletin, fetch_tag_list());
$formbit[description] = $bbcode_parser->parse($formbit[description]);
$formbit['qlc'] = trim($formbit['question']);
$formbit['qlc'] = substr($formbit['qlc'], -1);
if ($formbit['qlc'] != "?" && $formbit['qlc'] != ":" && $formbit['type'] != 7)
{
$formbit['question'] = $formbit['question'] . ":";
}
if ($formbit['compulsory'] == 1)
{
$formbit['question'] = $formbit['question'] . $vbphrase[form_compulsory_symbol];
}
$question++;
$formbit[inputerror] = $inputerror[$formbit[id]];
if ($formbit['type'] == 1)
{
Line 1242 is $formbit['value'] = $q[$formbit[id]];. If you need more code than that please let me know. I think it has to do with the questions being added. I have uninstalled this hack and reinstalled it as a fresh install twice and still get the same errors. When I reinstalled the second time instead of importing the client's backed up form I created a fresh test one and when I clicked on "View Form" before adding any questions to the form it worked just fine. But after I added questions I click on the "View Form" link and get that error again, so it is somehow related to the questions.
Some info about what we are running on the site:
vBulletin 4.2.2 P1 Suite
PHP 5.4.33
MySQL 5.5.37
i have been informed that the code would now need arrays but that is about all they have said which is great help if I were a programmer. I'm able to edit the code (With direction) with no problem, but I do not hand code it or know where everything should or should not be. Any help would be great on this matter. Thanks.
Edited by LenKaiser, 24 October 2014 - 07:39 PM. Hi all
i am using the code below, but am getting the error
Object of class mysqli_result could not be converted to int
<?php
$sql="SELECT lng,lng_prefix FROM tbl_languages where active = 1";
$result=mysqli_query($dbConn, $sql)or die(mysqli_error($dbConn)); //problem line
if(mysqli_num_rows($result==1)){
?>
The code continues with what I want to happen based on the result.
What does the error mean and how do I fix it?
Hi guys, I received an error, could anyone explain this current error? Thanks Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in D:\inetpub\vhosts\championtutor.com\httpdocs\questionnaire.php on line 32 Hi
I am a student who is fairly new to PHP and MySQL. I have been working on creating a registration page for a website and I'm getting the following warnings when I've tested the page:
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in /home/ed12e2w/public_html/COMM2735/dynamic_website/registration.php on line 74 Warning: mysqli_free_result() expects parameter 1 to be mysqli_result, boolean given in /home/ed12e2w/public_html/COMM2735/dynamic_website/registration.php on line 80 I think that my query has failed but I'm not completely sure on what to change in order to solve this. Here is the section of code I'm having problems with: Attached Files register.php 733bytes 4 downloads The following is an extract of PHP code I have interacting with a MySQL database and I keep getting the "object of class mysqli_result could not be converted to string" error on the line of code inside my loop. This is my code.
#This is just storing a single integer, a moduleID
$sqlmodID = mysqli_query($con,"select moduleID from module_details WHERE moduleName = '$moduleName' AND lecturerID = '$lecturerID'"); #This is a query to get relevant idNumbers $sqlstudent = "select idNum from user_info WHERE courseCode = '$courseCode'";
#Running the previous statement $result = mysqli_query($con, $sqlstudent);
#Storing the statements results in an array $row = mysqli_fetch_array($result);
#I'm not sure if this line is necessary but it converts the array values into a string (I'm storing the ID's as strings as they contain numbers and letters) $studentArray = array_map('strval', $row);
#The error flashes on my condition of this loop. I'm trying to take each element of my array, and enter it to my table, assigning each variable the same ModuleID.
