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PHP - Template (.tpl) Unable To View?
my firefox won't open up .tpl format im running apache...how can i view that format on my apache please?
Similar TutorialsHi there,
I'm new to all this so I've been following instructions from various sites and books. So far I have installed Apache, PHP and mysql, however when I browse to localhost/test.php (created to view phpinfo() through the browser) i can't see mysql or mysqli only the mysqlnd.
Here is an overview of software I've installed, OS and things I've added so far;
OS ver Windows7 Professional 32-bit VM Hello, I need some help modifying some code. I would like to change the layout to show more then currently offered. As of now I have a layout that shows either 3 or 10 images. I tried to change the numbers, but no luck and I can not seem to be able to change to view more. Any help would be great! Code: [Select] // image list $mysqlDataImage = mysql_query( "SELECT * FROM $DB_IMAGE where collectionID=$cat $where ORDER BY $order_by" ); $dataLength = mysql_num_rows( $mysqlDataImage ); $totalImages = $dataLength; //$cat_scrollview = 3; //FORCE SCROLLER if($scrollview == "smaller"){ $cat_scrollview = 0; } //User Override //SWITCH SCROLL LAYOUT BASED ON VIEW : HANDLES COLUMNS, ROWS, PAGES AND SHOW ALL if (($cat_scrollview == 3)||($scrollview == "bigger")){ $PAGE_SIZE = 3; //how many pics per page, all set in html $rowDefault = 1; //row default-changes the most $colDefault = $totalImages/ 1; //columns default use to breakup columns //echo "cols=".$colDefault; //echo "totalimage=".$totalImages; //See getNumberOfRows() $totalPages = $totalImages/$PAGE_SIZE; $cat_scrollview = 3; $scrollview = "bigger"; }else{ $PAGE_SIZE = 10; //how many pics per page, all set in html $rowDefault = 2; //row default-changes the most $colDefault = $totalImages/ 2; //columns default use to breakup columns //echo "cols=".$colDefault; //echo "totalimage=".$totalImages; //See getNumberOfRows() $totalPages = $totalImages/$PAGE_SIZE; $cat_scrollview = 0; $scrollview = "smaller"; } I am new to PHP so please be kind (and explain slowly) Thank you! hello, is there a simple way to have a full size calendar that shows current month and on each day, it will look into my mysql table and if i have an entry on that day, show the sales field. i have spent days googling, and trying my own and i just cant get anything. if i had a calendar script, i could do the rest, but i cant seem to find it, or make it. Dera All, SAMPLE TABLE FIELDS AND DATAS: USER PASSWORD ACCNO AMOUNT INTEREST JOE JOE@123 1234 4500.00 250.00 SAM SAM123 5678 12050.00 350.00 RAM RAM987 8521 15698.00 568.00 MARY MARY786 7542 14879.00 567.00 RAJ RAJ876 8531 45622.00 1500.00 FIRST PAGE: USER NAME : RAM PASSWORD : ******** SUBMIT SECOND PAGE: ACCOUNT NO 8521 THIRD PAGE: HI WELCOME RAM UR BALACE AND INTEREST IS BALANCE : 15698.00 INTEREST : 568.00 HI AM NEW TO PHP. I need the code for above page. If the user only authenticate to view his accounts. Others not possible to view the other accounts Please help! how can i query data from different tables? I've tried so many codes already but it won't work.