for($i=0; $i < count($studentArray); $i++){
Any help would be much appreciated. I hope I've explained my code sufficiently. I have searched the internet about this and found hundreds have asked the question and not once was it answered in a meaningful way--or maybe I'm just dense. Would somebody please tell me what is the problem he Simple, simple form:
<html>
<form action="send_post.php" method="post">
</body> =========== Simple, simple PHP script:
<?php
if (mysqli_num_rows($result) > 0) { But most importantly, how should it be written so that it returns the desired results? I have checked the query from the CMD line, it returns multiple entries. Really, I have reached FRUSTRATION OVERLOAD! Edited April 12, 2020 by eljaydeeHi all, I have received a warning message, which it still puzzles me. I suspect it might be my inner join command, which I have coded it wrongly? Line 37 refers to this line - if (mysqli_num_rows($data) == 1) { Do you guys have any idea? Thanks Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in D:\inetpub\vhosts\123.com\http\viewprofile.php on line 37 Code: [Select] <?php // Connect to the database $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); $query = "SELECT tp.name, tp.nric, tp.gender, tp.race_id, r.race_name AS race" . "FROM tutor_profile AS tp " . "INNER JOIN race AS r USING (race_id) " . "WHERE tutor_id = '" . $_GET['tutor_id'] . "'"; $data = mysqli_query($dbc, $query); if (mysqli_num_rows($data) == 1) { // The user row was found so display the user data $row = mysqli_fetch_array($data); echo '<table>'; if (!empty($row['name'])) { echo '<tr><td class="label">Name:</td><td>' . $row['name'] . '</td></tr>'; } if (!empty($row['nric'])) { echo '<tr><td class="label">NRIC:</td><td>' . $row['nric'] . '</td></tr>'; } if (!empty($row['last_name'])) { echo '<tr><td class="label">Last name:</td><td>' . $row['last_name'] . '</td></tr>'; } if (!empty($row['gender'])) { echo '<tr><td class="label">Gender:</td><td>'; if ($row['gender'] == 'M') { echo 'Male'; } if ($row['gender'] == 'F') { echo 'Female'; } echo '</td></tr>'; } if (!empty($row['race'])) { echo '<tr><td class="label">Race:</td><td>' . $row['race'] . '</td></tr>'; } echo '</table>'; //End of Table echo '<p>Would you like to <a href="editprofile.php?tutor_id=' . $_GET['tutor_id'] . '">edit your } // End of check for a single row of user results else { echo '<p class="error">There was a problem accessing your profile.</p>'; } mysqli_close($dbc); ?> Someone help me in this problem please?? Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in line 8 $rec= mysqli_query ($db, "SELECT FROM joborder WHERE id=$id"); $record = mysqli_fetch_array ($rec); // line 8 $fnames= $record ['fnames'] ; Edited March 8 by kei
<!DOCTYPE html>
{ Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in /home/myritebook/public_html/footer.php on line 13 I am trying to fix the above error. Please Help. code is given below:
<?php
if ($conn) {
try{
catch(Exception $e){ Hi Guys.
Doing an assignment for uni, and stuck on an error. Ill attach some files to show the problem and any help very much appreciated.
Error and the screen it comes on
Code
<?php $select = mysqli_query($con, "SELECT * FROM categories");
while ($row = mysqli_fetch_assoc($select)) { }
function dispsubcategories($parent_id) {
}
function getnumtopics($cat_id, $subcat_id) {
and the structure of the database
Edited March 28, 2020 by Ben555 I have a table with a list of users and an edit button and delete button. When the edit button is pressed on a site it passes the user_id as p_id to the page that catches it and displays the data. The problem is when I click on the "update user" button, I get the following error:
Warning: Undefined variable $the_user_id in C:\xampp\htdocs\3-19-21(2) - SafetySite\admin\edit_user.php on line 10 The weird thing is I had another update user page with a table I created that ran the query to update the table in the database just fine. But as I created it, it didn't look all that great so I recreated the page and used a bootstrap table because of the much cleaner look. Both pages have the exact same PHP code, the only difference is the bootstrap table I added in. So I'm really at a loss with this. Other than the table and PHP code, there is a script at the bottom of the page for the table itself to allow for searching within the table, i'll include that as well. The PHP code is as follows:
<?php //THE "p_id" IS BROUGHT OVER FROM THE EDIT BUTTON ON VIEW_ALL_USERS if (isset($_GET['p_id'])) { $the_user_id = $_GET['p_id']; } // QUERY TO PULL THE SITE INFORMATION FROM THE p_id THAT WAS PULLED OVER $query = "SELECT * FROM users WHERE user_id = $the_user_id "; $select_user = mysqli_query($connection,$query); //SET VALUES FROM ARRAY TO VARIABLES while($row = mysqli_fetch_assoc($select_user)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_email = $row['user_email']; $user_phone = $row['user_phone']; //$user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id']; } THE UPDATE QUERY CODE....................................................................................................................
<?php if(isset($_POST['update_user'])) { $user_id = $_POST['user_id']; $user_firstname = $_POST['user_firstname']; $user_lastname = $_POST['user_lastname']; $username = $_POST['username']; $user_email = $_POST['user_email']; $user_phone = $_POST['user_phone']; //$user_image = $_POST['user_image']; $user_title_id = $_POST['user_title_id']; $user_role_id = $_POST['user_role_id'];
$query = "UPDATE users SET "; $query .= "user_id = '{$user_id}', "; $query .= "user_firstname = '{$user_firstname}', "; $query .= "user_lastname = '{$user_lastname}', "; $query .= "username = '{$username}', "; $query .= "user_email = '{$user_email}', "; $query .= "user_phone = '{$user_phone}', "; //$query .= "user_image = '{$user_image}', "; $query .= "user_title_id = '{$user_title_id}', "; $query .= "user_role_id = '{$user_role_id}' "; $query .= "WHERE user_id = '{$the_user_id}' "; $update_user = mysqli_query($connection,$query); if(! $update_user) { die("QUERY FAILED" . mysqli_error($connection)); } } ?> THE "UPDATE USER" BUTTON THE USER CLICKS ON TO UPDATE....................................................................................................................
<div class="col-1"> <button class="btn btn-primary" type="submit" name="update_user">Update User</button> </div>
Any Help is Greatly Appreciated! Edited March 23 by ZsereneNOTE - Please read the information first as it contains important information to understand the problem. Rules → • There are 9 Columns(C1,C2,C3,C4,C5,C6,C7,C8,C9) [ Max columns will be 9] • The number of Rows can vary from 3,6,9,12,15,18 (Max). In this case Number of Rows shall be 12 Number of Rows = No of Tickets (Max Allowed 6) x Rows Per Ticket (Max Allowed 3). Thus, Max Rows can be 18 • Each Row is required to have 4 Blank Spaces and 5 Filled with Numbers • All numbers available in the Column Array have to be utilized • This configuration of an shall create a matrix of 9 Columns & 12 Rows (3 x 4 Tickets), which is 108 MATRIX BLOCKS where only a maximum of 60 numbers can be filled out of 108 available blocksrandomly with the above conditions being met 100%. • The numbers in column must be arranged / sorted in ASCENDING ORDER (For coding logic purpose, as soon as the number is assigned to the new MATRIX MAP use array_shift() or unset() the number so as to avoid repetition Example - Row 1 and Column 1 shall generate a MATRIX BLOCK - R1C1 Row 3 and Column 7 shall generate a MATRIX BLOCK - R3C7 Matrix Block can also be termed as Matrix Cell for your ease (if needed) MASTER SET OF ARRAY WITH NUMBERS array( "C1"=> array( 1, 2, 3, 5, 6, 7, 9 ), //7 Numbers "C2"=> array( 13, 14, 15, 17, 18, 19 ), //6 Numbers "C3"=> array( 21, 22, 23, 24, 25, 26, 30 ), //7 Numbers "C4"=> array( 31, 33, 34, 36, 37, 38, 39 ), //7 Numbers "C5"=> array( 41, 42, 46, 47, 48, 49, 50 ), //7 Numbers "C6"=> array( 51, 52, 53, 54, 55, 57, 58 ), //7 Numbers "C7"=> array( 61, 62, 64, 65, 69, 70 ), //6 Numbers "C8"=> array( 71, 74, 75, 76, 77, 78 ), //6 Numbers "C9"=> array( 82, 83, 85, 87, 88, 89, 90 ) //7 Numbers ); The above array has 60 Numbers to be filled out of 108 MATRIX BLOCK / CELL which meets the condition that for a FULL BLOCK containing 4 MINI BLOCKS WITH 3 ROWS (max. allowed) EACH I have been able to generate this without any issue meeting all the conditions of the Columns My Allocation Matrix Array will look like array( "R1"=> array( "C1"=> true, // Means that MATRIX BLOCK R1C1 will be NOT EMPTY "C2"=> false, // Means that MATRIX BLOCK R1C2 will be EMPTY "C3"=> true, "C4"=> false, "C5"=> true, "C6"=> false, "C7"=> true, "C8"=> true, "C9"=> false ), "R2"=> array( "C1"=> false, "C2"=> true, "C3"=> false, "C4"=> true, "C5"=> false, "C6"=> true, "C7"=> true, "C8"=> true, "C9"=> false ), "R3"=> array( "C1"=> true, "C2"=> true, "C3"=> true, "C4"=> true, "C5"=> false, "C6"=> false, "C7"=> false, "C8"=> false, "C9"=> true ), "R4"=> array( "C1"=> true, "C2"=> true, "C3"=> true, "C4"=> false, "C5"=> true, "C6"=> true, "C7"=> false, "C8"=> false, "C9"=> false ), "R5"=> array( "C1"=> false, "C2"=> false, "C3"=> false, "C4"=> false, "C5"=> true, "C6"=> true, "C7"=> true, "C8"=> true, "C9"=> true ), "R6"=> array( "C1"=> true, "C2"=> true, "C3"=> false, "C4"=> true, "C5"=> false, "C6"=> true, "C7"=> false, "C8"=> false, "C9"=> true ), "R7"=> array( "C1"=> false, "C2"=> false, "C3"=> true, "C4"=> false, "C5"=> true, "C6"=> false, "C7"=> true, "C8"=> true, "C9"=> true ), "R8"=> array( "C1"=> true, "C2"=> false, "C3"=> false, "C4"=> true, "C5"=> false, "C6"=> false, "C7"=> true, "C8"=> true, "C9"=> true ), "R9"=> array( "C1"=> true, "C2"=> false, "C3"=> true, "C4"=> false, "C5"=> true, "C6"=> true, "C7"=> false, "C8"=> false, "C9"=> true ), "R10"=> array( "C1"=> false, "C2"=> true, "C3"=> true, "C4"=> true, "C5"=> true, "C6"=> false, "C7"=> true, "C8"=> false, "C9"=> false ), "R11"=> array( "C1"=> false, "C2"=> true, "C3"=> false, "C4"=> true, "C5"=> true, "C6"=> true, "C7"=> false, "C8"=> true, "C9"=> false ), "R12"=> array( "C1"=> true, "C2"=> false, "C3"=> true, "C4"=> true, "C5"=> false, "C6"=> true, "C7"=> false, "C8"=> false, "C9"=> true ) ); In the above array R stands for Row, C for Column, TRUE/FALSE (Boolean) means that if TRUE a Number can be filled in the resulting MATRIX BLOCK / CELL ( Row[Number]Column[Number] ) else if FALSE the MATRIX BLOCK / CELL shall be EMPTY The result for the above shall be
PROBLEM : I am unable to understand what should possibly be the logic & loop used here for creating a MATRIX ALLOCATION MAP as shown above I have tried while, foreach & for but unable determine the perfect combination which would meet the conditions. (Tried all of the above with Nested Loops also) Edited May 1, 2020 by AlphaMikeTags hi i am trying to make a payroll calculator script that takes employee info, calculates pay, displays submitted info in a table, stores info in an array, and updates the array when new info is submitted. i have most of these accomplished, i am having trouble with the "store into an array, and update the array when new info is submitted" parts of the project. i am still not very fluent in php so there may be easier ways to achieve what i have so far. any pointers would be a great help, this part has got me stumped. I am having some problems getting a query correct. Basically I have two tables, one with listings and another with categories. In the listings table I have a column called shortdescription. I am trying to pull the shortdescription from the listings table with the query $shortdesc = array_shift(mysql_fetch_row(mysql_query("select shortdescription from links where category = '".$scat->id."' "))); The shortdecription display properly on the pages display the listings, however I am getting the following error on any pages that only display the parent categories Warning: array_shift() [function.array-shift]: The argument should be an array in /home/...path/file.php on line 1462 The listings id numbers begin at 75+ because the initial parent category id ends at 74. The query seems to be searching for listing ids below 75 and spitting out an error because it is not finding them. Any ideas on how to eliminate this error and/or stop the query from looking for non-existant data? Using curl_multi, I have loaded up 3 url's and then printed the array. 