Attached Files
Untitled1.png 39.93KB
0 downloads I'm very new to MVC and I'm trying to figure out how to transition my code and I'm not sure where to place things. It easy to want to just put everything in the view, but I know that doesn't make sense. Can you please guide me on how I should transition the rest of my code for my header? I'm currently using codeigniter. Current View Code: [Select] <?php $page = substr(end(explode(DIRECTORY_SEPARATOR, $_SERVER['PHP_SELF'])), 0, -4); $title = (array_key_exists($page, $page_names) !== false) ? $page_names[$page]: ''; if (array_key_exists($page, $page_names) !== false) { $title .= " | Jason Biondo"; } $banner_imgs = array('contact.jpg', 'about.jpg', 'tools.jpg', 'portfolio.jpg', 'articles.jpg'); $nav_names = array('Contact', 'About', 'Tools', 'Portfolio', 'Articles'); $gutter_values = array('307', '230', '161', '84', '0'); $alt_page = 'Articles'; foreach($nav_names as $k => $name) { if($page === strtolower($name)) { $g_value = $gutter_values[$k]; } } if(!isset($g_value)) { $g_value = 0; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" lang="en" dir="ltr"> <head> <meta http-equiv="content-type" content="text/html;charset=utf-8" /> <meta http-equiv="content-script-type" content="text/javascript" /> <meta http-equiv="content-style-type" content="text/css" /> <meta http-equiv="content-language" content="en" /> <meta name="description" content="Jason is a serial entrepreneur that builds web applications using advanced programming technologies and unique interface design." /> <meta name="keywords" content="jason , entrepreneur, investors, venture capitalist, angel investor, vc, ventures, private equity, startups, startup community, startup investments, investment network, raise capital, where to find capital, fund raising, venture financing, contact investors, angel fund, angel group, investment strategy, business plan" /> <title><?=$title?></title> <link rel="shortcut icon" type="image/x-icon" href="/assets/img/favicon.ico" /> <link rel="stylesheet" type="text/css" media="screen" href="/css/style.css" /> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.1/jquery.min.js"></script> <script src="./js/jquery.validate.min.js"></script> <script src="./js/jquery.corner.js"></script> <script src="./js/init.js"></script> <?php if (file_exists("./assets/js/pages/${page}.js")) { echo "<script type=\"text/javascript\" src=\"./js/pages/${page}.js\"></script>"; } ?> </head> <body> <div class="header"> <div class="header_container"> <a href="/"> <img class="logo" src="/assets/img/logo.png" alt="Jason" title="Jason" /> </a> <div class="navigation f_right"> <div class="gutter"> <span id="nav_highlight" class="nav_highlight" style="left: <?php echo $g_value; ?>px;"></span> </div> <ul> <?php foreach($nav_names as $k => $name) { if(is_odd($k)) { ?> <li class="pike"></li> <?php } ?> <li> <a id="<?php echo strtolower($name); ?>" <?php echo (($page === strtolower($name)) || ($alt_page === $name)) ? 'class="selected"' : ''; ?> href="/<?php echo ($name === $alt_page) ? '' : strtolower($name); ?>"><?php echo $name; ?></a> </li> <?php if(is_odd($k)) { ?> <li class="pike"></li> <?php } } ?> </ul> </div> </div> </div> <div class="stripe"></div> <div id="content_container" class="content_container"> <div id="banner" class="banner"> <?php foreach($nav_names as $k => $name) { if(($page === strtolower($name)) || ($alt_page === $name)) { ?> <img src="/assets/img/banners/<?php echo $banner_imgs[$k]; ?>" /> <h1><?php echo $name; ?></h1> <?php break; } if($alt_page === $name) { ?> <img src="/assets/img/banners/<?php echo $banner_imgs[$k]; ?>" /> <h1><?php echo $name; ?></h1> <?php } } ?> </div> <div class="banner_stripe"></div> <div class="content"> Current Controller Code: [Select] <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class Writing extends CI_Controller { public function index() { $this->load->library('common'); $data['page_names'] = $this->common->page_names(); $data['is_odd'] = $this->common->is_odd(); $this->load->view('includes/header', $data); $this->load->view('writing_view'); $this->load->view('includes/footer'); $this->output->enable_profiler(TRUE); } } Hi. idea: View image from /skins/ folder. The id for the image is taken from mysql DB field called PlayerDefaultSkin So, lets say a user has 240 in the field in database and in /skins/ folder I have image called 240.png What I want is to php read from PlayerDefaultSkin field and view the image from /skins/ Right now I have this: query to update: Code: [Select] `PlayerDefaultSkin` = $data[PlayerDefaultSkin]' and the output code Code: [Select] <img src="skins/<?php echo '$PlayerDefaultSkin' ?>.png"> which simply doesnt work and is probably very wrong. So can anyone help me with this? Hi, I have tried a "Hello.php" to open in my web browser. It throws 404 file not found error. I am using Intranet. How to determine the web server I am using? Thanks. Code: [Select] <?php function checking_out() { $conn = db_connect(); $nickname=$_SESSION['valid_user']; $query="select sum(price) from preorders where name='".$nickname."'"; $result = $conn->query($query); if ($result) { echo '<h1>'.$result.'</h1>'; } } ?> This is not working, there is no result in the browser, any idea ? Hello, I've never really used the update command before for mysql and I'm attempting to use it and struggling a little bit. I'm trying to use mysqli prepared statements.. here's the code that I have thus far: if($query = $database->connection->prepare("UPDATE videos SET comments=?, views=?, uploader=? WHERE title = ?")) { $query->bind_param('iiss', $comments, $views, $uploader, $title); $query->execute(); $result = $query->affected_rows; $query->close(); } For some reason I cannot get this working. I have created a modification page for the administrators to be able change any of the values and wanting to update the database to reflect the changes. When using the MySQL UPDATE command do all of the values have to get changed or modified, or am I able to pass back some of the same values? Like with the above code.. if I only wanted to update the views, would I still be able to just pass in the same values for comments and uploader and it would just replace the values? Hi all,
I am not sure why my header is not displaying the header image after using the CSS
I have a png file that repeats horizotally.
Please help
<!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title>Wikigets The online store</title> <style type="text/css"> body { margin:0 px;} #pageTop { background: url(style/headerline1.png); height:110 px; } </style> </head> <body> <div id="pageTop"> </div> <div id="pageMiddle"></div> <div id="pageBottom"></div> </body> </html> headerline1.png 2.82KB 0 downloads headerline1.png 2.82KB 0 downloads I get the unable to jump to row zero mysql error. Code: [Select] function is_admin($uid, $cid) { $uid = (int)$uid; $cid = (int)$cid; $sql = "SELECT `users`.`id` AS `uid`, `companies`.`companyid` AS `cid`, `companies`.`adminid` AS `aid` FROM `companies` LEFT JOIN `users` ON `users`.`id` = companies.adminid WHERE `users`.`id` = {$uid} AND `companies`.`companyid` = {$cid}"; $user = mysql_query($sql); return (mysql_result($user, 0) == '1') ? true : false; } by any means is there a way to view a email.php form source? not just the html part but the entire script including the php? Hi coders,
code below are running good, but my problem is i did not get the line echo $row->pof_num + 1; into view "generate_po.php".
since i want that line to get the value and put into input text like below. how and kindly assist.
<input type = "text" name = "num" value = "<?php echo $row->pof_num + 1; ?>">
public function generate_po()
{
$po_id = $this->input->post('selector');
$data['result'] = $this->public_base_model->generate_po($po_id);
if($this->session->userdata('logged_in'))
{
$session_data = $this->session->userdata('logged_in');
$data['username'] = $session_data['username'];
$data['fname'] = $session_data['fname'];
$data['userid'] = $session_data['userid'];
$this->load->view('generate_po', $data,$this->get_max());
}
else
{
$this->load->view('login');
}
}
public function get_max()
{
$query2 = $this->db->query("SELECT pof_num FROM pull_out where pof_num = '8800000582'");
$row = $query2->row();
echo $row->pof_num + 1; // i want this line to put into view.
$query2->free_result();
}
Hi all. How can i see all the difference between two dates in a column. I know to see a single date difference we can do: $stmt = $pdo->query("SELECT DATEDIFF(date_paid, next_due) AS diffdate FROM table_name"); while($row = $stmt->fetch(PDO::FETCH_ASSOC)) { echo $row['diffdate']; } but i want all the difference to show in a table along with other details. thanks Hi,
i have two methods with different function, each is calling to view a record from database. now i want store this two methods into one view.
ex.
model
function 1()
{
table_0ne
}
function 2()
{
table_two
}
controller
function 1()
{
view 1,2
}
it is possible, please help.. and i have code below, and it is not work when i apply $datax
public function generate_po()
{
$po_id = $this->input->post('selector');
$data['result'] = $this->public_base_model->generate_po($po_id);
$datax['result'] = $this->public_base_model->get_max_num();
if($this->session->userdata('logged_in'))
{
$session_data = $this->session->userdata('logged_in');
$data['username'] = $session_data['username'];
$data['fname'] = $session_data['fname'];
$data['userid'] = $session_data['userid'];
$this->load->view('generate_po', $data, $datax);
}
else
{
$this->load->view('login');
}
}
looking for a way to view the PHP source code of any PHP page on the web. Looking for a way to obtain PHP source code in order to help me with a certain issue. Advise. when i right click to view page source i just saw the javascript calling php as source file , while on page there is table, i need to read that table in database , is there nay way to do that, file_get contents dont work on it its just take javascript not the page table Hello im new to php and i cant seems to view my database in my php
<?php
include('../connect.php');
$sds=$_SESSION['SESS_FIRST_NAME'];
$result = mysql_query("SELECT * FROM paymentdetails WHERE idnumber='$sds'");
while($row = mysql_fetch_array($result))
{
echo '<tr class="record">';
echo '<td style="border-left: 1px solid #C1DAD7"><div align="left">'.$row['date'].'</div></td>';
echo '<td><div align="left">'.$row['amount'].'</div></td>';
echo '</tr>';
}
?>
</tbody>
</table>
Here my database im really confuse on what to doCREATE TABLE IF NOT EXISTS `paymentdetails` ( `id` int(11) NOT NULL AUTO_INCREMENT, `idnumber` varchar(30) NOT NULL, `date` varchar(30) NOT NULL, `amount` varchar(30) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; -- -- Dumping data for table `paymentdetails` -- INSERT INTO `paymentdetails` (`id`, `idnumber`, `date`, `amount`) VALUES (1, 'SID-YWU49JU', '2014-08-07', '50000'); |
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