1) How can I also set a timestamp on output to let me know when each url was run? 2) How can I explode the array to only display the data and timestamp, excluding the text "Array ( =>", "[1] =>", "[2] =>" and " )"? Code <?php function multiRequest($data, $options = array()) { // array of curl handles $curly = array(); // data to be returned $result = array(); // multi handle $mh = curl_multi_init(); // loop through $data and create curl handles // then add them to the multi-handle foreach ($data as $id => $d) { $curly[$id] = curl_init(); $url = (is_array($d) && !empty($d['url'])) ? $d['url'] : $d; curl_setopt($curly[$id], CURLOPT_URL, $url); curl_setopt($curly[$id], CURLOPT_HEADER, 0); curl_setopt($curly[$id], CURLOPT_RETURNTRANSFER, 1); // post? if (is_array($d)) { if (!empty($d['post'])) { curl_setopt($curly[$id], CURLOPT_POST, 1); curl_setopt($curly[$id], CURLOPT_POSTFIELDS, $d['post']); } } // extra options? if (!empty($options)) { curl_setopt_array($curly[$id], $options); } curl_multi_add_handle($mh, $curly[$id]); } // execute the handles $running = null; do { curl_multi_exec($mh, $running); } while($running > 0); // get content and remove handles foreach($curly as $id => $c) { $result[$id] = curl_multi_getcontent($c); curl_multi_remove_handle($mh, $c); } // all done curl_multi_close($mh); return $result; } $data = array(array(),array()); $data[0]['url'] = 'http://search.yahooapis.com/VideoSearchService/V1/videoSearch?appid=YahooDemo&query=Pearl+Jam&output=json'; $data[1]['url'] = 'http://search.yahooapis.com/VideoSearchService/V1/videoSearch?appid=YahooDemo&query=Black+Eyed+Peas&output=json'; $data[2]['url'] = 'http://search.yahooapis.com/VideoSearchService/V1/videoSearch?appid=YahooDemo&query=Nirvana&output=json'; $r = multiRequest($data); print_r($r); ?> Output Array ( => Pearl Jam [1] => Black Eyed Peas [2] => Nirvana ) Preferred Output 01:00:01 Pearl Jam 01:00:02 Black Eyed Peas 01:00:03 Nirvana How can i save array from inputs, witch is $igraci and it have 5 values, to mysql base, i tryed but in mysql it shows Array. This is form: <form action="dodaj_klan.php" method="post" > <p> <label>Naziv klana:</label> <input name="naziv" type="text" size="20%" /> <label>Web Sajt:</label> <input name="website" type="text" size="20%" /> <label>E-Mail:</label> <input name="email" type="text" size="20%" /> <br /><br /> <label>Igraci klana(5):</label> <input name="lider" type="radio" value="1" /> <input name="igraci[]" type="text" size="20%" /><br /> <input name="lider" type="radio" value="2" /> <input name="igraci[]" type="text" size="20%" /><br /> <input name="lider" type="radio" value="3" /> <input name="igraci[]" type="text" size="20%" /><br /> <input name="lider" type="radio" value="4" /> <input name="igraci[]" type="text" size="20%" /><br /> <input name="lider" type="radio" value="5" /> <input name="igraci[]" type="text" size="20%" /> <label><i>(obelezi lidera klana)</i></label> <br /><br /> <input class="button" type="submit" name="submit" value="Dodaj" /> </p> </form> Now i wonna save this igraci[] array in mysql, i tried like this but it doesn't work: $igraci = $_POST['igraci']; $query = "INSERT INTO klanovi (naziv, website, email, igraci) VALUES ('{$naziv}', '{$website}', '{$email}', '{$igraci}')"; $result = mysql_query($query, $connection); How can i do this? Thanks.. This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=344127.0 Hi there, Basic question, but I can't seem to find a page in the PHP docs that answers (though I'm sure such a one exists, I just can't seem to think up the right search terms - anyway) My question is: is there a short-hand way to use a value from an associative array as the key in another associative array? So for example, given this array: $the_array = array(0 => array('name': 'the_name', 'value' : 'the_value'), 1 => etc....); then this kind of foreach loop doesn't work Code: [Select] $new_data = array(); foreach($the_array as $element){ $new_data[$element['name']] = $element['value']; } Obviously I can just save out the values, like $name = $element['name'] --- but I was just wondering if there was a more efficient way to do it? Cheers, PS. I tried encapsulating with {} - i.e. $new_data[{$element['name']}] --- but that also fails. |
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